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  • Does dict.update affect a function's argspec?

    - by sbox32
    import inspect class Test: def test(self, p, d={}): d.update(p) return d print inspect.getargspec(getattr(Test, 'test'))[3] print Test().test({'1':True}) print inspect.getargspec(getattr(Test, 'test'))[3] I would expect the argspec for Test.test not to change but because of dict.update it does. Why?

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  • How can I access the "through" object of a Django ManyToManyField?

    - by Macha
    I have the following models in my Django app. How can I from the Team model find all the User objects who have accepted as True in the Membership model? I know I need to use Team.objects.filter(), but I'm not sure how to check the value of the accepted field. from django.contrib.auth.models import User class Team(models.Model): members = models.ManyToManyField(User, through="Membership") class Membership(models.Model): user = models.ForeignKey(User) team = models.ForeignKey(Team) accepted = models.BooleanField(default=False)

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  • Convert octet string to human readable

    - by Michael Lang
    Using the pysnmp framework i get some values doing a snmp walk. Unfortunately for the oid 1.3.6.1.21.69.1.5.8.1.2 (DOCS-CABLE-DEVICE-MIB) i get a weird result which i cant correctly print here since it contains ascii chars like BEL ACK When doing a repr i get: OctetString('\x07\xd8\t\x17\x03\x184\x00') But the output should look like: 2008-9-23,3:24:52.0 the format is called "DateAndTime". How can i translate the OctetString output to a "human readable" date/time ?

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  • Word filter that groups words?

    - by Legend
    Is there any library that achieves the following: Convert Microsoft Windows 98 Microsoft Windows XP Windows 7 Windows Ultimate Desktop Windows to Windows 4 The complicated part here is to recognize that "Desktop Windows" is an anomaly here and not count it. If nothing is added before the word "Windows", perhaps it can be counted but if there is something else and the suffix does not match any popular suffix, it can still be counted. Maybe I am a little vague here but perhaps someone could have an idea about what I am talking about here. Any suggestions?

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  • How to map one class against multiple tables with SQLAlchemy?

    - by tote
    Lets say that I have a database structure with three tables that look like this: items - item_id - item_handle attributes - attribute_id - attribute_name item_attributes - item_attribute_id - item_id - attribute_id - attribute_value I would like to be able to do this in SQLAlchemy: item = Item('item1') item.foo = 'bar' session.add(item) session.commit() item1 = session.query(Item).filter_by(handle='item1').one() print item1.foo # => 'bar' I'm new to SQLAlchemy and I found this in the documentation (http://www.sqlalchemy.org/docs/05/mappers.html#mapping-a-class-against-multiple-tables): j = join(items, item_attributes, items.c.item_id == item_attributes.c.item_id). \ join(attributes, item_attributes.c.attribute_id == attributes.c.attribute_id) mapper(Item, j, properties={ 'item_id': [items.c.item_id, item_attributes.c.item_id], 'attribute_id': [item_attributes.c.attribute_id, attributes.c.attribute_id], }) It only adds item_id and attribute_id to Item and its not possible to add attributes to Item object. Is what I'm trying to achieve possible with SQLAlchemy? Is there a better way to structure the database to get the same behaviour of "dynamic columns"?

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  • Pagination of Date-Based Generic Views in Django

    - by Apreche
    I have a pretty simple question. I want to make some date-based generic views on a Django site, but I also want to paginate them. According to the documentation the object_list view has page and paginate_by arguments, but the archive_month view does not. What's the "right" way to do it?

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  • Get node name with minidom

    - by Alex
    Is it possible to get the name of a node using minidom? for example i have a node: <heading><![CDATA[5 year]]></heading> what i'm trying to do is store the value heading so that i can use it as a key in a dictionary, the closest i can get is something like [<DOM Element: heading at 0x11e6d28>] i'm sure i'm overlooking something very simple here, thanks!

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  • Python2.7: How can I speed up this bit of code (loop/lists/tuple optimization)?

