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  • Selenium selected option in dropdown not displayed correctly

    - by luckyfool
    I have the following issue with Selenium Webdriver. There are two dropdown menus on a page i am testing "brand" and "items". The options of "items" depend on which brand you choose. I am trying to iterate through all possible choices and print brand-item pairs. I use two possible ways to pick an option from each dropdown menu Using Select(): def retryingSelectOption(name,n): result=False attempts=0 while attempts<5: try: element=Select(driver.find_element_by_name(name)) element.select_by_index(n) print element.all_selected_options[0].text result=True break except StaleElementReferenceException: pass attempts+=1 return result And using .click(): def retryingClickOption(name,n): result=False attempts=0 while attempts<5: try: driver.find_element_by_name(name).find_elements_by_tag_name("option")[n].click() result=True break except StaleElementReferenceException: pass attempts+=1 return result My problem is that at ,what seem to me as random moments (sometimes it works sometimes it does not), even though the above functions return True and printing out the selected option shows me the correct answer, the browser still displays the previous option. So basically Selenium tells me i have picked the right option but the browser displays the previous one.No idea what is wrong.

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  • get the list and input from one function and run them in different function

    - by rookie
    i have a programm that generate the list and then i ask them to tell me what they want to do from the menu and this is where my problem start i was able to get the input form the user to different function but when i try to use the if else condition it doesn't check, below are my code def menu(x,l): print (x) if x == 1: return make_table(l) if x == 2: y= input("enter a row (as a number) or a column (as an uppercase letter") if y in [ "1",'2','3']: print("Minmum is:",minimum(y,l)) if x== 3: print ('bye') def main(): bad_filename = True l =[] while bad_filename == True: try: filename = input("Enter the filename: ") fp = open(filename, "r") for f_line in fp: f_str=f_line.strip() f_str=f_str.split(',') for unit_str in f_str: unit=float(unit_str) l.append(unit) bad_filename = False except IOError: print("Error: The file was not found: ", filename) #print(l) condition=True while condition==True: print('1- open\n','2- maximum') x=input("Enter the choice") menu(x,l) main() from the bottom function i can get list and i can get the user input and i can get the data and move it in second function but it wont work after that.thank you

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  • SQLAlchemy Mapping problem

    - by asdvalkn
    Dear Everyone, I am trying to sqlalchemy to correctly map my data. Note that a unified group is basically a group of groups. (One unifiedGroup maps to many groups but each group can only map to one ug). So basically this is the definition of my unifiedGroups: CREATE TABLE `unifiedGroups` ( `ugID` INT AUTO_INCREMENT, `gID` INT NOT NULL, PRIMARY KEY(`ugID`, `gID`), KEY( `gID`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 ; Note that each row is a ugID, gID tuple. ( I do not know before hand how many gID is per ugID so this is probably the most sensible and simplest method). Definition for my UnifiedGroup class class UnifiedGroup(object): """UnifiedProduct behaves very much like a group """ def __init__(self, ugID): self.ugID=ugID #Added by mapping self.groups=False def __str__(self): return '<%s:%s>' % (self.ugID, ','.join( [g for g in self.groups])) These are my mapping tables: tb_groupsInfo = Table( 'groupsInfo', metadata, Column('gID', Integer, primary_key=True), Column('gName', String(128)), ) tb_unifiedGroups = Table( 'unifiedGroups', metadata, Column('ugID', Integer, primary_key=True), Column('gID', Integer, ForeignKey('groupsInfo.gID')), ) My mapper maps in the following manner: mapper( UnifiedGroup, tb_unifiedGroups, properties={ 'groups': relation( Group, backref='unifiedGroup') }) However, when I tried to do groupInstance.unifiedGroup, I am getting an empty list [], while groupInstance.unifiedGroup.groups returns me an error: AttributeError: 'InstrumentedList' object has no attribute 'groups' Traceback (most recent call last): File "Mapping.py", line 119, in <module> print p.group.unifiedGroup.groups AttributeError: 'InstrumentedList' object has no attribute 'groups' What is wrong?

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  • Reset selection of wx.lib.calendar.Calendar control?

