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  • User welcome message in php

    - by user225269
    How do I create a user welcome message in php. So that the user who has been logged on will be able to see his username. I have this code, but it doesn't seem to work. <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM users WHERE Username='$username'"); while($row = mysql_fetch_array($result)) { echo $row['Username']; echo "<br />"; } ?> I'm trying to make use of the data that is inputted in this login form: <form name="form1" method="post" action="verifylogin.php"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="myusername" type="text" id="idnum" maxlength="5"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="mypassword" type="password" id="lname" maxlength="15"></td> </tr> <td align="right" width="30"><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td align="right" width="30"><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> But this, verifylogin.php, seems to be in the way. <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $myusername=$_POST['myusername']; $mypassword=$_POST['mypassword']; $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count==1){ session_register("myusername"); session_register("mypassword"); header("location:userpage.php"); } else { echo "Wrong Username or Password"; } ?> How do I do it? I always get this error when I run it: Notice: Undefined variable: username in C:\wamp\www\exp\userpage.php on line 53 Can you recommend of an easier on how I can achieve the same thing?

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  • Linq-to-XML query to select specific sub-element based on additional criteria

    - by BrianLy
    My current LINQ query and example XML are below. What I'd like to do is select the primary email address from the email-addresses element into the User.Email property. The type element under the email-address element is set to primary when this is true. There may be more than one element under the email-addresses but only one will be marked primary. What is the simplest approach to take here? Current Linq Query (User.Email is currently empty): var users = from response in xdoc.Descendants("response") where response.Element("id") != null select new User { Id = (string)response.Element("id"), Name = (string)response.Element("full-name"), Email = (string)response.Element("email-addresses"), JobTitle = (string)response.Element("job-title"), NetworkId = (string)response.Element("network-id"), Type = (string)response.Element("type") }; Example XML: <?xml version="1.0" encoding="UTF-8"?> <response> <response> <contact> <phone-numbers/> <im> <provider></provider> <username></username> </im> <email-addresses> <email-address> <type>primary</type> <address>[email protected]</address> </email-address> </email-addresses> </contact> <job-title>Account Manager</job-title> <type>user</type> <expertise nil="true"></expertise> <summary nil="true"></summary> <kids-names nil="true"></kids-names> <location nil="true"></location> <guid nil="true"></guid> <timezone>Eastern Time (US &amp; Canada)</timezone> <network-name>Domain</network-name> <full-name>Alice</full-name> <network-id>79629</network-id> <stats> <followers>2</followers> <updates>4</updates> <following>3</following> </stats> <mugshot-url> https://assets3.yammer.com/images/no_photo_small.gif</mugshot-url> <previous-companies/> <birth-date></birth-date> <name>alice</name> <web-url>https://www.yammer.com/domain.com/users/alice</web-url> <interests nil="true"></interests> <state>active</state> <external-urls/> <url>https://www.yammer.com/api/v1/users/1089943</url> <network-domains> <network-domain>domain.com</network-domain> </network-domains> <id>1089943</id> <schools/> <hire-date nil="true"></hire-date> <significant-other nil="true"></significant-other> </response> <response> <contact> <phone-numbers/> <im> <provider></provider> <username></username> </im> <email-addresses> <email-address> <type>primary</type> <address>[email protected]</address> </email-address> </email-addresses> </contact> <job-title>Office Manager</job-title> <type>user</type> <expertise nil="true"></expertise> <summary nil="true"></summary> <kids-names nil="true"></kids-names> <location nil="true"></location> <guid nil="true"></guid> <timezone>Eastern Time (US &amp; Canada)</timezone> <network-name>Domain</network-name> <full-name>Bill</full-name> <network-id>79629</network-id> <stats> <followers>3</followers> <updates>1</updates> <following>1</following> </stats> <mugshot-url> https://assets3.yammer.com/images/no_photo_small.gif</mugshot-url> <previous-companies/> <birth-date></birth-date> <name>bill</name> <web-url>https://www.yammer.com/domain.com/users/bill</web-url> <interests nil="true"></interests> <state>active</state> <external-urls/> <url>https://www.yammer.com/api/v1/users/1089920</url> <network-domains> <network-domain>domain.com</network-domain> </network-domains> <id>1089920</id> <schools/> <hire-date nil="true"></hire-date> <significant-other nil="true"></significant-other> </response> </response>

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  • phpMyAdmin 3.2.4 error #1227 - Access denied; you need the SUPER privilege for this operation

    - by CheeseConQueso
    I want to make a simple sql trigger on inserts... something like this CREATE TRIGGER filter AFTER INSERT ON table FOR EACH ROW DELETE FROM table WHERE field LIKE "%chicken%" OR field LIKE "%egg%"; After running it through phpMyAdmin 3.2.4 & MySQL 5.0.45 you get an error that says #1227 - Access denied; you need the SUPER privilege for this operation Is this syntax wrong or do I have to change something else to get past this error?

