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  • Online Game programming in Google App Engine: AI

    - by Hortinstein
    I am currently in the planning stages of a game for google app engine, but cannot wrap my head around how I am going to handle AI. I intend to have persistant NPCs that will move about the map, but short of writing a program that generates the same XML requests I use to control player actions, than run it on another server I am stuck on how to do it. I have looked at the Task Queue feature, but due to long running processes not being an option on the App engine, I am a little stuck. I intend to run multiple server instances with 200+ persistant NPC entities that I will need to update. Most action is slowly roaming around based on player movements/concentrations, and attacking close range players(you can probably guess the type of game im developing)

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  • threading.Event wait function not signaled when subclassing Process class

    - by user1313404
    For following code never gets past the wait function in run. I'm certain I'm doing something ridiculously stupid, but since I'm not smart enough to figure out what, I'm asking. Any help is appreciated. Here is the code: import threading import multiprocessing from multiprocessing import Process class SomeClass(Process): def __init__(self): Process.__init__(self) self.event = threading.Event() self.event.clear() def continueExec(self): print multiprocessing.current_process().name print self print "Set:" + str(self.event.is_set()) self.event.set() print "Set:" + str(self.event.is_set()) def run(self): print "I'm running with it" print multiprocessing.current_process().name self.event.wait() print "I'm further than I was" print multiprocessing.current_process().name self.event.clear() def main(): s_list = [] for t in range(3): s = SomeClass() print "s:" + str(s) s_list.append(s) s.start() raw_input("Press enter to send signal") for t in range(3): print "s_list["+str(t)+"]:" + str(s_list[t]) s_list[t].continueExec() raw_input("Press enter to send signal") for t in range(3): s_list[t].join() print "All Done" if __name__ == "__main__": main()

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  • removing elements incrementally from a list

    - by Javier
    Dear all, I've a list of float numbers and I would like to delete incrementally a set of elements in a given range of indexes, sth. like: for j in range(beginIndex, endIndex+1): print ("remove [%d] => val: %g" % (j, myList[j])) del myList[j] However, since I'm iterating over the same list, the indexes (range) are not valid any more for the new list. Does anybody has some suggestions on how to delete the elements properly? Best wishes

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  • How do I do a semijoin using SQLAlchemy?

    - by Jason Baker
    http://en.wikipedia.org/wiki/Relational_algebra#Semijoin Let's say that I have two tables: A and B. I want to make a query that would work similarly to the following SQL statement using the SQLAlchemy orm: SELECT A.* FROM A, B WHERE A.id = B.id AND B.type = 'some type'; The thing is that I'm trying to separate out A and B's logic into different places. So I'd like to make two queries that I can define in separate places: one where A uses B as a subquery, but only returns rows from A. I'm sure this is fairly easy to do, but an example would be nice if someone could show me.

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  • How can I identify an element from a list within another list

    - by Alex
    I have been trying to make a block of code that finds the index of the largest bid for each item. Then I was going to use the index as a way to identify the person who paid that much moneys name. However no matter what i try I can't link the person and what they have gained from the auction together. Here is the code I have been writing: It has to be able to work with any information inputted def sealedBids(): n = int(input('\nHow many people are in the group? ')) z = 0 g = [] s = [] b = [] f = [] w = []#goes by number of items q = [] while z < n: b.append([]) z = z + 1 z = 0 while z < n: g.append(input('Enter a bidders name: ')) z = z + 1 z = 0 i = int(input('How many items are being bid on?')) while z < i: s.append(input('Enter the name of an item: ')) w.append(z) z = z + 1 z = 0 for j in range(n):#specifies which persons bids your taking for k in range(i):#specifies which item is being bid on b[j].append(int(input('How much money has {0} bid on the {1}? '.format(g[j], s[k])))) print(' ') for j in range(n):#calculates fair share f.append(sum(b[j])/n) for j in range(i):#identifies which quantity of money was the largest for each item for k in range(n): if w[j] < b[k][j]: w[j] = b[k][j] q.append(k) any advice is much appreciated.

