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  • detection of 'flush tables with read lock' in php

    - by theduke0
    I would like to know from my application if a myisam table can accept writes (i.e. not locked). If an exception is thrown, everything is fine as I can catch this and log the failed statement to a file. However, if a 'flush tables with read lock' command has been issued (possibly for backup), the query I send will pretty much hang out forever. If one table is locked at a time, insert delayed works well. But when this global lock is applied, my query just waits. The query I run is an insert statement. If this statement fails or hangs, user experience is degraded. I need a way to send the query to the server and forget about it (pretty much). Does anyone have any suggestions on how to deal with this? -set a query timeout? -run asyncronous request and allow for the lock to expire while application continues? -fork my php process? Please let me know if I can provide and clarification or details.

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  • Comparing date range quarters sql server

    - by CR41G14
    I have a policies in a system PolRef Start End POL123 22/11/2012 23/12/2014 POL212 24/09/2012 23/10/2012 POL214 23/08/2012 29/09/2012 I am asking a user for a reporting date, the user enters 24/10/2012 this becomes @StartDate From this I derive what the quarter is by the month: set @currentMonth = Month(@StartDate) if @currentMonth = 1 or @currentMonth = 2 or @currentMonth = 3 begin set @startmonth = 1 set @endmonth = 3 end if @currentMonth = 4 or @currentMonth = 5 or @currentMonth = 6 begin set @startmonth = 4 set @endmonth = 6 end if @currentMonth = 7 or @currentMonth = 8 or @currentMonth = 9 begin set @startmonth = 7 set @endmonth = 9 end if @currentMonth = 10 or @currentMonth = 11 or @currentMonth = 12 begin set @startmonth = 10 set @endmonth = 12 end I then get a date range: @quarterStartDate = CAST(CAST(YEAR(@StartDate) AS varchar) + '-' + CAST(@startMonth AS varchar) + '-' + '01') AS Date) @quarterEndDate = CAST(CAST(YEAR(@EcdDate) AS varchar) + '-' + CAST(@endMonth AS varchar) + '-' + '31') AS Date) This will give me 01-10-2012 and 31-12-2012. Basically I need a script to only bring back the policies that are in this quarter. The policy doesn't have to span the entire quarter date range, just exist in the quarter date range. The results expected would be PolRef Start End POL123 22/11/2012 23/12/2014 POL212 24/09/2012 23/10/2012 Pol123 appears because it spans over the quarterly date range. Pol212 is there because it expires in that quarter date range. Pol214 does not appear because it neither spans, expires or starts in this quarter. Any help would be greatly appreciated

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  • PHP & HTML Purifier Error: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given

    - by TaG
    I'm trying to Integrate HTML Purifier http://htmlpurifier.org/ to filter my user submitted data but I get the following error below. And I was wondering how can I fix this problem? I get the following error. on line 22: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given line 22 is. if (mysqli_num_rows($dbc) == 0) { Here is the php code. if (isset($_POST['submitted'])) { // Handle the form. require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['about_me'])); $interests = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['interests'])); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } }

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  • 3 small PHP errors I cannot decipher

    - by Dave
    *Notice: Use of undefined constant _ - assumed '_' in /.../uploader.php on line 45* Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Notice: Undefined index: approve in /.../uploader.php on line 81 Line 81 - the second last line here $query = sprintf("INSERT INTO `$db_name`.`the_table` (`id` , `name` , `photo` , `email` , `date` , `code` , `subscribe` , `approve` , `created` ) VALUES ( NULL , '%s', '%s', '%s', '%s', '%s', '%s', '1', CURRENT_TIMESTAMP );", mysql_real_escape_string($_POST['name']), mysql_real_escape_string($newname), mysql_real_escape_string($_POST['email']), mysql_real_escape_string($date), mysql_real_escape_string($_POST['code']), mysql_real_escape_string($subscribe), mysql_real_escape_string($_POST['approve']) ); Warning: Cannot modify header information - headers already sent by (output started at /.../uploader.php:45) in/.../uploader.php on line 102 Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Line 102 - the third line here if ($success == 'Done') { $page = 'uploader'; header('Location: ./thanks.php'); } else { echo "error"; }

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  • User's Post count from specific category [Wordpress]

    - by morningglory
    Hello, I want to show user's post count from specific category. Currently, I can only be able to query all posts. My code is like this <?php $userpost_count = $wpdb->get_var("SELECT COUNT(*) FROM $wpdb->posts WHERE post_status = 'publish' AND post_type ='post' AND post_author = '".$curauth->ID."'");?> <?php echo "<span>Total post: </b></span>".$userpost_count.""?> I know that, I need to join two table which is post table and term_relationships, but i don't know how to get it. Please kindly help me with that. Thank you.

