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  • Python: How to use code.InteractiveConsole?

    - by Rosarch
    I'm trying to use InteractiveConsole to create a new front-end for a Python interpreter. These code fragments are from me playing around with InteractiveConsole in IDLE: >>> ses = code.InteractiveConsole() >>> ses.runsource("def foo():") True >>> ses.runsource(" return 2") File "<input>", line 1 SyntaxError: 'return' outside function (<input>, line 1) False Why does it raise a syntax error? How else can I finish writing the function? Also, for something like this: >>> ses.runsource("x = 1") False >>> ses.runsource("x") 1 False How can I capture the 1 value from above? False is the return value, but 1 is written to some stream.

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  • When SET SCAN ON used after END throws error

    - by Karthik
    Hi, Im trying to use SET SCAN ON after as follows.. SET SCAN OFF; DECLARE -- declared a variable BEGIN --update statement END; SET SCAN ON; The use of SET SCAN ON; is causing the error when i try to run the script. The error captured ORA-06550: line 16, column 1: PLS-00103: Encountered the symbol "SET" 06550. 00000 - "line %s, column %s:\n%s" *Cause: Usually a PL/SQL compilation error. *Action:

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  • Only strip commas surrounded by numbers in a string

    - by overlook77
    I am using StreamReader to read each line of a CSV file into a string. As I am processing each line, I need to strip out any commas that ONLY are surrounded by other numbers. For example, if the string was: "textfield1", "textfield2", "100.00", "1,070.00" I would need to only take the comma out of "1,070.00" from this entire string, resulting in: "textfield1", "textfield2", "100.00", "1070.00" Each string read from the CSV file can differ in number of fields, length, etc., so I need to use something (Regular Expressions maybe?) that looks at the entire string without hardcoding a location or blanket removal of all commas. Here is the approach I have been trying: StreamReader sr = new StreamReader(strInputFile); string nextLine = sr.ReadLine(); try { while ((nextLine = sr.ReadLine()) != null) { string rawtext = nextLine.Replace("[0-9]"+","+"[0-9]" , "[0-9]"+"[0-9]"); // ....rest of code } } This obviously doesn't work because I don't understand how to do this :) I am new at C# and inexperienced in Regex, so hopefully this is relatively simple.

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  • MySqlConnection really not close

    - by stighy
    Hi guys, i've a huge problem. Take a look to this sample code private sub FUNCTION1() dim conn as new mysqlconnection(myconnstring) conn.open ---- do something FUNCTION2() ---- conn.close end sub private sub FUNCTION2() dim conn as new mysqlconnection(myconnstring) .... conn.open -- do something conn.close end sub Despite i close regulary all my connection, they remains "open" on the mysql server. I know this because i'm using MySQL Administration tool to check how many connection i open "line by line" of my source code. In fact i get a lot of time "user has exceeded the 'max_user_connections' resource (current value: 5)" My hoster permit ONLY 5 connection, but i think that if i write GOOD source code, this cannot be a problem. So my question is: why that "damn" connections remain open ?? Thank you in advance!

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  • MVC 3 Razor PopUp Window

    - by Vipul
    I need to open a new pop up window on click of a button in a view. The new window should be redirect to a specific actionmethod in a specific controller. I also need to provide attributes for size of the new pop up window. I have been trying the following code: <input type="button" name = "ClickMe" Value="ClickMe" onclick= "javascript:window.open('/Home/Create/','Customer Search',height='window.screen.height - 100', width='200',left='window.screen.width - 250' ,top='10',status='no',toobar='no',resizable='yes',scrollbars='yes')"/> On click of button, nothing happens. I get following Javascript error: Line: 19 Char: 1 Error: Invalid argument. Code: 0 When I check the ViewSource of the HTML rendered, I find the line to be the one which is rendering the button. I am using Windows Vista with IE 7. I am working on MVC 3 with Razor Engine in VS 2010

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  • GitHub: searching through older versions of files

    - by normski
    I know that using GitHub I can search through all the current versions of my files in a repo. However, I would also like to search through the older versions of my repo files. For example, say, I used to have a function called get_info() in my code, but deleted it several versions ago, is it possible to search for get_info and find the code. If it is not possible using GitHub, is it possible from the git command line? EDIT Thanks to @Mark Longair for showing how this can be done from the git command line. If it's not possible in GitHub it would be a great feature to have.

