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  • How to map (large) integer on (small in size( alphanumeric string with PHP? (Cantor?)

    - by Glooh
    Dear all, I can't figure out how to optimally do the following in PHP: In a database, I have messages with a unique ID, like 19041985. Now, I want to refer to these messages in a short-url service but not using generated hashes but by simply 'calculate' the original ID. In other words, for example: http://short.url/sYsn7 should let me calculate the message ID the visitor would like to request. To make it more obvious, I wrote the following in PHP to generate these 'alphanumeric ID versions' and of course, the other way around will let me calculate the original message ID. The question is: Is this the optimal way of doing this? I hardly think so, but can't think of anything else. $alphanumString = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ-_'; for($i=0;$i < strlen($alphanumString);$i++) { $alphanumArray[$i] = substr($alphanumString,$i,1); } $id = 19041985; $out = ''; for($i=0;$i < strlen($id);$i++) { if(isset($alphanumString["".substr($id,$i,2).""]) && strlen($alphanumString["".substr($id,$i,2).""]) 0) { $out.=$alphanumString["".substr($id,$i,2).""]; } else { $out.=$alphanumString["".substr($id,$i,1).""]; $out.=$alphanumString["".substr($id,($i+1),1).""]; } $i++; } print $out;

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  • Paging not working in my wordpress installation

    - by Bootcamp
    I recently started a blog site and wanted to give it a magazine look. I used Wordpress for my blog and used the Arthemia theme with it. I also changed the permalink structure to point to /%year%/%monthnum%/%day%/%postname%/ structure. Now the problem that i have is that the paging has stopped working on my home page. When i click on the next page link i get a 404 error. My /page/2 url does not show the next page. I check on google and found out that it was due to the redirection that is being performed due to the permalink change. The solution given was that i need to skip the url rewriting for the /page/* urls. This is the link to an article which said this http://www.yoursearchadvisor.com/blog/wordpress-next_posts_link-broken/ . I was not able to follow this article and solve my problem, as i could not find the permanent redirect manager under the settings section as said in this article. Can somebody please guide me how to solve this problem. I am using the latest Wordpress version and Arthemia theme with it. Thanks.

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  • cURL + HTTP_POST, keep getting 500 error. Has no idea?

    - by mysqllearner
    Okay, I want to make a HTTP_POST using cURL to a SSL site. I already imported the certificate to my server. This is my code: $url = "https://www.xxx.xxx"; $post = "";# all data that going to send $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $post); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE); curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0'); $exe = curl_exec($ch); $getInfo = curl_getinfo($ch); if ($exe === false) { $output = "Error in sending"; if (curl_error($ch)){ $output .= "\n". curl_error($ch); } } else if($geInfo['http_code'] != 777){ $output = "No data returned. Error: " . $geInfo['http_code']; if (curl_error($ch)){ $output .= "\n". curl_error($ch); } } curl_close($c); echo $output; It keep returned "500". Based on w3schools, 500 means Internal Server Error. Is my server having problem? How to solve/troubleshoot this?

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  • RetinaJS and LESS : Background image doesn't show on iOS

    - by jidma
    I am trying to make a background image into a retina image using LESS CSS and RetinaJs: in my index.html file : <html> <head> <meta http-equiv="content-type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1.0, user-scalable=0, minimum-scale=1.0, maximum-scale=1.0"> <meta name="apple-mobile-web-app-capable" content="yes"> <meta name="apple-mobile-web-app-status-bar-style" content="black"> [...] <link type="text/css" rel="stylesheet/less" href="resources/css/retina.less"> <script type="text/javascript" src="resources/js/less-1.3.0.minjs" ></script> [...] </head> <body> [...] <script type="text/javascript" src="resources/js/retina.js"></script> </body> </html> in my retina.less file: .at2x(@path, @w: auto, @h: auto) { background-image: url("@{path}"); @at2x_path: ~`"@{path}".split('.').slice(0, "@{path}".split('.').length - 1).join(".") + "@2x" + "." + "@{path}".split('.')["@{path}".split('.').length - 1]`; @media all and (-webkit-min-device-pixel-ratio : 1.5) { background-image: url("@{at2x_path}"); background-size: @w @h; } } .topMenu { .at2x('../../resources/img/topMenuTitle.png'); } I have both topMenuTitle.png (320px x 40px) and [email protected] (640px x 80px) in the same folder. When test this code: In Firefox i have the normal Background In the XCode iPhone simulator I also have the normal Background In the iPhone device, I don't have any background at all. I'm using GWT if that matters. Any suggestions ? Thanks.

