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  • PHP Upload file enhance security

    - by mandril
    Hey.. my question is how to prevent someone upload a virus or some malicious code with the extension you pretend for example i have a pdf file uploader, anyone can upload a binary with pdf camouflage there are lots of programs to do that.

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  • determine from where the function being called in php

    - by Avinash
    I have one function on my code. say its xyz(). This function is being called from different files of my project. Is there any way than I can get from where the function is being called. I want below infromation: File name from where its called. Line number of that file. if call is from inside the function then that function name. Class name Class method name. I know about use of magic constants like FILE and all that. but i don't want to pass all that in function call. like below: xyz('msg',__FILE__,__CLASS__); is there any way that i have to pass just my error related data only. and it will find the above details from where the function is called. let me know if anything is not clear.

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  • help with converting javascript function to php

    - by Haroldo
    My javascript isnt so great, but i found a brilliant looking function here I'm not sure what to do with this bit: var ranges = [], rstart, rend; full function: function getRanges(array) { var ranges = [], rstart, rend; for (var i = 0; i < array.length; i++) { rstart = array[i]; rend = rstart; while (array[i + 1] - array[i] == 1) { rend = array[i + 1]; // increment the index if the numbers sequential i++; } ranges.push(rstart == rend ? rstart+'' : rstart + '-' + rend); } return ranges; } getRanges([2,3,4,5,10,18,19,20]); // returns ["2-5", "10", "18-20"] getRanges([1,2,3,5,7,9,10,11,12,14 ]); // returns ["1-3", "5", "7", "9-12", "14"] getRanges([1,2,3,4,5,6,7,8,9,10]) // returns ["1-10"]

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  • PHP scope question

    - by Dan
    Hi, I'm trying to look through an array of records (staff members), in this loop, I call a function which returns another array of records (appointments for each staff member). foreach($staffmembers as $staffmember) { $staffmember['appointments'] = get_staffmember_appointments_for_day($staffmember); // print_r($staffmember['appointments'] works fine } This is working OK, however, later on in the script, I need to loop through the records again, this time making use of the appointment arrays, however they are unavailable. foreach ($staffmembers as $staffmember) { //do some other stuff //print_r($staffmember['appointments'] no longer does anything } Normally, I would perform the function from the first loop, within the second, however this loop is already nested within two others, which would cause the same sql query to be run 168 times. Can anyone suggest a workaround? Any advice would be greatly appreciated. Thanks

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  • curl cookie problem in PHP

    - by safaali
    hi as my client needs, I developed a code to login via cURl. login to www.web1.com and store cookies in cookie.txt go to www.web2.com and browse a page using that cookie.txt no problem with www.web2.com so when i want to do this with www.web3.com, the problem appears. the www.web3.com uses session and cookies itself and I have to gather and use them. it means I should have tow series of cookies, first those from www.web1.com , and second those from www.web3.com , then request the www.web3.com/somepage how I can do that?

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  • sort associative array PHP

    - by jim smith
    Here's my array, how do I sort it by saleref? Array ( [xml] => Array ( [sale] => Array ( [0] => Array ( [saleref] => 12345 [saleline] => 1 [product] => producta [date] => 19/ 3/10 [manifest] => 0 [qty] => 1 [nextday] => [order_status] => ) [1] => Array ( [saleref] => 12344 [saleline] => 1 [product] => productb [date] => 18/ 3/10 [manifest] => 11892 [qty] => 1 [nextday] => [order_status] => )

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  • Getting the title of a page in PHP

    - by Francesc
    Hi. When I want to get the title of a remote webiste, I use this script: function get_remotetitle($urlpage) { $file = @fopen(($urlpage),"r"); $text = fread($file,16384); if (preg_match('/<title>(.*?)<\/title>/is',$text,$found)) { $title = $found[1]; } else { $title = 'Title N/A'; } return $title; } But when I parase a webiste title with accents, I get "?". But if I look in PHPMyAdmin, I see the accents correctly. What's happening?

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  • Prevent PHP sesison hijack, are these good ideas?

    - by matthew Rhodes
    I'm doing a simple shopping cart for a small site. I plan to store cart items as well as logged in user_id in session variables. to make things a little more secure, I thought I'd do this: sha1() the user_id before storing it in the session. Also sha1() and store the http_user_agent var with some salt, and check this along with the user_id. I know there is more one can do, but I thought this at least helps quite a bit right? and is easy for me to implement.

