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  • using dictionaries with WebServices

    - by umit-alba
    Hi! I tried to pass a dictionary via WebServices. However it is not serializeable. So i wrote an Own Class that makes it serializeable: using System; using System.Net; using System.Windows; using System.Collections.Generic; using System.Xml.Serialization; using System.Xml; using System.Xml.Schema; namespace Platform { public class SaDictionary<TKey, TValue> : Dictionary<TKey, TValue>, IXmlSerializable { #region Constructors public SaDictionary() : base() { } public SaDictionary(IDictionary<TKey, TValue> dictionary) : base(dictionary) { } public SaDictionary(IEqualityComparer<TKey> comparer) : base(comparer) { } public SaDictionary(int capacity) : base(capacity) { } public SaDictionary(IDictionary<TKey, TValue> dictionary, IEqualityComparer<TKey> comparer) : base(dictionary, comparer) { } public SaDictionary(int capacity, IEqualityComparer<TKey> comparer) : base(capacity, comparer) { } //protected SaDictionary(SerializationInfo info, StreamingContext context) // : base(info, context) //{ //} #endregion public XmlSchema GetSchema() { return null; } public void ReadXml(XmlReader reader) { XmlSerializer keySerializer = new XmlSerializer(typeof(TKey)); XmlSerializer valueSerializer = new XmlSerializer(typeof(TValue)); bool wasEmpty = reader.IsEmptyElement; reader.Read(); if (wasEmpty) return; while (reader.NodeType != XmlNodeType.EndElement) { reader.ReadStartElement("item"); reader.ReadStartElement("key"); TKey key = (TKey)keySerializer.Deserialize(reader); reader.ReadEndElement(); //key reader.ReadStartElement("value"); TValue value = (TValue)valueSerializer.Deserialize(reader); reader.ReadEndElement(); //value this.Add(key, value); reader.ReadEndElement(); //item // reader.MoveToContent(); } reader.ReadEndElement(); } public void WriteXml(XmlWriter writer) { XmlSerializer keySerializer = new XmlSerializer(typeof(TKey)); XmlSerializer valueSerializer = new XmlSerializer(typeof(TValue)); foreach (TKey key in this.Keys) { writer.WriteStartElement("item"); writer.WriteStartElement("key"); keySerializer.Serialize(writer, key); writer.WriteEndElement(); //key writer.WriteStartElement("value"); TValue value = this[key]; valueSerializer.Serialize(writer, value); writer.WriteEndElement(); //value writer.WriteEndElement(); //item } } } } However i get an ArrayOfXElement back. Is there a way to cast it back to a Dictionary? greets

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  • do we need to escape the character '<'

    - by Ozkan
    In C# ASP.NET, if we have the characters < or in a string. Do we need to escape it like: string a = "\<test\>abcdef\</test\>" because this string will be send to an external method via webservices. And in that method, it will be converted to a some kind of xml file. contentHtml = "<?xml version=\"1.0\" encoding=\"utf-16\"?>" + contentHtml; content_ws.AddContent(contentHtml); //AddContent() method is a external method (via webservices) Thx for help

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  • Catching an error for a child resource in Ruby on Rails

    - by randombits
    What is the best way to add errors to render if a child resource is really what's having issues and not the parent resource? In english what I mean is the following.. imagine the following code: @foo = Foo.new foochild = Foochild.new // break foochild somehow @foo << foochild @foo.save now when I do: format.xml { render :xml => @foo.errors } I don't get anything about how foochild broke, meaning the error message is useless to the user. How does one go about fixing this?

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  • Export Multiple Sheets to Excel Through Browser

    - by ProfK
    I need to export multiple data tables to Excel on the clients machine, each to their own sheet. If it was just one sheet, I'd use the Excel/csv content type, but I've heard something about an XML format that can represent an entire workbook. I don't want to go down the Packaging and .xlsx route, so I need standard .xls. Our bug tracker, Gemini, used to have an export function that produced an XML file that Excel automatically opened as a multi-sheet workbook, but I can't find it. Is there still such a mechanism, and where can I find that schema?

