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  • .NET MVC Ajax Form - How do you hide it?

    - by Tommy
    Ok, everything is 'functionally' working with what I am attempting to accomplish and once again, I am sure this is something dumb, but I cannot figure out how to do this one thing. I have an edit form for an entity, lets say a car. This 'car' can have 0 - many passengers. So on my edit form, I have all the fields for the car, then a list view showing each passenger (partial). I also have a 'add new passenger' button that will render a new partial view that allows you to enter a passenger. This has a cancel link and an add button to submit an Ajax form. When you add a passenger, the passenger is automatically added to the list, but I need the enter passenger form to go away. I have tried using the onSuccess and onComplete functions to hide the div that the form is in, but both render just the partial view HTML elements (white screen, text) and not the partialView in the context of the entire page. Sources: 1) Main Edit View <script type="text/javascript"> Function hideForm(){ document.getElementById('newPassenger').style.display = 'none'; } </script> <h2>Edit</h2> <%-- The following line works around an ASP.NET compiler warning --%> <%= ""%> <%Html.RenderPartial("EditCar", Model)%> <h2>Passengers for this car</h2> <%=Ajax.ActionLink("Add New Passenger", "AddPassenger", New With {.ID = Model.carID}, New AjaxOptions With {.UpdateTargetId = "newPassenger", .InsertionMode = InsertionMode.Replace})%> <div id="newPassenger"></div> <div id="passengerList"> <%Html.RenderPartial("passengerList", Model.Passengers)%> </div> <div> <%= Html.ActionLink("Back to List", "Index") %> </div> 2) AddPassenger View. The cancel link below is an action that returns nothing, thus removing the information in the div. <% Using Ajax.BeginForm("AddPassengerToCar", New With {.id = ViewData("carID")}, New AjaxOptions With {.UpdateTargetId = "passengerList", .InsertionMode = InsertionMode.Replace})%> <%=Html.DropDownList("Passengers")%> <input type="submit" value="Add" /> <%=Ajax.ActionLink("Cancel", "CancelAddControl", _ New AjaxOptions With {.UpdateTargetId = "newPassenger", .InsertionMode = InsertionMode.Replace})%><% end using %>

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  • Fluent | Nhibernate multiple inheritance mapping?

    - by Broken Pipe
    I'm trying to map this classes: public interface IBusinessObject { Guid Id { get; set; } } public class Product { public virtual Guid Id { get; set; } public virtual int ProductTypeId { get; set; } } public class ProductWeSell : Product, IBusinessObject { } public class ProductWeDontSell : Product { } Using this Fluent mapping code: public class IBusinessObjectMap : ClassMap<IBusinessObject> { public IBusinessObjectMap() { Id(t => t.Id).GeneratedBy.Guid(); Table("BusinessObject"); } } public class ProductMap : ClassMap<Product> { public ProductMap() { Id(t => t.Id); DiscriminateSubClassesOnColumn("ProductTypeId", "null").Nullable(); } } public class ProductWeSellMap : SubclassMap<ProductWeSell> { public ProductWeSellMap() { DiscriminatorValue(1); KeyColumn("Id"); } } public class ProductWeDontSellMap : SubclassMap<ProductWeDontSell> { public ProductWeDontSellMap() { DiscriminatorValue(2); KeyColumn("Id"); } } But I get {"Duplicate class/entity mapping ProductWeSell"} error. And if we take a look at generated HBM, indeed it's duplicated, but i have no idea how to write this mapping without duplicating it if it's possible at all. Produced hbm: <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"> <class xmlns="urn:nhibernate-mapping-2.2" name="IBusinessObject" table="BusinessObject"> <joined-subclass name="ProductWeSell" table="ProductWeSell"/> </class> </hibernate-mapping> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"> <class xmlns="urn:nhibernate-mapping-2.2" discriminator-value="null" name="Product" table="Product"> <discriminator type="String"> <column name="ProductTypeId" not-null="false" /> </discriminator> <subclass name="ProductWeDontSell" discriminator-value="2" /> <subclass name="ProductWeSell" discriminator-value="1" /> </class> </hibernate-mapping> So far I was unable to figure out how to map this using fluent Nhibernate (i haven't tried mapping this using hmb files). Any help appreciated Fluent or HBM files. The thing I'm trying to solve look identical to this topic: NHibernate inheritance mapping question

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  • MVVM: how to set the datacontext of a user control

    - by EVA
    Hi, I'm writing an application in WPF, using the MVVm toolkit and have problems with hooking up the viewmodel and view. The model is created with ado.net entity framework. The viewmodel: public class CustomerViewModel { private Models.Customer customer; //constructor private ObservableCollection<Models.Customer> _customer = new ObservableCollection<Models.Customer>(); public ObservableCollection<Models.Customer> AllCustomers { get { return _customer; } } private Models.Customer _selectedItem; public Models.Customer SelectedItem { get { return _selectedItem; } } public void LoadCustomers() { List<Models.Customer> list = DataAccessLayer.getcustomers(); foreach (Models.Customer customer in list) { this._customer.Add(customer); } } } And the view (no code behind at the moment): <UserControl x:Class="Customers.Customer" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" mc:Ignorable="d" xmlns:vm ="clr-namespace:Customers.ViewModels" d:DesignHeight="300" d:DesignWidth="300" xmlns:toolkit="http://schemas.microsoft.com/wpf/2008/toolkit" > <Grid> <toolkit:DataGrid ItemsSource="{Binding AllCustomers}" SelectedItem="{Binding SelectedItem, Mode=TwoWay}" AutoGenerateColumns="True"> </toolkit:DataGrid> <toolkit:DataGrid ItemsSource="{Binding SelectedItem.Orders}"> </toolkit:DataGrid> </Grid> </UserControl> And dataaccesslayer class: class DataAccessLayer { public List<Customer> customers = new List<Customer>(); public static List<Customer> getcustomers() { entities db = new entities(); var customers = from c in db.Customer.Include("Orders") select c; return customers.ToList(); } } The problem is that no data is displayed simply because the data context is not set. I tried to do it in a code-behind but is did not work. I would prefer to do it in a xaml file anyway. Another problem is with the SelectedItem binding - the code is never used. Thanks for help! Regards, EV.

