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  • Passing Info From One View to Another

    - by 01010011
    EDIT 1. The results of a query from my database are displayed on my view page. Next to each unique result is a button: // first_view.php <?php echo form_open('controller/method'); ?> <?php foreach($results_found as $item): ?> <p><?php echo $item->name ?></p> <p><?php form_submit('buy','Buy This'); ?></p> When a user clicks on one of these buttons (lets say button 4), I would like to display the user's choice from the array onto another view. I've tried using this: // first_view.php <?php echo $this->session->set_userdata('choice',$item); ?> immediately before // first_view.php <?php echo form_close(); ?> thinking that the user's final choice would be stored there so I can display it on another view like this: // second_controller.php $c = $this->session->userdata('choice'); // second_view.php echo 'Your Choose: '. $c; However, what actually displays is the last result displayed on first_view.php, not what the user choose. My question is, if the user clicked on button 4, how do I get that particular choice displayed onto another view? END OF EDIT1 ORIGINAL QUESTION My view page (CodeIgniter) displays the contents of an array in the form of several links. If a user clicks on a link, I want the user to be taken to another view page (via a controller) that gives more information concerning that particular link (which is stored in that particular position in the array) My question is, how do I access and display the contents of that particular location within the array on the second view file without getting a "Undefined variable error" on the second view? Here is what I am trying to do in code form // my_controller.php $array_name['variable_name']; $this->load->view('first_view.php'); // first_view.php <?php foreach($variable_name as $vn): ?> <?php echo anchor('controller_name' $vn->info ?> // if user clicks on 3rd link <?php endforeach ?> // I want to beable to access // index 2 of the array in the // second view file so I can // display more info // second_view.php <?php $vn[2]->info ?>

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  • what is means of this problem when sending email through web-application

    - by Richa Media and services
    i have this error when i sending email through our web application " Mailbox unavailable. The server response was: Requested action not taken: mailbox unavailable or not local" this is detail of error System.Net.Mail.SmtpFailedRecipientException was caught Message=Mailbox unavailable. The server response was: Requested action not taken: mailbox unavailable or not local Source=System FailedRecipient=<[email protected]> StackTrace: at System.Net.Mail.SmtpTransport.SendMail(MailAddress sender, MailAddressCollection recipients, String deliveryNotify, SmtpFailedRecipientException& exception) at System.Net.Mail.SmtpClient.Send(MailMessage message) at email.Globals.SendMail(String EmailID, String subject, String message, String senderMail) in C:location InnerException:

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  • Do I need to include the 'this' when using a property name in a closure?

    - by Scott Whitlock
    I'm using a list of Actions to store an undo history for an object. Let's say I have a property of my object called myChildObject and it's being changed, so I want to store the undo action where I would set it back to it's current value: public class Class1 { public Class1() { } private readonly List<Action> m_undoActions = new List<Action>(); private SomeObject myChildObject { get; set; } public void ChangeState(SomeObject newChildObject) { // copies the reference SomeObject existingObject = myChildObject; m_undoActions.Add(() => myChildObject = existingObject); myChildObject = newChildObject; } } Looking at the lambda expression, existingObject is a local variable, so it's using a closure to pass a reference to that variable, but what about the property myChildObject? Do I need to use 'this' to preface it? Do I need to make a copy of the 'this' reference to a local variable first? Thanks for helping me understand this closure stuff.

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  • Can I mix static and shared-object libraries when linking?

    - by SiegeX
    I have a C project that produces ten executables, all of which I would like to be statically linked. The problem I am facing is that one of these executables uses a 3rd-party library of which only the shared-object version is available. If I pass the -static flag to gcc, ld will error saying it can't find the library in question (I presume it's looking for the .a version) and the executable will not be built. Ideally, I would like to be able to tell 'ld' to statically link as much as it can and fail over to the shared object library if a static library cannot be found. In the interium I tried something like gcc -static -lib1 -lib2 -shared -lib3rdparty foo.c -o foo.exe in hopes that 'ld' would statically link in lib1 and lib2 but only have a run-time dependence on lib3rdparty. Unfortunatly, this did not work as I intended; instead the -shared flag overwrote the -static flag and everything was compiled as shared-objects. Is statically linking an all-or-nothing deal, or is there some way I can mix and match?

