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  • Files mapping architecture

    - by user326198
    I need to know How I can achieve this goal by classes : we have two different applications in the company (App1 , App2) Appl can export xml with know items ( ID , Name) we need app2 to import this data but App2 display different items (CarID, CarName) and this items defined like this with the mapping info <CarID> <Mapping name="ID"/> </CarID> <CarNAme> <Mapping name="Name"/> </CarNAme>" How I can achieve this as classes or ARCHITECTURE , i will develop this with c# I need one interface because we may support different type of files not just xml

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  • Beginning with Datampper, Association question

    - by Ian
    I'm just diving into Datamapper (and Sinatra) and have a question about associations. Below are some models I have. This is what I want to implemented. I'm having an issue with Workoutitems and Workout. Workout will be managed separately, but Workoutitems has a single workout associated with each row. Workout - just a list of types of workouts (run, lift, situps, etc) Selected workout - this is the name of a set of workouts, along with notes by the user and trainer. It has a collection of N workoutitems Workoutitems - this takes a workout and a number of repetitions to it that go in the workout set. class Workout include DataMapper::Resource property :id, Serial #PK id property :name, String, :length=50,:required=true # workout name property :description, String, :length=255 #workout description end class Selectedworkout include DataMapper::Resource property :id, Serial property :name, String, :length=50, :required=true property :workout_time, String, :length=20 property :user_notes, String, :length=255 property :coach_notes, String, :length=255 has n, :workoutitems end class Workoutitem include DataMapper::Resource property :id, Serial property :reps, String, :length=50, :required=true belongs_to :selectedworkout end

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  • How to dynamically order many-to-many relationship with JPA or HQl?

    - by Indrek
    I have a mapping like this: @ManyToMany(cascade = CascadeType.PERSIST) @JoinTable( name="product_product_catalog", joinColumns={@JoinColumn(name="product_catalog", referencedColumnName="product_catalog")}, inverseJoinColumns={@JoinColumn(name="product", referencedColumnName="product")}) public List<Product> products = new ArrayList<Product>(); I can fetch the products for the catalog nicely, but I can't (dynamically) order the products. How could I order them? I probably have to write a many-to-many HQL query with the order-by clause? I though of passing the orderBy field name string to the query, or is there a better solution? Tables are: products, product_catalog, product_product_catalog (associative table) P.S. Using Play! Framework JPASupport for my entities.

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  • Extract Data from a Website using PHP

    - by 01jayss
    I am trying to get PHP to extract the TOKEN (the uppercase one), USERID (uppercase), and the USER NAME (uppercase) from a web page with the following text. {"rsp":{"stat":"ok","auth":{"token":"**TOKEN**","perms":"read","user":{"id":"**USERID**","username":"**USER NAME**","fullname":"**NAME OF USER**"}}}} (This is from the RTM api, getting the authentication token of the user). How would I go about doing this? Thanks!

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  • Keep data with specific value on top when sorting a gridview

    - by aspNetAficionado
    Hi i have a gridview with information about documents: name, document type (policy, guidelines, forms, etc), category, etc. I want to sort the gridview alphabetically (name) and by document type, but always having the 'policy' above the other document types when document name is the same. How do I do that? eg If I do sort by DocumentName, DocumentType ('policy' maybe not be the first one in the list) but if I do sort by DocumentType , DocumentName (I would get for example all guidelines first in alphabetical order, then procedures, then policies, etc)

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  • Returning string in java using 3 parameters

    - by user2905118
    Need to write a method describePerson() that takes 3 parameters, a String giving a person’s name, a boolean indicating their gender (true for female, false for male), and an integer giving their age. The method should return a String formatted as in the following examples: Lark is female. She is 2 years old. Or Jay is male. He is 1 year old. I am not sure how to write it correctly (my code): int describePerson(String name, boolean gender, int age) { String words=""; if(gender==true) return (name + "is "+gender+". "+"She is"+age+ "years old.); else return (name + "is "+gender+". "+"She is"+age+ "years old.); } The outcome "year" and "years" is also differs, but i don't know how to make it correct..

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  • How do I collect a bunch of Django abstract models in a QuerySet?

    - by Thierry Lam
    I have the following abstract Django models: class Food(models.Model): name = models.CharField(max_length=100) class Meta: abstract = True In one of my view, I created a bunch of Food model: panino = Food(name='Panino') poutine = Food(name='Poutine') food = [panino, poutine] From the above, I'm not saving the model and storing the Food model in a regular Python list. I want to store the above food models in a QuerySet object. How can I do that without storing any data to the database?