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  • Linq-to-sql Compiled Query returning object NOT belonging to submitted DataContext

    - by Vladimir Kojic
    Compiled query: public static class Machines { public static readonly Func<OperationalDataContext, short, Machine> QueryMachineById = CompiledQuery.Compile((OperationalDataContext db, short machineID) => db.Machines.Where(m => m.MachineID == machineID).SingleOrDefault() ); public static Machine GetMachineById(IUnitOfWork unitOfWork, short id) { Machine machine; // Old code (working) //var machineRepository = unitOfWork.GetRepository<Machine>(); //machine = machineRepository.Find(m => m.MachineID == id).SingleOrDefault(); // New code (making problems) machine = QueryMachineById(unitOfWork.DataContext, id); return machine; } It looks like compiled query is caching Machine object and returning the same object even if query is called from new DataContext (I’m disposing DataContext in the service but I’m getting Machine from previous DataContext). I use POCOs and XML mapping. Revised: It looks like compiled query is returning result from new data context and it is not using the one that I passed in compiled-query. Therefore I can not reuse returned object and link it to another object obtained from datacontext thru non compiled queries. [TestMethod] public void GetMachinesTest() { // Test Preparation (not important) using (var unitOfWork = IoC.Get<IUnitOfWork>()) { var machineRepository = unitOfWork.GetRepository<Machine>(); // GET ALL List<Machine> list = machineRepository.FindAll().ToList<Machine>(); VerifyIntegratedMachine(list[2], 3, "Machine 3", "333333", "G300PET", "MachineIconC.xaml", false, true, LicenseType.Licensed, "10.0.97.3", "10.0.97.3", 0); var machine = Machines.GetMachineById(unitOfWork, 3); Assert.AreSame(list[2], machine); // PASS !!!! } using (var unitOfWork = IoC.Get<IUnitOfWork>()) { var machineRepository = unitOfWork.GetRepository<Machine>(); // GET ALL List<Machine> list = machineRepository.FindAll().ToList<Machine>(); VerifyIntegratedMachine(list[2], 3, "Machine 3", "333333", "G300PET", "MachineIconC.xaml", false, true, LicenseType.Licensed, "10.0.97.3", "10.0.97.3", 0); var machine = Machines.GetMachineById(unitOfWork, 3); Assert.AreSame(list[2], machine); // FAIL !!!! } } If I run other (complex) unit tests I'm getting as expected: An attempt has been made to Attach or Add an entity that is not new, perhaps having been loaded from another DataContext.

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  • JSF Composite Component

    - by purecharger
    I'm trying to create a composite component for use in my Seam application, and I'm running into problems with the simplest "hello, world" component. I have placed a file named hello.xhtml in {jboss deploy}/application.ear/application.war/resources/greet : <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html" xmlns:composite="http://java.sun.com/jsf/composite"> <head> <title>My First Composite Component</title> </head> <body> <composite:interface> <composite:attribute name="who"/> </composite:interface> <composite:implementation> <h:outputText value="Hello, #{cc.attrs.who}!"/> </composite:implementation> </body> </html> Now in home.xhtml, located at the root of my webapp ({jboss deploy}/application.ear/application.war/home.xhtml): <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <ui:composition xmlns="http://www.w3.org/1999/xhtml" xmlns:ui="http://java.sun.com/jsf/facelets" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core" xmlns:g="http://java.sun.com/jsf/composite/greet" xmlns:s="http://jboss.com/products/seam/taglib" template="layout/template.xhtml"> <ui:define name="content"> <div id="content"> <g:hello who="World"/> <br/> </div> </ui:define> </ui:composition> But my "hello, world" is not displayed, and I dont get any error messages, even when I turn on debug level logging for com.sun and javax.faces categories. Any ideas?

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  • Is Ogre's use of Exceptions a good way of using them?

    - by identitycrisisuk
    I've managed to get through my C++ game programming career so far virtually never touching exceptions but recently I've been working on a project with the Ogre engine and I'm trying to learn properly. I've found a lot of good questions and answers here on the general usage of C++ exceptions but I'd like to get some outside opinions from here on whether Ogre's usage is good and how best to work with them. To start with, quoting from Ogre's documentation of it's own Exception class: OGRE never uses return values to indicate errors. Instead, if an error occurs, an exception is thrown, and this is the object that encapsulates the detail of the problem. The application using OGRE should always ensure that the exceptions are caught, so all OGRE engine functions should occur within a try{} catch(Ogre::Exception& e) {} block. Really? Every single Ogre function could throw an exception and be wrapped in a try/catch block? At present this is handled in our usage of it by a try/catch in main that will show a message box with the exception description before exiting. This can be a bit awkward for debugging though as you don't get a stack trace, just the function that threw the error - more important is the function from our code that called the Ogre function. If it was an assert in Ogre code then it would go straight to the code in the debugger and I'd be able to find out what's going on much easier - I don't know if I'm missing something that would allow me to debug exceptions already? I'm starting to add a few more try/catch blocks in our code now, generally thinking about whether it matters if the Ogre function throws an exception. If it's something that will stop everything working then let the main try/catch handle it and exit the program. If it's not of great importance then catch it just after the function call and let the program continue. One recent example of this was building up a vector of the vertex/fragment program parameters for materials applied to an entity - if a material didn't have any parameters then it would throw an exception, which I caught and then ignored as it didn't need to add to my list of parameters. Does this seem like a reasonable way of dealing with things? Any specific advice for working with Ogre is much appreciated.

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  • Use a subdirectory as root with htaccess in Apache 1.3

    - by Andrew
    I'm trying to deploy a site generated with Jekyll and would like to keep the site in its own subfolder on my server to keep everything more organized. Essentially, I'd like to use the contents of /jekyll as the root unless a file similarly named exists in the actual web root. So something like /jekyll/sample-page/ would show as http://www.example.com/sample-page/, while something like /other-folder/ would display as http://www.example.com/other-folder. My test server runs Apache 2.2 and the following .htaccess (adapted from http://gist.github.com/97822) works flawlessly: RewriteEngine On # Map http://www.example.com to /jekyll. RewriteRule ^$ /jekyll/ [L] # Map http://www.example.com/x to /jekyll/x unless there is a x in the web root. RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_URI} !^/jekyll/ RewriteRule ^(.*)$ /jekyll/$1 # Add trailing slash to directories without them so DirectoryIndex works. # This does not expose the internal URL. RewriteCond %{REQUEST_FILENAME} -d RewriteCond %{REQUEST_FILENAME} !/$ RewriteRule ^(.*)$ $1/ # Disable auto-adding slashes to directories without them, since this happens # after mod_rewrite and exposes the rewritten internal URL, e.g. turning # http://www.example.com/about into http://www.example.com/jekyll/about. DirectorySlash off However, my production server runs Apache 1.3, which doesn't allow DirectorySlash. If I disable it, the server gives a 500 error because of internal redirect overload. If I comment out the last section of ReWriteConds and rules: RewriteCond %{REQUEST_FILENAME} -d RewriteCond %{REQUEST_FILENAME} !/$ RewriteRule ^(.*)$ $1/ …everything mostly works: http://www.example.com/sample-page/ displays the correct content. However, if I omit the trailing slash, the URL in the address bar exposes the real internal URL structure: http://www.example.com/jekyll/sample-page/ What is the best way to account for directory slashes in Apache 1.3, where useful tools like DirectorySlash don't exist? How can I use the /jekyll/ directory as the site root without revealing the actual URL structure? Edit: After a ton of research into Apache 1.3, I've found that this problem is essentially a combination of two different issues listed at the Apache 1.3 URL Rewriting Guide. I have a (partially) moved DocumentRoot, which in theory would be taken care of with something like this: RewriteRule ^/$ /e/www/ [R] I also have the infamous "Trailing Slash Problem," which is solved by setting the RewriteBase (as was suggested in one of the responses below): RewriteBase /~quux/ RewriteRule ^foo$ foo/ [R] The problem is combining the two. Moving the document root doesn't (can't?) use RewriteBase—fixing trailing slashes requires(?) it… Hmm…

