Search Results

Search found 16680 results on 668 pages for 'python datetime'.

Page 397/668 | < Previous Page | 393 394 395 396 397 398 399 400 401 402 403 404  | Next Page >

  • Sort a list of tuples without case sensitivity

    - by dound
    How can I efficiently and easily sort a list of tuples without being sensitive to case? For example this: [('a', 'c'), ('A', 'b'), ('a', 'a'), ('a', 5)] Should look like this once sorted: [('a', 5), ('a', 'a'), ('A', 'b'), ('a', 'c')] The regular lexicographic sort will put 'A' before 'a' and yield this: [('A', 'b'), ('a', 5), ('a', 'a'), ('a', 'c')]

    Read the article

  • How do I call setattr() on the current module?

    - by Matt Joiner
    What do I pass as the first parameter "object" to the function setattr(object, name, value), to set variables on the current module? For example: setattr(object, "SOME_CONSTANT", 42); giving the same effect as: SOME_CONSTANT = 42 within the module containing these lines (with the correct object). I'm generate several values at the module level dynamically, and as I can't define __getattr__ at the module level, this is my fallback.

    Read the article

  • How to turn a list of tuples into a string?

    - by matt
    I have a list of tuples that I'm trying to incorporate into a SQL query but I can't figure out how to join them together without adding slashes. My like this: list = [('val', 'val'), ('val', 'val'), ('val', 'val')] If I turn each tuple into a string and try to join them with a a comma I'll get something like ' (\'val\, \'val\'), ... ' What's the right way to do this, so I can get the list (without brackets) as a string?

    Read the article

  • How do I store multiple copies of the same field in Django?

    - by Alistair
    I'm storing OLAC metadata which describes linguistic resources. Many of the elements of the metadata are repeatable -- for example, a resource can have two languages, three authors and four dates associated with it. Is there any way of storing this in one model? It seems like overkill to define a model for each repeatable metadata element -- especially since the models will only have one field: it's value.

    Read the article

  • Error -3 while decompressing data: incorrect header check

    - by Rahul99
    I have .zip file which contain csv data. I am reading .zip file using <input type = "file" name = "select_file"/> I want to decompress that .zip file and read csv data. file_data = self.request.get('select_file') file_str = zlib.decompress(file_data) #file_data_list = file_str.split('\n') #file_Reader = csv.reader(file_data_list,quoting=csv.QUOTE_NONE ) I am expecting csv data in file_str but I am getting error. error :: Error -3 while decompressing data: incorrect header check What I have to use?

    Read the article

  • how to import a.py not a folder

    - by zjm1126
    zjm_code |-----a.py |-----a |----- __init__.py |-----b.py in a.py is : c='ccc' in b.py is : import a print dir(a) when i execute b.py ,it show (it import 'a' folder): ['__builtins__', '__doc__', '__file__', '__name__', '__path__'] and when i delete a folder, it show ,(it import a.py): ['__builtins__', '__doc__', '__file__', '__name__', 'c'] so my question is : how to import a.py via not delete a folder thanks

    Read the article

  • Sending data from one Protocol to another Protocol in Twisted?

    - by veb
    Hi! One of my protocols is connected to a server, and with the output of that I'd like to send it to the other protocol. I need to access the 'msg' method in ClassA from ClassB but I keep getting: exceptions.AttributeError: 'NoneType' object has no attribute 'write' Actual code: http://pastebin.com/MQPhduSY Any ideas please? :-)

    Read the article

  • How can I detect whether an image is a PNG or APNG format?

    - by perlit
    APNG is backwards compatible with PNG. I opened up an apng and png file in a hex editor and the first few bytes look identical. So if a user uploads either of these formats, how do I detect what the format really is? I've seen this done on some sites that block apng. I'm guessing the ImageMagick library makes this easy, but what if I were to do the detect without the use of an image processing library (for learning purposes)? Can I look for specific bytes that tell me if the file is apng? Solutions in any language is welcome.