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  • Select videos using UIImagePickerController in 2G/3G

    - by Raj
    Hi, I am facing a problem where-in I cannot select videos from the photo album in iPhone 2G/3G device. The default photos application does show videos and is capable of playing them, which in turn means that UIImagePickerController should clearly be capable of showing videos in photo album and selecting them. I have coded this to determine whether the device is capable of snapping a photo, recording video, selecting photos and selecting videos: // Check if camera and video recording are available: [self setCameraAvailable:NO]; [self setVideoRecordingAvailable:NO]; [self setPhotoSelectionAvailable:NO]; [self setVideoSelectionAvailable:NO]; // For live mode: NSArray *availableTypes = [UIImagePickerController availableMediaTypesForSourceType:UIImagePickerControllerSourceTypeCamera]; NSLog(@"Available types for source as camera = %@", availableTypes); if ([UIImagePickerController isSourceTypeAvailable:UIImagePickerControllerSourceTypeCamera]) { if ([availableTypes containsObject:(NSString*)kUTTypeMovie]) [self setVideoRecordingAvailable:YES]; if ([availableTypes containsObject:(NSString*)kUTTypeImage]) [self setCameraAvailable:YES]; } // For photo library mode: availableTypes = [UIImagePickerController availableMediaTypesForSourceType:UIImagePickerControllerSourceTypePhotoLibrary]; NSLog(@"Available types for source as photo library = %@", availableTypes); if ([availableTypes containsObject:(NSString*)kUTTypeImage]) [self setPhotoSelectionAvailable:YES]; if ([availableTypes containsObject:(NSString*)kUTTypeMovie]) [self setVideoSelectionAvailable:YES]; The resulting logs for 3G device is as follows: 2010-05-03 19:09:09.623 xyz [348:207] Available types for source as camera = ( "public.image" ) 2010-05-03 19:09:09.643 xyz [348:207] Available types for source as photo library = ( "public.image" ) As the logs state, for photo library the string equivalent of kUTTypeMovie is not available and hence the UIImagePickerController does not show up (or rather throws exception if we set the source types array which includes kUTTypeMovie) the movie files in photo library. I havent tested for 3GS, but I am sure that this problem does not exist in it with reference to other threads. I have built the app for both 3.0 (base SDK) and 3.1 but with the same results. This issue is already discussed in the thread: http://www.iphonedevsdk.com/forum/iphone-sdk-development/36197-uiimagepickercontroller-does-not-show-movies-albums.html But it does not seem to host a solution. Any solutions to this problem? Thanks and Regards, Raj Pawan

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  • SQLite UPSERT - ON DUPLICATE KEY UPDATE

    - by Alix Axel
    MySQL has something like this: INSERT INTO visits (ip, hits) VALUES ('127.0.0.1', 1) ON DUPLICATE KEY UPDATE hits = hits + 1; As far as I'm know this feature doesn't exist in SQLite, what I want to know is if there is any way to archive the same effect without having to execute two queries. Also, if this is not possible, what do you prefer: SELECT + (INSERT or UPDATE) or UPDATE (+ INSERT if UPDATE fails)

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  • Sql Query - Limiting query results

    - by Gublooo
    I am quite certain we cannot use the LIMIT clause for what I want to do - so wanted to find if there are any other ways we can accomplish this. I have a table which captures which user visited which store. Every time a user visits a store, a row is inserted into this table. Some of the fields are shopping_id (primary key) store_id user_id Now what I want is - for a given set of stores, find the top 5 users who have visited the store max number of times. I can do this 1 store at a time as: select store_id,user_id,count(1) as visits from shopping where store_id = 60 group by user_id,store_id order by visits desc Limit 5 This will give me the 5 users who have visited store_id=60 the max times What I want to do is provide a list of 10 store_ids and for each store fetch the 5 users who have visited that store max times select store_id,user_id,count(1) as visits from shopping where store_id in (60,61,62,63,64,65,66) group by user_id,store_id order by visits desc Limit 5 This will not work as the Limit at the end will return only 5 rows rather than 5 rows for each store. Any ideas on how I can achieve this. I can always write a loop and pass 1 store at a time but wanted to know if there is a better way

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  • phpexcel write excel and save ?

