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• Android : Connecting to MySQL using PHP

  - by user1771128

  I followed the following article http://blog.sptechnolab.com/2011/02/10/android/android-connecting-to-mysql-using-php/ I am able to execute my php file. I executed it individually and its working fine. The problem is in the android execution part. Am posting the Log Cat for the error am facing. Tried putting in a List View with id "list" but the error stil 10-28 16:08:27.201: E/AndroidRuntime(664): **FATAL EXCEPTION: main** 10-28 16:08:27.201: E/AndroidRuntime(664): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.example.city/com.example.city.City}: java.lang.RuntimeException: Your content must have a ListView whose id attribute is 'android.R.id.list' 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1956) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:1981) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.access$600(ActivityThread.java:123) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1147) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.os.Handler.dispatchMessage(Handler.java:99) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.os.Looper.loop(Looper.java:137) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.main(ActivityThread.java:4424) 10-28 16:08:27.201: E/AndroidRuntime(664): at java.lang.reflect.Method.invokeNative(Native Method) 10-28 16:08:27.201: E/AndroidRuntime(664): at java.lang.reflect.Method.invoke(Method.java:511) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:784) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:551) 10-28 16:08:27.201: E/AndroidRuntime(664): at dalvik.system.NativeStart.main(Native Method) 10-28 16:08:27.201: E/AndroidRuntime(664): Caused by: java.lang.RuntimeException: Your content must have a ListView whose id attribute is 'android.R.id.list' 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ListActivity.onContentChanged(ListActivity.java:243) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.android.internal.policy.impl.PhoneWindow.setContentView(PhoneWindow.java:254) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Activity.setContentView(Activity.java:1835) 10-28 16:08:27.201: E/AndroidRuntime(664): at com.example.city.City.onCreate(City.java:35) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Activity.performCreate(Activity.java:4465) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1049) 10-28 16:08:27.201: E/AndroidRuntime(664): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1920) 10-28 16:08:27.201: E/AndroidRuntime(664): ... 11 more

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• Drupal 6: getting random data from database

  - by artmania

  Hi friends, I spend few hours at google, but cant find :/ is it possible to get a random data from database with Drupal 6? appreciate helps!! thanks!

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• what is avarage balance

  - by user329820

  Hi I have a homework that I can not understand this part of that would you please help me ? thanks List the average balance of customers by city and short zip code(5 digits of zip code)

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• Specify fields in a recursive find with cakephp

  - by Razor Storm

  Suppose I have a table Recipe that hasmany ingredients. I do a recursive find to grab recipes with their associated ingredients: $this->Recipe->find('all', array('fields' => array('id','title','description'))); Here I can use the 'fields' attribute to specify that I only want it to return id, title, and description. However, despite this, cakephp still returns ALL columns from the ingredients table. How do I tell cakephp that I only want ingredient table's id and name fields? btw ingredient model is "Ingredient" and the table is ingredients, and the aggregation table is recipes_ingredients.

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• Secure php code for copyright

  - by cosy

  I have an eCommerce platform, and i wand to secure it. How can it be possible ? I don't want to somebody copy my code. Like a license for 1 year with a code for activation. Or somethings like this. Sorry my English, thanks a lot!

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• undefined offset error in php

  - by user225269

  I don't know why but the code below is working when I have a different query: $result = mysql_query("SELECT * FROM student WHERE IDNO='".$_GET['id']."'") ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <?php list($year,$month,$day)=explode("-", $row['BIRTHDAY']); ?> <tr> <td width="30" height="35"><font size="2">Month:</td> <td width="30"><input name="mm" type="text" id="mm" onkeypress="return handleEnter(this, event)" value="<?php echo $month;?>"> <td width="30" height="35"><font size="2">Day:</td> <td width="30"><input name="dd" type="text" id="dd" maxlength="25" onkeypress="return handleEnter(this, event)" value="<?php echo $day;?>"> <td width="30" height="35"><font size="2">Year:</td> <td width="30"><input name="yyyy" type="text" id="yyyy" maxlength="25" onkeypress="return handleEnter(this, event)" value="<?php echo $year;?>"> And it works when this is my query: $idnum = mysql_real_escape_string($_POST['idnum']); mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); Please help, why do I get the undefined offset error when I use this query: $result = mysql_query("SELECT * FROM student WHERE IDNO='".$_GET['id']."'") I assume that the query is the problem because its the only thing that's different between the two.

