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  • How to take value from radio selection and pass that value into a hidden inputs value attribute?

    - by Matthew
    Hello guys, I need to know if this can be done and if so can someone push me in the right direction. Okay I have a series of radio buttons: <input type="radio" name="level_id" id="radio1" value="XXXX" class="radio1" /> <label for="radio1">choice 1</label> <input type="radio" name="level_id" id="radio2" value="XXXX" class="radio2" /> <label for="radio2">choice 2</label> <input type="radio" name="level_id" id="radio3" value="XXXX" class="radio3" /> <label for="radio3">choice 3</label> <label for="radio4">second choice1</label> <input type="radio" name="level_id" id="radio4" value="1" class="radio4" /> <label for="radio5">second choice2</label> <input type="radio" name="level_id" id="radio5" value="2" class="radio5" /> <label for="radio6">second choice3</label> <input type="radio" name="level_id" id="radio6" value="3" class="radio6" /> Now what I am looking to do is if someone selects CHOICE 1 and then selects SECOND CHOICE1 I would like to pass the value of SECOND CHOICE1 into the value of a hidden input. <input type="hidden" name="sub_source" id="sub_source" value="" /> So that when the form is ready to submit the value that gets passed would be: <input type="hidden" name="sub_source" id="sub_source" value="1" />

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  • Instantiate a form, then find it later, without showing it initially

    - by awilson53
    I am having a problem that is strange to me but hopefully is not so strange to someone else. : ) Some background: I am working on a simple IM client that allows the user to broadcast messages to multiple recipients. The goal is to create a chat form for each of the recipients containing the text of the broadcast message, then show that form only if the recipient responds to the broadcast-er. However, when the application receives a response then attempts to locate the form for that particular chat session (using Application.OpenForms) it cannot find it UNLESS I .Show at the time it is created. I would like to avoid having to show this form when it is created because this means that the user will see a flash on the screen. The form doesn't seem to really be created until I show it, but it would seem there has to be a way to do this without showing first. Can anyone assist? I can provide code snippets if needed, I didn't in this post because this feels more like a conceptual misunderstanding on my part than a bug in the code. Thanks in advance!

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  • submitting a form inside a modalbox with jquery

    - by birdy
    submitting form with jQuery works $('#testform').submit(); doesn't work $('#testform').submit(function () { alert('test1'); return true; }); This is just an exmaple but at times i'd like to do stuff before submission of the form. Like for example submit the form using $.POST Update: If I keep both then the $.POST has no value because the form still gets submitted the traditional way, without ajax... $("#testform").submit(function() { $.post('/myajaxcontroller', function(data) { $('#result').html(data); }); }); $("#testform").submit();

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  • Send <p> tags and simple HTML formatting through a form via PHP.

    - by Jonathan
    Hi, so I need the user to write a review about an article or book and send it to a DB via PHP but with some basic HTML formatting.. I mean, I have a form , when the user writes the review, the data is sent but without any kind of formatting, If the user want to write in a new line, the text is sent like plain text, I need to get also those new line breaks and simple stuff. I know how to use PHP and DB connection, I just need to know how to get those new line breakes and stuff..

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  • (Python/Pyramid) Better ways to have standard list/form editors?

    - by badcat
    I'm working on a number of Pyramid (former Pylons) projects, and often I have the need to display a list of some content (let's say user accounts, log entries or simply some other data). A user should be able to paginate through the list, click on a row and get a form where he/she can edit the contents of that row. Right now I'm always re-inventing the wheel by having Mako templates which use webhelpers for the pagination, Jquery UI for providing a dialog and I craft the editor form and AJAX requests on the client and server side by hand. As you may know, this eats up painfully much time. So what I'm wondering is: Is there a better way of providing lists, editor dialog and server/client communication about this, without having to re-invent the wheel every time? I heard Django takes off a big load of that by providing user accounts and other stuff out of the box; but in my case it's not just about user accounts, it can be any kind of data that is stored on the server-side in a SQL database, which should be able to be edited by a user. Thanks in advance!

