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  • How do I check for Existence of a Record in GAE

    - by VDev
    I am trying to create a simple view in Django & GAE, which will check if the user has a profile entity and prints a different message for each case. I have the program below, but somehow GAE always seem to return a object. My program is below import datetime from django.http import HttpResponse, HttpResponseRedirect from google.appengine.api import users from google.appengine.ext import db from models import Profile import logging #from accounts.views import profile # Create your views here. def login_view(request): user = users.get_current_user() profile = db.GqlQuery("SELECT * FROM Profile WHERE account = :1", users.get_current_user()) logging.info(profile) logging.info(user) if profile: return HttpResponse("Congratulations Your profile is already created.") else: return HttpResponse("Sorry Your profile is NOT created.") My model object is Profile defined as follows: class Profile(db.Model): first_name = db.StringProperty() last_name = db.StringProperty() gender = db.StringProperty(choices=set(["Male", "Female"])) account = db.UserProperty(required = True) friends = db.ListProperty(item_type=users.User) last_login = db.DateTimeProperty(required=True) Thanks for the help.

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  • rename keys in a dictionary

    - by user366660
    i want to rename the keys of a dictionary are which are ints, and i need them to be ints with leading zeros's so that they sort correctly. for example my keys are like: '1','101','11' and i need them to be: '001','101','011' this is what im doing now, but i know there is a better way tmpDict = {} for oldKey in aDict: tmpDict['%04d'%int(oldKey)] = aDict[oldKey] newDict = tmpDict

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  • How do I make a defaultdict safe for unexpecting clients?

    - by ~miki4242
    Several times (even several in a row) I've been bitten by the defaultdict bug. d = defaultdict(list) ... try: v = d["key"] except KeyError: print "Sorry, no dice!" For those who have been bitten too, the problem is evident: when d has no key 'key', the v = d["key"] magically creates an empty list and assigns it to both d["key"] and v instead of raising an exception. Which can be quite a pain to track down if d comes from some module whose details one doesn't remember very well. I'm looking for a way to take the sting out of this bug. For me, the best solution would be to somehow disable a defaultdict's magic before returning it to the client.

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  • Problems installing a package from PyPI: root files not installed

    - by intuited
    After installing the BitTorrent-bencode package, either via easy_install BitTorrent-bencode or pip install BitTorrent-bencode, or by downloading the tarball and installing that via easy_install $tarball, I discover that /usr/local/lib/python2.6/dist-packages/BitTorrent_bencode-5.0.8-py2.6.egg/ contains EGG-INFO/ and test/ directories. Although both of these subdirectories contain files, there are no files in the BitTorr* directory itself. The tarball does contain bencode.py, which is meant to be the actual source for this package, but it's not installed by either of those utils. I'm pretty new to all of this so I'm not sure if this is a problem with the package or with what I'm doing. The package was packaged a while ago (2007), so perhaps it's using some deprecated configuration aspect that I need to supply a command-line flag for. I'm more interested in learning what's wrong with either the package or my procedures than in getting this particular package installed; there is another package called hunnyb that seems to do a decent enough job of decoding bencoded data. Mostly I'd like to know how to deal with such problems in other packages.

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  • Default subclass objects in Sqlalchemy?

    - by Timmy
    im using the example from the pylons book orm.mapper(Comment, comment_table) orm.mapper(Tag, tag_table) orm.mapper(Nav, nav_table, polymorphic_on=nav_table.c.type, polymorphic_identity='nav') orm.mapper(Section, section_table, inherits=Nav, polymorphic_identity='section') orm.mapper(Page, page_table, inherits=Nav, polymorphic_identity='page', properties={ 'comments':orm.relation(Comment, backref='page', cascade='all'), 'tags':orm.relation(Tag, secondary=pagetag_table) }) i am mostly copying from this, but is there a simple way have a default Page that gets referenced, but if users requests a change, create a new Page object? thanks i want something similar to this class DefaultPage(Page): __init__(self): self.a = a self.b = b self.c = c orm.mapper(DefaultPage, None, inherits=Nav, yada yada )

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  • Django template context not working with imported class