    - by boss
    code: <?php /** PHPExcel */ require_once '../Classes/PHPExcel.php'; /** PHPExcel_IOFactory */ require_once '../Classes/PHPExcel/IOFactory.php'; // Create new PHPExcel object $objPHPExcel = new PHPExcel(); // Set properties $objPHPExcel->getProperties()->setCreator("Maarten Balliauw") ->setLastModifiedBy("Maarten Balliauw") ->setTitle("Office 2007 XLSX Test Document") ->setSubject("Office 2007 XLSX Test Document") ->setDescription("Test document for Office 2007 XLSX, generated using PHP classes.") ->setKeywords("office 2007 openxml php") ->setCategory("Test result file"); $result = 'select * from table1'; for($i=0;$i<count($result);$i++){ $result1 = 'select * from table2 where table1_id = ' . $result[$i]['table1_id']; for ($j=0;$j<count($result1);$j++) { $objPHPExcel->setActiveSheetIndex(0)->setCellValue('A' . $j, $result1[$j]['name']); } // Set active sheet index to the first sheet, so Excel opens this as the first sheet $objPHPExcel->setActiveSheetIndex(0); // Save Excel 2007 file $objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel2007'); $objWriter->save(str_replace('.php', '.xlsx', __FILE__)); // Echo done echo date('H:i:s') . " Done writing file.\r\n"; } ?> The above code executes and save n no of .xlsx files in the folder, but the problem im getting is biggest count(result1) in the for loop executing in all saved excel files. Please give me the solution.

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  • google reader like architecture

    - by islam
    dear i want to make architect for application like google reader that save users feeds(rss,atoms) in database what is the best architecture i can do to make something like this ineed to know a good db desgin if i have to save something on files (xml or something) need to archive .etc hope to find some hints

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  • mysqldump table names prefix

    - by Bogdan Gusiev
    I have two mysql databases that have almost the same structure and representing the data of the same web app but one of them represents the current version and second one was made long time ago. How can I create the database with both dumps inside but with old_ prefix for tables from the first and new_ prefix for tables from the second database? Is there any mysqldump options to setup the prefix or other solution?

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  • Disable button until tabs have ben read...

    - by jimbo
    I have some tabs which have been created using Javascript and Mootools, my client wants the 'next button' at the bottom of the page to be disabled, until the tabs have been read(clicked). The page is dynamic (created with PHP and MySQL) and there could be two tabs or three, depending on the set-up. I am struggling today to think of the best solution. Any help more than welcome...

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  • PHP5.3 is not working with MySQL5.1 IIS7 Times out

