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  • How to make the value in submit button ,transparent?

    - by aquero
    Hi, I have a submit button in a form and i use a css class which sets a background image as the submit button. I need to give a value to this submit button, but i dont want it to be displayed to the user. If i set the css color property to transparent it works fine in my firefox 3.6. But the value gets displayed in ie 6 and 7. How can i solve this problem?

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  • Relatively simple task: How do I pass back the selected item from one activity to another?

    - by Brian D
    I have two activities: one displays an image and a button, the other displays a photo gallery. I want to be able to select any of the images in the gallery and then display them on the first activity in place of the default image. public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.gallery); Gallery g = (Gallery) findViewById(R.id.gallery); g.setAdapter(new ImageAdapter(this)); g.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView parent, View v, int position, long id) { Toast.makeText(PhotoGallery.this, "Position: " + id, Toast.LENGTH_SHORT).show(); Intent intent=new Intent(); intent.putExtra("PictureID", position); setResult(RESULT_OK, intent); finish(); } }); } Am I even close here? I'm not quite sure what to do with any string or int I would attach to the Intent -- can I attach the object itself? I'd much rather pass back at minimum the string name of the resource (image), but the only thing I can seem to figure out right now is how to pass back the position of the picture ... not a great solution. I can clarify more if necessary -- thanks.

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  • How to show back and forward button on popup opened thru window.open or self.open?

    - by M Sach
    i am opening the popup window with below code snippet self.open('myJSPPage','ServicePopUp','height=600,width=800,resizable=yes,scrollbars=yes,toolbar=yes,menubar=yes,location=yes'); Once the window opens i do not see any back button or forward button on popup. I just see title then address bar under it and then myJSPPage under address bar. I am not getting how to show back and forward button on popup?

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  • Problems with starting an activity in onStart

    - by Fizz
    Hello everyone. I'm trying to start a floating activity from onStart to retrieve some info from the user right when the initial activity begins. I have the following: @Override public void onStart(){ super.onStart(); callProfileDialog(); } And callProfileDialog() is just: private void callProfileDialog(){ Intent i = new Intent(this, com.utility.ProfileDialog.class); startActivityForResult(i, PROFDIALOG); } ProfileDialog.class returns a String from an input box. If the result returned is RESULT_CANCELED then I restart the activity. The problem I'm having is that when the program starts, the screen is just black. If I hit the Back button a RESULT_CANCELED is returned then the initial activity shows as well as the floating activity (since it recalled itself when it got a RESULT_CANCELED). Why can't I get the activities show by calling ProfileDialog.class from onStart()? I got the same result when I called it at the end of onCreate() which is way I switch over to use onStart(). Thanks for the help.

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  • Unlock device, display a text, then lock again

    - by Waza_Be
    For the need of my application, I need to display a message on the screen even if the lockscreen is enabled, then wait 3 seconds, than I have to lock again the phone as I don't want it to make unwanted phone calls in your pockets. First part is easy: if (PreferenceManager.getDefaultSharedPreferences( getBaseContext()).getBoolean("wake", false)) { KeyguardManager kgm = (KeyguardManager) getSystemService(Context.KEYGUARD_SERVICE); boolean isKeyguardUp = kgm.inKeyguardRestrictedInputMode(); WakeLocker.acquire(ProtoBenService.this); Intent myIntent = new Intent(ProtoBenService.this,LockActivity.class); myIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK); if (isKeyguardUp) { ProtoBenService.this.startActivity(myIntent); } else Toast.makeText(ProtoBenService.this.getBaseContext(), intention, Toast.LENGTH_LONG).show(); WakeLocker.release(); } With this class: public abstract class WakeLocker { private static PowerManager.WakeLock wakeLock; public static void acquire(Context ctx) { if (wakeLock != null) wakeLock.release(); PowerManager pm = (PowerManager) ctx.getSystemService(Context.POWER_SERVICE); wakeLock = pm.newWakeLock(PowerManager.FULL_WAKE_LOCK | PowerManager.ACQUIRE_CAUSES_WAKEUP | PowerManager.ON_AFTER_RELEASE, "CobeIm"); wakeLock.acquire(); } public static void release() { if (wakeLock != null) wakeLock.release(); wakeLock = null; } } And the Activity: public class LockActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); Window window = getWindow(); window.addFlags(WindowManager.LayoutParams.FLAG_DISMISS_KEYGUARD); window.addFlags(WindowManager.LayoutParams.FLAG_TURN_SCREEN_ON); window.addFlags(WindowManager.LayoutParams.FLAG_KEEP_SCREEN_ON); TextView tv = new TextView(this); tv.setText("This is working!"); tv.setTextSize(45); setContentView(tv); Runnable mRunnable; Handler mHandler = new Handler(); mRunnable = new Runnable() { @Override public void run() { LockActivity.this.finish(); } }; mHandler.postDelayed(mRunnable, 3 * 1000); } } So, this is nice, the phone can display my text! The only problem comes when I want to lock again the phone, it seems that locking the phone is protected by the system... Programmatically turning off the screen and locking the phone how to lock the android programatically I think that my users won't understand the Device Admin and won't be able to activate it. Is there any workaround to lock the screen without the Device Admin stuff?

