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• Applet User-agent

  - by Jonathan Barbero

  Hello! This is a simple question, but I didn´t found any documentation about this. When an applet makes a request, how is the user agent of the request. I want to know the applet user-agent expression to detect if a request comes from an applet. I make two test, with IE7 and Firefox 3.0.5 with JDK 1.6.0_03 and the user agent was "Mozilla/4.0 (Windows 2003 5.2) Java/1.6.0_03" in both, but I can´t generalize from two test. Thanks in advance, Jonathan.

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• Gamepad Control for Processing + Android to Control Arduino Robot

  - by Iker

  I would like to create a Multitouch Gamepad control for Processing and use it to control a remote Arduino Robot. I would like to make the GUI on Processing and compile it for Android. Here is the GUI Gamepad for Processing I have created so far: float easing = 0.09; // start position int posX = 50; int posY = 200; // target position int targetX = 50; int targetY = 200; boolean dragging = false; void setup() { size(500,250); smooth(); } void draw() { background(255); if (!dragging) { // calculate the difference in position, apply easing and add to vx/vy float vx = (targetX - (posX)) * easing; float vy = (targetY - (posY)) * easing; // Add the velocity to the current position: make it move! posX += vx; posY += vy; } if(mousePressed) { dragging = true; posX = mouseX; posY = mouseY; } else { dragging = false; } DrawGamepad(); DrawButtons(); } void DrawGamepad() { //fill(0,155,155); //rect(0, 150, 100, 100, 15); ellipseMode(RADIUS); // Set ellipseMode to RADIUS fill(0,155,155); // Set fill to blue ellipse(50, 200, 50, 50); // Draw white ellipse using RADIUS mode ellipseMode(CENTER); // Set ellipseMode to CENTER fill(255); // Set fill to white// ellipse(posX, posY, 35, 35); // Draw gray ellipse using CENTER mode } void DrawButtons() { fill(0,155,155); // Set fill to blue ellipse(425, 225, 35, 35); ellipse(475, 225, 35, 35); fill(255,0,0); // Set fill to blue ellipse(425, 175, 35, 35); ellipse(475, 175, 35, 35); } I have realized that probably that code will not support Multitouch events on Android so I came up with another code found on this link Can Processing handle multi-touch? So the aim of this project is to create de multitouch gamepad to use to control my Arduino Robot. The gamepad should detect which key was pressed as well as the direction of the Joystick. Any help appreciated.

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• Best source control system for maintaining different versions

  - by dalecooper

  Hi all! We need to be able to simultanously maintain a set of different versions of our system. I assume this is best done using branching. We currently use TFS2008 for source control, work items and automatic builds. What is the best version control solution for this task? Our organization is in the process of merging to TFS2010. Will TFS2010 give us the functionality we need to easily manage a series of branches per system version. We need to be able to keep each version isolated from the others, so that we can do testing deployment for each version. Our dev team consists of 5 .net developers and two flash developers. I have heard a lot of talk about GIT. Should we consider using GIT instead of TFS for source control? Is it possible to use TFS2010 together with GIT? Does anyone have similar setups that works nicely? Any sugggestions are appreciated! Thanks, Kjetil.

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• Stored Procedures In Source Control - Automate Build/Deployment Process

  - by Alex

  My company provides a large .NET service-oriented solution. The services layer interact with a T-SQL back-end consisting of hundreds of tables and stored procedures. Our C# code is in version-control (SVN) but our stored procedures and schema are not. After much lobbying of expedient upper-management, I was allowed to review our (non-existent) build/deployment process to accomplish the following goals: Place schema and stored procedures under source-control. Automate the build/deployment process. I would like to proceed per the accepted answer's strategy in this post but have additional questions: I would like to use Hudson as my build server. Is this a reasonable choice for a C#/SQL solution? What better alternatives should I explore? Assuming I have all triggers, stored-procedures, schema, etc... under source control, and that they are scripted to individual files, how do I generate a build script which will take into account dependencies/references between these items? (SQL Server does this automatically, but it generates one giant script) What does the workflow of performing an update at the client look like? i.e. I have to keep existing table data. How do I roll-back schema changes? I am the only programmer. Several other pseudo-technical staff like to make changes directly inside SQL Management Studio. Is it realistic to expect others to adhere to this solution -- how can I enforce this? Thank you in advance for your help.