    - by Thorn007
    I have set up PHP5.3, MySQL5.1, and IIS7 on Window 7 but php doesn't want to work with MySQL. I'm assuming it is a configuration error or an incomplete install on my part. MySQL5.1 is working PHP5.3 is working, phpinfo() shows info and that i have enabled MySQL IIS is setup and using fastCgiModule to run PHP IIS registers php.ini updates port 3306 is firewall free and open to the world php.ini is configured correctly I have added c:\php to the Windows systems PATH In the past I remember moving a file, libmysql.dll, to System32 but I doesn't look like that come with php5.3.1, as the driver comes built in now http://us3.php.net/manual/en/mysqlnd.install.php. (This has been giving me so much trouble I have been documenting my findings on my blog as http://inteldesigner.com/2010/code/having-problems-getting-php5-3-to-work-with-mysql5-1 ) NEED: I need to install PHP manually, don't want to use the quick installer or an older version I need to get PHP5.3 to work with MySQL5.1 so i can install Wordpress2.9 and Drupal7a Any links or suggestion would be great, I have already done everything on the iis web site, nothing is working. I'm guessing they have not updated for new software. BUGS/SOLUTION: The solution is here: http://bugs.php.net/bug.php?id=50172 thanks go to don.raman on the iis.net forums http://forums.iis.net/p/1164911/1933894.aspx SYMPTOMS: The php function mysql_connect() in conjunction with php5.3 locks up sever and returns error 500. (IPv6 is the problem see above link) TEST CODE: <?php $con = mysql_connect("localhost","root","***"); if (!$con) { die('Could not connect: ' . mysql_error()); } // some code mysql_close($con); ?> ERRORS: From Browser: HTTP Error 500.0 - Internal Server Error C:\php\php-cgi.exe - The FastCGI process exceeded configured activity timeout When i run php -f c:\public_html\index.php from the command line i got: PHP Warning: mysql_connect(): [2002] A connection attempt failed because the co nnected party did not (trying to connect via tcp://localhost:3306) in C:\public _html\index.php on line 10 Warning: mysql_connect(): [2002] A connection attempt failed because the connect ed party did not (trying to connect via tcp://localhost:3306) in C:\public_html \index.php on line 10 PHP Warning: mysql_connect(): A connection attempt failed because the connected party did not properly respond after a period of time, or established connectio n failed because connected host has failed to respond. in C:\public_html\index.php on line 10 Warning: mysql_connect(): A connection attempt failed because the connected part y did not properly respond after a period of time, or established connection fai led because connected host has failed to respond. in C:\public_html\index.php on line 10 Could not connect: A connection attempt failed because the connected party did n ot properly respond after a period of time, or established connection failed bec ause connected host has failed to respond. C:\Users\Kevin>

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  • Convert the uploaded files to specific file format which can not download

    - by Avinash
    Hi, I have a problem regarding to prevent download and saving of uploaded files. My users can upload multiple files types like doc, pdf, ppt,etc.... This all file types are easily download if any one have url. So what is the better way to prevent the download of the file. Or i convert the uploaded files to some specific format which can not download easily (e.g flash).. I am running on php and mysql. Thanks Avinash

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  • Can't enter to webadmin in godaddy mssql

    - by gon009
    I just pay for the deluxe plan in godaddy for my website but I have a problem, I created the database in mssql and when I click to webadmin ,it redirects me to: http://mssql.myname.com/silentlogon.aspx with the message: This webpage is not available. But if I create a mysql database everything is ok, idk what I am doing wrong , I know I cant contact GoDaddy but the line is busy or when I talk to them they don't understand. Thanks four your time and help :)

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  • Use a stored procedure parameter for unit parameter of DATE_SUB

    - by Mike
    I would like to know if it's possible to pass a parameter to a mysql stored procedure and use this parameter as the unit parameter of the DATE_SUB function. It seems that the unit parameter is a reserved word so I don't know if there's a type for unit. Exemple of what I'm trying to do : DELIMITER $$ DROP PROCEDURE IF EXISTS `test` $$ CREATE DEFINER=`root`@`%` PROCEDURE `test`(param1 unit) BEGIN select DATE_SUB(now(), INTERVAL 1 param1); END $$ DELIMITER ;

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  • TXT File or Database?

    - by Ruth Rettigo
    Hey folks! What should I use in this case (Apache + PHP)? Database or just a TXT file? My priority #1 is speed. Operations Adding new items Reading items Max. 1 000 records Thank you. Database (MySQL) +----------+-----+ | Name | Age | +----------+-----+ | Joshua | 32 | | Thomas | 21 | | James | 34 | | Daniel | 12 | +----------+-----+ TXT file Joshua 32 Thomas 21 James 34 Daniel 12

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  • What ORMs work in medium trust?

    - by rcravens
    Environment: C#, MySql, GoDaddy Shared Hosting (medium trust). Assuming the above environment, what ORMs will work in a medium trust environment? Also consider the following features: minimal code changes to the ORM library. minimal disabling of features to run in medium trust. Bonus feature: fluent interface There are a lot of ORMs to choose from. What would your selection be?

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  • Automatically backing up a file to another server?

    - by codemonkey613
    I have a backup created of my mysql database (vbulletin forum v3.8) everyday. It's about 360mb in size. It's stored as one text file in a secure folder. I'm thinking of getting another server, through a different host, and somehow automatically transferring the backup to my second server every day. Any ideas on how I could automate this process? I'm thinking PHP and a cron job.