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  • HTML / CSS How to add image icon to input type="button" ?

    - by Brett
    Hi, I'm using this css, but it puts an image in the center. Any way to left or right align an icon using an input type="button" html button, so that the text and the image fit on the button nicely? background: url('/common/assets/images/icons/16x16/add.png');background-position:center;background-repeat:no-repeat;

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  • CSS/Jquery How can I display a div directly under button?

    - by user342391
    I have a button that when hovered displays a div. How can I postion this div to appear directly under the button when displayed??? <script type="text/javascript"> $(document).ready(function(){ $(".plans").hover(function() { $("#planssubnav").show("slow"); }, function(){ $("#planssubnav").hide("slow"); }); }); </script> <a href="/plans" style="font-size:14px;" class="plans fg-button fg-button-icon-right ui-state-default ui-corner-all"><span class="ui-icon ui-icon-circle-triangle-s"></span>Plans</a> <div id="planssubnav" style="display:none"> <h1> content</h1> </div>

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  • Can I create an activity for a particular task without that task coming to the foreground?

    - by Neil Traft
    Here's my use case: The app starts at a login screen. You enter your credentials and hit the "Login" button. Then a progress dialog appears and you wait for some stuff to download. Once the stuff has downloaded, you are taken to a new activity. Exactly which activity you are taken to depends on the server response. Here's my problem: If you go HOME during this login/download process, at some point in the near future your download will complete and will invoke startActivity(). So then the new activity will be pushed to the foreground, rudely interrupting the user. I can't start the activity before I start the download, because, as I mentioned earlier, the activity I start depends on the result of the download. I would obviously not like to interrupt the user like this. One way to solve this is to refrain from calling startActivity() until the user returns to the app. I can do this by keeping track of the LoginActivity's onStop() and onRestart(). But I'm wondering, is there any way to create the activity while it is in the background? That way the user returns to the app and he is ready to go... otherwise he would have to wait for the new activity to be created (which could take some time because the new activity also has to download and display some data). Update: Guess what? I LIED! I could have sworn that starting this activity was causing it to come to the foreground, but I went back to test it again and the problem has magically disappeared. I tested in both 1.6 and 2.0.1 and both OSes were smart enough not to bring a backgrounded task to the front.

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  • How can I play video by touching the button on the video image of the video in tableviewcell ?

    - by srikanth rongali
    I have a table view in which if each cell is touched video plays. Each cell have image of the video cell.imageView.image. And on the image I have a button (UIButton) with play symbol. If I touch the play button the corresponding video should be played same like the when cell is touched. I have a selector for the play button. How can I relate the corresponding cell to the play button. Thank You.

