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  • fluent nhibernate select n+1 problem

    - by Andrew Bullock
    I have a fairly deep object graph (5-6 nodes), and as I traverse portions of it NHProf is telling me I've got a "Select N+1" problem (which I do). The two solutions I'm aware of are Eager load children Break apart my object graph (and eager load) I don't really want to do either of these (although I may break the graph apart later as I forsee it growing) For now.... Is it possible to tell NHibernate (with fluentnhib) that whenever i try to access children, to load them all in one go, instead of selectn+1ing as i iterate over them? I'm also getting "unbounded results set"s, which is presumably the same problem (or rather, will be solved by the above solution if possible). Each child collection (throughout the graph) will only ever have about 20 members, but 20^5 is a lot, so i dont want to eager load everything when i get the root, but simply get all of a child collection whenever i go near it Edit: an afterthought.... what if i want to introduce paging when i want to render children? do i HAVE to break my object graph here, or is there some sneakyness i can employ to solve all these issues?

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  • How to do Grouping using JPA annotation with mapping given field

    - by hemal
    I am using JPA Annotation mapping with the table given below, but having problem that i am doing mapping on same table but on diffrent field given ProductImpl.java @Entity @Table(name = "Product") public class ProductImpl extends SimpleTagGroup implements Product { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private long id = -1; @OneToMany(fetch = FetchType.EAGER, cascade = CascadeType.ALL) @JoinTable(name = "ProductTagMapping", joinColumns =@JoinColumn(name = "productId"), inverseJoinColumns =@JoinColumn(name = "tagId")) private List<SimpleTag> tags; @OneToMany(fetch = FetchType.EAGER, cascade = CascadeType.ALL) @JoinTable(name = "ProductTagMapping", joinColumns =@JoinColumn(name = "productId"), inverseJoinColumns =@JoinColumn(name = "tagId")) private List<SimpleTag> licenses; @OneToMany(fetch = FetchType.EAGER, cascade = CascadeType.ALL) @JoinTable(name = "ProductTagMapping", joinColumns =@JoinColumn(name = "productId"), inverseJoinColumns =@JoinColumn(name = "tagId")) private List<SimpleTag> os; I want to get values like windows and linux in os , GPLv2 and GPLv3 in licenses ,so we are using TagGroup table . but here i got all tagValues in each of the os,licenses and tag fileds,so how could i do group by or some other things with JPA. and ProductTagMapping is the mapping table between Tag and TagGroup TagGroup Table ID TAGGROUPNAME 1 PRODUCTTYPE 2 LICENSE 3 TAGS 4 OS SimpleTag ID TAGVALUE 1 Application 2 Framework 3 Apache2 4 GPLv2 5 GPLv3 6 learning 7 Linux 8 Windows 9 mature

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  • EJB3 Entity and Lazy Problem

    - by Stefano
    My Entity beAN have 2 list: @Entity @Table(name = "TABLE_INTERNAL") public class Internal implements java.io.Serializable { ...SOME GETTERS AND SETTERS... private List<Match> matchs; private List<Regional> regionals; } mapped one FetchType.LAZY and one FetchType.EAGER : @OneToMany(fetch = FetchType.LAZY,mappedBy = "internal") public List<Match> getMatchs() { return matchs; } public void setMatchs(List<Match> matchs) { this.matchs = matchs; } @ManyToMany(targetEntity = Regional.class, mappedBy = "internals", fetch =FetchType.EAGER) public List<Regional> getRegionals() { return regionals; } public void setRegionals(List<Regional> regionals) { this.regionals = regionals; } I need both lists full ! But I cant put two FetchType.EAGER beacuse it's an error. I try some test: List<Internal> out; out= em.createQuery("from Internal").getResultList(); out= em.createQuery("from Internal i JOIN FETCH i.regionals ").getResultList(); I'm not able to fill both lists...Help!!! Stefano

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  • Deleting objects with FK constraints in Spring/Hibernate

