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  • DRYing up Rails Views with Nested Resources

    - by viatropos
    What is your solution to the problem if you have a model that is both not-nested and nested, such as products: a "Product" can belong_to say an "Event", and a Product can also just be independent. This means I can have routes like this: map.resources :products # /products map.resources :events do |event| event.resources :products # /events/1/products end How do you handle that in your views properly? Note: this is for an admin panel. I want to be able to have a "Create Event" page, with a side panel for creating tickets (Product), forms, and checking who's rsvp'd. So you'd click on the "Event Tickets" side panel button, and it'd take you to /events/my-new-event/tickets. But there's also a root "Products" tab for the admin panel, which could list tickets and other random products. The 'tickets' and 'products' views look 90% the same, but the tickets will have some info about the event it belongs to. It seems like I'd have to have views like this: products/index.haml products/show.haml events/products/index.haml events/products/show.haml But that doesn't seem DRY. Or I could have conditionals checking to see if the product had an Event (@product.event.nil?), but then the views would be hard to understand. How do you deal with these situations? Thanks so much.

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  • Strategies for Mapping Views in NHibernate

    - by Nathan Fisher
    It seems that NHibernate needs to have an id tag specified as part of the mapping. This presents a problem for views as most of the time (in my experience) a view will not have an Id. I have mapped views before in nhibernate, but they way I did it seemed to be be messy to me. Here is a contrived example of how I am doing it currently. Mapping <class name="ProductView" table="viewProduct" mutable="false" > <id name="Id" type="Guid"> <generator class="guid.comb" /> </id> <property name="Name" /> <!-- more properties --> </class> View SQL Select NewID() as Id, ProductName as Name, --More columns From Product Class public class ProductView { public virtual Id {get; set;} public virtual Name {get; set;} } I don't need an Id for the product or in the case of some views I may not have an id for the view, depending on if I have control over the View Is there a better way of mapping views to objects in nhibernate?

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  • Deploying Django at Dreamhost

    - by Imran
    I'm trying to get the Poll tutorial working at my Dreamhost account (I don't have any prior experience of deploying Django). I downloaded the script I found here (http://gabrielfalcao.com/2008/12/02/hosting-and-deploying-django-apps-on-dreamhost/) at my home directory and executed it. Now I have Python 2.5 and Django in ~/.myroot/ and my Django projects directory is ~/projects/ Here's the content of ~/projects/ directory (I copied the polls/ and and templates/polls/ directories myself). projects/ |-- admin_media -> /home/imran2140/.myroot/usr/lib/python2.5/site-packages/django/contrib/admin/media |-- dispatch.fcgi |-- polls | |-- __init__.py | |-- __init__.pyc | |-- admin.py | |-- admin.pyc | |-- models.py | |-- models.pyc | |-- polls.db | |-- urls.py | |-- urls.pyc | |-- views.py | `-- views.pyc |-- script_templates | |-- dispatch.template | `-- htaccess.template `-- templates `-- polls |-- detail.html |-- index.html `-- results.html 5 directories, 17 files Now what should I do to get the Polls app working? Update I finally got a "Hello World" Django app working with Passanger WSGI. It worked fine with both Server's default Python 2.3.5 and my installed Python 2.5.2. Passanger WSGI - Django at Dreamhost Wiki

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  • django internationalization and translations problem

    - by Zayatzz
    I have a problem with django translations. Problem 1 - i updated string in django.po file, but the change does not appear on the webpage. Problem 2 - i have created my own locale file with django-admin.py makemessages -l et, added the translation string into file, but they too do not appear on the page. I do not think this is setting problem, because the translations from django.po file do appear on the website, its just the changes and the translations from my own generated file that do not appear. Edit: My settings.py contains this: gettext = lambda s: s LANGUAGE_CODE = 'et' LANGUAGES = ( ('et', gettext('Estonian')), ) my own locale files are in /path/to/project/locale/et/LC_MESSAGES/ and the files are django.mo and django.po the file i refer to in problem 1 is django own et transaltion, which i changed.

