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  • least value in count

    - by Nyfer
    i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute. Show all the employee who were hired on the day of the week on which least no of employee were hired. i have done the query, but am not able to get the least. please check if am correct. select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count from test.employee group by days

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  • How can I Create a CMS using php where end user doesn't have to know anything about database. Is that possible

    - by cryptex_vinci
    In genera sense if I create a CMS using php .Where I created and named the database in my localhost. Now if I or my clent upload the CMS in any server how will it work. because there is no database in that server. And in my php code I wrote to create database. Now how can i create a CMS which can automatically create database and tables where client doesn't have to know about anything besides uploading the CMS.

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  • wp+sql+image not goin in the folder

    - by happy
    this is my code for uploading image in database but image are going to the desird forlder...but when i m tryin to retrieve the images to diaplay,,they are not displayed..anyone help me...... $category=$_POST['category']; $uploadDir = 'D:/xampp/htdocs/js/wordpress/wp-content/plugins/img/imagess/ '; $fileName = $_FILES['Photo']['name']; $tmpName = $_FILES['Photo']['tmp_name']; $fileSize = $_FILES['Photo']['size']; $fileType = $_FILES['Photo']['type']; $filePath = $uploadDir . $fileName; $result = move_uploaded_file($tmpName,$filePath); if (!$result) { echo "Error uploading file"; exit; } if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); $filePath = addslashes($filePath); } global $wpdb; //$insert=$wpdb->insert('images',array('image_name'=>$filePath,'cat_name'=>$category),array('%b','%s')); $insert=$wpdb->insert('images',array('image_name'=>$filePath,'cat_name'=>$category)); $wpdb->insert('categories',array('cat_name'=>$category)); echo "Successfully Submitted";

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  • How can I add dynamic text from a different table where primary key is a foreign key to adynamic table being shown?

    - by Jethro Tamares Doble
    I have here a dynamic table named tb_user with column region_id and institute_id and both ids are primary key of another table tb_region (with column region_name and region_id) and tb_institute (column institute_id and institute_name). I wanted to see region_name and institute_name instead of the ids. I've used this php script <?php echo $row_institute['institution_name']; ?> and query to collect data for tb_institute mysql_select_db($database_connection_ched, $connection_ched); $query_institution = "SELECT institute_id, institute_name FROM tb_institute"; $institution = mysql_query($query_institution, $connection_ched) or die(mysql_error()); $row_institution = mysql_fetch_assoc($institution); $totalRows_institution = mysql_num_rows($institution); but it seems not to display the correct name of id. query i used to collect data: mysql_select_db($database_connection_ched, $connection_ched); $query_notification = sprintf("SELECT * FROM tb_user WHERE status = 'inactive' ORDER BY date_register ASC", GetSQLValueString($colname_notification, "text")); $query_limit_notification = sprintf("%s LIMIT %d, %d", $query_notification, $startRow_notification, $maxRows_notification); $notification = mysql_query($query_limit_notification, $connection_ched) or die(mysql_error()); $row_notification = mysql_fetch_assoc($notification); if (isset($_GET['totalRows_notification'])) { $totalRows_notification = $_GET['totalRows_notification']; } else { $all_notification = mysql_query($query_notification); $totalRows_notification = mysql_num_rows($all_notification); } $totalPages_notification = ceil($totalRows_notification/$maxRows_notification)-1;

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  • Working with sets of rows in (My)SQL and comparing values

    - by Pep.
    Hello, I am trying to figure out the SQL for doing some relatively simple operations on sets of records in a table but I am stuck. Consider a table with multiple rows per item, all identified by a common key. For example: serial model color XX1 A blue XX2 A blue XX3 A green XX5 B red XX6 B blue XX1 B blue What I would for example want to do is: Assuming that all model A rows must have the same color, find the rows which dont. (for example, XX3 is green). Assuming that a given serial number can only point to a single type of model, find out the rows which that does not occur (for example XX1 points both to A and B) These are all simple logically things to do. To abstract it, I want to know how to group things by using a single key (or combination of keys) and then compare the values of those records. Should I use a join on the same table? should i use some sort of array or similar? thanks for your help

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  • How to first get different related values from diferent SQL tables (PHP)

    - by Ole Jak
    I am triig to fill options list. I have 2 tables USERS and STREAMS I vant to get all streams and get names of users assigned to that streams. Users consists of username and id Streams consists of id, userID, streamID I try such code: <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); while ($row = mysql_fetch_array($streams_set)){ $userid = $row['userID']; global $connection; $query2 = "SELECT email, username "; $query2 .= "FROM users "; $query2 .= "WHERE id = '{$userid}' "; $qs = mysql_query($query2, $connection); confirm_query($qs); $found_user = mysql_fetch_array($qs); echo ' <option value="'.$row['streamID'].'">'.$row['userID'].$found_user.'</option> '; } ?> But it does not return USER names from DB=( So what shall I do to this code to see usernames as "options" text?