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  • How do I return the numeric value from a database query in PHP?

    - by Luke
    Hello, I am looking to retreive a numerical value from the database function adminLevel() { $q = "SELECT userlevel FROM ".TBL_USERS." WHERE id = '$_SESSION[id]'"; return mysql_query($q, $this->connection); } This is the SQL. I then wrote the following php/html: <?php $q = $database->adminLevel(); if ($q > 7) { ?> <a href="newleague.php">Create a new league</a> <? } ?> The problem I have is that the userlevel returned isn't affecting the if statement. It is always displayed. How do i get it to test the value of userlevel is greater than 7? Thanks

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  • select query related problem

    - by user222585
    i have interest rate and amount in a table where interest rate are ranged in different values like 4.5,4.6,5.2,5.6 etc. i want to get sum of amounts classified by interest rate where interest rate will be separated by .25. for example all amount having interest rate 1.25,1.3,1.4 will be in one group and 1.5,1.67,1.9 will be in another group how can i write the query?

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  • PHP - How to display other values, when a query is limited by 3?

    - by Dodi300
    Hello. Can anyone tell me how to display the other values, when a query is limited my 3. In this question I asked how to order and limit values, but now I want to show the others in another query. How would I go about doing this? Here's the code I used before: $query = "SELECT gmd FROM account ORDER BY gmd DESC LIMIT 3"; $result = mysql_query($query); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { } Thanks!

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  • php query cant figure out the problem

    - by Eat
    I dont get an error but it does not return me the row values as well. How can I address the problem? <?php //DATABASE $dbConn = mysql_connect($host,$username,$password); mysql_select_db($database,$dbConn); $SQL = mysql_query("SELECT N.*, C.CatID FROM News N INNER JOIN Categories C ON N.CatID = C.CatID WHERE N.Active = 1 ORDER BY DateEntered DESC"); while ( $Result = mysql_fetch_array($SQL) or die(mysql_error())) { $CatID[] = $Result[CatID]; $NewsName[] = $Result[NewsName]; $NewsShortDesc[] = $Result[NewsShortDesc]; } // mysql_free_result($Result); ?> <div class="toparticle"> <span class="section"><?=$CatID[0] ?> </span> <span class="headline"><?=$NewsName[0] ?></span> <p><?=$NewsShortDesc[0] ?></p> </div>

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  • Select rows where column LIKE dictionary word

    - by Gerve
    I have 2 tables: Dictionary - Contains roughly 36,000 words CREATE TABLE IF NOT EXISTS `dictionary` ( `word` varchar(255) NOT NULL, PRIMARY KEY (`word`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; Datas - Contains roughly 100,000 rows CREATE TABLE IF NOT EXISTS `datas` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `hash` varchar(32) NOT NULL, `data` varchar(255) NOT NULL, `length` int(11) NOT NULL, `time` int(11) NOT NULL, PRIMARY KEY (`ID`), UNIQUE KEY `hash` (`hash`), KEY `data` (`data`), KEY `length` (`length`), KEY `time` (`time`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=105316 ; I would like to somehow select all the rows from datas where the column data contains 1 or more words. I understand this is a big ask, it would need to match all of these rows together in every combination possible, so it needs the best optimization. I have tried the below query, but it just hangs for ages: SELECT `datas`.*, `dictionary`.`word` FROM `datas`, `dictionary` WHERE `datas`.`data` LIKE CONCAT('%', `dictionary`.`word`, '%') AND LENGTH(`dictionary`.`word`) > 3 ORDER BY `length` ASC LIMIT 15 I have also tried something similar to the above with a left join, and on clause that specified the like statement.

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  • A better understanding of the relations beetween database tables

    - by Nistor Alexandru
    Hi I am trying to get a better understanding of relational databases and there is something that I keep bumping into and don't understand.Let's take this two tables: In this case Login.ID is the primary key with auto_increment set and Profile.ID_LOGIN is the Foreign KEY.When a user is created and it's username and password is stored in the login database does the ID coresponding to the curesnt username and password get automaticly added into ID_LOGIN or do I have to create an SQL statement to do this? If I have to create a SQL statement how should I aproach adding the ID_LOGIN to make sure I am adding it corectly?