    - by maxdj
    This seems like such a simple scenario to me, yet I cannot for the life of my find a solution online or in print. I have several objects like so (trimmed down): @Entity public class Group extends BaseObject implements Identifiable<Long> { private Long id; private String name; private Set<HiringManager> managers = new HashSet<HiringManager>(); private List<JobOpening> jobs; @ManyToMany(fetch=FetchType.EAGER) @JoinTable( name="group_hiringManager", joinColumns=@JoinColumn(name="group_id"), inverseJoinColumns=@JoinColumn(name="hiringManager_id") ) public Set<HiringManager> getManagers() { return managers; } @OneToMany(mappedBy="group", fetch=FetchType.EAGER) public List<JobOpening> getJobs() { return jobs; } } @Entity public class JobOpening extends BaseObject implements Identifiable<Long> { private Long id; private String name; private Group group; @ManyToOne @JoinColumn(name="group_id", updatable=false, nullable=true) public Group getGroup() { return group; } } @Entity public class HiringManager extends User { @ManyToMany(mappedBy="managers", fetch=FetchType.EAGER) public Set<Group> getGroups() { return groups; } } Say I want to delete a Group object. Now there are dependencies on it in the JobOpening table and in the group_hiringManager table, which cause the delete function to fail. I don't want to cascade the delete, because the managers have other groups, and the jobopenings can be groupless. I have tried overriding the remove() function of my GroupManager to remove the dependencies, but it seems like no matter what I do they persist, and the delete fails! What is the right way to remove this object?

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  • Saving owned/child objects in Hibernate

    - by maxdj
    I'm having a hard time wrapping my head around the way hibernate objects work. Here's a little chunk of what my model looks like: JobOpening: @ManyToMany(fetch=FetchType.EAGER,cascade=CascadeType.ALL) @JoinTable( name="jobOpening_questionSet", joinColumns=@JoinColumn(name="jobOpenings_id"), inverseJoinColumns=@JoinColumn(name="questionSets_id") ) @IndexColumn(name="question_sets_idx",base=0,nullable=false) public List<QuestionSet> getQuestionSets() { return questionSets; } QuestionSet: @ManyToMany(mappedBy="questionSets",fetch=FetchType.EAGER) public Set<JobOpening> getJobOpenings() { return jobOpenings; } @OneToMany(cascade=CascadeType.ALL,fetch=FetchType.EAGER) @IndexColumn(name="questions_idx",base=0) @JoinColumn(name="questionset_id",nullable=false) public List<FormQuestion> getQuestions() { return questions; } FormQuestion: @ManyToOne @JoinColumn(name="questionset_id", insertable=false, updatable=false, nullable=false) @OnDelete(action=OnDeleteAction.CASCADE) public QuestionSet getQuestionSet() { return questionSet; } Now how would I go about, say, modifying a question in the question set, or changing which jobs a questionset is associated with? For example, to edit a question in a questionset, I imagine I should be able to just get the question via its id, change some values, and merge() it back in, but this doesn't work. I'm using Hibernate from Spring (appfuse), usually as detached objects.

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  • Hibernate noob fetch join problem

    - by Bruce
    Hi all I have two classes, Test2 and Test3. Test2 has an attribute test3 that is an instance of Test3. In other words, I have a unidirectional OneToOne association, with test2 having a reference to test3. When I select Test2 from the db, I can see that a separate select is being made to get the details of the associated test3 class. This is the famous 1+N selects problem. To fix this to use a single select, I am trying to use the fetch=join annotation, which I understand to be @Fetch(FetchMode.JOIN) However, with fetch set to join, I still see separate selects. Here are the relevant portions of my setup.. hibernate.cfg.xml: <property name="max_fetch_depth">2</property> Test2: public class Test2 { @OneToOne (cascade=CascadeType.ALL , fetch=FetchType.EAGER) @JoinColumn (name="test3_id") @Fetch(FetchMode.JOIN) public Test3 getTest3() { return test3; } NB I set the FetchType to EAGER out of desperation, even though it defaults to EAGER anyway for OneToOne mappings, but it made no difference. Thanks for any help! Edit: I've pretty much given up on trying to use FetchMode.JOIN - can anyone confirm that they have got it to work ie produce a left outer join? In the docs I see that "Usually, the mapping document is not used to customize fetching. Instead, we keep the default behavior, and override it for a particular transaction, using left join fetch in HQL" If I do a left join fetch instead: query = session.createQuery("from Test2 t2 left join fetch t2.test3"); then I do indeed get the results I want - ie a left outer join in the query.