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  • Browser window popups - risks and special features

    - by Sandeepan Nath
    1. What exactly is the security risk with popups? The new browsers provide settings to block window popups (on blocking, sites with active popups display a message to user). What exactly is the security risk with popups? If allowing popups can execute something dangerous, then the main window can too. Is it not the case. I think I don't know about some special powers of window popups. 2. Any special features of popup windows? Take for example the HDFC bank netbanking site. The entire netbanking session happens in a new window popup and a user neither manually edit the URL or paste the URL in the main browser window. it does not work. Is a popup window needed for this feature? Does it improve security? (Asking because everything that is there in this site revolves around security - so they must have done that for a reason too). Why otherwise they would implement the entire netbanking on a popup window? 3. Is it possible to override browser's popup blocking settings Lastly, the HDFC site succcessfully displays popup window even when in the browser settings popups are blocked. So, how do they do it? Is that a browser hack? To see this - go to http://hdfcbank.com/ Under the "Login to your account" section select "HDFC Bank NetBanking" and click the "Login" button. You can verify that even if popups are blocked/popup blocker is enabled in the browser settings, this site is able to display popups. The answers to this question say that it is not possible to display popup windows if it has been blocked in browser settings. Solved Concluded with Pointy's solution and comments under that. Here is a fiddle demonstrating the same.

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  • OpenMeetings + Python + Suds

    - by user366774
    Trying to integrate openmeetings with django website, but can't understand how properly configure ImportDoctor: (here :// replaced with __ 'cause spam protection) print url http://sovershenstvo.com.ua:5080/openmeetings/services/UserService?wsdl imp = Import('http__schemas.xmlsoap.org/soap/encoding/') imp.filter.add('http__services.axis.openmeetings.org') imp.filter.add('http__basic.beans.hibernate.app.openmeetings.org/xsd') imp.filter.add('http__basic.beans.data.app.openmeetings.org/xsd') imp.filter.add('http__services.axis.openmeetings.org') d = ImportDoctor(imp) client = Client(url, doctor = d) client.service.getSession() Traceback (most recent call last): File "", line 1, in File "/usr/lib/python2.6/site-packages/suds/client.py", line 539, in call return client.invoke(args, kwargs) File "/usr/lib/python2.6/site-packages/suds/client.py", line 598, in invoke result = self.send(msg) File "/usr/lib/python2.6/site-packages/suds/client.py", line 627, in send result = self.succeeded(binding, reply.message) File "/usr/lib/python2.6/site-packages/suds/client.py", line 659, in succeeded r, p = binding.get_reply(self.method, reply) File "/usr/lib/python2.6/site-packages/suds/bindings/binding.py", line 159, in get_reply resolved = rtypes[0].resolve(nobuiltin=True) File "/usr/lib/python2.6/site-packages/suds/xsd/sxbasic.py", line 63, in resolve raise TypeNotFound(qref) suds.TypeNotFound: Type not found: '(Sessiondata, http__basic.beans.hibernate.app.openmeetings.org/xsd, )' what i'm doing wrong? please help and sorry for my english, but you are my last chance to save position :( need webinars at morning (2.26 am now)

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  • How can I shared controller logic in ASP.NET MVC for 2 controllers, where they are overriden

