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  • How-to delete a tree node using the context menu

    - by frank.nimphius
    Hierarchical trees in Oracle ADF make use of View Accessors, which means that only the top level node needs to be exposed as a View Object instance on the ADF Business Components Data Model. This also means that only the top level node has a representation in the PageDef file as a tree binding and iterator binding reference. Detail nodes are accessed through tree rule definitions that use the accessor mentioned above (or nested collections in the case of POJO or EJB business services). The tree component is configured for single node selection, which however can be declaratively changed for users to press the ctrl key and selecting multiple nodes. In the following, I explain how to create a context menu on the tree for users to delete the selected tree nodes. For this, the context menu item will access a managed bean, which then determines the selected node(s), the internal ADF node bindings and the rows they represent. As mentioned, the ADF Business Components Data Model only needs to expose the top level node data sources, which in this example is an instance of the Locations View Object. For the tree to work, you need to have associations defined between entities, which usually is done for you by Oracle JDeveloper if the database tables have foreign keys defined Note: As a general hint of best practices and to simplify your life: Make sure your database schema is well defined and designed before starting your development project. Don't treat the database as something organic that grows and changes with the requirements as you proceed in your project. Business service refactoring in response to database changes is possible, but should be treated as an exception, not the rule. Good database design is a necessity – even for application developers – and nothing evil. To create the tree component, expand the Data Controls panel and drag the View Object collection to the view. From the context menu, select the tree component entry and continue with defining the tree rules that make up the hierarchical structure. As you see, when pressing the green plus icon  in the Edit Tree Binding  dialog, the data structure, Locations -  Departments – Employees in my sample, shows without you having created a View Object instance for each of the nodes in the ADF Business Components Data Model. After you configured the tree structure in the Edit Tree Binding dialog, you press OK and the tree is created. Select the tree in the page editor and open the Structure Window (ctrl+shift+S). In the Structure window, expand the tree node to access the conextMenu facet. Use the right mouse button to insert a Popup  into the facet. Repeat the same steps to insert a Menu and a Menu Item into the Popup you created. The Menu item text should be changed to something meaningful like "Delete". Note that the custom menu item later is added to the context menu together with the default context menu options like expand and expand all. To define the action that is executed when the menu item is clicked on, you select the Action Listener property in the Property Inspector and click the arrow icon followed by the Edit menu option. Create or select a managed bean and define a method name for the action handler. Next, select the tree component and browse to its binding property in the Property Inspector. Again, use the arrow icon | Edit option to create a component binding in the same managed bean that has the action listener defined. The tree handle is used in the action listener code, which is shown below: public void onTreeNodeDelete(ActionEvent actionEvent) {   //access the tree from the JSF component reference created   //using the af:tree "binding" property. The "binding" property   //creates a pair of set/get methods to access the RichTree instance   RichTree tree = this.getTreeHandler();   //get the list of selected row keys   RowKeySet rks = tree.getSelectedRowKeys();   //access the iterator to loop over selected nodes   Iterator rksIterator = rks.iterator();          //The CollectionModel represents the tree model and is   //accessed from the tree "value" property   CollectionModel model = (CollectionModel) tree.getValue();   //The CollectionModel is a wrapper for the ADF tree binding   //class, which is JUCtrlHierBinding   JUCtrlHierBinding treeBinding =                  (JUCtrlHierBinding) model.getWrappedData();          //loop over the selected nodes and delete the rows they   //represent   while(rksIterator.hasNext()){     List nodeKey = (List) rksIterator.next();     //find the ADF node binding using the node key     JUCtrlHierNodeBinding node =                       treeBinding.findNodeByKeyPath(nodeKey);     //delete the row.     Row rw = node.getRow();       rw.remove();   }          //only refresh the tree if tree nodes have been selected   if(rks.size() > 0){     AdfFacesContext adfFacesContext =                          AdfFacesContext.getCurrentInstance();     adfFacesContext.addPartialTarget(tree);   } } Note: To enable multi node selection for a tree, select the tree and change the row selection setting from "single" to "multiple". Note: a fully pictured version of this post will become available at the end of the month in a PDF summary on ADF Code Corner : http://www.oracle.com/technetwork/developer-tools/adf/learnmore/index-101235.html 

