Search Results

Search found 13683 results on 548 pages for 'python sphinx'.

Page 412/548 | < Previous Page | 408 409 410 411 412 413 414 415 416 417 418 419  | Next Page >

  • Change web service url for a suds client on runtime (keeping the wsdl)

    - by patanpatan
    Hi. First of all, my question is similar to this one But it's a little bit different. What we have is a series of environments, with the same set of services. For some environments (the local ones) we can get access to the wsdl, and thus generating the suds client. For external environment, we cannot access the wsdl. But being the same, I was hoping I can change just the URL without regenerating the client. I've tried cloning the client, but it doesn't work.

    Read the article

  • sip.conf configuration file - add new line to each record

    - by Flukey
    I have a sip configuration file which looks like this: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no For each record I need to add another line (vmxten for each record) for example the above becomes: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1664 [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1679 [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1700 [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1701 What would you say would be the quickest way to do this? there are hundreds of records in the file, therefore modifying all of the records by hand would take a long time. Would you use Regex? Would you use sed? I'm interested to know how you would approach the problem. Thanks

    Read the article

  • GTK+: How do I process RadioMenuItem choice without marking it chosen? And vise versa

    - by eugene.shatsky
    In my program, I've got a menu with a group of RadioMenuItem entries. Choosing one of them should trigger a function which can either succeed or fail. If it fails, this RadioMenuItem shouldn't be marked chosen (the previous one should persist). Besides, sometimes I want to set marked item without running the choice processing function. Here is my current code: # Update seat menu list def update_seat_menu(self, seats, selected_seat=None): seat_menu = self.builder.get_object('seat_menu') # Delete seat menu items for menu_item in seat_menu: # TODO: is it a good way? does remove() delete obsolete menu_item from memory? if menu_item.__class__.__name__ == 'RadioMenuItem': seat_menu.remove(menu_item) # Fill menu with new items group = [] for seat in seats: menu_item = Gtk.RadioMenuItem.new_with_label(group, str(seat[0])) group = menu_item.get_group() seat_menu.append(menu_item) if str(seat[0]) == selected_seat: menu_item.activate() menu_item.connect("activate", self.choose_seat, str(seat[0])) menu_item.show() # Process item choice def choose_seat(self, entry, seat_name): # Looks like this is called when item is deselected, too; must check if active if entry.get_active(): # This can either succeed or fail self.logind.AttachDevice(seat_name, '/sys'+self.device_syspath, True) Chosen RadioMenuItem gets marked irrespective of the choose_seat() execution result; and the only way to set marked item without triggering choose_seat() is to re-run update_seat_menu() with selected_seat argument, which is an overkill. I tried to connect choose_seat() with 'button-release-event' instead of 'activate' and call entry.activate() in choose_seat() if AttachDevice() succeeds, but this resulted in whole X desktop lockup until AttachDevice() timed out, and chosen item still got marked.

    Read the article

  • Indexing over the results returned by selenium

    - by Guy
    Hi I try to index over results returned by an xpath. For example: xpath = '//a[@id="someID"]' can return a few results. I want to get a list of them. I thought that doing: numOfResults = sel.get_xpath_count(xpath) l = [] for i in range(1,numOfResults+1): l.append(sel.get_text('(%s)[%d]'%(xpath, i))) would work because doing something similar with firefox's Xpath checker works: (//a[@id='someID'])[2] returns the 2nd result. Ideas why the behavior would be different and how to do such a thing with selenium Thanks

    Read the article

  • How to get attributes from parent?

    - by bribon
    Hi all, Let's say we have these classes: class Foo(object): _bar = "" def __init__(self): self.bar = "hello" def getBar(self): return self._bar def setBar(self, bar): self._bar = bar def getAttributes(self): for attr in self.__dict__: print attr bar = property(getBar, setBar) class Child(Foo): def __init__(self): super(Child, self).__init__() self.a = "" self.b = "" if I do something like: child = Child() child.getAttributes() I get all the attributes from parent and child. How could I get the attributes only from the parent? Thanks in advance!

