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  • Copying content on webpages in safari. To HTML

    - by Carl Smith
    Hi, is there an easier way to copy and paste website content in html? Want to copy and look like this. Product Information: Length: S / M / L Material: Polyester and Elasthane Brand: Roxana Exclusive Style: Basque But when i paste it into my content box it looks like this- Product Information Length: S / M / L Material: Polyester and Elasthane Brand: Roxana Exclusive Style: Basque Then i need to edit it in the html editor to rearrange it. Is the some sort of app or plugin that i can get so i can turn the text of the page into html so it looks right straight away when i copy it into my content box? If that makes any sense? Thanks Carl Smith :-)

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  • Gateway IP Returns to Zero

    - by Robert Smith
    When you set a static IP under Ubuntu 12.04.1, you must supply the desired machine IP and the gateway IP, all using the Network Manager. When I first entered them and rebooted, everything worked great. On the second boot, however, Firefox could find no Web page. Upon checking, I discovered that the gateway IP had returned to zero. Now, no matter how often I resupply it, it returns to zero immediately after NM "saves" it: that is, appears as zero when redisplayed. The only way I can get to the Internet is to restore DHCP operation. I need to use static IP for access to my home network. Would appreciate any suggestion. --Robert Smith

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  • OT: Airlines and Podcasts

    - by Greg Low
    Those that know me know that I spend an inordinate amount of time on airlines. I also love podcasts, as you can tell from my www.sqldownunder.com site and show. So anything that combines the two is just awesome. Fly With Joe fits that perfectly. Joe D'Eon provides great insights in his show. I was sad last year that he hadn't posted many shows. I've also been quiet for a couple of months (but that's about to change with a bunch of SQL Server 2008 R2 shows). But I've been so pleased that Joe's got...(read more)

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  • Ways to ensure unique instances of a class?

    - by Peanut
    I'm looking for different ways to ensure that each instance of a given class is a uniquely identifiable instance. For example, I have a Name class with the field name. Once I have a Name object with name initialised to John Smith I don't want to be able to instantiate a different Name object also with the name as John Smith, or if instantiation does take place I want a reference to the orginal object to be passed back rather than a new object. I'm aware that one way of doing this is to have a static factory that holds a Map of all the current Name objects and the factory checks that an object with John Smith as the name doesn't already exist before passing back a reference to a Name object. Another way I could think of off the top of my head is having a static Map in the Name class and when the constructor is called throwing an exception if the value passed in for name is already in use in another object, however I'm aware throwing exceptions in a constructor is generally a bad idea. Are there other ways of achieving this?

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  • Join me on MSDN Radio next Monday Mark your calendar.

    Announcement: MSDN Radio: The ASP.NET Developer Evolved with Joe Stagner Event ID: 1032448575 Date: Monday, April 12, 2010 9:00 AM Pacific Time (US & Canada) 30 Minutes Event Overview You may know him as Mr. How Do I with Microsoft ASP.NET. For the last few years Joe has been busy working with the ASP.NET product team to simplify and educate developers on what's possible with the latest web tools. We talk with Joe about how the web developer is able to learn about and leverage new tools...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Lenovo Y570 nVidia drivers are giving me problems. (GT 555)

    - by Joe
    So, I've tried the bumblebee "hack" listed HERE:https://github.com/Bumblebee-Project/bbswitch/tree/hack-lenovo I copied every line below into the terminal, is that what I was supposed to do? I'm a Linux noob. git clone http://github.com/Bumblebee-Project/bbswitch.git -b hack-lenovo cd bbswitch mkdir /usr/src/acpi-handle-hack-0.0.1 cp Makefile acpi-handle-hack.c /usr/src/acpi-handle-hack-0.0.1 cp dkms/acpi-handle-hack.conf /usr/src/acpi-handle-hack-0.0.1/dkms.conf dkms add acpi-handle-hack/0.0.1 dkms build acpi-handle-hack/0.0.1 dkms install acpi-handle-hack/0.0.1 echo acpi-handle-hack | sudo tee -a /etc/modules sudo update-initramfs -u (had to use http:// instead of git://, in my uni) It doesn't change anything, I get joe@ubuntu:~$ optirun glxspheres [ 4447.830749] [ERROR]Cannot access secondary GPU - error: Could not load GPU driver [ 4447.830844] [ERROR]Aborting because fallback start is disabled.