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  • How can i bind a Database field value to a hidden field inside a gridview

    - by Dorababu
    I use the following to bind a field from the table to a hidden field inside a gridview but i am getting the error as System.Data.DataRowView' does not contain a property with the name 'AccountType'. This is how i assigned <asp:TemplateField> <ItemTemplate> <asp:HiddenField ID="hdnAccntType" runat="Server" Value='<%#Eval("AccountType") %>' /> </ItemTemplate> </asp:TemplateField> Is it correct or i have to make any corrections

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  • Get previous and next row from current id

    - by Hukr
    How can I do to get the next row in a table? `image_id` int(11) NOT NULL auto_increment `image_title` varchar(255) NOT NULL `image_text` mediumtext NOT NULL `image_date` datetime NOT NULL `image_filename` varchar(255) NOT NULL If the current image is 3 for example and the next one is 7 etc. this won’t work: $query = mysql_query("SELECT * FROM images WHERE image_id = ".intval($_GET['id'])); echo $_GET['id']+1; How should I do? thanks

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  • trying to redirect the php page is get id is empty ir does not exists.

    - by user570782
    <? include..... if ($picid != $_GET['picid']) || (empty($picid)) { echo "page not working"; } else { $picid = $_GET['picid']; $query = mysql_query("SELECT * FROM pic_info WHERE picid = 'picid1' ");// problem while($rows = mysql_fetch_assoc($query)): $picid = $rows['picid']; $title = $rows['title']; $link = $rows['link']; $description = $rows['description']; $movie_pic = $rows['movie_pic']; $source = $rows['source']; } $get_comment = mysql_query("SELECT * FROM comment WHERE picid ='$picid'");// work partially $comment_count = mysql_num_rows($get_comment); if ($comment_count>0) { messages = " "; while ($com = mysql_fetch_array($get_comment)){ $comment_id = $com['comment_id']; $name = $com['name']; $message = $com['message']; $time_post= $com['time_post']; $messages .= '<em> on ' .$time_post.'</em><b> '.$name.' said.....</b><br/> '.$message.'<hr/>'; // line with problem } } ?> i am stuck i am trying to say that if $_GET['picid']; is empty echo out error message or if the movid does not exist in the db echo out error message. when i run it i get an error. not sure if i am calling the correct function. what am i doing wrong please help

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  • Convert multiquery to a query using group by and so on

    - by ffffff
    -schema CREATE TABLE `ratings` ( `id` int(11) NOT NULL default '0', `rating` int(11) NOT NULL default '1', `rating_start` datetime NOT NULL default '0000-00-00 00:00:00', PRIMARY KEY (`id`) ) TYPE=MyISAM -myprogram.php foreach($ids as $id){ $sql = "SELECT rating FROM ratings WHERE id = '$id' AND rating_start >= NOW()"; $sql .= "ORDER BY rating_start DESC LIMIT 1;" $ret = $db->execute($id); } Can I teke same date from a Query? by using id IN (".implode(",",$ids).") and GROUP BY id

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  • where id = multiple artists

    - by pixel
    Any time there is an update within my music community (song comment, artist update, new song added, yadda yadda yadda), a new row is inserted in my "updates" table. The row houses the artist id involved along with other information (what type of change, time and date, etc). My users have a "favorite artists" section where they can do just that -- mark artists as their favorites. As such, I'd like to create a new feature that shows the user the changes made to their various favorite artists. How should I be doing this efficiently? SELECT * FROM table_updates WHERE artist_id = 1 and artist_id = 500 and artist_id = 60032 Keep in mind, a user could have 43,000 of our artists marked as a favorite. Thoughts?

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  • Why does this properly escaped SQL query fail?

    - by Jason Rhodes
    Here's the query: INSERT INTO jobemails (jobid, to, subject, message, headers, datesent) VALUES ('340', '[email protected]', 'We\'ve received your request for a photo shoot called \'another\'.', 'message', 'headers', '2010-04-22 15:55:06') The datatypes are all correct, it always fails at the subject, so it must be how I'm escaping the values, I assume. I'm sure one of you will see my idiot mistake right away. A little help?