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  • C++ find largest BST in a binary tree

    - by fonjibe
    what is your approach to have the largest BST in a binary tree? I refer to this post where a very good implementation for finding if a tree is BST or not is bool isBinarySearchTree(BinaryTree * n, int min=std::numeric_limits<int>::min(), int max=std::numeric_limits<int>::max()) { return !n || (min < n->value && n->value < max && isBinarySearchTree(n->l, min, n->value) && isBinarySearchTree(n->r, n->value, max)); } It is quite easy to implement a solution to find whether a tree contains a binary search tree. i think that the following method makes it: bool includeSomeBST(BinaryTree* n) { if(!isBinarySearchTree(n)) { if(!isBinarySearchTree(n->left)) return isBinarySearchTree(n->right); } else return true; else return true; } but what if i want the largest BST? this is my first idea, BinaryTree largestBST(BinaryTree* n) { if(isBinarySearchTree(n)) return n; if(!isBinarySearchTree(n->left)) { if(!isBinarySearchTree(n->right)) if(includeSomeBST(n->right)) return largestBST(n->right); else if(includeSomeBST(n->left)) return largestBST(n->left); else return NULL; else return n->right; } else return n->left; } but its not telling the largest actually. i struggle to make the comparison. how should it take place? thanks

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  • Open source LINQ search engine for website

    - by Noel
    I want to add a search engine to my website. I want it to handler boolean searches and give me a list of results in order or best match. I need it to be able to work with LINQ, because I want to add additional where clauses to the final query that gets run. I am looking for the best open source .NET search engine that works with LINQ. I like lucene.net but the problem is the LINQ interface (LINQ to Lucene) hasn't been updated since 2008. Are there any good options out there?

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  • Find kth smallest element in a binary search tree in Optimum way

    - by Bragaadeesh
    Hi, I need to find the kth smallest element in the binary search tree without using any static/global variable. How to achieve it efficiently? The solution that I have in my mind is doing the operation in O(n), the worst case since I am planning to do an inorder traversal of the entire tree. But deep down I feel that I am not using the BST property here. Is my assumptive solution correct or is there a better one available ?

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  • Transform Search String into FullText Compatible Search String?

    - by Alex
    I'm working with the fulltext search engine of MSSQL 2008 which expects a search string like this: ("keyword1" AND "keyword2*" OR "keyword3") My users are entering things like this: engine 2009 "san francisco" hotel december xyz stuff* "in miami" 1234 something or "something else" I'm trying to transform these into fulltext engine compatible strings like these: ("engine" AND "2009") ("san francisco" AND "hotel" AND "december" AND "xyz") ("stuff*" "in miami" "1234") ("something" OR "something else") I have a really difficult time with this, tried doing it using counting quotation marks, spaces and inserting etc. but my code looks like horrible for-and-if vomit. Can someone help?

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  • Event Driven Behavior Tree: deterministic traversal order with parallel

    - by Heisenbug
    I've studied several articles and listen some talks about behavior trees (mostly the resources available on AIGameDev by Alex J. Champandard). I'm particularly interested on event driven behavior trees, but I have still some doubts on how to implement them correctly using a scheduler. Just a quick recap: Standard Behavior Tree Each execution tick the tree is traversed from the root in depth-first order The execution order is implicitly expressed by the tree structure. So in the case of behaviors parented to a parallel node, even if both children are executed during the same traversing, the first leaf is always evaluated first. Event Driven BT During the first traversal the nodes (tasks) are enqueued using a scheduler which is responsible for updating only running ones every update The first traversal implicitly produce a depth-first ordered queue in the scheduler Non leaf nodes stays suspended mostly of the time. When a leaf node terminate(either with success or fail status) the parent (observer) is waked up allowing the tree traversing to continue and new tasks will be enqueued in the scheduler Without parallel nodes in the tree there will be up to 1 task running in the scheduler Without parallel nodes, the tasks in the queue(excluding dynamic priority implementation) will be always ordered in a depth-first order (is this right?) Now, from what is my understanding of a possible implementation, there are 2 requirements I think must be respected(I'm not sure though): Now, some requirements I think needs to be guaranteed by a correct implementation are: The result of the traversing should be independent from which implementation strategy is used. The traversing result must be deterministic. I'm struggling trying to guarantee both in the case of parallel nodes. Here's an example: Parallel_1 -->Sequence_1 ---->leaf_A ---->leaf_B -->leaf_C Considering a FIFO policy of the scheduler, before leaf_A node terminates the tasks in the scheduler are: P1(suspended),S1(suspended),leaf_A(running),leaf_C(running) When leaf_A terminate leaf_B will be scheduled (at the end of the queue), so the queue will become: P1(suspended),S1(suspended),leaf_C(running),leaf_B(running) In this case leaf_B will be executed after leaf_C at every update, meanwhile with a non event-driven traversing from the root node, the leaf_B will always be evaluated before leaf_A. So I have a couple of question: do I have understand correctly how event driven BT work? How can I guarantee the depth first order is respected with such an implementation? is this a common issue or am I missing something?

