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  • Replace ",**" with a linebreak using RegEx (or something else)

    - by John
    I'm getting started with RegEx and I was wondering if anyone could help me craft a statement to convert coordinates as follows: 145.00694,-37.80421,9 145.00686,-37.80382,9 145.00595,-37.8035,16 145.00586,-37.80301,16 to 145.00694,-37.80421 145.00686,-37.80382 145.00595,-37.8035 145.00586,-37.80301 (Strip off the last comma and value and turn it into a line break.) I can't figure out how to use wildcards to do something like that. Any help would be greatly appreciated! Thanks.

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  • Django Template Inheritance -- Missing Images?

    - by user367817
    Howdy, I have got the following file heirarchy: project   other stuff   templates       images           images for site       app1           templates for app1       registration           login template       base.html (base for entire site)       style.css (for base.html) In the login template, I am extending 'base.html.' 'base.html' uses 'style.css' along with all of the images in the 'templates/images' directory. For some reason, none of the CSS styles or images will show up in the login template, even though I'm extending it. Does this missing image issue have something to do with screwed up "media" settings somewhere? I never understood those, but this is a major roadblock in my proof-of-concept, so any help is appreciated. Thanks!

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  • Transaction within transaction

    - by user281521
    Hello, I want to know if open a transaction inside another is safe and encouraged? I have a method: def foo(): session.begin try: stuffs except Exception, e: session.rollback() raise e session.commit() and a method that calls the first one, inside a transaction: def bar(): stuffs try: foo() #<<<< there it is :) stuffs except Exception, e: session.rollback() raise e session.commit() if I get and exception on the foo method, all the operations will be rolled back? and everything else will work just fine? thanks!!

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  • Online job-searching is tedious. Help me automate it.

    - by ehsanul
    Many job sites have broken searches that don't let you narrow down jobs by experience level. Even when they do, it's usually wrong. This requires you to wade through hundreds of postings that you can't apply for before finding a relevant one, quite tedious. Since I'd rather focus on writing cover letters etc., I want to write a program to look through a large number of postings, and save the URLs of just those jobs that don't require years of experience. I don't require help writing the scraper to get the html bodies of possibly relevant job posts. The issue is accurately detecting the level of experience required for the job. This should not be too difficult as job posts are usually very explicit about this ("must have 5 years experience in..."), but there may be some issues with overly simple solutions. In my case, I'm looking for entry-level positions. Often they don't say "entry-level", but inclusion of the words probably means the job should be saved. Next, I can safely exclude a job the says it requires "5 years" of experience in whatever, so a regex like /\d\syears/ seems reasonable to exclude jobs. But then, I realized some jobs say they'll take 0-2 years of experience, matches the exclusion regex but is clearly a job I want to take a look at. Hmmm, I can handle that with another regex. But some say "less than 2 years" or "fewer than 2 years". Can handle that too, but it makes me wonder what other patterns I'm not thinking of, and possibly excluding many jobs. That's what brings me here, to find a better way to do this than regexes, if there is one. I'd like to minimize the false negative rate and save all the jobs that seem like they might not require many years of experience. Does excluding anything that matches /[3-9]\syears|1\d\syears/ seem reasonable? Or is there a better way? Training a bayesian filter maybe?

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  • Lucene: Fastest way to return the document occurance of a phrase?

    - by dont say the kid's name
    Hi Guys, I am trying to use Lucene (actually PyLucene!) to find out how many documents contain my exact phrase. My code currently looks like this... but it runs rather slow. Does anyone know a faster way to return document counts? phraseList = ["some phrase 1", "some phrase 2"] #etc, a list of phrases... countsearcher = IndexSearcher(SimpleFSDirectory(File(STORE_DIR)), True) analyzer = StandardAnalyzer(Version.LUCENE_CURRENT) for phrase in phraseList: query = QueryParser(Version.LUCENE_CURRENT, "contents", analyzer).parse("\"" + phrase + "\"") scoreDocs = countsearcher.search(query, 200).scoreDocs print "count is: " + str(len(scoreDocs))

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  • Solution for distributing MANY simple network tasks?