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  • codeigniter populate form from database

    - by Delirium tremens
    In the controller, I have... function update($id = null) { $this->load->database(); // more code $data = array(); $data = $this->db->get_where( 'users', array( 'id' => $id ) ); $data = $data->result_array(); $data = $data[0]; // more code $this->load->view('update', $data); } In the view, I have... <h5>Username</h5> <input type="text" name="username" value="<?php echo set_value('username'); ?>" size="50" /> <h5>Email</h5> <input type="text" name="email" value="<?php echo set_value('email'); ?>" size="50" /> <h5>Email Confirmation</h5> <input type="text" name="emailconf" value="<?php echo set_value('emailconf'); ?>" size="50" /> <h5>Password</h5> <input type="text" name="password" value="<?php echo set_value('password'); ?>" size="50" /> <h5>Password Confirmation</h5> <input type="text" name="passconf" value="<?php echo set_value('passconf'); ?>" size="50" /> set_value() isn't reading $data search for value="" at http://codeigniter.com/forums/viewthread/103837/ The poster uses only the set_value() function between "" in value="". I'm wondering how to do the same, but I can't get it to work. Help?

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  • Spreatsheet:WriteExcel create Chart

    - by yaohung
    Hi, I used csv2xls.pl to convert a text log into .xls file, and then apply create chart function as following: my $chart3 = $workbook-add_chart( type = 'line' , embedded = 1); Configure the series. $chart3-add_series( categories = '=Sheet1!$B$2:$B$64', values = '=Sheet1!$C$2:$C$64', name = 'Test data series 1', ); Add some labels. $chart3-set_title( name = 'Bridge Rate Analysis' ); $chart3-set_x_axis( name = 'Packet Size ' ); $chart3-set_y_axis( name = 'BVI Rate' ); Insert the chart into the main worksheet. $worksheet-insert_chart( 'G2', $chart3 ); ========== I can see the chart in .xls file, however, all the data is in text format, not number, therefore, the chart looks wrong. I am wondering can you tell me how to convert text into number before apply this create chart function? One other thing is any idea how to apply sorting on the .xls file before create chart? Thanks. Yaohung

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  • Grails: How can I search through children in a hasMany relationship?

    - by intargc
    If I have a Client domain class, and that Client hasMany Courses. How do I find the course I'm looking for? For instance: class Client { String name static hasMany = [courses:Course] } class Course { String name static belongsTo = [client:Client] } def client = Client.get(1) I want to "find" or "search" within that courses relationship. Maybe something like: client.courses.find(name:'Whatever') Is there any way to do this with Grails?

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  • submit a form and get json response

    - by ruhit
    I have made an application to convert text to image formate and its workingout well. Now I want json response when i fill the form of the html page, my html page is given below...Please help me to do this <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN"> <html lang="en"> <head> <title>kandarpa</title> </head> <div> <form action="img.php" method="get"><b>enter your text here:</b><br/> <textarea id="text" name="text" style=" background-color:inherit" cols="50" rows="10"></textarea><br/><br/> <input type="submit" value="Text to Image" name="submit"> </div><br/> <div> <tr> <td>Font Size</td> <td><select name="size"> <option value="8">8</option> <option value="12">12</option> <option value="18">18</option> <option value="24">24</option> <option value="32" selected="selected">32</option> <option value="48">48</option> <option value="64">64</option> </select></td> </tr> </div><br/> <div> <td>Font </td> <td><select name="font" id="font"> <option value="Fonts/arial.ttf">Arial</option> <option value="Fonts/times.ttf">Times New Roman</option> <option value="Fonts/tahoma.ttf">Tahoma</option> <option value="Fonts/Grand Stylus.ttf">Grand Stylus</option> <option value="Fonts/GARAIT.ttf">G</option> </select></td> </tr> </div><br/> <div> <td>Choose your Color </td> <td><select name="color" id="color"> <option value="white">white</option> <option value="black">black</option> <option value="grey">grey</option> <option value="red">red</option> </select></td> </tr> </div> <br/> <div> <td>Height </td> <input type="text" id="height" name="height"> </td><br/><br/> <td>Width</td> <input type="text" id="width" name="width"> </div> </form> </body> </html>

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  • How do you use build labels in publishers in cruisecontrol?

    - by Omnifarious
    I have this section in my CruiseControl config.xml file: <publishers> <onsuccess> <artifactspublisher dest="artifacts/${project.name}" file="projects/${project.name}/fred"/> <execute command="hg -R hg-succeeded/${project.name} pull"/> <execute command="hg -R hg-succeeded/${project.name} tag -l build-${label} -r tip"/> </onsuccess> </publishers> I'm getting tags that look like build-${label}. The ${label} part isn't being replaced by the build label like I expect. I'm expecting something like build.1 to show up in place of ${label}. How do I make this happen? I do have the default labelincrementer configured with a <labelincrementer /> tag in my project. Also, the CruiseControl documentation is absolutely awful. Is there better documentation anywhere?