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  • Search predictions broken in Chrome - reinstall didn't solve the problem

    - by Shimmy
    I recently changed the default search engine to a custom google search URL (using baseUrl) with some additional parameters and removed all the rest of the search engines, and since then, the search predictions stopped working. I even tried to reinstall Chrome but as soon as I resync, the problem is back! Search predictions are just gone without option to fix!! In IE changing the search provider allows specifying a prediction (suggestion) provider, In chrome, once you change the default search engine, you'll never be able to have predictions again!! This is a terrible bug, I mean WTF!!! Is there any workaround to that? I posted a bug report a while ago but it seems no one looks at it. I'm about to give up on Chrome and go back to IE, the only good thing about Chrome is the Extension market and the AdBlocker (which I can find in IE as well). The perfrormance changes don't matter to me too much. Thanks

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  • What is the kd tree intersection logic?

    - by bobobobo
    I'm trying to figure out how to implement a KD tree. On page 322 of "Real time collision detection" by Ericson The text section is included below in case Google book preview doesn't let you see it the time you click the link text section Relevant section: The basic idea behind intersecting a ray or directed line segment with a k-d tree is straightforward. The line is intersected against the node's splitting plane, and the t value of intersection is computed. If t is within the interval of the line, 0 <= t <= tmax, the line straddles the plane and both children of the tree are recursively descended. If not, only the side containing the segment origin is recursively visited. So here's what I have: (open image in new tab if you can't see the lettering) The logical tree Here the orange ray is going thru the 3d scene. The x's represent intersection with a plane. From the LEFT, the ray hits: The front face of the scene's enclosing cube, The (1) splitting plane The (2.2) splitting plane The right side of the scene's enclosing cube But here's what would happen, naively following Ericson's basic description above: Test against splitting plane (1). Ray hits splitting plane (1), so left and right children of splitting plane (1) are included in next test. Test against splitting plane (2.1). Ray actually hits that plane, (way off to the right) so both children are included in next level of tests. (This is counter-intuitive - shouldn't only the bottom node be included in subsequent tests) Can some one describe what happens when the orange ray goes through the scene correctly?

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  • C++ design question on traversing binary trees

    - by user231536
    I have a binary tree T which I would like to copy to another tree. Suppose I have a visit method that gets evaluated at every node: struct visit { virtual void operator() (node* n)=0; }; and I have a visitor algorithm void visitor(node* t, visit& v) { //do a preorder traversal using stack or recursion if (!t) return; v(t); visitor(t->left, v); visitor(t->right, v); } I have 2 questions: I settled on using the functor based approach because I see that boost graph does this (vertex visitors). Also I tend to repeat the same code to traverse the tree and do different things at each node. Is this a good design to get rid of duplicated code? What other alternative designs are there? How do I use this to create a new binary tree from an existing one? I can keep a stack on the visit functor if I want, but it gets tied to the algorithm in visitor. How would I incorporate postorder traversals here ? Another functor class?

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  • What is validating a binary search tree?