    - by EmpireJones
    I would like to create some sort of a distributed setup for running a ton of small/simple REST web queries in a production environment. For each 5-10 related queries which are executed from a node, I will generate a very small amount of derived data, which will need to be stored in a standard relational database (such as PostgreSQL). What platforms are built for this type of problem set? The nature, data sizes, and quantities seem to contradict the mindset of Hadoop. There are also more grid based architectures such as Condor and Sun Grid Engine, which I have seen mentioned. I'm not sure if these platforms have any recovery from errors though (checking if a job succeeds). What I would really like is a FIFO type queue that I could add jobs to, with the end result of my database getting updated. Any suggestions on the best tool for the job?

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  • How can I implement "real time" messaging on Google AppEngine?

    - by Freed
    I'm creating a web application on Google AppEngine where I want the user to be notified a quickly as possible after certain events occour. The problem is similar to say a chat server in that I need something happening on one connection (someone is writing a message in a chat room) to propagate to a number of other connections (other people in that chat room gets the message). To get speedy updates from the server to the client I'm planning on using long polling with XmlHttpRequest, hoping that AppEngine won't interfere other than possibly restriing the timeout. The real problem however is efficient notification between connections on AppEngine. Is there any support for this type of cross connection notification on AppEngine that does not involve busy-waiting? The only tools I can think of to do this at all is either using the data storage (slow) or memcache (unreliable), and none of them would let me avoid busy-waiting. Note: I know about XMPP support on AppEngine. It's related, but I want a browser based solution, sending messages to the users by XMPP is not an option.

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  • Django. default=datetime.now() problem

    - by Shamanu4
    Hello. I've such db model: from datetime import datetime class TermPayment(models.Model): dev_session = models.ForeignKey(DeviceSession, related_name='payments') user_session = models.ForeignKey(UserSession, related_name='payment') date = models.DateTimeField(default=datetime.now(),blank=True) sum = models.FloatField(default=0) cnt = models.IntegerField(default=0) class Meta: db_table = 'term_payments' ordering = ['-date'] and here new instance is added: # ... tp = TermPayment() tp.dev_session = self.conn.session # device session hash tp.user_session = self.session # user session hash tp.sum = sum tp.cnt = cnt tp.save() But i've a problem: all records in database have the same value in date field - the date of the first payment. After server restart - one record have new date and others have the same as first after restart. It's look like some data cache is using but I can't found where. database: mysql 5.1.25 django v1.1.1

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  • Celery / Django Single Tasks being run multiple times

    - by felix001
    I'm facing an issue where I'm placing a task into the queue and it is being run multiple times. From the celery logs I can see that the same worker is running the task ... [2014-06-06 15:12:20,731: INFO/MainProcess] Received task: input.tasks.add_queue [2014-06-06 15:12:20,750: INFO/Worker-2] starting runner.. [2014-06-06 15:12:20,759: INFO/Worker-2] collection started [2014-06-06 15:13:32,828: INFO/Worker-2] collection complete [2014-06-06 15:13:32,836: INFO/Worker-2] generation of steps complete [2014-06-06 15:13:32,836: INFO/Worker-2] update created [2014-06-06 15:13:33,655: INFO/Worker-2] email sent [2014-06-06 15:13:33,656: INFO/Worker-2] update created [2014-06-06 15:13:34,420: INFO/Worker-2] email sent [2014-06-06 15:13:34,421: INFO/Worker-2] FINISH - Success However when I view the actual logs of the application it is showing 5-6 log lines for each step (??). Im using Django 1.6 with RabbitMQ. The method for placing into the queue is via placing a delay on a function. This function (task decorator is added( then calls a class which is run. Has anyone any idea on the best way to troubleshoot this ? Edit : As requested heres the code, views.py In my view im sending my data to the queue via ... from input.tasks import add_queue_project add_queue_project.delay(data) tasks.py from celery.decorators import task @task() def add_queue_project(data): """ run project """ logger = logging_setup(app="project") logger.info("starting project runner..") f = project_runner(data) f.main() class project_runner(): """ main project runner """ def __init__(self,data): self.data = data self.logger = logging_setup(app="project") def self.main(self): .... Code settings.py THIRD_PARTY_APPS = ( 'south', # Database migration helpers: 'crispy_forms', # Form layouts 'rest_framework', 'djcelery', ) import djcelery djcelery.setup_loader() BROKER_HOST = "127.0.0.1" BROKER_PORT = 5672 # default RabbitMQ listening port BROKER_USER = "test" BROKER_PASSWORD = "test" BROKER_VHOST = "test" CELERY_BACKEND = "amqp" # telling Celery to report the results back to RabbitMQ CELERY_RESULT_DBURI = "" CELERY_IMPORTS = ("input.tasks", ) celeryd The line im running is to start celery, python2.7 manage.py celeryd -l info Thanks,