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  • How can I embed a conditional comment for IE with innerHTML?

    - by Samuel Charpentier
    Ok so I want to conditionally add this line of code; <!--[if ! IE]> <embed src="logo.svg" type="image/svg+xml" /> <![endif]--> Using: document.getElementById("logo") .innerHTML='...'; In a if()/else() statement and it don't write it! If i get rid of the selective comment ( <!--[if ! IE]><![endif]-->) and only put the SVG ( <embed src="logo.svg" type="image/svg+xml" /> ) it work! what should I do? I found a way around but i think in the Android browser the thing will pop up twice. here's what I've done ( and its Validated stuff!); <!DOCTYPE html> <html> <head> <META CHARSET="UTF-8"> <title>SVG Test</title> <script type="text/javascript"> //<![CDATA[ onload=function() { var ua = navigator.userAgent.toLowerCase(); var isAndroid = ua.indexOf("android") > -1; //&& ua.indexOf("mobile"); if(isAndroid) { document.getElementById("logo").innerHTML='<img src="fin_palais.png"/>'; } } //]]> </script> </head> <body> <div id="logo"> <!--[if lt IE 9]> <img src="fin_palais.png"/> <![endif]--> <!--[if gte IE 9]><!--> <embed src="fin_palais.svg" type="image/svg+xml" /> <!--<![endif]--> </div> </body>

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  • How do I construct a request for a WCF http post call?

    - by James Hay
    I have a really simple service that I'm messing about with defined by: [OperationContract] [WebInvoke(UriTemplate = "Review/{val}", RequestFormat = WebMessageFormat.Xml, Method = "POST", BodyStyle=WebMessageBodyStyle.Bare)] void SubmitReview(string val, UserReview review); UserReview is, at the moment, a class with no properties. All very basic. When I try and test this in Fiddler I get a bad request status (400) message. I'm trying to call the service using the details: POST http://127.0.0.1:85/Service.svc/Review/hello Headers User-Agent: Fiddler Content-Type: application/xml Host: 127.0.0.1:85 Content-Length: 25 Body <UserReview></UserReview> I would think i'm missing something fairly obvious. Any pointers?

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  • Define keyref selector based on element type in XPath

    - by Robert Sirre
    Let's say I have an XML file that will look like this: <a> <b d="value1"/> <c d="value2"/> </a> In the XSD file that defines the structure of this XML file I defined the elements by name 'b' and 'c' to be of the same type (and the type requires attribute 'd'). Let's say that I want to make a keyReference of all elements of the type that both 'b' and 'c' are, is there any way in XPath to do this? At the definition of the type of 'a' I would expect something like this: <xs:keyref name="myReferenceName" refer="keyToReferTo"> <xs:selector xpath="[@type='typenameof elements b and c?']"/> <xs:field xpath="@d"/> </xs:keyref> Is something like this possible, or is XPath, even in the XSD, schema-unaware?

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  • having trouble with jpa, looks to be reading from cache when told to ignore