    - by AbeP
    Hello, I am trying to implement user-friendly URLS, while keeping the existing routes, and was able to do so using the ActionName tag on top of my controller (http://stackoverflow.com/questions/436866/can-you-overload-controller-methods-in-asp-net-mvc) I have 2 controllers: ActionName("UserFriendlyProjectIndex")] public ActionResult Index(string projectName) { ... } public ActionResult Index(long id) { ... } Basically, what I am trying to do is I store the user-friendly URL in the database for each project. If the user enters the URL /Project/TopSecretProject/, the action UserFriendlyProjectIndex gets called. I do a database lookup and if everything checks out, I want to apply the exact same logic that is used in the Index action. I am basically trying to avoid writing duplicate code. I know I can separate the common logic into another method, but I wanted to see if there is a built-in way of doing this in ASP.NET MVC. Any suggestions? I tried the following and I go the View could not be found error message: [ActionName("UserFriendlyProjectIndex")] public ActionResult Index(string projectName) { var filteredProjectName = projectName.EscapeString().Trim(); if (string.IsNullOrEmpty(filteredProjectName)) return RedirectToAction("PageNotFound", "Error"); using (var db = new PIMPEntities()) { var project = db.Project.Where(p => p.UserFriendlyUrl == filteredProjectName).FirstOrDefault(); if (project == null) return RedirectToAction("PageNotFound", "Error"); return View(Index(project.ProjectId)); } } Here's the error message: The view 'UserFriendlyProjectIndex' or its master could not be found. The following locations were searched: ~/Views/Project/UserFriendlyProjectIndex.aspx ~/Views/Project/UserFriendlyProjectIndex.ascx ~/Views/Shared/UserFriendlyProjectIndex.aspx ~/Views/Shared/UserFriendlyProjectIndex.ascx Project\UserFriendlyProjectIndex.spark Shared\UserFriendlyProjectIndex.spark I am using the SparkViewEngine as the view engine and LINQ-to-Entities, if that helps. thank you!

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  • Ruby and RSS2 Feed not displaying image

    - by pcasa
    Trying to create a simple RSS2 Feed that I could later pass on to FeedBurner but can't get RSS feed to display images at all. Also, from what I have read having xml.instruct! on top might cause IE to complain it's not a valid feed. Is this true? My Code looks like xml.instruct! xml.rss "version" => "2.0", "xmlns:dc" => "http://purl.org/dc/elements/1.1/" do xml.channel do xml.title "Store" xml.link url_for :only_path => false, :controller => 'products' xml.description "Store" xml.pubDate @products.first.updated_at.rfc822 if @products.any? @products.each do |product| xml.item do xml.title product.name xml.pubDate (product.updated_at.rfc822) xml.image do xml.url domain_host + product.product_image.url(:small) xml.title "Store" xml.link url_for :only_path => false, :controller => 'products' end xml.link url_for :only_path => false, :controller => 'products', :action => 'show', :id => product.permalink xml.description product.fine_print xml.guid url_for :only_path => false, :controller => 'products', :action => 'show', :id => product.permalink end end end end

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  • android view web pictures in gallery

    - by bitma
    I am new to android, I just finished Hello gallery tutorial, and a web pciture tutorial. Now I want to know how can I show some web images in gallery? the hello gallery code is from andorid tutor this is Web gallery code, I want to load some pictures from web and then show them in gallery, how can I write it? public class WebGallery extends Activity { String imageUrl = "http://i.pbase.com/o6/92/229792/1/80199697.uAs58yHk.50pxCross_of_the_Knights_Templar_svg.png"; Bitmap bmImg; ImageView imView; public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); imView = (ImageView) findViewById(R.id.imview); imView.setImageBitmap(getRemoteImage(imageUrl)); } public Bitmap getRemoteImage(String imageUrl) { try { URL aURL = new URL(imageUrl); final URLConnection conn = aURL.openConnection(); conn.connect(); final BufferedInputStream bis = new BufferedInputStream(conn.getInputStream()); final Bitmap bm = BitmapFactory.decodeStream(bis); bis.close(); return bm; } catch (IOException e) { Log.d("DEBUGTAG", "Oh noooz an error..."); } return null; } }

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  • e4x filter on more than one children?