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  • How To Get YEARWEEK() To See Sunday As The Start Of The Week?

    - by tan
    I'm trying to get the YEARWEEK function to see Sunday as the 1st day of the week. An example date is: Sunday 1st Mar 2009 Here is my sql SELECT YEARWEEK('2009-03-01') and the result is - 200909 Which is week 9. I believe it is telling me this is week 9 because it sees the sunday as the last day of the previous week. How would I get this function to see sunday as the 1st day of the week and therefore return as week 10?

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  • Complex SELECT statement; one-to-many all details in one row

    - by RubyWedge
    There are two tables: Products ID (Primary Key), ProductName PlannedByMonths ProductID (Primary Key) (Link to the Products table many-to-one), MonthNumber (Primary Key), QtytoProduce, How to write SELECT statement to retrieve results in the following format? ProductName, QtytoProduceMonth1, QtytoProduceMonth2, QtytoProduceMonth3, QtytoProduceMonth4, QtytoProduceMonth5, QtytoProduceMonth6, QtytoProduceMonth7, QtytoProduceMonth8, QtytoProduceMonth9, QtytoProduceMonth10, QtytoProduceMonth11, QtytoProduceMonth12 Thank you.

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  • Does it make sense to replace sub-queries by join?

    - by Roman
    For example I have a query like that. select col1 from t1 where col2>0 and col1 in (select col1 from t2 where col2>0) As far as I understand, I can replace it by the following query: select t1.col1 from t1 join (select col1 from t2 where col2>0) as t2 on t1.col1=t2.col1 where t1.col2>0 ADDED In some answers I see join in other inner join. Are both right? Or they are even identical?

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  • With a SELECT...WHERE id IN (...), order results by IN() ?

    - by Deca
    With a query such as: SELECT * FROM images WHERE id IN (12,9,15,3,1) is it possible to order the results by the contents of the IN clause? The result I'm looking for would be something like: [0] => Array ( [id] => 12 [file_name] => foo ) [1] => Array ( [id] => 9 [file_name] => bar ) [2] => Array ( [id] => 15 [file_name] => baz ) ...

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  • PHP from database and query

    - by Kyle R
    I have a table: id, affiliate Each time somebody clicks a link, a new row is inserted, ID being the ID of the page, and affiliate being the ID of the affiliate. For example: Page ID: 9 Affiliate ID: 1 Page ID: 9 Affiliate ID: 2 Page ID: 9 Affiliate ID: 3 I only have 3 affiliates. I want to select this information, and group them by affiliate, for the ID. I have tried this query: SELECT COUNT(*) FROM table WHERE id = '9' GROUP BY affiliate It works fine when I do it in php my admin, how do I get the info in PHP? I have tried: $q = mysql_query("SELECT COUNT(*) FROM table WHERE id = '" . $id . "' GROUP BY affiliate"); $r = mysql_fetch_array($q); When trying to print the data onto the page, I am only getting one result. Do I need to use a foreach/while loop to get all 3? How would I go about doing this? Thank you!

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  • mysql_affected_rows() always returns 1 even though no row was updated.

    - by happyhardik
    What I am trying to do is: (programmatically) Update status where id is something, if no rows where updated, give error: we cannot find the record with id something, otherwise give message success. Here I am using mysql_affected_rows() to know if a row was updated or not, but it always return 1, so the user gets a success message, even though there was no row updated. Can anyone tell me what could it be?

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  • limiting a query to a specific item

    - by Dev-Ria
    I have a db with thousands of domains and data. I want to list only 100 rows of each domain. i can't use LIMIT 100 cause that only limits 100 records but I want dom1 to list 100 dom2 to list 100 dom3 to list 100 all in one query. This is what I have so far. SELECT domain COUNT(Key) AS DomCount FROM table_domain GROUP BY user,location ORDER BY domain,DomCount DESC Could I use a CASE?

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  • Dont know how to select a few records from a table as utf8

    - by kwokwai
    Hi all, I don't have phpMyAdmin installed in my web site. Sometimes I was doing some select SQL command at the backend, but when I typed in this command to show all records from table Users: select * from Users; The records were printed as ???? | ??? ??? ??? |. I don't want to make any permanent changes to the charset in the database, so, how is it possible to temporarily displayed a few records as utf8 when needed?

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  • Allow users to pull temporary data then delete table data (headers remain)?