    - by Andy Hume
    I'm using Django's templating on appengine, and am having a problem whereby a class I'm importing from another package is not correctly being made available to the template context. Broadly speaking, this is the code. The prop1 is not available in the template in the first example below, but is in the second. MyClass is identical in both cases. This does not work: from module import MyClass context = MyClass() self.response.out.write(template.render(path, context)) This does: class MyClass(object): def __init__(self): self.prop1 = "prop1" context = MyClass() self.response.out.write(template.render(path, context)) If I log the context in the above code I get: <module.MyClass object at 0x107b1e450> when it's imported, and: <__main__.MyClass object at 0x103759390> when it's defined in the same file. Any clues as to what might cause this kind of behaviour?

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  • numpy arange with multiple intervals

    - by Heiko Westermann
    Hi, i have an numpy array which represents multiple x-intervals of a function: In [137]: x_foo Out[137]: array([211, 212, 213, 214, 215, 216, 217, 218, 940, 941, 942, 943, 944, 945, 946, 947, 948, 949, 950]) as you can see, in x_foo are two intervals: one from 211 to 218, and one from 940 to 950. these are intervals, which i want to interpolate with scipy. for this, i need to adjust the spacing, e.g "211.0 211.1 211.2 ..." which you would normaly do with: arange( x_foo[0], x_foo[-1], 0.1 ) in the case of multiple intervals, this is not possible. so heres my question: is there a numpy-thonic way to do this in array-style? or do i need to write a function which loops over the whole array and split if the difference is 1? thanks!

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  • Partially flattening a list

    - by alj
    This is probably a really silly question but, given the example code at the bottom, how would I get a single list that retain the tuples? (I've looked at the itertools but it flattens everything) What I currently get is: ('id', 20, 'integer') ('companyname', 50, 'text') [('focus', 30, 'text'), ('fiesta', 30, 'text'), ('mondeo', 30, 'text'), ('puma', 30, 'text')] ('contact', 50, 'text') ('email', 50, 'text') what I would like is a single level list like: ('id', 20, 'integer') ('companyname', 50, 'text') ('focus', 30, 'text') ('fiesta', 30, 'text') ('mondeo', 30, 'text') ('puma', 30, 'text') ('contact', 50, 'text') ('email', 50, 'text') def getproducts(): temp_list=[] product_list=['focus','fiesta','mondeo','puma'] #usually this would come from a db for p in product_list: temp_list.append((p,30,'text')) return temp_list def createlist(): column_title_list = ( ("id",20,"integer"), ("companyname",50,"text"), getproducts(), ("contact",50,"text"), ("email",50,"text"), ) return column_title_list for item in createlist(): print item Thanks ALJ

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  • Display values and how many times they occured using a Dictionary

    - by user1730056
    I've been told to By using a dictionary (or your solution to Part 4), write a method at_least(a, n) that takes a list, a, and an integer, n, as arguments and returns a list containing only the elements of a that occur at least n times. For complete marks, the list should contain the elements in order of their first occurrence in a. I was able to figure this without using a dictionary, with def at_least2(a, n): return [x for x in a if a.count(x) is n] I was wondering how I can write this using a dictionary? The input is: a = [-6, 8, 7, 3, 2, -9, 1, -3, 2, -4, 4, -8, 7, 8, 2, -2, -7, 0, 1, -9, -3, -7, -3, -5, 6, -3, 6, -3, -10, -8] def at_least(a, 2): and the output: [8, 7, 2, -9, 1, -3, 2, -8, 7, 8, 2, -7, 1, -9, -3, -7, -3, 6, -3, 6, -3, -8] Edit: I don't understand how a dictionary is being used, yet the output isn't in dictionary form? My understanding is that dictionaries have values for each object. I'm not sure if I'm using the right terms.

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  • Remove all user's cookies/sessions when password is reset

    - by Juraj
    I'm interested in improving security of my TurboGears 2.2 application so that when user changes his password, it logs him out from all sessions and he must login again. When user changes password on browser 1, he must relogin on browser 2, too. Experiments show that this is not the case, especially if browser 2 had "remember me" enabled. It's standard quickstarted app using repoze.who. It seems maybe I need to change AuthTktCookiePlugin, but don't see a way to do it without much rewiring.

