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  • Hibernate: update on parent-child relationship causes duplicate children

    - by TimmyJ
    I have a parent child relationship in which the parent has a collection of children (a set to be specific). The child collection is setup with cascade="all-delete-orphan". When I initially save the parent element everything works as expected. However, when I update the parent and save again, all the children are re-saved. This behavior leads me to believe that the parent is losing its reference to the collection of children, and therefore when persisting all the children are re-saved. It seems the only way to fix this is to not use the setter method of this child collection, but unfortunately this setter is called implicitly in my application (Spring MVC is used to bind a multi-select form element to this collection, and the setter is called by spring on the form submission). Overwriting this setter to not lose the reference (ie, do a colleciton.clear() and collection.addAll(newCollection) rather than collection = newCollection) is apparently a hibernate no-no, as is pointed out here: https://forum.hibernate.org/viewtopic.php?t=956859 Does anyone know how to circumvent this problem? I've posted some of my code below. The parent hibernate configuration: <hibernate-mapping package="org.fstrf.masterpk.domain"> <class name="ReportCriteriaBean" table="masterPkReportCriteria"> <id name="id" column="id"> <generator class="org.hibernate.id.IncrementGenerator" /> </id> <set name="treatmentArms" table="masterPkTreatmentArms" sort="org.fstrf.masterpk.domain.RxCodeComparator" lazy="false" cascade="all-delete-orphan" inverse="true"> <key column="runid"/> <one-to-many class="TreatmentArm"/> </set> </class> </hibernate-mapping> The parent object: public class ReportCriteriaBean{ private Integer id; private Set<TreatmentArm> treatmentArms; public Integer getId() { return id; } public void setId(Integer id) { this.id = id; } public Set<TreatmentArm> getTreatmentArms() { return treatmentArms; } public void setTreatmentArms(Set<TreatmentArm> treatmentArms) { this.treatmentArms = treatmentArms; if(this.treatmentArms != null){ for(TreatmentArm treatmentArm : this.treatmentArms){ treatmentArm.setReportCriteriaBean(this); } } } The child hibernate configuration: <hibernate-mapping package="org.fstrf.masterpk.domain"> <class name="TreatmentArm" table="masterPkTreatmentArms"> <id name="id" column="id"> <generator class="org.hibernate.id.IncrementGenerator" /> </id> <many-to-one name="reportCriteriaBean" class="ReportCriteriaBean" column="runId" not-null="true" /> <property name="rxCode" column="rxCode" not-null="true"/> </class> </hibernate-mapping> The child object: public class TreatmentArm { private Integer id; private ReportCriteriaBean reportCriteriaBean; private String rxCode; public Integer getId() { return id; } public void setId(Integer id) { this.id = id; } public ReportCriteriaBean getReportCriteriaBean() { return reportCriteriaBean; } public void setReportCriteriaBean(ReportCriteriaBean reportCriteriaBean) { this.reportCriteriaBean = reportCriteriaBean; } public String getRxCode() { return rxCode; } public void setRxCode(String rxCode) { this.rxCode = rxCode; } }

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  • LINQ to SQL filter combobox output

    - by Brendan
    OK so I've got 2 tables for this instance, Users{UserID, Name}, Company{CompanyID, UserID, Name, Payrate} i also have 2 combo boxes, first one is for Users which Displays Name, and the Value is UserID i need the second combobox to get the Names from the Company table, but only showing Companies that are relevant to the selected user. I cant work out how to get it to go... Any ideas???

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  • How to reduce virtual memory by optimising my PHP code?