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  • FIFO implementation

    - by Narek
    While implementing a FIFO I have used the following structure: struct Node { T info_; Node* link_; Node(T info, Node* link=0): info_(info), link_(link) {} }; I think this a well known trick for lots of STL containers (for example for List). Is this a good practice? What it means for compiler when you say that Node has a member with a type of it's pointer? Is this a kind of infinite loop? And finally, if this is a bad practice, how I could implement a better FIFO. EDIT: People, this is all about implemenation. I am enough familiar with STL library, and know a plenty of containers from several libraries. Just I want to discuss with people who can gave a good implementation or a good advice.

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  • Problem with CruiseControl.net configuration

    - by Pawel
    Hi I started using ccnet to build my project. This is quite new issue for me so I have some problems. First thing: Why does ccnet copy directory with my project to another directory (ccnet creates new folder named the same as project name included in ccnet.config file and copies to them directory with my project) Second thing: Dashboard page cannot show reports for recent build (When I click on any item in recent build then I get page: "The page Cannot be found" I suppose that page cannot link files with logs. but I don't know how to link it. I create one publisher: <publishers> <xmllogger logDir="c:\Branches" /> Can anyone help me?

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  • Windows Azure - Microsoft.IdentityModel not found

    - by rjovic
    I installed WIF runtime and SDK on my machine. I added Microsoft.IdentityModel.dll to my azure web application and locally everything is running great. I build simple web application which use Azure AppFabric Access control. I follow azure labs for that and as I told, local everything is great. When I published my web application to Azure, I'm getting following error : Unable to find assembly 'Microsoft.IdentityModel, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35'. I get it after Appfabric Relaying part is going to return url, after sign in on identity provider. The weird thing is that I set Copy Local to TRUE, because that .dll is not part of Azure GAC. I tried to publish it again, but I received same error. I found few same problems on the internet but with no concrete solution. Does anybody here had something similar and probably have a working solution? Thank you in advance

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  • Git. Remote HEAD is ambiguous.

    - by Siegfried
    I checked the relevant thread but still can't solve this problem. When I typed "git remote show origin", I got * remote origin Fetch URL: xxxx Push URL: xxxx HEAD branch (remote HEAD is ambiguous, may be one of the following): development master Remote branches: development tracked master tracked Local branches configured for 'git pull': development merges with remote development master merges with remote master Local ref configured for 'git push': master pushes to master (up to date) I also checked "git show-ref", and I got: 3f8f4292e31cb8fa5938dbdd406b2f357764205b refs/heads/development 3f8f4292e31cb8fa5938dbdd406b2f357764205b refs/heads/master 3f8f4292e31cb8fa5938dbdd406b2f357764205b refs/remotes/origin/development 3f8f4292e31cb8fa5938dbdd406b2f357764205b refs/remotes/origin/master Here is the list of all branches I have by executing "git branch -a" development * master remotes/origin/development remotes/origin/master And this is what is in the .git/config: [core] repositoryformatversion = 0 filemode = false bare = false logallrefupdates = true ignorecase = true hideDotFiles = dotGitOnly autocrlf = false [remote "origin"] fetch = +refs/heads/*:refs/remotes/origin/* url = xxxx push = refs/heads/master:refs/heads/master [branch "master"] remote = origin merge = refs/heads/master [branch "development"] remote = origin merge = refs/heads/development I and it seems that the remote development and master branch share the same node. How to solve this ambiguity problem? Thank you!

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  • Loader for images that are in another page that are gathered with ajax, in jQuery

    - by abdullah kahraman
    Hello. Let's say I have a link in "index.php", when I click on that link, it loads, via ajax, a content from a page "content.php" into a div element in "index.php", that has an id of "#content". That content in "content.php" has large images. I want to display an image loader, say "ajax-loader.gif", instead of those large images, until the images are downloaded by client. ( I know how to have an image loader .gif for the images on "index.php". ) How can I achieve this?

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  • Android webview cookie problem

    - by Tori
    I have a video link in a web view, on the emulator, I hear the audio and no video is displayed. I think this is an emulator issue. I tried on my Nexus One, when I click the link, it opens a new webview and tries to access the server almost immediately reverts back to the webview and does not show the video. Logcat says: WARN/ResponseProcessCookies(486): Cookie rejected: "BasicClientCookie[version=0,name=GX,domain=mail.google.com,path=/proxy/gmail/mail,expiry=Tue Mar 22 19:55:33 EDT 2011]". Illegal domain attribute "mail.google.com". Domain of origin: "android.clients.google.com" How can I fix this?

