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  • SQLAlchemy: a better way for update with declarative?

    - by hadrien
    I am a SQLAlchemy noob. Let's say I have an user table in declarative mode: class User(Base): __tablename__ = 'user' id = Column(u'id', Integer(), primary_key=True) name = Column(u'name', String(50)) When I know user's id without object loaded into session, I update such user like this: ex = update(User.__table__).where(User.id==123).values(name=u"Bob Marley") Session.execute(ex) I dislike using User.__table__, should I stop worrying with that? Is there a better way to do this? Thanx!

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  • Creating form object for variable kind of form.

    - by Bunny Rabbit
    i want to create a form for users to submit questions in django ..so far the models i have created are class Question(models.Model): statement=models.CharField(max_length=100) class Choice(models.Model): statement=models.CharField(max_length=100) value=models.IntegerField() question=models.ForeignKey(Question) Now i want to write a Form class for creating a above form but the problem is the number of choices are variable,a user can decide how many choices a question must have .How do i do that in django?

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  • Django adminsite customize search_fields query

    - by dArignac
    Howdy! In the django admin you can set the search_fields for the ModelAdmin to be able to search over the properties given there. My model class has a property that is not a real model property, means it is not within the database table. The property relates to another database table that is not tied to the current model through relations. But I want to be able to search over it, so I have to somehow customize the query the admin site creates to do the filtering when the search field was filled - is this possible and if, how? I can query the database table of my custom property and it then returns the ids of the model classes fitting the search. This then, as I said, has to flow into the admin site search query. Thanks!

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  • slicing 2d numpy array

    - by MedicalMath
    I have a 2d numpy array called FilteredOutput that has 2 columns and 10001 rows, though the number of rows is a variable. I am trying to take the 2nd column of FilteredOutput and use it to populate a new 1d numpy array called timeSeriesArray using the following line of code: timeSeriesArray=p.array(FilteredOutput[:,0]) I got this syntax from the following link. But the problem is that I am getting the following error message: TypeError: list indices must be integers, not tuple Can anyone show me the proper syntax for populating the 1d array timeSeriesArray with the contents of the second column of the 2d array FilteredOutput?

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  • Convert object to DateRange

    - by user655832
    I'm querying an underlying PostgreSQL database using Pandas 0.8. Pandas is returning the DataFrame properly but the underlying timestamp column in my database is being returned as a generic "object" type in Pandas. As I would eventually like to seasonal normalization of my data I am curious as to how to convert this generic "object" column to something that is appropriate for analysis. Here is my current code to retrieve the data: # get records from db example import pandas.io.sql as psql import psycopg2 # define query to get all subs created this year QRY = """ select i i, i * random() f, case when random() > 0.5 then true else false end t, (current_date - (i*random())::int)::timestamp with time zone tsz from generate_series(1,1000) as s(i) order by 4 ; """ CONN_STRING = "host='localhost' port=5432 dbname='postgres' user='postgres'" # connect to db conn = psycopg2.connect(CONN_STRING) # get some data set index on relid column df = psql.frame_query(QRY, con=conn) print "Row count retrieved: %i" % (len(df),) Thanks for any help you can render. M

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  • Self Authenticating Links in Django

    - by awolf
    In my web app I would like to be able to email self-authenticating links to users. These links will contain a unique token (uuid). When they click the link the token being present in the query string will be enough to authenticate them and they won't have to enter their username and password. What's the best way to do this?

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  • How do I create a Status Icon / System Tray Icon with custom text and transparent background using P