    Read the article

  • Execute function without sending 'self' to it

    - by Sergey
    Is that possible to define a function without referencing to self this way? def myfunc(var_a,var_b) But so that it could also get sender data, like if I defined it like this: def myfunc(self, var_a,var_b) That self is always the same so it looks a little redundant here always to run a function this way: myfunc(self,'data_a','data_b'). Then I would like to get its data in the function like this sender.fields. UPDATE: Here is some code to understand better what I mean. The class below is used to show a page based on Jinja2 templates engine for users to sign up. class SignupHandler(webapp.RequestHandler): def get(self, *args, **kwargs): utils.render_template(self, 'signup.html') And this code below is a render_template that I created as wrapper to Jinja2 functions to use it more conveniently in my project: def render_template(response, template_name, vars=dict(), is_string=False): template_dirs = [os.path.join(root(), 'templates')] logging.info(template_dirs[0]) env = Environment(loader=FileSystemLoader(template_dirs)) try: template = env.get_template(template_name) except TemplateNotFound: raise TemplateNotFound(template_name) content = template.render(vars) if is_string: return content else: response.response.out.write(content) As I use this function render_template very often in my project and usually the same way, just with different template files, I wondered if there was a way to get rid of having to call it like I do it now, with self as the first argument but still having access to that object.

    Read the article

  • django newbie question : cant start a new project

    - by Moayyad Yaghi
    hello . I'm totally new to django . and I'm using its documentation to get help on how to use it but seems like something is missing. i installed django using setup.py install command and i added the ( django/bin ) to system path variable but. i still cant start a new project i use the following syntax to start a project : django-admin.py startproject myNewProject but it says Type 'django-admin.py help' for usage. 1 do i miss anything ? thank u

    Read the article

  • Scrapy Not Returning Additonal Info from Scraped Link in Item via Request Callback

    - by zoonosis
    Basically the code below scrapes the first 5 items of a table. One of the fields is another href and clicking on that href provides more info which I want to collect and add to the original item. So parse is supposed to pass the semi populated item to parse_next_page which then scrapes the next bit and should return the completed item back to parse Running the code below only returns the info collected in parse If I change the return items to return request I get a completed item with all 3 "things" but I only get 1 of the rows, not all 5. Im sure its something simple, I just can't see it. class ThingSpider(BaseSpider): name = "thing" allowed_domains = ["somepage.com"] start_urls = [ "http://www.somepage.com" ] def parse(self, response): hxs = HtmlXPathSelector(response) items = [] for x in range (1,6): item = ScrapyItem() str_selector = '//tr[@name="row{0}"]'.format(x) item['thing1'] = hxs.select(str_selector")]/a/text()').extract() item['thing2'] = hxs.select(str_selector")]/a/@href').extract() print 'hello' request = Request("www.nextpage.com", callback=self.parse_next_page,meta={'item':item}) print 'hello2' request.meta['item'] = item items.append(item) return items def parse_next_page(self, response): print 'stuff' hxs = HtmlXPathSelector(response) item = response.meta['item'] item['thing3'] = hxs.select('//div/ul/li[1]/span[2]/text()').extract() return item

    Read the article

  • Convert args to flat list?

    - by Mark
    I know this is very similar to a few other questions, but I can't quite get this function to work correctly. def flatten(*args): return list(item for iterable in args for item in iterable) The output I'm looking for is: flatten(1) -> [1] flatten(1,[2]) -> [1, 2] flatten([1,[2]]) -> [1, 2] The current function, which I from another SO answer doesn't seem to produce correct results at all: >>> flatten([1,[2]]) [1, [2]] I wrote the following function which seems to work for 0 or 1 levels of nesting, but not deeper: def flatten(*args): output = [] for arg in args: if hasattr(arg, '__iter__'): output += arg else: output += [arg] return output

    Read the article

  • Matplotlib: plotting discrete values

    - by Arkapravo
    I am trying to plot the following ! from numpy import * from pylab import * import random for x in range(1,500): y = random.randint(1,25000) print(x,y) plot(x,y) show() However, I keep getting a blank graph (?). Just to make sure that the program logic is correct I added the code print(x,y), just the confirm that (x,y) pairs are being generated. (x,y) pairs are being generated, but there is no plot, I keep getting a blank graph. Any help ?

    Read the article

  • Why is win32com so much slower than xlrd?