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  • Adding Information in SQLite

    - by Cam
    Hi All, I am having trouble with my Android App when adding information into SQLite. I am relatively new to Java/SQLite and though I have followed a lot of tutorials on SQLite and have been able to get the example code to run I am unable to get tables to be created and data to import when running my own app. I have included my code in two Java files Questions (Main Program) and QuestionData (helper class represents the database). Questions.java: public class Questions extends Activity { private QuestionData questions; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.quiztest); questions = new QuestionData(this); try { Cursor cursor = getQuestions(); showQuestions(cursor); } finally { questions.close(); } } private Cursor getQuestions() { //Select Query String loadQuestions = "SELECT * FROM questionlist"; SQLiteDatabase db = questions.getReadableDatabase(); Cursor cursor = db.rawQuery(loadQuestions, null); startManagingCursor(cursor); return cursor; } private void showQuestions(Cursor cursor) { // Collect String Values from Query and Display them this part of the code is wokring fine when there is data present. QuestionData.java public class QuestionData extends SQLiteOpenHelper { private static final String DATABASE_NAME = "TriviaQuiz.db" ; private static final int DATABASE_VERSION = 2; public QuestionData(Context ctx) { super(ctx, DATABASE_NAME, null, DATABASE_VERSION); } @Override public void onCreate(SQLiteDatabase db) { db.execSQL("CREATE TABLE questionlist (_id INTEGER PRIMARY KEY AUTOINCREMENT, QID TEXT, QQuestion TEXT, QAnswer TEXT, QOption1 TEXT, QOption2 TEXT, QOption3 TEXT, QCategoryTagLvl1 TEXT, QCategoryTagLvl2 TEXT, QOptionalTag1 TEXT, QOptionalTag2 TEXT, QOptionalTag3 TEXT, QOptionalTag4 TEXT, QOptionalTag5 TEXT, QTimePeriod TEXT, QDifficultyRating TEXT, QGenderBias TEXT, QAgeBias TEXT, QRegion TEXT, QWikiLink TEXT, QValidationLink1 TEXT, QValidationLink2 TEXT, QHint TEXT, QLastValidation TEXT, QNotes TEXT, QMultimediaType TEXT, QMultimediaLink TEXT, QLastAsked TEXT);"); db.execSQL("INSERT INTO questionlist (_id, QID, QQuestion, QAnswer, QOption1, QOption2, QOption3, QCategoryTagLvl1, QCategoryTagLvl2, QOptionalTag1, QOptionalTag2, QOptionalTag3, QOptionalTag4, QOptionalTag5, QTimePeriod, QDifficultyRating, QGenderBias, QAgeBias, QRegion, QWikiLink, QValidationLink1, QValidationLink2, QHint, QLastValidation, QNotes, QMultimediaType, QMultimediaLink, QLastAsked)"+ "VALUES (null,'Q00001','Example','Ans1','Q1','Q2','Q3','Q4','','','','','','','','','','','','','','','','','','','','')"); } @Override public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) { db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME); onCreate(db); } } Any suggestions at all would be great. I have tried debugging which suggests that the database does not exist. Thanks in advance for your assistance.

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  • File sorting, Comparison method violates its general contract

    - by user2677383
    My file sorting comparator sometimes invoke java.lang.IllegalArgumentException in android app. I cannot figure out the reason. could you explain that? here is my code block: Comparator cc = new Comparator<File>() { @Override public int compare(File f1, File f2) { if (f1.isDirectory() && !f2.isDirectory()) { return 1; } if (f2.isDirectory() && !f1.isDirectory()) { return -1; } if ((f1.isFile() && f2.isFile()) || (f1.isDirectory() && f2.isDirectory())) { if (sort == 1) { return Util.compareFileName(f2.getName(), f1.getName()); } else if (sort == 2) { return (int) (f1.lastModified() - f2.lastModified()); } else if (sort == 3) { return (int) (f2.lastModified() - f1.lastModified()); } else if (sort == 4) { return (int) (f1.length() - f2.length()); } else if (sort == 5) { return (int) (f2.length() - f1.length()); } else return Util.compareFileName(f1.getName(), f2.getName()); } return f1.compareTo(f2); } }; Util.compareFileName is as followings: public static int compareFileName(String s1, String s2) { int thisMarker = 0; int thatMarker = 0; int s1Length = s1.length(); int s2Length = s2.length(); while (thisMarker < s1Length && thatMarker < s2Length) { String thisChunk = getChunk(s1, s1Length, thisMarker); thisMarker += thisChunk.length(); String thatChunk = getChunk(s2, s2Length, thatMarker); thatMarker += thatChunk.length(); // If both chunks contain numeric characters, sort them numerically int result = 0; if (isDigit(thisChunk.charAt(0)) && isDigit(thatChunk.charAt(0))) { // Simple chunk comparison by length. int thisChunkLength = thisChunk.length(); result = thisChunkLength - thatChunk.length(); // If equal, the first different number counts if (result == 0) { for (int i = 0; i < thisChunkLength; i++) { result = thisChunk.charAt(i) - thatChunk.charAt(i); if (result != 0) { return result; } } } } else { result = thisChunk.compareTo(thatChunk); } if (result != 0) return result; } return s1Length - s2Length; }