    - by iCeR
    My current code (see below) uses 147MB of virtual memory! My provider has allocated 100MB by default and the process is killed once run, causing an internal error. The code is utilising curl multi and must be able to loop with more than 150 iterations whilst still minimizing the virtual memory. The code below is only set at 150 iterations and still causes the internal server error. At 90 iterations the issue does not occur. How can I adjust my code to lower the resource use / virtual memory? Thanks! <?php function udate($format, $utimestamp = null) { if ($utimestamp === null) $utimestamp = microtime(true); $timestamp = floor($utimestamp); $milliseconds = round(($utimestamp - $timestamp) * 1000); return date(preg_replace('`(?<!\\\\)u`', $milliseconds, $format), $timestamp); } $url = 'https://www.testdomain.com/'; $curl_arr = array(); $master = curl_multi_init(); for($i=0; $i<150; $i++) { $curl_arr[$i] = curl_init(); curl_setopt($curl_arr[$i], CURLOPT_URL, $url); curl_setopt($curl_arr[$i], CURLOPT_RETURNTRANSFER, 1); curl_setopt($curl_arr[$i], CURLOPT_SSL_VERIFYHOST, FALSE); curl_setopt($curl_arr[$i], CURLOPT_SSL_VERIFYPEER, FALSE); curl_multi_add_handle($master, $curl_arr[$i]); } do { curl_multi_exec($master,$running); } while($running > 0); for($i=0; $i<150; $i++) { $results = curl_multi_getcontent ($curl_arr[$i]); $results = explode("<br>", $results); echo $results[0]; echo "<br>"; echo $results[1]; echo "<br>"; echo udate('H:i:s:u'); echo "<br><br>"; usleep(100000); } ?> Processor Information Total processors: 8 Processor #1 Vendor GenuineIntel Name Intel(R) Xeon(R) CPU E5405 @ 2.00GHz Speed 1995.120 MHz Cache 6144 KB Processor #2 Vendor GenuineIntel Name Intel(R) Xeon(R) CPU E5405 @ 2.00GHz Speed 1995.120 MHz Cache 6144 KB Processor #3 Vendor GenuineIntel Name Intel(R) Xeon(R) CPU E5405 @ 2.00GHz Speed 1995.120 MHz Cache 6144 KB Processor #4 Vendor GenuineIntel Name Intel(R) Xeon(R) CPU E5405 @ 2.00GHz Speed 1995.120 MHz Cache 6144 KB Processor #5 Vendor GenuineIntel Name Intel(R) Xeon(R) CPU E5405 @ 2.00GHz Speed 1995.120 MHz Cache 6144 KB Processor #6 Vendor GenuineIntel Name Intel(R) Xeon(R) CPU E5405 @ 2.00GHz Speed 1995.120 MHz Cache 6144 KB Processor #7 Vendor GenuineIntel Name Intel(R) Xeon(R) CPU E5405 @ 2.00GHz Speed 1995.120 MHz Cache 6144 KB Processor #8 Vendor GenuineIntel Name Intel(R) Xeon(R) CPU E5405 @ 2.00GHz Speed 1995.120 MHz Cache 6144 KB Memory Information Memory for crash kernel (0x0 to 0x0) notwithin permissible range Memory: 8302344k/9175040k available (2176k kernel code, 80272k reserved, 901k data, 228k init, 7466304k highmem) System Information Linux server3.server.com 2.6.18-194.17.1.el5PAE #1 SMP Wed Sep 29 13:31:51 EDT 2010 i686 i686 i386 GNU/Linux Physical Disks SCSI device sda: 1952448512 512-byte hdwr sectors (999654 MB) sda: Write Protect is off sda: Mode Sense: 03 00 00 08 SCSI device sda: drive cache: write back SCSI device sda: 1952448512 512-byte hdwr sectors (999654 MB) sda: Write Protect is off sda: Mode Sense: 03 00 00 08 SCSI device sda: drive cache: write back sd 0:1:0:0: Attached scsi disk sda sd 4:0:0:0: Attached scsi removable disk sdb sd 0:1:0:0: Attached scsi generic sg4 type 0 sd 4:0:0:0: Attached scsi generic sg7 type 0 Current Memory Usage total used free shared buffers cached Mem: 8306672 7847384 459288 0 487912 6444548 -/+ buffers/cache: 914924 7391748 Swap: 4095992 496 4095496 Total: 12402664 7847880 4554784 Current Disk Usage Filesystem Size Used Avail Use% Mounted on /dev/mapper/VolGroup00-LogVol00 898G 307G 546G 36% / /dev/sda1 99M 19M 76M 20% /boot none 4.0G 0 4.0G 0% /dev/shm /var/tmpMnt 4.0G 1.8G 2.0G 48% /tmp

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  • SQL Server pivots? some way to set column names to values within a row

    - by ccsimpson3
    I am building a system of multiple trackers that are going to use a lot of the same columns so there is a table for the trackers, the tracker columns, then a cross reference for which columns go with which tracker, when a user inserts a tracker row the different column values are stored in multiple rows that share the same record id and store both the value and the name of the particular column. I need to find a way to dynamically change the column name of the value to be the column name that is stored in the same row. i.e. id | value | name ------------------ 23 | red | color 23 | fast | speed needs to look like this. id | color | speed ------------------ 23 | red | fast Any help is greatly appreciated, thank you.