    - by Joseph
    I have a wx.lib.calendar.Calendar control (not wx.lib.calendar.CalendarCtrl!). I am selecting a number of days using the following function call: self.cal.AddSelect([days], 'green', 'white') This works, and draws the days highlighted. However, I cannot work out how to reverse this (i.e., clear the selection so the days go back to their normal colouring). Any hints, please?

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  • django url matching

    - by ben
    can anyone see why this wouldn't be working. Fairly new to django so any help would be much appreciated actual url: http://127.0.0.1:8000/2010/may/12/my-second-blog-post/ urls.py: (r'(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/(?P<slug>[-w]+)/$', 'object_detail', dict(info_dict, slug_field='slug',template_name='blog/detail.html')),

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  • How to print an Objectified Element?

    - by BeeBand
    I have xml of the format: <channel> <games> <game slot='1'> <id>Bric A Bloc</id> <title-text>BricABloc Hoorah</title-text> <link>Fruit Splat</link> </game> </games> </channel> I've parsed this xml using lxml.objectify, via: tree = objectify.parse(file) There will potentially be a number of <game>s underneath <games>. I understand that I can generate a list of <game> objects via: [ tree.games[0].game[0:4] ] My question is, what class are those objects and is there a function to print any object of whatever class these objects belong to?

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  • Get local network interface addresses using only proc?

    - by Matt Joiner
    How can I obtain the (IPv4) addresses for all network interfaces using only proc? After some extensive investigation I've discovered the following: ifconfig makes use of SIOCGIFADDR, which requires open sockets and advance knowledge of all the interface names. It also isn't documented in any manual pages on Linux. proc contains /proc/net/dev, but this is a list of interface statistics. proc contains /proc/net/if_inet6, which is exactly what I need but for IPv6. Generally interfaces are easy to find in proc, but actual addresses are very rarely used except where explicitly part of some connection. There's a system call called getifaddrs, which is very much a "magical" function you'd expect to see in Windows. It's also implemented on BSD. However it's not very text-oriented, which makes it difficult to use from non-C languages.

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  • Combine Related Resources With TastyPie

    - by Aaron Ng
    How can I combine multiple Resources in TastyPie? I have 3 models I'd like to combine: users, profiles and posts. Ideally I'd like profiles nested within user. I'm not sure where to go from here. class UserResource(ModelResource): class Meta: queryset = User.objects.all() resource_name = 'user' fields = ['username','id','date_joined'] #Improper Auth authorization = Authorization() class UserProfileResource(ModelResource): class Meta: queryset = UserProfile.objects.all() resource_name = 'profile' class UserPostResource(ModelResource): user = fields.ForeignKey(UserResource,'user', full=True) class Meta: queryset = UserPost.objects.all() resource_name = 'userpost' #Improper Auth authorization = Authorization()

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  • Changing printer preferences in Windows programmatically

    - by Andrew Alexander
    I've written a script that installs several printers for a new user. I want to change the settings on some of these so that they can print on both sides of the page. I BELIEVE this involves modifying an attribute with printui, however it might need VB script or possibly another .NET language (I'd either use VB, C# or IronPython). I can add a comment to a given printer, but how do I select preferences and modify them? Pseudocode would look like this: printui.exe /n printername /??? [how to change quality desired] OR calls to the relevant Windows API.

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  • django admin site - filtering available objects for user

    - by JPG
    I have models that belong to some 'group' (Company class). I want to add users, who will also belong to a one group and should be able to edit/manage/add objects with membership in associated group. something like: class Company() class Something() company = ForeignKey(Company) user Microsoft_admin company = ForeignKey(Company) and this user should only see and edit objects belonging to associated Company in the Admin Interface. How to acomplish that?