    - by jeff
    i'm using jpa and eclipselink. it says version 2.0.2.v20100323-r6872 for eclipselink. it's an SE application, small. local persistence unit. i am using a postgres database. i have some code the wakes up once per second and does a jpa query on a table. it's polling to see whether some fields on a given record change. but when i update a field in sql, it keeps showing the same value each time i query it. and this is after waiting, creating a new entitymanager, and giving a query hint. when i query the table from sql or python, i can see the changed field. but from within my jpa query, once i've read the value, it never changes in later executions of the query -- even though the entity manager has been recreated. i've tried telling it to not look in the cache. but it seems to ignore that. very puzzling, can you help please? here is the method. i call this once every 3 seconds. the tgt.getTrlDlrs() println shows me i get the same value for this field on every call of the method ("value won't change"). even if i change the field in the database. when i query the record from outside java, i see the change right away. also, if i stop the java program and restart it, i see the new value printed out immediately: public void exitChk(EntityManagerFactory emf, Main_1 mn){ // this will be a list of the trade close targets that are active List<Pairs01Tradeclosetgt> mn_res = new ArrayList<Pairs01Tradeclosetgt>(); //this is a list of the place number in the array list above //of positions to close ArrayList<Integer> idxsToCl = new ArrayList<Integer>(); EntityManager em = emf.createEntityManager(); em.getTransaction().begin(); em.clear(); String qryTxt = "SELECT p FROM Pairs01Tradeclosetgt p WHERE p.isClosed = :isClosed AND p.isFilled = :isFilled"; Query qMn = em.createQuery(qryTxt); qMn.setHint(QueryHints.CACHE_USAGE, CacheUsage.DoNotCheckCache); qMn.setParameter("isClosed", false); qMn.setParameter("isFilled", true); mn_res = (List<Pairs01Tradeclosetgt>) qMn.getResultList(); // are there any trade close targets we need to check for closing? if (mn_res!=null){ //if yes, see whether they've hit their target for (int i=0;i<mn_res.size();i++){ Pairs01Tradeclosetgt tgt = new Pairs01Tradeclosetgt(); tgt = mn_res.get(i); System.out.println("value won't change:" + tgt.getTrlDlrs()); here is my entity class (partial): @Entity @Table(name = "pairs01_tradeclosetgt", catalog = "blah", schema = "public") @NamedQueries({ @NamedQuery(name = "Pairs01Tradeclosetgt.findAll", query = "SELECT p FROM Pairs01Tradeclosetgt p"), @NamedQuery(name = "Pairs01Tradeclosetgt.findByClseRatio", query = "SELECT p FROM Pairs01Tradeclosetgt p WHERE p.clseRatio = :clseRatio")}) public class Pairs01Tradeclosetgt implements Serializable { private static final long serialVersionUID = 1L; @Id @Basic(optional = false) @Column(name = "id") @SequenceGenerator(name="pairs01_tradeclosetgt_id_seq", allocationSize=1) @GeneratedValue(strategy=GenerationType.SEQUENCE, generator = "pairs01_tradeclosetgt_id_seq") private Integer id; and my persitence unit: <?xml version="1.0" encoding="UTF-8"?> <persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"> <persistence-unit name="testpu" transaction-type="RESOURCE_LOCAL"> <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider> <class>mourv02.Pairs01Quotes</class> <class>mourv02.Pairs01Pair</class> <class>mourv02.Pairs01Trderrs</class> <class>mourv02.Pairs01Tradereq</class> <class>mourv02.Pairs01Tradeclosetgt</class> <class>mourv02.Pairs01Orderstatus</class> <properties> <property name="javax.persistence.jdbc.url" value="jdbc:postgresql://192.168.1.80:5432/blah"/> <property name="javax.persistence.jdbc.password" value="secret"/> <property name="javax.persistence.jdbc.driver" value="org.postgresql.Driver"/> <property name="javax.persistence.jdbc.user" value="noone"/> </properties> </persistence-unit> </persistence>

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  • Java + Eclipse + Pulpcore

    - by cable729
    I've never programmed in java or eclipse before, although I have used c# and visual studio. I'm trying to get started with java development, and develop 2d games, but I can't get the project to run. I've followed the tutorial here: http://cloningtheclassics.com/getting-started-with-pulpcore/ I've retried the tutorial at least 5 times, and I still can't get it to work. The error it displays is: Buildfile: C:\workspace\javapulp\project\build.xml [taskdef] Could not load definitions from resource tasks.properties. It could not be found. [taskdef] Could not load definitions from resource tasks.properties. It could not be found. -init: BUILD FAILED C:\workspace\javapulp\project\build.xml:127: Required file not found: ../../build/pulpcore-applet-debug-0.11.jar Total time: 1 second Thanks in advance!

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  • getResourceAsStream not loading resource

    - by Michal Gorecki
    The project that I am currently working on utilizes an old application contained within a .jar file. One of the responsibilities of this application is that it updates the database when changes to the configuration files are made. Every time I try to run this file (which is a simple Ant Task extension), I get an exception thrown early in the process. I decompiled the Java file responsible, and found that the exception being thrown happens here. I do not know what the issue is, as "hibernate.cfg.xml" is contained within the same .jar file as the .class throwing the exception. ClassLoader loader = Thread.currentThread().getContextClassLoader(); InputStream in = loader.getResourceAsStream("hibernate.cfg.xml"); if (in == null) { throw new RuntimeException("Couldn't find built in hibernate config"); } If anyone has any ideas, even pointing me in the right direction, I would be grateful. Of course, any solution will have to be external, as the client already has this build of the program in production use.