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  • OutOfMemoryError loading Bitmap via DefaultHttpClient

    - by Goddchen
    i have a simple problem: Although i'm using sampleSize properly, my code doesn't even reach the BitmapFactorycode, since DefaultHttpClient is already throwing the exception. Here is my code: DefaultHttpClient client = new DefaultHttpClient(); HttpGet request = new HttpGet(mSongInfo.imageLarge); HttpResponse response = client.execute(request); int sampleSize = 1; while (response.getEntity().getContentLength() / sampleSize / sampleSize > 100 * 1024) { sampleSize *= 2; } BitmapFactory.Options options = new BitmapFactory.Options(); options.inSampleSize = sampleSize; final Bitmap bitmap = BitmapFactory.decodeStream(response .getEntity().getContent(), null, options); And here is the exception: 0 java.lang.OutOfMemoryError: (Heap Size=11463KB, Allocated=7623KB, Bitmap Size=9382KB) 1 at org.apache.http.util.ByteArrayBuffer.<init>(ByteArrayBuffer.java:53) 2 at org.apache.http.impl.io.AbstractSessionInputBuffer.init(AbstractSessionInputBuffer.java:82) 3 at org.apache.http.impl.io.SocketInputBuffer.<init>(SocketInputBuffer.java:98) 4 at org.apache.http.impl.SocketHttpClientConnection.createSessionInputBuffer(SocketHttpClientConnection.java:83) 5 at org.apache.http.impl.conn.DefaultClientConnection.createSessionInputBuffer(DefaultClientConnection.java:170) 6 at org.apache.http.impl.SocketHttpClientConnection.bind(SocketHttpClientConnection.java:106) 7 at org.apache.http.impl.conn.DefaultClientConnection.openCompleted(DefaultClientConnection.java:129) 8 at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:173) 9 at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164) 10 at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119) 11 at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:359) 12 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555) 13 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487) 14 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465) 15 at de.goddchen.android.easysongfinder.fragments.SongFragment$1.run(SongFragment.java:79) 16 at java.lang.Thread.run(Thread.java:1027) As you can see, the code doesn't even reach the part where i check the size (Content-Length) of the image and calculate a proper sample size. I wasn't aware that simply calling DefaultHttpClient.execute(...) will already load the complete content into the memory. Am i doing something wrong? What is the right way to first retrieve the content length and then start reading the content from an InputStream? EDIT To avoid common answers that show how to load images from a URL: i already know how to do that, i have also posted the code above, so why do you keep referencing tutorials on that? I explicitly was very clear about the problem: Why is HttpClient.execute(...)already fetching the whole content and storing it in memory instead of providing a proper ÌnputStreamto me? Please don't post any beginner tutorials on how to load aBitmap`from a URL...