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  • Want to add labels and textboxes on clicking a Href link

    - by user1740184
    I am using code in view of MVC as below <div class="form-inline"> <label class="control-label"><b>Length</b></label> <input type="text" name="Refinishing.Room.Length.Feet" id="Refinishing_Room_Length_Feet" style="width: 80px" class="floor-text" />Ft <input type="text" name="Refinishing.Room.Length.Inch" id="Refinishing_Room_Length_Inch" class="floor-text" />Inch <label><b>Width</b></label> <input type="text" name="Refinishing.Room.Width.Feet" id="Refinishing_Room_Width_Feet" class="floor-text" />Ft <input type="text" name="Refinishing.Room.Width.Inch" id="Refinishing_Room_Width_Inch" class="floor-text" />Inch<br /> <a href="#">Add Room</a> / <a href="#">Remove Room</a> </div> and I want to add the contents of "<div>" on clicking the link "Add Room". How can it be done?

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  • how to combine the error message from jquery validation

    - by aon
    how to combine the error message from jquery validation. for example: messages: { first_name: { required: "Please enter your first name." }, email: { required: "Please enter a valid email address.", remote: "Email has been registered." }, username: { required: "Please enter username.", remote: "Username has been registered." } }, Desired message will be like this: Please enter your first name, a valid email address and username or Please enter your first name and username, email has been registered etc.

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  • Jquery get array details

    - by Matt
    I'm having trouble getting a response back from a Jquery ajax call... (It's a script to authenticate a user, and needs to return their name and user ID. My understanding was that I could encode it as JSON and get the data in the format below. It is returning an error of "undefined" for the alert(). The javascript $.ajax({ type: "POST", url: "myURL.php", data: {username: username, password: password}, success: function(results) { //THIS IS WHERE THE PROBLEM IS alert('Hi '+results.name); //Should be "Hi Basil Fawlty" } }); The PHP (myURL.php) //This comes from a SQL call that returns the following name json_encode(array( 'id'=>1, 'name'=>'Basil Fawlty' )); Any help or ideas on where I am going wrong would be greatly appreciated! Thanks.

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  • How can I get all the checked items from a submitted form with sinatra's params?

    - by 102405176597896213397
    I'm running Sinatra 1.0 with HAML, my form has a number of checkboxes, for example books I like, and you would select all the books you want. The checkbox name is "books". In sinatra params['books'] there should be an array of all the books that were checked, but it only has the last item that was checked, not an array. How can I get all the checked items? HAML: %form{:action => "/test", :method => 'post'} %input{:name=>'check',:type=>'checkbox',:value=>'item1'} item 1 %input{:name=>'check',:type=>'checkbox',:value=>'item2'} item 2 %input{:name=>'check',:type=>'checkbox',:value=>'item3'} item 3 %input{:type => "submit", :value => "send", :class => "button"} Sinatra get method post '/test' do puts params['check'] #should be an array but is last item checked end

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  • Object reference case study

    - by Skogen
    When person 1 become partner with person 3, person 2 should no longer have person 1 as partner. How should I solve this? public class Person { private String name; private Person partner; public Person(String name){ this.name = name; } public void setPartner(Person partner){ this.partner = partner; partner.partner = this; } public static void main(String[] args) { Person one = new Person("1"); Person two = new Person("2"); Person three = new Person("3"); Person four = new Person("4"); one.setPartner(two); three.setPartner(four); one.setPartner(three); //Person two is still partner with person 1 }

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  • Generics limitation, or lack of skillz ?

    - by Two Shoes
    I want to define the following class as such: public class CollectionAttribute<E extends Collection<T>> { private String name; private E value; public CollectionAttribute(String name, E value) { this.name = name; this.value = value; } public E getValue() { return value; } public void addValue(T value) { value.add(T); } } This won't compile (cannot resolve symbol T). If I replace the class declaration with the following: public class CollectionAttribute<E extends Collection<?>> Then I can't reference the parametrized type of the collection. Am I missing something or have I reached a limitation with generics in Java ?