    Read the article

  • index error:list out of range

    - by kaushik
    from string import Template from string import Formatter import pickle f=open("C:/begpython/text2.txt",'r') p='C:/begpython/text2.txt' f1=open("C:/begpython/text3.txt",'w') m=[] i=0 k='a' while k is not '': k=f.readline() mi=k.split(' ') m=m+[mi] i=i+1 print m[1] f1.write(str(m[3])) f1.write(str(m[4])) x=[] j=0 while j<i: k=j-1 l=j+1 if j==0 or j==i: j=j+1 else: xj=[] xj=xj+[j] xj=xj+[m[j][2]] xj=xj+[m[k][2]] xj=xj+[m[l][2]] xj=xj+[p] x=x+[xj] j=j+1 f1.write(','.join(x)) f.close() f1.close() It say line 33,xj=xj+m[l][2] has index error,list out of range please help thanks in advance

    Read the article

  • Using SQLAlchemy, how can I return a count with multiple columns

    - by Andy
    I am attempting to run a query like this: SELECT comment_type_id, name, count(comment_type_id) FROM comments, commenttypes WHERE comment_type_id=commenttypes.id GROUP BY comment_type_id Without the join between comments and commenttypes for the name column, I can do this using: session.query(Comment.comment_type_id,func.count(Comment.comment_type_id)).group_by(Comment.comment_type_id).all() However, if I try to do something like this, I get incorrect results: session.query(Comment.comment_type_id, Comment.comment_type, func.count(Comment.comment_type_id)).group_by(Comment.comment_type_id).all() I have two problems with the results: (1, False, 82920) (2, False, 588) (3, False, 4278) (4, False, 104370) Problems: The False is not correct The counts are wrong My expected results are: (1, 'Comment Type 1', 13820) (2, 'Comment Type 2', 98) (3, 'Comment Type 2', 713) (4, 'Comment Type 2', 17395) How can I adjust my command to pull the correct name value and the correct count?

    Read the article

  • Filtering SQLAlchemy query on attribute_mapped_collection field of relationship

    - by bsa
    I have two classes, Tag and Hardware, defined with a simple parent-child relationship (see the full definition at the end). Now I want to filter a query on Tag using the version field in Hardware through an attribute_mapped_collection, eg: def get_tags(order_code=None, hardware_filters=None): session = Session() query = session.query(Tag) if order_code: query = query.filter(Tag.order_code == order_code) if hardware_filters: for k, v in hardware_filters.iteritems(): query = query.filter(getattr(Tag.hardware, k).version == v) return query.all() But I get: AttributeError: Neither 'InstrumentedAttribute' object nor 'Comparator' object associated with Tag.hardware has an attribute 'baseband The same thing happens if I strip it back by hard-coding the attribute, eg: query.filter(Tag.hardware.baseband.version == v) I can do it this way: query = query.filter(Tag.hardware.any(artefact=k, version=v)) But why can't I filter directly through the attribute? Class definitions class Tag(Base): __tablename__ = 'tag' tag_id = Column(Integer, primary_key=True) order_code = Column(String, nullable=False) version = Column(String, nullable=False) status = Column(String, nullable=False) comments = Column(String) hardware = relationship( "Hardware", backref="tag", collection_class=attribute_mapped_collection('artefact'), ) __table_args__ = ( UniqueConstraint('order_code', 'version'), ) class Hardware(Base): __tablename__ = 'hardware' hardware_id = Column(Integer, primary_key=True) tag_id = Column(String, ForeignKey('tag.tag_id')) product_id = Column(String, nullable=True) artefact = Column(String, nullable=False) version = Column(String, nullable=False)

    Read the article

  • How to pickle and unpickle objects with self-references and from a class with slots?

