Search Results

Search found 14344 results on 574 pages for 'path'.

Page 399/574 | < Previous Page | 395 396 397 398 399 400 401 402 403 404 405 406  | Next Page >

  • Android webview cookie problem

    - by Tori
    I have a video link in a web view, on the emulator, I hear the audio and no video is displayed. I think this is an emulator issue. I tried on my Nexus One, when I click the link, it opens a new webview and tries to access the server almost immediately reverts back to the webview and does not show the video. Logcat says: WARN/ResponseProcessCookies(486): Cookie rejected: "BasicClientCookie[version=0,name=GX,domain=mail.google.com,path=/proxy/gmail/mail,expiry=Tue Mar 22 19:55:33 EDT 2011]". Illegal domain attribute "mail.google.com". Domain of origin: "android.clients.google.com" How can I fix this?

    Read the article

  • Implementing Dijkstra's Algorithm

    - by DeadMG
    I've been tasked (coursework @ university) to implement a form of path-finding. Now, in-spec, I could just implement a brute force, since there's a limit on the number of nodes to search (begin, two in the middle, end), but I want to re-use this code and came to implement Dijkstra's algorithm. I've seen the pseudo on Wikipedia and a friend wrote some for me as well, but it flat out doesn't make sense. The algorithm seems pretty simple and it's not a problem for me to understand it, but I just can't for the life of me visualize the code that would realize such a thing. Any suggestions/tips?

    Read the article

  • Location of my own directories

    - by Nicsoft
    Hello, I am trying to understand how to create my own directory tree and access it from my application. I am doing some kind of learning program and want to create a directory structure like this: -MyLessonsDirectory --LessonDirectory_1 ---Step_1 ---Step_2 ---Step_3 --LessonDirectory_2 ---Step_1 ---Step_2 ---Step_3 . . and so on In each "Step"-directory I will have specific content for that step of the lesson. The content is added by me while developing. Hence, I don't want to create the structure and content from within the application, just access it and reading the content of the directories. If I can create this kind of structure and use it it will be very easy to create a nice design that makes it easy to create new lessons in my app. What I cannot figure out is where I should create those directories in the file-structure in xCode and what is the path to those directories from my application. Thanks in advance!

    Read the article

  • RadUpload problem with firefox

    - by just_name
    Q: I use RadUpload Telerik control to upload more than image ..this control is flexible and amazing one.. it works perfectly but recently i find the following problem :: the problem appears only in firefox not IE when click on Select button in this control to select my file the button doesn't work at all ,,but when i click on the textbox(which the file path appear in)it opens the window which i can select a file from it .. i don't know what is the problem with firefox .. i wanna the default behavior to not confuse the user ,i wanna when clicking on Select button , showing a window to select my file from it like IE.. any suggestions to fix this problem please...

    Read the article

  • ASP.NET MVC thinks my virtual directory is a controller

    - by kmehta
    I have a virtual directory under my MVC website in IIS called "Files". This directory is at the same level as my Views directory. When I link to a file from my MVC app to a file under my Files directory, I get the following error: The controller for path '/Files/Images/1c7f7eb8-5d66-4bca-a73a-4ba6340a7805.JPG' was not found or does not implement IController. It thinks that my Files VD is a controller. How do I access my files like a normal VD without MVC interfering? Thanks.

    Read the article

  • Refer to te current directory in a shell script

    - by One Two Three
    How do I refer to the current directory in a shell script So I have this script which calls another script in the same directory #! /bin/sh #Call the other script ./foo.sh # do something ... For this I got ./foo.sh: No such file or directory So I changed it to: #! /bin/sh #Call the other script foo.sh # do something ... But this would call the foo script which is, by default, in the PATH. This is not what I want. So the question is, what's the syntax of doing './` in a shell script?

    Read the article

  • Powershell's import-clixml from string

    - by rocku
    Is there any way to run import-clixml cmdlet on a string or xml object? It requires a file path as input to produce ps objects and can't get input from an xml object. Since there is convertto-xml cmdlet which serializes ps object into xml object, why isn't there a convertfrom-xml, which would do the opposite? I am aware of System.Xml.Serialization.XmlSerializer class which would do just that, however I would like to stick with cmdlets to do this. Is there any way to do this with cmdlets (probably just with import-clixml), without creating temporary files?