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  • PyQt - How to connect multiple signals to the same widget

    - by Orchainu
    [ ]All1 [ ]All2 [ ]checkbox1A [ ]checkbox1B [ ]checkbox2A [ ]checkbox2B Based on the chart above, a few things need to happen: The All checkboxes only affect the on/off of the column it resides in, and checks on/off all the checkboxes in that column. All checkboxes work in pairs, so if checkbox1A is on/off, checkbox1B needs to be on/off If an All checkbox is checked on, and then the user proceeds to check off one or more checkbox in the column, the All checkbox should be unchecked, but all the checkboxes that are already checked should remain checked. So really this is more like a chain reaction setup. If checkbox All1 is on, then chieckbox1A and 2A will be on, and because they are on, checkbox1B and 2B are also on, but checkbox All2 remains off. I tried hooking up the signals based on this logic, but only the paired logic works 100%. The All checkbox logic only works 50% of the time, and not accurately, and there's no way for me to turn off the All checkbox without turning all already checked checkboxes off. Really really need help ... T-T Sample code: cbPairKeys = cbPairs.keys() for key in cbPairKeys: cbOne = cbPairs[key][0][0] cbTwo = cbPairs[key][1][0] cbOne.stateChanged.connect(self.syncCB) cbTwo.stateChanged.connect(self.syncCB) def syncCB(self): pairKeys = cbPairs.keys() for keys in pairKeys: cbOne = cbPairs[keys][0][0] cbOneAllCB = cbPairs[keys][0][4] cbTwo = cbPairs[keys][1][0] cbTwoAllCB = cbPairs[keys][1][4] if self.sender() == cbOne: if cbOne.isChecked() or cbTwoAllCB.isChecked(): cbTwo.setChecked(True) else: cbTwo.setChecked(False) else: if cbTwo.isChecked() or cbOneAllCB.isChecked(): cbOne.setChecked(True) else: cbOne.setChecked(False) EDIT Thanks to user Avaris's help and patience, I was able to reduce the code down to something much cleaner and works 100% of the time on the 1st and 2nd desired behavior: #Connect checkbox pairs cbPairKeys = cbPairs.keys() for key in cbPairKeys: cbOne = cbPairs[key][0][0] cbTwo = cbPairs[key][1][0] cbOne.toggled.connect(cbTwo.setChecked) cbTwo.toggled.connect(cbOne.setChecked) #Connect allCB and allRO signals cbsKeys = allCBList.keys() for keys in cbsKeys: for checkbox in allCBList[keys]: keys.toggled.connect(checkbox.setChecked) Only need help on turning off the All checkbox when the user selectively turns off the modular checkboxes now

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  • re.sub emptying list

    - by jmau5
    def process_dialect_translation_rules(): # Read in lines from the text file specified in sys.argv[1], stripping away # excess whitespace and discarding comments (lines that start with '##'). f_lines = [line.strip() for line in open(sys.argv[1], 'r').readlines()] f_lines = filter(lambda line: not re.match(r'##', line), f_lines) # Remove any occurances of the pattern '\s*<=>\s*'. This leaves us with a # list of lists. Each 2nd level list has two elements: the value to be # translated from and the value to be translated to. Use the sub function # from the re module to get rid of those pesky asterisks. f_lines = [re.split(r'\s*<=>\s*', line) for line in f_lines] f_lines = [re.sub(r'"', '', elem) for elem in line for line in f_lines] This function should take the lines from a file and perform some operations on the lines, such as removing any lines that begin with ##. Another operation that I wish to perform is to remove the quotation marks around the words in the line. However, when the final line of this script runs, f_lines becomes an empty lines. What happened? Requested lines of original file: ## English-Geek Reversible Translation File #1 ## (Moderate Geek) ## Created by Todd WAreham, October 2009 "TV show" <=> "STAR TREK" "food" <=> "pizza" "drink" <=> "Red Bull" "computer" <=> "TRS 80" "girlfriend" <=> "significant other"

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  • How can this code be made more Pythonic?

    - by usethedeathstar
    This next part of code does exactly what I want it to do. dem_rows and dem_cols contain float values for a number of things i can identify in an image, but i need to get the nearest pixel for each of them, and than to make sure I only get the unique points, and no duplicates. The problem is that this code is ugly and as far as I get it, as unpythonic as it gets. If there would be a pure-numpy-solution (without for-loops) that would be even better. # next part is to make sure that we get the rounding done correctly, and than to get the integer part out of it # without the annoying floatingpoint-error, and without duplicates fielddic={} for i in range(len(dem_rows)): # here comes the ugly part: abusing the fact that i overwrite dictionary keys if I get duplicates fielddic[int(round(dem_rows[i]) + 0.1), int(round(dem_cols[i]) + 0.1)] = None # also very ugly: to make two arrays of integers out of the first and second part of the keys field_rows = numpy.zeros((len(fielddic.keys())), int) field_cols = numpy.zeros((len(fielddic.keys())), int) for i, (r, c) in enumerate(fielddic.keys()): field_rows[i] = r field_cols[i] = c

