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  • Efficient job progress update in web application

    - by Endru6
    Hi, Creating a web application (Django in my case, but I think the question is more general) that is administrating a cluster of workers doing queued jobs, there is a need to track each jobs progress. When I've done it using database UPDATE (PostgreSQL in this case), it severely hits the database performance, because each UPDATE creates a new row in a table, and in my case only vacuuming DB removes obsolete rows. Having 30 jobs running and reporting progress every 1 minute DB may require vacuuming (and it means huge slow downs on a front end side for all the employees working with the system) every 10 days. Because the progress information isn't critical, ie. it doesn't have to be persistent, how would you do the progress updates from jobs without using an overhead database implies? There are 30 worker servers, each doing 1 or 2 jobs simultaneously, 1 front end server which serves a web application to users, and 1 database server.

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  • A Tkinter StringVar() Question

    - by Graham
    I would like to create a StringVar() that looks something like this: someText = "The Spanish Inquisition" #Here's a normal variable whose value I will change eventually TkEquivalent = StringVar() #and here's the StringVar() TkEquivalent.set(string(someText)) #and here I set it equal to the normal variable. When someText changes, this variable will too... HOWEVER: TkEquivalent.set("Nobody Expects " + string(someText)) If I do this, the StringVar() will no longer automatically update! How can I include that static text and still have the StringVar() update to reflect changes made to someText? Thanks for your help.

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  • Django - count date between

    - by DJPy
    I have many record in my database wich contains datetime field (e.g. 2010-05-23 17:45:57). I want to count all records between e.g. 15:00 and 15:59 (it all can by from other day, month or year). How can I do this?

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  • Pagination of Date-Based Generic Views in Django

    - by Apreche
    I have a pretty simple question. I want to make some date-based generic views on a Django site, but I also want to paginate them. According to the documentation the object_list view has page and paginate_by arguments, but the archive_month view does not. What's the "right" way to do it?

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  • Number guessing game (3+- guessed result)

    - by Nick Waring
    I've been assigned a task to create a game that generates 4 digits and the user has to guess the digits one at a time to get the correct result. If the number is correct a Y is displayed and if not, a N. This was easy, now the next step was to implement another two responses. If the answer is too high, a H is displayed and too low, an N. Again, was easy - now the third is to use the same design as game 2 but if the number is 3 higher than a H is displayed and same if it's 3 lower than a L is displayed - otherwise an X is displayed. I can't figure out how to do this. Here's my test code for game 2 for just one of the digits - any help is appreciated. (5 was used just for a test.) def guess(): x = 5 g= int(input("Guess the number: ")) if g == x: print("Y") elif g < x: print("L") else: print("H")

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  • Python2.7: How can I speed up this bit of code (loop/lists/tuple optimization)?

    - by user89
    I repeat the following idiom again and again. I read from a large file (sometimes, up to 1.2 million records!) and store the output into an SQLite databse. Putting stuff into the SQLite DB seems to be fairly fast. def readerFunction(recordSize, recordFormat, connection, outputDirectory, outputFile, numObjects): insertString = "insert into NODE_DISP_INFO(node, analysis, timeStep, H1_translation, H2_translation, V_translation, H1_rotation, H2_rotation, V_rotation) values (?, ?, ?, ?, ?, ?, ?, ?, ?)" analysisNumber = int(outputPath[-3:]) outputFileObject = open(os.path.join(outputDirectory, outputFile), "rb") outputFileObject, numberOfRecordsInFileObject = determineNumberOfRecordsInFileObjectGivenRecordSize(recordSize, outputFileObject) numberOfRecordsPerObject = (numberOfRecordsInFileObject//numberOfObjects) loop1StartTime = time.time() for i in range(numberOfRecordsPerObject ): processedRecords = [] loop2StartTime = time.time() for j in range(numberOfObjects): fout = outputFileObject .read(recordSize) processedRecords.append(tuple([j+1, analysisNumber, i] + [x for x in list(struct.unpack(recordFormat, fout))])) loop2EndTime = time.time() print "Time taken to finish loop2: {}".format(loop2EndTime-loop2StartTime) dbInsertStartTime = time.time() connection.executemany(insertString, processedRecords) dbInsertEndTime = time.time() loop1EndTime = time.time() print "Time taken to finish loop1: {}".format(loop1EndTime-loop1StartTime) outputFileObject.close() print "Finished reading output file for analysis {}...".format(analysisNumber) When I run the code, it seems that "loop 2" and "inserting into the database" is where most execution time is spent. Average "loop 2" time is 0.003s, but it is run up to 50,000 times, in some analyses. The time spent putting stuff into the database is about the same: 0.004s. Currently, I am inserting into the database every time after loop2 finishes so that I don't have to deal with running out RAM. What could I do to speed up "loop 2"?

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  • Is it possible to use a back reference to specify the number of replications in a regular expression

    - by user307894
    Is it possible to use a back reference to specify the number of replications in a regular expression? foo= 'ADCKAL+2AG.+2AG.+2AG.+2AGGG+.+G+3AGGa4.' The substrings that start with '+[0-9]' followed by '[A-z]{n}.' need to be replaced with simply '+' where the variable n is the digit from earlier in the substring. Can that n be back referenced? For example (doesn't work) '+([0-9])[A-z]{/1}.' is the pattern I want replaced with "+" (that last dot can be any character and represents a quality score) so that foo should come out to ADCKAL++++G.G+. foo = 'ADCKAL+2AG.+2AG.+2AG.+2AGGG^+.+G+3AGGa4.' indelpatt = re.compile('\+([0-9])') while indelpatt.search(foo): indelsize=int(indelpatt.search(foo).group(1)) new_regex = '\+%s[ACGTNacgtn]{%s}.' % (indelsize,indelsize) newpatt=re.compile(new_regex) foo = newpatt.sub("+", foo) I'm probably missing an easier way to parse the string.