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• Fetching a result twice with deferend name

  - by user1799842

  I have 1 table with tasks named opentask:columns: id,title,description,expires,creator_id,creator_name, executer_id, executer_name, priority_id, status_id1 table with users named user: with columns: user_id, username What I want is to create a query where there will be all columns from opentask table where the executer_id will be equal to the user_id of user table AND the creator_id will be equal to the user_id again. This creates a confusion because the first equality excludes the second.So I need somehow to create a query where I will include the usernames for the executer with something like where "opentask.executer_id=user_user_id" and at the same time I will include the username again (as a differend name?) for the creator with something like "where opentask.executer_id=user_user_id"So I try this, which of course I know that is missing something, can you help? SELECT DISTINCT id, title, description, expires, creator_id, executer_id, oc_opentask.priority_id, oc_opentask.status_id, priority_name, status_name, user_id, username, (SELECT username FROM oc_opentask, oc_user WHERE oc_opentask.creator_id=oc_user.user_id) AS username2 FROM oc_opentask, oc_opentask_priority, oc_user, oc_opentask_status WHERE oc_opentask.priority_id=oc_opentask_priority.priority_id AND oc_opentask.executer_id=oc_user.user_id AND oc_opentask.status_id=oc_opentask_status.status_id ORDER BY oc_opentask.expires DESC

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• SQL where clasue to work with Group by clasue after performing a count()

  - by Matt

  Tried my usual references at w3schools and google. No luck I'm trying to produce the following results. QTY is a derived column | Position | QTY -------------------- 1 Clerk 2 2 Mgr 2 Here's what I'm not having luck with: SELECT Position, Count(position) AS 'QTY' FROM tblemployee Where ('QTY' != 1) GROUP BY Position I know that my Position is set up as varchar(255) Count produces a integer data and my where clasue is accurate so that leads me to believe that that Count() is jamming me up. Please throw up an example so I can reference later. Thanks for the help!

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• problem with logout script in php

  - by user225269

  I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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• I want to add and remove items from a menu with PHP.

  - by CDeanMartin

  This menu will need to be updated daily. <html><head></head><body> <h1> Welcome to Burgerama </h1> <?php include("menuBuilder.php"); showBurgerMenu(); ?> </body></html> Menu items are stored in the database. Items have a display field; if it is on, the item should be displayed on the menu. The menu only displays 4 or 5 "specials" at a time, and the manager needs to change menu items easily. I want to make a menu editing page like this: <?php include("burger_queries.php"); dbconnect("burger_database"); foreach($menuItem in burger_database) { echo createToggleButton($menuItem); } ?> .. with a toggle button for each menu item. Ideally the button will be labeled with the menu item, in blue if the item is "on", and red if the item is "off." Clicking the button switches between "on" and "off" I am stuck trying to a get a button to execute an UPDATE query on its corresponding menu item.

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• Translate SQL statement into named_scope?

  - by keruilin

  How can I translate this SQL into a named_scope? Also, I want the total comments param to be passed through a lambda. "select users., count() as total_comments from users, comments where (users.id = comments.user_id) and (comments.public_comment = 1) and (comments.aasm_state = 'posted') and (comments.forum_user_id is null) group by users.id having total_comments 25"

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• second time auto login to twitter using oauth php

  - by JAMES

  Any can tell me how to second time auto connect with twitter from my site. I did... the following CODE if(empty($outh_key_db)){ $token=$_SESSION['oauth_token'] ; $outh_secr_db=$_SESSION['oauth_token_secret']; $con = mysql_connect("localhost","rathin","xxxxxxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_twtbook", $con); mysql_query("UPDATE register SET outh_key = '".$token."', outh_secr='".$outh_secr_db."' WHERE userid='".$loguser_email."'"); mysql_close($con); This code save the outh_token and outh_tk_secret to my DB. But on second time log in to my site I passed the 'outh_token and outh_tk_secret' in session with username. The oauth not authenticate that.... Kindly suggest me.... to make aouth connect to twitter using oauth...if user once(1st time made the) connect twitter

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• Input html tag not parsing properly in php

  - by Akaash

  I have a database with names that I would like displayed in the form of a table with checkboxes. Everything works until I try to place the html tag into my php code. When I put the input tag in it gives me the error: Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' I can't see where I would put a comma or semi colon. <form> <?php $name = $_POST['name']; $host = "mysql16.000webhost.com"; $user_name = "a1611480_akaash"; $pwd = "****"; $database_name = "a1611480_akaash"; $db = mysql_connect($host, $user_name, $pwd); mysql_select_db($database_name); $result = mysql_query("SELECT name FROM Sort"); $var = array(); while ($row = mysql_fetch_array($result)) { $var[] = $row['name']; } $unique = array_unique($var); foreach ($unique as $value) { echo "<p class = Body_text><label>$value</label> <input type="checkbox" name="name" value="$value" /> </p>\n"; } ?> </form>