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  • How to slice a list of objects in association of the object attributes

    - by gizgok
    I have a list of fixtures.Each fixture has a home club and a away club attribute.I want to slice the list in association of its home club and away club.The sliced list should be of homeclub items and awayclub items. Easier way to implement this is to first slice a list of fixtures.Then make a new list of the corresponding Home Clubs and Away Clubs.I wanted to know if we can do this one step.

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  • Setting 0/1-to-1 relationship in SQLAlchemy?

    - by Timmy
    is there a proper way of setting up a 0/1-to-1 relationship? i want to be able to check if the related item exists without creating it: if item.relationship is None: item.relationship = item2() but it creates the insert statements on the if statement

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  • Appengine filter inequality and ordering fails

    - by davezor
    I think I'm overlooking something simple here, I can't imagine this is impossible to do. I want to filter by a datetime attribute and then order the result by a ranking integer attribute. When I try to do this: query.filter("submitted >=" thisweek).order("ranking") I get the following: BadArgumentError: First ordering property must be the same as inequality filter property, if specified for this query; received ranking, expected submitted Huh? What am I missing? Thanks.

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  • How to get these values with BeautifulSoup?

    - by Damiano
    Hello everybody, I have this html table: <table> <tr> <td class="datax">a</td> <td class="datax">b</td> <td class="datax">c</td> <td class="datax">d</td> </tr> <tr> <td class="datax">e</td> <td class="datax">f</td> <td class="datax">g</td> <td class="datax">h</td> </tr> </table> How to get the second and the fourth value of each <tr> ? If i do: bs.findAll('td', {'class':'datax'}) I get: <td class="datax">a</td> <td class="datax">b</td> <td class="datax">c</td> <td class="datax">d</td> <td class="datax">e</td> <td class="datax">f</td> <td class="datax">g</td> <td class="datax">h</td> it's correct! but I would like to have this result: <td class="datax">b</td> <td class="datax">d</td> <td class="datax">f</td> <td class="datax">h</td> so, the values I want are - b - d - f - h (the second and the forth <td> of each <tr>) Is it possible with BeautifulSoup module? Thank you very much!

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  • error in fetching url data

    - by Rahul s
    from google.appengine.ext import webapp from google.appengine.ext.webapp import util from google.appengine.ext import db from google.appengine.api import urlfetch class TrakHtml(db.Model): hawb = db.StringProperty(required=False) htmlData = db.TextProperty() class MainHandler(webapp.RequestHandler): def get(self): Traks = list() Traks.append('93332134') #Traks.append('91779831') #Traks.append('92782244') #Traks.append('38476214') for st in Traks : trak = TrakHtml() trak.hawb = st url = 'http://etracking.cevalogistics.com/eTrackResultsMulti.aspx?sv='+st result = urlfetch.fetch(url) self.response.out.write(result.read()) trak.htmlData = result.read() trak.put() result.read() is not giving whole file , it giving some portion. trak.htmlData is a textproparty() so it have to store whole file and i want that only

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  • I Made Simple Generator,, Is there any faster way ??

    - by Rami Jarrar
    Hi, i do like this: import time f = open('wl4.txt', 'w') hh = 0 ###################################### for n in range(1,5): for l in range(33,127): if n==1: b = chr(l) + '\n' f.write(b) hh += 1 elif n==2: for s0 in range(33, 127): b = chr(l) + chr(s0) + '\n' f.write(b) hh += 1 elif n==3: for s0 in range(33, 127): for s1 in range(33, 127): b = chr(l) + chr(s0) + chr(s1) + '\n' f.write(b) hh += 1 elif n==4: for s0 in range(33, 127): for s1 in range(33, 127): for s2 in range(33,127): b = chr(l) + chr(s0) + chr(s1) + chr(s2) + '\n' f.write(b) hh += 1 ###################################### print "We Made %d Words." %(hh) ###################################### f.close() So, is there any faster method to make it faster,,

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