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  • Storing "binary" data type in C program

    - by puchu
    I need to create a program that converts one number system to other number systems. I used itoa in Windows (Dev C++) and my only problem is that I do not know how to convert binary numbers to other number systems. All the other number systems conversion work accordingly. Does this involve something like storing the input to be converted using %? Here is a snippet of my work: case 2: { printf("\nEnter a binary number: "); scanf("%d", &num); itoa(num,buffer,8); printf("\nOctal %s",buffer); itoa(num,buffer,10); printf("\nDecimal %s",buffer); itoa(num,buffer,16); printf("\nHexadecimal %s \n",buffer); break; } For decimal I used %d, for octal I used %o and for hexadecimal I used %x. What could be the correct one for binary? Thanks for future answers!

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  • The best way to structure this database?

    - by James P
    At the moment I'm doing this: gems(id, name, colour, level, effects, source) id is the primary key and is not auto-increment. A typical row of data would look like this: id => 40153 name => Veiled Ametrine colour => Orange level => 80 effects => +12 sp, +10 hit source => Ametrine (Some of you gamers might see what I'm doing here :) ) But I realise this could be sorted a lot better. I have studied database relationships and secondary keys in my A-Level computing class but never got as far as to set one up properly. I just need help with how this database should be organised, like what tables should have what data with what secondary and foreign keys? I was thinking maybe 3 tables: gem, effects, source. Which then have relationships to each other? Can anyone shed some light on this? Is a complex way like I'm proposing really the way to go or should I just carry on with what I'm doing? Cheers.

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  • PHP Code Problem...

    - by aamir Fayyaz
    function check_login($array_val) { $strQury = "Select * from tblsignup where usr_email ='".$array_val[0]."' and usr_password = '".$array_val[1]."'" ; $result = mysql_query($strQury); $row_user = mysql_fetch_array($result); if(mysql_num_rows($result)>0) { $msg = "true"; } else { $msg = "false"; } return $msg ; } The return value is Object id #1true???? what is object id#1?

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  • Is this possible with sql?

    - by Andrew
    Is it possible to do something like this: INSERT INTO table(col1, col2) VALUES(something_from_another_table, value); With something_from_another_table being a SQL command? Like, is there something I can do that's equivelant to: INSERT INTO table(col1, col2) VALUES((SELECT value FROM table2 WHERE id = 3), value);

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  • Creating dynamic icons based on data entered into database from django forms

    - by John Hoke
    So I'm using Django to create a projects page with multiple forms for each project. Let's call them form 1, 2, 3, and 4. Once you create a project you can fill out any of these forms. I want to create "buttons" or links for each one of the forms that would show up on the main page. Now this is the part I need help with: Step 1. I want it so that if you click on a button for a form (say form 1) and none exists for that project yet a pop up would come up saying "This form does not exist yet, are you sure you want to create one?". And if you'd answer yes you would be directed to the form page. Step 2. But if that form does exist, I don't want any pop up to open and I want the link to take the user directly to that page. Step 3. My next problem is this. These forms are in order, so if you didn't create form 1 but created form 2, I don't want to give the user access to form 1. So in this scenario, if you click on form 1 I want a pop up to open and say "This form can no longer be created", and the link wouldn't function anymore. Basically the button will have 3 function. First it should look at the database and if data for that specific form exists it should do "Step 2", if data for that form and the proceeding forms don't exist it should do "Step 1", and if data for that form doesn't exist but data for proceeding form's does exist is should do "Step 3". Is this possible? Please help as I need to find a solution to this soon. Any help would be highly appreciated. Thank you

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  • How would I go about writing a conditional statement to check if visitor is coming from a particular

    - by Matthew
    Hello guys, What I have in mind is this... We are going to have people come from a particular site during a acquisition campaign and was wondering how I could conditionalize a certain section of my site to display a thank you message instead of the sign up form as they would have had the opportunity to fill this out before coming to my landing page. I have seen solutions like: $referal = mysql_real_escape_string($_SERVER['HTTP_REFERER']); I would like to know if this is the best way to get this to work??? - okay this is what i think might work. The third party website that is referring people to our landing page once the form on that site has been filled out can push into the record a hidden input value of "www.sample.com" or whatever... then I can have something check the for that particular value and fire off the conidtional. Does that even sound right?

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