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  • Ubuntu One not syncing and not providing feedback

    - by Joe
    Firstly, I apologize for not being more specific with my problem, but Ubuntu One is just not providing me with any information. It appears to be working, it states that "syncronization in progress..." but it never actually syncronizes (by never I mean 3 days). When I first selected a folder to sync using Ubuntu One it took on the order of hours to sync over 500MB of files - it uploaded the folder hierarchy first and populated the folders over a few hours. That is not happening at all now. Please let me know if there is a way I can get more information out of Ubuntu One that I can post and hopefully resolve this issue. Thanks, Joe

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  • Gnome Shell opens as classic

    - by Joe Horgan
    I'm running 12.04 on a Gateway LT4004u netbook, and I installed Gnome3 using the apt-get commands in the terminal. When I rebooted and ran "Gnome Shell" it opened up classic mode. I thought that my cursor might have slipped the first time, but on multiple retries logging in under gnome shell would open the gnome classic desktop. I even uninstalled Gnome Shell and reinstalled it with software center, but I still have the same problem. I was wondering if this might be an issue with my graphics card? Any help would be much appreciated, thanks! -Joe

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  • Copying VBoxAdditions to usr/share/virtualbox folder

    - by Joe
    Since for some reason VBox does not find the Additions on the internet, I was trying to install them in the Ubuntu directory Vbox is looking for them - which is: usr/share/virtualbox but I am denied permission to do so. Any way around it? I am relatively new to ubuntu (know how to use the GUI, but still learning how to talk to the machine proper, so many things will be new to me; used to be power user/analyst for MS Windows, 98-Vista, so not a PC newbie, but still I'd say Linux newbie). Any suggestion is more than welcome! Thanks Joe

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  • What is the effect of this order_by clause?

    - by bread
    I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

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  • hierachical query to return final row

    - by jeff
    I have a hierarchical query that doesn't return an expected row (employee badge = 444). TABLE: hr_data badge fname supervisor_badge 111 Jeff 222 222 Joe 333 333 John 444 444 Tom 444 SQL: SELECT CONNECT_BY_ISCYCLE As IC, badge, fname, supervisor_badge FROM hr_data START WITH badge = '111' CONNECT BY NOCYCLE badge = PRIOR supervisor_badge What is Returned: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 1 333 John 444 What is Expected: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 **0** 333 John 444 **1** 444 Tom 444 How can I get this query to return the employee Tom and then stop?

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  • Twitter User/Search Feature Header Support in LINQ to Twitter

    - by Joe Mayo
    LINQ to Twitter’s goal is to support the entire Twitter API. So, if you see a new feature pop-up, it will be in-queue for inclusion. The same holds for the new X-Feature… response headers for User/Search requests.  However, you don’t have to wait for a special property on the TwitterContext to access these headers, you can just use them via the TwitterContext.ResponseHeaders collection. The following code demonstrates how to access the new X-Feature… headers with LINQ to Twitter: var user = (from usr in twitterCtx.User where usr.Type == UserType.Search && usr.Query == "Joe Mayo" select usr) .FirstOrDefault(); Console.WriteLine( "X-FeatureRateLimit-Limit: {0}\n" + "X-FeatureRateLimit-Remaining: {1}\n" + "X-FeatureRateLimit-Reset: {2}\n" + "X-FeatureRateLimit-Class: {3}\n", twitterCtx.ResponseHeaders["X-FeatureRateLimit-Limit"], twitterCtx.ResponseHeaders["X-FeatureRateLimit-Remaining"], twitterCtx.ResponseHeaders["X-FeatureRateLimit-Reset"], twitterCtx.ResponseHeaders["X-FeatureRateLimit-Class"]); The query above is from the User entity, whose type is Search; allowing you to search for the Twitter user whose name is specified by the Query parameter filter. After materializing the query, with FirstOrDefault, twitterCtx will hold all of the headers, including X-Feature… that Twitter returned.  Running the code above will display results similar to the following: X-FeatureRateLimit-Limit: 60 X-FeatureRateLimit-Remaining: 59 X-FeatureRateLimit-Reset: 1271452177 X-FeatureRateLimit-Class: namesearch In addition to getting the X-Feature… headers a capability you might have noticed is that the TwitterContext.ResponseHeaders collection will contain any HTTP that Twitter sends back to a query. Therefore, you’ll be able to access new Twitter headers anytime in the future with LINQ to Twitter. @JoeMayo

