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  • regular expression on replace method of js not working

    - by user950146
    why this is not working var value = arr[row][col].replace(new RegExp('"', 'g'),'""'); Error : Webpage error details User Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.2; Tablet PC 2.0) Timestamp: Tue, 10 Apr 2012 11:22:01 UTC Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Message: Object doesn't support this property or method Line: 1041 Char: 25 Code: 0 URI: http://example.com/? Note: : Error copied directly from debugger of IE8

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  • regular expression not behaving as expected - Python

    - by philippe
    I have the following function which is supposed to read a .html file and search for <input> tags, and inject a <input type='hidden' > tag into the string to be shown into the page. However, that condition is never met:( e.g the if statement is never executed. ) What's wrong with my regex? def print_choose( params, name ): filename = path + name f = open( filename, 'r' ) records = f.readlines() print "Content-Type: text/html" print page = "" flag = True for record in records: if re.match( '<input*', str(record) ) != None: print record page += record page += "<input type='hidden' name='pagename' value='psychology' />" else: page += record print page Thank you

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  • How to escape regular expression in javascript ?

    - by Relax
    My codes is like pattern = 'arrayname[1]'; // fetch from dom, make literal here just for example reg = new RegExp(RegExp.quote(pattern), 'g'); mystring.replace(reg, 'arrayname[2]'); But it just cannot get running with error message says: "RegExp.quote is not a function", am i missing something simple?

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  • Javascript: regular expression

    - by Dmitry Nesteruk
    I need to replace a substring from some string. I've already created corrected code for doing it. But I amn't sure is it best way. Please, see code below: var str = 'test ruby,ruby on rails,ruby,' var substr = 'ruby'; var reg = new RegExp(',' + substr + ',|^' + substr + ',', 'gi'); str.replace(reg, ','); //returns "test ruby,ruby on rails,"

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  • Java regular expression: how to include '-'

    - by changed
    I am using this pattern and matching a string. String s = "//name:value /name:value"; if (s.matches("(//?\\s*\\w+:\\w+\\s*)+")) { // it fits } This works properly. But if I want to have a string like "/name-or-address:value/name-or-address:value" which has this '-' in second part, it doesn't work. I am using \w to match A-Za-z_, but how can I include - in that?

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  • Regular Expression: Allow letters, numbers, and spaces (with at least one letter or number)

    - by makeee
    I'm currently using this regex ^[A-Z0-9 _]*$ to accept letters, numbers, spaces and underscores. I need to modify it to require at least one number or letter somewhere in the string. Any help would be appreciated! This would be for validating usernames for my website. I'd actually like to support as many characters as I can, but just want to ensure that I prevent code injection and that characters will display fine for all users. So I'm definately open to regex validation suggestions that would support a wider set of characters.

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  • Pick up relevant information from a string using regular expression C#3.0

    - by Newbie
    Hi, I have a situation. I have been given some file name which can be like <filename>YYYYMMDD<fileextension> some valid file names that will satisfy the above pattern are as under xxx20100326.xls, xxx2v20100326.csv, x_20100326.xls, xy2z_abc_20100326_xyz.csv, abc.xyz.20100326.doc, ab2.v.20100326.doc, abc.v.20100326_xyz.xls In what ever be the above defined case, I need to pick up the dates only. So for all the cases, the output will be 20100326. I am trying to achieve the same but no luck. Here is what I have done so far string testdata = "x2v20100326.csv"; string strYYYY = @"\d{4}"; string strMM = @"(1[0-2]|0[1-9])"; string strDD = @"(3[0-1]|[1-2][0-9]|0[1-9])"; string regExPattern = @"\A" + strYYYY + strMM + strDD + @"\Z"; Regex regex = new Regex(regExPattern); Match match = regex.Match(testdata); if (match.Success) { string result = match.Groups[0].Value; } I am using c#3.0 and dotnet framework 3.5 Please help. It is very urgent Thanks in advance.

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  • Perl Regular Expression [] for <>

    - by bmucklow
    So I am trying to read an XML file into a string in Perl and send it as part of a SOAP message. I know this is not ideal as there are methods for SOAP sending files, however, I am limited to having to use the SOAP that is set up, and it is not set up for sending with file support. Therefore I need to parse out the markup tags < and replace them with []. What is the best way to do this?

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  • Regular expression for a string containing one word but not another

    - by Chris Stahl
    I'm setting up some goals in Google Analytics and could use a little regex help. Lets say I have 4 URLs http://www.anydotcom.com/test/search.cfm?metric=blah&selector=size&value=1 http://www.anydotcom.com/test/search.cfm?metric=blah2&selector=style&value=1 http://www.anydotcom.com/test/search.cfm?metric=blah3&selector=size&value=1 http://www.anydotcom.com/test/details.cfm?metric=blah&selector=size&value=1 I want to create an expression that will identify any URL that contains the string selector=size but does NOT contain details.cfm I know that to find a string that does NOT contain another string I can use this expression: (^((?!details.cfm).)*$) But, I'm not sure how to add in the selector=size portion. Any help would be greatly appreciated!

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  • VB.net Regular Expression

    - by xzerox
    Alright so I want to grab the information on a website thats between [usernames] and [/usernames] I know how to get the string but how would I use regex to only have the information in the middle. Remember I am going to be having more then one thing on the page.

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  • Regular expression on a URL

    - by alphaexe
    I need to be able to catch when the URL contains a image of multiple file types or follow this syntax. http://localhost:8080/fdlic-web/webpic/101 Here is what i have so far. (.*)(jpg|gif|png|bmp|jpeg|webpic/(\d+))$

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  • Php regular expression to match a div

    - by Thoman
    Hello all <div id="a"> <div id="b"> Foo </div> <div id="m"> Bar </div> </div> <div id="c"> Bar </div> I want find all object in id="a" and out put is <div id="a"> <div id="b"> Foo </div> <div id="m"> Bar </div> </div> Geat thanks.

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  • PHP Regular Expression to quotations to attributes

    - by atwellpub
    hey Guys, I need to run a string of html through a regex function that checks to see if the attributes are closed in quotes, and if they aren't then close them. for example i want <img src=http://www.domain.com/image.gif border=0> to turn into <img src='http://www.domain.com/image.gif' border='0'> Can anyone help me?

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  • Regular expression matching in php

    - by user1836428
    I have this regexp: /(.*)(([0-9]([^a-zA-Z])*){7,}[0-9])(.*)/. Given the following values 0654535263 065453-.-5263 065asd4535263 Expected Results 06**** 06**** 06**** Actual Results 0654535263 06**** 065asd4535263 It does not match the last row because of the letters (I want to match from 0-3 letters) and it matches only last occurence (in the second row in example, it skips first row).

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  • regular expression for validation not working

    - by Camran
    I have a "description textarea" inside a form where user may enter a description for an item. This is validated with javascript before the form beeing submitted. One of the validation-steps is this: else if (!fld.value.match(desExp)){ And desExp: var desExp = /^\s*(\w[^\w]*){3}.*$/gm; Now my problem, this works fine on all cases except for descriptions where the description BEGINS with a special character of the swedish language (å, ä, ö). This wont work: åäö hello world But this will: hello world åäö Any fixes? Thanks

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  • Regular Expression Program

    - by david robers
    Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

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