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• ASP.NET - Exception logging approach for concurrent user scenario

  - by Whiskey-Tango-Foxtrot

  I am involved in designing a asp.net webforms application using .NET 3.5. I have a requirement where we need to log exceptions. What is the best approach for exception handling, given that there would be concurrent users for this application? Is there a need or possibility to log in exceptions at a user level? My support team in-charge wants to have a feature where the support team can get user specific log files. To give you a background, this application is currently on VB 6.0 and we are migrating it along with some enhancements. So, today the support personnel have a provision to get user specific log files.

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• ssh - "Connection closed by xxx.xxx.xxx.xxx" - using password

  - by Michael B

  I attempted to create an new user account that I wish to use to log in using ssh. I did this (in CentOs): /usr/sbin/adduser -d /home/testaccount -s /bin/bash user passwd testaccount This is the error I receive when trying to log in via ssh: ~/.ssh$ ssh -v [email protected] OpenSSH_5.1p1 Debian-5ubuntu1, OpenSSL 0.9.8g 19 Oct 2007 debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug1: Connecting to xxx.xxx.xxx [xxx.xxx.xxx.xxx] port 22. debug1: Connection established. debug1: identity file /home/user/.ssh/identity type -1 debug1: identity file /home/user/.ssh/id_rsa type 1 debug1: Checking blacklist file /usr/share/ssh/blacklist.RSA-2048 debug1: Checking blacklist file /etc/ssh/blacklist.RSA-2048 debug1: identity file /home/user/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_4.3 debug1: match: OpenSSH_4.3 pat OpenSSH_4* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.1p1 Debian-5ubuntu1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-cbc hmac-md5 none debug1: kex: client->server aes128-cbc hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'xxx.xxx.xxx.xxx' is known and matches the RSA host key. debug1: Found key in /home/user/.ssh/known_hosts:8 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Next authentication method: gssapi-with-mic debug1: Unspecified GSS failure. Minor code may provide more information No credentials cache found debug1: Unspecified GSS failure. Minor code may provide more information No credentials cache found debug1: Unspecified GSS failure. Minor code may provide more information debug1: Next authentication method: publickey debug1: Offering public key: /home/user/.ssh/id_rsa debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Trying private key: /home/user/.ssh/identity debug1: Trying private key: /home/user/.ssh/id_dsa debug1: Next authentication method: password testaccount@xxx's password: Connection closed by xxx.xxx.xxx.xxx The "connection closed" message appeared immediately after entering the password (if I enter the wrong password it waits and then prompts for another password) I am able to log in from the same computer using other accounts that had been setup previously. When logged into the remote machine I am able to do 'su testaccount' Thanks for your time.

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• C++ Detecting ENTER key pressed by user

  - by user69514

  I have a loop where I ask the user to enter a name. I need to stop when the user presses the ENTER key..... or when 20 names have been entered. However my method doesn't stop when the user presses the ENTER key //loop until ENTER key is entered or 20 elements have been added bool stop = false; int ind = 0; while( !stop || ind >= 20 ){ cout << "Enter name #" << (ind+1) << ":"; string temp; getline(cin, temp); int enterKey = atoi(temp.c_str()); if(enterKey == '\n'){ stop = true; } else{ names[ind] = temp; } ind++; }

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• How do I create a user history?

  - by ggfan

  I want to create a user history function that allows shows users what they done. ex: commented on an ad, posted an ad, voted on an ad, etc. How exactly do I do this? I was thinking about... in my site, when they log in it stores their user_id ($_SESSION['user_id']) so I guess whenever an user posts an ad(postad.php), comments(comment.php), I would just store in a database table "userhistory" what they did based on whenever or not their user_id was activate. When they comment, I store the user_id in the comment dbc table, so I'll also store it in the "userhistory" table. And then I would just queries all the rows in the dbc for the user to show it Any steps/improvements I can make? :)

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• Storing user settings in table - how?