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  • How to print an Objectified Element?

    - by BeeBand
    I have xml of the format: <channel> <games> <game slot='1'> <id>Bric A Bloc</id> <title-text>BricABloc Hoorah</title-text> <link>Fruit Splat</link> </game> </games> </channel> I've parsed this xml using lxml.objectify, via: tree = objectify.parse(file) There will potentially be a number of <game>s underneath <games>. I understand that I can generate a list of <game> objects via: [ tree.games[0].game[0:4] ] My question is, what class are those objects and is there a function to print any object of whatever class these objects belong to?

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  • zend-framework navigation

    - by ulduz114
    i have this xml file for Creating a container , if i want create a db for save this items and and create container from db how should i do ? <?xml version="1.0" encoding="utf-8"?> <config> <nav> <logout> <label>logout</label> <controller>authentication</controller> <action>logout</action> <resource>logout</resource> </logout> <login> <label>login</label> <controller>authentication</controller> <action>login</action> <resource>login</resource> </login> <test> <label>test</label> <uri>#</uri> <resource>test</resource> <pages> <list> <label>list</label> <controller>tset</controller> <action>listtest</action> </list> <archive> <label>archive</label> <controller>myarchive</controller> <action>archive</action> </archive> </pages> </test> </nav> </config> and code in bootsrap $navContainerConfig = new Zend_Config_Xml(APPLICATION_PATH . 'navigation.xml', 'nav'); $navContainer = new Zend_Navigation($navContainerConfig);

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  • Rails: include related object in JSON output

    - by Codezy
    I have a note class that belongs to a user (ie a user can create many notes). clip from my notes controller class NotesController < ApplicationController before_filter :authenticate_user! respond_to :html, :xml, :json # GET /notes # GET /notes.xml def index @notes = Note.includes(:user).order("created_at DESC") respond_with @notes end When I ask for the index in json results for example /notes.json, it returns the notes but only returns user_id for the user object. I would like it to also include user.username (and would be curious how to have the whole user object embedded). Bonus question: I could not find a way to make the column show as author_id and have it relate back to user. If this is easy to do, how do you do it?

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  • generating class from hibernate mapping file

    - by Mrityunjay
    hi, i have one mapping file viz. student.hbm.xml.. i need to generate Student.java from the same. the file is below :- <?xml version="1.0" encoding="UTF-8"?> <hibernate-mapping> <class name="org.hibernate.entity.ClassRoom" table="class_room"> <id name="roomId" column="room_id" type="int"/> <property name="roomClass" column="room_class" type="string"/> <property name="floor" column="floor" type="int"/> <property name="roomMaster" column="room_mast" type="string"/> </class> </hibernate-mapping> is there any way i can create the class file from the above file.please help...

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  • xml2struct cannot access element(s)

    - by csetzkorn
    I try to use this: xml2struct when I use this xml: <XMLname attrib1="Some value"> <Element>Some text</Element> <DifferentElement attrib2="2">Some more text</DifferentElement> <DifferentElement attrib3="2" attrib4="1">Even more text</DifferentElement> </XMLname> I can create a struct: test = xml2struct('C:\bla\bla.xml'); (tested it with class(test)) It looks like this: test = Name: 'XMLname' Attributes: [1x1 struct] Data: '' Children: [1x7 struct] But I cannot access: test.XMLname.Element.Text I get: ??? Reference to non-existent field 'XMLname'. Any ideas?

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  • Getting my webapp to be database agnostic with Hibernate...