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  • PHP: imagepng is creating inordinately large files

    - by Rafael
    I'm using a simple thumbnailing script I wrote and it's pretty standard: $imgbuffer = imagecreatetruecolor($thumbwidth, $thumbheight); switch($type) { case 1: $image = imagecreatefromgif($img); break; case 2: $image = imagecreatefromjpeg($img); break; case 3: $image = imagecreatefrompng($img); break; case 6: $image = imagecreatefrombmp($img); break; case 15: $image = imagecreatefromwbmp($img); break; default: return log_error("Tried to create thumbnail from $img: not a valid image"); } imagecopyresampled($imgbuffer, $image, 0, 0, 0, 0, $thumbwidth, $thumbheight, $width, $height); $output = imagepng($imgbuffer, "$album/thumbs/$imgname.png", 9); 9 is the lowest quality setting, yet from a 400 x 600 JPEG image (at 56kB) I'm getting a thumbnail 27 kB in size (140 x 140). Using imagejpeg (quality of 80) instead of imagepng it's about 4kB. How can this be, especially at the lowest quality setting for imagepng? I tried using imagecopy instead of imagecopyresampled, and imagecreate instead of the true color version. Unfortunately the images come out mangled somehow. Is there any way to get PNG thumbnails of a reasonably small file size (about 4 kB at 140 x 140)? Or do I have to use JPEG?

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  • Partial PHP code refresh

    - by Tom
    Is it possible to refresh only the part of the page? How? the part: if (checkExpiry($member->expires)==true) { print timeLeft($leftts); } else { print "expired"; } I have table which is showing name, email, time until membership ends and I need to refresh 'time until membership ends' every second.

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  • Connecting PHP Server and Android?

    - by user3439988
    I am trying to create a simple test application to transfer data back and forth between my server and Android device. The following are the things I aim for: Ability to upload data and files to the server. To be able to view my files on the server. To be able to download the files from the server to my android device. Ability of the server to send me updates on the files or notifications to my phone. I need a safe and secure way to do these things. I have tried these: HTTPPost requests onto the server and echoing the output accordingly and capturing the HTTPresponse and parsing it. For files I have tried using MultipartEntity, but I think that has been deprecated.

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  • SQL-How to retrieve the correct data using php

    - by Programatt
    I am new to SQL so please excuse my question if it is simple. I have a database with a few tables. 1 is a users table, the others are application tables that contain the users preferences for receiving notifications about that application based on the country they are interested in. What I want to do, is retrieve the e-mail address of all users that have an interest in that country. I am struggling to think about how to do this. I currently have the following query constructed, and the code to populate the values function check($string) { if (isset($_POST[$string])) { $print = implode(', ', $_POST[$string]); //Converts an array into a single string $imanageSQLArr = Array(); if (substr_count($print,'Benelux') > 0) { $imanageSQLArr[0] = "checked"; } else { $imanageSQLArr[0] = "off"; } if (substr_count($print, 'France') > 0) { $imanageSQLArr[1] = "checked"; } else { $imanageSQLArr[1] = "off"; } if (substr_count($print, 'Germany') > 0) { $imanageSQLArr[2] = "checked"; } else { $imanageSQLArr[2] = "off"; } if (substr_count($print, 'Italy') > 0) { $imanageSQLArr[3] = "checked"; } else { $imanageSQLArr[3] = "off"; } if (substr_count($print, 'Netherlands') > 0) { $imanageSQLArr[4] = "checked"; } else { $imanageSQLArr[4] = "off"; } if (substr_count($print, 'Portugal') > 0) { $imanageSQLArr[5] = "checked"; } else { $imanageSQLArr[5] = "off"; } if (substr_count($print, 'Spain') > 0) { $imanageSQLArr[6] = "checked"; } else { $imanageSQLArr[6] = "off"; } if (substr_count($print, 'Sweden') > 0) { $imanageSQLArr[7] = "checked"; } else { $imanageSQLArr[7] = "off"; } if (substr_count($print, 'Switzerland') > 0) { $imanageSQLArr[8] = "checked"; } else { $imanageSQLArr[8] = "off"; } if (substr_count($print, 'UK') > 0) { $imanageSQLArr[9] = "checked"; } else { $imanageSQLArr[9] = "off"; } and the query $tocheck = $db->prepare( "SELECT users.email FROM users,app WHERE users.id=app.userid AND BENELUX=:BENELUX AND FRANCE=:FRANCE AND GERMANY=:GERMANY AND ITALY=:ITALY AND NETHERLANDS=:NETHERLANDS AND PORTUGAL=:PORTUGAL AND SPAIN=:SPAIN AND SWEDEN=:SWEDEN AND SWITZERLAND=:SWITZERLAND AND UK=:UK"); $tocheck->execute($country); $row = $tocheck->fetchAll(); This does retrieve data, but only people who's preferences match EXACTLY what is put (so what they haven't selected is taken into account as much as what they have). Any help would be greatly appreciated.