  - by Mdillion

  I have settings for the user about 200 settings, these include notice settings and tracing settings from user activities on objects. The problem is how to store it in the DB? Should each setting be a row or a column? If colunm then table will have 200 colunms. If row then about 3 colunms but 200 rows per user x even 10 million users = not good. So how else can i store all these settings? NOTE: these settings are a mix of text entry and FK lookups to other tables. Thanks.

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• Django admin panel doesn't work after modify default user model.

  - by damienix

  I was trying to extend user profile. I founded a few solutions, but the most recommended was to create new user class containing foreign key to original django.contrib.auth.models.User class. I did it with this so i have in models.py: class UserProfile(models.Model): user = models.ForeignKey(User, unique=True) website_url = models.URLField(verify_exists=False) and in my admin.py from django.contrib import admin from someapp.models import * from django.contrib.auth.admin import UserAdmin # Define an inline admin descriptor for UserProfile model class UserProfileInline(admin.TabularInline): model = UserProfile fk_name = 'user' max_num = 1 # Define a new UserAdmin class class MyUserAdmin(UserAdmin): inlines = [UserProfileInline, ] # Re-register UserAdmin admin.site.unregister(User) admin.site.register(User, MyUserAdmin) And now when I'm trying to create/edit user in admin panel i have an error: "Unknown column 'content_userprofile.id' in 'field list'" where content is my appname. I was trying to add line AUTH_PROFILE_MODULE = 'content.UserProfile' to my settings.py but with no effect. How to tell panel admin to know how to correctly display fields in user form?

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• How do I reinstate my admin user privileges to global read/write

  - by Matt

  I am running Ubuntu 12.04 LTS. I only have the one user which I created when I installed Ubuntu. Everything has been fine - love it - until I updated a software package recently from the command line using sudo (not gksudo). I was having a little bother which did not make sense to me and in a fluff changed my user read/write privileges through the GUI (not even clear how I got there!). After restart I was stuck in a login loop - using the right login password but kept getting looped back to the login and could only login as Guest. I could still login with my user/password via ctrl + alt + f1 Eventually I was able to login again at start up. Not sure exactly what it was I changed that worked but it was one of/or a combination of installing latest security updates, changing login manager from LightDM to DGM and back again, removing the ICE/Xauthority and chown user. Current dilemma is my primary admin user privileges were read only. In the command line ls -ls /home/user returned this value: drwx------ 48 username username 20480 I have since changed this using sudo chmod 0755 /home/username (from my limited understanding 755 should return my user privileges to their original read/write glory). ls -ld /home/user currently shows my user privileges as: drwxr-xr-x 48 username username 20480 I still seem to have only read access permissions. I've been through lots of threads (and the help file) that talk about creating new users/groups permissions etc. but specific info on returning my existing global/admin/primary users privileges to what they were when I first created that user - baffling me. I feel this is something really simple I'm just not getting it. Please help! sudo mount /dev/sda1 on / type ext4 (rw,errors=remount-ro) proc on /proc type proc (rw,noexec,nosuid,nodev) sysfs on /proc type sysfs (rw,noexec,nosuid,nodev) none on /sys/fs/fuse/connections type fusect1 (rw) none on /sys/kernel/debug type debugfs (rw) none on /sys/kernel/security type securityfs (rw) udev on /dev type devtmpfs (rw,mode=07pe tmpfs55) devpts on /dev/pts type devpts (rw,noexec,nosuid,gid=5,mode=0620) tmpfs on /run type tmpfs (rw,noexec,nosuid,size=10%,mode=0755) none on /run/lock type tmpfs (rw, ,nosuid,nodev,size=5242880 none on /run/shm type tmpfs (rw,nosuid,nodev) gvfs-fuse-daemon on /home/meng/.gvfs type fuse.gvfs-fuse-daemon (rw,nosuid,nodev,user=meng) none on /tmp/guest-1R2Fi5 type tmpsf (rw,mode=700)