    - by Chris
    My XML Looks like this: <?xml version="1.0" encoding="utf-8" ?> <projects> <project id="1" thumb="media/images/thumb.jpg" > <categories> <id>1</id> <id>2</id> </categories> <director>Director name</director> <name><![CDATA[IPhone commercial]]></name> <url><![CDATA[http://www.iphone.com]]></url> <description><![CDATA[Description about the project]]></description> <thumb><![CDATA[/upload/images/thumb.jpg]]></thumb> </project> </projects> But I cannot figure out how to filter projects based on a category id? Does anybody know how to do ? :) Something like: projects.project.(categories.(id == 3)) Just returns all items :(

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  • HTML href with css ie Problem

    - by Jordan Pagaduan
    <style type="text/css"> .web_westloh { background-image: url(images/web_westloh.png); background-repeat: no-repeat; height: 100px; width: 350px; } .web_westloh:hover { border-bottom-width: 2px; border-bottom-style: dashed; border-bottom-color: #999999; padding-bottom: 5px; } .web_money { background-image: url(images/web_money.png); background-repeat: no-repeat; height: 100px; width: 350px; } .web_money:hover { border-bottom-width: 2px; border-bottom-style: dashed; border-bottom-color: #999999; padding-bottom: 5px; } </style> <a href="http://www.westloh.com" title="Click to Visit http://www.westloh.com" target="_blank" class="web_westloh"> <div class="web_westloh"></div> </a> <a href="http://www.money-mind-set.com" title="Click to Visit http://www.money-mind-set.com" target="_blank"> <div class="web_money"></div> </a> The Problem is: In mozilla linking is ok. No problem. But in IE the link is a problem, it will not link in the target. See this page to see Problem: http://replytowest.com -- at the bottom. Thank You

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  • Jquery Sorting by Letter

    - by Batfan
    I am using jquery to sort through a group of paragraph tags (kudos to Aaron Harun). It pulls the value "letter" (a letter) from the url string and displays only paragraphs that start with that letter. It hides all others and also consolidates the list so that there are no duplicates showing. See the code: var letter = '<?php echo(strlen($_GET['letter']) == 1) ? $_GET['letter'] : ''; ?>' function finish(){ var found_first = []; jQuery('p').each(function(){ if(jQuery(this).text().substr(0,1).toUpperCase() == letter){ if(found_first[jQuery(this).text()] != true){ jQuery(this).addClass('current-series'); found_first[jQuery(this).text()] = true; }else{ jQuery(this).hide(); } } else{ jQuery(this).hide();} }) } Been working with this all day and I have 2 Questions on this: Is there a way to get it to ignore the word 'The', if it's first? For example, if a paragraph starts with 'The Amazing', I would like it to show up on the 'A' page, not the 'T' page, like it currently is. Is there a way to have a single page for (all) numbers? For example, the url to the page would be something similar to domain.com/index.php?letter=0 and this would show only the paragraph tags that start with a number, any number. I can currently do this with single numbers but, I would like 1 page for all numbers.

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  • loading a href's content into a shadowbox using .load() HELP!!!

    - by kielie
    <script type="text/javascript"> $(function() { $('#wp-calendar a').click(function(event) { event.preventDefault(); var url = $(this).attr('href') + ' #content'; var loaded = Shadowbox.load(url); Shadowbox.open({ content: loaded, player: "html", title: "<?php the_title(); ?>", height: 300, width: 470, }); }); }); </script> That is the code I am using to try and display content in a shadowbox, I am using the default wordpress calendar and with jQuery/AJAX (if I am not mistaken) adding this click event to every link in the calendar, so that when a link is clicked, the content is loaded and displayed in a shadowbox instead of opening on a new page. When I click on one of the links all I get inside of the shadowbox is "undefined". As I am sure you can see in my code, I am still very new to this, so any help or pointers would be appreciated. Thanx in advance!

