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  • Oracle Hyperion si conferma leader nel Magic Quadrant Gartner 2012

    - by Andrea Cravero
    L'edizione 2012 del Gartner Magic Quadrant for Corporate Performance Management Suites conferma la leadership Oracle Hyperion, che dura ininterrotta dal 2005. Secondo Gartner, "Oracle is a Leader in CPM suites, with one of the most widely distributed solutions in the market. Oracle Hyperion Enterprise Performance Management is recognized by CFOs worldwide. The vendor has a well-established partner channel, with both large and smaller CPM SI specialists. Hyperion skills are also plentiful among the independent consultant community, given the well-established products." "Oracle continues to innovate, bringing incremental improvements across the portfolio as well as new financial close management, disclosure management and predictive planning additions. Furthermore, Oracle has improved integration of Hyperion with the Oracle BI platform, and has improved planning performance, enabling Hyperion Planning to use Oracle Exalytics In-Memory Machine." Il rapporto completo è disponibile qui: Gartner: Magic Quadrant for Corporate Performance Management Suites, 2012 Buona lettura!

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  • Gartner: Magic Quadrant for Corporate Performance Management Suites, 2012

    - by Mike.Hallett(at)Oracle-BI&EPM
    Hyperion clearly leads the pack again in Gartner’s analysis of the CPM / EPM market, saying; “Oracle is a Leader in CPM suites, with one of the most widely distributed solutions in the market. Oracle Hyperion Enterprise Performance Management is recognized by CFOs worldwide. The vendor has a well-established partner channel, with both large and smaller CPM SI specialists. Hyperion skills are also plentiful among the independent consultant community, given the well-established products. “ “Oracle continues to innovate, bringing incremental improvements across the portfolio as well as new financial close management, disclosure management and predictive planning additions. Furthermore, Oracle has improved integration of Hyperion with the Oracle BI platform, and has improved planning performance, enabling Hyperion Planning to use Oracle Exalytics In-Memory Machine.” For the full article see here: Gartner: Magic Quadrant for Corporate Performance Management Suites, 2012 And if you missed it, here is also the MQ for BI: Gartner: Magic Quadrant for Business Intelligence Platforms, 2012

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  • Formatting numbers by tokens with php

    - by Adam D
    I'm looking for a way to format numbers using "tokens". This needs to be conditional (for the first few leading characters). Example: <?php $styles=array('04## ### ###','0# #### ####','13# ###','1800 ### ###'); format_number(0412345678); /*should return '0412 345 678'*/ format_number(0812345678); /*should return '08 1234 5678'*/ format_number(133622); /*should return '133 622'*/ format_number(1800123456); /*should return '1800 123 456'*/ ?> Incase you haven't guessed, my use of this is to format Australian phone numbers, dependent on their 'type'. I have a PHP function that does this, but it is ~114 lines and contains a lot of repeated code. Can anyone help?

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  • how to convert big-endian numbers to native numbers delphi

    - by steve0
    hi all i want to know how to convert big endian numbers to native numbers in delphi i am porting some c++ code in that i came accross this part unsigned long blockLength = *blockLengthPtr++ << 24; blockLength |= *blockLengthPtr++ << 16; blockLength |= *blockLengthPtr++ << 8; blockLength |= *blockLengthPtr; unsigned long dataLength = *dataLengthPtr++ << 24; dataLength |= *dataLengthPtr++ << 16; dataLength |= *dataLengthPtr++ << 8; dataLength |= *dataLengthPtr; i am not familiar with c++ ,so i didnt understand what those operators doing can any one help ? regards

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  • Generating strongly biased radom numbers for tests