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  • Python change the working directory for an exe opened with startfile

    - by Saulpila
    In python i'm using the os.startfile command to start a windows executable that does especific stuff in its own folder, the python code is running from another folder, so when I start the file, it starts in the python script's working directory, but it has to start in its own directory. I've tried to use os.chdir(path) to change the working directory, but it fails, the file still not runs in it's own folder. I thought maybe there is a command like shortcut's "Start in" line. I've searched everywere, but not success. The only solution comes to my mind is to create a shortcut and add the "start in" line, then launch the shortcut, but that is very impractical.

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  • Connecting to the database in a Created Library - CodeIgniter

    - by Brogrammer
    I have a little issue right now and its bugging me, hopefully one of you guys will be able to help me out. Basically I'm creating a library to use in CodeIgniter and I'm getting this error: A PHP Error was encountered Severity: Notice Message: Undefined property: Functions::$db Filename: libraries/Functions.php Line Number: 11 The Database library is already on autoload aswell as my functions library: $autoload['libraries'] = array('database','session','encrypt','functions'); The Functions.php file is located in the application/libraries folder accordingly. Line number 11 consists of this: $this->db->where('username', $data); Not sure as to why the db is an undefined property?

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  • Error when creating database in MySQL using Netbeans 6.8

    - by nix
    I am trying to create a database using MySQL statements in NetBeans 6.8. However, I keep getting Error code 1064. I don't know what the problem is really since the same statements work in NetBeans 6.0. Here is the error: Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '; /*!40000 ALTER TABLE students ENABLE KEYS */; -- -- Definition of table `w' at line 1016 Line 46, column 1

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  • Saving substrings using Regular Expressions

    - by user362971
    I'm new to regular expressions in Java (or any language, for that matter) and I'm wanting to do a find using them. The tricky part that I don't understand how to do is replace something inside the string that matches. For example, if the line I'm looking for is Person item6 [can {item thing [wrap]}] I'm able to write a regex that finds that line, but finding what the word "thing" is (as it may differ among different lines) is my problem. I may want to either replace that word with something else or save it in a variable for later. Is there any easy way to do this using Java's regex engine?

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  • Add button to a layout programmatically

    - by mmmbaileys
    I'm having trouble adding a button to a layout that I've created in XML. Here's what I want to achieve: //some class else { startActivity(new Intent(StatisticsScreen.this, ScreenTemperature.class)); } //// //ScreenTemperatureClass @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //this is where I call another class that //displays a nice graph setContentView(new GraphTemperature(getApplicationContext())); } I want to add a Button to this new screen so that it'll appear below the graph. I've tried creating a LinearLayout view, then create a Button and add it to this view but I just get NullPointerExceptions.. Any help would be appreciated. Thanks EDIT#1 Here's what I've tried using that created a NullPointerException and 'force close': Button buybutton; LinearLayout layout; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(new GraphTemperature(getApplicationContext())); layout = (LinearLayout) findViewById(R.id.statsviewlayout); Button buyButton = new Button(this); buyButton.setText(R.string.button_back); buyButton.setLayoutParams(new LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); layout.addView(buyButton); } And here's the logcat error: ERROR/AndroidRuntime(293): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.weatherapp/com.weatherapp.ScreenTemperature}: java.lang.NullPointerException ERROR/AndroidRuntime(293): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2663) ERROR/AndroidRuntime(293): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2679) ERROR/AndroidRuntime(293): at android.app.ActivityThread.access$2300(ActivityThread.java:125) ERROR/AndroidRuntime(293): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:2033) theres abviously more lines to do with this error in logcat, not sure if you want it? EDIT#2 So i tried bhups method: @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); GraphTemperature GT = new GraphTemperature(getApplicationContext()); layout = (LinearLayout) findViewById(R.id.statsviewlayout); Button buyButton = new Button(this); buyButton.setText(R.string.button_back); buyButton.setLayoutParams(new LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); layout.addView(GT); // line 27 layout.addView(buyButton); setContentView(layout); } This method produced the same logcat error as above, NullPointerException, indicating it was something to do with line no. 27 which is the layout.addView line of code. Any ideas? Thanks again

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  • Java PreparedStatement Throws MySQLSyntaxErrorException

    - by sqlBugs
    I have the following Java code: String query = "Select 1 from myTable where name = ? and age = ?"; PreparedStatement stmt = conn.prepareStatement(query); stmt.setString(1, name); stmt.setInt(2, age); ResultSet rs = stmt.executeQuery(); Whenever I run the above code, it throws an exception on line 2 (where the PreparedStatement is declared): Error 0221202: SQLException = com.mysql.jdbc.exceptions.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? AND age = ?' at line 1 Does anyone have any suggestions about what I am doing wrong? Thanks!