    Read the article

  • Prevent Django from redirecting to add trailing slash

    - by konrad
    UPDATED: Sorry, it looks like it's Apache that's rewriting it for some reason, not Django. I'll investigate further and post my findings. I need to add a /xmlrpc.php to my Byteflow installation to handle an application that is written for PHP blog engines and uses this hardcoded path. For some reason Byteflow appends a slash to this URL using a 301 Moved Permanently redirect, which breaks the application. It does not do so for the /robots.txt that is configured in a similar way. Relevant lines from the project urls.py: url(r'^xmlrpc.php$', 'django_xmlrpc.views.xmlrpc_handler'), url(r'^robots.txt$', include('robots.urls')), I read that the behavior was changed in the Django codebase in commit 6852 (in 2007) to prevent redirects being done for urls that have been explicitly configured not to contain any trailing slashes. I'm using Django 1.1. I assume that once I have fixed this problem, I should be able to use this application with Byteflow, because the application uses the MetaWeblog XML-RPC API. Any clue?

    Read the article

  • php5 , how makes templates?

    - by oussama17
    I am currently developing a social network using PHP5 without any framework , I create the template by this method , every time I put the header -content -footer but I found that the previous template still there , how can I make templates with this method and show me the path to the best method to play with templates in PHP5.public function affiche($afficheTPL){ $this->registry->getObject('template')->addTemplateBit('hello', 'hellop.tpl.php'); $this->registry -> getObject('template') -> buildFromTemplates($afficheTPL.'/header.tpl.php', $afficheTPL.'/main.tpl.php', $afficheTPL.'/footer.tpl.php'); $this->registry -> getObject('template') -> parseOutput(); print $this -> registry -> getObject('template') -> getPage() -> getContentToPrint(); }

    Read the article

  • "Could not find the main class: bla.bla.yada", although specified correctly in the MANIFEST.MF

    - by Bernhard V
    Hi, I'm trying to run a .jar file with the command "java -jar Filename.jar", but I am always getting an error saying "Could not find the main class: bla.bla.yada". I build the whole application with Maven and specified a Main-Class in the MANIFEST.MF. The path in the file is correct and the class also exists at the right location in the jar. The ending .class is omitted in the MANIFEST.MF. I hope this is correct. Do you have any other hints?

    Read the article

  • javac - differences between classpath and sourcepath options

    - by Alex
    Hi, I read the Sun documentation and a lot of Q/A on SO but I'm still a little bit confuse regarding the differences between the javac options -cp and -sourcepath. Let say I have this directory structure: c:\Java\project1\src (where the .java source files are) c:\Java\project1\bin (where the .class will be or are already) The class source MainClass.java is in a package "com.mypackage" and the directory structure is ok in src. I'm in the project1 directory. I run c:\Java\Project1\javac -d bin -sourcepath src src/com/mypackage/MainClass.java or c:\Java\Project1\javac -d bin -classpath src src/com/mypackage/MainClass.java and I obtain the same result. In verbose mode, the search path for source files is src in both cases. If anybody could help me figure out the specifics of these options, it would be great. Thank you.

    Read the article

  • New NCover 3.4.2 makes all my MSTest unit tests fail

    - by Steven
    Yesterday, I decided to install the newest NCover version (3.4.2). However, when I ran it on my existing .ncover configuration file, the NCover output suddenly reported that all my MSTest tests failed. Of course those tests succeed when ran within Visual Studio. Because of this, NCover isn't able to determine any coverage. Somehow the old configuration doesn't seem to work with the new version. Does anyone have any idea what the problem could be or how to solve it? Btw. Here is my ncover configuration. Project settings: Path to application to profile: c:\Program Files\Microsoft Visual Studio 9.0\Common7\IDE\MSTest.exe Arguments for the application to profile: /testcontainer:D:\dev\MyApp\MyApp.Services.Tests.Unit\bin\Debug\MyApp.Services.Tests.Unit.dll /testcontainer:D:\dev\MyApp\MyApp.WS.Tests.Unit\bin\Debug\MyApp.WS.Tests.Unit.dll Working folder: D:\dev\MyApp

    Read the article

  • Can I start my new Career as a web application developer over an age of 32

    - by Sami
    Greetings Guys.. Iam 32 years old, I graduated from university in 2005 but from that time I didnt work in my career as a developer,and I dont have any experience in that major. My current career is software testing, but actually iam not satisfied in that job since i dont see any future for it and i dont know its path (to where will I arrive). Now i decided to take extra cources in VB.net, asp.net since I want to change my career to become webdeveloper. But 1 thing that always desturb me is that I feel that time is passed iam iam too old to become web developer. Is my feeling true?? and are there any poeple who start programing at a late age and did the succeed?? Thanks

    Read the article

  • How to use OpenCV in Python?

    - by Roman
    I have just installed OpenCV on my Windows 7 machine. As a result I get a new directory: C:\OpenCV2.2\Python2.7\Lib\site-packages In this directory I have two files: cv.lib and cv.pyd. Then I try to use the opencv from Python. I do the following: import sys sys.path.append('C:\OpenCV2.2\Python2.7\Lib\site-packages') import cv As a result I get the following error message: File "<stdin>", line 1, in <module> ImportError: DLL load failed: The specified module could not be found. What am I doing wrong? ADDED As it was recommended here, I have copied content of C:\OpenCV2.0\Python2.6\Lib\site-packages to the C:\Python26\Lib\site-packages. It did not help.

