Question on SQL Grouping
- by Lijo
Hi Team,
I am trying to achieve the following without using sub query.
For a funding, I would like to select the latest Letter created date and the ‘earliest worklist created since letter created’ date for a funding.
FundingId Leter (1, 1/1/2009 )(1, 5/5/2009) (1, 8/8/2009) (2, 3/3/2009)
FundingId WorkList (1, 5/5/2009 ) (1, 9/9/2009) (1, 10/10/2009) (2, 2/2/2009)
Expected Result -
FundingId Leter WorkList (1, 8/8/2009, 9/9/2009)
I wrote a query as follows. It has a bug. It will omit those FundingId for which the minimum WorkList date is less than latest Letter date (even though it has another worklist with greater than letter created date).
CREATE TABLE #Funding(
[Funding_ID] [int] IDENTITY(1,1) NOT NULL,
[Funding_No] [int] NOT NULL,
CONSTRAINT [PK_Center_Center_ID] PRIMARY KEY NONCLUSTERED ([Funding_ID] ASC)
) ON [PRIMARY]
CREATE TABLE #Letter(
[Letter_ID] [int] IDENTITY(1,1) NOT NULL,
[Funding_ID] [int] NOT NULL,
[CreatedDt] [SMALLDATETIME],
CONSTRAINT [PK_Letter_Letter_ID] PRIMARY KEY NONCLUSTERED ([Letter_ID] ASC)
) ON [PRIMARY]
CREATE TABLE #WorkList(
[WorkList_ID] [int] IDENTITY(1,1) NOT NULL,
[Funding_ID] [int] NOT NULL,
[CreatedDt] [SMALLDATETIME],
CONSTRAINT [PK_WorkList_WorkList_ID] PRIMARY KEY NONCLUSTERED ([WorkList_ID] ASC)
) ON [PRIMARY]
SELECT F.Funding_ID,
Funding_No,
MAX (L.CreatedDt),
MIN(W.CreatedDt)
FROM #Funding F
INNER JOIN #Letter L ON L.Funding_ID = F.Funding_ID
LEFT OUTER JOIN #WorkList W ON W.Funding_ID = F.Funding_ID
GROUP BY F.Funding_ID,Funding_No
HAVING MIN(W.CreatedDt) MAX (L.CreatedDt)
How can I write a correct query without using subquery?
Please help
Thanks
Lijo