    - by nobody
    I want to run tests with randomized inputs and need to generate 'sensible' random numbers, that is, numbers that match good enough to pass the tested function's preconditions, but hopefully wreak havoc deeper inside its code. math.random() (I'm using Lua) produces uniformly distributed random numbers. Scaling these up will give far more big numbers than small numbers, and there will be very few integers. I would like to skew the random numbers (or generate new ones using the old function as a randomness source) in a way that strongly favors 'simple' numbers, but will still cover the whole range, I.e. extending up to positive/negative infinity (or ±1e309 for double). This means: numbers up to, say, ten should be most common, integers should be more common than fractions, numbers ending in 0.5 should be the most common fractions, followed by 0.25 and 0.75; then 0.125, and so on. A different description: Fix a base probability x such that probabilities will sum to one and define the probability of a number n as xk where k is the generation in which n is constructed as a surreal number1. That assigns x to 0, x2 to -1 and +1, x3 to -2, -1/2, +1/2 and +2, and so on. This gives a nice description of something close to what I want (it skews a bit too much), but is near-unusable for computing random numbers. The resulting distribution is nowhere continuous (it's fractal!), I'm not sure how to determine the base probability x (I think for infinite precision it would be zero), and computing numbers based on this by iteration is awfully slow (spending near-infinite time to construct large numbers). Does anyone know of a simple approximation that, given a uniformly distributed randomness source, produces random numbers very roughly distributed as described above? I would like to run thousands of randomized tests, quantity/speed is more important than quality. Still, better numbers mean less inputs get rejected. Lua has a JIT, so performance can't be reasonably predicted. Jumps based on randomness will break every prediction, and many calls to math.random() will be slow, too. This means a closed formula will be better than an iterative or recursive one. 1 Wikipedia has an article on surreal numbers, with a nice picture. A surreal number is a pair of two surreal numbers, i.e. x := {n|m}, and its value is the number in the middle of the pair, i.e. (for finite numbers) {n|m} = (n+m)/2 (as rational). If one side of the pair is empty, that's interpreted as increment (or decrement, if right is empty) by one. If both sides are empty, that's zero. Initially, there are no numbers, so the only number one can build is 0 := { | }. In generation two one can build numbers {0| } =: 1 and { |0} =: -1, in three we get {1| } =: 2, {|1} =: -2, {0|1} =: 1/2 and {-1|0} =: -1/2 (plus some more complex representations of known numbers, e.g. {-1|1} ? 0). Note that e.g. 1/3 is never generated by finite numbers because it is an infinite fraction – the same goes for floats, 1/3 is never represented exactly.

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  • A function where small changes in input always result in large changes in output

    - by snowlord
    I would like an algorithm for a function that takes n integers and returns one integer. For small changes in the input, the resulting integer should vary greatly. Even though I've taken a number of courses in math, I have not used that knowledge very much and now I need some help... An important property of this function should be that if it is used with coordinate pairs as input and the result is plotted (as a grayscale value for example) on an image, any repeating patterns should only be visible if the image is very big. I have experimented with various algorithms for pseudo-random numbers with little success and finally it struck me that md5 almost meets my criteria, except that it is not for numbers (at least not from what I know). That resulted in something like this Python prototype (for n = 2, it could easily be changed to take a list of integers of course): import hashlib def uniqnum(x, y): return int(hashlib.md5(str(x) + ',' + str(y)).hexdigest()[-6:], 16) But obviously it feels wrong to go over strings when both input and output are integers. What would be a good replacement for this implementation (in pseudo-code, python, or whatever language)?

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  • printing out prime numbers from array

    - by landscape
    I'd like to print out all prime numbers from an array with method. I can do it with one int but don't know how to return certain numbers from array. Thanks for help! public static boolean isPrime(int [] tab) { boolean prime = true; for (int i = 3; i <= Math.sqrt(tab[i]); i += 2) if (tab[i] % i == 0) { prime = false; break; } for(int i=0; i<tab.length; i++) if (( tab[i]%2 !=0 && prime && tab[i] > 2) || tab[i] == 2) { return true; } else { return false; } //return prime; } thanks both of you. Seems like its solved: public static void isPrime(int[] tab) { for (int i = 0; i < tab.length; i++) { if (isPrimeNum(tab[i])) { System.out.println(tab[i]); } } } public static boolean isPrimeNum(int n) { boolean prime = true; for (long i = 3; i <= Math.sqrt(n); i += 2) { if (n % i == 0) { prime = false; break; } } if ((n % 2 != 0 && prime && n > 2) || n == 2) { return true; } else { return false; } }