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• Help converting subquery to query with joins

  - by Tim

  I'm stuck on a query with a join. The client's site is running mysql4, so a subquery isn't an option. My attempts to rewrite using a join aren't going too well. I need to select all of the contractors listed in the contractors table who are not in the contractors2label table with a given label ID & county ID. Yet, they might be listed in contractors2label with other label and county IDs. Table: contractors cID (primary, autonumber) company (varchar) ...etc... Table: contractors2label cID labelID countyID psID This query with a subquery works: SELECT company, contractors.cID FROM contractors WHERE contractors.complete = 1 AND contractors.archived = 0 AND contractors.cID NOT IN ( SELECT contractors2label.cID FROM contractors2label WHERE labelID <> 1 AND countyID <> 1 ) I thought this query with a join would be the equivalent, but it returns no results. A manual scan of the data shows I should get 34 rows, which is what the subquery above returns. SELECT company, contractors.cID FROM contractors LEFT OUTER JOIN contractors2label ON contractors.cID = contractors2label.cID WHERE contractors.complete = 1 AND contractors.archived = 0 AND contractors2label.labelID <> 1 AND contractors2label.countyID <> 1 AND contractors2label.cID IS NULL

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• Query to add a column depending of outcome of there columns

  - by Tam

  I have a user table 'users' that has fields like: id first_name last_name ... and have another table that determines relationships: user_id friend_id user_accepted friend_accepted .... I would like to generate a query that selects all the users but also add another field/column say 'network_status' that depends on the values of user_accepted and fiend_accepted. For example, if user_accepted is true friend_accepted is false I want the 'network_status' field to say 'request sent'. Can I possibly do this in one query? (I would prefer not to user if/else inside the query but if that's the only way so be it)

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• How can I get all children from a parent row in the same table?

  - by Johnny Freeman

  Let's say I have a table called my_table that looks like this: id | name | parent_id 1 | Row 1 | NULL 2 | Row 2 | NULL 3 | Row 3 | 1 4 | Row 4 | 1 5 | Row 5 | NULL 6 | Row 6 | NULL 7 | Row 7 | 8 8 | Row 8 | NULL 9 | Row 9 | 4 10 | Row 10 | 4 Basically I want my final array in PHP to look like this: Array ( [0] => Array ( [name] => Row 1 [children] => Array ( [0] => Array ( [name] => Row 3 [children] => ) [1] => Array ( [name] => Row 4 [children] => Array ( [0] => Array ( [name] => Row 9 [children] => ) [1] => Array ( [name] => Row 10 [children] => ) ) ) ) ) [1] => Array ( [name] => Row 2 [children] => ) [2] => Array ( [name] => Row 5 [children] => ) [3] => Array ( [name] => Row 6 [children] => ) [4] => Array ( [name] => Row 8 [children] => Array ( [0] => Array ( [name] => Row 7 [children] => ) ) ) ) So, I want it to get all of the rows where parent_id is null, then find all nested children recursively. Now here's the part that I'm having trouble with: How can this be done with 1 call to the database? I'm sure I could do it with a simple select statement and then have PHP make the array look like this but I'm hoping this can be done with some kind of fancy db joining or something like that. Any takers?

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• Use count or have a field that tallies?

  - by Dan LaManna

  Fairly simple concept, making an extremely basic message board system and I want users to have a post count. Now I was debating on whether or not to have a tally in their row that is added each time a post by them is created, or subtracted by one each time a post of theirs is deleted. However I'm sure that performing a count query when the post count is requested would be more accurate due to unforseen circumstances (say a thread gets deleted and it doesn't lower their tally properly), however this seems like it would be less efficient to run a query EVERY time their post count is loaded, especially in the case of them having 10 posts on the same page and it lists their post count each post. Thoughts/Advice? Thanks

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• GROUP BY on multiple columns

  - by Tams

  I have a table that looks like the following - Id Reference DateAttribute1 DateAttribute2 1 MMM005 2011-09-11 2012-09-10 2 MMM005 2012-06-13 2012-09-10 3 MMM006 2012-08-22 2012-09-10 4 MMM006 2012-08-22 2012-09-11 I have handle to the id values. I would like to query such that I get the following result Id Reference DateAttribute1 DateAttribute2 2 MMM005 2012-06-13 2012-09-10 4 MMM006 2012-08-22 2012-09-11 I would like my result to be grouped by reference and then 'DateAttribute1' and then 'DateAttribute2' as such - DateAttribute1 has a priority over DateAttribute2 as you can see above in the result. How should I write my query to fetch the results in the above manner? Any solution?