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  • EJB client can't find a DataSource that tests successfully in WebLogic admin console

    - by suszterpatt
    Disclaimer: I'm completely new to JEE/EJB and all that, so bear with me. I have a simple EJB that I can successfully deploy using JDeveloper 11g's integrated WebLogic server and a remote database connection (JDBC). I have a DataSource named "PGY2" defined in WebLogic, and I can test it successfully from the admin console. Here's the code of the client I'm trying to test it with (generated entirely by JDev except for the three method calls on adminManager): public class AdminManagerClient { public static void main(String [] args) { try { final Context context = getInitialContext(); AdminManager adminManager = (AdminManager)context.lookup("Uran-AdminManager#hu.elte.pgy2.BACNAAI.UranEJB.AdminManager"); adminManager.addAdmin("root", "root", "Kovács Isten"); adminManager.addStudent("BACNAAI", "matt", "B Cs", 2005); adminManager.addTeacher("SIPKABT", "patt", "S P", "numanal", "Dr."); } catch (Exception ex) { ex.printStackTrace(); } } private static Context getInitialContext() throws NamingException { Hashtable env = new Hashtable(); // WebLogic Server 10.x connection details env.put( Context.INITIAL_CONTEXT_FACTORY, "weblogic.jndi.WLInitialContextFactory" ); env.put(Context.PROVIDER_URL, "t3://127.0.0.1:7101"); return new InitialContext( env ); } } But when I try to run this, I get the following error on the line with adminManager.addAdmin (that is, after the lookup): javax.ejb.EJBException: EJB Exception: ; nested exception is: Exception [EclipseLink-4002] (Eclipse Persistence Services - 1.0.2 (Build 20081024)): org.eclipse.persistence.exceptions.DatabaseException Internal Exception: java.sql.SQLException: Internal error: Cannot obtain XAConnection Creation of XAConnection for pool PGY2 failed after waitSecs:30 : java.sql.SQLException: Data Source PGY2 does not exist. Why can't the client find the data source, and how do I make it find it? EDIT: I took a closer look at WebLogic's output during deployment, and I found this. I have no idea what it means, but it may be relevant: <2010.05.20. 0:50:43 CEST> <Error> <Deployer> <BEA-149231> <Unable to set the activation state to true for the application 'PGY2'. weblogic.application.ModuleException: at weblogic.jdbc.module.JDBCModule.activate(JDBCModule.java:349) at weblogic.application.internal.flow.ModuleListenerInvoker.activate(ModuleListenerInvoker.java:107) at weblogic.application.internal.flow.DeploymentCallbackFlow$2.next(DeploymentCallbackFlow.java:411) at weblogic.application.utils.StateMachineDriver.nextState(StateMachineDriver.java:37) at weblogic.application.internal.flow.DeploymentCallbackFlow.activate(DeploymentCallbackFlow.java:74) Truncated. see log file for complete stacktrace weblogic.common.ResourceException: is already bound at weblogic.jdbc.common.internal.RmiDataSource.start(RmiDataSource.java:387) at weblogic.jdbc.common.internal.DataSourceManager.createAndStartDataSource(DataSourceManager.java:136) at weblogic.jdbc.common.internal.DataSourceManager.createAndStartDataSource(DataSourceManager.java:97) at weblogic.jdbc.module.JDBCModule.activate(JDBCModule.java:346) at weblogic.application.internal.flow.ModuleListenerInvoker.activate(ModuleListenerInvoker.java:107) Truncated. see log file for complete stacktrace >

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  • PHP Doctrine frustration: loading models doesn't work..?

    - by ropstah
    I'm almost losing it, i really hope someone can help me out! I'm using Doctrine with CodeIgniter. Everything is setup correctly and works until I generate the classes and view the website. Fatal error: Class 'BaseObjecten' not found in /var/www/vhosts/domain.com/application/models/Objecten.php on line 13 I'm using the following bootstrapper (as CodeIgniter plugin): <?php // system/application/plugins/doctrine_pi.php // load Doctrine library require_once BASEPATH . '/plugins/Doctrine/lib/Doctrine.php'; // load database configuration from CodeIgniter require_once APPPATH.'/config/database.php'; // this will allow Doctrine to load Model classes automatically spl_autoload_register(array('Doctrine', 'autoload')); // we load our database connections into Doctrine_Manager // this loop allows us to use multiple connections later on foreach ($db as $connection_name => $db_values) { // first we must convert to dsn format $dsn = $db[$connection_name]['dbdriver'] . '://' . $db[$connection_name]['username'] . ':' . $db[$connection_name]['password']. '@' . $db[$connection_name]['hostname'] . '/' . $db[$connection_name]['database']; Doctrine_Manager::connection($dsn,$connection_name); } // CodeIgniter's Model class needs to be loaded require_once BASEPATH.'/libraries/Model.php'; // telling Doctrine where our models are located Doctrine::loadModels(APPPATH.'/models'); // (OPTIONAL) CONFIGURATION BELOW // this will allow us to use "mutators" Doctrine_Manager::getInstance()->setAttribute( Doctrine::ATTR_AUTO_ACCESSOR_OVERRIDE, true); // this sets all table columns to notnull and unsigned (for ints) by default Doctrine_Manager::getInstance()->setAttribute( Doctrine::ATTR_DEFAULT_COLUMN_OPTIONS, array('notnull' => true, 'unsigned' => true)); // set the default primary key to be named 'id', integer, 4 bytes Doctrine_Manager::getInstance()->setAttribute( Doctrine::ATTR_DEFAULT_IDENTIFIER_OPTIONS, array('name' => 'id', 'type' => 'integer', 'length' => 4)); ?> Anyone? p.s. I also tried adding the following right after // (OPTIONAL CONFIGURATION) Doctrine_Manager::getInstance()->setAttribute(Doctrine::ATTR_MODEL_LOADING, Doctrine::MODEL_LOADING_CONSERVATIVE); spl_autoload_register(array('Doctrine', 'modelsAutoload'));

