Search Results

Search found 15838 results on 634 pages for 'android layout'.

Page 398/634 | < Previous Page | 394 395 396 397 398 399 400 401 402 403 404 405  | Next Page >

  • Cursor while loop returning every value but the last

    - by LordSnoutimus
    Hello, I am using a while loop to iterate through a cursor and then outputing the longitude and latitude values of every point within the database. For some reason it is not returning the last (or first depending on if I use Cursor.MoveToLast) set of longitude and latitude values in the cursor. Here is my code: public void loadTrack() { SQLiteDatabase db1 = waypoints.getWritableDatabase(); Cursor trackCursor = db1.query(TABLE_NAME, FROM, "trackidfk=1", null, null, null,ORDER_BY); trackCursor.moveToFirst(); while (trackCursor.moveToNext()) { Double lat = trackCursor.getDouble(2); Double lon = trackCursor.getDouble(1); //overlay.addGeoPoint( new GeoPoint( (int)(lat*1E6), (int)(lon*1E6))); System.out.println(lon); System.out.println(lat); } } From this I am getting: 04-02 15:39:07.416: INFO/System.out(10551): 3.0 04-02 15:39:07.416: INFO/System.out(10551): 5.0 04-02 15:39:07.416: INFO/System.out(10551): 4.0 04-02 15:39:07.416: INFO/System.out(10551): 5.0 04-02 15:39:07.416: INFO/System.out(10551): 5.0 04-02 15:39:07.416: INFO/System.out(10551): 5.0 04-02 15:39:07.416: INFO/System.out(10551): 4.0 04-02 15:39:07.416: INFO/System.out(10551): 4.0 04-02 15:39:07.416: INFO/System.out(10551): 3.0 04-02 15:39:07.416: INFO/System.out(10551): 3.0 04-02 15:39:07.416: INFO/System.out(10551): 2.0 04-02 15:39:07.416: INFO/System.out(10551): 2.0 04-02 15:39:07.493: INFO/System.out(10551): 1.0 04-02 15:39:07.493: INFO/System.out(10551): 1.0 7 Sets of values, where I should be getting 8 sets. Thanks.

    Read the article

  • identifying id of listitem for contextmenu

    - by martinjd
    I have a View that extends Activity. A ListView will display a number of listitems. When the user long clicks I would like to present them with a contextmenu allowing them to select edit, delete etc... and then identify the listitem that was selected as the item to perform the action on. In onCreate I have: listView.setAdapter(adapter); listView.setOnItemClickListener(onListClick); listView.setOnItemLongClickListener(onListLongClick); registerForContextMenu(listView); I have a method onCreateContextMenu @Override public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) { super.onCreateContextMenu(menu, v, menuInfo); menu.setHeaderTitle("Context Menu"); menu.add(0, v.getId(), 0, "Edit"); menu.add(0, v.getId(), 0, "Delete"); } and also onContextItemSelected @Override public boolean onContextItemSelected(MenuItem item) { if (item.getTitle() == "Edit") { // edit action } else if (item.getTitle() == "Delete") { // delete action } else { return false; } return true; } I am not sure where to go from here to get the correct row/listitem.

    Read the article

  • How to establish a two-way communication between Activity and Service in different process?

    - by steff
    Hi everyone, I'm working on establishing a two-way communication between an Activity and a Service which runs in a different process. Querying the process from the Activity is no big deal. But I want the process to notify the Activity on events. The idea behind it is this: the service runs independently from the actual app. It queries a webserver periodically. If a new task is found on the webserver the process should notify the activity. I found this thread over at AndDev.org but it doesn't seem to work for me. I've been messing around with BroadcastReceiver. I've implemented an interface which should notify the Activity but the problem is that the listener is always null since the Broadcast from the process is done via Intent, hence the class that extends BroadcastReceiver will be newly instantiated. How can I establish a 2-way communication? This has to be possible. Thanks for any help, steff

    Read the article

  • T-Mobile G1 (MSM7200) GPU Memory

    - by Reflog
    Hello. I'm trying to find some information regarding the available GPU (for OpenGL) memory on the T-Mobile G1. This phone has a MSM7200 Qualcomm chip inside with ATI Imageon GPU. Unfortunately I am not able to dig any info regarding the specifics of GPU memory usage. How much memory is available in total for the textures? Is the memory shared with the CPU memory? Thanks in advance, Eli

    Read the article

  • Animating View.scrollTo(...)

    - by alex
    How to implement scrolling animation? I'm ok with setting a simple AlphaAnimation that triggers at scrollTo(...) but what kind of animation is required for one screen to replace another in a sophisticated manner?