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  • Javascript form validation only works in firefox

    - by Logic Artist
    Hello, I am relatively new to Javascript so I'm hoping this is a simple mistake. I building a generic form validation function that is called on the form's onSubmit. The function loops through all the form's child elements, looks for certain classes, and analyzes the contents of the appropriate fields. If it finds something missing or erroneous, it displays the appropriate error message div and returns false, thus preventing the form from being submitted to the php page. It works well in firefox 3.6.3, but in every other browser I've tested (Safari 4.0.4, Chrome 4.1, IE8) it seems to ignore the onSubmit and jump straight to the php processing page. HTML CODE: <form name='myForm' id='myForm' action='process_form.php' method='post' onSubmit="return validateRequired('myForm')"> <fieldset class="required radioset"> <label for='selection1'> <input type='radio' name='selection' id='selection1' value='1'/> Option 1 </label> <label for='selection2'> <input type='radio' name='selection' id='selection2' value='2'/> Option 2 </label> <label for='selection3'> <input type='radio' name='selection' id='selection3' value='3'/> Option 3 </label> <label for='selection4'> <input type='radio' name='selection' id='selection4' value='4'/> Option 4 </label> <div class='errorBox' style='visibility:hidden'> Please make a selection </div> </fieldset> <fieldset class="required checkset"> <label> Choice 1 <input type='checkbox' name='choices' id='choice1' value='1'/> </label> <label> Choice 2 <input type='checkbox' name='choices' id='choice2' value='2'/> </label> <label> Choice 3 <input type='checkbox' name='choices' id='choice3' value='3'/> </label> <label> Choice 4 <input type='checkbox' name='choices' id='choice4' value='4'/> </label> <div class='errorBox' style='visibility:hidden'> Please choose at least one </div> </fieldset> <fieldset class="required textfield" > <label for='textinput1'> Required Text: <input type='text' name='textinput1' id='textinput1' size='40'/> </label> <div class='errorBox' style='visibility:hidden'> Please enter some text </div> </fieldset> <fieldset class="required email textfield"> <label for='email'> Required Email: <input type='text' name='email' id='email' size='40'/> </label> <div class='errorBox' style='visibility:hidden'> The email address you have entered is invalid </div> </fieldset> <div> <input type='submit' value='submit'> <input type='reset' value='reset'> </div> </form> JAVASCRIPT CODE: function validateRequired(id){ var form = document.getElementById(id); var errors = 0; var returnVal = true; for(i = 0; i < form.elements.length; i++){ var elem = form.elements[i]; if(hasClass(elem,"required")){ /*RADIO BUTTON or CHECK BOX SET*/ if(hasClass(elem,"radioset") || hasClass(elem,"checkset")){ var inputs = elem.getElementsByTagName("input"); var check = false; for(j = 0; j < inputs.length; j++){ if(inputs[j].checked){ check = true; } } if(check == false){ errors += 1; showError(elem); } else { hideError(elem); } } /*TEXT FIELD*/ else if(hasClass(elem,"textfield")){ var input = elem.getElementsByTagName("input"); if(input[0].value == ""){ errors += 1; showError(elem); } else { hideError(elem); /*EMAIL ADDRESS*/ if(hasClass(elem,"email")){ if(isValidEmail(input[0].value) == false){ errors += 1; showError(elem); } else { hideError(elem); } } } } } } if(errors > 0){ returnVal = false; } else { returnVal = true; } return returnVal;} I know this is a lot of code to look at, but any help would be appreciated. Since it works fine in one browser, Im not sure how to start debugging. Thanks Andrew

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  • set an input value from jquery function

    - by user1499220
    I'm simply trying to set a value for an input but it doesn't work. Here is my jquery function : function display_form() { try { $('#start_date').val('2012/08/21'); }catch (e){ alert('error'); } window.alert( $('[name=start_date]').val() ); } This shows "undefined". Here is my form : <input id="start_date" name="start_date" type="text" size="6" /> Should I put somewhere the id of the form that I want to use? I just followed what is said in the documentation of jquery but it doesn't seem to work. Could anyone help me ?