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  • Matplotlib not showing up in Mac OSX

    - by Werner
    Hi, I am running Mac OSX 10.5.8. I installed matplotlib using macports. I get some examples from the matplotlib gallery like this one, without modification: http://matplotlib.sourceforge.net/examples/api/unicode_minus.html I run it, get no error, but the picture does not show up. In Linux Ubuntu I get it. Do you know what could be wrong here? Thanks

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  • variable being weirdly deleted

    - by calccrypto
    im having a weird problem with one variable: its not being recognized but its still printing. i would post my code, but it is massive. the basic idea is: # pseudocode def function(stuff): <do stuff> # These are the only 2 conditions if tag == 3: pka = <a string> if tag == 4: pka = <a string> print pka # (1) print pka # (2) <do stuff not modifying pka> print pka # (3) if pka == 'RSA': <do stuff> elif pka == 'DSA': <do stuff> my code will error at (2). however, it will print out (1), (2), and (3), all of which are the same. is there any general explanation of why this is happening? if my code is really needed, i will post it, but otherwise, i would rather not due to its size update: now the code will error at the if statement after (3), saying UnboundLocalError: local variable 'pka' referenced before assignment even though (1),(2),(3) just printed

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  • 50 million+ Rows of Data - CSV or MySQL

    - by eWizardII
    Hello, I have a CSV file which is about 1GB big and contains about 50million rows of data, I am wondering is it better to keep it as a CSV file or store it as some form of a database. I don't know a great deal about MySQL to argue for why I should use it or another database framework over just keeping it as a CSV file. I am basically doing a Breadth-First Search with this dataset, so once I get the initial "seed" set the 50million I use this as the first values in my queue. Thanks,

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  • How fast are App Engine db.get(keys) and A.all(keys_only=True).filter('b =', b).fetch(1000)?

    - by Liron Shapira
    A db.get() of 50 keys seems to take me 5-6 seconds. Is that normal? What is the time a function of? I also did a A.all(keys_only=True).filter('b =', b).fetch(1000) where A.b is a ReferenceProperty. I did 50 such round trips to the datastore, with different values of b, and the total time was only 3-4 seconds. How is this possible? db.get() is done in parallel, with only one trip to the datastore, and I would think that looking up an entity by key is a faster operation than fetch.

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  • A faster alternative to Pandas `isin` function

    - by user3576212
    I have a very large data frame df that looks like: ID Value1 Value2 1345 3.2 332 1355 2.2 32 2346 1.0 11 3456 8.9 322 And I have a list that contains a subset of IDs ID_list. I need to have a subset of df for the ID contained in ID_list. Currently, I am using df_sub=df[df.ID.isin(ID_list)] to do it. But it takes a lot time. IDs contained in ID_list doesn't have any pattern, so it's not within certain range. (And I need to apply the same operation to many similar dataframes. I was wondering if there is any faster way to do this. Will it help a lot if make ID as the index? Thanks!