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  • JSP 2.0 SEO friendly links encoding

    - by victor hugo
    Currently I have something like this in my JSP <c:url value="/teams/${contact.id}/${contact.name}" /> The important part of my URL is the ID, I just put the name on it for SEO purposes (just like stackoverflow.com does). I was just wondering if there is a quick and clean way to encode the name (change spaces per +, latin chars removal, etc). I'd like it to be like this: <c:url value="/teams/${contact.id}/${supercool(contact.name)}" /> Is there a function like that out there or should I make my own?

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  • Overriding unique indexed values

    - by Yeti
    This is what I'm doing right now (name is UNIQUE): SELECT * FROM fruits WHERE name='apple'; Check if the query returned any result. If yes, don't do anything. If no, a new value has to be inserted: INSERT INTO fruits (name) VALUES ('apple'); Instead of the above is it ok to insert the value into the table without checking if it already exists? If the name already exists in the table, an error will be thrown and if it doesn't, a new record will be inserted. Right now I am having to insert 500 records in a for loop, which results in 1000 queries. Will it be ok to skip the "already-exists" check?

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  • Write problem - lossing the original data

    - by John
    Every time I write to the text file I will lose the original data, how can I read the file and enter the data in the empty line or the next line which is empty? public void writeToFile() { try { output = new Formatter(myFile); } catch(SecurityException securityException) { System.err.println("Error creating file"); System.exit(1); } catch(FileNotFoundException fileNotFoundException) { System.err.println("Error creating file"); System.exit(1); } Scanner scanner = new Scanner (System.in); String number = ""; String name = ""; System.out.println("Please enter number:"); number = scanner.next(); System.out.println("Please enter name:"); name = scanner.next(); output.format("%s,%s \r\n", number, name); output.close(); }

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  • a query is inserted from PHPMYAdmin but not from PHP

    - by iyad al aqel
    i'm writing a php code to insert form values in a forum values $dbServer = mysql_connect("localhost" , "root", "") ; if(!$dbServer) die ("Unable to connect"); mysql_select_db("kfumWonder"); $name= $_POST['name'] ; $password= md5($_POST['password']); $email= $_POST['email'] ; $major= $_POST['major'] ; $dateOfBirth=$_POST['dateOfBirth'] ; $webSite = $_POST['website']; $joinDate= date("Y m d") ; $query = "INSERT INTO user (name, password, email, major, dob, website, join_date) Values ('$name', '$password', '$email', '$major', '$dateOfBirth', '$webSite' , '$joinDate')" ; //echo $query ; $result = mysql_query($query) ; if (! $result ) echo " no results " ; this works perfectly fine when i took the printed query and run it in PHPMyAdmin but when i run this code nothing happens , any ideas !?

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  • Passing password value through URL

    - by Steven Wright
    OK I see a lot of people asking about passing other values, URLS, random stuff through a URL, but don't find anything about sending a password to a password field. Here is my situation: I have a ton of sites I use on a daily basis with my work and oh about 90% require logins. Obviously remembering 80 bajillion logins for each site is dumb, especially when there are more than one user name I use for each site. So to make life easier, I drew up a nifty JSP app that stores all of my logins in a DB table and creates a user interface for the specific page I want to visit. Each page has a button that sends a username, password into the id parameters of the html inputs. Problem: I can get the usernames and other info to show up just dandy, but when I try and send a password to a password field, it seems that nothing gets received by the page I'm trying to hit. Is there some ninja stuff I need to be doing here or is it just not easily possible? Basically this is what I do now: http://addresshere/support?loginname=steveoooo&loginpass=passwordhere and some of my html looks like this: <form name="userform" method="post" action="index.jsp" > <input type="hidden" name="submit_login" value="y"> <table width="100%"> <tr class="main"> <td width="100" nowrap>Username:</td> <td><input type="text" name="loginname" value="" size="30" maxlength="64"></td> </tr> <tr class="main"> <td>Password: </font></td> <td><input type="password" name="loginpass" value="" size="30" maxlength="64"></td> </tr> <tr class="main"> <td><center><input type="submit" name="submit" value="Login"></center></td> </tr> </table> </form> Any suggestions?