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  • PostgreSQL and PHP forms

    - by MrEnder
    Ok I have a PostgreSQL server with a Database titled brittains_db that I only have PuTTY access to. I can also upload via FTP to the web server which has access to PostgreSQL and the Database somehow... I have made a SQL file named logins.sql CREATE TABLE logins( userName VARCHAR(25) NOT NULL PRIMARY KEY, password VARCHAR(25) NOT NULL, firstName NOT NULL, lastName NOT NULL, ageDay INTEGER NOT NULL, ageMonth INTEGER NOT NULL, ageYear INTEGER NOT NULL, email VARCHAR(255) NOT NULL, createDate DATE ) Then I made a form to get all that information. <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" > <table> <tr> <td class="signupTd"> First Name:&nbsp; </td> <td> <input type="text" name="firstNameSignupForm" value="<?php echo $firstNameSignup; ?>" size="20"/> </td> <td> <?php echo $firstNameSignupError; ?> </td> </tr> ... code continues I had it save all the information in variables if page run on POST $firstNameSignup=trim($_POST["firstNameSignupForm"]); $lastNameSignup=trim($_POST["lastNameSignupForm"]); $userNameSignup=trim($_POST["userNameSignupForm"]); $passwordSignup=trim($_POST["passwordSignupForm"]); $passwordConfirmSignup=trim($_POST["passwordConfirmSignupForm"]); $monthSignup=trim($_POST["monthSignupForm"]); $daySignup=trim($_POST["daySignupForm"]); $yearSignup=trim($_POST["yearSignupForm"]); $emailSignup=trim($_POST["emailSignupForm"]); $emailConfirmSignup=trim($_POST["emailConfirmSignupForm"]); All information was then validated Now comes the points where I need to upload it to PostgreSQL How do I put my table in Postgre? How do I insert my information into my table? and how would I recall that information to display it?

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  • Scared of Calculus - Required to pass Differential Calculus as part of my Computer science major

    - by ke3pup
    Hi guys I'm finishing my Computer science degree in university but my fear of maths (lack of background knowledge) made me to leave all my maths units til' the very end which is now. i either take them on and pass or have to give up. I've passed all my programming units easily but knowing my poor maths skills won't do i've been staying clear of the maths units. I have to pass Differential Calculus and Linear Algebra first. With a help of book named "Linear Algebra: A Modern Introduction" i'm finding myself on track and i think i can pass the Linear Algebra unit. But with differential calculus i can't find a book to help me. They're either too advanced or just too simple for what i have to learn. The things i'm required to know for this units are: Set notation, the real number line, Complex numbers in cartesian form. Complex plane, modulus. Complex numbers in polar form. De Moivre’s Theorem. Complex powers and nth roots. Definition of ei? and ez for z complex. Applications to trigonometry. Revision of domain and range of a function Working in R3. Curves and surfaces. Functions of 2 variables. Level curves.Partial derivatives and tangent planes. The derivative as a difference quotient. Geometric significance of the derivative. Discussion of limit. Higher order partial derivatives. Limits of f(x,y). Continuity. Maxima and minima of f(x,y). The chain rule. Implicit differentiation. Directional derivatives and the gradient. Limit laws, l’Hoˆpital’s rule, composition law. Definition of sinh and cosh and their inverses. Taylor polynomials. The remainder term. Taylor series. Is there a book to help me get on track with the above? Being a student i can't buy too many books hence why i'm looking for a book that covers topics I need to know. The University library has a fairly limited collection which i took as loan but didn't find useful as it was too complex.

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  • CodeGolf: Brothers

    - by John McClane
    Hi guys, I just finished participating in the 2009 ACM ICPC Programming Conest in the Latinamerican Finals. These questions were for Brazil, Bolivia, Chile, etc. My team and I could only finish two questions out of the eleven (not bad I think for the first try). Here's one we could finish. I'm curious to seeing any variations to the code. The question in full: ps: These questions can also be found on the official ICPC website available to everyone. In the land of ACM ruled a greeat king who became obsessed with order. The kingdom had a rectangular form, and the king divided the territory into a grid of small rectangular counties. Before dying the king distributed the counties among his sons. The king was unaware of the rivalries between his sons: The first heir hated the second but not the rest, the second hated the third but not the rest, and so on...Finally, the last heir hated the first heir, but not the other heirs. As soon as the king died, the strange rivaly among the King's sons sparked off a generalized war in the kingdom. Attacks only took place between pairs of adjacent counties (adjacent counties are those that share one vertical or horizontal border). A county X attacked an adjacent county Y whenever X hated Y. The attacked county was always conquered. All attacks where carried out simultanously and a set of simultanous attacks was called a battle. After a certain number of battles, the surviving sons made a truce and never battled again. For example if the king had three sons, named 0, 1 and 2, the figure below shows what happens in the first battle for a given initial land distribution: INPUT The input contains several test cases. The first line of a test case contains four integers, N, R, C and K. N - The number of heirs (2 <= N <= 100) R and C - The dimensions of the land. (2 <= R,C <= 100) K - Number of battles that are going to take place. (1 <= K <= 100) Heirs are identified by sequential integers starting from zero. Each of the next R lines contains C integers HeirIdentificationNumber (saying what heir owns this land) separated by single spaces. This is to layout the initial land. The last test case is a line separated by four zeroes separated by single spaces. (To exit the program so to speak) Output For each test case your program must print R lines with C integers each, separated by single spaces in the same format as the input, representing the land distribution after all battles. Sample Input: Sample Output: 3 4 4 3 2 2 2 0 0 1 2 0 2 1 0 1 1 0 2 0 2 2 2 0 0 1 2 0 0 2 0 0 0 1 2 2 Another example: Sample Input: Sample Output: 4 2 3 4 1 0 3 1 0 3 2 1 2 2 1 2

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  • .NET asmx web services: serialize object property as string property to support versioning