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  • Suffix if statement

    - by Aardschok
    I was looking for a way to add a suffix to jointchain in Maya. The jointchain has specific naming so I create a list with the names they need to be. The first chain has "_1" as suffix, result: R_Clavicle_1|R_UpperArm_1|R_UnderArm_1|R_Wrist_1 When I create the second this is the result: R_Clavicle_2|R_UpperArm_1|R_UnderArm_1|R_Wrist_1 The code: DRClavPos = cmds.xform ('DRClavicle', q=True, ws=True, t=True) DRUpArmPos = cmds.xform ('DRUpperArm', q=True, ws=True, t=True) DRUnArmPos = cmds.xform ('DRUnderArm', q=True, ws=True, t=True) DRWristPos = cmds.xform ('DRWrist', q=True, ws=True, t=True), cmds.xform('DRWrist', q=True, os=True, ro=True) suffix = 1 jntsA = cmds.ls(type="joint", long=True) while True: jntname = ["R_Clavicle_"+str(suffix),"R_UpperArm_"+str(suffix),"R_UnderArm_"+str(suffix),"R_Wrist_"+str(suffix)] if jntname not in jntsA: cmds.select (d=True) cmds.joint ( p=(DRClavPos)) cmds.joint ( p=(DRUpArmPos)) cmds.joint ( 'joint1', e=True, zso=True, oj='xyz', radius=0.5, n=jntname[0]) cmds.joint ( p=(DRUnArmPos)) cmds.joint ( 'joint2', e=True, zso=True, oj='xyz', radius=0.5, n=jntname[1]) cmds.joint ( p=(DRWristPos[0])) cmds.joint ( 'joint3', e=True, zso=True, oj='xyz', radius=0.5, n=jntname[2]) cmds.rename ('joint4', jntname[3]) cmds.select ( cl=True) break else: suffix + 1 I tried adding +1 in jntname which resulted in a good second chain but the third chain had "_2" after R_Clavicle_3 The code, in my eyes should work. Can anybody point me in the correct direction :)

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  • Using Django view variables inside templates

    - by William
    Hi, this is a rather basic question (I'm new to Django) but I'm having trouble using a variable set in my view inside my template. If I initialize a string or list inside my view (i.e. h = "hello") and then attempt to call it inside a template: {{ h }} there is neither output nor errors. Similarly, if I try to use a variable inside my template that doesn't exist: {{ asdfdsadf }} there is again no error reported. Is this normal? And how can I use my variables within my templates. Thanks!

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  • How can this code be made more Pythonic?

    - by usethedeathstar
    This next part of code does exactly what I want it to do. dem_rows and dem_cols contain float values for a number of things i can identify in an image, but i need to get the nearest pixel for each of them, and than to make sure I only get the unique points, and no duplicates. The problem is that this code is ugly and as far as I get it, as unpythonic as it gets. If there would be a pure-numpy-solution (without for-loops) that would be even better. # next part is to make sure that we get the rounding done correctly, and than to get the integer part out of it # without the annoying floatingpoint-error, and without duplicates fielddic={} for i in range(len(dem_rows)): # here comes the ugly part: abusing the fact that i overwrite dictionary keys if I get duplicates fielddic[int(round(dem_rows[i]) + 0.1), int(round(dem_cols[i]) + 0.1)] = None # also very ugly: to make two arrays of integers out of the first and second part of the keys field_rows = numpy.zeros((len(fielddic.keys())), int) field_cols = numpy.zeros((len(fielddic.keys())), int) for i, (r, c) in enumerate(fielddic.keys()): field_rows[i] = r field_cols[i] = c

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  • Cant get the child dir in django hosting (alwaysdata.com) .

    - by zjm1126
    this is my file : mysite templates homepage.html accounts a.html login_view.html i can get the homepage.html and accounts\a.html on 127.0.0.1:8000 but in http://zjm1126.alwaysdata.net , i can only get the homepage.html ,and cant get the account\a.html , this is my code : return render_to_response('accounts/login_view.html') and the accounts/login_view.html is : {% include "accounts\a.html" %} what can i do , thanks ,

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  • Most secure way to generate a random session ID for a cookie?

    - by ensnare
    I'm writing my own sessions controller that issues a unique id to a user once logged in, and then verifies and authenticates that unique id at every page load. What is the most secure way to generate such an id? Should the unique id be completely random? Is there any downside to including the user id as part of the unique id?

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  • Is there something similar to 'rake routes' in django?

    - by The MYYN
    In rails, on can show the active routes with rake (http://guides.rubyonrails.org/routing.html): $ rake routes users GET /users {:controller=>"users", :action=>"index"} formatted_users GET /users.:format {:controller=>"users", :action=>"index"} POST /users {:controller=>"users", :action=>"create"} POST /users.:format {:controller=>"users", :action=>"create"} Is there a similar tool/command for django showing the e.g. the URL pattern, the name of the pattern (if any) and the associated function in the views?

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