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  • Ruby on Rails has_one Model Not Supplying ID Column

    - by Metric Scantlings
    I have a legacy rails (version 1.2.3) app which runs without issue on a number of servers (not to mention my local environment). Deployed to its newest server, though, and I now get ActiveRecord::StatementInvalid: Mysql::Error: #23000Column 'video_id' cannot be null errors. Below are the models/relationships, simplified: class Video < ActiveRecord::Base has_one(:user, :dependent => :destroy) end class User < ActiveRecord::Base belongs_to(:video) end And below is a rails console transcript of the relationships failing: >> video = Video.create(:title => 'New Video') => #<Video:0xb6d5e31c>... >> video.id => 5 >> video.user = User.create(:name => 'Tester') ActiveRecord::StatementInvalid: Mysql::Error: #23000Column 'video_id' cannot be null: INSERT INTO users (`name`, `video_id`) VALUES('Tester', NULL) from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/connection_adapters/abstract_adapter.rb:128:in `log' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/connection_adapters/mysql_adapter.rb:243:in `execute' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/connection_adapters/mysql_adapter.rb:253:in `insert' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/base.rb:1811:in `create_without_callbacks' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/callbacks.rb:254:in `create_without_timestamps' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/timestamp.rb:39:in `create' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/base.rb:1789:in `create_or_update_without_callbacks' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/callbacks.rb:242:in `create_or_update' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/base.rb:1545:in `save_without_validation' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/validations.rb:752:in `save_without_transactions' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/transactions.rb:129:in `save' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/connection_adapters/abstract/database_statements.rb:59:in `transaction' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/transactions.rb:95:in `transaction' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/transactions.rb:121:in `transaction' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/transactions.rb:129:in `save' from /usr/lib/ruby/gems/1.8/gems/activerecord-1.15.3/lib/active_record/base.rb:451:in `create' from (irb):3 from :0 Has anyone else come across ActiveRecord not sending an ID when it clearly knows it?

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  • Using Hibernate's ScrollableResults to slowly read 90 million records

    - by at
    I simply need to read each row in a table in my MySQL database using Hibernate and write a file based on it. But there are 90 million rows and they are pretty big. So it seemed like the following would be appropriate: ScrollableResults results = session.createQuery("SELECT person FROM Person person") .setReadOnly(true).setCacheable(false).scroll(ScrollMode.FORWARD_ONLY); while (results.next()) storeInFile(results.get()[0]); The problem is the above will try and load all 90 million rows into RAM before moving on to the while loop... and that will kill my memory with OutOfMemoryError: Java heap space exceptions :(. So I guess ScrollableResults isn't what I was looking for? What is the proper way to handle this? I don't mind if this while loop takes days (well I'd love it to not). I guess the only other way to handle this is to use setFirstResult and setMaxResults to iterate through the results and just use regular Hibernate results instead of ScrollableResults. That feels like it will be inefficient though and will start taking a ridiculously long time when I'm calling setFirstResult on the 89 millionth row... UPDATE: setFirstResult/setMaxResults doesn't work, it turns out to take an unusably long time to get to the offsets like I feared. There must be a solution here! Isn't this a pretty standard procedure?? I'm willing to forgo Hibernate and use JDBC or whatever it takes. UPDATE 2: the solution I've come up with which works ok, not great, is basically of the form: select * from person where id > <offset> and <other_conditions> limit 1 Since I have other conditions, even all in an index, it's still not as fast as I'd like it to be... so still open for other suggestions..

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  • Complex Query with Sphinx

    - by maSnun
    I am using -- http://sphinxsearch.com/ . Its working fine for me except one problem. I need to exclude some entries where a specific field doesn't contain a word. Something that would look like this in mysql: Select * from table where yescolumn = 'query' and othercolumn not like '%keyword%' Please help. Thanks.

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  • Createing a new Index in SQL when current records don't meet that index

    - by Jonathan
    Hey all- I'd like to add an index to a table that already contains data. I know that there a few records currently in the table that are not unique with this new index. Clearly, MySQL won't let me add the index until all of them are. I need a query to identify the rows which currently have the same index. I can then delete or modify these rows as necessary. The new index contains 6 fields. Thanks- Jonathan

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  • Many-to-many relations in RDBMS databases

    - by Industrial
    What is the best way of handling many-to-many relations in a RDBMS database like mySQL? Have tried using a pivot table to keep track of the relationships, but it leads to either one of the following: Normalization gets left behind Columns that is empty or null What approach have you taken in order to support many-to-many relationships?

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