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  • Question regarding built-in type variable is returned from a function

    - by Chan
    Hello, If a local object is returned in a function call, it has to do at least three steps: 1. Copy constructor is called to hold a copy. 2. Destroy local object. 3. A copy is return. For example: x = y + z If x is an integer object. A copy of y + z should be returned, then a new object is created, then assignment operator of x will take this object as parameter. So my question is: Is the same process used for built-in type such as int, double...? If they're not the same, how's it done? Thanks, Chan

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  • Use a grepped file as an included source in bash

    - by Andrew
    I'm on a shared webhost where I don't have permission to edit the global bash configuration file at /ect/bashrc. Unfortunately there is one line in the global file, mesg y, which puts the terminal in tty mode and makes scp and similar commands unavailable. My local ~./bashrc includes the global file as a source, like so: # Source global definitions if [ -f /etc/bashrc ]; then . /etc/bashrc fi My current workaround uses grep to output the global file, sans offending line, into a local file and use that as a source. # Source global definitions if [ -f /etc/bashrc ]; then grep -v mesg /etc/bashrc > ~/.bash_global . ~/.bash_global fi Is there a way to do include a grepped file like this without the intermediate step of creating an actual file? Something like this? . grep -v mesg /etc/bashrc > ~/.bash_global

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  • Bullets WILL NOT dissapear in firefox

    - by DunlopBurns
    Hoping you can help me with a problem. I cannot get rid of Bullets in Firefox, i don't want any anywhere, hence my list-style-type: none!important being everywhere. It only appears in Firefox as far as i can tell. the HTML.... <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en"> <head> <title>littleprints.nl</title> <meta name="description" content="----" /> <meta name="keywords" content="----" /> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script type="text/javascript" src="js/slimbox2.js"></script> <link rel="stylesheet" href="css/slimbox2.css" type="text/css" media="screen" /> <link rel="stylesheet" href="layout.css"/> <link rel="stylesheet" href="style.css"/> </head> <body> <div id="container"> <div id="inline1"> <div id="mainpic"> <img src="myimages/circle.jpg" width="100%" alt="Circle bracelet"/> </div> <div id="intro"> <p>Hi and welcome to little prints NL. we make this and that all by hand with 100% silver. my name is Donna Burns and i work by commision, ive been studying for 4 years and am currently learning to become a goldsmith.</p> </div> </div> <div id="inline2"> <p>Click for more...</p> <div id="images"> <a href="myimages/photos/dogtag.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/chunky.gif" alt="chunky"/></a> <a href="myimages/photos/hearts.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/hearts.gif" alt="hearts"/></a> <a href="myimages/photos/close.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/close.gif" alt="close"/></a> <a href="myimages/photos/pearl.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/flower.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/frontcircle.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/dogtag.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> </div> </div> </div><!--end container--> <div id="footer"> <div id="footalign"> <div id="social"> <ul> <li> <a href="http://www.facebook.com/littleprints" title="Little Prints"> <img src="myimages/facebook.png" width="50px" height="50px" alt="FB"/> </a> </li> <li> <a href="contact.html" title="contact"> <img src="myimages/at.gif" alt="@"/> </a> </li> </ul> </div> <div id="contact"> <p><br/>To enquire about a charm either phone:<br/> 0787463289<br/> or use one of the methods to the side.</p> </div> </div> </div> </body> </html> the CSS... * {margin: 0; padding: 0; border: 0;} html, body { background-color: #000000;image; text-align: center; font: 16px/1.8 Verdana, Arial, Helvetica, sans-serif; list-style-type: none!important; text-decoration: none;} #container { position: relative; width: 900px; top: 0; min-height: 100%; margin-left: auto; margin-right: auto; padding-top: 20px; background-image: URL(myimages/back2.gif); margin-bottom: 180px; } #footer { background-color: #555555; position: relative; clear: both; bottom: 0; width: 900px; height: auto; margin-left: auto; margin-right: auto; margin-bottom: 20px; padding-bottom: 22px; margin-top: -180px; } #inline1{ display: inline-block; margin-top: 250px; margin-bottom: 20px; } #inline2 { display: inline-block; margin-top: 30px; margin-bottom: 50px; } #mainpic { float: left; width: 68%; margin-left: 20px; } #intro { float: right; width: 20%; margin-left: auto; margin-right: 50px; margin-top: 20px; } #images { margin-bottom: 20px; margin-left: auto; margin-right: auto; } #footalign { display: inline; width:900px; list-style-type: none; } #contact { text-align: center; background-color:#555555; float: middle; list-style-type: none; } #social{ background-color:#555555; float: right; list-style: none; padding:0; padding-right: 5px; text-align:center; list-style-type: none!important; } #social img{ border: none; list-style-type: none!important; margin: 3px; } #social ul{ border: none; list-style-type: none!important; } #social a{ display:inline-block; -webkit-transition:all .5s ease-out; -moz-transition:all .5s ease-out; -ms-transition:all .5s ease-out; -o-transition:all .5s ease-out; transition:all .5s ease-out; list-style-type: none!important; } #social a:hover{ display:inline-block; -webkit-transform:translate(-10px,0px); -moz-transform:translate(0px,-10px); -ms-transform:translate(-10px,0px); -o-transform:translate(-10px,0px); transform:translate(-10px,0px); list-style-type: none!important; } #form { margin-top: 250px; margin-bottom: 50px; } .nav1 {font-family: sans-serif;font-size: 22px;text-shadow: 2px 2px 5px #000000;} a:link {text-decoration:none; color:#000000; padding:3px;} a:visited {text-decoration:none; color:#000000;} a:active {text-decoration:none; color:#555555;} a:hover {text-decoration:none; color:#555555;} .nav2 {font-family: sans-serif;font-size: 22px;text-shadow: 2px 2px 5px #ffffff;} a:link {text-decoration:none; color:#ffffff; padding:3px;} a:visited {text-decoration:none; color:#ffffff;} a:active {text-decoration:none; color:#555555;} a:hover {text-decoration:none; color:#555555;} .p1 { color: #ffffff; } div#images img { max-width: 500px; height: auto; }