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  • Parsing the Youtube API with DOM

    - by Kirk
    I'm using the Youtube API and I can retrieve the date information without a problem, but don't know how to retrieve the description information. My Code: <?php $v = "dQw4w9WgXcQ"; $url = "http://gdata.youtube.com/feeds/api/videos/". $v; $doc = new DOMDocument; $doc->load($url); $pub = $doc->getElementsByTagName("published")->item(0)->nodeValue; $desc = $doc->getElementsByTagName("media:description")->item(0)->nodeValue; echo "<b>Video Uploaded:</b> "; echo date( "F jS, Y", strtotime( $pub ) ); echo '<br>'; if (isset ($desc)) { echo "<b>Description:</b> "; echo $desc; echo '<br>'; } ?> Here's a link to the feed: http://gdata.youtube.com/feeds/api/videos/dQw4w9WgXcQ?prettyprint=true And the excerpt of code I don't know how to retrieve data from: <media:group> <media:description type='plain'>Music video by Rick Astley performing Never Gonna Give You Up. (C) 1987 PWL</media:description> </media:group> Thanks in advance.

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  • Play Multiple iPod Library Songs On iPhone At The Same Time With Pitch Bending & Other Effects

    - by Dino
    Hi, I have been going at this for the past two weeks and it is driving me crazy. I asked this question a couple of days ago (Extract iPod Library raw PCM samples and play with sound effects) and whilst the answer got me half way there I am still stuck. Basically what I am trying to achieve is load up multiple songs from the iPod library for playback with effects such as pitch bend, eq effects etc... I have gone down the route of AVPlayer and AVAudioPlayer which are too simple. The only framework I've seen that can play audio with these effects is OpenAL. I have tried a few objective c wrappers (Finch and ObjectAL) Finch does not play compressed audio whilst ObjectAL will only convert it for me if I pass in a URL for the file (which is something I cannot do because I only have an incompatible iPod library URL). An example of an app that does what I want beautifilly is Tap DJ. It can load up songs from the iPod library fast (unlike TouchDJ and it plays them with all sorts of effects. Any help would be much appreciated.

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  • tomcat resource missing, servlet not running

    - by user2837260
    import javax.servlet.*; import java.io.*; public class MyServlet implements Servlet { public void init(ServletConfig con) {} public void service(ServletRequest req, ServletResponse res) throws IOException,ServletException { res.setContentType("text/html"); PrintWriter out=res.getWriter(); String s="blah"; String s1="blah"; out.println("<html><body>"); if((s.equals(req.getParameter("firstname")))&&(s1.equals(req.getParameter("pwd")))) out.println("passwords match"); else out.println("password and name combo does not match"); out.println("</body></html>"); } public void destroy() {} public ServletConfig getServletConfig() { return null;} public String getServletInfo() { return null;} } this is my java file with the servlet class.its saved with the name MyServlet.java and so is the class file. and here is the xml file: <web-app> <servlet> <servlet-name>demoo</servlet-name> <servlet-class>MyServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>demoo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping> </web-app> i have made the folder as WEB-INF and then classes... WEB-INF also contains the .xml file but when i try to run the servlet , it says resource not found ps- i am already looking for the servlet with the name :demo localhost:8081/s1/demo* s1 is the war file * a html file in the war file seems to run fine on the server though. *

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  • Address family not supported by protocol exception

    - by srg
    I'm trying to send a couple of values from an android application to a web service which I've setup. I'm using Http Post to send them but when I run the application I get the error- request time failed java.net.SocketException: Address family not supported by protocol. I get this while debugging with both the emulator as well as a device connected by wifi. I've already added the internet permission using: <uses-permission android:name="android.permission.INTERNET" /> This is the code i'm using to send the values void insertData(String name, String number) throws Exception { String url = "http://192.168.0.12:8000/testapp/default/call/run/insertdbdata/"; HttpClient client = new DefaultHttpClient(); HttpPost post = new HttpPost(url); try { List<NameValuePair> params = new ArrayList<NameValuePair>(2); params.add(new BasicNameValuePair("a", name)); params.add(new BasicNameValuePair("b", number)); post.setEntity(new UrlEncodedFormEntity(params)); HttpResponse response = client.execute(post); }catch(Exception e){ e.printStackTrace(); } Also I know that my web service work fine because when I send the values from an html page it works fine - <form name="form1" action="http://192.168.0.12:8000/testapp/default/call/run/insertdbdata/" method="post"> <input type="text" name="a"/> <input type="text" name="b"/> <input type="submit"/> I've seen questions of similar problems but haven't really found a solution. Thanks