    - by mcliedtk
    I am in the process of upgrading our web services to support versioning. We will be publishing our versioned web services like so: http://localhost/project/services/1.0/service.asmx http://localhost/project/services/1.1/service.asmx One requirement of this versioning is that I am not allowed to break the original wsdl (the 1.0 wsdl). The challenge lies in how to shepherd the newly versioned classes through the logic that lies behind the web services (this logic includes a number of command and adapter classes). Note that upgrading to WCF is not an option at the moment. To illustrate this, let's consider an example with Blogs and Posts. Prior to the introduction of versions, we were passing concrete objects around instead of interfaces. So an AddPostToBlog command would take in a Post object instead of an IPost. // Old AddPostToBlog constructor. public AddPostToBlog(Blog blog, Post post) { // constructor body } With the introduction of versioning, I would like to maintain the original Post while adding a PostOnePointOne. Both Post and PostOnePointOne will implement the IPost interface (they are not extending an abstract class because that inheritance breaks the wsdl, though I suppose there may be a way around that via some fancy xml serialization tricks). // New AddPostToBlog constructor. public AddPostToBlog(Blog blog, IPost post) { // constructor body } This brings us to my question regarding serialization. The original Post class has an enum property named Type. For various cross-platform compatibility issues, we are changing our enums in our web services to strings. So I would like to do the following: // New IPost interface. public interface IPost { object Type { get; set; } } // Original Post object. public Post { // The purpose of this attribute would be to maintain how // the enum currently is serialized even though now the // type is an object instead of an enum (internally the // object actually is an enum here, but it is exposed as // an object to implement the interface). [XmlMagic(SerializeAsEnum)] object Type { get; set; } } // New version of Post object public PostOnePointOne { // The purpose of this attribute would be to force // serialization as a string even though it is an object. [XmlMagic(SerializeAsString)] object Type { get; set; } } The XmlMagic refers to an XmlAttribute or some other part of the System.Xml namespace that would allow me to control the type of the object property being serialized (depending on which version of the object I am serializaing). Does anyone know how to accomplish this?

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  • OSGI classcast exception on felix

    - by Nico
    Hi, i'm fairly new to osgi and am trying to get a functional proof of concept together. The setup is that my common api is created in a bundle creatively named common-api.jar with no bundle activator, but it exports all it's interfaces. the one of interest in this situation is DatabaseService.java. I then have a Second bundle called systemx-database-service. That implements the database service interface. this works fine as in the activator of the implementation bundle i test the connection to the database and select some arbitraty values. I also register the service i want to be available to the other bundle's like so: context.registerService(DatabaseService.class.getName(), new SystemDatabaseServiceImpl(context), new Properties()); The basic idea being when you look for a service reference for a Database service you'll get back the SystemDatabaseService implementation. When i do a inspect service the output it this: -> inspect s c 69 System Database Service (69) provides services: ---------------------------------------------- objectClass = za.co.xxx.xxx.common.api.DatabaseService service.id = 39 which would lead me to believe that if i do this in a test bundle: context.getService(context.getServiceReference(DatabaseService.class)); i should get back an instance of DatabaseService.class, but alas no such luck. it simply seems like it cannot find the service. stick with me here my story gets stranger. figuring there is no where to go but up i wrote this monstrosity: for (Bundle bundle : bundles) { if (bundle.getSymbolicName().equals("za.co.xxx.xxx.database-service")) { ServiceReference[] registeredServices = bundle.getRegisteredServices(); for (ServiceReference ref : registeredServices) { DatabaseService service = (DatabaseService) context.getService(ref); // use service here. } } } } now i can actually see the service reference, but i get this error java.lang.ClassCastException: za.co.xxx.xxx.database.service.impl.SystemDatabaseServiceImpl cannot be cast to za.co.xxx.xx.common.api.DatabaseService which is crazy since the implementation clearly implements the interface! Any help would be appreciated. Please keep in mind i'm very new at the osgi way of thinking so my whole approach here might be flawed. oh. if anyone wants the manifests i can post them. and i'm using the maven-bnd-plugin to build and executing on felix. thanks Nico

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  • Suggest the best options to me to design the dynamic web interface using PHP MYSQL and AJAX

    - by Krishna
    Hello, I am designing a web interface for a company. I am describing the company's profile: company is currently having 5 branches and planning to extend their branches all over the country. it is an insurance surveying company. they are dealing with 6 Categories in the insurance domain, vide .. Engineering Fire Marine Motor Miscellaneous Risk Inspection and branches named as b1, b2, b3, b4, b5 and Extending. and finally they have contract with 22 companies. For each claim they are assign a unique ID. like contractcompany/category/serialno Ex: take a contracted company names as xxx, sss, zzz. xxx/Engineering/001 sss/Engineering/001 . . . xxx/Enginnering/002 sss/Engineering/002 . . . xxx/Fire/001 sss/Fire/001 . . . xxx/Fire/002 . . . xxx/Fire/002 . . . and so on..... by this way they issue the unique ID for each claim. Finally what i want is developing the interface with PHP mysql and ajax auto generating the unique id for each claim. store full details of the claims with reference to unique id. show all claims in one page, and they can view by branch wise and category wise. send monthly Report (All claims they have given and status of claims) to contract companies. give access to contracted companies, but they can view only their respective claims. Each claim has its own documents. So they can be uploaded by own company users or administrator. these files are associated with unique ID. contracted companies can view files. Give access to branches to enter new claims and update old claims. Administrator can create, update and delete all the claims and their details. Only administrator can grant new users (own company branches / contracted companies) Finally the the panel is completely database driven. Could any body can help. Thanks in advance Kindly do the needful and oblige Thanks and Regards Krishna. P [email protected]

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  • WPF DataTemplates with VS2010 designer support + reusable - would you do it that way?

    - by Christian
    Ok, I am currently tidying up all my old stuff. I ran into the issue of "code only DataTemplates" - which are really a pain in the ass. You can't see anything, they are really hard to design, and I want to improve my project. So I had the idea to use the following solution. The main benefits are: You have designer support for your data template You can easily include example sample data The file naming is consistent and easy to remember The preview does not require an additional XAML wrapper (even with code only controls) I will try to explain and illustrate my solution using a few pictures. I am interested in feedback, especially if you can imagine a better way to do it. And, of course, if you see any maintenance or performance issues. Ok, lets start with a simple PreviewObject. I want to have some data in it, so I create a subclass which will automatically fill in some dummy data. Then I add a list to the control, and name this list. Afterwards I add a DataTemplate, this is the sole reason for the whole control (to be able to see and edit the DataTemplate in place): Now I use this control to get my DataTemplate, to use it in other places. To make this easier, I added some code in the code behind, see here: Now I want a control to show me a list of PreviewItems, so I created a "code-only" control which creates an instance of my service (or gets one using DI in real world) and fills its list box with it: To view the result of this work, I added this control inside the same named XAML, this is basically only to be able to see the final result: What I do not like in this solution: The need to create the last control in "code only". So I tried something different while writing this post. The following two screenshots illustrate the approach. I am creating an instance of the service inside the DataContext, and I am using bindings to supply the Itemssourc and the ItemTemplate. The reason for the strange "static property" is refactoring support. If I hardcode the path in the designer (e.g. using "Path = PreviewHistory") and I refactor the names (which happens quite often, early design phase) - I screw up my controls without realizing it. Does anyone has a better idea for this? I am using Resharper, btw. Thanks for any input, and sorry for the image overkill. Just easier to explain that way.. Chris