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  • list editabale error

    - by ha22109
    Hello all, I m using django 1.1 beta.I m facing porblem in case of list_editable.First it was throughing exception saying need ordering in case of list_editable" then i added ordering in model but know it is giving me error.The code is working fine with django1.1 final. here is my code model.py class User(models.Model): advertiser = models.ForeignKey(WapUser,primary_key=True) status = models.CharField(max_length=20,choices=ADVERTISER_INVITE_STATUS,default='invited') tos_version = models.CharField(max_length=5) contact_email = models.EmailField(max_length=80) contact_phone = models.CharField(max_length=15) contact_mobile = models.CharField(max_length=15) contact_person = models.CharField(max_length=80) feedback=models.BooleanField(choices=boolean_choices,default=0) def __unicode__(self): return self.user.login class Meta: db_table = u'roi_advertiser_info' managed=False ordering=['feedback',] admin.py class UserAdmin(ReadOnlyAdminFields, admin.ModelAdmin): list_per_page = 15 fields = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person'] list_display = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person','status','feedback'] list_editable=['feedback'] readonly = ('advertiser',) search_fields = ['advertiser__login_id'] radio_fields={'approve_auto': admin.HORIZONTAL} list_filter=['status','feedback'] admin.site.register(User,UserADmin)

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  • How do you pass or share variables between django views?

    - by Hugh
    Hi, I'm kind of lost as to how to do this: I have some chained select boxes, with one select box per view. Each choice should be saved so that a query is built up. At the end, the query should be run. But how do you share state in django? I can pass from view to template, but not template to view and not view to view. Or I'm truly not sure how to do this. Please help!

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  • Why can't I use 'django-admin.py makemessages -l cn'

    - by zjm1126
    print : D:\zjm_code\register2>python D:\Python25\Lib\site-packages\django\bin\django-adm in.py makemessages -l cn Error: This script should be run from the Django SVN tree or your project or app tree. If you did indeed run it from the SVN checkout or your project or applica tion, maybe you are just missing the conf/locale (in the django tree) or locale (for project and application) directory? It is not created automatically, you ha ve to create it by hand if you want to enable i18n for your project or applicati on. 2.i made a locale directory ,and D:\zjm_code\register2>python D:\Python25\Lib\site-packages\django\bin\django-adm in.py makemessages -l cn processing language cn Error: errors happened while running xgettext on __init__.py 'xgettext' ?????????,????????? ??????? D:\Python25\lib\site-packages\django\core\management\base.py:234: RuntimeWarning : tp_compare didn't return -1 or -2 for exception sys.exit(1) 3. ok http://hi.baidu.com/zjm1126/blog/item/f28e09deced15353ccbf1a82.html

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  • How do I make a project in Django? Beginner

    - by ggfan
    Okay I just started with Django and it's totally different from PHP. I installed Python 2.6 and Django. Both are located in my C drive. C: Django build django docs Python26 I am doing the django site tutorial and when they say to write django-admin.py startproject mysite from my Python command line, I keep getting: Syntax error: invalid syntax >>>django-admin.py startproject mysite FILE "<stdin>", line 1 django-admin.py startproject mysite ^ My django-admin.py is in the django/bin folder. I installed Python via python setup.py. Am I suppose to use my window's CP? When I do that, I get window's can't open a .py file. I thought I was just creating a folder? How do I create a project with django? Thanks :)

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  • VS2012 - How to manually convert .NET Class Library to a Portable Class Library

