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  • retrieve contact's nickname

    - by TomTasche
    Hello, I want to get the nickname of a contact from addressbook. I start with his phone number, query it and want the nickname (aka alias) as a result. Cursor cur = context.getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.NUMBER + " = " + incomingNumber, null, null); if (cur.moveToFirst()) { Log.e("saymyname", cur.getString(cur.getColumnIndex(ContactsContract.CommonDataKinds.Nickname.NAME))); Log.e("saymyname", cur.getString(cur.getColumnIndex(ContactsContract.CommonDataKinds.Nickname.LABEL))); } Output of the logs is the incomingNumber (first Log.e() ) and null (second Log.e() ), but I want to get the contact's nickname! Thanks Tom

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  • Get the AVG of two SQL Access Queries

    - by reggiereg
    Hi, I'm trying to get the AVERAGE from the results of two separate sql queries built in MS Access. The first sql query pulls the largest record: SELECT DISTINCTROW Sheet1.Tx_Date, Sheet1.LName, Sheet1.Patient_Name, Sheet1.MRN, Max(Sheet1.) AS [Max Of FEV1_ACT], Max(Sheet1.FEF_25_75_ACT) AS [Max Of FEF_25_75_ACT] FROM Sheet1 GROUP BY Sheet1.Tx_Date, Sheet1.LName, Sheet1.Patient_Name, Sheet1.MRN; The second sql query pulls the second largest record: SELECT Sheet1.MRN, Sheet1.Patient_Name, Sheet1.Lname, Max(Sheet1.FEV1_ACT) AS 2ndLrgOfFEV1_ACT, Max(Sheet1.FEF_25_75_ACT) AS 2ndLrgOfFEF_25_75_ACT FROM Sheet1 WHERE (((Sheet1.FEV1_ACT)<(SELECT MAX( FEV1_ACT ) FROM Sheet1 ))) GROUP BY Sheet1.MRN, Sheet1.Patient_Name, Sheet1.Lname; These two queries work great, I just need some help on pulling the AVERAGE of the results of these two queries into one. Thanks.

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  • problems with studying algorithms

    - by rookie
    hello everyone, I'm currently studying computer science at the Institute, and I have some problems with course which is named Algorithms, I've just begun to study it, but I'm already feeling, that I'm going to fail it, my problem is that while understanding different algorithms on graphs I need to keep in my mind a lot of info, and usually I can't do it, I forget some points of the exercise or can't proceed to final result, I'm very desperate about it cause I like programming very much. Did somebody feel the same while studying in the University? thanks in advance for any help P.S. I began to program only two years ago, may it be the problem?

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  • Hibernate: same generated value in two properties

    - by Markos Fragkakis
    Hi, I have an entity A with fields: aId (the system id) bId I want the first to be generated: @Id @Column(name = "PRODUCT_ID", unique = true, nullable = false, precision = 12, scale = 0) @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "PROD_GEN") @BusinessKey public Long getAId() { return this.aId; } I want the bId to be initially exactly as the aId. One approach is to insert the entity, then get the aId generated by the DB (2nd query) and then update the entity, setting the bId to be equal to aId (3rd query). Is there a way to get the bId to get the same generated value as aId? Note that afterwards, I want to be able to update bId from my gui. If the solution is JPA, even better.

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  • Rails relation select

    - by Dimitar Vouldjeff
    Hi, I have the following models: class User < ActiveRecord::Base has_many :results, :dependent => :destroy has_many :participants, :dependent => :destroy has_many :courses, :through => :participants end class Course < ActiveRecord::Base has_many :tests, :dependent => :destroy has_many :participants, :dependent => :destroy has_many :users, :through => :participants end class Result < ActiveRecord::Base belongs_to :test belongs_to :user end class Test < ActiveRecord::Base belongs_to :course has_many :results, :dependent => :destroy end The Idea is that a user has_and_belongs_to_many courses, the course has_many tests, and every test has_and_belongs_to_many users (results). So what is the best query to select every Result from a single Course (not test), and also the query to select every Result from a single Course, but from one user. Thanks!