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  • JQuery remove() not working with a two word id

    - by Programer
    I have a button <button onclick="takedown()"> take down </button> that creates a H1 and button with the id of the text in my text field and h1 at the end for the h1 and button at the end for the button the button has a onclick onclick="delete()". This is that function function takedown(){ note = document.getElementById("noteinput").value; idh1 = note + "h1"; idbutton = note + "button"; idcenter = note + "center"; $('<center id="' + idcenter + '"> <h1 id="' + idh1 + '">' + note + '</h1> <button id="'+ idbutton +'" onclick="deletenote()"> Delete </button> </center>').appendTo("body"); } For the delete function the remove() works only if the id of the button and the h1 is one word. function deletenote(){ // First setting var idbuttondelete = event.target.id; var idh1delete = idbuttondelete.replace("button", "h1"); // Removing the button, h1,center $('#' + idbuttondelete).remove(); $('#' + idh1delete).remove(); } Does anybody know whats wrong or how to use JQuery to delete something if it has a two word id.

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  • How to give the appearance of a button with a <div>?

    - by user246114
    Hi, I'm looking at the buttons used on twitter's home page, specifically the big orange 'signup' button. I see it is defined like this: <p id="signup-btn"> <a id="signup_submit" href="/signup"> <span>Sign Up</span> </a> </p> are they just using css to give the orange button appearance (which may just be a jpg), and also using css to specify the roll-over appearance (another jpg), and finally a third state for mouse-click (another jpg) to give the impression of a real clickable button? If that's how it works, what should I look for to do the same thing? In my case I just want to make a button I guess, like: <div class='mybutton'>Hello!</div> .mybutton { bgcolor: red; bgcolor-mouseover: yellow; bgcolor-mousedown: green; } yeah something like that would be great, Thanks

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  • This should be real easy. How to find a button through its Value (Jquery Selector)

    - by Raja
    I have this HTML: <div id='grid'> <input type="button" value="edit"/> <input type='button' value='update'/> </div> How to I attach a click event only to Update button. I know I could add a class to it or specity an id but both are not possible since it is in gridview. I tried this: $("input:button[@value='update']").click(function(){alert('test');}); but it displays an alert for both buttons. I know I must be doing something silly. Any help is much appreciated. Thanks Kobi for helping me out. Given below is the right answer. $("input[value='update']").click(function(){alert('test');});

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  • Why the actionscript 3.0 snippet below failed to import Button and TextInput?

    - by user198729
    package { import fl.controls.Button; import fl.controls.TextInput; public class MinRecord extends Sprite { private var recordBtn:Button; private var stopBtn:Button; private var textInput:TextInput; ... When I run it reports: Type was not found or was not a compile-time constant: Button. Type was not found or was not a compile-time constant: TextInput. Can someone point out what's wrong here?

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  • AudioTrack lag: obtainBuffer timed out

    - by BTR
    I'm playing WAVs on my Android phone by loading the file and feeding the bytes into AudioTrack.write() via the FileInputStream BufferedInputStream DataInputStream method. The audio plays fine and when it is, I can easily adjust sample rate, volume, etc on the fly with nice performance. However, it's taking about two full seconds for a track to start playing. I know AudioTrack has an inescapable delay, but this is ridiculous. Every time I play a track, I get this: 03-13 14:55:57.100: WARN/AudioTrack(3454): obtainBuffer timed out (is the CPU pegged?) 0x2e9348 user=00000960, server=00000000 03-13 14:55:57.340: WARN/AudioFlinger(72): write blocked for 233 msecs, 9 delayed writes, thread 0xba28 I've noticed that the delayed write count increases by one every time I play a track -- even across multiple sessions -- from the time the phone has been turned on. The block time is always 230 - 240ms, which makes sense considering a minimum buffer size of 9600 on this device (9600 / 44100). I've seen this message in countless searches on the Internet, but it usually seems to be related to not playing audio at all or skipping audio. In my case, it's just a delayed start. I'm running all my code in a high priority thread. Here's a truncated-yet-functional version of what I'm doing. This is the thread callback in my playback class. Again, this works (only playing 16-bit, 44.1kHz, stereo files right now), it just takes forever to start and has that obtainBuffer/delayed write message every time. public void run() { // Load file FileInputStream mFileInputStream; try { // mFile is instance of custom file class -- this is correct, // so don't sweat this line mFileInputStream = new FileInputStream(mFile.path()); } catch (FileNotFoundException e) {} BufferedInputStream mBufferedInputStream = new BufferedInputStream(mFileInputStream, mBufferLength); DataInputStream mDataInputStream = new DataInputStream(mBufferedInputStream); // Skip header try { if (mDataInputStream.available() > 44) mDataInputStream.skipBytes(44); } catch (IOException e) {} // Initialize device mAudioTrack = new AudioTrack(AudioManager.STREAM_MUSIC, ConfigManager.SAMPLE_RATE, AudioFormat.CHANNEL_CONFIGURATION_STEREO, AudioFormat.ENCODING_PCM_16BIT, ConfigManager.AUDIO_BUFFER_LENGTH, AudioTrack.MODE_STREAM); mAudioTrack.play(); // Initialize buffer byte[] mByteArray = new byte[mBufferLength]; int mBytesToWrite = 0; int mBytesWritten = 0; // Loop to keep thread running while (mRun) { // This flag is turned on when the user presses "play" while (mPlaying) { try { // Check if data is available if (mDataInputStream.available() > 0) { // Read data from file and write to audio device mBytesToWrite = mDataInputStream.read(mByteArray, 0, mBufferLength); mBytesWritten += mAudioTrack.write(mByteArray, 0, mBytesToWrite); } } catch (IOException e) { } } } } If I can get past the artificially long lag, I can easily deal with the inherit latency by starting my write at a later, predictable position (ie, skip past the minimum buffer length when I start playing a file).