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  • SVN directories not showing up in localhost when using WAMP

    - by JsusSalv
    Hi: I recently installed WAMP for actual local use. I've worked on live development servers but now am working on localhost. I've managed to get multiple virtual hosts setup on my WAMP/Vista 64-bit box but am having difficulty with directories pulled from SVN. I have four vhosts setup. Two work well and they are not tied to any SVN just yet. I'm also using TortoiseSVN in case it makes any difference. However, the other projects are coming from SVN repositories. When I view these two projects I get the following error: Internal Server Error The server encountered an internal error or misconfiguration and was unable to complete your request. Please contact the server administrator, admin@localhost and inform them of the time the error occurred, and anything you might have done that may have caused the error. More information about this error may be available in the server error log. The way I setup the vhosts is as follows: httpd.conf # Multiple Virtual Hosts <VirtualHost 127.0.0.1> ServerName localhost DocumentRoot "C:/wamp/www/" </VirtualHost> <VirtualHost 127.0.1.0> ServerName testone.local DocumentRoot "C:/wamp/www/root/projectone/" </VirtualHost> <VirtualHost 127.0.2.0> ServerName testtwo.local DocumentRoot "C:/wamp/www/root/projecttwo/" </VirtualHost> <VirtualHost 127.0.3.0> ServerName testthree.local DocumentRoot "C:/wamp/www/root/projectthree/" </VirtualHost> <VirtualHost 127.0.3.1> ServerName testfour.local DocumentRoot "C:/wamp/www/root/projectfour/" </VirtualHost> And here's the 'hosts' file: # Localhost 127.0.0.1 localhost ::1 localhost # Project One 127.0.1.0 testone.local # Project Two 127.0.2.0 testtwo.local # Project Three 127.0.3.0 testthree.local # Project Four 127.0.3.1 testfour.local Everything works just fine. So if you want to tell me I'm doing something wrong then by all means point out a few things. But as it stands, it works and I'm content using different IPs and/or named-based vhosts. The problem comes in not being able to see the directories and files in the projects that are tied to an SVN. Whenever I visit http://testxxxx.local I get the error message at the top of this post. Please provide some suggestions. Thank you!

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  • Add rss xmlns namespace definition to a php simplexml document?

    - by talkingnews
    I'm trying to create an itunes-valid podcast feed using php5's simplexml: <?php $xml_string = <<<XML <?xml version="1.0" encoding="UTF-8"?> <channel> </channel> XML; $xml_generator = new SimpleXMLElement($xml_string); $tnsoundfile = $xml_generator->addChild('title', 'Main Title'); $tnsoundfile->addChild('itunes:author', "Author", ' '); $tnsoundfile->addChild('category', 'Audio Podcasts'); $tnsoundfile = $xml_generator->addChild('item'); $tnsoundfile->addChild('title', 'The track title'); $enclosure = $tnsoundfile->addChild('enclosure'); $enclosure->addAttribute('url', 'http://test.com'); $enclosure->addAttribute('length', 'filelength'); $enclosure->addAttribute('type', 'audio/mpeg'); $tnsoundfile->addChild('itunes:author', "Author", ' '); header("Content-Type: text/xml"); echo $xml_generator->asXML(); ?> It doesn't validate, because I've got to put the line: <rss xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd" version="2.0"> as per http://www.apple.com/itunes/podcasts/specs.html. So the output SHOULD be: <?xml version="1.0" encoding="UTF-8"?> <rss xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd" version="2.0"> <channel> etc. I've been over and over the manual and forums, just can't get it right. If I put, near the footer: header("Content-Type: text/xml"); echo '<rss xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd" version="2.0">'; echo $xml_generator->asXML(); ?> Then it sort of looks right in firefox and it doesn't complain about undefined namespaces anymore, but feedvalidator complains that line 1, column 77: XML parsing error: :1:77: xml declaration not at start of external entity [help] because the document now starts: <rss xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd" version="2.0"><?xml version="1.0" encoding="UTF-8"?> and not <?xml version="1.0" encoding="UTF-8"?><rss xmlns:itunes="http://www.itunes.com/dtds/podcast-1.0.dtd" version="2.0"> Thank you in advance.

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  • Setting up Django on an internal server (os.environ() not working as expected?)

    - by monkut
    I'm trying to setup Django on an internal company server. (No external connection to the Internet.) Looking over the server setup documentation it appears that the "Running Django on a shared-hosting provider with Apache" method seems to be the most-likely to work in this situation. Here's the server information: Can't install mod_python no root access Server is SunOs 5.6 Python 2.5 Apache/2.0.46 I've installed Django (and flup) using the --prefix option (reading again I probably should've used --home, but at the moment it doesn't seem to matter) I've added the .htaccess file and mysite.fcgi file to my root web directory as mentioned here. When I run the mysite.fcgi script from the server I get my expected output (the correct site HTML output). But, it won't when trying to access it from a browser. It seems that it may be a problem with the PYTHONPATH setting since I'm using the prefix option. I've noticed that if I run mysite.fcgi from the command-line without setting the PYTHONPATH enviornment variable it throws the following error: prompt$ python2.5 mysite.fcgi ERROR: No module named flup Unable to load the flup package. In order to run django as a FastCGI application, you will need to get flup from http://www.saddi.com/software/flup/ If you've already installed flup, then make sure you have it in your PYTHONPATH. I've added sys.path.append(prefixpath) and os.environ['PYTHONPATH'] = prefixpath to mysite.fcgi, but if I set the enviornment variable to be empty on the command-line then run mysite.fcgi, I still get the above error. Here are some command-line results: >>> os.environ['PYTHONPATH'] = 'Null' >>> >>> os.system('echo $PYTHONPATH') Null >>> os.environ['PYTHONPATH'] = '/prefix/path' >>> >>> os.system('echo $PYTHONPATH') /prefix/path >>> exit() prompt$ echo $PYTHONPATH Null It looks like Python is setting the variable OK, but the variable is only applicable inside of the script. Flup appears to be distributed as an .egg file, and my guess is that the egg implementation doesn't take into account variables added by os.environ['key'] = value (?) at least when installing via the --prefix option. I'm not that familiar with .pth files, but it seems that the easy-install.pth file is the one that points to flup: import sys; sys.__plen = len(sys.path) ./setuptools-0.6c6-py2.5.egg ./flup-1.0.1-py2.5.egg import sys; new=sys.path[sys.__plen:]; del sys.path[sys.__plen:]; p=getattr(sys,'__egginsert',0); sy s.path[p:p]=new; sys.__egginsert = p+len(new) It looks like it's doing something funky, anyway to edit this or add something to my code so it will find flup?