    - by dotnetdev
    I read on here of an exercise in interviews known as validating a binary search tree. How exactly does this work? What would one be looking for in validating a binary search tree? I have written a basic search tree, but never heard of this concept. Thanks

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  • Singular or Plural Nouns as file names for better Search & SEO friendlyness? [closed]

    - by Sam
    Possible Duplicate: Should I use singular or plural nouns in a domain name and why? Dear folks, two scenarios where file names should be best representing the search volume by audiences searching for it. Scenario 1 website.org/en/logo.php website.org/en/brochure.php website.org/en/poster.php website.org/en/design.php OR Scenario 2 website.org/en/logos.php website.org/en/brochures.php website.org/en/posters.php website.org/en/designs.php Q1. What do you intuitivly think would be the best? Q2. What do the facts in general show? people search for singular or plural in search? Q3. Do Search engines have common rule of thumb for this? Q4. Should I pick either and go with either scenario consistently or does it depend on the word? Thanks very much for your ideas/suggestions. I reall don't know which one to go for.

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  • Algorithm for parsing a flat tree into a non-flat tree

    - by Chad Johnson
    I have the following flat tree: id name parent_id is_directory =========================================================== 50 app 0 1 31 controllers 50 1 11 application_controller.rb 31 0 46 models 50 1 12 test_controller.rb 31 0 31 test.rb 46 0 and I am trying to figure out an algorithm for getting this into the following tree structuree: [{ id: 50, name: app, is_directory: true children: [{ id: 31, name: controllers, is_directory: true, children: [{ id: 11, name: application_controller.rb is_directory: false },{ id: 12, name: test_controller.rb, is_directory: false }], },{ id: 46, name: models, is_directory: true, children: [{ id: 31, name: test.rb, is_directory: false }] }] }] Can someone point me in the right direction? I'm looking for steps (eg. build an associative array; loop through the array looking for x; etc.).

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  • Google Sites page never shows up in Google Search organic results?

    - by gus
    I use Google Sites (i.e.: https://sites.google.com/site/EXAMPLE/ ) as a convenient way to maintain up-to-date info on several residential properties, info that's often requested by my property agents, its been around for about 1 year, but I still can never get it to appear in organic Google search results or Bing, even if I search the specific keywords such as the street names. I submitted the URL manually to search engines, knowing that my Sites page probably has very few incoming links. Is this expected behavior? The content of my page has simple formatted text, and outgoing links to Picasa/G+/imgur photo albums. Am I doing something wrong or do all GoogleSites pages have poor organic search rank? Thank you very much.

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  • Why my website doesn't appear in Google search results? [duplicate]

    - by cyrfandli
    This question already has an answer here: What are the best ways to increase a site's position in Google? 20 answers Why aren't search engines indexing my content? 1 answer I've made a simple website for a friend's bakery and it doesn't appear in Google's search results even if I search for the whole domain name of the site. What can be the problem? How to make it appear? (The site)

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  • Can a binary tree or tree be always represented in a Database as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Can a binary tree or tree be always represented in a Database table as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person under him can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Implementation of Race Game Tree

    - by Mert Toka
    I build a racing game right in OpenGL using Glut, and I'm a bit lost in all the details. First of all, any suggestions as a road map would be more than great. So far what I thought is this: Tree implementation for transformations. Simulated dynamics.(*) Octree implementation for collusion detection. Actual collusion detection.(*) Modelling in Maya and export them as .OBJs. Polishing the game with GLSL or something like that for graphics quality. (*): I am not sure the order of these two. So I started with the simulated dynamics without tree, and it turned out to be a huge chaos for me. Is there any way you can think of such that could help me to build such tree to use in racing game? I thought something like this but I have no idea how to implement it. Reds are static, yellows are dynamic nodes

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  • How to take search query and append modifers to the end of it