    - by Raugturi
    Here is the code that I have so far to define the icon: icon_bg = gtk.gdk.pixbuf_new_from_file('gmail.png') w, h = icon_bg.get_width(), icon_bg.get_height() cmap = gtk.gdk.Colormap(gtk.gdk.visual_get_system(), False) drawable = gtk.gdk.Pixmap(None, w, h, 24) drawable.set_colormap = cmap gc = drawable.new_gc() drawable.draw_pixbuf(gc, icon_bg, 0, 0, 0, 0, w, h) drawn_icon = gtk.gdk.Pixbuf(gtk.gdk.COLORSPACE_RGB, False, 8, w, h) drawn_icon.get_from_drawable(drawable, cmap, 0, 0, 0, 0, w, h) icon = gtk.status_icon_new_from_pixbuf(drawn_icon) This works to get the png into the icon, but falls short in two areas. First, transparency is not working. If I use a 22x22 png with transparent background and the image centered, I end up with sections of other active icons showing up inside of mine, like this: http://i237.photobucket.com/albums/ff311/Raugturi/22x22_image_with_transparency.png The icon it choose to steal from is somewhat random. Sometimes it's part of the dropbox icon, others the NetworkManager Applet. If I instead use this code: icon_bg = gtk.gdk.pixbuf_new_from_file('gmail.png') w, h = icon_bg.get_width(), icon_bg.get_height() cmap = gtk.gdk.Colormap(gtk.gdk.visual_get_system(), False) drawable = gtk.gdk.Pixmap(None, w, h, 24) drawable.set_colormap = cmap gc = drawable.new_gc() drawable.draw_pixbuf(gc, icon_bg, 0, 0, 0, 0, w, h) drawn_icon = gtk.gdk.Pixbuf(gtk.gdk.COLORSPACE_RGB, False, 8, 22, 22) drawn_icon.get_from_drawable(drawable, cmap, 0, 0, 3, 6, w, h) icon = gtk.status_icon_new_from_pixbuf(drawn_icon) And an image that is only 16x11 with the transparent edges removed, what I end up with is this: Same URL but file is 16x11_image_positioned_in_middle.png So how do I end up with a transparent block like the 1st one that doesn't pull in stuff from other icons? As for the second problem, I need the ability to write on the image before converting it to the icon. I tried using draw_glyphs and it told me I should be using Pango layout/context instead. Unfortunately all the Pango tutorials I could find deal with actual windows, not the status icon. Is there a good tutorial out there for Pango that would apply to this issue (and also maybe have at least some explanation of how to tell it what font to use as all of them that I found seem to lack this and it won't write anything without it). Note: Sorry for the lack of actual images and only one working link, apparently this is a spam prevention feature due to my lack of reputation.

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  • Trying and expand the contrib.auth.user model and add a "relatipnships" manage

    - by dotty
    I have the following model setup. from django.db import models from django.contrib.auth.models import User class SomeManager(models.Manager): def friends(self): # return friends bla bla bla class Relationship(models.Model): """(Relationship description)""" from_user = models.ForeignKey(User, related_name='from_user') to_user = models.ForeignKey(User, related_name='to_user') has_requested_friendship = models.BooleanField(default=True) is_friend = models.BooleanField(default=False) objects = SomeManager() relationships = models.ManyToManyField(User, through=Relationship, symmetrical=False) relationships.contribute_to_class(User, 'relationships') Here i take the User object and use contribute_to_class to add 'relationships' to the User object. The relationship show up, but if call User.relationships.friends it should run the friends() method, but its failing. Any ideas how i would do this? Thanks

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  • Removing a node from a linked list

    - by lost_with_coding
    I would like to create a delete_node function that deletes the node at the location in the list as a count from the first node. So far this is the code I have: class node: def __init__(self): self.data = None # contains the data self.next = None # contains the reference to the next node class linked_list: def __init__(self): self.cur_node = None def add_node(self, data): new_node = node() # create a new node new_node.data = data new_node.next = self.cur_node # link the new node to the 'previous' node. self.cur_node = new_node # set the current node to the new one. def list_print(self): node = ll.cur_node while node: print node.data node = node.next def delete_node(self,location): node = ll.cur_node count = 0 while count != location: node = node.next count+=1 delete node ll = linked_list() ll.add_node(1) ll.add_node(2) ll.add_node(3) ll.list_print()

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  • django link format words joined with hypens

    - by soField
    href="http://www.torontolife.com/daily/daily-dish/restauranto/2010/03/10/best-new-restaurants-2010-james-chatto-names-five-honourable-mentions/"Best new restaurants 2010: honourable mentions is django has built in mechanism to format links above i mean words joined with hypens how can achieve this ?

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  • Right way to return proxy model instance from a base model instance in Django ?

    - by sotangochips
    Say I have models: class Animal(models.Model): type = models.CharField(max_length=255) class Dog(Animal): def make_sound(self): print "Woof!" class Meta: proxy = True class Cat(Animal): def make_sound(self): print "Meow!" class Meta: proxy = True Let's say I want to do: animals = Animal.objects.all() for animal in animals: animal.make_sound() I want to get back a series of Woofs and Meows. Clearly, I could just define a make_sound in the original model that forks based on animal_type, but then every time I add a new animal type (imagine they're in different apps), I'd have to go in and edit that make_sound function. I'd rather just define proxy models and have them define the behavior themselves. From what I can tell, there's no way of returning mixed Cat or Dog instances, but I figured maybe I could define a "get_proxy_model" method on the main class that returns a cat or a dog model. Surely you could do this, and pass something like the primary key and then just do Cat.objects.get(pk = passed_in_primary_key). But that'd mean doing an extra query for data you already have which seems redundant. Is there any way to turn an animal into a cat or a dog instance in an efficient way? What's the right way to do what I want to achieve?