    - by Josh
    I have the same code, written using win32com and xlrd. xlrd preforms the algorithm in less than a second, while win32com takes minutes. Here is the win32com: def makeDict(ws): """makes dict with key as header name, value as tuple of column begin and column end (inclusive)""" wsHeaders = {} # key is header name, value is column begin and end inclusive for cnum in xrange(9, find_last_col(ws)): if ws.Cells(7, cnum).Value: wsHeaders[str(ws.Cells(7, cnum).Value)] = (cnum, find_last_col(ws)) for cend in xrange(cnum + 1, find_last_col(ws)): #finds end column if ws.Cells(7, cend).Value: wsHeaders[str(ws.Cells(7, cnum).Value)] = (cnum, cend - 1) break return wsHeaders And the xlrd def makeDict(ws): """makes dict with key as header name, value as tuple of column begin and column end (inclusive)""" wsHeaders = {} # key is header name, value is column begin and end inclusive for cnum in xrange(8, ws.ncols): if ws.cell_value(6, cnum): wsHeaders[str(ws.cell_value(6, cnum))] = (cnum, ws.ncols) for cend in xrange(cnum + 1, ws.ncols):#finds end column if ws.cell_value(6, cend): wsHeaders[str(ws.cell_value(6, cnum))] = (cnum, cend - 1) break return wsHeaders

    Read the article

  • The dictionary need to add every word in SpellingMistakes and the line number but it only adds the l

    - by Will Boomsight
    modules import sys import string Importing and reading the files form the Command Prompt Document = open(sys.argv[1],"r") Document = open('Wc.txt', 'r') Document = Document.read().lower() Dictionary = open(sys.argv[2],"r") Dictionary = open('Dict.txt', 'r') Dictionary = Dictionary.read() def Format(Infile): for ch in string.punctuation: Infile = Infile.replace(ch, "") for no in string.digits: Infile = Infile.replace(no, " ") Infile = Infile.lower() return(Infile) def Corrections(Infile, DictWords): Misspelled = set([]) Infile = Infile.split() DictWords = DictWords.splitlines() for word in Infile: if word not in DictWords: Misspelled.add(word) Misspelled = sorted(Misspelled) return (Misspelled) def Linecheck(Infile,ErrorWords): Infile = Infile.split() lineno = 0 Noset = list() for line in Infile: lineno += 1 line = line.split() for word in line: if word == ErrorWords: Noset.append(lineno) sorted(Noset) return(Noset) def addkey(error,linenum): Nodict = {} for line in linenum: Nodict.setdefault(error,[]).append(linenum) return Nodict FormatDoc = Format(Document) SpellingMistakes = Corrections(FormatDoc,Dictionary) alp = str(SpellingMistakes) for word in SpellingMistakes: nSet = str(Linecheck(FormatDoc,word)) nSet = nSet.split() linelist = addkey(word, nSet) print(linelist) # # for word in Nodict.keys(): # Nodict[word].append(line) Prints each incorrect word on a new line

    Read the article

  • Find subset with K elements that are closest to eachother

    - by Nima
    Given an array of integers size N, how can you efficiently find a subset of size K with elements that are closest to each other? Let the closeness for a subset (x1,x2,x3,..xk) be defined as: 2 <= N <= 10^5 2 <= K <= N constraints: Array may contain duplicates and is not guaranteed to be sorted. My brute force solution is very slow for large N, and it doesn't check if there's more than 1 solution: N = input() K = input() assert 2 <= N <= 10**5 assert 2 <= K <= N a = [] for i in xrange(0, N): a.append(input()) a.sort() minimum = sys.maxint startindex = 0 for i in xrange(0,N-K+1): last = i + K tmp = 0 for j in xrange(i, last): for l in xrange(j+1, last): tmp += abs(a[j]-a[l]) if(tmp > minimum): break if(tmp < minimum): minimum = tmp startindex = i #end index = startindex + K? Examples: N = 7 K = 3 array = [10,100,300,200,1000,20,30] result = [10,20,30] N = 10 K = 4 array = [1,2,3,4,10,20,30,40,100,200] result = [1,2,3,4]

    Read the article

< Previous Page | 393 394 395 396 397 398 399 400 401 402 403 404  | Next Page >