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  • Render only a portion of a PDF on iPhone/iPad

    - by Infinity
    Hello guys! I am rendering my pdf in an UIView's drawRect method. Here's my code: - (void)drawRect:(CGRect)rect2 { NSString *filename = @"lol.pdf"; CFStringRef path = CFStringCreateWithCString (NULL, [filename UTF8String], kCFStringEncodingUTF8); CFURLRef url = CFURLCreateWithFileSystemPath (NULL, path, kCFURLPOSIXPathStyle, 0); CGPDFDocumentRef pdf = CGPDFDocumentCreateWithURL(url); CGPDFPageRef page = CGPDFDocumentGetPage (pdf, 1); CGAffineTransform m; CGContextRef context = UIGraphicsGetCurrentContext(); CGRect aRect = CGRectMake(0, 0, 768, 1024); CGContextTranslateCTM(context, 0.0, aRect.size.height); CGContextScaleCTM(context, 1.0, -1.0); m = CGPDFPageGetDrawingTransform (page, kCGPDFMediaBox, aRect, 0, YES); CGContextSaveGState (context); CGContextConcatCTM (context, m); CGContextClipToRect (context,CGPDFPageGetBoxRect (page, kCGPDFCropBox)); CGContextDrawPDFPage (context, page); CGContextRestoreGState (context); } It renders the whole pdf. How can I render only a part from it? Can you help me with it?

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  • Rails - any fancy ways to handle 404s?

    - by jyoseph
    I have a rails app I built for an old site I converted from another cms (in a non-rails language, hehe). Most of the old pages are mapped to the new pages using routes.rb. But there are still a few 404s. I am a rails newb so I'm asking if there are any advanced ways to handle 404s. For example, if I was programming in my old language I'd do this: Get the URL (script_name) that was being accessed and parse it. Do a lookup in the database for any keywords, ids, etc found in the new URL. If found, redirect to the page (or if multiple records are found, show them all on a results page and let user choose). With rails I'd probably want to do :status = :moved_permanently I'm guessing? If not found, show a 404. Are there any gems/plugins or tutorials you know of that would handle such a thing, if it's even possible. Or can you explain on a high level how that can be done? I don't need a full code sample, just a push in the right direction. PS. It's a simple rails 3 app that uses a single Content model.

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  • facebook authentication / login trouble

    - by salmane
    I have setup facebook authentication using php and it goes something like this first getting the authorization here : https://graph.facebook.com/oauth/authorize?client_id=<?= $facebook_app_id ?>&redirect_uri=http://www.example.com/facebook/oauth/&scope=user_about_me,publish_stream then getting the access Token here : $url = "https://graph.facebook.com/oauth/access_token?client_id=".$facebook_app_id."&redirect_uri=http://www.example.com/facebook/oauth/&client_secret=".$facebook_secret."&code=".$code;" function get_string_between($string, $start, $end){ $string = " ".$string; $ini = strpos($string,$start); if ($ini == 0) return ""; $ini += strlen($start); $len = strpos($string,$end,$ini) - $ini; return substr($string,$ini,$len); } $access_token = get_string_between(file_get_contents($url), "access_token=", "&expires="); then getting user info : $facebook_user = file_get_contents('https://graph.facebook.com/me?access_token='.$access_token); $facebook_id = json_decode($facebook_user)->id; $first_name = json_decode($facebook_user)->first_name; $last_name = json_decode($facebook_user)->last_name; this is pretty ugly ( in my opinion ) but it works....how ever....the user is still not logged in...because i did not create or retrieve any session variables to confirm that the user is logged in to facebook... which means that after getting the authentication done the use still has to login .... first: is there a better way using php to do what i did above ? second: how do i set/ get session variable / cookies that ensure that the user doesnt have to click login thanks for your help