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  • Rails scalar query

    - by Craig
    I need to display a UI element (e.g. a star or checkmark) for employees that are 'favorites' of the current user (another employee). The Employee model has the following relationship defined to support this: has_and_belongs_to_many :favorites, :class_name => "Employee", :join_table => "favorites", :association_foreign_key => "favorite_id", :foreign_key => "employee_id" The favorites has two fields: employee_id, favorite_id. If I were to write SQL, the following query would give me the results that I want: SELECT id, account, IF( ( SELECT favorite_id FROM favorites WHERE favorite_id=p.id AND employee_id = ? ) IS NULL, FALSE, TRUE) isFavorite FROM employees Where the '?' would be replaced by the session[:user_id]. How do I represent the isFavorite scalar query in Rails? Another approach would use a query like this: SELECT id, account, IF(favorite_id IS NULL, FALSE, TRUE) isFavorite FROM employees e LEFT OUTER JOIN favorites f ON e.id=f.favorite_id AND employee_id = ? Again, the '?' is replaced by the session[:user_id] value. I've had some success writing this in Rails: ee=Employee.find(:all, :joins=>"LEFT OUTER JOIN favorites ON employees.id=favorites.favorite_id AND favorites.employee_id=1", :select=>"employees.*,favorites.favorite_id") Unfortunately, when I try to make this query 'dynamic' by replacing the '1' with a '?', I get errors. ee=Employee.find(:all, :joins=>["LEFT OUTER JOIN favorites ON employees.id=favorites.favorite_id AND favorites.employee_id=?",1], :select=>"employees.*,favorites.favorite_id") Obviously, I have the syntax wrong, but can :joins expressions be 'dynamic'? Is this a case for a Lambda expression? I do hope to add other filters to this query and use it with will_paginate and acts_as_taggable_on, if that makes a difference. edit errors from trying to make :joins dynamic: ActiveRecord::ConfigurationError: Association named 'LEFT OUTER JOIN favorites ON employees.id=favorites.favorite_id AND favorites.employee_id=?' was not found; perhaps you misspelled it? from /Users/craibuc/.gem/ruby/1.8/gems/activerecord-2.3.5/lib/active_record/associations.rb:1906:in `build' from /Users/craibuc/.gem/ruby/1.8/gems/activerecord-2.3.5/lib/active_record/associations.rb:1911:in `build' from /Users/craibuc/.gem/ruby/1.8/gems/activerecord-2.3.5/lib/active_record/associations.rb:1910:in `each' from /Users/craibuc/.gem/ruby/1.8/gems/activerecord-2.3.5/lib/active_record/associations.rb:1910:in `build' from /Users/craibuc/.gem/ruby/1.8/gems/activerecord-2.3.5/lib/active_record/associations.rb:1830:in `initialize' from /Users/craibuc/.gem/ruby/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:1789:in `new' from /Users/craibuc/.gem/ruby/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:1789:in `add_joins!' from /Users/craibuc/.gem/ruby/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:1686:in `construct_finder_sql' from /Users/craibuc/.gem/ruby/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:1548:in `find_every' from /Users/craibuc/.gem/ruby/1.8/gems/activerecord-2.3.5/lib/active_record/base.rb:615:in `find'

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  • hibernate column uniqueness question

    - by Seth
    I'm still in the process of learning hibernate/hql and I have a question that's half best practices question/half sanity check. Let's say I have a class A: @Entity public class A { @Id @GeneratedValue(strategy=GenerationType.AUTO) private Long id; @Column(unique=true) private String name = ""; //getters, setters, etc. omitted for brevity } I want to enforce that every instance of A that gets saved has a unique name (hence the @Column annotation), but I also want to be able to handle the case where there's already an A instance saved that has that name. I see two ways of doing this: 1) I can catch the org.hibernate.exception.ConstraintViolationException that could be thrown during the session.saveOrUpdate() call and try to handle it. 2) I can query for existing instances of A that already have that name in the DAO before calling session.saveOrUpdate(). Right now I'm leaning towards approach 2, because in approach 1 I don't know how to programmatically figure out which constraint was violated (there are a couple of other unique members in A). Right now my DAO.save() code looks roughly like this: public void save(A a) throws DataAccessException, NonUniqueNameException { Session session = sessionFactory.getCurrentSession(); try { session.beginTransaction(); Query query = null; //if id isn't null, make sure we don't count this object as a duplicate if(obj.getId() == null) { query = session.createQuery("select count(a) from A a where a.name = :name").setParameter("name", obj.getName()); } else { query = session.createQuery("select count(a) from A a where a.name = :name " + "and a.id != :id").setParameter("name", obj.getName()).setParameter("name", obj.getName()); } Long numNameDuplicates = (Long)query.uniqueResult(); if(numNameDuplicates > 0) throw new NonUniqueNameException(); session.saveOrUpdate(a); session.getTransaction().commit(); } catch(RuntimeException e) { session.getTransaction().rollback(); throw new DataAccessException(e); //my own class } } Am I going about this in the right way? Can hibernate tell me programmatically (i.e. not as an error string) which value is violating the uniqueness constraint? By separating the query from the commit, am I inviting thread-safety errors, or am I safe? How is this usually done? Thanks!

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  • Adding ComboBoxItem to a combobox inside a user control (XAML/WPF)

    - by byte
    I am currently learning to create custom controls in WPF. I successfully created a simple custom control using a Label and a Text Box. I was able to allow setting the Label text by DependencyProperty. Now I am creating a user control that has a ComboBox. I need to allow adding items to this ComboBox from outside the control. To achieve this, I tried exposing a DependencyProperty of type ItemsCollection and it will allows access to the ComboBox's Items property (the DP in my control sample is named 'CbItems'). But I get errors because Items property of Combobox is ReadOnly. Control XAML <UserControl x:Class="MyWpfApp.Controls.MyControl" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Height="Auto" Width="Auto"> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition /> <ColumnDefinition /> </Grid.ColumnDefinitions> <Label Grid.Column="0" Content="{Binding FieldLabel}"></Label> <ComboBox Name="cmb" Grid.Column="1" Width="150"></ComboBox> </Grid> </UserControl> MainWindow XAML <Window x:Class="MyWpfApp.Window1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:ctl="clr-namespace:MyWpfApp.Controls" Title="Window1" Height="300" Width="300"> <Grid> <ctl:MyControl> <ctl:MyControl.CbItems> <ComboBoxItem>Hello</ComboBoxItem> <ComboBoxItem>World</ComboBoxItem> <ComboBoxItem>Hi</ComboBoxItem> </ctl:LobCombox.CbItems> </ctl:LobCombox> </Grid> </Window> I would like to know what the correct way is to achieve this functionality. I believe the answer to this might also help with other controls like GridView etc Many Thanks

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  • Am I "wasting" my time learning C and other low level stuff ?