    - by Igor Milovanovic
    The portable libraries are the  response to the growing profile fragmentation in .NET frameworks. With help of portable libraries you can share code between different runtimes without dreadful #ifdef PLATFORM statements or even worse “Add as Link” source file sharing practices. If you have an existing .net class library which you would like to reference from a different runtime (e.g. you have a .NET Framework 4.5 library which you would like to reference from a Windows Store project), you can either create a new portable class library and move the classes there or edit the existing .csproj file and change the XML directly. The following example shows how to convert a .NET Framework 4.5 library to a Portable Class Library. First Unload the Project and change the following settings in the .csproj file: <Import Project="$(MSBuildToolsPath)\Microsoft.CSharp.targets" /> to: <Import Project="$(MSBuildExtensionsPath32)\Microsoft\Portable \$(TargetFrameworkVersion)\Microsoft.Portable.CSharp.targets" /> and add the following keys to the first property group in order to get visual studio to show the framework picker dialog: <ProjectTypeGuids>{786C830F-07A1-408B-BD7F-6EE04809D6DB}; {FAE04EC0-301F-11D3-BF4B-00C04F79EFBC}</ProjectTypeGuids>   After that you can select the frameworks in the Library Tab of the Portable Library:   As last step, delete any framework references from the library as you have them already referenced via the .NET Portable Subset.     [1] Cross-Platform Development with the .NET Framework - http://msdn.microsoft.com/en-us/library/gg597391.aspx [2] Framework Profiles in .NET: http://nitoprograms.blogspot.de/2012/05/framework-profiles-in-net.html

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  • Storing ASP.Net MVC Views in the Database

    - by Adam Albrecht
    For an ASP.Net MVC application, I'm interested in storing some views and/or partial views in the database so that a few semi-technical users can do some basic view logic. Does anyone have any tips or lessons from experience on doing this? I know Phil Haack wrote a blog post on this about a year ago. He used IronRuby for scripting his views, (which would be fine for me). He created a quick proof-of-concept, but I can't find any other information on the topic. Any ideas, thoughts, tips, etc would be appreciated. Thanks!

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  • How do views reduce code duplication?

    - by Debuger
    Hi! I read something like this about db views: Views are incredibly powerful and useful for one reason that stands out above all the other very good reasons. They reduce code duplication. That is, in most cases, the bottom line. If a query will be used in three or more places, then a view will drastically simplify your changes if the schema or query parameters change. I once had to edit 22 stored procedures to change some query logic. If the original architecture had utilized views, then I would have had only three changes. Can anyone explain to me how it works, and maybe give me some examples? Best regards!

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  • Embedded strongly-typed views with ASP.NET MVC

    - by Brian Vallelunga
    I'm working on a plugin-type of system for ASP.NET MVC that loads views from an embedded assembly. I have created a VirtualPathProvider that does the work of retrieving out of the assembly. Everything is working fine except for strongly-typed views. Whenever I try to load one of those, I get an exception of: Could not load type 'System.Web.Mvc.ViewPage'. The problem is that there is no Web.config file under the Views folder. Well, actually there is, but the system doesn't seem to want to read the embedded version. If I manually create the file under the corresponding directory in the web app, everything is fine. This isn't an acceptable workaround however, as each plugin would need its own file in its own specific directory. Does anyone know how I might get ASP to read the embedded Web.config file? Thanks, Brian

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  • Drupal, Views: header doesn't accept PHP..

    - by Patrick
    hi, I'm using Views for some nodes, and I want to display a different View title according to which taxonomy tags are selected in my filter. I already have taxonomy field for each node in my view. But this is not what I need. I basically need to display all the currently filtered tags on the top of my view. I was wondering if I can solve adding some line with php, how ? Thanks Update: I'm now using the Views Header field in Views settings, but it only processes html code, not php, so I cannot add taxonomy terms. Is it because of my CCK Editor settings ? thanks

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  • jQuery how to add class to a parent div which has a 3rd level child div with a specific class name.