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• Looping Through Database Query

  - by DrakeNET

  I am creating a very simple script. The purpose of the script is to pull a question from the database and display all answers associated with that particular question. We are dealing with two tables here and there is a foreign key from the question database to the answer database so answers are associated with questions. Hope that is enough explanation. Here is my code. I was wondering if this is the most efficient way to complete this or is there an easier way? <html> <head> <title>Advise Me</title> <head> <body> <h1>Today's Question</h1> <?php //Establish connection to database require_once('config.php'); require_once('open_connection.php'); //Pull the "active" question from the database $todays_question = mysql_query("SELECT name, question FROM approvedQuestions WHERE status = active") or die(mysql_error()); //Variable to hold $todays_question aQID $questionID = mysql_query("SELECT commentID FROM approvedQuestions WHERE status = active") or die(mysql_error()); //Print today's question echo $todays_question; //Print comments associated with today's question $sql = "SELECT commentID FROM approvedQuestions WHERE status = active"; $result_set = mysql_query($sql); $result_num = mysql_numrows($result_set); for ($a = 0; $a < $result_num; $a++) { echo $sql; } ?> </body> </html>

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• Is there a way to echo this only once and not have it repeat?

  - by Fernando

  I have the following query: $select = mysql_query("SELECT * FROM posts WHERE id = $postIds"); while ($return = mysql_fetch_assoc($select)) { $postUrl = $return['url']; $postTitle = $return['title']; echo "<h1><a href='$postUrl'>".$postTitle."</a></h1>"; } Now the problem is, the variable $postIds often times contain the same id multiple times. So the title of the post echos itself multiple times. Is there a way to have it echo only once?

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• Best practice for writing sql statements in php.

  - by ghostz00

  Can someone point me towards a resource or show me an example of a good way of writing sql statements in php. Most statements seem so ugly and unreadable.

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• Get the sum by comparing between two tables

  - by Ismail Gunes

  I have to tables ProdBiscuit As tb and StockData As sd , I have to get the sum of the quantity in StockData (quantite) with the condition of if (sd.status0 AND sd.prodid = tb.id AND sd.matcuisine = 3) Here is my sql query SELECT tb.id, tb.nom, tb.proddate, tb.qty, tb.stockrecno FROM ProdBiscuit AS tb JOIN (SELECT id, prodid, matcuisine, status, SUM(quantite) AS rq FROM StockData) AS sd ON (tb.id = sd.prodid AND sd.status > 0 AND sd.matcuisine = 3) LIMIT 25 OFFSET @Myid This gives me no rows at all ? There is only 3 rows in ProdBiscuit and 11 rows in Stockdata and there is only 2 rows in StockData good with the condition. And as shown in the picture there is only two rows which give the condition. What is wrong in my query ? PS: The green lines on the image shows the condition in my query.

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• How to export an SQL-Database

  - by DanPB

  in phpmyadmin to my local disk? I don't see a field where I can specify the destination.

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• why is ADODB inserting NULL values on update?

  - by every_answer_gets_a_point

  i have: With rs .AddNew ' create a new record ' add values to each field in the record .Fields("datapath") = dpath .Fields("analysistime") = "atime" .Fields("reporttime") = "rtime" .Fields("lastcalib") = "lcalib" .Fields("analystname") = "aname" .Fields("reportname") = "rname" .Fields("batchstate") = "bstate" .Fields("instrument") = "NA" .Update ' stores the new record End With when i check the database, it looks like it ONLY inserted the last field! has anyone encountered this problem?

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• In SQL, a Join is actually an Intersection? And it is also a linkage or a "Sideway Union"?

  - by Jian Lin

  I always thought of a Join in SQL as some kind of linkage between two tables. For example, select e.name, d.name from employees e, departments d where employees.deptID = departments.deptID In this case, it is linking two tables, to show each employee with a department name instead of a department ID. And kind of like a "linkage" or "Union" sideway". But, after learning about inner join vs outer join, it shows that a Join (Inner join) is actually an intersection. For example, when one table has the ID 1, 2, 7, 8, while another table has the ID 7 and 8 only, the way we get the intersection is: select * from t1, t2 where t1.ID = t2.ID to get the two records of "7 and 8". So it is actually an intersection. So we have the "Intersection" of 2 tables. Compare this with the "Union" operation on 2 tables. Can a Join be thought of as an "Intersection"? But what about the "linking" or "sideway union" aspect of it?

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