    - by JM4
    I don't know the best way to title this question but am trying to accomplish the following goal: When a client logs into their profile, they are presented with a link to download data from an existing database in CSV format. The process works, however, I would like for this data to be 'fresh' each time they click the link so my plan was - once a user has clicked the link and downloaded the CSV file, the database table would 'erase' all of its data and start fresh (be empty) until the next set of data populated it. My EXISTING CSV creation code: <?php $host = 'localhost'; $user = 'username'; $pass = 'password'; $db = 'database'; $table = 'tablename'; $file = 'export'; $link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error()); mysql_select_db($db) or die("Can not connect."); $result = mysql_query("SHOW COLUMNS FROM ".$table.""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row['Field'].", "; $i++; } } $csv_output .= "\n"; $values = mysql_query("SELECT * FROM ".$table.""); while ($rowr = mysql_fetch_row($values)) { for ($j=0;$j<$i;$j++) { $csv_output .= '"'.$rowr[$j].'",'; } $csv_output .= "\n"; } $filename = $file."_".date("Y-m-d",time()); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); header( "Content-disposition: filename=".$filename.".csv"); print $csv_output; exit; ?> any ideas?

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  • Make SQL query more efficient

    - by Webnet
    I currently have this query which runs 2 of the exact same sub queries but pull different data. When I make the values comma separated it throws an SQL error saying the sub query can return only one value. Is there anything else I can do to avoid running multiple sub queries? SELECT product_id, ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc WHERE product_id = product_master.product_id) as listing_count, sku, type_id, ( SELECT AVG(ebay_archive_listing.current_price), AVG(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing WHERE id IN ( SELECT listing_id FROM ebay_archive_product_listing_assoc WHERE product_id = product_master.product_id ) AND ebay_archive_listing.start_time >= '.$startTimestamp.' AND ebay_archive_listing.start_time <= '.$endTimestamp.' AND ebay_archive_listing.current_price > 0 ) as average_bid_price, ( SELECT FROM ebay_archive_listing WHERE id IN ( SELECT listing_id FROM ebay_archive_product_listing_assoc WHERE product_id = product_master.product_id ) AND ebay_archive_listing.start_time >= '.$startTimestamp.' AND ebay_archive_listing.start_time <= '.$endTimestamp.' AND ebay_archive_listing.buy_it_now_price > 0 ) as average_buyout_price FROM product_master I'm aware of the syntax error... I'm selecting 2 seperate averages and am wondering if I can do it any simpler way.

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  • Preventing SQL injecting in a database class

    - by Josh
    I'm building a database class and thought it'd be a good idea to incorporate some form of SQL injection prevention (duh!). Here's the method that runs a database query: class DB { var $db_host = 'localhost'; var $db_user = 'root'; var $db_passwd = ''; var $db_name = 'whatever'; function query($sql) { $this->result = mysql_query($sql, $this->link); if(!$this->result) { $this->error(mysql_error()); } else { return $this->result; } } } There's more in the class than that but I'm cutting it down just for this. The problem I'm facing is if I just use mysql_real_escape_string($sql, $this->link); then it escapes the entire query and leads to a SQL syntax error. How can I dynamically find the variables that need to be escaped? I want to avoid using mysql_real_escape_string() in my main code blocks, i'd rather have it in a function. Thanks.

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  • Multiple &(AND) fails in query

    - by N e w B e e
    here is my query $sql = 'SELECT * FROM Orders INNER JOIN [Order Details] ON Orders.OrderNumber = [Order Details].OrderNumber WHERE Orders.CartID =2 AND [Order Details].Option10 Is Null AND [Order Details].Status="Shipped"'; this queries when entered in MS_Access sql view, returns the correct results, but when I copy and paste the same query in my php script, it fails and gives the error Too few parameters, expected 1... although data is there, query is working in access... Please note if I omitted on AND condition, it works eg if I removed shipped conidtion or is null condition, it works then too.. any hint? whats wrong with it?? any help?thanks

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  • Select products with users

    - by Ploppe
    I have not worked with SQL for quite a long time, and I need some help for a basic query. I have the three following tables: users (id, name) products (id, name) owners (userid, productid, date) One product can be sold by user A to user B and then back to A. Now, I want the list of all products currently owned by every single user with the date of transaction. Currently, my query is this one, but I'm stuck with old data (first association of one product to one user, and not the newest one): SELECT users.name, products.name, date FROM products JOIN owners ON products.id = owners.id JOIN users ON owners.id = user.id GROUP BY product.id Do you have some hints? Thanks

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  • datesub question

    - by Ahmet vardar
    Hi, is it possible to use date_sub like this ? $dt = date("Y-m-d h:i:s"); $query = "INSERT INTO `table` (`date`) VALUES ('DATE_SUB('$dt', INTERVAL 15 DAY)')"; $result = MYSQL_QUERY($query); Thanks

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  • custom function is not getting called

    - by nectar
    here my code - $child1 = create_childid()."01"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child1', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); echo $newid; update_level(); $child2 = create_childid()."02"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child2', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child3 = create_childid()."03"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child3', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child4 = create_childid()."04"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child4', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child5 = create_childid()."05"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child5', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); ERROR : update_level(); is executing only once why??

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