    - by user89
    I repeat the following idiom again and again. I read from a large file (sometimes, up to 1.2 million records!) and store the output into an SQLite databse. Putting stuff into the SQLite DB seems to be fairly fast. def readerFunction(recordSize, recordFormat, connection, outputDirectory, outputFile, numObjects): insertString = "insert into NODE_DISP_INFO(node, analysis, timeStep, H1_translation, H2_translation, V_translation, H1_rotation, H2_rotation, V_rotation) values (?, ?, ?, ?, ?, ?, ?, ?, ?)" analysisNumber = int(outputPath[-3:]) outputFileObject = open(os.path.join(outputDirectory, outputFile), "rb") outputFileObject, numberOfRecordsInFileObject = determineNumberOfRecordsInFileObjectGivenRecordSize(recordSize, outputFileObject) numberOfRecordsPerObject = (numberOfRecordsInFileObject//numberOfObjects) loop1StartTime = time.time() for i in range(numberOfRecordsPerObject ): processedRecords = [] loop2StartTime = time.time() for j in range(numberOfObjects): fout = outputFileObject .read(recordSize) processedRecords.append(tuple([j+1, analysisNumber, i] + [x for x in list(struct.unpack(recordFormat, fout))])) loop2EndTime = time.time() print "Time taken to finish loop2: {}".format(loop2EndTime-loop2StartTime) dbInsertStartTime = time.time() connection.executemany(insertString, processedRecords) dbInsertEndTime = time.time() loop1EndTime = time.time() print "Time taken to finish loop1: {}".format(loop1EndTime-loop1StartTime) outputFileObject.close() print "Finished reading output file for analysis {}...".format(analysisNumber) When I run the code, it seems that "loop 2" and "inserting into the database" is where most execution time is spent. Average "loop 2" time is 0.003s, but it is run up to 50,000 times, in some analyses. The time spent putting stuff into the database is about the same: 0.004s. Currently, I am inserting into the database every time after loop2 finishes so that I don't have to deal with running out RAM. What could I do to speed up "loop 2"?

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  • Prevent web2py from caching ?

    - by Joe
    Hi ! I'm working with web2py and for some reason web2py seems to fail to notice when code has changed in certain cases. I can't really narrow it down, but from time to time changes in the code are not reflected, web2py obviously has the old version cached somewhere. The only thing that helps is quitting web2py and restarting it (i'm using the internal server). Any hints ? Thank you !

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  • Make qwidget in new window in PyQt4

    - by matt
    I'm trying to make a class that extends qwidget, that pops up a new window, I must be missing something fundamental, class NewQuery(QtGui.QWidget): def __init__(self, parent): QtGui.QMainWindow.__init__(self,parent) self.setWindowTitle('Add New Query') grid = QtGui.QGridLayout() label = QtGui.QLabel('blah') grid.addWidget(label,0,0) self.setLayout(grid) self.resize(300,200) when a new instance of this is made in main window's class, and show() called, the content is overlaid on the main window, how can I make it display in a new window?

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  • How to store and retrieve file in mongoengine?

    - by Seiverence
    I am attempting to store and retrieve file within mongodb, but am having issues with the retrieval. class Animal(Document): genus = StringField() family = StringField() photo = FileField() def get_file(): marmot = Animal.objects(genus='Marmota').first() photo = marmot.photo.read() content_type = marmot.photo.content_type print marmot.family # Prints out "Sciuridae" print content_type # Gives me an error, as content_type is "None" def save_file(): marmot = Animal( genus='Marmota', family='Sciuridae') marmot_photo = open('marmot.jpg', 'r') marmot.photo = marmot_photo marmot.photo.content_type = 'image/jpeg' marmot.save() When I check mongodb, it appears the document does save after the save_file, but when I call get_file, it appears the content_type is "None"? Am I saving and retrieving the file correctly? If not, whats wrong with the code? NOTE: The issue appears only to occur in the Windows environment. When run on linux, it works fine... very confused.

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  • Fastest method in merging of the two: dicts vs lists

    - by tipu
    I'm doing some indexing and memory is sufficient but CPU isn't. So I have one huge dictionary and then a smaller dictionary I'm merging into the bigger one: big_dict = {"the" : {"1" : 1, "2" : 1, "3" : 1, "4" : 1, "5" : 1}} smaller_dict = {"the" : {"6" : 1, "7" : 1}} #after merging resulting_dict = {"the" : {"1" : 1, "2" : 1, "3" : 1, "4" : 1, "5" : 1, "6" : 1, "7" : 1}} My question is for the values in both dicts, should I use a dict (as displayed above) or list (as displayed below) when my priority is to use as much memory as possible to gain the most out of my CPU? For clarification, using a list would look like: big_dict = {"the" : [1, 2, 3, 4, 5]} smaller_dict = {"the" : [6,7]} #after merging resulting_dict = {"the" : [1, 2, 3, 4, 5, 6, 7]} Side note: The reason I'm using a dict nested into a dict rather than a set nested in a dict is because JSON won't let me do json.dumps because a set isn't key/value pairs, it's (as far as the JSON library is concerned) {"a", "series", "of", "keys"} Also, after choosing between using dict to a list, how would I go about implementing the most efficient, in terms of CPU, method of merging them? I appreciate the help.