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  • PyQt - How to connect multiple signals to the same widget

    - by Orchainu
    [ ]All1 [ ]All2 [ ]checkbox1A [ ]checkbox1B [ ]checkbox2A [ ]checkbox2B Based on the chart above, a few things need to happen: The All checkboxes only affect the on/off of the column it resides in, and checks on/off all the checkboxes in that column. All checkboxes work in pairs, so if checkbox1A is on/off, checkbox1B needs to be on/off If an All checkbox is checked on, and then the user proceeds to check off one or more checkbox in the column, the All checkbox should be unchecked, but all the checkboxes that are already checked should remain checked. So really this is more like a chain reaction setup. If checkbox All1 is on, then chieckbox1A and 2A will be on, and because they are on, checkbox1B and 2B are also on, but checkbox All2 remains off. I tried hooking up the signals based on this logic, but only the paired logic works 100%. The All checkbox logic only works 50% of the time, and not accurately, and there's no way for me to turn off the All checkbox without turning all already checked checkboxes off. Really really need help ... T-T Sample code: cbPairKeys = cbPairs.keys() for key in cbPairKeys: cbOne = cbPairs[key][0][0] cbTwo = cbPairs[key][1][0] cbOne.stateChanged.connect(self.syncCB) cbTwo.stateChanged.connect(self.syncCB) def syncCB(self): pairKeys = cbPairs.keys() for keys in pairKeys: cbOne = cbPairs[keys][0][0] cbOneAllCB = cbPairs[keys][0][4] cbTwo = cbPairs[keys][1][0] cbTwoAllCB = cbPairs[keys][1][4] if self.sender() == cbOne: if cbOne.isChecked() or cbTwoAllCB.isChecked(): cbTwo.setChecked(True) else: cbTwo.setChecked(False) else: if cbTwo.isChecked() or cbOneAllCB.isChecked(): cbOne.setChecked(True) else: cbOne.setChecked(False) EDIT Thanks to user Avaris's help and patience, I was able to reduce the code down to something much cleaner and works 100% of the time on the 1st and 2nd desired behavior: #Connect checkbox pairs cbPairKeys = cbPairs.keys() for key in cbPairKeys: cbOne = cbPairs[key][0][0] cbTwo = cbPairs[key][1][0] cbOne.toggled.connect(cbTwo.setChecked) cbTwo.toggled.connect(cbOne.setChecked) #Connect allCB and allRO signals cbsKeys = allCBList.keys() for keys in cbsKeys: for checkbox in allCBList[keys]: keys.toggled.connect(checkbox.setChecked) Only need help on turning off the All checkbox when the user selectively turns off the modular checkboxes now

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  • Selenium selected option in dropdown not displayed correctly

    - by luckyfool
    I have the following issue with Selenium Webdriver. There are two dropdown menus on a page i am testing "brand" and "items". The options of "items" depend on which brand you choose. I am trying to iterate through all possible choices and print brand-item pairs. I use two possible ways to pick an option from each dropdown menu Using Select(): def retryingSelectOption(name,n): result=False attempts=0 while attempts<5: try: element=Select(driver.find_element_by_name(name)) element.select_by_index(n) print element.all_selected_options[0].text result=True break except StaleElementReferenceException: pass attempts+=1 return result And using .click(): def retryingClickOption(name,n): result=False attempts=0 while attempts<5: try: driver.find_element_by_name(name).find_elements_by_tag_name("option")[n].click() result=True break except StaleElementReferenceException: pass attempts+=1 return result My problem is that at ,what seem to me as random moments (sometimes it works sometimes it does not), even though the above functions return True and printing out the selected option shows me the correct answer, the browser still displays the previous option. So basically Selenium tells me i have picked the right option but the browser displays the previous one.No idea what is wrong.

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  • Appengine Model SelfReferenceProperty and parent child relationship

    - by GeekTantra
    I have a scenario in which I need a self reference property as follow: class Post(db.Model): creator = db.UserProperty() post_title = db.StringProperty(required=True) post_status = db.StringProperty(required=True, choices=['draft', 'published']) post_parent = db.SelfReferenceProperty() Now, I want ensure that an entity shouldn't be its own parent and a child of an entity cannot be its parent. How can I ensure this kind of a relationship in the PostForm model form and the Post model.