    - by Kimber
    This is a greasemonkey question. What I'm trying to do is modify an old google discussions script. What were wanting to do is be able to take the google search query and add modifiers to the end of it. Like this: search query: "superuser" modifiers: inurl:greasemonkey+question end result: "superuser" inurl:greasemonkey+question The old script creates a new div within the "hdtb_more_mn" element which is where you get the new discussions tab. However, since the "tbm=dsc" option to do a discussion search has died, this script no longer works. Hence the need to add modifiers to your searches. I tried to edit the script, but it appends the modifiers to the end of the url which includes "&client=firefox-a&hs=8uS&rls=org.mozilla:en-US:official". This means you're also searching for the above as well as your query, which doesn't work. I would like to be able to append the modifiers @ the end of the search querty, rather than the whole URL. I'm just not sure how to code it to where it adds the below "&tbm=" stuff within "discussionDiv.innerHTML" to the end of the query. The google search id seems to be, "gbqfq" for the search box, but I'm not sure how to add this id. Here is the old script // ==UserScript== // @name Add Back Google Discussions // @version 1.4 // @description Adds back the Discussion filters to Google Search // @include *://*.google.tld/search* // ==/UserScript== var url = location.href; if (url.indexOf('tbm=dsc') < 0) addFilterType('dsc', 'Discussions'); function addFilterType(val, name) { var searchType = document.getElementById('hdtb_more_mn'); var discussionDiv = document.createElement('DIV'); discussionDiv.className = 'hdtb_mitem'; discussionDiv.innerHTML = '<a class="q qs" href="'+ (url.replace(/&tbm=[^&]*/g,'') + '&tbm=' + val) +'">'+name+'</a>'; searchType.innerHTML += discussionDiv.outerHTML; } Thanks for any help, or suggestions on who to ask. Google Chrome has an extension for discussion searches, but FF doesn't seem to have one as of yet, which is why I'm trying to modify the above.

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  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

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  • Adding UCM as a search source in Windows Explorer

    - by kyle.hatlestad
    A customer recently pointed out to me that Windows 7 supports federated search within Windows Explorer. This means you can perform searches to external sources such as Google, Flickr, YouTube, etc right from within Explorer. While we do have the Desktop Integration Suite which offers searching within Explorer, I thought it would be interesting to look into this method which would not require any client software to implement. Basically, federated searching hooks up in Windows Explorer through the OpenSearch protocol. A Search Connector Descriptor file is run and it installs the search provider. The file is a .osdx file which is an OpenSearch Description document. It describes the search provider you are hooking up to along with the URL for the query. If those results can come back as an RSS or ATOM feed, then you're all set. So the first step is to install the RSS Feeds component from the UCM Samples page on OTN. If you're on 11g, I've found the RSS Feeds works just fine on that version too. Next, you want to perform a Quick Search with a particular search term and then copy the RSS link address for that search result. Here is what an example URL might looks like: http://server:16200/cs/idcplg?IdcService=GET_SCS_FEED&feedName=search_results&QueryText=%28+%3cqsch%3eoracle%3c%2fqsch %3e+%29&SortField=dInDate&SortOrder=Desc&ResultCount=20&SearchQueryFormat= Universal&SearchProviders=server& Now you want to create a new text file and start out with this information: <?xml version="1.0" encoding="UTF-8"?><OpenSearchDescription xmlns:ms-ose="http://schemas.microsoft.com/opensearchext/2009/"> <ShortName></ShortName> <Description></Description> <Url type="application/rss+xml" template=""/> <Url type="text/html" template=""/> </OpenSearchDescription> Enter a ShortName and Description. The ShortName will be the value used when displaying the search provider in Explorer. In the template attribute for the first Url element, enter the URL copied previously. You will then need to convert the ampersand symbols to '&' to make them XML compliant. Finally, you'll want to switch out the search term with '{searchTerms}'. For the second Url element, you can do the same thing except you want to copy the UCM search results URL from the page of results. That URL will look something like: http://server:16200/cs/idcplg?IdcService=GET_SEARCH_RESULTS&SortField=dInDate&SortOrder=Desc&ResultCount=20&QueryText=%3Cqsch%3Eoracle%3C%2Fqsch%3E&listTemplateId= &ftx=1&SearchQueryFormat=Universal&TargetedQuickSearchSelection= &MiniSearchText=oracle Again, convert the ampersand symbols and replace the search term with '{searchTerms}'. When complete, save the file with the .osdx extension. The completed file should look like: <?xml version="1.0" encoding="UTF-8"?> <OpenSearchDescription xmlns="http://a9.com/-/spec/opensearch/1.1/" xmlns:ms-ose="http://schemas.microsoft.com/opensearchext/2009/"> <ShortName>Universal Content Management</ShortName> <Description>OpenSearch for UCM via Windows 7 Search Federation.</Description> <Url type="application/rss+xml" template="http://server:16200/cs/idcplg?IdcService=GET_SCS_FEED&amp;feedName=search_results&amp;QueryText=%28+%3Cqsch%3E{searchTerms}%3C%2fqsch%3E+%29&amp;SortField=dInDate&amp;SortOrder=Desc&amp;ResultCount=200&amp;SearchQueryFormat=Universal"/> <Url type="text/html" template="http://server:16200/cs/idcplg?IdcService=GET_SEARCH_RESULTS&amp;SortField=dInDate&amp;SortOrder=Desc&amp;ResultCount=20&amp;QueryText=%3Cqsch%3E{searchTerms}%3C%2Fqsch%3E&amp;listTemplateId=&amp;ftx=1&amp;SearchQueryFormat=Universal&amp;TargetedQuickSearchSelection=&amp;MiniSearchText={searchTerms}"/> </OpenSearchDescription> After you save the file, simply double-click it to create the provider. It will ask if you want to add the search connector to Windows. Click Add and it will add it to the Searches folder in your user folder as well as your Favorites. Now just click on the search icon and in the upper right search box, enter your term. As you are typing, it begins executing searches and the results will come back in Explorer. Now when you double-click on an item, it will try and download the web viewable for viewing. You also have the ability to save the search, just as you would in UCM. And there is a link to Search On Website which will launch your browser and go directly to the search results page there. And with some tweaks to the RSS component, you can make the results a bit more interesting. It supports the Media RSS standard, so you can pass along the thumbnail of the documents in the results. To enable this, edit the rss_resources.htm file in the RSS Feeds component. In the std_rss_feed_begin resource include, add the namespace 'xmlns:media="http://search.yahoo.com/mrss/' to the rss definition: <rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:sy="http://purl.org/rss/1.0/modules/syndication/" xmlns:media="http://search.yahoo.com/mrss/"> Next, in the rss_channel_item_with_thumb include, below the closing image element, add this element: </images> <media:thumbnail url="<$if strIndexOf(thumbnailUrl, "@t") > 0 or strIndexOf(thumbnailUrl, "@g") > 0 or strIndexOf(thumbnailUrl, "@p") > 0$><$rssHttpHost$><$thumbnailUrl$><$elseif dGif$><$HttpWebRoot$>images/docgifs/<$dGif$><$endif$>" /> <description> This and lots of other tweaks can be done to the RSS component to help extend it for optimum use in Explorer. Hopefully this can get you started. *Note: This post also applies to Universal Records Management (URM).