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  • need help with jquery selector

    - by Gandalf StormCrow
    I have a following HTML : <ul class="someclass"> <li id="1"> <button type="button" class="grey"></button> </li> <li id="2"> <button type="button" class="grey"></button> </li> <li id="44"> <button type="button" class="grey"></button> </li> <li id="54"> <button type="button" class="grey"></button> </li> </ul> Now here is what I'm trying to accomplish with jquery : When button is clicked to find out id of parent li, here is how I tried and failed: $(".grey").live('click', function(){ alert($(this).parents("li").attr("id")); alert($(this).parents("li:first").attr("id")); }); Both give me null alerted, how can I do this ?

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  • I am trying to make a simple toggle button in javascript.

    - by CDeanMartin
    I am trying to make a simple toggle button in javascript. However, the button will only turn "OFF" and will not turn back "ON" <html><head></head> <script type="text/javascript"> function toggle(button) { if(document.getElementById("1").value=="OFF"){ document.getElementById("1").value="ON";} if(document.getElementById("1").value=="ON"){ document.getElementById("1").value="OFF";} } </script> <body> <form action=""> <input type="button" id="1" value="ON" style="color:blue" onclick="toggle(this);"> </form></body></html> I am running:HP Netbook : Ubuntu Linux 10.04 : Firefox for Ubuntu 1.0.

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  • For a user who is not logged into Facebook, the like button gives an error in the pop up window (non

    - by dealsvista
    Hi, In order to make full use the Facebook like button, I am trying to switching from iframe-based like button to js-based like button. url: http://www.dealsvista.com Everything works fine for a user who is logged into Facebook. However, for a user who is not logged into Facebook, when he clicks the like button, there is a error in the popup window. Could someone point me to the right direction? I am really new to Facebook api and have no idea what is going on? Do I have to implement connect at the same time? Do I have to set up the connect call back url in my apps?

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  • Why I see only part of the image in the button?

    - by Roman
    I add an image to the button in the following way: ImageIcon icon = new ImageIcon("images/col.jpg"); tmp = new JButton(icon); My image is a red sphere but in my button I see only read color. I assume that I see just a small part of the sphere. How can I see the whole image in the button?

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  • How much Java should I have learnt before trying Android programming?

    - by Sidney Yin
    Hi - I have been seeking beginner learning books in Android, and of course found out that I should learn Java first. So I began studying Java and now I am quite comfortable with objects, classes, inheritance, interfaces, and just moved onto Layouts in Swing as well as Swing Features. But I am starting to wonder.... do I know enough about Java now? Can I start programming Android yet? Of course I can keep going in Java, but have been itching to begin programming Android apps. Any definitive answer here about how much Java I need to know before Android? Thanks so much!

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