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  • trying to divide complex numbers, division by zero

    - by user553619
    I'm trying the program below to divide complex numbers, it works for complex numbers but not when the denominator is real (i.e, the complex part is zero). Division by zero occurs in this line ratio = b->r / b->i ;, when the complex part b->i is zero (in the case of a real denominator). How do I get around this? and why did the programmer do this, instead of the more straightforward rule for complex division The wikipedia rule seems to be better, and no division by zero error would occur here. Did I miss something? Why did the programmer not use the wikipedia formula?? Thanks /*! @file dcomplex.c * \brief Common arithmetic for complex type * * <pre> * -- SuperLU routine (version 2.0) -- * Univ. of California Berkeley, Xerox Palo Alto Research Center, * and Lawrence Berkeley National Lab. * November 15, 1997 * * This file defines common arithmetic operations for complex type. * </pre> */ #include <math.h> #include <stdlib.h> #include <stdio.h> #include "slu_dcomplex.h" /*! \brief Complex Division c = a/b */ void z_div(doublecomplex *c, doublecomplex *a, doublecomplex *b) { double ratio, den; double abr, abi, cr, ci; if( (abr = b->r) < 0.) abr = - abr; if( (abi = b->i) < 0.) abi = - abi; if( abr <= abi ) { if (abi == 0) { fprintf(stderr, "z_div.c: division by zero\n"); exit(-1); } ratio = b->r / b->i ; den = b->i * (1 + ratio*ratio); cr = (a->r*ratio + a->i) / den; ci = (a->i*ratio - a->r) / den; } else { ratio = b->i / b->r ; den = b->r * (1 + ratio*ratio); cr = (a->r + a->i*ratio) / den; ci = (a->i - a->r*ratio) / den; } c->r = cr; c->i = ci; }

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  • Random numbers from -10 to 10 in C++

    - by Chris_45
    How does one make random numbers in the interval -10 to 10 in C++ ? srand(int(time(0)));//seed for(int i = 0; i < size; i++){ myArray[i] = 1 + rand() % 20 - 10;//this will give from -9 to 10 myArray2[i] =rand() % 20 - 10;//and this will -10 to 9 }

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  • Zend Lucene - cannot search numbers

    - by Pavel Dubinin
    Using Zend Lucene I cannot search numbers in description fields Added it like this: $doc->addField(Zend_Search_Lucene_Field::Text('description', $current_item['item_short_description'], 'utf-8')); Googling for this showed that applying following code should solve the problem, but it did not..: Zend_Search_Lucene_Analysis_Analyzer::setDefault(new Zend_Search_Lucene_Analysis_Analyzer_Common_TextNum_CaseInsensitive()); any thougts?

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  • form a number using consecutive numbers

    - by Mahesh
    Hi, I was puzzled with one of the question in Microsoft interview which is as given below: A function should accept a range( 3 - 21 ) and it should print all the consecutive numbers combination's to form each number as given below: 3=1+2 5=2+3 6=1+2+3 7=3+4 9=4+5 10=1+2+3+4 11=5+6 13=6+7 15=1+2+3+4+5 17=7+8 19=8+9 21=10+11 21=1+2+3+4+5+6 could you please help me in forming this sequence in C#? Thanks, Mahesh

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  • Formatting numbers in loop

    - by dave9909
    I want to list all numbers from 0000-9999 however I am having trouble holding the zero places. I tried: for(int i = 0; i <= 9999; ++i) { cout << i << "\n"; } but I get: 1,2,3,4..ect How can I make it 0001,0002,0003....0010, etc

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  • order array containing text and numbers

    - by ptrn
    I'm looking for the easiest way to sort an array that consists of numbers and text, and a combination of these. E.g. '123asd' '19asd' '12345asd' 'asd123' 'asd12' turns into '19asd' '123asd' '12345asd' 'asd12' 'asd123' This is going to be used in combination with the solution to another question I've asked here. The sorting function in itself works, what I need is a function that can say that that '19asd' is smaller than '123asd'. I'm writing this in JavaScript.