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  • Do dconf use EXI binary XML?

    - by Hibou57
    A question came to my mind reading an answer to the question What are the differences between gconf and dconf?. In an reply to the above question, Oli said: Binary read access is far faster than parsing XML. However, there exist a W3C recommendation for binary XML, since 2010: Efficient XML Interchange (EXI) Format 1.0. Is this what dconf uses? If Yes, where is it confirmed? If No, was there some investigations toward it at some time, and what was the conclusions? Thanks for any tracks, I'm curious to know.

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  • Binary on the Coat of Arms of the Governor General of Canada

    - by user132636
    Can you help me further this investigation? Here is about 10% of the work I have done on it. I present it only to see if there are any truly curious people among you. I made a video a few weeks ago showing some strange things about the Governor General's Coat of Arms and the binary on it. Today, I noticed something kinda cool and thought I would share. Here is the binary as it appears on the COA: 110010111001001010100100111010011 As DEC: 6830770643 (this is easily found on the web) Take a close look at that number. What do you notice about it? It has a few interesting features, but here is the one no one has pointed out... Split it down the middle and you have 68307 70643. The first digit is double the value of the last digit. The second digit is double the second last digit. The third digit is half of the third to last digit. And the middle ones are even or neutral. At first, I thought of it as energy. ++-nnnn+-- But actually you can create something else with it using the values. 221000211. See how that works. You may be asking why that is significant. Bare with me. I know 99% are rolling their eyes. 221000211 as base3 gives you this as binary: 100011101000111 100011101000111 as HEX is 4747, which converts to "GG". Initials of Governor General. GG.ca is his website. When you convert to base 33 (there are 33 digits in the original code) you get "GOV" Interesting? :D There is a lot more to it. I'll continue to show some strange coincidences if anyone is interested. Sorry if I am not explaining this correctly. By now you have probably figured out that I have no background in this. Which is why I am here. Thank you.

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