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  • jquery script that used to work is not working with jquery 1.4.2

    - by Zayatzz
    ... and i cant figure out why. The script is following: <script type="text/javascript" src="http://path/to/js/jquery-1.4.2.min.js"></script> <script type="text/javascript"> function openMediaPlayer() { $('#flashMovie').animate({'height':'333px'}); } function closeMediaPlayer() { $('#flashMovie').animate({'height':'80px'}); } jQuery(function($){ $('#videoholder').bind('mouseenter', function(){ openMediaPlayer(); }); $('#videoholder').bind('mouseleave', function(){ closeMediaPlayer(); }); }); </script> <div id="videoholder" style="height:80px;width:412px;"> <object width="412" height="80" type="application/x-shockwave-flash" id="flashMovie" name="flashMovie" style="height: 80px;" data="http://path/to/Player.swf"><param name="menu" value="false"><param name="bgcolor" value="#666666"><param name="allowFullscreen" value="true"><param name="flashvars" value="playlistURL=http://path/to/Player/data/playlist.xml"></object> </div> pure and simple resizing flash object. It worked with older(1.3.2) jquery verision. The animate just does not work. Can anyone tell me what i should change to get it working again? Alan.

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  • Showing div based on filled form field

    - by Fabio
    I have this script where I use a slider to show some elements of a form. So far so good. The way I'm doing it is by having a slider (can't use a multistep form since it uses a plugin not allowing multistep forms, plus some graphic behaviors) and a button that goes to the next slider. So now I need that button (not part of the form) to show only if a certain field is filled. I tried teh following, but it's not working, I assume some error but can't figure what. My code is as follows: $('#clientname').change(function() { var clientVal = $("input").val() == ''; $(".next").hide(); if ($('#clientname').val() != '').show(); else $('.next').hide(); }); and the html as follows: <div class="b40-right"> <h3>The Basics</h3> <div class="label"> Your Name (required)</div> <div class="inputes"> <span class="wpcf7-form-control-wrap your-name"><input id="clientname" type="text" name="your-name" value="" class="wpcf7-form-control wpcf7-text wpcf7-validates-as-required" size="40" /></span> </div> <div class="label">Your Email (required)</div> <div class="inputes"> <span class="wpcf7-form-control-wrap your-email"><input type="text" name="your-email" value="" class="wpcf7-form-control wpcf7-text wpcf7-email wpcf7-validates-as-required wpcf7-validates-as-email" size="40" /></span> </div> <div class="label">Type of Business</div> <div class="inputes"> <span class="wpcf7-form-control-wrap type-of-business"><textarea name="type-of-business" class="wpcf7-form-control wpcf7-textarea" cols="40" rows="10"></textarea></span> </div> </div> <a class="next" href="javascript:stepcarousel.stepBy('mygallery2', 1)"><img id="nextbut1" src="<?php bloginfo('template_directory'); ?>/images/next.png" alt="" /></a> any help on what am I doing wrong? Is there a better approach/solution? (I'm not a programmer as you may figure) Thank you in advance!

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  • cellForRowAtIndexPath not being called, but rowsInSections is and it's delegate is set