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  • Django: Update order attribute for objects in a queryset

    - by lazerscience
    I'm having a attribute on my model to allow the user to order the objects. I have to update the element's order depending on a list, that contains the object's ids in the new order; right now I'm iterating over the whole queryset and set one objects after the other. What would be the easiest/fastest way to do the same with the whole queryset? def update_ordering(model, order): """ order is in the form [id,id,id,id] for example: [8,4,5,1,3] """ id_to_order = dict((order[i], i) for i in range(len(order))) for x in model.objects.all(): x.order = id_to_order[x.id] x.save()

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  • List all form related errors in django

    - by Mridang Agarwalla
    Hi, Is there a direct way of listing out 'all' form errors in Django templates. I'd like to list out both field and non-field errors and any other form errors. I've found out how to do this on a per-field basis but as said earlier, I'd like to list out everything. The method I'm using doesn't seem to list out everything. {% for error in form.errors %} {{ error|escape }} {% endfor %} Thanks.

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  • How do I create a Django ModelForm, so that it's fields are sometimes required, sometimes not?

    - by Graf
    Ok, here is the question. Imagine I have a ModelForm which have only two fields. like this one: class ColorForm(forms.Form): color_by_name = forms.CharField() color = forms.IntegerField(widget = forms.Select(choices=COLOR_CHOICES)) So a user can either input a color name, a choose it from a list. Color is required, but that doesn't mean, that user should enter it manually. There do I put validation, so that my code checks if user selected color in dropdownlist and if not then he should write it manually?

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  • Simple numpy question

    - by dassouki
    I can't get this snippet to work: #base code A = array([ [ 1, 2, 10 ], [ 1, 3, 20 ], [ 1, 4, 30 ], [ 2, 1, 15 ], [ 2, 3, 25 ], [ 2, 4, 35 ], [ 3, 1, 17 ], [ 3, 2, 27 ], [ 3, 4, 37 ], [ 4, 1, 13 ], [ 4, 2, 23 ], [ 4, 3, 33 ] ]) # Number of zones zones = unique1d(A[:,0]) for origin in zones: for destination in zones: if origin != destination: A_ik = A[(A[:,0] == origin & A[:,1] == destination), 2]

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  • The truth value of an array with more than one element is ambigous when trying to index an array

    - by user1440194
    I am trying to put all elements of rbs into a new array if the elements in var(another numpy array) is =0 and <=.1 . However when I try the following code I get this error: ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all() rbs = [ish[4] for ish in realbooks] for book in realbooks: var -= float(str(book[0]).replace(":", "")) bidsred = rbs[(var <= .1) and (var >=0)] any ideas on what I'm doing wrong?

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  • How to retrieve view of MultiIndex DataFrame

    - by Henry S. Harrison
    This question was inspired by this question. I had the same problem, updating a MultiIndex DataFrame by selection. The drop_level=False solution in Pandas 0.13 will allow me to achieve the same result, but I am still wondering why I cannot get a view from the MultiIndex DataFrame. In other words, why does this not work?: >>> sat = d.xs('sat', level='day', copy=False) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python27\lib\site-packages\pandas\core\frame.py", line 2248, in xs raise ValueError('Cannot retrieve view (copy=False)') ValueError: Cannot retrieve view (copy=False) Of course it could be only because it is not implemented, but is there a reason? Is it somehow ambiguous or impossible to implement? Returning a view is more intuitive to me than returning a copy then later updating the original. I looked through the source and it seems this situation is checked explicitly to raise an error. Alternatively, is it possible to get the same sort of view from any of the other indexing methods? I've experimented but have not been successful. [edit] Some potential implementations are discussed here. I guess with the last question above I'm wondering what the current best solution is to index into arbitrary multiindex slices and cross-sections.

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  • Can pydoc/help hide the documentation for inherited class methods and attributes?

    - by EOL
    When declaring a class that inherits from a specific class: class C(dict): added_attribute = 0 the documentation for C lists all the methods of dict (either through help(C) or pydoc). Is there a way to hide the inherited methods from the automatically generated documentation (the documentation string can refer to the base class, for non-overwritten methods)? This would be useful: pydoc lists the functions defined in a module after its classes. Thus, when the classes have a very long documentation, a lot of less than useful information is printed before the new functions provided by the module are presented, which makes the documentation harder to exploit (you have to skip all the documentation for the inherited methods until you reach something specific to the module being documented).

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  • split twice in the same expression?

    - by UcanDoIt
    Imagine I have the following: inFile = "/adda/adas/sdas/hello.txt" # that instruction give me hello.txt Name = inFile.name.split("/") [-1] # that one give me the name I want - just hello Name1 = Name.split(".") [0] Is there any chance to simplify that doing the same job in just one expression?

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  • Histogram in Matplotlib with input file

    - by Arkapravo
    I wish to make a Histogram in Matplotlib from an input file containing the raw data (.txt). I am facing issues in referring to the input file. I guess it should be a rather small program. Any Matplotlib gurus, any help ? I am not asking for the code, some inputs should put me on the right way !

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