    - by Vikram
    Hello friends I have an issue adding a special class to a couple of my divs. My layout is like this. <div class="container"> <div class="grid-6 push-3 equal" style="height: 999px;"> <div class="block"> <div id="mainbody"> <!-- Body content here --> </div> </div> </div> <div class="grid-2 equal" style="height: 999px;"> <div class="block"> <div id="sidebar-a"> <!-- Sidebar-a content here --> </div> </div> </div> <div class="grid-2 equal" style="height: 999px;"> <div class="block"> <div id="sidebar-b"> <!-- Sidebar-b content here --> </div> </div> </div> <div class="grid-2 equal" style="height: 999px;"> <div class="block"> <div id="sidebar-b"> <!-- Sidebar-c content here --> </div> </div> </div> </div> I want to add a different background color to each of my sidebars via CSS and when I code like: #mainbody { background : #fff; } #sidebar-a { background : #eee; } #sidebar-b { background : #ddd; } #sidebar-c { background : #ccc; } It is applying the background only to that specific class but that specific class is not of equal height. I actually need to apply to this <div class="grid-2 equal" style="height: 999px;"> div. Now the issue is that in this <div class="grid-6 push-3 equal" style="height: 999px;"> and class="grid-2 equal" style="height: 999px;"> the class names grid-6 and grid-2 are generated dynamically by my PHP of 960 Grid System and also the style="height: 999px; is generated by a jQuery script for Equal-Columns. What I want is to add a unique class name like this...... Look for a div with a class of .equal which has a child div with a class of .block and which further has a child div with an ID of sidebar-a. IF TRUE then add a class of .sidebar-a to the maindiv which has a class of .equal So that the result looks like this: <div class="grid-6 equal push-3 mainbody" style="height: 999px;"> <div class="grid-2 equal sidebar-a" style="height: 999px;"> <div class="grid-2 equal sidebar-b" style="height: 999px;"> <div class="grid-2 equal sidebar-c" style="height: 999px;"> Then I'll be able to style it like this: .mainbody { background : #fff; } .sidebar-a { background : #eee; } .sidebar-b { background : #ddd; } .sidebar-c { background : #ccc; } Hence I thought since I am anyway using jQuery in my Template, why not use it to deal with this issue. Please feel free to suggest a better way if you have something else in mind.

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  • Login and Redirect

    - by xRobot
    This is my login views: def login(request): redirect_to = request.REQUEST.get("next") if request.method == 'POST': formL = LoginForm(data=request.POST) if formL.is_valid(): if not redirect_to or '//' in redirect_to or ' ' in redirect_to: redirect_to = "/blogs/" from django.contrib.auth import login login(request, formL.get_user()) if request.session.test_cookie_worked(): request.session.delete_test_cookie() return HttpResponseRedirect(redirect_to) else: formL = LoginForm(request) request.session.set_test_cookie() return render_to_response('blogs.html', { 'formL': formL, }, context_instance=RequestContext(request)) login = never_cache(login) When I go, for example, to example.com/myblog/ then I have been redirect to example.com/accounts/login/?next=/myblog/ but when I insert user and psw for login then I have been redirect to /blogs/ and not /myblog/ Why ?

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  • Possible form field types per model field type

    - by Jonathan
    Django's documentation specifies for each model field type the corresponding default form field type. Alas, I couldn't find in the documentation, or anywhere else, what form field types are possible per model field type. Not all combinations are possible, right? Same question for widgets...

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  • Could I use urlize filter in this way ?

    - by xRobot
    Could I use urlize filter in this way? : from django.utils.html import urlize def save(self, force_insert=False, force_update=False): self.body = urlize(self.body) super(Post, self).save(force_insert, force_update) body is a TextField.

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  • Django select distinct sum

    - by yoshi
    I have the following (greatly simplified) table structure: Order: order_number = CharField order_invoice_number = CharField order_invoice_value = CharField An invoice number can be identical on more than one order (order O1 has invoice number I1, order O2 has invoice number I1, etc.). All the orders with the same invoice number have the same invoice value. For example: Order no. Invoice no. Value O1 I1 200 O2 I1 200 O3 I1 200 04 I2 50 05 I2 100 What I am trying to do is do a sum over all the invoice values, but don't add the invoices with the same number more than once. The sum for the above items would be: 200+50+100. I tried doing this using s = orders.values('order_invoice_id').annotate(total=Sum('order_invoice_value')).order_by() and s = orders.values('order_invoice_id').order_by().annotate(total=Sum('order_invoice_value')) but I didn't get the desired result. I tried a few different solutions from similar questions around here but I couldn't get the desired result. I can't figure out what I'm doing wrong and what I actually should do to get a sum that uses each invoice value just once.