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  • My IF statement is changing variables in PHP

    - by user1902509
    I am fairly new to the whole programming thing, so forgive me if this is a stupid question. It seems odd that I haven't run into it before. I am trying to make an order form for a cake. You fill out the form, submit it, and it will then display the order in a new window, where you then hit "submit," and upload it to the Database. I have a series of If Statements to check for errors in the form before submitting it. Here is a simplified version of the code. Writing means any writing you want on the cake, Name is your name, and cake is what type of cake you want (the default is "None"). try { $name = trim($params->name); $cake = trim($params->cake); $writing = trim($params->writing); if (strlen($name) < 3){ throw new Exception("Please enter Your name."); } if ($cake = "None") { throw new Exception("Please select a Cake" } if ($cake = "Caramel Apple Pie" or $cake = "Pumpkin Pie" or $cake = "Eggnog Pie" and strlen($writing) > 1) { throw new Exception("We are sorry, but you can't write on any of our specialty pies."); } } catch(Exception $x) { $error = $x->getmessage(); } So what is happening is that when I go and hit submit the first time, the correct cake type comes up, but when you submit it the second time, the error comes up saying that I have "None" selected. All the other values are there and remain the same. I think the problem is that the first "IF" statement (Where it says "If($cake = "None")) is automatically changing $cake to "None" because I have tried commenting just that statement out, and it will then change the cake to be "Caramel Apple Pie," which is in the top of the next IF statement. Anyone know why it is doing this? And how to fix it?

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  • how to convert video from one format to another using php

    - by Meena
    hi i want to include the vedio download option in my webpage. I am using ffmpeg, but it seems to work very slow. Is there is any other way to do this or how to spead up the ffmpeg. i am using this code to get the frames from the vedio. to convert the vedio $call="ffmpeg -i ".$_SESSION['video_to_convert']." -vcodec libvpx -r 30 -b ".$quality." -acodec libvorbis -ab 128000 -ar ".$audio." -ac 2 -s ".$size." ".$converted_vids.$name.".".$type." -y 2> log/".$name.".txt"; $convert = (popen("start /b ".$call, "r")); pclose($convert); to get the frame from the vedio exec("ffmpeg -vframes 1 -ss ".$time_in_seconds." -i $converted_vids video_images.jpg -y 2>); but this code does not generate any error its loading continously.

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  • PHP sql with foreach loop variable problem

    - by anthony
    This is really getting frustrating. I have a text file that I'm reading for a list of part numbers that goes into an array. I'm using the following foreach function to search a database for matching numbers. $file = file('parts_array.txt'); foreach ($file as $newPart) { $sql = "SELECT products_sku FROM products WHERE products_sku='" . $newPart . "'"; $rs = mysql_query($sql); $num_rows = mysql_num_rows($rs); echo $num_rows; echo "<br />"; } The problem is I'm getting 0 rows returned from mysql_num_rows. I can type the sql statement without the variable and it works perfectly. I can even echo out the sql statement from this script, copy and paste the statement from the browser and it works. But, for some reason I'm not getting any records when I'm using the variable. I've used variables in sql statements tons of times, but this really has me stumped.

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  • PHP/json My field names are being truncated to 30 characters. Can I stop this?

    - by Biff MaGriff
    Hi Everyone! Ok so I got this piece of vendor software that they said should be run on an apache php server and MySql database. I didn't have either of those so I put it on a PHP IIS server and I converted the code to work on SQL server. ex. mysql_select_db - mssql_select_db (among other things) So I have the following code in a php file $query = "SELECT * FROM TableName WHERE KEY_FIELD = '".$keyField."';"; $result = mssql_query($query); $arr = array(); while ( $obj = mssql_fetch_object($result) ) { $arr[] = $obj; } echo '{"results":'.json_encode($arr).'}'; and my results look something like this (captured with fiddler 2) {"results":[{"KEY_FIELD":"57", "My30characterlongfieldthatiscu":"GoodValue"}]} "My30characterlongfieldthatiscu" should be "My30characterlongfieldthatiscutoff" Kinda weird, no? The vendor claims that the app works perfectly on their end. I'm thinking this is some sort of IIS PHP limit, is there a way around it or can I expand it? I found this solution http://www.php.net/manual/en/ref.mssql.php#74834 but I don't understand it. Thanks!

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  • frameworks for coding a php library?

