Function returns CSV File: How to go about checking it ?
- by Rachel
I am doing something like:
$outputFile = getCurrentDBSnapshot($data);
where $data is the resource stream that am passing in, basically from command prompt am passing an file and am opening it using fopen for writing with 'w+' permissions, now getCurrentDBSnapshot would get the current state of a table and would update the $data csv file, so basically $outputFile would be updated with the current state of database table, now I want to var_dump or print the value of $outputFile to see the data present into it.
But when I do
$this->fout = fopen($outputFile,'r') or die('Cannot open file');
$test = fgetcsv($outputFile,5000,":");
var_dump($test);
It gives me an error saying that it expects parameter 1 to be a string type and am passing resource.
My goal to see the contains of $outputFile
and so my question is that
How can I see the contains present in $outputFile or how can I see what getcurrentDBSnapshot function is returning me ?