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  • printing only the last 8 entries in a .csv file

    - by user2341103
    I have an input csv file as below,I want to print only the most recent 8 entries..can anyone provide inputs on how to do this? INPUT:- trend.csv ['2013-06-25 20:01', '10'] ['2013-06-25 20:06', '9'] ['2013-06-25 20:06', '8'] ['2013-06-26 20:06', '7'] ['2013-06-26 20:06', '6'] ['2013-06-26 20:06', '5'] ['2013-06-26 20:06', '4'] ['2013-06-26 20:06', '3'] ['2013-06-26 20:06', '2'] ['2013-06-26 20:08', '1'] OUTPUT:- ['2013-06-25 20:06', '8'] ['2013-06-26 20:06', '7'] ['2013-06-26 20:06', '6'] ['2013-06-26 20:06', '5'] ['2013-06-26 20:06', '4'] ['2013-06-26 20:06', '3'] ['2013-06-26 20:06', '2'] ['2013-06-26 20:08', '1'] import csv #Now read the recent 8 entries and print cr = csv.reader(open("trend.csv","rb")) for row in cr: #print only the recent most 8 entries print row

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  • Django - count date between

    - by DJPy
    I have many record in my database wich contains datetime field (e.g. 2010-05-23 17:45:57). I want to count all records between e.g. 15:00 and 15:59 (it all can by from other day, month or year). How can I do this?

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  • Feedback on availability with Google App Engine

    - by Ron
    We've had some good experiences building an app on Google App Engine, this first app's target audience are Google Apps users, so no issues there in terms of it being hosted on Google infrastructure. We like it so much that we would like to investigate using it for a another app, however this next project is for a client who is not really that interested in what technology it sits on, they just want it to work, and work all of the time. In this scenario, given that we have the technology applicability and capability side covered, are there any concerns that this stuff is still relatively new and that we may not be as much "in control" as if we had it done with traditional hosting?

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  • One-to-One relation classes

    - by SeyZ
    I want to have a class named ProjectDirectory and a class named MetaDirectory. Each project has a MetaDirectory which contains some meta data. Is it the good way to write the classes like this: class ProjectDirectory(object): def __init__(self, directory=None): self.directory = directory self.meta_directory = MetaDirectory(self) def __repr__(self): return self.directory class MetaDirectory(object): def __init__(self, project_directory=None): self.project_directory = project_directory self.directory = "%s/.meta/" % project_directory ProjectDirectory has a reference to MetaDirectory and MetaDirectory has a reference to ProjectDirectory. Is there an other solution or this solution is good ?

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  • Efficient job progress update in web application

    - by Endru6
    Hi, Creating a web application (Django in my case, but I think the question is more general) that is administrating a cluster of workers doing queued jobs, there is a need to track each jobs progress. When I've done it using database UPDATE (PostgreSQL in this case), it severely hits the database performance, because each UPDATE creates a new row in a table, and in my case only vacuuming DB removes obsolete rows. Having 30 jobs running and reporting progress every 1 minute DB may require vacuuming (and it means huge slow downs on a front end side for all the employees working with the system) every 10 days. Because the progress information isn't critical, ie. it doesn't have to be persistent, how would you do the progress updates from jobs without using an overhead database implies? There are 30 worker servers, each doing 1 or 2 jobs simultaneously, 1 front end server which serves a web application to users, and 1 database server.

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  • Live Updating Widget for 100+ concurrent users

    - by flavio87
    Hi there what would you use if you had to have a div box on your website that would have to be updated constantly with new HTML content from the server. simple polling is probably not very resource inefficient - imagine also having 10'000 users and the div has to update. what is the most efficient or elegant solution for such a problem? are there existing widgets which contain this "autoupdate" functionality?

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  • how to render custom columns with a GenericTreeModel

    - by Giorgio Gelardi
    I have to display some data in a treeview. The "real" data model is huge and I cannot copy all the stuff in a TreeStore, so I guess I should use a GenericTreeModel to act like a virtual treeview. Btw the first column is the classic icon+text style and I think I should declare a column with a CellRendererPixbuf (faq sample), but I'm not sure what the model methods on_get_n_columns() and on_get_value() should return. It's both a Pixbuf and a string value for the same column. Any help will be appreciated.

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