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  • JPA behaviour...

    - by Marcel
    Hi I have some trouble understanding a JPA behaviour. Mabye someone could give me a hint. Situation: Product entity: @Entity public class Product implements Serializable { ... @OneToMany(mappedBy="product", fetch=FetchType.EAGER) private List<ProductResource> productResources = new ArrayList<ProductResource>(); .... public List<ProductResource> getProductResources() { return productResources; } public boolean equals(Object obj) { if (obj == this) return true; if (obj == null) return false; if (!(obj instanceof Product)) return false; Product p = (Product) obj; return p.productId == productId; } } Resource entity: @Entity public class Resource implements Serializable { ... @OneToMany(mappedBy="resource", fetch=FetchType.EAGER) private List<ProductResource> productResources = new ArrayList<ProductResource>(); ... public void setProductResource(List<ProductResource> productResource) { this.productResources = productResource; } public List<ProductResource> getProductResources() { return productResources; } public boolean equals(Object obj) { if (obj == this) return true; if (obj == null) return false; if (!(obj instanceof Resource)) return false; Resource r = (Resource) obj; return (long)resourceId==(long)r.resourceId; } } ProductResource Entity: This is a JoinTable (association class) with additional properties (amount). It maps Product and Resources. @Entity public class ProductResource implements Serializable { ... @JoinColumn(nullable=false, updatable=false) @ManyToOne(fetch=FetchType.EAGER, cascade=CascadeType.PERSIST) private Product product; @JoinColumn(nullable=false, updatable=false) @ManyToOne(fetch=FetchType.EAGER, cascade=CascadeType.PERSIST) private Resource resource; private int amount; public void setProduct(Product product) { this.product = product; if(!product.getProductResources().contains((this))){ product.getProductResources().add(this); } } public Product getProduct() { return product; } public void setResource(Resource resource) { this.resource = resource; if(!resource.getProductResources().contains((this))){ resource.getProductResources().add(this); } } public Resource getResource() { return resource; } ... public boolean equals(Object obj) { if (obj == this) return true; if (obj == null) return false; if (!(obj instanceof ProductResource)) return false; ProductResource pr = (ProductResource) obj; return (long)pr.productResourceId == (long)productResourceId; } } This is the Session Bean (running on glassfish). @Stateless(mappedName="PersistenceManager") public class PersistenceManagerBean implements PersistenceManager { @PersistenceContext(unitName = "local_mysql") private EntityManager em; public Object create(Object entity) { em.persist(entity); return entity; } public void delete(Object entity) { em.remove(em.merge(entity)); } public Object retrieve(Class entityClass, Long id) { Object entity = em.find(entityClass, id); return entity; } public void update(Object entity) { em.merge(entity); } } I call the session Bean from a java client: public class Start { public static void main(String[] args) throws NamingException { PersistenceManager pm = (PersistenceManager) new InitialContext().lookup("java:global/BackITServer/PersistenceManagerBean"); ProductResource pr = new ProductResource(); Product p = new Product(); Resource r = new Resource(); pr.setProduct(p); pr.setResource(r); ProductResource pr_stored = (ProductResource) pm.create(pr); pm.delete(pr_stored); Product p_ret = (Product) pm.retrieve(Product.class, pr_stored.getProduct().getProductId()); // prints out true ???????????????????????????????????? System.out.println(p_ret.getProductResources().contains(pr_stored)); } } So here comes my problem. Why is the ProductResource entity still in the List productResources(see code above). The productResource tuple in the db is gone after the deletion and I do newly retrieve the Product entity. If I understood right every method call of the client happens in a new persistence context, but here i obviously get back the non-refreshed product object!? Any help is appreciated Thanks Marcel

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  • Why a graduate program in South Africa?