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  • how to get selected item in pyqt Qmenu

    - by Moayyad Yaghi
    hello is there any way to get the selected item in a qmenu ? i want to bind all items in that list to one function and get the item once user click it . i've been looking for a way to get the item's label or index for 3 days , but couldn't find it . any ideas ? thanks in advance

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  • HttpResponseRedirect question

    - by Hulk
    Cant we send a dictionary variable when using HttpResponseRedirect render_to_response('edited/display.html',context_instance=RequestContext(request,{'newlist': newlist})) //How can the dictionary and the request sent back again //sumthing like this return HttpResponseRedirect('edited/display.html',context_instance=RequestContext(request,{'newlist': newlist}))

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  • How can I have multiple navigation paths with Django, like a simplifies wizard path and a full path?

    - by Zeta
    Lets say I have an application with a structure such as: System set date set name set something Other set death ray target calibrate and I want to have "back" and "next" buttons on a page. The catch is, if you're going in via the "wizard", I want the nav path to be something like "set name" - "set death ray target" - "set name". If you go via the Advanced options menu, I want to just iterate options... "set date" - "set name" - "set something" - "set death ray target" - calibrate. So far, I'm thinking I have to use different URIs, but that's that. Any ideia how this could be done? Thanks.

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  • Declaring models elsewhere than in "models.py" AND dynamically

    - by sebpiq
    Hi ! I have an application that splits models into different files. Actually the folder looks like : >myapp __init__.py models.py >hooks ... ... myapp don't care about what's in the hooks, folder, except that there are models, and that they have to be declared somehow. So, I put this in myapp.__init__.py : from django.conf import settings for hook in settings.HOOKS : try : __import__(hook) except ImportError as e : print "Got import err !", e #where settings.HOOKS = ("myapp.hooks.a_super_hook1", ...) The problem is that it doesn't work when I run syncdb(and throws some strange "Got import err !"... strange considering that it's related to another module of my program that I don't even import anywhere :/ ) ! So I tried successively : 1) for hook in settings.HOOKS : try : exec ("from %s import *" % hook) - doesn't work either : syncdb doesn't install the models in hooks 2) from myapp.hooks.a_super_hook1 import * - This works 3) exec("from myapp.hooks.a_super_hook1 import *") - This works to So I checked that in the test 1), the statement executed is the same than in tests 2) and 3), and it is exactly the same ... Any idea ???

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  • I need to change a zip code into a series of dots and dashes (a barcode), but I can't figure out how

    - by Maggie
    Here's what I've got so far: def encodeFive(zip): zero = "||:::" one = ":::||" two = "::|:|" three = "::||:" four = ":|::|" five = ":|:|:" six = ":||::" seven = "|:::|" eight = "|::|:" nine = "|:|::" codeList = [zero,one,two,three,four,five,six,seven,eight,nine] allCodes = zero+one+two+three+four+five+six+seven+eight+nine code = "" digits = str(zip) for i in digits: code = code + i return code With this I'll get the original zip code in a string, but none of the numbers are encoded into the barcode. I've figured out how to encode one number, but it wont work the same way with five numbers.

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  • exeuting command in background

    - by tazim
    Hi, Trying to execute shell command in background using pythons commands module >>>import commands >>>output = commands.getstatusoutput("find / > tmp.txt &") sh: Syntax error: ";" unexpected Can anyone explain what is wrong with the syntax ? How should it be executed then ? Tazim.

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  • Design question?

    - by Mohamed
    I am building music app, where user can do several tasks including but not limited to listening song, like song, recommend song to a friend and extra. currently I have this model: class Activity(models.Model): activity = models.TextField() user = models.ForeignKey(User) date = models.DateTimeField(auto_now=True) so far I thought about two solutions. 1. saving a string to database. e.g "you listened song xyz" 2. create a dictionary about the activity and save to the database using pickle or json. e.g. dict_ = {"activity_type":"listening", "song":song_obj} I am leaning to the second implementation, but not quite sure. so what do you think about those two methods? do you know better way to achieve the goal?