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  • dynamic button in jsp

    - by kawtousse
    hi everyone, in my jsp i have a table constructed dynamically like the following: retour.append("<tr>"); try { s= HibernateUtil.currentSession(); tx=s.beginTransaction(); Query query = s.createQuery(HQL_QUERY); for(Iterator it=query.iterate();it.hasNext();) { if(it.hasNext()){ Dailytimesheet object=(Dailytimesheet)it.next(); retour.append("<td>" +object.getActivity() +"</td>"); retour.append("<td>" +object.getProjectCode() + "</td>"); retour.append("<td>" +object.getWAName() + "</td>"); retour.append("<td>" +object.getTaskCode() +"</td>"); retour.append("<td>" +object.getTimeFrom() +"</td>"); retour.append("<td>" +object.getTimeSpent() + "</td>"); retour.append("<td>" +object.getPercentTaskComplete() + "</td>"); if (droitdaccess) { retour.append(""); retour.append(""); retour.append(""); retour.append("<td bordercolor=#FFFFFF>"); retour.append("<input type=\"hidden\" id=\"id_"+nomTab+"_"+compteur+"\" value=\""+object.getIdDailyTimeSheet()+"\"/>"); retour.append("<img src=\"icon_delete.gif\" onClick=\"deletearowById('id_"+nomTab+"_"+compteur+"')\" style=\"cursor:pointer\" name=\"action\" value=\"deleting\" />"); retour.append("</td>"); } } compteur++; retour.append("</tr>"); } //terminer la table. retour.append ("</table>"); next to the table i want to display a button named send in order to send the table content. I do not really want to dispaly this button where the table is empty. So at least if the table is populated by nly one record i want that button being displayed. How should i deal in this case. Thanks.

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  • does mysql stored procedures support data types like array, hash,etc?

    - by Yang
    i am creating a mysql function which takes in a varchar and change it to a int based on a mapping table. select name, convert_to_code(country) from users where sex = 'male' here, the convert_to_code() function takes in a country name (e.g. Japan, Finland..) and change it to country code which is an integer (e.g. 1001, 2310..) based on a mapping table called country_maping like below: country_name (varchar) | country_code (int) Japan | 1001 Finland | 2310 Canada | 8756 currently, the stored function need to select country_code from country_mapping where country_name = country_name and return the query result. is that possible to create a hash data struct in SP to optimize the process so that it will not need to perform the query for each row matches the where clause. thanks in advance!

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  • Deleting rows with MySQL LEFT JOIN

    - by fabrik
    Hello! I have two tables, one for job deadlines, one for describe a job. Each job can take a status and some statuses means the jobs' deadlines must be deleted from the other table. I can easily SELECT the jobs/deadlines that meets my criteria with a LEFT JOIN: SELECT * FROM `deadline` LEFT JOIN `job` ON deadline.job_id = job.job_id WHERE `status` = 'szamlazva' OR `status` = 'szamlazhato' OR `status` = 'fizetve' OR `status` = 'szallitva' OR `status` = 'storno' (status belongs to job table not deadline) But when i'd like to delete these rows from deadline, MySQL throws an error. My query is: DELETE FROM `deadline` LEFT JOIN `job` ON deadline.job_id = job.job_id WHERE `status` = 'szamlazva' OR `status` = 'szamlazhato' OR `status` = 'fizetve' OR `status` = 'szallitva' OR `status` = 'storno' MySQL error says nothing: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LEFT JOIN `job` ON deadline.job_id = job.job_id WHERE `status` = 'szaml' at line 1 How can i turn my SELECT into a working DELETE query? Thanks, fabrik

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  • How to disable automatic login?