    - by JellyHead
    So the ultimate in scope-creep came in the other day: since we're using Hibernate, could we make our webapp run on Oracle as well as MySQL, interchangably? I thought this would be a simple case of changing hibernate.cfg.xml so that instead of explicity stating MySQL-specific options, it would reference a JNDI datasource, allowing the application to build regardless of the database we intend to deploy to. Then changing to a different database would simply mean changing the separate datasource configuration in JBoss, Jetty, WebLogic etc. Is this realistic? Well, I got as far as setting that up in Jetty, but What's tripping me up right now is error about the hibernate.dialect not having been set in hibernate.cfg.xml. But If I set the dialect there, then my app is still going to be built in either MySQL or Oracle flavours, which is not really what I want. Either I'm trying to attempt the impossible or I've missed something fundamentally obvious... anyone else had a similar problem (and subsequent solution/workaround)?

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  • how to get SOURCE

    - by laknath27
    i do some development with jena ontology API.my ontology file in my local machine..when i'm going to read the model.. there is an error.. and i made ontology with protege and tried to read that file. String SOURCE = "http://www.owl-ontologies.com/Ontology1275995702";(it's XML:base value) //String NS = SOURCE + "#"; //InputStream in = FileManager.get().open("tourism.owl"); OntModel model = ModelFactory.createOntologyModel(OntModelSpec.OWL_MEM); model.read(SOURCE,"RDF/XML"); OntClass paper = model.getOntClass( SOURCE + "srilanka" ); how can i fix this?

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  • Is it possible to use wildcards within J2EE - fitlers?

    - by Sergio del Amo
    I would like to apply a filter to severl url endings. The next configuraiton seems to work. <filter> <filter-name>LanguageFilter</filter-name> <filter-class>filters.LanguageFilter</filter-class> </filter> <filter-mapping> <filter-name>LanguageFilter</filter-name> <url-pattern>*.do</url-pattern> </filter-mapping> <filter-mapping> <filter-name>LanguageFilter</filter-name> <url-pattern>*.xml</url-pattern> </filter-mapping> Originally I asked if it was possible to use wildcards such as: <url-pattern>*.do|*.xml</url-pattern> But it does not seem to be possible.

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  • How do I find iTunes library folder on Mac and Windows?

    - by Boris
    I made an application that parse the iTunes library to retrieve its content. It works fine in most cases but if a user moved his library somewhere else than the default iTunes folder (see: http://lifehacker.com/238296/ultranewb--how-to-move-your-itunes-library-to-an-external-drive), then I need a way to find this path. On Mac, I was looking into ~/Library/Preferences/com.apple.iTunes.plist. There is a setting called "alis:1:iTunes Library Location" but it contains several parameters all concatenated and converted to hexadecimal. On Windows, I found this file "C:\Documents and Settings\\Application Data\Apple Computer\iTunes\iTunesPrefs.xml" that contains a setting "iTunes Library XML Location:1" but this one is encoded. Any help would be greatly appreciated. Thanks!

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  • frame by frame animation not running

    - by abc
    well,i am a newbie to android..and i dont know whats wrong in my code.. this is my xml file <?xml version="1.0" encoding="utf-8"?> <animation-list xmlns:android="http://schemas.android.com/apk/res/android" id="selected" android:oneshot="false"> <item android:drawable="@drawable/w1" android:duration="50" /> <item android:drawable="@drawable/w2" android:duration="50" /> </animation-list> my java file ImageView img = (ImageView)findViewById(R.id.s); img.setBackgroundResource(R.anim.shape_animation); // Get the background, which has been compiled to an AnimationDrawable object. AnimationDrawable frameAnimation = (AnimationDrawable) img.getBackground(); // Start the animation (looped playback by default). frameAnimation.start();

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  • How to add Ads for my android app using eclipse?