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  • Java Scanner class reading strings

    - by Max
    I've created a scanner class to read through the text file and get the value what I'm after. Let's assume that I have a text file contains 1 : Fnjiei : ID 7868860 : Age 18 2 : Oipuiieerb : ID 334134 : Age 39 3 : Enekaree : ID 6106274 : Age 31 I'm trying to get a name and id number and age, but everytime I try to run my code it gives me an exception. Here's my code. Any suggestion from java gurus?:) public void readFile(String fileName)throws IOException{ Scanner input = null; input = new Scanner(new BufferedReader(new FileReader(fileName))); try { while (input.hasNextLine()){ int howMany = 3; System.out.println(howMany); String userInput = input.nextLine(); String name = ""; String idS = ""; String ageS = ""; int id; int age; int count=0; for (int j = 0; j <= howMany; j++){ for (int i=0; i < userInput.length(); i++){ if(count < 2){ // for name if(Character.isLetter(userInput.charAt(i))){ name+=userInput.charAt(i); // store the name }else if(userInput.charAt(i)==':'){ count++; i++; } }else if(count == 2){ // for id if(Character.isDigit(userInput.charAt(i))){ idS+=userInput.charAt(i); // store the id } else if(userInput.charAt(i)==':'){ count++; i++; } }else if(count == 3){ // for age if(Character.isDigit(userInput.charAt(i))){ ageS+=userInput.charAt(i); // store the age } } id = Integer.parseInt(idS); // convert id to integer age = Integer.parseInt(ageS); // convert age to integer Fighters newFighters = new Fighters(id, name, age); fighterList.add(newFighters); } userInput = input.nextLine(); } } }finally{ if (input != null){ input.close(); } } } My appology if my mere code begs to be changed.

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  • Help with a query

    - by stackoverflowuser
    Hi Based on the following table ID Effort Name ------------------------- 1 1 A 2 1 A 3 8 A 4 10 B 5 4 B 6 1 B 7 10 C 8 3 C 9 30 C I want to check if the total effort against a name is less than 40 then add a row with effort = 40 - (Total Effort) for the name. The ID of the new row can be anything. If the total effort is greater than 40 then trucate the data for one of the rows to make it 40. So after applying the logic above table will be ID Effort Name ------------------------- 1 1 A 2 1 A 3 8 A 10 30 A 4 10 B 5 4 B 6 1 B 11 25 B 7 10 C 8 3 C 9 27 C I was thinking of opening a cursor, keeping a counter of the total effort, and based on the logic insert existing and new rows in another temporary table. I am not sure if this is an efficient way to deal with this. I would like to learn if there is a better way.

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  • PHP 5 functioning returning an array- interaction without assignment?

    - by Lee
    I'm wondering if this kind of thing will ever be possible in PHP (and whether it already is and I'm just missing something...) <?php function test() { return array( 'id'=>10, 'name'=>'John' ); } echo 'Your name is: '.test()['name']; ?> I'd really like to be able to use returned arrays directly instead of first assigning them to a var... possible?

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  • How optimize queries with fully qualified names in t-sql?

    - by tomaszs
    Whe I call: select * from Database.dbo.Table where NAME = 'cat' It takes: 200 ms And when I change database to Database in Management Studio and call it without fully qualified name it's much faster: select * from Table where NAME = 'cat' It takes: 17 ms Is there any way to make fully qualified queries faster without changing database?

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  • Very difficult SQL query

    - by db666
    For the following table definitions: Name Null? Type Comments ------------------------------- -------- ---- ------------------------------------ ENUM NOT NULL NUMBER(4) ENUM should not exceed a length of 4. ENAME CHAR(15) ADDRESS CHAR(25) ADDRESS should not exceed 25 characters. SALARY NUMBER(5) OFFICE CHAR(4) DNUM NOT NULL NUMBER(4) Department which this employee belongs to department Name Null? Type Comments ------------------------------- -------- ---- ------------------------------------- DNUM NOT NULL NUMBER(4) DMGR NOT NULL NUMBER(4) Department manager DNAME NOT NULL CHAR(15) project Name Null? Type Comments ------------------------------- -------- ---- ------------------------------------- PNUM NOT NULL NUMBER(4) PMGR NOT NULL NUMBER(4) Project manager PTITLE NOT NULL CHAR(15) emp_proj Name Null? Type ------------------------------- -------- ---- PNUM NOT NULL NUMBER(4) ENUM NOT NULL NUMBER(4) I have to write SQL query which will find the names of employees who do not share an office but work on the same project, and have different salaries... I've spent last three days trying to figure out something, but no idea as far. I will appreciate any advice.

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  • cant get values printed in to a file

    - by user1371896
    Iam trying to pass the value stored in the variable fieldCSV to file data.csv...Ive used javascript and php to do this.. I have triggered an ajax request when a value is stored in to the variable fieldCSV, bt this is nt working as the file that gets downloaded prints the php error inside it instead of csv.. $.ajax({ type: "POST", url: "/test/fileDownload.php", data: { name: fieldCSV}, }); <?php $name = $_POST["name"]; header('Content-Type: text/csv; charset=utf-8'); header('Content-Disposition: attachment; filename=data.csv'); $output = fopen('php://output', 'w'); fputcsv($output, $name); ?> What am I doing wrong?

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