    - by EOL
    Is it possible to pickle an object from a class with slots, when this object references itself through one of its attributes? Here is a simple example: import weakref import pickle class my_class(object): __slots__ = ('an_int', 'ref_to_self', '__weakref__') def __init__(self): self.an_int = 42 self.ref_to_self = weakref.WeakKeyDictionary({self: 1}) # __getstate__ and __setstate__ not defined: how should this be done? if __name__ == '__main__': obj = my_class() # How to make the following work? obj_pickled = pickle.dumps(obj) obj_unpickled = pickle.loads(obj_pickled) # Self-references should be kept: print "OK?", obj_unpickled == obj_unpickled.ref_to_self.keys()[0]

    Read the article

  • wxPython formatting questions

    - by Kevin
    I have an app I was working on to learn more about wxPython( I have been primarily been a scripter ). I forgot about it now I am opening it back up. It's a screen scraper, and I have it working almost the way I want it, going to build a regex parser to strip out the links in every scrape that I don't need. The questions I have are this. In it current state, if I check more than one site, it goes out and scrapes, and returns it in separate windows, the for:each section in the Clicked function. I want to put them in a frame, in the window, altogether. I also want to know if I can take the list they are read into and send it to a checklist, so someone could check off separate items, I want to build a save function and keep certain ones. In regards to a save function, I want to keep saved checks, are there calls to the widgets to save their states? I know it's a lot, but thanks for the help.

    Read the article

  • Object for storing strings geted from prints

    - by evg
    class MyWriter: def __init__(self, stdout): self.stdout = stdout self.dumps = [] def write(self, text): self.stdout.write(smart_unicode(text).encode('cp1251')) self.dumps.append(text) def close(self): self.stdout.close() writer = MyWriter(sys.stdout) save = sys.stdout sys.stdout = writer I use self.dumps list to store geted data from prints. Is it exists more convinient object for storing string lines in memory? ideally i want dump it to one big string. I can get it like this "\n".join(self.dumps) from code above. Mb it's better to just concat strings - self.dumps += text ?

    Read the article

  • Using classes for the first time,help in debugging

    - by kaushik
    here is post my code:this is no the entire code but enough to explain my doubt.please discard any code line which u find irrelavent enter code here saving_tree={} isLeaf=False class tree: global saving_tree rootNode=None lispTree=None def __init__(self,x): file=x string=file.readlines() #print string self.lispTree=S_expression(string) self.rootNode=BinaryDecisionNode(0,'Root',self.lispTree) class BinaryDecisionNode: global saving_tree def __init__(self,ind,name,lispTree,parent=None): self.parent=parent nodes=lispTree.getNodes(ind) print nodes self.isLeaf=(nodes[0]==1) nodes=nodes[1]#Nodes are stored self.name=name self.children=[] if self.isLeaf: #Leaf Node print nodes #Set the leaf data self.attribute=nodes print "LeafNode is ",nodes else: #Set the question self.attribute=lispTree.getString(nodes[0]) self.attribute=self.attribute.split() print "Question: ",self.attribute,self.name tree={} tree={str(self.name):self.attribute} saving_tree=tree #Add the children for i in range(1,len(nodes)):#Since node 0 is a question # print "Adding child ",nodes[i]," who has ",len(nodes)-1," siblings" self.children.append(BinaryDecisionNode(nodes[i],self.name+str(i),lispTree,self)) print saving_tree i wanted to save some data in saving_tree{},which i have declared previously and want to use that saving tree in the another function outside the class.when i asked to print saving_tree it printing but,only for that instance.i want the saving_tree{} to have the data to store data of all instance and access it outside. when i asked for print saving_tree outside the class it prints empty{}.. please tell me the required modification to get my required output and use saving_tree{} outside the class..