    Read the article

  • Linking Boost to my C++ project in Eclipse

    - by MahlerFive
    I'm trying to get the Boost library working in my C++ projects in Eclipse. I can successfully build when using header-only libraries in Boost such as the example simple program in the "Getting Started" guide using the lambda header. I cannot get my project to successfully link to the regex Boost library as shown later in the guide. Under my project properties - c/c++ build - settings - tool settings tab - libraries, I have added "libboost_regex" to the Libraries box, and "C:\Program Files\boost\boost_1_42_0\bin.v2\libs" to the Library search path box since this is where all the .lib files are. I've even tried adding "libboost_regex-mgw34-mt-d-1_42.lib" to the libraries box instead of "libboost_regex" since that is the exact file name, but this did not work either. I keep getting an error that says "cannot find -llibboost_regex" when I try to build my project. Any ideas as to how I can fix this?

    Read the article

  • How to Store Cookies in Ruby?

    - by viatropos
    I am programmatcally accessing authenticated content in my CDN on Google App Engine, and it's returning a cookie that I'm supposed to store: {"set-cookie"=>"ACSID=cookie-hash; expires=Mon, 12-Apr-2010 01:56:06 GMT; path=/"} What do I do with that? This is my first time dealing with Cookies. I can put in the header of the next request, but what's the recommended way to store that? I'm testing this with irb in the console and when I exit and try again, the cookie is gone. How do I save it for a few days/weeks? I'm using pure ruby without Rails or anything. Thanks so much.

    Read the article

  • How to check value of stored procedure output parameter

    - by Anna T
    I have a stored procedure that: A. inserts some rows into a "table variable" based on some joins B. selects all values from column x from that table into a string with comma separated values C. selects all from the "table variable" If I execute the procedure like this: EXEC CatalogGetFilmDetails2 2,111111; a table is returned as instructed per step C above. How can I execute it so that also the output parameter value is displayed? (see point B above). I need to check if it's calculated properly. And since the second parameter is of output type, meaning it's calculated inside the procedure, why is it mandatory to specify a value for it when executing the procedure? I normally use a random value for it, it anyway doesn't matter/impact the result. On the other hand if I try to execute it without the output parameter, it returns an error) Thank you very much! This is how the procedure starts: CREATE PROCEDURE CatalogGetFilmDetails2 (@FilmID int, @CommaSepString VARCHAR(50) OUTPUT) AS And this is how @CommaSepString is calculated: SELECT @CommaSepString = STUFF((SELECT ', ' + Categ FROM @Filme1 FOR XML PATH('')), 1,1,'')

    Read the article

  • IIS Virtual Directory/Application & Forms authentication

    - by user216194
    I've setup and deployed a simple forms authentication website with membership using .NET 4. I've created a virtual directory (now converted to "Application") in IIS7 and setup the web.config file in the virtual directory as follows: <system.webServer> <directoryBrowse enabled="true" /> </system.webServer> Great! I browse to the virtual directory: ../mydomain/books/ and I'm automatically redirected to the login page specified by web.config in my root directory and the url path is placed as follows: ../Account/Login.aspx?ReturnUrl=%2fbooks At this point, I login succesfully, but I am not redirected anywhere, and when I manually return to the directory, ../books, I'm sent back to the login page, where I'm already logged in? So I'm confused about what my problem is! I should be successfully authenticated, and than redirected back to the directory, or at the very least be able to view it manually after I log in right?

    Read the article

  • Arraylist as repeater datasource (how to access from .aspx)

    - by Phil
    I have an arraylist: Dim downloadsarray As New ArrayList downloadsarray.Add(iconlink) downloadsarray.Add(imgpath) downloadsarray.Add(filesize) downloadsarray.Add(description) Which is the datasource of my repeater: DownloadsRepeater.DataSource = downloadsarray DownloadsRepeater.DataBind() Please can you tell me how I output the items in the array to the .aspx page. I usually use (when using sqldatareader as datasource): <%#Container.DataItem("1stcolumnnamestring")%> <%#Container.DataItem("2ndcolumnnamestring")%> But this does not work when using the arraylist as datasource. Thanks. ps... I know how to use <%#Container.DataItem% to dump everything but I need to get at the items in the array individually, not have them all ditched out to the page in one go. For example, item 1 contains a link, item 2 contains an image path, item 3 contains a description. I need to have them kick out in the correct order to build the link and icon correctly.