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• Having an issue with overwriting an element of a file correctly (numeric)

  - by IngeniousHax

  This is an ATM style program, but currently it doesn't do exactly what I need it to do... I need to get the current balance, and when money is transferred from either checking or savings, it should add it to checking and subtract it from savings. which is does, but not correctly... Input example -=[ Funds Transfer ]=- -=[ Savings to Checking ]=- Account Name: nomadic Amount to transfer: $400 New Balance in Checking: $900 // original was 500 New Balance in Savings: $7.7068e+012 // this should now be 1100... Here is my code, it's a lot of code, but there are no errors, so throwing it into an IDE and compiling should be fairly quick for whoever would like to help. mainBankClass.h mainBankClass.h #ifndef MAINBANKCLASS_H #define MAINBANKCLASS_H #include <iostream> #include <fstream> #include <string> using namespace std; class Banking { protected: string checkAcctName, saveAcctName; // Name on the account int acctNumber[13]; // Account number float acctBalance, initSaveDeposit, initCheckDeposit, depAmt; // amount in account, and amount to deposit public: char getBalanceChoice(); // Get name on account for displaying relevant information char newAccountMenu(); // Create a new account and assign it a random account number void invalid(char *); // If an invalid option is chosen char menu(); // Print the main menu for the user. virtual float deposit(){ return 0; } // virtual function for deposits // virtual float withdrawal() = 0; // Virtual function for withdrawals void fatal(char *); // Handles fatal errors. Banking(); }; class Checking : public Banking { public: friend ostream operator<<(ostream &, Checking &); friend istream operator>>(istream &, Checking &); Checking operator <= (const Checking &) const; void newCheckingAccount(); void viewCheckingBalance(); void transferFromSaving(); float deposit() { return (acctBalance += depAmt); } }; class Saving : public Banking { public: friend ostream &operator<<(ostream &, Saving &); friend istream &operator>>(istream &, Saving &); Saving operator <= (const Saving &) const; void newSavingAccount(); void viewSavingBalance(); void transferFromChecking(); float deposit() { return (acctBalance += depAmt); } }; class checkAndSave : public Banking { public: void newCheckAndSave(); void viewBothBalances(); }; #endif bankAccount.cpp #include <iostream> #include <sstream> #include <string> #include <iomanip> #include <fstream> #include <time.h> #include "MainBankClass.h" /*****************************\ | BANKING CONSTRUCTOR | \*****************************/ Banking::Banking() { string acctName; // Name on the account acctNumber[13] = 0; // Account number acctBalance = 0; initCheckDeposit = 0; initSaveDeposit = 0; depAmt = 0; }; /********************************\ | The following code is to print the menu | | and recieve the users choice on what | | they want to do with the ATM | \********************************/ char Banking::menu() { char choice; system("cls"); cout << "\t\t -=[ Main Menu ]=- \n\n" << "\tA) Create New Account\n" << "\tB) View Account Balance\n" << "\tC) Transfer Funds From Checking To Savings\n" << "\tD) Transfer Funds From Savings To Checking\n" << "\tE) Exit\n" << "\n\n\tSelection: "; cin >> choice; cin.ignore(); choice = toupper(choice); while(!isalpha(choice)) { invalid("[!!] Invalid selection.