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  • Form wont stay on top. How do I keep my excel form from hiding behind other windows after I browse

    - by ScottK
    I have a vb.net program that opens up an excel workbook and runs a macro ("Report") in that workbook when a button is clicked. //Workbook with macro and form xlWorkbook = xlApp.Workbooks.Open("W:Data\Excel Program.xls") //Macro: xlApp.Run("Report") //Macro opens form from workbook. I browse for my two .csv files //and then click a button to run code that creates my reports. //form closes, show the excel report after its created xlApp.Visible = True After I browse my first file and select it so that its location is displayed in my text box, the excel form then hides behind any open windows. I want this form to stay on top. It is after this code executes that the form will hide behind all other open windows: Private Sub btnBrowseFile1_Click() Dim fileName1 As String fileName1 = Application.GetOpenFilename("CSV file (*.csv), *.csv") If fileName1 <> "False" Then Me.txtFileName1.text = fileName1 End If End Sub EDIT: I still have no luck with this problem. When the excel macro is opened from a vb program I have this hiding issue...but only after browsing for a file. Why does the focus leave the form and go to Windows after browsing a file? Any one have any suggestions?

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  • Customizing Django Form: Required and InputId?

    - by Mark
    I'm trying to customize how my form is displayed by using a form_snippet as suggested in the docs. Here's what I've come up with so far: {% for field in form %} <tr> <th><label for="{{ field.html_name }}">{{ field.label }}:</label></th> <td> {{ field }} {% if field.help_text %}<br/><small class="help_text">{{ field.help_text }}</small>{% endif %} {{ field.errors }} </td> </tr> {% endfor %} Of course, field.html_name is not what I'm looking for. I need the id of the input field. How can I get that? Also, is there a way I can determine if the field is required, so that I can display an asterisk beside the label?

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  • Select multiple submit issue - POST is empty if not selected

    - by Dasun
    I have a multiple select as below. It allows me to select options as below. Assume that 3 sports are selected. When the items are select as shown above form submit is successful. But unfortunately if the sports are not selected like below when the form is submitted post is empty. Select box <select style="width: 100px; height: 80px;" class="input" id="selected_sport_list" name="selected_sport_list[]" multiple=""> <option value="2">sport 2</option> <option value="3">sport 3</option> <option value="5">sport test x</option></select> How can I make sure that when the form is submitted particular items are selected? Is it possible to use jquery to fix this ? or how? Thanks

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  • jQuery: serializing array returns empty string

    - by John Smith
    I did not forget to add name attributes as is a common problem and yet my serialized form is returning an empty string. What am I doing wrong? HTML/javascript: <head> <script src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script> <script> $( document ).ready( function() { $('#word_form').submit(function(e) { e.preventDefault(); console.log($(this).serialize()); //returns an empty string }); }); </script> </head> <body> <div id="wrapper"> <form name="word_form" id="word_form" method="POST"> <input type="image" name="thumbsUp" id="thumb1" value="1" src="http://upload.wikimedia.org/wikipedia/commons/8/87/Symbol_thumbs_up.svg" style="width:50px;height:50px;"> <input type="image" name="thumbsDown" id="thumb2" value="2" src="http://upload.wikimedia.org/wikipedia/commons/8/84/Symbol_thumbs_down.svg" style="width:50px;height:50px;"> </form> </div> </body> Thanks!

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  • Make form redirect users after posting

    - by Liso22
    I need to change a form so that instead of reloading the page after submitting it, it redirects the user to another page, this is the form: <form class="questionform" name="questionform-0" id="questionform-0"> <textarea class="question-box" cols="12" rows="5" id="question-box-' . $questionformid . '" name="title" type="text" maxlength="200" size="28"></textarea> <input type="text" class="ubicacion" value="" name="question"> <input type="button" name="ask" value="Publicar" onclick="askquestion('questionform-0'); window.location.reload(true);"> I want to remove the window.location.reload and change it for a redirect that sends users to the page their comment will appear. Which is: www.chusmix.com/s?= (the content of the second field) The problem is that the content of the second field is part of the url I want to redirect, it's not simply always the same URL. So I have no idea how to do it. How do I do it? Anyway thanks for any info or whatever that points me on the right direction. Thanks

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  • Set hidden form field values with JavaScript but request still empty

    - by tigerstyle
    HI volks, I try to set some hidden form field values with an onclick event. Ok, after I did something like this: document.getElementById('hidden_field').value = 123; I can output the value with the firebug console by entering this: alert(document.getElementById('hidden_field').value); So the values are definitely set. But now when I submit the form, the hidden field values are still empty. Do you have any idea whats going wrong? Thx for your answers.