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  • Tricky SQL query involving consecutive values

    - by Gabriel
    I need to perform a relatively easy to explain but (given my somewhat limited skills) hard to write SQL query. Assume we have a table similar to this one: exam_no | name | surname | result | date ---------+------+---------+--------+------------ 1 | John | Doe | PASS | 2012-01-01 1 | Ryan | Smith | FAIL | 2012-01-02 <-- 1 | Ann | Evans | PASS | 2012-01-03 1 | Mary | Lee | FAIL | 2012-01-04 ... | ... | ... | ... | ... 2 | John | Doe | FAIL | 2012-02-01 <-- 2 | Ryan | Smith | FAIL | 2012-02-02 2 | Ann | Evans | FAIL | 2012-02-03 2 | Mary | Lee | PASS | 2012-02-04 ... | ... | ... | ... | ... 3 | John | Doe | FAIL | 2012-03-01 3 | Ryan | Smith | FAIL | 2012-03-02 3 | Ann | Evans | PASS | 2012-03-03 3 | Mary | Lee | FAIL | 2012-03-04 <-- Note that exam_no and date aren't necessarily related as one might expect from the kind of example I chose. Now, the query that I need to do is as follows: From the latest exam (exam_no = 3) find all the students that have failed (John Doe, Ryan Smith and Mary Lee). For each of these students find the date of the first of the batch of consecutively failing exams. Another way to put it would be: for each of these students find the date of the first failing exam that comes after their last passing exam. (Look at the arrows in the table). The resulting table should be something like this: name | surname | date_since_failing ------+---------+-------------------- John | Doe | 2012-02-01 Ryan | Smith | 2012-01-02 Mary | Lee | 2012-01-04 Ann | Evans | 2012-02-03 How can I perform such a query? Thank you for your time.

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  • How do I correctly organize output into columns?

    - by wrongusername
    The first thing that comes to my mind is to do a bunch of \t's, but that would cause words to be misaligned if any word is longer than any other word by a few characters. For example, I would like to have something like: Name Last Name Middle initial Bob Jones M Joe ReallyLongLastName T Instead, by including only "\t"'s in my cout statement I can only manage to get Name Last Name Middle initial Bob Jones M Joe ReallyLongLastName T or Name Last Name Middle initial Bob Jones M Joe ReallyLongLastName T What else would I need to do?

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  • Odd SQL Results

    - by Ryan Burnham
    So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

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  • Receiving an MVP Award and Credibility

    - by Joe Mayo
    The post titled, The Problem with MVPs, by Steve Barbour was interesting because it makes you think about the thousands of MVPs around the world and what their value really is. Having been the recipient of multiple MVP awards, it’s an opportunity to reflect and judge my own performance. This is not a dangerous thing to do, but quite the opposite. If a person believes in self improvement, then critical analysis is an important part of that process. A lot of MVPs will tell you that they would be doing the same thing, regardless of whether they were an MVP or not; helping others in the community, which is also where I prefer to hang my hat. I’ve never defined myself as an expert and never will; this determination is left to others. In fact, let me just come out and say it, “I don’t know everything”. Shocked? Sometimes the gap between expectations and reality extends beyond a reasonable measure. Being labeled as a technical expert feels good for one's self esteem and is certainly a useful motivational technique. A problem can emerge though when an individual believes, too much, in what they are told. The problem is not with a pat on the back, but with a person does with the positive reinforcement. Is narcissism too strong a word? How often have you been in a public forum reading a demeaning response to a question that only serves in attempt to raise the stature of the person providing the response? Such behavior compromises one’s credibility, raises questions about validity of the MVP award, and is limited in community value. I’m currently under consideration for another MVP award on April 1st. If it happens, it will be good. Otherwise, I’ll keep writing articles, coding open source software, and whatever else I enjoy doing; with the best reward being that people find value in what I do. Joe