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  • Error : The Type Initializer of Daemon.Global threw an exception in c#

    - by srk
    I am using the below class file, where some variables are declared to use in the entire application. Now I used that variable BlockLogOut in another class file to make the value true. I just put this below line and getting error in it.. TypeInitializationException Global.BlockLogOut = True; The weird thing is, it was working fine for many months and i am getting this error now on the above line. Of course i was modifying some other stuffs in the application, but surely not this class file. What would have been the problem? namespace Daemon { class Global { public static bool BlockLogOut = false; } }

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  • Why are some strings displayed as garbage when I scroll my read-only multiline Win32 edit control ve

    - by sharptooth
    In my native C+ Win32 GUI application I have a property sheet with two property pages. One of the property pages contains an edit box: EDITTEXT IDC_EDIT_ID,x,y,width,height,ES_MULTILINE | ES_READONLY | NOT WS_BORDER | WS_VSCROLL | WS_HSCROLL | NOT WS_TABSTOP,WS_EX_STATICEDGE I set a multiline text to this edit box. The text has more lines than the edit can fit, so some of the text is clipped and a vertical scroll bar appears. When I scroll up with the mouse the lines that come "from under clip area" are drawn as garbage - it looks like first one line is drawn, then some other line is drawn on the same place without first painting the background. The lines that just move up - ones that were visible before scrolling and remain visible after scrolling are displayed allright. What's the reason and workaround for this behavior?

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  • Windows XP batch file concat

    - by dls
    I'm trying to accomplish the following ridiculous task: I have a text file containing a set of fully qualified filesnames. I want to iterate through the file and append each line to a common variable, that can be passed to a command line tool. For example, the file might be: C:\dir\test.txt C:\WINDOWS\test2.txt C:\text3.txt and I'd like to assign them to some variable 'a' such that: a = "C:\dir\test.txt C:\WINDOWS\test2.txt C:\text2.txt" A secondary question is - what is a good batch file reference? I'm finding some stuff in the Windows material, and a lot of home-grown websites, but nothing particularly complete. Thanks!

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  • string having '<br/>' throws unterminated string literal js error.

    - by kranthi
    Hi All, I am fetching some data from Db and displaying it in a textarea using jquery in the following way. $('#textareatest').val('<% =teststring %>').It is possible that the string 'teststring' can contain XHTML line breaks(<br/>).whenever the string contains <br/> I am getting the 'unterminated string literal' error.I saw a number of posts considering '\n' as line breaks and suggesting to escape it.I tried to escape the <br/> similarly,but it didn't work. Could someone please help me with this? UPDATE:: I've already escaped single quotes. here is an example string test string<br /> Thanks.

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  • Permission error while trying to access an (server) program started by a Java program.

    - by Zardoz
    I am starting a server application (normally to be started from the Unix command line) by using Runtime.getRuntime().exec("path/mmserver"). My problem is now that as long as my Java program, which started that server runs, the server is correctly accessible (from command line and other programs). But when my Java program exits the sever is not accessible anymore (the process of the server is still running). I just get such a error message when trying to access the server: "Error: permission_error(flush_output(user_output),write,stream,user_output,errno(32))". The server is a blackbox for me. I am just looking for other ways to start a new process. And maybe someone has a hint why I get that permission error (even if one doesn't know what that server exactly is ... you rather won't know it).

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  • Sleeping a thread blocking stdin

    - by Sid
    Hey, I'm running a function which evaluates commands passed in using stdin and another function which runs a bunch of jobs. I need to make the latter function sleep at regular intervals but that seems to be blocking the stdin. Any advice on how to resolve this would be appreciated. The source code for the functions is def runJobs(comps, jobQueue, numRunning, limit, lock): while len(jobQueue) >= 0: print(len(jobQueue)); if len(jobQueue) > 0: comp, tasks = find_computer(comps, 0); #do something time.sleep(5); def manageStdin(): print "Global Stdin Begins Now" for line in fileinput.input(): try: print(eval(line)); except Exception, e: print e; --Thanks

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  • multiline column in data grid view. using c#

    - by syedsaleemss
    Im using c# .net windows form application. i have a datagrid view. It has two columns.I need to make all the cells on the second column as to have multiple line. i.e a multiline column. I will edit something in a cell and press enter key. the cursor should reach the next line in the same cell. It should not go to the next cell. What should i do?