    - by user3896367
    I am trying to add ads to my app but I don't know how I followed the instructions from this site: https://developer.android.com/google/play-services/ads.html I did step 1 and 2 in the getting started column, I imported the google-play-services_libs to my workspace then I referenced it in my app and I added this code in my mainfest: <meta-data android:name="com.google.android.gms.version" android:value="@integer/google_play_services_version" /> I opened the sample ad and copied this code to my xml: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:ads="http://schemas.android.com/apk/res-auto" android:layout_width="match_parent" android:layout_height="match_parent" android:background="@android:color/black" android:gravity="center" android:orientation="vertical" > <com.google.android.gms.ads.AdView android:id="@+id/adView" android:layout_width="match_parent" android:layout_height="wrap_content" android:layout_alignParentBottom="true" android:layout_alignParentLeft="true" ads:adUnitId="@string/ad_unit_id"/> but I am getting this error: The following classes could not be instantiated: - com.google.android.gms.ads.AdView so do you know how to fix this problem and can you tell me what should i write in the java to make in work thanks

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  • Bind Config section to DataTable using c#

    - by srk
    I have the following config section in my app.config file and the code to iterate through config section to retrieve the values. But i want to save the values of config section to a datatable in a proper structure. How ? I want to show all the values in datagridview with appropriate columns. <configSections> <section name="ServerInfo" type="System.Configuration.IConfigurationSectionHandler" /> </configSections> <ServerInfo> <Server id="1"> <Name>SRUAV1</Name> <key> 1 </key> <IP>10.1.150.110</IP> <Port>7901</Port> </Server> <Server id="2"> <Name>SRUAV2</Name> <key> 4 </key> <IP>10.1.150.110</IP> <Port>7902</Port> </Server> <Server id="3"> <Name>SRUAV3</Name> <key> 6 </key> <IP>10.1.150.110</IP> <Port>7904</Port> </Server> </ServerInfo> Code : public void GetServerValues(string strSelectedServer) { Configuration config = ConfigurationManager.OpenExeConfiguration(ConfigurationUserLevel.None); ConfigurationSection section = config.GetSection("ServerInfo"); XmlDocument xml = new XmlDocument(); xml.LoadXml(section.SectionInformation.GetRawXml()); string temp = ""; XmlNodeList applicationList = xml.DocumentElement.SelectNodes("Server"); for (int i = 0; i < applicationList.Count; i++) { object objAppId = applicationList[i].Attributes["id"]; int iAppId = 0; if (objAppId != null) { iAppId = Convert.ToInt32(applicationList[i].Attributes["id"].Value); } temp = BuildServerValues(applicationList[i]); } } public string BuildServerValues(XmlNode applicationNode) { for (int i = 0; i < applicationNode.ChildNodes.Count; i++) { if (applicationNode.ChildNodes.Item(i).Name.ToString().Equals("Name")) { strServerName = applicationNode.ChildNodes.Item(i).InnerXml.ToString(); } if (applicationNode.ChildNodes.Item(i).Name.ToString().Equals("IP")) { strIP = applicationNode.ChildNodes.Item(i).InnerXml.ToString(); } if (applicationNode.ChildNodes.Item(i).Name.ToString().Equals("Port")) { strPort = applicationNode.ChildNodes.Item(i).InnerXml.ToString(); } } return strServerName; }

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  • How do I override a Spring bean definition yet still reference the overriden bean?

    - by Kevin
    I'm attempting to implement a delegate Service provider by overriding the bean definition for the original service with my delegate Service. However, as the name would imply, the delegate Service needs a reference to the original service to delegate calls to. I'm having trouble figuring out how to override the bean definition while using the original bean def without running into a circular reference issue. For example: <!-- Original service def in spring-context.xml --> <bean id="service" class="com.mycompany.Service"/> <!-- Overridden definition in spring-plugin-context.xml --> <bean id="service" class="com.mycompany.DelegatedService"/> <constructor-arg ref="service"/> </bean> Is this possible?

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  • MS SQL Server Text Datatype Maxlength = 65,535?

    - by craigmj
    Software I'm working with uses a text field to store XML. From my searches online, the text datatype is supposed to hold 2^31 - 1 characters. Currently SQL Server is truncating the XML at 65,535 characters every time. I know this is caused by sqlserver, because if I add a 65,536th character to the field directly in Management Studio, it states that it will not update because characters will be truncated. Is the Maxlength really 65,535 or could this be because the database was designed in an earlier version of MS SQL Server (2000) and it's using the legacy text datatype instead of 2005's? If this is the case, will Altering the datatype to Text in sql server 2005 fix this issue?

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