    Read the article

  • TabHost remove all content activities

    - by tiex
    I have a code for populating content for tabs dynamically. First time it works ok, but when I want to replace tabs (and their content) with new content - tabs are changed but tabs' contents are not, how can I clear completely whole TabHost and replace with other content? TabHost tabHost = getTabHost(); Intent intent; TabHost.TabSpec spec; tabHost.setCurrentTab(0); tabHost.clearAllTabs(); int idx = 0; for(Group g: c.getGroups()){ intent = new Intent().setClass(this, GroupActivity.class); ItemLookup.createForGroup(idx).putToIntent(intent); spec = tabHost .newTabSpec("tab"+idx) .setIndicator(g.getTitle()) .setContent(intent); tabHost.addTab(spec); idx++; } tabHost.setCurrentTab(0);

    Read the article

  • Enable mobile network

    - by Sebi
    In my application it is necessary to have internet connection. Therefore i check while starting if a Internet connection is availaible. If not I ask the user if he would establish an Internet Connection, and what type (wifi oder mobile). The wifi connection i can establish with the following code WifiManager wifiManager = (WifiManager) getSystemService(Context.WIFI_SERVICE); wifiManager.setWifiEnabled(true); But how do i establish a mobile connection? Coulnd't find a single code snippet at Google.

    Read the article

  • HttpURLConnection: What's the deal with having to read the whole response?

    - by stormin986
    My current problem is very similar to this one. I have a downloadFile(URL) function that creates a new HttpURLConnection, opens it, reads it, returns the results. When I call this function on the same URL multiple times, the second time around it almost always returns a response code of -1 (But throws no exception!!!). The top answer in that question is very helpful, but there are a few things I'm trying to understand. So, if setting http.keepAlive to false solves the problem, it indicates what exactly? That the server is responding in a way that violates the http protocol? Or more likely, my code is violating the protocol in some way? What will the trace tell me? What should I look for? And what's the deal with this: You need to read everything from error stream. Otherwise, it's going to confuse next connection and that's the cause of -1. Does this mean if the response is some type of error (which would be what response code(s)?), the stream HAS to be fully read? Also, every time I am attempting an http request I am basically creating a new connection, and then disconnect()ing it at the end. However, in my case I'm not getting a 401 or whatever. It's always a 200. But my second connection almost always fails. Does this mean there's some other data I should be reading that I'm not (in a similar manner that the error stream must be fully read)? Please help shed some light on this? I feel like there's some fundamental http protocol understanding I'm missing.

    Read the article

  • TabWidget white foreground color?

    - by Kurian
    I don't know what I did but for a period of time my TabWidget had white colored tabs which looked really nice. I never set a theme or background/foreground color in my project at all. The next time I compiled it it reverted back to the gray tabs. My application is using the default dark theme. Even if I set the application theme to light, the tabs are still gray. So obviously it was something else that changed the tabs' color. Anyone know how to do this?

    Read the article

  • ListView and undeterminate ProgressBar

    - by Spredzy
    Sorry for the question it might sounds stupid, But: how do you activate a ProgressBar according to the cell you just cliked on ? I have a list view, with a menu that shows after a long press. When I click on one of my option I would like to display the ProgressBar in the listView according to the cell I clicked on. It is currently always displaying the one of my first cell, whatever I am doing public boolean onContextItemSelected(MenuItem item) { AdapterContextMenuInfo info = (AdapterContextMenuInfo) item.getMenuInfo(); switch (item.getOrder()) { case 0: mProgressBar = (ProgressBar)findViewById(R.id.welcome_progressbar); mProgressBar.setVisibility(View.VISIBLE); ... some execution .... return true; case 1: ... Does anyone see anything wrong?

    Read the article

  • CheckBox checked state in a ListView

    - by anselmophil
    I'm using a ListView with CheckBox, but as most of you know, when you roll down the scroll, a checked CheckBox gets unchecked as you roll up back the scroll. So i've been reading and i found out that you can pass (using getView) the id of the CB to the position parameter of getView to save the CheckBox state! But i can't use getView with SimpleCursorAdapter, can i? Because i'm using bindView! Thanks

    Read the article

  • How to keep the session of user login?

    - by YaW
    Hi, I have an app that requires user to register. I've got the app conected to PHP in my server to do the logic of register/login and so, this is not problem at all. But, I want to keep a session of the user in local, so the user doesn't have to login again every time he runs the app. So, I want something like this: First time user, he opens the app, register and login. Do some stuff with the app and closes it. Open the app again, the user is recognized so he doesn't need to login again. I only need to store an ID and a Username (both fetched from the DB in the login php method). What's the best way to do this?? I've thought about doing a custom preference, store the data in files or even a local DB (sqlite). Any suggestions?

    Read the article

  • How to get the result for return statement from JSON parsing?