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  • I can I separate multiple logical pages in a text file I create in Perl?

    - by Micah
    So far, I've been successful with generating output to individual files by opening a file for output as part of outer loop and closing it after all output is written. I had used a counting variable ($x) and appended .txt onto it to create a filename, and had written it to the same directory as my perl script. I want to step the code up a bit, prompt for a file name from the user, open that file once and only once, and write my output one "printed letter" per page. Is this possible in plain text? From what I understand, chr(12) is an ascii line feed character and will get me close to what I want, but is there a better way? Thanks in advance, guys. :) sub PersonalizeLetters{ print "\n\n Beginning finalization of letters..."; print "\n\n I need a filename to save these letters to."; print "\n Filename > "; $OutFileName = <stdin>; chomp ($OutFileName); open(OutFile, ">$OutFileName"); for ($x=0; $x<$NumRecords; $x++){ $xIndex = (6 * $x); $clTitle = @ClientAoA[$xIndex]; $clName = @ClientAoA[$xIndex+1]; #I use this 6x multiplier because my records have 6 elements. #For this routine I'm only interested in name and title. #Reset OutLetter array #Midletter has other merged fields that aren't specific to who's receiving the letter. @OutLetter = @MiddleLetter; for ($y=0; $y<=$ifLength; $y++){ #Step through line by line and insert the name. $WorkLine = @OutLetter[$y]; $WorkLine =~ s/\[ClientTitle\]/$clTitle/; $WorkLine =~ s/\[ClientName\]/$clName/; @OutLetter[$y] = $WorkLine; } print OutFile "@OutLetter"; #Will chr(12) work here, or is there something better? print OutFile chr(12); $StatusX = $x+1; print "Writing output $StatusX of $NumRecords... \n\n"; } close(OutFile); }

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  • UDK "Error, Accessing a member of _'s within class through a context expression requires explicit 'O

    - by Ricket
    I get the following error in the UDK Frontend when I try to make my project: C:\UDK\UDK-2010-03\Development\Src\FixIt\Classes\ZInteraction.uc(58) : Error, Accessing a member of GameUISceneClient's within class through a context expression requires explicit 'Outer' The class ZInteraction extends Interaction. Line 58 is: GetSceneClient().ConsoleCommand("KEYNAME"@Key); What is the problem here? I am still investigating and I will update as I find out more. edit: Tried fixing the line up as class'UIRoot'.static.GetSceneClient().ConsoleCommand("KEYNAME"@Key); - no change.

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  • Notepad++ regular expression find and replace $_REQUEST with $_GET but a more secure

    - by David
    What I am doing is replacing, in a large program, all $_REQUEST['var'] and mysql_escape_string($_REQUEST['var']) with either the 1st or 2nd line below the dotted line. Now, I have figured out this much of the regular expression but I would like to make it simpler. Instead of having to run the top one first then the 2nd one I would like to just run one all together. I tried this but it did not work. (mysql_escape_string\()*$_REQUEST\[\'([^']*)\'\]\)(\)*) So below is what works but again have to do it twice. $_REQUEST\[\'([^']*)\'\] mysql_escape_string\($_REQUEST\[\'([^']*)\'\]\) (isset($_GET['\1'])?mysql_real_escape_string($_GET['\1']):false) (isset($_POST['\1'])?mysql_real_escape_string($_POST['\1']):false) ============================ Update: Yeah, after some research I figured out that Notepad++ does not support most regular expressions. I guess one additional step can not hurt a person. It's just laziness. *NOTE: BUT if anyone wants to try feel free to comment. At least it is just 2 steps and not 20.

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  • MySQL, PHP, and Apache errors while connecting to DB

    - by cypherdelton
    I'm having two errors when I test the "mysql_connect()" function in php. I just installed PHP and MySQL from scratch. These errors may be related, so I will post them both here: Warning: mysql_connect() [function.mysql-connect]: Headers and client library minor version mismatch. Headers:50158 Library:50518 in /usr/local/apache2/htdocs/index.php on line 6 Warning: mysql_connect() [function.mysql-connect]: Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) in /usr/local/apache2/htdocs/index.php on line 6 Many websites say to start the mysql server if you are getting error #2. Whenever I execute the command mysqld start --user=mysql I get the error "mysqld: Too many arguments (first extra is 'start'); Adding the "&" to the end of the command makes no difference (I don't know if it is supposed to). Thanks, Cypher Delton

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