\n[!!] Choose a valid option: "); cin >> choice; cin.ignore(); } return choice; } /*********************\ | Will read in account choic | | and display it for the user | \*********************/ char Banking::getBalanceChoice() { char choice; fstream saveFile("saving.dat", ios::in | ios::beg); system("cls"); cout << "\t\t -=[ View Account Balance ]=-\n\n"; cout << "A) View Checking Account\n" << "B) View Saving Account\n" << "C) View Checking \\ Saving Account\n" << endl; cout << "Choice: "; cin >> choice; choice = toupper(choice); if(!isalpha(choice)) fatal(" [!!] Invalid Choice"); return choice; } /***************************\ | Incase an invalid decision to made | | this throws the error message sent | | to it by the calling area | \***************************/ void Banking::invalid(char *msg) { cout << msg; } /*************************\ | Used if files can not be opened | | and exits with code 251: | | miscommunication with server | \*************************/ void Banking::fatal(char *msg) { cout << msg; exit(1); } /***************************\ | Create an account, either checking | | or savings, or both. | | Must should create a randomly | | generated account number that will | | correspond with each account. | \***************************/ /************************\ NOTE:: WILL BE UPDATED TO CONTAIN A PIN FOR ACCOUNT VERIFICATION *************************/ char Banking::newAccountMenu() { srand(time(NULL)); // Seed random generator with time initialized to NULL char acctChoice; // choice for the account type ofstream checkFile("checking.dat", ios::out | ios::app); // For saving checking accounts ofstream saveFile("saving.dat", ios::out | ios::app); // For saving savings accounts system("cls"); cout << "\t\t-=[ New Account Creation ]=-\n\n" << endl; cout << "A) Checking Account\n" << "B) Savings Account\n" << "C) Checking and Saving Account\n" << endl; cout << "New account type: "; cin >> acctChoice; acctChoice = toupper(acctChoice); cin.clear(); cin.sync(); return acctChoice; } /********************************************************************* ********************************************************************** CHECKING ACCOUNT CODE ********************************************************************** **********************************************************************/ // New Checking Account Creation void Checking::newCheckingAccount() { system("cls"); ofstream checkFile("checking.dat", ios::out | ios::app); // For saving checking accounts cout << "\t\t -=[ New Checking Account ]=- \n" << endl; cout << "Name of the main holder to be on the account: "; getline(cin, checkAcctName); cout << "Initial deposit amount: $"; cin >> initCheckDeposit; if(initCheckDeposit <= 0) { while(initCheckDeposit <= 0) { invalid("[!!] 0 or negative amount entered\nMaybe a typo?\n"); cout << "Deposit Amount: $"; cin >> initCheckDeposit; } } if(!checkFile) fatal("[!!] Fatal Error 251: Miscommunication with server\n"); checkFile << checkAcctName << endl; for(int j = 0; j < 13; j++) { acctNumber[j] = (rand() % 10); // Build a random checking account number checkFile << acctNumber[j]; } checkFile << endl; checkFile << initCheckDeposit << endl; checkFile.close(); } void Checking::viewCheckingBalance() { fstream checkFile("checking.dat", ios::in | ios::beg); string name; int i = 0; double balance = 0; system("cls"); cout << "\t\t -=[ View Checking Account ]=-\n\n" << endl; cout << "Account Name: "; cin.sync(); getline(cin, name); getline(checkFile, checkAcctName); while(name != checkAcctName && !checkFile.fail()) { i++; getline(checkFile, checkAcctName); } if(name == checkAcctName) { system("cls"); cout << "\t\t -=[ Checking Account Balance ]=-\n\n" << endl; cout << "Account Name: " << checkAcctName << "\n"; cout << "Account Number: "; for(int j = 0; j < 13; j++) { char input_number; stringstream converter; checkFile.get(input_number); converter << input_number; converter >> acctNumber[j]; cout << acctNumber[j]; } // if balance a problem, try the below commented out line // checkFile.ignore(numeric_limits<streamsize>::max(), '\n'); cout << endl; checkFile >> acctBalance; cout << "Balance: $" << fixed << showpoint << setprecision(2) << acctBalance << endl; } else fatal("[!!] Invalid Account\n"); checkFile.close(); getchar(); } void Checking::transferFromSaving() // Move funds FROM SAVINGS