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  • Creating an excel macro to sum lines with duplicate values

    - by john
    I need a macro to look at the list of data below, provide a number of instances it appears and sum the value of each of them. I know a pivot table or series of forumlas could work but i'm doing this for a coworker and it has to be a 'one click here' kinda deal. The data is as follows. A B Smith 200.00 Dean 100.00 Smith 100.00 Smith 50.00 Wilson 25.00 Dean 25.00 Barry 100.00 The end result would look like this Smith 3 350.00 Dean 2 125.00 Wilson 1 25.00 Barry 1 100.00 Thanks in advance for any help you can offer!

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  • Simple Select Statement on MySQL Database Hanging

    - by AlishahNovin
    I have a very simple sql select statement on a very large table, that is non-normalized. (Not my design at all, I'm just trying to optimize while simultaneously trying to convince the owners of a redesign) Basically, the statement is like this: SELECT FirstName, LastName, FullName, State FROM Activity Where (FirstName=@name OR LastName=@name OR FullName=@name) AND State=@state; Now, FirstName, LastName, FullName and State are all indexed as BTrees, but without prefix - the whole column is indexed. State column is a 2 letter state code. What I'm finding is this: When @name = 'John Smith', and @state = '%' the search is really fast and yields results immediately. When @name = 'John Smith', and @state = 'FL' the search takes 5 minutes (and usually this means the web service times out...) When I remove the FirstName and LastName comparisons, and only use the FullName and State, both cases above work very quickly. When I replace FirstName, LastName, FullName, and State searches, but use LIKE for each search, it works fast for @name='John Smith%' and @state='%', but slow for @name='John Smith%' and @state='FL' When I search against 'John Sm%' and @state='FL' the search finds results immediately When I search against 'John Smi%' and @state='FL' the search takes 5 minutes. Now, just to reiterate - the table is not normalized. The John Smith appears many many times, as do many other users, because there is no reference to some form of users/people table. I'm not sure how many times a single user may appear, but the table itself has 90 Million records. Again, not my design... What I'm wondering is - though there are many many problems with this design, what is causing this specific problem. My guess is that the index trees are just too large that it just takes a very long time traversing the them. (FirstName, LastName, FullName) Anyway, I appreciate anyone's help with this. Like I said, I'm working on convincing them of a redesign, but in the meantime, if I someone could help me figure out what the exact problem is, that'd be fantastic.

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  • Javascript Regex to convert dot notation to bracket notation

    - by Tauren
    Consider this javascript: var joe = { name: "Joe Smith", location: { city: "Los Angeles", state: "California" } } var string = "{name} is currently in {location.city}, {location.state}"; var out = string.replace(/{([\w\.]+)}/g, function(wholematch,firstmatch) { return typeof values[firstmatch] !== 'undefined' ? values[firstmatch] : wholematch; }); This will output the following: Joe Smith is currently in {location.city}, {location.state} But I want to output the following: Joe Smith is currently in Los Angeles, California I'm looking for a good way to convert multiple levels of dot notation found between braces in the string into multiple parameters to be used with bracket notation, like this: values[first][second][third][etc] Essentially, for this example, I'm trying to figure out what regex string and function I would need to end up with the equivalent of: out = values[name] + " is currently in " + values["location"]["city"] + values["location"]["state"];

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  • Is it possible to use ContainsTable to get results for more than one column?