    Read the article

  • How to save to two tables using one SQLAlchemy model

    - by Oatman
    I have an SQLAlchemy ORM class, linked to MySQL, which works great at saving the data I need down to the underlying table. However, I would like to also save the identical data to a second archive table. Here's some psudocode to try and explain what I mean my_data = Data() #An ORM Class my_data.name = "foo" #This saves just to the 'data' table session.add(my_data) #This will save it to the identical 'backup_data' table my_data_archive = my_data my_data_archive.__tablename__ = 'backup_data' session.add(my_data_archive) #And commits them both session.commit() Just a heads up, I am not interested in mapping a class to a JOIN, as in: http://www.sqlalchemy.org/docs/05/mappers.html#mapping-a-class-against-multiple-tables

    Read the article

  • What is the proper way to check the previous value of a field before saving an object? (Using Django

    - by anonymous coward
    I have a Django Model with updated_by and an approved_by fields, both are ForeignKey fields to the built-in (auth) User models. I am aware that with updated_by, it's easy enough to simply over-ride the .save() method on the Model, and shove the request.user in that field before saving. However, for approved_by, this field should only ever be filled in when a related field (date_approved) is first filled in. I'm somewhat certain that I can check this logically, and fill in the field if the previous value was empty. What is the proper way to check the previous value of a field before saving an object? I do not anticipate that date_approved will ever be changed or updated, nor should there be any reason to ever update the approved_by entry. UPDATE: Regarding forms/validation, I should have mentioned that none of the fields in question are seen by or editable by users of the site. If I have misunderstood, I'm sorry, but I'm not sure how forms and validation apply to my question.

    Read the article

  • Creating tables with pylons and SQLAlchemy

    - by Sid
    I'm using SQLAlchemy and I can create tables that I have defined in /model/__init__.py but I have defined my classes, tables and their mappings in other files found in the /model directory. For example I have a profile class and a profile table which are defined and mapped in /model/profile.py To create the tables I run: paster setup-app development.ini But my problem is that the tables that I have defined in /model/__init__.py are created properly but the table definitions found in /model/profile.py are not created. How can I execute the table definitions found in the /model/profile.py so that all my tables can be created? Thanks for the help!

    Read the article

  • How to attach a line to a moving object?

    - by snow-spur
    Hello i have designed a maze and i want to draw a path between the cells as the 'person' moves from one cell to the next. So each time i move the cell a line is drawn I have done this so far but do not want to show my full code However i get an error saying Circle has no attribute center my circle which is my cell center = Point(15, 15) c = Circle(center, 12) c.setFill('blue') c.setOutline('yellow') c.draw(win) p1 = Point(c.center().getx(), c.center().gety()) this bit is in my loop p2 = Point(getx(), gety()) line = graphics.Line(p1, p2)

    Read the article

  • Replacing text with variables

    - by Steve
    I have to send out letters to certain clients and I have a standard letter that I need to use. I want to replace some of the text inside the body of the message with variables. Here is my maturity_letter models.py class MaturityLetter(models.Model): default = models.BooleanField(default=False, blank=True) body = models.TextField(blank=True) footer = models.TextField(blank=True) Now the body has a value of this: Dear [primary-firstname], AN IMPORTANT REMINDER… You have a [product] that is maturing on [maturity_date] with [financial institution]. etc Now I would like to replace everything in brackets with my template variables. This is what I have in my views.py so far: context = {} if request.POST: start_form = MaturityLetterSetupForm(request.POST) if start_form.is_valid(): agent = request.session['agent'] start_date = start_form.cleaned_data['start_date'] end_date = start_form.cleaned_data['end_date'] investments = Investment.objects.all().filter(maturity_date__range=(start_date, end_date), plan__profile__agent=agent).order_by('maturity_date') inv_form = MaturityLetterInvestments(investments, request.POST) if inv_form.is_valid(): sel_inv = inv_form.cleaned_data['investments'] context['sel_inv'] = sel_inv maturity_letter = MaturityLetter.objects.get(id=1) context['mat_letter'] = maturity_letter context['inv_form'] = inv_form context['agent'] = agent context['show_report'] = True Now if I loop through the sel_inv I get access to sel_inv.maturity_date, etc but I am lost in how to replace the text. On my template, all I have so far is: {% if show_letter %} {{ mat_letter.body }} <br/> {{ mat_letter.footer }} {% endif %} Much appreciated.

    Read the article

< Previous Page | 408 409 410 411 412 413 414 415 416 417 418 419  | Next Page >