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  • Parsing numbers at PreviewTextInput

    - by Nitin Chaudhari
    I have a WPF application in which I have a hook at PreviewTextInput, through that I get the currently entered character and I have the string already entered. Given this I need to write the following function : bool ShouldAccept(char newChar,string existingText) existingText can be comma seperated valid numbers(including exponential) and it should just return false when invalid characters are pressed. My code(if else based) currently has a lot of flaws, I wanted to know if there is any smart way to do it.

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  • SQL, Auxiliary table of numbers

    - by vzczc
    For certain types of sql queries, an auxiliary table of numbers can be very useful. It may be created as a table with as many rows as you need for a particular task or as a user defined function that returns the number of rows required in each query. What is the optimal way to create such a function?

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  • Pi/Infinite Numbers

    - by Ben Shelock
    I'm curious about infinite numbers in computing, in particular pi. For a computer to render a circle it would have to understand pi. But how can it if it is infinite? Am I looking too much into this? Would it just use a rounded value?

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  • C code to round numbers

    - by webgenius
    Is there any way to round numbers in C? I do not want to use ceil and floor. Is there any other alternative? I came across this code snippet when I Googled for the answer: (int)(num < 0 ? (num - 0.5) : (num + 0.5)) The above line always prints the value as 4 even when float num =4.9. Please suggest a solution.

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  • Algorithm to generate N random numbers between A and B which sum up to X

    - by Shaamaan
    This problem seemed like something which should be solvable with but a few lines of code. Unfortunately, once I actually started to write the thing, I've realized it's not as simple as it sounds. What I need is a set of X random numbers, each of which is between A and B and they all add up to X. The exact variables for the problem I'm facing seem to be even simpler: I need 5 numbers, between -1 and 1 (note: these are decimal numbers), which add up to 1. My initial "few lines of code, should be easy" approach was to randomize 4 numbers between -1 and 1 (which is simple enough), and then make the last one 1-(sum of previous numbers). This quickly proved wrong, as the last number could just as well be larger than 1 or smaller than -1. What would be the best way to approach this problem? PS. Just for reference: I'm using C#, but I don't think it matters. I'm actually having trouble creating a good enough solution for the problem in my head.

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  • 3 threads printing numbers of different range

    - by user875036
    This question was asked in an Electronic Arts interview: There are 3 threads. The first thread prints the numbers 1 to 10. The second thread prints the numbers 11 to 20. The third thread prints the numbers from from 21 to 30. Now, all three threads are running. The numbers are printed in an irregular order like 1, 11, 2, 21, 12 etc. If I want numbers to be printed in sorted order like 1, 2, 3, 4..., what should I do with these threads?

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  • GDL Presents: Make Web Magic | Part I

    GDL Presents: Make Web Magic | Part I Using the latest open web technologies, the developers creating some of the most inspired Chrome Experiments showcase their latest web experiments and discuss how they are making the web faster, more fun, and more open in this 3-episode hangout. Happy experimenting. Host: Paul Irish, Developer Advocate, Chrome Guest: Michael Deal From: GoogleDevelopers Views: 115 2 ratings Time: 31:44 More in Science & Technology

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  • GDL Presents: Make Web Magic | Part II

    GDL Presents: Make Web Magic | Part II Using the latest open web technologies, the developers creating some of the most inspired Chrome Experiments showcase their latest web experiments and discuss how they are making the web faster, more fun, and open in this 3-episode hangout. Host: Paul Irish, Developer Advocate, Chrome Guest: Mark Danks From: GoogleDevelopers Views: 2 0 ratings Time: 17:41 More in Science & Technology

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  • Does the concept of "magic number" change from language to language?

    - by Gerardo Marset
    Take the following code in C/C++, for example: int foo[] = {0, 0, 0, 0}; No magic numbers, right? Now, the Python "equivalent" of that would be: foo = [0, 0, 0, 0] Still no magic numbers. However, in Python, that same thing can be written like this: foo = [0] * 4 And now we DO have a magic number. Or do we? I'm guessing this and other similar things are present on these and other languages.

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