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  • Django: Serving a Download in a Generic View

    - by TheLizardKing
    So I want to serve a couple of mp3s from a folder in /home/username/music. I didn't think this would be such a big deal but I am a bit confused on how to do it using generic views and my own url. urls.py url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), The example I am following is found in the generic view section of the Django documentations: http://docs.djangoproject.com/en/dev/topics/generic-views/ (It's all the way at the bottom) I am not 100% sure on how to tailor this to my needs. Here is my views.py def song_download(request, song_id): song = Song.objects.get(id=song_id) response = object_detail( request, object_id = song_id, mimetype = "audio/mpeg", ) response['Content-Disposition'= "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response I am actually at a loss of how to convey that I want it to spit out my mp3 instead of what it does now which is to output a .mp3 with all of the current pages html contained. Should my template be my mp3? Do I need to setup apache to serve the files or is Django able to retrieve the mp3 from the filesystem(proper permissions of course) and serve that? If it do need to configure Apache how do I tell Django that? Thanks in advanced. These files are all on the HD so I don't need to "generate" anything on the spot and I'd like to prevent revealing the location of these files if at all possible. A simple /song/1234/download would be fantastic.

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  • Add class active when clicking the menu link with Jquery

    - by Adrian
    I have HTML <div id="top" class="shadow"> <ul class="gprc"> <li><a href="http://www.domain.com/">Home</a></li> <li><a href="http://www.domain.com/link1/">Text1</a></li> <li><a href="http://www.domain.com/link2/">Text2</a></li> <li><a href="http://www.domain.com/link3/">Text3</a></li> <li><a href="http://www.domain.com/link4">Text4</a></li> </ul> </div> and JQUERY $(function () { var url = window.location.pathname, urlRegExp = new RegExp(url.replace(/\/$/, '') + "$"); $('#top a').each(function () { if (urlRegExp.test(this.href.replace(/\/$/, ''))) { $(this).addClass('active'); } }); }); The problem is that when i click on the Home link all tabs are getting active class and don't understand why. I need it for the first link to not get any active class.

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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

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  • Is there a Java equivalent for Ruby on Rails "url_for"?

    - by Oren Ben-Kiki
    I have written something like this pretty easily in C# (string GetUrl(new { controller = "foo", action = "bar", baz = "fnord" }), based on the existing capabilities of the XmlRouteCollection class provided by the ASP.NET MVC framework (why it isn't there out of the box is beyond me; the additional required code was trivial). I am now faced with a JSP project, and I need the same ability: centralize the logic for generating all URLs in one place, based on a list of routing rules. Is there some code somewhere I could reuse/adapt to do this in Java? It seems like a common enough requirement, but google proved surprisingly unhelpful in finding something like this.

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  • rails not recognizing project

    - by tipu
    I can create a new project using rails and I can use stuff like rails migration ... and i (correctly) get a error because the sqlite gem is missing. but when i try using rails migration ... with a project i checked out from github, it doesn't recognize that it is a rails project i get: Usage: rails new APP_PATH [options] Options: -d, [--database=DATABASE] # Preconfigure for selected database (options: mysql/oracle/postgresql/sqlite3/frontbase/ibm_db) # Default: sqlite3 -O, [--skip-active-record] # Skip Active Record files [--dev] # Setup the application with Gemfile pointing to your Rails checkout -J, [--skip-prototype] # Skip Prototype files -T, [--skip-test-unit] # Skip Test::Unit files -G, [--skip-git] # Skip Git ignores and keeps -b, [--builder=BUILDER] # Path to an application builder (can be a filesystem path or URL) [--edge] # Setup the application with Gemfile pointing to Rails repository -m, [--template=TEMPLATE] # Path to an application template (can be a filesystem path or URL) -r, [--ruby=PATH] # Path to the Ruby binary of your choice # Default: /usr/bin/ruby1.8 [--skip-gemfile] # Don't create a Gemfile and it goes on. any ideas? edit: it's probably an important detail that earlier my rails wasn't working at all. i had to cp /usr/bin/ruby to /usr/bin/local/ruby

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