to CHECKING { system("cls"); string name; long checkPos = 0; long savePos = 0; float savingBalance = 0; string saveAcctName; int i = 0; cin.clear(); fstream saveFile("saving.dat", ios::in | ios::out | ios::beg); fstream checkFile("checking.dat", ios::in | ios::out | ios::beg); cout << "\t\t-=[ Funds Transfer ]=-" << endl; cout << "\t\t-=[ Savings to Checking ]=-" << endl; cout << "Account Name: "; cin.sync(); getline(cin, name); getline(checkFile, checkAcctName); while(name != checkAcctName && !checkFile.fail()) { i++; getline(checkFile, checkAcctName); } getline(saveFile, saveAcctName); while(name != saveAcctName && !saveFile.fail()) { i = 0; i++; getline(saveFile, saveAcctName); } if(name == checkAcctName) { cout << "Amount to transfer: $"; float depAmt = 0; cin >> depAmt; for(int j = 0; j < 13; j++) { char input_number; stringstream converter; checkFile.get(input_number); converter << input_number; converter >> acctNumber[j]; } checkPos = checkFile.tellg(); // if the file is found, get the position of acctBalance and store it in ptrPos checkFile.seekg(checkPos); checkFile >> acctBalance; savePos = saveFile.tellg(); saveFile.seekg(savePos); // sending the cursor in the file to ptrPos + 1 to ignore white space saveFile >> savingBalance; if(savingBalance < depAmt) // if checking account does not have enough funds, exit with NSF code fatal("[!!] Insufficient Funds\n"); acctBalance += depAmt; // can be changed to an overloaded operator savingBalance -= depAmt; // can be changed to an overloaded operator checkFile.seekp(checkPos); // go to position previously set above checkFile << acctBalance; // write new balance to checkFile saveFile.seekp(savePos); // same thing as above comment saveFile << savingBalance; // write new balance to saveFile cout << "New Balance in Checking: $" << acctBalance << endl; // will be removed later cout << "New Balance in Savings: $" << savingBalance << endl; // will be removed later aswell } else fatal("[!!] Linked accounts do not exist.\n"); // if account is not found saveFile.close(); checkFile.close(); } /******************************************************** ******************************************************** SAVING ACCOUNT CODE ********************************************************* *********************************************************/ void Saving::newSavingAccount() { system("cls"); ofstream saveFile("saving.dat", ios::out | ios::app); // For saving savings accounts cout << "\t\t -=[ New Savings Account ]=- \n" << endl; cout << "Name of the main holder to be on account: "; getline(cin, saveAcctName); cout << "Deposit Amount: $"; cin >> initSaveDeposit; if(initSaveDeposit <= 0) { while(initSaveDeposit <= 0) { invalid("[!!]0 or negative value entered.\nPerhaps a typo?\n"); cout << "Deposit amount: $"; cin >> initSaveDeposit; } } if(!saveFile) fatal("[!!] Fatal Error 251: Miscommunication with server\n"); saveFile << saveAcctName << endl; for(int j = 0; j < 13; j++) { acctNumber[j] = (rand() % 10); saveFile << acctNumber[j]; } saveFile << endl; saveFile << initSaveDeposit << endl; saveFile.close(); } void Saving::viewSavingBalance() { string name; int i = 0; fstream saveFile("saving.dat", ios::in | ios::beg); cin.clear(); system("cls"); cout << "\t\t -=[ View Saving Account ]=-\n\n" << endl; cout << "Account Name: "; cin.sync(); getline(cin, name); getline(saveFile, saveAcctName); while(name != saveAcctName && !saveFile.fail()) { i++; getline(saveFile, saveAcctName); } if(name == saveAcctName) { system("cls"); cout << "\t\t -=[ Saving Account Balance ]=-\n\n" << endl; cout << "Account Name: " << saveAcctName << "\n"; cout << "Account Number: "; for(int j = 0; j < 13; j++) { char input_number; stringstream converter; saveFile.get(input_number); converter << input_number; converter >> acctNumber[j]; cout << acctNumber[j]; } // if balance a problem, try the below commented out line // checkFile.ignore(numeric_limits<streamsize>::max(), '\n'); cout << endl; saveFile >> acctBalance; cout << "Balance: $" << fixed << showpoint << setprecision(2) << acctBalance << endl; } else fatal("[!!] Invalid Account\n"); saveFile.close(); getchar(); } // NEED TO WORK ON THIS PORTION TOMORROW AND MONDAY, ADD OVERLOADED OPS FOR ASSIGNMENT!!!!!!! void Saving::transferFromChecking() // This is to take money FROM checking and ADD IT TO SAVING { system("cls"); string name; long savePos = 0; long checkPos = 0; float checkingBalance = 0; string checkAcctName; int i = 0; cin.clear(); fstream saveFile("saving.dat", ios::in | ios::out | ios::beg); fstream checkFile("checking.dat", ios::in | ios::out | ios::beg); cout << "\t\t-=[ Funds Transfer ]=-" << endl; cout << "\t\t-=[ Checking to Savings ]=-" << endl; cout << "Account Name: "; cin.sync(); getline(cin, name); getline(saveFile, saveAcctName); getline(checkFile, checkAcctName); while(name != saveAcctName && name != checkAcctName && !saveFile.fail() && !checkFile.fail()) { i++; getline(saveFile, saveAcctName); getline(checkFile, checkAcctName); } if(name == saveAcctName) { cout << "Amount to transfer: $"; float depAmt = 0; cin >> depAmt; for(int j = 0; j < 13; j++) { char input_number; stringstream converter; saveFile.get(input_number); converter << input_number; converter >> acctNumber[j]; } savePos = saveFile.tellg(); // if the file is found, get the position of acctBalance and store it in ptrPos saveFile.seekg(savePos); saveFile >> acctBalance; checkPos = checkFile.tellg(); checkFile.seekg(checkPos); // if file is found, store current position of the cursor to ptrPos checkFile >> checkingBalance; if(checkingBalance < depAmt) // if checking account does not have enough funds, exit with NSF code fatal("[!!] Insufficient Funds\n"); // Can also place overloaded op here acctBalance += depAmt; // can be changed to an overloaded operator checkingBalance -= depAmt; // can be changed to an overloaded operator saveFile.seekg(savePos); // go to position previously set above saveFile << acctBalance; // write new balance to saveFile checkFile.seekg(checkPos); // same thing as above comment checkFile << checkingBalance; // write new balance to checkFile cout << "New Balance in Savings: $" << acctBalance << endl; // will be removed later cout << "New Balance in Checking: $" << checkingBalance << endl; // will be removed later aswell } else fatal("[!!] Linked accounts do not exist.\n"); // if account is not found saveFile.close(); checkFile.close(); } /******************************************** ******************************************** CHECK AND SAVE CODE ********************************************** **********************************************/ void checkAndSave::newCheckAndSave() { system("cls"); ofstream saveFile("saving.dat", ios::out | ios::app); // For saving savings accounts ofstream checkFile("checking.dat", ios::out | ios::app); // For saving checking accounts cout << "\t -=[ New Checking & Saving Account ]=- \n" << endl; cout << "Name of the main holder to be on account: "; getline(cin, checkAcctName); saveAcctName = checkAcctName; cout << "Checking Deposit Amount: $"; cin >> initCheckDeposit; if(initCheckDeposit <= 0) { while(initCheckDeposit <= 0) { invalid("[!!] 0 or negative amount entered\nMaybe a typo?\n"); cout << "Deposit Amount: $"; cin >> initCheckDeposit; } } cout << "Saving Deposit Amount: $"; cin >> initSaveDeposit; if(initSaveDeposit <= 0) { while(initSaveDeposit <= 0) { invalid("[!!]0 or negative value entered.\nPerhaps a typo?