    - by Jhorra
    I searched around prior to posting this and made sure I hadn't missed anything obvious, though I have a feeling I am missing something basic. I'm using this as a sidebar navigation view. I tried making them static cells and pre-populating them, but they were blank that way as well. When I do it this way I can see everything gets called except that. I've tried deleting it and re-adding it. #import "acxSideBarController.h" @interface acxSideBarController () @end @implementation acxSideBarController @synthesize sidebarDelegate = _sidebarDelegate; - (id)initWithStyle:(UITableViewStyle)style { self = [super initWithStyle:style]; if (self) { // Custom initialization } return self; } - (void)viewDidLoad { [super viewDidLoad]; if ([self.sidebarDelegate respondsToSelector:@selector(lastSelectedIndexPathForSidebarViewController:)]) { NSIndexPath *indexPath = 0; [self.tableView selectRowAtIndexPath:indexPath animated:NO scrollPosition:UITableViewScrollPositionNone]; } self.tableView.backgroundColor = [UIColor underPageBackgroundColor]; self.tableView.dataSource = self; self.tableView.delegate = self; } - (void)viewDidUnload { [super viewDidUnload]; } - (void)viewWillAppear:(BOOL)animated { [super viewWillAppear:animated]; } - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { return (interfaceOrientation == UIInterfaceOrientationPortrait); } #pragma mark - Table view data source - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { return 3; } - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { if(section == 0) return 2; else if(section == 1) return 1; else return 1; } - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"linkCell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier]; } NSString *name = @""; if(indexPath.section == 1) name = @"Inbox"; else if(indexPath.section == 2) name = @"Logout"; else { if(indexPath.row == 0) name = @"Roster"; else if(indexPath.row == 1) name = @"Environmental Variables"; } cell.textLabel.text = name; cell.textLabel.textColor = [UIColor darkTextColor]; return cell; } - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section { if(section == 0) return @"Students"; else if(section == 1) return @"Communication"; else return @" "; } #pragma mark - Table view delegate - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { if (self.sidebarDelegate) { [self.sidebarDelegate acxSideBarController:self atIndexPath:indexPath]; } } @end If it's helpful here's the header file #import <UIKit/UIKit.h> @protocol acxSideBarControllerDelegate; @interface acxSideBarController : UITableViewController @property (nonatomic, assign) id <acxSideBarControllerDelegate> sidebarDelegate; @end @protocol acxSideBarControllerDelegate <NSObject> - (void)acxSideBarController:(acxSideBarController *)acxSideBarController atIndexPath:(NSIndexPath *)indexPath; @optional - (NSIndexPath *)lastSelectedIndexPathForacxSideBarController:(acxSideBarController *)acxSideBarController; @end

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  • How to test if a user has SELECTED a file to upload ?

    - by Tristan
    Hello, on a page, i have : if (!empty($_FILES['logo']['name'])) { $dossier = 'upload/'; $fichier = basename($_FILES['logo']['name']); $taille_maxi = 100000; $taille = filesize($_FILES['logo']['tmp_name']); $extensions = array('.png', '.jpg', '.jpeg'); $extension = strrchr($_FILES['logo']['name'], '.'); if(!in_array($extension, $extensions)) { $erreur = 'ERROR you must upload the right type'; } if($taille>$taille_maxi) { $erreur = 'too heavy'; } if(!empty($erreur)) { ....................... } The problem is, if the users wants to edit information WITHOUT uploading a LOGO, it raises an error : 'error you must upload the right type' So, if a user didn't put anything in the inputbox in order to upload it, i don't want to enter in these conditions test. i tested : if (!empty($_FILES['logo']['name']) and if (isset($_FILES['logo']['name']) but both doesn't seems to work. Any ideas? edit : maybe i wasn't so clear, i don't want to test if he uploaded a logo, i want to test IF he selected a file to upload, because right now, if he doesn't select a file to upload, php raises an error telling he must upload with the right format. thanks.

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  • Custom keys for Google App Engine models (Python)

    - by Cameron
    First off, I'm relatively new to Google App Engine, so I'm probably doing something silly. Say I've got a model Foo: class Foo(db.Model): name = db.StringProperty() I want to use name as a unique key for every Foo object. How is this done? When I want to get a specific Foo object, I currently query the datastore for all Foo objects with the target unique name, but queries are slow (plus it's a pain to ensure that name is unique when each new Foo is created). There's got to be a better way to do this! Thanks.