    - by iammilind
    I was playing around with "User accounts" and somehow set automatic login. Now, when I start my PC, it just has one button named as "login". Clicking that button, directly logs me in to my PC. There is no music or no asking for password while logging in. As a side effect, it asks me separately for keyring password How to disable auto login and make login/keyring password unified again like before? NOTE: Attempting to disable Automatic Login from System Settings User Accounts does not work. This is the content of my /etc/lightdm/lightdm.conf (where I have commented the autologin for my username mgandhi): [SeatDefaults] greeter-session=unity-greeter user-session=ubuntu #autologin-user=mgandhi

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  • MySQL JDBC date issues with database server in different timezone

    - by Somatik
    I have a database server in "Europe/London" time zone and my web server in "Europe/Brussels". Since it is summer time now my application server has a 2 hour difference. I created a test to reproduce my issue: Query q = JPA.em().createNativeQuery("SELECT UNIX_TIMESTAMP(startDateTime) FROM `Event` WHERE `id` =574"); BigInteger unix = (BigInteger) q.getSingleResult(); System.out.println(unix + "000 UNIX_TIMESTAMP to BigInteger"); Query q2 = JPA.em().createNativeQuery("SELECT startDateTime FROM `Event` WHERE `id` =574"); Timestamp o = (Timestamp) q2.getSingleResult(); System.out.println(o.getTime() + " Timestamp"); The startDateTime column is defined as 'datetime' (but same issue with 'timestamp') The output I am getting is this: 1340291591000 UNIX_TIMESTAMP to BigInteger 1340284391000 Timestamp Reading java date objects results in a shift in time zone, how do I fix this? I would expect the jdbc driver to just set the "unix time" value it gets from the server in the Date object. (a proper solution should work with any timezone combination, not only for db in GMT)

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  • forbidden foldername?

    - by j0h
    I have a little webserver i run to help me at work. in an effort to neaten up the internal bits, I made a forlder named "doc" for documents. When i try to navigate to that folder i get "You don't have permission to access /doc/ on this server." so then, i looked at the permissions. drwxrwxr-x 2 J0h J0h 4096 Nov 7 22:46 doc/ drwxrwxr-x 5 J0h J0h 4096 Nov 6 12:35 ece/ drwxrwxr-x 2 J0h J0h 4096 Nov 6 12:35 exe/ permissions of "doc" looks legit. ece/ and exe both work, and have the same permissions. So then I changed the name of the folder "doc" to "docs" and it works. So evidently the folder-name doc is a black listed folder name? is that right? what is going one here?

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  • Insert multiple records from a XML string differing on one parameter in SQL SERVER 2008

    - by Rohit
    Below in a query which inserts records to SimpleDictationProfileMapping table after reading it from a XML string. Now this query inserts a single record in which DictationCaptureProfileID is @dictationCaptureProfileId . Now i want to insert multiple rows in which @dictationCaptureProfileId is different and other 2 values are same. What i want to achieve by this is in case parent changes all child values should also change. INSERT INTO SimpleDictationProfileMapping ( DictationCaptureProfileID, DictationProfileMappingAttributeID, DictationProfileMappingAttributeValue ) SELECT @dictationCaptureProfileId, row.value('@attrId','varchar(max)'), row.value('@value', 'varchar(max)') FROM @simpleDictationCaptureProfileMappings.nodes('/simpleMappingAtribute/attribute') AS d ( row ) ; I want INSERT INTO SimpleDictationProfileMapping ( DictationCaptureProfileID OR (SELECT DictationCaptureProfileID FROM DictationCaptureProfile WHERE SystemDictationCaptureProfileID = @systemDictationCaptureProfileID), DictationProfileMappingAttributeID, DictationProfileMappingAttributeValue ) SELECT @dictationCaptureProfileId , row.value('@attrId','varchar(max)'), row.value('@value', 'varchar(max)') FROM @simpleDictationCaptureProfileMappings.nodes ('/simpleMappingAtribute/attribute') AS d ( row ) ; Please tell how to achieve this.