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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • Persisting object changes from child form to parent form based on button press.

    - by Shyran
    I have created a form that is used for both adding and editing a custom object. Which mode the form takes is provided by an enum value passed from the calling code. I also pass in an object of the custom type. All of my controls at data bound to the specific properties of the custom object. When the form is in Add mode, this works great as when the controls are updated with data, the underlying object is as well. However, in Edit mode, I keep two variables of the custom object supplied by the calling code, the original, and a temporary one made through deep copying. The controls are then bound to the temporary copy, this makes it easy to discard the changes if the user clicks the Cancel button. What I want to know is how to persist those changes back to the original object if the user clicks the OK button, since there is now a disconnect because of the deep copying. I am trying to avoid implementing a internal property on the Add/Edit form if I can. Below is an example of my code: public AddEditCustomerDialog(Customer customer, DialogMode mode) { InitializeComponent(); InitializeCustomer(customer, mode); } private void InitializeCustomer(Customer customer, DialogMode mode) { this.customer = customer; if (mode == DialogMode.Edit) { this.Text = "Edit Customer"; this.tempCustomer = ObjectCopyHelper.DeepCopy(this.customer); this.customerListBindingSource.DataSource = this.tempCustomer; this.phoneListBindingSource.DataSource = this.tempCustomer.PhoneList; } else { this.customerListBindingSource.DataSource = this.customer; this.phoneListBindingSource.DataSource = this.customer.PhoneList; } }

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  • Does Spring MVC form submit data bind children objects automagically?

    - by predhme
    I have a data model that is something like this: public class Report { // report owner private User user; ... typical getter setter ... } public class User { ... omitted for clarity } What happens is when a report is created, the current user is set to the report user object. When the report is edited, the spring controller handling the POST request is receiving a report where the user object is null. Here is what my controller looks like: @Controller @RequestMapping("/report") public class ReportController { @RequestMapping(value = "/edit/{id}", method = RequestMethod.GET) public String editReport(@PathVariable Long id, Model model) { Report r = backend.getReport(id); // fully loads object model.addAttribute("report", report); return "report/edit"; } @RequestMapping(value = "/edit/{id}", method = RequestMethod.POST) public String process(@ModelAttribute("report") Report r) { backend.save(r); return "redirect:/report/show" + r.getId(); } } I ran things throw the debugger and it looks like in the editReport method the model object is storing the fully loaded report object (I can see the user inside the report). On the form jsp I can do the following: ${report.user.username} and the correct result is rendered. However, when I look at the debugger in the process method, the passed in Report r has a null user. I don't need to do any special data binding to ensure that information is retained do I?

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  • How to set title and class in the HTML for the options of a ModelChoiceField?

    - by celopes
    I have a model class MyModel(models.Model): name = models.CharField(max_length=80, unique=True) parent = models.ForeignKey('self', null=True, blank=True) I want to render a ModelChoiceField for that model that looks like: <select name="mymodel" id="id_mymodel"> <option value="1" title="Value 1" class="">Value 1</option> <option value="2" title="Value 2" class="Value 1">Value 2</option> </select> The differences between this output and the default output for a ModelChoiceField are the title and class elements in the OPTION tag. They don't exist in ModelChoiceField's default output. For my purposes: The title element is supposed to be the Option Name. The class element is supposed to be self.parent.name. (this is my problem) So, in the HTML snippet above, Value 1 has no parent and Value 2 has a parent of Value 1. What is the best mechanism to change ModelChoiceField's default HTML output? EDIT: I understand how to create a new Widget for rendering HTML. The problem is how to render a value from the underlying model in each of the options.

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  • How to get the right row in a sorted DataView?