    - by blankon91
    I've follow the code for parsing the value with JSON from here, but I get the problem in my return statement. I want to put the parsing result into my return statement. How to do that? Here is my code: public String MASUK(String user, String password) { SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME); PropertyInfo pi = new PropertyInfo(); pi.setName("ccduser"); pi.setValue(user); pi.setType(String.class); request.addProperty(pi); PropertyInfo pi2 = new PropertyInfo(); pi2.setName("password"); pi2.setValue(password); pi2.setType(String.class); request.addProperty(pi2); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.dotNet = true; envelope.setOutputSoapObject(request); HttpTransportSE httpTransport = new HttpTransportSE(SOAP_ADDRESS); try { httpTransport.call(SOAP_ACTION, envelope); SoapObject resultSOAP = (SoapObject) envelope.bodyIn; /* gets our result in JSON String */ String ResultObject = resultSOAP.getProperty(0).toString(); resultSOAP = (SoapObject) envelope.bodyIn; ResultObject = resultSOAP.getProperty(0).toString(); if (ResultObject.startsWith("{")) { // if JSON string is an object JSONObj = new JSONObject(ResultObject); Iterator<String> itr = JSONObj.keys(); while (itr.hasNext()) { String Key = (String) itr.next(); String Value = JSONObj.getString(Key); BundleResult.putString(Key, Value); // System.out.println(bundleResult.getString(Key)); } } else if (ResultObject.startsWith("[")) { // if JSON string is an array JSONArr = new JSONArray(ResultObject); System.out.println("length" + JSONArr.length()); for (int i = 0; i < JSONArr.length(); i++) { JSONObj = (JSONObject) JSONArr.get(i); BundleResult.putString(String.valueOf(i), JSONObj.toString()); // System.out.println(bundleResult.getString(i)); } } } catch (Exception exception) { } return null; }

    Read the article

  • ExpandableListView context menu

    - by Aleksander O
    I'm trying to add a context menu to my ExpandableListView. I've implemented onCreateContextMenu() and onContextItemSelected() but if I hold my finger on a menu item context menu doesn't appear. What's my mistake? Thanks, Aleksander

    Read the article

  • How to use Web-View as page by page while scrolling or Flinging/swiping?

    - by Jetti
    Hi, I want to convert an .docx/.doc file to html and displaying in emulator with help of Web- view. But i am displaying entire data into webview as Single page(we need to scroll many times). So, i want to match the content of .docx file with webview as pages or put some buttons or gestures to get next page.But i unable to display text as pages in Web-View. is there any solution or suggestion to get as pages? How to get the height and width of webview? Thanks

    Read the article

  • Simplest Way to Process Basic HTTPS GET File Requests?

    - by stormin986
    All I need to do is download some basic text-based and image files from a web server that has a self-signed SSL certificate. I have been trying to figure out how to use HttpClient to do this, but getting the SSL to work is a nightmare that seems to be way too much trouble for such a simple task. Is there a better way to perform these file downloads? Perhaps through a WebView or Browser feature? Reinventing the wheel of making a simple HTTPS GET request is a major pain, and is significantly holding up my development schedule.

    Read the article

  • How to Identify a ListViewItem to Update a Single Row

    - by tunneling
    I have a ListView displays information about an object. When I click a ListView Item, I open an Activity that let's me manipulate parameters of the object held in the adapter. These parameters are updated and stored remotely. When I return to the ListView (via the back button), I want to update the ListView Item that I clicked originally by requesting the parameter values from the remote server. I am currently doing this up updating the entire ListView by clearing it and rebuilding it. How do I reference the ListView Item so that I can update the data for that item only? Thanks, Jason

    Read the article

  • How to send a JSONObject to a REST service?

    - by Sebi
    Retrieving data from the REST Server works well, but if I want to post an object it doesn't work: public static void postJSONObject(int store_type, FavoriteItem favorite, String token, String objectName) { String url = ""; switch(store_type) { case STORE_PROJECT: url = URL_STORE_PROJECT_PART1 + token + URL_STORE_PROJECT_PART2; //data = favorite.getAsJSONObject(); break; } HttpClient httpClient = new DefaultHttpClient(); HttpPost postMethod = new HttpPost(url); try { HttpEntity entity = new StringEntity("{\"ID\":0,\"Name\":\"Mein Projekt10\"}"); postMethod.setEntity(entity); HttpResponse response = httpClient.execute(postMethod); Log.i("JSONStore", "Post request, to URL: " + url); System.out.println("Status code: " + response.getStatusLine().getStatusCode()); } catch (ClientProtocolException e) { I always get a 400 Error Code. Does anybody know whats wrong? I have working C# code, but I can't convert: System.Net.WebRequest wr = System.Net.HttpWebRequest.Create("http://localhost:51273/WSUser.svc/pak3omxtEuLrzHSUSbQP/project"); wr.Method = "POST"; string data = "{\"ID\":1,\"Name\":\"Mein Projekt\"}"; byte [] d = UTF8Encoding.UTF8.GetBytes(data); wr.ContentLength = d.Length; wr.ContentType = "application/json"; wr.GetRequestStream().Write(d, 0, d.Length); System.Net.WebResponse wresp = wr.GetResponse(); System.IO.StreamReader sr = new System.IO.StreamReader(wresp.GetResponseStream()); string line = sr.ReadToEnd();

    Read the article

  • Add Dynamic ListView Row

    - by soclose
    Hi, I could intercept ContentObserver changes at any time. In these time, I'd like to add a dynamic listview row with or without opening my application but i don't know how to implement it. Please share me some hints. Thank you.

    Read the article

< Previous Page | 394 395 396 397 398 399 400 401 402 403 404 405  | Next Page >