    - by Andreas Grech
    I have just recently started learning C and the reason I did that was because frankly, I consider myself to be of a "less-developer" than the people who know and work with C. Thus I planned to start learning ASM, C, C++ and bought the K&R book and started pushing myself to learn the C Programming Language and up till now I'm doing great...learning about arrays the low level way (ie the pointer + offset thing), pointers and all that and obviously asking questions on stackoverflow for guidance. My problem is that sometimes I get thinking if instead of learning this low level stuff, maybe I should maybe spend more time learning newer, more widely used technologies...basically, more web stuff. Now I am well versed with both C# and ASP.Net and currently that's what I do for a living, but still there exists Microsoft technologies that I haven't quite touched upon...such as ASP.Net MVC, The Entity Framework etc... And those are only Microsoft Technologies...obviously there are other stuff that I would like to touch upon...stuff like Ruby, which would lead me to Ruby on Rails, or Python for Django or even Java and J2EE, or maybe even PHP; ie, basically mainly Web Stuff. Mind you, I did touch upon some of the stuff I mentioned earlier on, such as PHP and Java but I am still not quite versed in them as I am in C# and ASP.Net...but still, I think that by learning other languages that are used in the web environment will broaden my horizons...both as a developer who loves learning, and also Career wise. My point is, am I really using up my time correctly by learning older, lower level stuff? Stuff that for my current line of work, will most probably never use, but still is interesting to know ? To be frankly honest, I am also learning C so that I could, maybe someday, get into Electronics and Micro-controller programming but that is a whole new world for me and, if I choose to go there, will take some time to get adjusted to. And even then, I don't know if I can get a career in working in that line of work. ...but I still wonder about this question over and over...Am I doing the right thing by learning C instead of something (Web-stuff) that will most probably be more useful for me career-wise? I'm sorry for such asking such a long and most probably a boring question, but I feel as if this is the only place where I can ask such a question and get an honest answer from experts in the field. Thank you for your time.

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  • Why do I get a NullPointerException when initializing Spring

    - by niklassaers
    Hi guys, I've got a problem running a batch job on my server, whereas it runs fine from Eclipse on my development workstation. I've got my Spring environment set up using Roo, made an entity, and make a batch that does some work, and test it well on my develompent box. I initialize my context and do the work, but when I run my batch on the server, the context isn't initialized properly. Here's the code: public class TestBatch { private static ApplicationContext context; @SuppressWarnings("unchecked") public static void main(final String[] args) { context = new ClassPathXmlApplicationContext("/META-INF/spring/applicationContext.xml"); try { @SuppressWarnings("unused") TestBatch app = new TestBatch(); } catch (Exception ex) { ex.printStackTrace(); } } public void TestBatch() { /** Do Something using the context **/ } } And here's the log and exception: 2010-02-16 11:54:16,072 [main] INFO org.springframework.context.support.ClassPathXmlApplicationContext - Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@6037fb1e: startup date [Tue Feb 16 11:54:16 CET 2010]; root of context hierarchy Exception in thread "main" java.lang.ExceptionInInitializerError at org.springframework.context.support.AbstractRefreshableApplicationContext.createBeanFactory(AbstractRefreshableApplicationContext.java:194) at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:127) at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:458) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:388) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:139) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:83) at tld.mydomain.myproject.batch.TestBatch.main(TestBatch.java:51) Caused by: java.lang.NullPointerException at org.springframework.beans.factory.support.DefaultListableBeanFactory.<clinit>(DefaultListableBeanFactory.java:103) ... 7 more Any idea or hints as to what's going on? My classpath is set to $PROJECTHOME/target/classes, and all my dependencies are in $PROJECTHOME/target/lib, and I execute using "export CLASSPATH=$PROJECTHOME/target/classes; java -Djava.endorsed.dirs=$PROJECTHOME/target/lib tld.mydomain.myproject.batch.TestBatch" Is there anything in my setup that looks very wrong? When I run this from Eclipse, no problems, but when I deploy it on the server where I want to run it and run it as described above, I get this problem. Because it runs from Eclipse, I believe my config files are all right, but how can I debug what's causing this? Perhaps I have some config errors or a mismatch between the server and the development workstation after all? Or is this a really weird way of saying file not found, and if so, how do I make sure it finds the correct file?? I'm really looking forward to hearing your suggestions as to how to tackle this problem. Cheers Nik

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  • Eclipselink read complex oject model in an ordered way

    - by Raven
    Hi, I need to read a complex model in an ordered way with eclipselink. The order is mandantory because it is a huge database and I want to have an output of a small portion of the database in a jface tableview. Trying to reorder it in the loading/quering thread takes too long and ordering it in the LabelProvider blocks the UI thread too much time, so I thought if Eclipselink could be used that way, that the database will order it, it might give me the performance I need. Unfortunately the object model can not be changed :-( The model is something like: @SuppressWarnings("serial") @Entity public class Thing implements Serializable { @Id @GeneratedValue(strategy = GenerationType.TABLE) private int id; private String name; @OneToMany(cascade=CascadeType.ALL) @PrivateOwned private List<Property> properties = new ArrayList<Property>(); ... // getter and setter following here } public class Property implements Serializable { @Id @GeneratedValue(strategy = GenerationType.TABLE) private int id; @OneToOne private Item item; private String value; ... // getter and setter following here } public class Item implements Serializable { @Id @GeneratedValue(strategy = GenerationType.TABLE) private int id; private String name; .... // getter and setter following here } // Code end In the table view the y-axis is more or less created with the query Query q = em.createQuery("SELECT m FROM Thing m ORDER BY m.name ASC"); using the "name" attribute from the Thing objects as label. In the table view the x-axis is more or less created with the query Query q = em.createQuery("SELECT m FROM Item m ORDER BY m.name ASC"); using the "name" attribute from the Item objects as label. Each cell has the value Things.getProperties().get[x].getValue() Unfortunately the list "properties" is not ordered, so the combination of cell value and x-axis column number (x) is not necessarily correct. Therefore I need to order the list "properties" in the same way as I ordered the labeling of the x-axis. And exactly this is the thing I dont know how it is done. So querying for the Thing objects should return the list "properties" "ORDER BY name ASC" but of the "Item"s objects. My ideas are something like having a query with two JOINs. Joing Things with Property and with Item but somehow I was unable to get it to work yet. Thank you for your help and your ideas to solve this riddle.

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