    - by anca.rosu
    South Africa, like many other countries, is desperate for skills. Good, solid, technical skills – together with a get-up-and-go attitude – and the desire to work for a world-class organization that is leading the way! In addition, we have made a commitment in South Africa that we need to transform our organization and develop and empower Black individuals who historically have not had the opportunity to participate in the global economy. It is through this investment in our country's people that we contribute to the development of a nation capable of competing on the global stage. This makes for an exciting recipe! We have: Plenty of young and talented individuals who are eager to get stuck in and learn. Formal, recognized qualifications that form the basis for further development. A huge big global organization – Oracle – that is committed to developing these graduates and giving them an opportunity that is out of this world! Mix the above ‘ingredients’ together Tackle and remove potential “lumps & bumps” along the way as we learn and grow together Nurture and care for each other in a warm but tough environment What have we achieved? In most cases, the outcome is an awesome bunch of new talent that is well equipped to face the IT world. Where we have the opportunity and suitable headcount available to employ these graduates at Oracle we snap them up – alternatively our business partners and customers are always eager to recruit Oracle graduates into their organizations! These individuals go through real-life work place experience whilst at Oracle. In some cases they get to travel internationally. The excitement and buzz gets into their system and their blood becomes truly RED! Oracle RED! This is valuable talent and expertise to have in our eco-system and it’s an exciting program to be a part of not only as a graduate but as an Oracle employee too!   If you have any questions related to this article feel free to contact  [email protected].  You can find our job opportunities via http://campus.oracle.com. Technorati Tags: South Africa,technical skills,graduate program,opportunity,global organization,new talent

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  • Geek City: Growing Rows with Snapshot Isolation

    - by Kalen Delaney
    I just finished a wonderful week in Stockholm, teaching a class for Cornerstone Education. We had 19 SQL Server enthusiasts, all eager to find out everything they could about SQL Server Internals. One questions came up on Thursday that I wasn’t sure of the answer to. I jokingly told the student who asked it to consider it a homework exercise, but then I was so interested in the answer, I try to figure it out myself Thursday evening. In this post, I’ll tell you what I did to try to answer the question....(read more)

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  • installation ubunto 14.01 on a different partition with windows 8.1

    - by bilel abidi
    Please assist me. I am eager to install Ubunto 14.01 on a different partition but I do not know how to do it. I have HP with windows 7 pre-installed then I upgraded to windows 8.1 please show me how to make a dedicated partition to install ubuntu 14.01. please find the partition that I have. I appreciate your help on a I have : partition : /dev/sda1 NTFS label system 922.50KB /dev/ sda2 NTFS 199.00MIB flags : boot /dev/sda3 NTFS label receovery 488.77 GB /dev/sda4 unknown 16 GB unallocated 1 MIB

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  • What platform were old TV video games developed on?

    - by Mihir
    I am very eager to know how TV video games (which we all used to play in our childhood) were developed and on which platform. I know how games are developed for mobile devices, Windows PC's and Mac but I'm not getting how (in those days) Contra, Duck Hunt and all those games were developed. As they have high graphics and a large number of stages. So how did they manage to develop games in such a small size environment and with lower configuration platform?

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  • Career Change Need Advice: Professional Web Developer