    - by ZeissS
    Hi, I have a DataGrid containing a small table. Until now, I had a double click handler on this grid which iterated over all rows to find the selected one: DataTable table = (DataTable)this.dataGrid.DataSource; int selectedRow = -1; for (int i=0; i<table.Rows.Count; i++) if (this.dataGrid.IsSelected(i)) selectedRow = i; break; } if ( selectedRow != -1 ) { DataRow row = table.Rows[selectedRow]; // More code ... } Problem: When the user clicks on a column header and sort the table, table.Rows does not return the right rows. It still contains the unsorted rows. How can I get the right column?

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  • Javascript - Text Input Attributes

    - by bobrusha
    I need to create a form element <input disabled type="text" value="smth" /> which is disabled by default. It enables when onmouseover occures. onmouseover="this.disabled=false;" And is disabled by onmouseout onmouseout="this.disabled=true;" What I need is to check the following. If the <input> is focused then it shouldn't be disabled. And if the form element loses focus it disables. Please help me to complete the events. <input disabled type="text" value="smth" onmouseover="this.disabled=false;" onfocus="???" onblur="???" onmouseout="if(???){this.disabled=true;}" />

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  • Pass PHP variables without being seen when working with a database generated list

    - by Wilcoholic
    Looking for any help regarding the problem. Here's the deal: I have a database that has a teams table and it contains team_id. On one of my pages, I generate a list of links that contain the team_id of the creator in their get URL. I need the team_id on the next page but can't figure out how to pass it through any other way. Using a form and POST isn't an option because this method would only pass through the last links data on the list. Storing in a session isn't an option either because there is no way to discretely pass the the variables I need to a function to set the session variables. I have tried and it can pretty easily be viewed from viewing the source code. So here's some sample code to see exactly what I'm dealing with. <? if(mysql_num_rows($result2)>0){ ?> <a class="fltrt btn btn-danger btn-small" onclick="test()" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=cancel">Cancel Match</a> <?}else{?> <a class="fltrt btn btn-success btn-small" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=accept">Accept Match</a> <?} ?> The code above is generated multiple times on a page via a while loop that was excluded. I want to pass the match_id and team_id variables without being seen anywhere. If I made this a form, it wouldn't pass the correct variables unless there is only one result at the time (not likely). I'm sure there has to be an easy method that is eluding me, so please share thoughts on how to solve this. I feel as though I am not explaining it well enough, but it's not really easy to explain. I basically want something that works like GET but acts like POST and can be hidden from people viewing source code or link locations. Thanks

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  • Visual Basic: Newbie questions.

    - by Omega
    Hello there. I am starting to learn visual basic. So far, it is quite simple and easy to use. I am liking it! Anyway, I want to make applications a little bit more complex. So far I have done very silly things. I would appreciate if you could help me with these: How do I open a new window (form)? Maybe I click a button on my main form and another form pops up. How do I "deactivate" the main form while the new form is running? (if I try to click the main form, an error sound plays) So my second form has a text field and a "OK" button. If I click it, the second form closes activating the main form again. I want to "pass" the text in the text field from the second form to the first one. How do I do that? Thank you, I am enjoying this new programming environment (didn't use Visual Studio much before)

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  • How do I submit a form from another page?

    - by Tommy
    I have a two page site. Each page contains a header with "tabs" at the top, to navigate between page 1 and 2. When a tab is selected, I need the selected page to re-POST to the server, to quickly refresh before it is displayed. I have a form on each page that allows a manual refresh from that page but need to submit that form from the other page. For example, page 2 is displayed. The tab for page 1 is selected (which is on page 2) It should then submit the refresh form on page 1. Any help is appreciated. (Using jQuery, js, html and CSS)

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  • Best approach to store username & password

    - by Zerotoinfinite
    Hi All, I have created a site in asp.net 3.5 & my query is this that I have only 2 or 3 login Id (user) who can login to my website, then what would be the better way to save the login details. What I know I am writing below, please let me know which would be the correct approach to achieve this also if their is any nice approach to get this done: 1: to save username and password in web.config file 2: to create a text file in directory and modify it 3: To use form authentication Please let me know the approach I can use to solve it. thanks in advance P.S. : I have to create only 2-3 users, or in future may be 1-2 more, that's it.

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