    - by ajsie
    there are plenty of frameworks for coding MVC web applications. this time im going to code a library (think of Doctrine or Solr) with a bunch of class files. u just include a bootstrap or a class file and you are ready to use my classes. i have never tried to code a library before and intend to code one for learning purpose so that i can use various design patterns i have learned. are there any great frameworks for this, how i should organize the different class files, where i can put configuration files and so on? tutorials or other information would be great too. thanks

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  • php mysql search

    - by mckenzie
    Hello, My code contain SELECT * FROM newchap WHERE company LIKE '%$company%' OR Category LIKE '%$cat%' It works perfectly however, when the field $company contain empty, it return all result in MYSQL. How to prevent it?

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  • Escaping quotes twice in PHP

    - by Genadinik
    Hello, I have a complicated form where I first have to take some _GET parameters and obviously I have to do a mysql_real_escape_string() on them since I look stuff up in the database with them. Them problem for me is after the initial db lookup. When the user submits a form, I send them along as a _POST request and obviously have to do this mysql_real_escape_string call again just in case someone tries to hack my site with a faked form submission. Then the problem I have is the arguments are escaped twice and my queries begin to look strange like this: select field1 , field2 , from my_table where some_id = \'.$lookup_id.\' ... So the system seems to be adding \' and it is messing me up :) Also, in my other forms I have not seen such behavior. Any ideas on what may be causing this? One weird thing is that I tried to send unescaped parameters to the post, and the same problem happens. That is a clue, but not a sufficient one for me. :( Thanks, Alex

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  • Dividing numbers between rows in MySQL + PHP

    - by André Figueira
    Hi I am working on a kind of raffle system which divides 1 million random numbers into an x amount of tickets, e.g. 1 million random numbers to 10,000 tickets. Each ticket is a row in a database, we then have another table ticket numbers in which i need to give 100 numbers to each ticket they are related by the ticket id. So at the moment this is my code: //Amount of the 1 million tickets divided to the tickets $numbersPerTickets = $_POST['numbersPerTicket']; //The total cost of the property $propertyPrice = $_POST['propertyPrice']; //The total amount of tickets $totalTickets = NUMBER_CIELING / $numbersPerTickets; //The ticket price $ticketPrice = $propertyPrice / $totalTickets; //Generate array with random numbers up to 999,999 $randomTicketNumbers = createTicketNumbers(); //Creation loop counter $ticketCreationCount = 1; //Loop and create each ticket while($ticketCreationCount <= $totalTickets) { //Create a padded ticket number $ticketNumber = str_pad($ticketCreationCount, 6, 0, STR_PAD_LEFT); $query = ' INSERT INTO tickets( propertyID, ticketNumber, price ) VALUES( "'.$propertyID.'", "'.$ticketNumber.'", "'.$ticketPrice.'" ) '; $db->query($query); //Get the ID of the inserted ticket to use to insert the ticket numbers $ticketID = $db->insert_id; $loopBreak = $numbersPerTickets; $addedNumberCount = 1; foreach($randomTicketNumbers as $key => $value) { $query = ' INSERT INTO ticketNumbers( ticketID, number ) VALUES( "'.$ticketID.'", "'.$value.'" ) '; $db->query($query); unset($randomTicketNumbers[$key]); if($addedNumberCount == $loopBreak){ break; }else{ $addedNumberCount++; } } $ticketCreationCount++; } But this isn't working it adds the right amount of tickets, which in the case for testing is 10,000 but then adds far too many ticket numbers, it ends up exceeding the million numbers in the random tickets array, The random tickets array is just a simple 1 tier array with 1 million numbers sorted randomly.

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  • PHP Path issue running backticks/exec()

    - by Lee
    Hey all I'm trying to run a java jar file from the command line and within the the execution it gives a path. Withing this path their are spaces and this is causing the issue. ie $f = `java -jar /OCR/ocr.jar /Folder/Sub Folder/filetoocr.pdf /ocr/output.txt`; echo "<pre>$output</pre>"; If you can see the space in between the Sub Folder name causes the issue. By command line it would be (which works) java -jar /OCR/ocr.jar /Folder/Sub\ Folder/filetoocr.pdf /ocr/output.txt any suggestions how I can resolve this ?? Hope you can advise

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  • PHP use function return value as array

    - by Richard Knop
    Why is it that this works: $cacheMatchesNotPlayed = $cache->load('externalData'); $cacheMatchesNotPlayed = $cacheMatchesNotPlayed['matchesNotPlayed']; But this doesn't work: $cacheMatchesNotPlayed = $cache->load('externalData')['matchesNotPlayed']; Is there some reason for it? The second bit is easier to write.

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