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  • Could random.randint(1,10) ever return 11?

    - by Tim Pietzcker
    When researching for this question and reading the sourcecode in random.py, I started wondering whether randrange and randint really behave as "advertised". I am very much inclined to believe so, but the way I read it, randrange is essentially implemented as start + int(random.random()*(stop-start)) (assuming integer values for start and stop), so randrange(1, 10) should return a random number between 1 and 9. randint(start, stop) is calling randrange(start, stop+1), thereby returning a number between 1 and 10. My question is now: If random() were ever to return 1.0, then randint(1,10) would return 11, wouldn't it?

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  • How do you extend the Site model in django?

    - by John Giotta
    What is the best approach to extending the Site model in django? Creating a new model and ForeignKey the Site or there another approach that allows me to subclass the Site model? I prefer subclassing, because relationally I'm more comfortable, but I'm concerned for the impact it will have with the built-in Admin.

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  • How to break a loop when inputting unspecified raw_input?

    - by user1874510
    I want to write an interface using a while loop and raw_input. My code looks like this: while True: n = raw_input("'p' = pause, 'u' = unpause, 'p' = play 's' = stop, 'q' = quit) if n.strip() == 'p': mp3.pause() if n.strip() == 'u': mp3.unpause() if n.strip() == 'p': mp3.play() if n.strip() == 's': mp3.stop() if n.strip() == 'q': break But I want it to break if I input anything that isn't specified in the raw_input. if not raw_input: break Returns and IndentationError: unindent does not match any outer indentation level. if not raw_input: break Does not return any error but doesn't work as I want it to. As far as I know, it does nothing at all. Also, if there's a cleaner way to write my loop, I love to hear it.

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  • What is an alternative to eval in this situation?

    - by CppLearner
    Many of my view functions do similar things. For the most part, they reverse to a different views upon clicking a button / a text link. So I wrote a helper function render_reverse def render_reverse(f, args): # args are all string type return eval('reverse(' + f + ', ' + args + ')' ) eval is a bad practice, and is pretty slow. It takes 3 seconds to start redirecting, whereas calling reverse directly takes less than 1 second to start redirecting. What alternative do I have? By the way, the function above doesn't work properly. I was modelling after this line (which works) eval('reverse("homepage", args=["abcdefg"])') Thanks.

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  • How to verify object creation in Django ?

    - by Martin
    So.. this never crossed my head before but now I just can't figure out how to do that !! I want to verify that the object I created was really created, and return True or False according to that : obj = object(name='plop') try: obj.save() return True except ???: return False Any idea ? Cheers, -M

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  • Fastest method in merging of the two: dicts vs lists

    - by tipu
    I'm doing some indexing and memory is sufficient but CPU isn't. So I have one huge dictionary and then a smaller dictionary I'm merging into the bigger one: big_dict = {"the" : {"1" : 1, "2" : 1, "3" : 1, "4" : 1, "5" : 1}} smaller_dict = {"the" : {"6" : 1, "7" : 1}} #after merging resulting_dict = {"the" : {"1" : 1, "2" : 1, "3" : 1, "4" : 1, "5" : 1, "6" : 1, "7" : 1}} My question is for the values in both dicts, should I use a dict (as displayed above) or list (as displayed below) when my priority is to use as much memory as possible to gain the most out of my CPU? For clarification, using a list would look like: big_dict = {"the" : [1, 2, 3, 4, 5]} smaller_dict = {"the" : [6,7]} #after merging resulting_dict = {"the" : [1, 2, 3, 4, 5, 6, 7]} Side note: The reason I'm using a dict nested into a dict rather than a set nested in a dict is because JSON won't let me do json.dumps because a set isn't key/value pairs, it's (as far as the JSON library is concerned) {"a", "series", "of", "keys"} Also, after choosing between using dict to a list, how would I go about implementing the most efficient, in terms of CPU, method of merging them? I appreciate the help.

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  • how to trigger a script located on a machine in one domain from a machine on another domain

    - by user326814
    Hi, I am basically from QA. What we testers do each day is 1. Open a web browser. Type in http://11.12.13.27.8080/cruisecontrol (since we are in a particular network, only we can access this) 2. Check if the latest nightly build has been successful. If it is successful, deploy it on a test environment by clicking on 'Deploy this build' link. This deploying takes around 1-1.5 hours. During this time we cannot use our machines to work on anything else. Only after this deploying can we begin to test. Now, i wanted to know if its possible to do the below. When at home in the morning, i use something which will trigger a script (which will be on my machine at workplace). This script will inturn automatically deploy the build. I already have such a similar script. What i want to know is how is it possible to trigger this script from my home machine? Is it even possible? For e.g the external trigger will say "Deploy xxx branch on yyy test environment". So the script on my workplace machine will be invoked and it will automatically deploy it before i actually come to my desk. Please help. I am from QA and have no idea about all this.

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  • wxWidgets/wxPython: Do two identical events cause two handlings?

    - by cool-RR
    When there are two identical events in the event loop, will wxPython handle both of them, or will it call the handler only once for them both? I mean, in my widget I want to have an event like EVT_NEED_TO_RECALCULATE_X. I want this event to be posted in all kinds of different circumstances that require x to be recalculated. However, even if there are two different reasons to recalculate x, only one recalculation needs to be done. How do I do this?

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  • Live Updating Widget for 100+ concurrent users

    - by flavio87
    Hi there what would you use if you had to have a div box on your website that would have to be updated constantly with new HTML content from the server. simple polling is probably not very resource inefficient - imagine also having 10'000 users and the div has to update. what is the most efficient or elegant solution for such a problem? are there existing widgets which contain this "autoupdate" functionality?

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