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  • Pointers to class fields

    - by newbie_cpp
    My task is as follows : Using pointers to class fields, create menu allowing selection of ice, that Person can buy in Ice shop. Buyer will be charged with waffel and ice costs. Selection of ice and charging buyers account must be shown in program. Here's my Person class : #include <iostream> using namespace std; class Iceshop { const double waffel_price = 1; public: } class Person { static int NUMBER; char* name; int age; const int number; double plus, minus; public: class Account { int number; double resources; public: Account(int number, double resources) : number(number), resources(resources) {} } Person(const char* n, int age) : name(strcpy(new char[strlen(n)+1],n)), number(++NUMBER), plus(0), minus(0), age(age) {} Person::~Person(){ cout << "Destroying resources" << endl; delete [] name; } friend void show(Person &p); int* take_age(){ return &age; } char* take_name(){ return name; } void init(char* n, int a) { name = n; age = a; } Person& remittance(double d) { plus += d; return *this; } Person& paycheck(double d) { minus += d; return *this; } Account* getAccount(); }; int Person:: Person::Account* Person::getAccount() { return new Account(number, plus - minus); } void Person::Account::remittance(double d){ resources = resources + d; } void Person::Account::paycheck(double d){ resources = resources - d; } void show(Person *p){ cout << "Name: " << p->take_name() << "," << "age: " << p->take_age() << endl; } int main(void) { Person *p = new Person; p->init("Mary", 25); show(p); p->remittance(100); system("PAUSE"); return 0; } How to start this task ? Where and in what form should I store menu options ?

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  • How to create factories with attr_accesible?

    - by regedarek
    How to deal with factories and attr_accessible? My example: # model class SomeModel attr_accessible :name, full_name, other_name end #spec require 'spec_helper' describe "test" do it do create(:some_model, name: "test name", user: User.first) #factory end end #error ruby(17122,0x12a055000) malloc: *** error for object 0x8: pointer being freed was not allocated *** set a breakpoint in malloc_error_break to debug I think the error is because user_id is not in attr_accesible atributes

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  • Ternary operator in if-statement?

    - by Pindatjuh
    I've written the following if-statement in Java: if(methodName.equals("set" + this.name) || isBoolean() ? methodName.equals("is" + this.name) : methodName.equals("get" + this.name)) { ... } Is this a good practice to write such expressions in if, to separate state from condition? And can this expression be simplified?

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  • SEO URL building - simple or hierarchy

    - by Pawel
    I run an online shop and I wonder what would be more SEO-friendly URL for a product page: a) domain.com/category-name/product-name OR b) domain.com/product-name I already have URL-s for product category pages with format domain.com/category-name. On one hand I heard (but cannot find proof for) that Google like tree hierarchies in URL (vote for "a"). On the other hand though longer URL could lead to smaller kewyord density, also "product_name" comes as the last URL part so probably the least important (vote for "b"). Maybe both options are equally SEO-effective? PS. I know about canonical URL's but this is not the case, I don't want/need both URL's formats, just want to choose the best.

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  • How do I restrict foreign keys choices to related objects only in django

    - by Jeff Mc
    I have a two way foreign relation similar to the following class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True) class Child(models.Model): name = models.CharField(max_length=255) myparent = models.ForeignKey(Parent) How do I restrict the choices for Parent.favoritechild to only children whose parent is itself? I tried class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True, limit_choices_to = {"myparent": "self"}) but that causes the admin interface to not list any children.

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  • Display Wordpress parent Category with their child category

    - by saorabh
    Hi, I want to display only those the parent category which have some child category with their child category without using child_of= I was trying to display but i am only able to get the list of child category not their parent category name. <?php $querystr = "SELECT wp_terms.name, wp_terms.term_id, wp_terms.name FROM wp_terms, wp_term_taxonomy WHERE wp_terms.term_id = wp_term_taxonomy.term_id AND wp_term_taxonomy.parent !=0 "; $cat_child = $wpdb->get_results($querystr, OBJECT); var_dump($cat_child); foreach ($cat_child as $category) { echo $category->name. ' , '; } ?> Help me.. Thanks

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  • JSF tags not being rendered as HTML