    - by LockeCJ
    Consider the following table: People FirstName nvarchar(50) LastName nvarchar(50) Let's assume for the moment that this table has a full-text index on it for both columns. Let's suppose that I wanted to find all of the people named "John Smith" in this table. The following query seems like a perfectly rational way to accomplish this: SELECT * from People p INNER JOIN CONTAINSTABLE(People,*,'"John*" AND "Smith*"') Unfortunately, this will return no results, assuming that there is no record in the People table that contains both "John" and "Smith" in either the FirstName or LastName columns. It will not match a record with "John" in the FirstName column, and "Smith" in the LastName column, or vice-versa. My question is this: How does one accomplish what I'm trying to do above? Please consider that the example above is simplified. The real table I'm working with has ten columns and the input I'm receiving is a single string which is split up based on standard word breakers (space, dash, etc.)

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  • Parsing complex string using regex

    - by wojtek_z
    My regex skills are not very good and recently a new data element has thrown my parser into a loop Take the following string "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write" Previously I had the following for my regex : [+\\-/] Which would turn the result into USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read But now I have values with dashes in them which is causing bad output New string looks like "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write/FUNCTION=Read-Write" Which gives me the following result , and breaks the key = value structure. USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read Write Can someone help me formulate a valid regex for handling this or point me to some key / value examples. Basically I need to be able to handle + - / signs in order to get combinations.

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  • Cassandra API equivalent of "SELECT ... FROM ... WHERE id IN ('...', '...', '...');"

    - by knorv
    Assume the following data set: id age city phone == === ==== ===== alfred 30 london 3281283 jeff 43 sydney 2342734 joe 29 tokyo 1283881 kelly 54 new york 2394929 molly 20 london 1823881 rob 39 sydney 4928381 To get the following result set .. id age phone == === ===== alfred 30 3281283 joe 29 1283881 molly 20 1823881 .. using SQL one would issue .. SELECT id, age, phone FROM dataset WHERE id IN ('alfred', 'joe', 'molly'); What is the corresponding Cassandra API call that would yield the same result set in one command?

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  • Oracle ADF Mobile and Developing On-device Mobile Applications

    - by Joe Huang
    Hi, everyone: It has been almost a year since we posted to this blog, and I am happy to report that we are steadily marching toward releasing a new generation of ADF Mobile.  This blog site has been quiet as we are heads down to develop this new generation of ADF Mobile.  As we are nearing releasing this next generation product, there are substantial number of Oracle internal application teams and external customers/partners actively developing using the beta version of this framework.  We are actively taking feedbacks from these teams and ensuring the product is ready for general availability. If you are intersted for more details around this new generation of ADF Mobile, we are hosting a session and a hands on lab this week at the ODTUG KScope 12 conference.  The lab is booked completely full weeks in advance, but perhaps you can still get into the session (Wed at 9:45 AM).   Look for updates from this blog site as well as the Oracle OTN ADF Mobile landing page during the weeks leading to Oracle OpenWorld 2012.   Thanks, Joe Huang

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  • How do I change the logged in user to another?

    - by TruMan1
    I would like to change the logged in user to another user temporarily to do some process. For example, say I am logged in as "Joe". In my method, I want to make the logged in user from "Joe" to "SuperUser", do some process, then change the logged in user back to "Joe". Can someone help with this?

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  • Distributed development systems

    - by Nathan Adams
    I am interested in a system that allows for distributed development with an authentication piece. What do I mean by that? Ok so lets take SVN, SVN keeps track of revisions and doesn't care who submits, as long as you have the right to submit you can submit, really, to any part in the repository. Where does my system come into play? Being able to granulate access control and give a stackoverflow like feel to the environment. In the system I am describing we have 4 users Bob, Alice, Dan, Joe. Bob is a project managed, Alice and Dan are programmers under Bob and Joe is a random programmer on the internet who wants to help. Ideally in this system, Bob can commit any changes and won't require approval. Alice and Dan can commit to their branches, or a branch, but a commit to the trunk would need approval by Bob. This is where Joe comes in, wants to help, however, you just don't want to give him the keys to the kingdom just yet so to speak, so in my system you would setup a "low user" account. Any commits that Joe makes would need to be approved by Dan, Alice or both. However, in the system, Joe can build up "Karma" where after so many approved commits it would only need approval by one of the programmers, and then eventually no approval would be necessary. Does that make sense and do you know if a system like that exists? Or am I just crazy to even think such a system/environment would be possible?

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