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  • Using images and css file for a generated HTML UIWebView

    - by Tom
    Hi! I'm generating an HTML file for an app, and in this HTML file there's a link to a stylesheet and one to an image. Here's what I tried so far: NSMutableString *toReturn = [NSMutableString stringWithCapacity:100]; NSString *cssPath = [[NSBundle mainBundle] pathForResource:@"etapes.css" ofType:nil]; [toReturn appendFormat:@"<html><head><title></title><link href=\"%@\" media=\"all\" rel=\"stylesheet\" type=\"text/css\" /></head><body>", cssPath]; It generates the right full path to the right file, this is okay if I want to access it on my mac, but on the simulator or my iPhone it doesn't point to the right place at all... Do you have any idea of how could I make this? Thanks

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  • How to instantiate JQuery UI widget by string?

    - by limcheekin
    Hi there, Do you know how to instantiate JQuery UI widget by string? Let's illustrate it with some sample code. Given the html link element below: <a id="testLink" href="#">Test Link</a> Normally, we can make it into button using code below: $('#testLink').button(); What if I want to instantiate the button with string, for example: var widget='button'; $('#testLink').[widget](); Of course the code block above is not working (It is just for illustration purpose only), otherwise you will not see this question. Please advice. Thanks, Chee Kin

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  • Ruby on Rails - where to write business logic while processing a request? (newbie)

    - by Genadinik
    I am learning Ruby on Rails. I made a simple link like this: <%= link_to "Alex Link", alexes_path(@alex) %> then I routed it in routes.rb like this: resources :alexes get "home/index" then I am a bit unclear, but I think it goes to this part of the controller: def index #@alexes = Alex.all respond_to do |format| format.html # index.html.erb format.json { render json: @alexes } end end Am I correct that it goes to this part of the controller? Then nothing much happens and it goes to the next page which is index.html.rb under views\alexes So what I am wondering is - if I needed to do some business logic, would I write that in the controller snippet? Where inside the snippet? An example would be nice to take a look. Also, I would like to connect to a MongoDb database. Would I also write that in the middle of the controller? Thanks!

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  • Maintaining Project with Git

    - by gkrdvl
    Hi All, I have 2 project, and actually these 2 project is about 80% same each other, the mainly difference is just about language and business model, one is for larger audience using english language and have a 9$/month business model, another is using local language with freemium business model. Sometime when I want to add new feature/functionality, I want to add it in both of the project, but also sometime I want to add feature especially just for the local project. My question is, how do I maintain these 2 project with git ? Maintain 2 git repository for each project or Maintain single git repository with 2 mainly branch or Any other suggestion ?