    - by Toto
    I'm following the Java EE firstcup tutorial using Netbeans and Glassfish. When I execute the JSF web tier I've been instructed to code, the browser gets the same JSF markup coded in the .xhtml file, and the tags are not rendered as HTML tags. I know this by using the view source code in my browser. For example, for this code: <html xmlns="http://www.w3.org/1999/xhtml" xmlns:f="http://java.sun.com/jsf/core" xmlns:h="http://java.sun.com/jsf/html"> <h:head> <title>Page title here</title> </h:head> <h:body> <h2> <h:outputText value="#{bundle.WelcomeMessage}" /> </h2> </h:body> </html> The browser should get something like: <html ...> <head> <title>Page title here</title> </head> <body> <h2> the welcome message goes here </h2> </body> </html> Right? Well, my browser is getting jsf code (the first piece of code above) and not the html code (the second piece of code above). It seems to be a configuration problem in netbeans or glassfish but don't know what. Any ideas? This is my web.xml file: <?xml version="1.0" encoding="UTF-8"?> <web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"> <context-param> <param-name>javax.faces.PROJECT_STAGE</param-name> <param-value>Development</param-value> </context-param> <servlet> <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>/firstcup/*</url-pattern> </servlet-mapping> <session-config> <session-timeout> 30 </session-timeout> </session-config> <welcome-file-list> <welcome-file>greetings.xhtml</welcome-file> </welcome-file-list> </web-app> This is my faces-config.xml file: <?xml version='1.0' encoding='UTF-8'?> <!-- =========== FULL CONFIGURATION FILE ================================== --> <faces-config version="2.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-facesconfig_2_0.xsd"> <application> <resource-bundle> <base-name>firstcup.web.WebMessages</base-name> <var>bundle</var> </resource-bundle> <locale-config> <default-locale>en</default-locale> <supported-locale>es</supported-locale> </locale-config> </application> <navigation-rule> <from-view-id>/greetings.xhtml</from-view-id> <navigation-case> <from-outcome>success</from-outcome> <to-view-id>/response.xhtml</to-view-id> </navigation-case> </navigation-rule> </faces-config> Moreover: The url I'm entering in the browser is http://localhost:8081/firstcup/ but I've also tried: http://localhost:8081/firstcup/greetings.xhtml I've checked Glassfish logs and there's no information about not being able to load FacesServlet

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  • FancyBox, Obtaining an ATTR of the item clicked

    - by nobosh
    I have the following lines of code: $("a.quickview").fancybox({ ajax : { type : "POST", data : 'itemID=' + $(this).attr("name") } }); Which is binding on: <a name="614" class="quickview" href="/URL/index.cfm">quick view</a> I want data to post as itemID=614, but $(this).attr("name") is coming back as undefined? What am I doing wrong? Thanks

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  • Working with libpath with java reflection.

    - by C. Ross
    I'm dynamically loading a class and calling a method on it. This class does JNI. When I call the class, java attempts to load the library. This causes an error because the library is not on the libpath. I'm calling from instead a jar so I can't easily change the libpath (especially since the library is not in the same directory or a sub directory of the jar). I do know the path of the library, but how can I load it before I load the class. Current code: public Class<?> loadClass(String name) throws ClassNotFoundException { if(!CLASS_NAME.equals(name)) return super.loadClass(name); try { URL myUrl = new URL(classFileUrl); URLConnection connection = myUrl.openConnection(); InputStream input = connection.getInputStream(); byte[] classData = readConnectionToArray(input); return defineClass(CLASS_NAME, classData, 0, classData.length); } catch (MalformedURLException e) { throw new UndeclaredThrowableException(e); } catch (IOException e) { throw new UndeclaredThrowableException(e); } } Exception: Can't find library libvcommon.so java.lang.UnsatisfiedLinkError: vcommon (A file or directory in the path name does not exist.) at java.lang.ClassLoader.loadLibraryWithPath(ClassLoader.java:998) at java.lang.ClassLoader.loadLibraryWithClassLoader(ClassLoader.java:962) at java.lang.System.loadLibrary(System.java:465) at vcommon.(vcommon.java:103) at java.lang.J9VMInternals.initializeImpl(Native Method) at java.lang.J9VMInternals.initialize(J9VMInternals.java:200) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:37) at java.lang.reflect.Method.invoke(Method.java:599) at com.fortune500.fin.v.vunit.reflection.ReflectionvProcessor.calculateV(ReflectionvProcessor.java:36) at com.fortune500.fin.v.vunit.UTLTestCase.execute(UTLTestCase.java:42) at com.fortune500.fin.v.vunit.TestSuite.execute(TestSuite.java:15) at com.fortune500.fin.v.vunit.batch.Testvendor.execute(Testvendor.java:101) at com.fortune500.fin.v.vunit.batch.Testvendor.main(Testvendor.java:58) Related: Dynamic loading a class in java with a different package name

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  • JPA/Hibernate Parent/Child relationship