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  • Finding out event that called a CGI script

    - by Acorn
    What I want is to be able to make my CGI script do different things depending on what action initiated the calling of the script. For example, if one button is pressed, a database is cleared. If another button is pressed, a form is submitted and that data is added to the database. Should I be doing something like adding the name of the form/button to the end of the POST data submitted in jQuery and then .poping it off in the script? Or is there some other data that's already sent in the POST that I could get from FieldStorage that would give me the information I need to decide what the script should do when it's called? And what if I wasn't using javascript? Would I have to have a hidden field that gets submitted with the name of the form/button? Or is it best to use a different target script for each button on a page?

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  • how to fetch more than 1000 entities NON keybased?

    - by user291071
    If I should be approaching this problem through a different method, please suggest so. I am creating an item based collaborative filter. I populate the db with the LinkRating2 class and for each link there are more than a 1000 users that I need to call and collect their ratings to perform calculations which I then use to create another table. So I need to call more than 1000 entities for a given link. For instance lets say there are over a 1000 users rated 'link1' there will be over a 1000 instances of this class for the given link property that I need to call. How would I complete this example? class LinkRating2(db.Model): user = db.StringProperty() link = db.StringProperty() rating2 = db.FloatProperty() query =LinkRating2.all() link1 = 'link string name' a = query.filter('link = ', link1) aa = a.fetch(1000)##how would i get more than 1000 for a given link1 as shown? ##keybased over 1000 in other post example i need method for a subset though not key class MyModel(db.Expando): @classmethod def count_all(cls): """ Count *all* of the rows (without maxing out at 1000) """ count = 0 query = cls.all().order('__key__') while count % 1000 == 0: current_count = query.count() if current_count == 0: break count += current_count if current_count == 1000: last_key = query.fetch(1, 999)[0].key() query = query.filter('__key__ > ', last_key) return count

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  • better for-loop syntax for detecting empty sequences?

    - by Dmitry Beransky
    Hi, Is there a better way to write the following: row_counter = 0 for item in iterable_sequence: # do stuff with the item counter += 1 if not row_counter: # handle the empty-sequence-case Please keep in mind that I can't use len(iterable_sequence) because 1) not all sequences have known lengths; 2) in some cases calling len() may trigger loading of the sequence's items into memory (as the case would be with sql query results). The reason I ask is that I'm simply curious if there is a way to make above more concise and idiomatic. What I'm looking for is along the lines of: for item in sequence: #process item *else*: #handle the empty sequence case (assuming "else" here worked only on empty sequences, which I know it doesn't)

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  • MongoDB lists with paginations?

    - by Timmy
    for documents with lists with pagination, is it better to embed or use reference? im reading the custom type "SONManipulator" and it appears to transform every thing on retrieval, even the sub docs. i want to keep the list in the document sorted, should this impact anything?

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  • Construct Numpy index given list of starting and ending positions

    - by Abiel
    I have two identically-sized numpy.array objects (both one-dimensional), one of which contains a list of starting index positions, and the other of which contains a list of ending index positions (alternatively you could say I have a list of starting positions and window lengths). In case it matters, the slices formed by the starting and ending positions are guaranteed to be non-overlapping. I am trying to figure out how to use these starting and ending positions to form an index for another array object, without having to use a loop. For example: import numpy as np start = np.array([1,7,20]) end = np.array([3,10,25]) Want to reference somearray[1,2,7,8,9,20,21,22,23,24])

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  • slicing arrays in numpy/scipy

    - by user248237
    I have an array like: a = array([[1,2,3],[3,4,5],[4,5,6]]) what's the most efficient way to slice out a 1x2 array out of this that has only the first two columns of "a"? I.e., array([[2,3],[4,5],[5,6]]) in this case. thanks.