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  • Disable printing extraneous job info when I print a images

    - by pgrytdal
    As of 10/11/12 I this is still a problem. Peterling, that link you gave me was for Windows. Not Ubuntu. I need to know how to do this in Ubuntu. Whenever I print off an image, before the actual image prints, I get these weird "print job" sheets. (I named them that, because I don't know what else to call them.) They say something like: Media Limits: 0.12 x 0.38 to 8.38 x 10.38 inches Job ID: Officejet-Pro-L7700-64 Driver: hp-officejet_pro_17700.ppd Driver version: Description: HP Officejet Pro L7700 Make and Model: HP Officejet Pro L7700, hpcups 3.12.2 Printer: Officejet-Pro-L7700 Created at: Fri Sep 28 14:12:53 2012 Printed at: Fri Sep 28 14:12:53 2012 How do I fix this so the page doesn't print?

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  • Picture lens doesn't find anything

    - by Han Cnx
    I get Facebook results, but nothing from my computer. If I open a terminal and use 'locate' then I can find stuff, but the picture lens is empty. Note that my picture files are on an NTFS partition. I have made a link named 'Pictures' in my home folder that points to the location where the picture files are. Again, this works with the 'locate' command and it also works for the Music lens, which is also a link in my home folder. It also (kinda) works for the Video lens, though it only wants to find videos I have opened, which seems not consistent with the other lenses. (and also not very useful this way)

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  • How to skip all the column names in MySQL when the table has auto increment primary key?

    - by Jian Lin
    A table is: mysql> desc gifts; +---------------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------------+-------------+------+-----+---------+----------------+ | giftID | int(11) | NO | PRI | NULL | auto_increment | | name | varchar(80) | YES | | NULL | | | filename | varchar(80) | YES | | NULL | | | effectiveTime | datetime | YES | | NULL | | +---------------+-------------+------+-----+---------+----------------+ the following is ok: mysql> insert into gifts -> values (10, "heart", "heart_shape.jpg", now()); Query OK, 1 row affected (0.05 sec) but is there a way to not specify the "10"... and just let each one be 11, 12, 13... ? I can do it using mysql> insert into gifts (name, filename, effectiveTime) -> values ("coffee", "coffee123.jpg", now()); Query OK, 1 row affected (0.00 sec) but the column names need to be all specified. Is there a way that they don't have to be specified and the auto increment of primary key still works? thanks.

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  • Mysql Select 1:n

    - by clinisbut
    Hello, I have two tables that relates 1:n content --------- - id - title - text content_meta ------------- - id - content_id - meta_key - meta_value A content can have multiple content_meta registers associated to it. Typically content_meta will contain the category, tags, descriptions and all that stuff, so I really don't know the number of registers a content will have. What I want to accomplish is to take the content register and also all the related registers in content_meta in a single query. I've tried the subselect approachment but seems that I can only get one register/column (¿?) SELECT content.*, ( SELECT * FROM content_meta WHERE content_id = content.id ) FROM content This query complains that "Operand should contain 1 column(s)", so changing the '*' by for example meta_key clears the error, but returns a NULL for this subselect... SELECT content.*, ( SELECT meta_key FROM content_meta WHERE content_id = content.id ) FROM content Can anybody show me where to go from here please?

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  • Using a ICollection Value in sqlite SELECT parameterized statment

    - by case23
    Im trying to get all the entrys from a sqlite Database which have the same name as the keys in a Hashtable. My Statement looks like this. // the keys from the hashtable are names equivalent // to name entrys in the SomeTable Names Collumn Hashtable names; String query = "SELECT Id, Name FROM SomeTable WHERE Name LIKE (@Names)"; SQLiteCommand command = new SQLiteCommand(query, _databaseConnection); command.Parameters.AddWithValue("@Names", names.Keys); SQLiteDataReader reader = reader.ExecuteReader(); while(reader.Read()) { Console.WriteLine("Name: {0}, ID: {1}", reader[1].ToString(), reader[0].ToString()); } Im totally sure there are similar values in the Database, but i get nothing back and the reader does not execute. Is it impossible to add a ICollection as a Parameter Value so i need to start the reader only one time?