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  • problem in decoupling urls.py , while following a tutorial of django

    - by Nitin Garg
    http://docs.djangoproject.com/en/dev/intro/tutorial03/ I was at the step Decoupling the URLconfs where the tutorial illustrates how to decouple urls.py. On doing exactly what it says, i get the following error- error at /polls/1/ nothing to repeat Request Method: GET Request URL: http://localhost:8000/polls/1/ Exception Type: error Exception Value: nothing to repeat Exception Location: C:\jython2.5.1\Lib\re.py in _compile, line 241 Python Executable: C:\jython2.5.1\jython.bat Python Version: 2.5.1 Python Path: ['E:\\Programming\\Project\\django_app\\mysite', 'C:\\jython2.5.1\\Lib\\site-packages\\setuptools-0.6c11-py2.5.egg', 'C:\\jython2.5.1\\Lib', '__classpath__', '__pyclasspath__/', 'C:\\jython2.5.1\\Lib\\site-packages'] Server time: Mon, 12 Apr 2010 12:02:56 +0530

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  • Django-pyodbc mssql/freetds server connection problems on linux

    - by wizard
    Error: ('IM002', '[IM002] [unixODBC][Driver Manager]Data source name not found, and no default driver specified (0) (SQLDriverConnectW)') I'm migrating from developing on a windows development machine to linux machine in production and I'm having issues with the freetds driver. As far as I can tell that error message means it can't find the driver. I can connect via the cli via sqsh and tsql. I've setup my settings.py as such. 'bc2db': { 'ENGINE': 'sql_server.pyodbc', 'NAME': 'DataTEST', 'USER': 'appuser', 'PASSWORD': 'PASS', 'HOST': 'bc2.domain.com', 'options': { 'driver': 'FreeTDS', } }, Does anyone have any mssql experience with djano? do I have to use a dns? (how would I format that?) Thanks

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  • adding errors to Django form errors.__all__

    - by hendrixski
    How do I add errors to the top of a form after I cleaned the data? I have an object that needs to make a REST call to an external app (google maps) as a pre-save condition, and this can fail, which means I need my users to correct the data in the form. So I clean the data and then try to save and add to the form errors if the save doesn't work: if request.method == "POST": #clean form data try: profile.save() return HttpResponseRedirect(reverse("some_page", args=[some.args])) except ValueError: our_form.errors.__all__ = [u"error message goes here"] return render_to_response(template_name, {"ourform": our_form,}, context_instance=RequestContext(request)) This failed to return the error text in my unit-tests (which were looking for it in {{form.non_field_errors}}), and then when I run it through the debugger, the errors had not been added to the forms error dict when they reach the render_to_response line, nor anywhere else in the our_form tree. Why didn't this work? How am I supposed to add errors to the top of a form after it's been cleaned?

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  • Django formsets: make first required?

    - by Mark
    These formsets are exhibiting exactly the opposite behavior that I want. My view is set up like this: def post(request): # TODO: handle vehicle formset VehicleFormSetFactory = formset_factory(VehicleForm, extra=1) if request.POST: vehicles_formset = VehicleFormSetFactory(request.POST) else: vehicles_formset = VehicleFormSetFactory() And my template looks like this: <div id="vehicle_forms"> {{ vehicles_formset.management_form }} {% for form in vehicles_formset.forms %} <h4>Vehicle {{forloop.counter}}</h4> <table> {% include "form.html" %} </table> {% endfor %} </div> That way it initially generates only 1 form, like I want. But I want that one form to be required! When I dynamically add blank forms with JavaScript and vehicles_formset.empty_form all those extra forms are required, which I don't want. From the docs: The formset is smart enough to ignore extra forms that were not changed. This is the behavior the first form is exhibiting (not what I want) but not the behavior that the extra forms are exhibiting (what I do want). Is there some attribute I can can change to at least make one form required?

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