    - by bikedorkseattle
    I'm hoping to get some advice here on the steps I should take to make a career change into professional web development. I've been working in cancer research the last 14 years and I need a change. The job market is terrible, the pay is worse, and despite what one would think the atmosphere is generally un-collegial, even in your own group. Venture funding never returned after the dot com burst and with 3 to 5 wars our country is now in, NIH funding is only going to get worse. I know things are not going to get better for my field, sadly, and I know I need to move on. For probably just as long I have fiddled around with web development, I even run a fairly popular site with close to 1 million/month pageviews that pulls a decent income, but not stable enough to live off of right now. My skills are ok for being self taught. I enjoy the fast paced nature of the web and the tools the community creates and how eager people are to help and share knowledge; it's what science should be. I have been trying to find an entry level developer job doing standard HTML/CSS/PHP/MySQL/JS/jQuery type work. A good 50%+ of the jobs want someone with a CS degree, and most want 5 years experience. Having no professional experience and no formal education, I know I'm at a huge disadvantage. I am now considering my options on how to move forward professionally. The way I see it I have basically 3 options. Build up my portfolio of work as much as I can and continue to learn as much as I can on my own. Try to contribute on some open source project when time allows. Network like crazy and go to meetups. Be confident and pray a lot in private. OR While doing above, do some certification programs in PHP and Java, possibly others. Get a Zend Certification. OR Spend a few years getting a CS degree while doing 1. I've already done the work fulltime go to school thing and it doesn't excite me one bit. I didn't have the greatest college experience and am not too eager to return, but I have a family to feed. Is the degree really necessary or is it more of a right of passage type thing in most instances? I appreciate everyones input. Thanks for taking the time to respond.

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  • SEO For Beginners

    So you've started your new site added you're products and your eager to see some return on your investment, some sales. You won't get any sales without any traffic that's why shops pay a premium to be in busy shopping malls. You could have the best shop in the world stocking the greatest products at the keenest prices, if no one can get to it your not going to sell much are you?

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  • Introduction par l'exemple à Entity Framework 5 Code First, un article de Serge Tahé

    Bonjour, J'ai mis en ligne "Introduction par l'exemple à Entity Framework 5 Code First". C'est un tutoriel destiné en priorité aux débutants même s'il peut intéresser d'autres publics. Citation: - Création d'une base SQL Server 2012 à partir d'entités EF5 ; - Ajout, Modification, Suppression d'entités ; - Requêtage du contexte de persistance avec LINQ to Entities ; - Gestion des entités détachées ; - Lazy et Eager loading ;

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  • How can I limit the number of open AF_INET sockets?

    - by Stefano Palazzo
    Is there a way to limit the number of concurretly open AF_INET sockets (only)? If so, how do I do it, and how will the networking behave if I'm above the limit? For background: My cheap commodity router is a bit eager to detect 'syn flooding'. When it does, it crashes (and doesn't automatically restart itself). I'm thinking limiting concurrent connections to around 1000 should keep it from bickering.

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  • Creating an Underwater Scene in Blender- Part 3

    <b>Packt:</b> "From the point we started our scene, we haven't tried any test renders yet to see how our underwater environment looks and I know you're all so eager to try and press that RENDER button (so am I), but let's make sure that we don't waste a second of our time by rendering something that's not worth the button press at all."

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  • Dedicated GRUB2 Partition and Windows 8

    - by captain
    Ok so as many of you may know the Windows 8 developer preview was released today and as such I'm very eager to use it but I have both Ubuntu and Windows 7 installed on my machine. I don't want to disturb these drives and have recently set up a dedicated grub partition on /media/sdb8 My question is if I install windows 8 will it overwrite the grub partition and if so what are the steps I should take to recover it.

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  • New Remoting Features in PowerShell 2.0

    Eager to quell misinformation, Jonathan Medd points why PowerShell 2.0 is so much more than just super-charged SSH. He describes some new commands with full remoting functionality, and then explains persistent sessions, and how they give you that much sought-after power: administration automation.

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  • Offshore Development - 3 Challenges and 3 Solutions

    Offshore development has become synonymous with cost saving for software and web development companies situated in North America, Europe and various other eastern countries. It saves the cost for sure but it there are challenges that needed to be addressed. If those challenges are addressed well, there are millions of small and medium businesses eager to try these offshore software and web development services. I am trying to list few of those challenges and their solutions in this article.

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  • How an SEO Service Can Facilitate Small Business Success!

    With a growing market for SEO services, many businesses are searching for valid and affordable way to relay their message to eager customers and clients through web-based means and marketing. Focusing your marketing efforts on building your customer portfolio through web-based marketing is must in today's' business world.

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