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  • Crossed import in django

    - by Kuhtraphalji
    On example, i have 2 apps: alpha and beta in alpha/models.py import of model from beta.models and in beta/models.py import of model from alpha.models manage.py validate says that ImportError: cannot import name ModelName how to solve this problem?

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  • PyQt - How to connect multiple signals to the same widget

    - by Orchainu
    [ ]All1 [ ]All2 [ ]checkbox1A [ ]checkbox1B [ ]checkbox2A [ ]checkbox2B Based on the chart above, a few things need to happen: The All checkboxes only affect the on/off of the column it resides in, and checks on/off all the checkboxes in that column. All checkboxes work in pairs, so if checkbox1A is on/off, checkbox1B needs to be on/off If an All checkbox is checked on, and then the user proceeds to check off one or more checkbox in the column, the All checkbox should be unchecked, but all the checkboxes that are already checked should remain checked. So really this is more like a chain reaction setup. If checkbox All1 is on, then chieckbox1A and 2A will be on, and because they are on, checkbox1B and 2B are also on, but checkbox All2 remains off. I tried hooking up the signals based on this logic, but only the paired logic works 100%. The All checkbox logic only works 50% of the time, and not accurately, and there's no way for me to turn off the All checkbox without turning all already checked checkboxes off. Really really need help ... T-T Sample code: cbPairKeys = cbPairs.keys() for key in cbPairKeys: cbOne = cbPairs[key][0][0] cbTwo = cbPairs[key][1][0] cbOne.stateChanged.connect(self.syncCB) cbTwo.stateChanged.connect(self.syncCB) def syncCB(self): pairKeys = cbPairs.keys() for keys in pairKeys: cbOne = cbPairs[keys][0][0] cbOneAllCB = cbPairs[keys][0][4] cbTwo = cbPairs[keys][1][0] cbTwoAllCB = cbPairs[keys][1][4] if self.sender() == cbOne: if cbOne.isChecked() or cbTwoAllCB.isChecked(): cbTwo.setChecked(True) else: cbTwo.setChecked(False) else: if cbTwo.isChecked() or cbOneAllCB.isChecked(): cbOne.setChecked(True) else: cbOne.setChecked(False) EDIT Thanks to user Avaris's help and patience, I was able to reduce the code down to something much cleaner and works 100% of the time on the 1st and 2nd desired behavior: #Connect checkbox pairs cbPairKeys = cbPairs.keys() for key in cbPairKeys: cbOne = cbPairs[key][0][0] cbTwo = cbPairs[key][1][0] cbOne.toggled.connect(cbTwo.setChecked) cbTwo.toggled.connect(cbOne.setChecked) #Connect allCB and allRO signals cbsKeys = allCBList.keys() for keys in cbsKeys: for checkbox in allCBList[keys]: keys.toggled.connect(checkbox.setChecked) Only need help on turning off the All checkbox when the user selectively turns off the modular checkboxes now

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  • Building a user subscription application

    - by Tristan O'Neil
    Hello, I'm trying to come up with the best way to handle user subscription and management for our magazine website. What I want to happen is a user purchases a subscription and they are granted online access of a certain membership role for a certain amount of time depending on how many years they subscribed for. I would also like the system to be able to send out emails when a subscription is almost up. I've seen some third party projects to help accomplish this but I'd prefer to write this from scratch as I want total control over how it works. Any suggestions would be helpful. The main thing I can't figure out is how to have an expiring membership. You must keep track of when the user signed up and how long until they should expire.

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  • More compact layout

    - by Jesse Aldridge
    In the following code, I'd like to get rid of the margin around the buttons. I'd like to have the buttons stretch all the way to the edge of the frame. How can I do that? import sys from PyQt4.QtGui import * from PyQt4.QtCore import * app = QApplication(sys.argv) window = QWidget() layout = QVBoxLayout() layout.setSpacing(0) window.setLayout(layout) for i in range(2): layout.addWidget(QPushButton()) window.show() app.exec_()

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