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  • using dictionary to assign misspelled words to its line number

    - by jad
    This is the code I have so far d = {} counter = 0 for lines in words: counter += 1 for word in text1: if word not in words: d[word] = [counter] else: d[word].append(counter) print(word, d[counter]) words = my text file text1 is my misspelled words But this gives me an error. What I want to do is print the word and the line number e.g. togeher 5 7

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  • What does this `_time_independent_equals` mean?

    - by Satoru.Logic
    In the tornado.web module there is a function called _time_independent_equals: def _time_independent_equals(a, b): if len(a) != len(b): return False result = 0 for x, y in zip(a, b): result |= ord(x) ^ ord(y) return result == 0 It is used to compare secure cookie signatures, and thus the name. But regarding the implementation of this function, is it just a complex way to say a==b?

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  • Tkinter after that survives clock rewinding.

    - by Oren
    I noticed that in my version of Tkinter, the after() call does not survive system clock rewinding. If the after(x, func) was called, and the system clock was rewinded, func will be called only after the clock returned to its time before the rewind + x milliseconds. I assume this is because Tkinter uses the system-clock instead of the "time.clock" (the amount of time that the program is running). I tested it only on windows, and maybe its because I have an old version of Tkinter. I want my App to work on computers that synchronize their clock from the network... Does anyone have a simple solution?

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  • How to execute machine language from memory?

    - by Mike Curry
    I wrote a program to compile a simple text program to a compiled executable... Is it possible that I can load an executable to memory an some how point a pc counter to the memory space at will? Here is what I made that I would like to store the programs to memory for execution on demand... Kind of wanting to make a little web language like php but compile it... Just for learning. http://spiceycurry.blogspot.com/2010/05/simple-compilable-programming-language.html

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  • Does Google appengine cache external requests?

    - by Andy Hume
    I have a very simple application running on appengine that requests a web page every five minutes and parses for a specific piece of data. Everything works fine except that the response I get back from the external request (using urllib2) doesn't reflect the latest changes to the page. Sometimes it takes a few minutes to get the latest, sometimes over an hour. Is there a transparent layer of caching that appengine puts in place? Or is there something else I am missing here? I've looked at the caching headers of the requested page and there is no Expires or LastModified's sent. Update: Sometimes, it will get the new version of the page for a number of requests and then randomly later get an old out of date version.

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  • Django filter by hour

    - by DJPy
    I've found that link: http://code.djangoproject.com/attachment/ticket/8424/time_filters.diff and changed my django 1.2 files by adding taht what you can see there. But now, when I'm trying to write Entry.objects.filter(pub_date__hour = x) - the result is following error: Field has invalid lookup: hour What should I do else, to make it work? (sorry for my english)

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  • Calculating the null space of a matrix

    - by Ainsworth
    I'm attempting to solve a set of equations of the form Ax = 0. A is known 6x6 matrix and I've written the below code using SVD to get the vector x which works to a certain extent. The answer is approximately correct but not good enough to be useful to me, how can I improve the precision of the calculation? Lowering eps below 1.e-4 causes the function to fail. from numpy.linalg import * from numpy import * A = matrix([[0.624010149127497 ,0.020915658603923 ,0.838082638087629 ,62.0778180312547 ,-0.336 ,0], [0.669649399820597 ,0.344105317421833 ,0.0543868015800246 ,49.0194290212841 ,-0.267 ,0], [0.473153758252885 ,0.366893577716959 ,0.924972565581684 ,186.071352614705 ,-1 ,0], [0.0759305208803158 ,0.356365401030535 ,0.126682113674883 ,175.292109352674 ,0 ,-5.201], [0.91160934274653 ,0.32447818779582 ,0.741382053883291 ,0.11536775372698 ,0 ,-0.034], [0.480860406786873 ,0.903499596111067 ,0.542581424762866 ,32.782593418975 ,0 ,-1]]) def null(A, eps=1e-3): u,s,vh = svd(A,full_matrices=1,compute_uv=1) null_space = compress(s <= eps, vh, axis=0) return null_space.T NS = null(A) print "Null space equals ",NS,"\n" print dot(A,NS)

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