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  • 6 Great Alternative Browsers for Your Android Device

    - by Chris Hoffman
    Android’s default browser, named “Internet,” is a very simple browser that’s tied to your Android OS version. Other, third-party browsers offer more powerful interfaces, greater configurability, and more frequent updates. Unlike on Apple’s iOS, Android browsers can implement their own rendering engines, although not all do. That Firefox app isn’t just a shell over the stock browser, like it is on iOS – it brings Mozilla’s Gecko to Android. How to Own Your Own Website (Even If You Can’t Build One) Pt 1 What’s the Difference Between Sleep and Hibernate in Windows? Screenshot Tour: XBMC 11 Eden Rocks Improved iOS Support, AirPlay, and Even a Custom XBMC OS

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  • Avoiding Nested Queries

    - by Midhat
    How Important is it to avoid nested queries. I have always learnt to avoid them like a plague. But they are the most natural thing to me. When I am designing a query, the first thing I write is a nested query. Then I convert it to joins, which sometimes takes a lot of time to get right. And rarely gives a big performance improvement (sometimes it does) So are they really so bad. Is there a way to use nested queries without temp tables and filesort

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  • Finding Cities within 'X' Kilometers (or Miles)

    - by Mike Curry
    This may or may not be clear, leave me a comment if I am off base, or you need more information. Perhaps there is a solution out there already for what I want in PHP. I am looking for a function that will add or subtract a distance from a longitude OR latitude value. Reason: I have a database with all Latitudes and Longitudes in it and want to form a query to extract all cities within X kilometers (or miles). My query would look something like this... Select * From Cities Where (Longitude > X1 and Longitude < X2) And (Latitude > Y1 and Latitude < Y2) Where X1 = Longitude - (distance) Where X2 = Longitude + (distance) Where Y1 = Latitude - (distance) Where Y2 = Latitude + (distance) I am working in PHP, with a MySql Database. Open to any suggestions also! :)

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  • Full text search for irregular rapper names with Solr

    - by Horace Loeb
    I'm implementing full text search functionality on my rap website, and I'm running into some issues with rapper and song names. For example, someone might want to search for the rapper "Cam'ron" using the query "camron" (leaving out the mid-word apostrophe). Likewise, someone might search for the song "3 Peat" using the query "3peat". "The Notorious B.I.G." is a bit of a weird case: both "The Notorious BIG" and "The Notorious B.I.G." both work (I guess because the solr.StandardFilterFactory removes dots from acronyms?), but "The Notorious B.I.G" (i.e., minus the trailing dot) doesn't. Ideally all reasonable variations of these names should work. I'm guessing the answer has something to do with the solr.WordDelimiterFilterFactory, but I'm not sure. Also, I'm using Sunspot with Rails if that's relevant.

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  • WebLogic Application Server: free for developers!

    - by Bruno.Borges
    Great news! Oracle WebLogic Server is now free for developers! What does this mean for you? That you as a developer are permited to: "[...] deploy the programs only on your single developer desktop computer (of any type, including physical, virtual or remote virtual), to be used and accessed by only (1) named developer." But the most interesting part of the license change is this one: "You may continue to develop, test, prototype and demonstrate your application with the programs under this license after you have deployed the application for any internal data processing, commercial or production purposes" (Read the full license agreement here) If you want to take advantage of this licensing change and start developing Java EE applications with the #1 Application Server in the world, read now the previous post, How To Install WebLogic Zip on Linux!

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  • problem in counting children category

    - by moustafa
    I have this table: fourn_category (id , sub) I am using this code to count: function CountSub($id){ $root = array($id); $query = mysql_query("SELECT id FROM fourn_category WHERE sub = '$id'"); while( $row = mysql_fetch_array( $query, MYSQL_ASSOC ) ){ array_push($root,$row['id']); CountSub($row['id']); } return implode(",",$root); } It returns the category id as 1,2,3,4,5 to using it to count the sub by IN() But the problem is that it counts this: category 1 category 2 category 3 category 4 category 5 Category 1 has 1 child not 4. Why? How can I get all children's trees?

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