    - by NubieJ
    Hi I am quite new to JPA/Hibernate (Java in general) so my question is as follows (note, I have searched far and wide and have not come across an answer to this): I have two entities: Parent and Child (naming changed). Parent contains a list of Children and Children refers back to parent. e.g. @Entity public class Parent { @Id @Basic @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "PARENT_ID", insertable = false, updatable = false) private int id; /* ..... */ @OneToMany(cascade = { CascadeType.ALL }, fetch = FetchType.LAZY) @JoinColumn(name = "PARENT_ID", referencedColumnName = "PARENT_ID", nullable = true) private Set<child> children; /* ..... */ } @Entity public class Child { @Id @Basic @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "CHILD_ID", insertable = false, updatable = false) private int id; /* ..... */ @ManyToOne(cascade = { CascadeType.REFRESH }, fetch = FetchType.EAGER, optional = false) @JoinColumn(name = "PARENT_ID", referencedColumnName = "PARENT_ID") private Parent parent; /* ..... */ } I want to be able to do the following: Retrieve a Parent entity which would contain a list of all its children (List), however, when listing Parent (getting List, it of course should omit the children from the results, therefore setting FetchType.LAZY. Retrieve a Child entity which would contain an instance of the Parent entity. Using the code above (or similar) results in two exceptions: Retrieving Parent: A cycle is detected in the object graph. This will cause infinitely deep XML... Retrieving Child: org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: xxxxxxxxxxx, no session or session was closed When retrieving the Parent entity, I am using a named query (i.e. calling it specifically) @NamedQuery(name = "Parent.findByParentId", query = "SELECT p FROM Parent AS p LEFT JOIN FETCH p.children where p.id = :id") Code to get Parent (i.e. service layer): public Parent findByParentId(int parentId) { Query query = em.createNamedQuery("Parent.findByParentId"); query.setParameter("id", parentId); return (Parent) query.getSingleResult(); } Why am I getting a LazyInitializationException event though the List property on the Parent entity is set as Lazy (when retrieving the Child entity)?

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  • FB Connect going in an infinite loop with google chrome

    - by Mitesh
    Hi, I am having the following php code which i am trying for testing FB Connect <?php define('FACEBOOK_APP_ID', 'YOUR_APP_ID'); define('FACEBOOK_SECRET', 'YOUR_APP_SECRET'); function get_facebook_cookie($app_id, $application_secret) { enter code here $args = array(); parse_str(trim($COOKIE['fbs' . $app_id], '\"'), $args); ksort($args); $payload = ''; foreach ($args as $key = $value) { if ($key != 'sig') { $payload .= $key . '=' . $value; } } if (md5($payload . $application_secret) != $args['sig']) { return null; } return $args; } $cookie = get_facebook_cookie(FACEBOOK_APP_ID, FACEBOOK_SECRET); ? <!DOCTYPE html <html xmlns="http://www.w3.org/1999/xhtml" xmlns:fb="http://www.facebook.com/2008/fbml" <body <?php if ($cookie) { ? Your user ID is <?= $cookie['uid'] ? <br / Your Acess Token is <br / <?php $user = json_decode(file_get_contents( 'https://graph.facebook.com/me?access_token=' . $cookie['access_token'])); if($user) { echo "<br /Display Name = " . $user-name; echo "<br /First Name = " . $user-first_name; echo "<br /Last Name = " . $user-last_name; echo "<br /Birthday = " . $user-birthday; echo "<br /Home Town = " . $user-hometown-name; echo "<br /Location = " . $user-location-name; echo "<br /Email = " . $user-email . "<br /"; } ? <?php } else { ? <fb:login-button perms="email,user_birthday,publish_stream"</fb:login-button <?php } ? <div id="fb-root">&lt;/div> <script src="http://connect.facebook.net/en_US/all.js"></script> <script> FB.init({appId: '<?= FACEBOOK_APP_ID ?>', status: true, cookie: true, xfbml: true}); FB.Event.subscribe('auth.login', function(response) { window.location.reload(); }); </script> </body </html The problem faced by me is it works fine with IE and Firefox, however when done the same with google chrome I am running into an infinite loop when I click on reload/refresh button of chrome after logging in. Any hints as to why is it happening with chrome? Also how can it be avoided. Thanks, Mitesh

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