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  • how do I put a variable inside an attribute for an href tag

    - by Ido
    Hi I'm new to scripting Trying to change the css acording to a url variable, using jqURL plugin. for some reason this does not work for me: $(function(){ var n= $.jqURL.qs(); alert(n) $("link[rel=stylesheet]").attr({href : 'n + ".css"'}); }); the alert is there for debug, and works well, so it is a matter of how i put the var in the attribute. this, for example, works fine: if(n == 'red') { $("link[rel=stylesheet]").attr({href : "red.css"});} help please

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  • pdf file download

    - by rex
    Once a member signs up a form they can download the pdf file. Currently, the pdf file is link with HTML which means that anyone with the url can download it. What's the best way to encrypt a page so that the user don't see the url to a pdf file. I tried creating a flash file and link the URL from flash using the following: var myPDF = new URLRequest("temp/test.pdf"); navigateToURL(myPDF); but it opens a new window and show's the URL !!! is there a way to make the browse forcefully download the file instead of opening in on a new browser. Thanks, Rex

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  • Can i make products on Paypal site

    - by Mirage
    I offer hosting to only 2 clients for 2 diff products. I don't want to build the site and tell them to pay. Is is possible that on my paypal account i create two products like Product1 - monthly subscription 20 product 2 - monnthly yearly subscription 150 So that i can just send them the link and it automatically gets deducted from their account. One thing more can i send same link to other client as well who has bought the same product. Can i group them in paypal system to see which one has paid and which one does not Thanks

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  • Converting SQL to LINQ to XML

    - by Morano88
    I'm writing the following code to convert SQL to LINQ and then to XML: SqlConnection thisConnection = new SqlConnection(@"Data Source=3BDALLAH-PC;Initial Catalog=XMLC;Integrated Security=True;Pooling=False;"); thisConnection.Open(); XElement eventsGive = new XElement("data", from c in ?????? select new XElement("event", new XAttribute("start", c.start), new XAttribute("end",c.eend), new XAttribute("title",c.title), new XAttribute("Color",c.Color), new XAttribute("link",c.link))); Console.WriteLine(eventsGive); The name of the table is "XMLC" and I want to refer to it. How can I do that? When I put its name directly VS gives an error. Also when I say thisConnection.XMLC it doesn't work.

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  • How can I specify resources in an MVVM view model?

    - by gix
    Suppose I want to show list of objects where each object should have a name and a suitable image (for example MenuItems with Icons, or buttons with text and image). All examples and programs exposed the image in the viewmodel as a path to a PNG file and then bound the Source of an Image to that. But what if I want to use vector images (for example as a DrawingImage in a local ResourceDictionary)? Exposing the DrawingImage from the view model seems bad because I would have to store a reference to the application/window/user control/... (and it is advised to not expose such XAML objects from view models). So a better approach would be to use a string identifier in the view model and then somehow select the appropriate resource. If that identifier is the resource key this snippet looks tempting but does not work: <Image Source="{StaticResource {Binding Icon}}"/> I found two workarounds for that though they did not work for me. The first one was using a normal binding to the icon with a converter that looked up the resource in Application.Current. This does not work if the resource is stored somewhere else I think (and the situation where I initially bumped into this problem had no Application running yet since it was a Window choosing the Application to launch!). The second workaround was using a markup extension derived from StaticResourceExtension that fetched its ResourceKey from the passed binding: <Image Source="{local:BindableStaticResource {Binding Icon}"/> This one looks really neat because it could use local resources, also be used for other things. But when using it I always got an exception ("Resource named {FooIcon} could not be found.", showing the correct XAML file and position of the extension). Even an empty resource extension derived from StaticResourceExtension that just passed the resource key to the base constructor did not work and I cannot explain why. Just using StaticResourceExtension worked just fine. Any ideas how I could fix the second approach, or even better solutions? Edit I noticed that it does work when used directly like this: <Window> <Window.Resources> <DrawingImage x:Key="SomeIcon"/> </Window.Resources> <Image Source="{BindableStaticResource {Binding Icon}}"/> </Window> but fails for example in a DataTemplate. Though a normal StaticResourceExtension works on both occasions so I am puzzled what is going wrong.

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