    Read the article

  • how to use font-faces in css file within spring 3

    - by miguel.angel
    I'm trying to use font-faces inside a style.css file. I have put my style font .ttf file into resources with Spring 3. When use font-faces i need to put the path to the .ttf file like this: @font-face{ font-family: NosiferCaps-Regular; src: url('../fonts/1942/1942.ttf'); } .myClass{ font:39px/1.2 NosiferCaps-Regular, verdana ; text-shadow:2px 2px 9px gray; } So, how do I refer to "src: url('../fonts/1942/1942.ttf')" inside a style.css file with Spring?

    Read the article

  • Shell script to name videos on device

    - by Jordan
    I have a .sh script that automounts any usb device that is plugged in. I need it to also find if there are videos in a certain location on the device that is plugged in then write them to a videos.txt file. Here's what I have and its not working. Also I need it to put the mountpoint in the videos.txt file. ${MOUNTPOINT}$count is the path to the mounted device. VIDEOS=ls ${MOUNTPOINT}$count/dcim/100Video | grep mp4 if [ "$VIDEOS" -ne "" ] ; then "${MOUNTPOINT}$count" > ${MOUNTPOINT}$count/videos.txt; "$VIDEOS" >> ${MOUNTPOINT}$count/videos.txt; fi What am I doing wrong?

    Read the article

  • Javascript calls to an Ajax WebMethod. How to get multiple output params returned?

    - by George
    OK, I know how to call a simple old fashion asmx webservice webthod that returns a single value as a function return result. But what if I want to return multiple output params? My current approach is to separate the params by a dividing character and parse them on teh client. Is there a better way. Here's how I return a single function result. How do I return multiple output values? <asp:ScriptManager ID="ScriptManager1" runat="server"> <Services> <asp:ServiceReference Path="WebService.asmx" /> </Services> function CallHelloWebMethod() { WebService.Hello(OnComplete1, OnTimeOut, OnError); } function OnComplete1(arg) { alert(arg); } function OnTimeOut(arg) { } <WebMethod()> Public Function Hello(ByVal x As String) As String Return "Hello " & x End Function

    Read the article

  • yiic shell: failed to perform 'crud'

    - by ufw
    Debian Squeeze, PHP 5.3.2-1, Yii 1.1.2, PHP $path to php is /usr/bin/php, permissions are '777'. When I try to run 'crud Test' in yii shell, I get the following error message: PHP Warning: include(/var/www/test/protected/models/Test.php): failed to open stream: No such file or directory in /var/www/yii/framework/YiiBase.php on line 335 PHP Warning: include(): Failed opening '/var/www/test/protected/models/Test.php' for inclusion (include_path='.:/var/www/test/protected/components:/var/www/test/protected/models:/usr/share/php:/usr/share/pear') in /var/www/yii/framework/YiiBase.php on line 335 PHP Fatal error: Class 'Test' not found in /var/www/yii/framework/db/ar/CActiveRecord.php on line 341

    Read the article

  • accessing pdf via https URL

    - by Paul
    I send out a newsletter email containing URLs to a https website that then redirects to a pdf document. On first invocation of a URL the user is prompted with the typical https browser "security alert" popup, on selecting "Yes" the display of the PDF fails. The HTTP Header on the failed response is: HTTP/1.1 200 OK Server: ECS/HTTP-Server Date: Tue, 16 Mar 2010 15:57:26 GMT Content-type: application/pdf Content-language: en-US Set-cookie: JSESSIONID=0000r111cRz1Vc-PtCJg8Cdu4eR:-1; Path=/ Expires: Thu, 01 Dec 1994 16:00:00 GMT Cache-control: no-cache="set-cookie, set-cookie2" Connection: close Subsequent invocations of the URL successfully opens the PDF (at this point we have the session id cookie set by the initial failed request). The HTTP Header on the successful response is: HTTP/1.1 200 OK Server: ECS/HTTP-Server Date: Tue, 16 Mar 2010 16:53:03 GMT Content-type: application/pdf Content-language: en-US Connection: close The email client is Lotus Notes 6.5 which launches an IE6 browser Any ideas?

    Read the article

  • How to read information from .3gp and .mp4 using ffmpeg-php?

    - by Neltharian
    I have a bit of a problem with ffmpeg-php. I'm trying to get some information from video files and it works pretty fine with file formats like .avi, .mpg or .flv but when I try to use .3gp or .mp4 in: $movie = new ffmpeg_movie('path/to/file/test.3gp'); I get error like this : ffmpeg_movie::__construct() []: ISO: File Type Major Brand: 3gp5 or ffmpeg_movie::__construct() []: ISO: File Type Major Brand: mp42 I installed ffmpeg-php on WAMP using instructions found here: http://stackoverflow.com/questions/1172916/how-to-install-ffmpeg-in-wampserver-2-0-windows-xp I need those information to send them to ffmpeg using exec(). Anyone could help me with this?

    Read the article

< Previous Page | 395 396 397 398 399 400 401 402 403 404 405 406  | Next Page >