\n"); cout << "Deposit amount: $"; cin >> initSaveDeposit; } } if(!saveFile || !checkFile) fatal("[!!] Fatal Error 251: Miscommunication with server\n"); checkFile << checkAcctName << endl; saveFile << saveAcctName << endl; for(int j = 0; j < 13; j++) { acctNumber[j] = (rand() % 10); checkFile << acctNumber[j]; saveFile << acctNumber[j]; } saveFile << endl; saveFile << initSaveDeposit << endl; checkFile << endl; checkFile << initCheckDeposit << endl; checkFile.close(); saveFile.close(); } void checkAndSave::viewBothBalances() { string name; int i = 0; fstream checkFile("checking.dat", ios::in | ios::beg); fstream saveFile("saving.dat", ios::in | ios::beg); system("cls"); cin.clear(); cout << "\t-=[ Saving & Checking Account Balance ]=-\n\n" << endl; cout << "Account Name: "; cin.sync(); getline(cin, name); getline(checkFile, checkAcctName); saveAcctName = name; /**********************\ | Checking Account portion | | of the checking & savings | | overview | \**********************/ while(name != checkAcctName && !checkFile.fail()) { i++; getline(checkFile, checkAcctName); } system("cls"); if(name != checkAcctName && checkFile.fail()) invalid("\n\n[!!] No Checking Account Found\n"); cout << "\t\t -=[ Checking Account ]=- \n" << endl; cout << "Account Name: " << checkAcctName << "\n"; cout << "Account Number: "; for(int j = 0; j < 13; j++) { char input_number; stringstream converter; checkFile.get(input_number); converter << input_number; converter >> acctNumber[j]; cout << acctNumber[j]; } // if balance a problem, try the below commented out line // checkFile.ignore(numeric_limits<streamsize>::max(), '\n'); cout << endl; checkFile >> acctBalance; cout << "Balance: $" << fixed << showpoint << setprecision(2) << acctBalance << endl; /*********************\ | Saving Account portion | | of the checking & saving | | overview | \*********************/ getline(saveFile, saveAcctName); while(name != saveAcctName && !saveFile.fail()) { i++; getline(saveFile, saveAcctName); } if(name != saveAcctName && saveFile.fail()) invalid("\n\n[!!] No Saving Account Found\n"); if(name == saveAcctName) { cout << "\t\t -=[ Saving Account ]=-\n\n" << endl; cout << "Account Name: " << saveAcctName << "\n"; cout << "Account Number: "; for(int j = 0; j < 13; j++) { char input_number; stringstream converter; saveFile.get(input_number); converter << input_number; converter >> acctNumber[j]; cout << acctNumber[j]; } // if balance a problem, try the below commented out line // checkFile.ignore(numeric_limits<streamsize>::max(), '\n'); cout << endl; saveFile >> acctBalance; cout << "Balance: $" << fixed << showpoint << setprecision(2) << acctBalance << endl; } if(name != saveAcctName && name != checkAcctName && saveFile.fail() && checkFile.fail()) fatal("[!!] No Accounts Have Been Found\n"); checkFile.close(); saveFile.close(); getchar(); } Main.cpp #include <iostream> #include "MainBankClass.h" using namespace std; int main() { Banking bank; Checking check; Saving save; checkAndSave CanS; char choice; choice = bank.menu(); // Call the banking menu switch(choice) { case 'A': choice = bank.newAccountMenu(); switch(choice) { case 'A': check.newCheckingAccount(); break; case 'B': save.newSavingAccount(); break; case 'C': CanS.newCheckAndSave(); break; default: system("cls"); bank.fatal("[!!] Invalid option\n"); break; } break; /***********************************************/ case 'B': choice = bank.getBalanceChoice(); switch(choice) { case 'A': check.viewCheckingBalance(); break; case 'B': save.viewSavingBalance(); break; case 'C': CanS.viewBothBalances(); break; default: bank.fatal("Invalid decision\n"); break; } /*************************************************/ break; case 'C': check.transferFromSaving(); break; case 'D': save.transferFromChecking(); break; case 'E': system("cls"); cout << "\t\t-=[ Disconnecting From System ]=-\n"; cout << "\t\t\t Thank you" << endl; cout << "\t\t Have a nice day!" << endl; exit(1); break; default: system("cls"); bank.invalid("\n\n\n\n\t\t [+] Invalid Selection \n\t\t[+] Disconnecting From System \n\t\t\tGood-bye \n\n\n\n\n\n\n"); exit(1); break; } return 0; }

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• How do you manage the user groups that users are assoicated to in Mac OS X?

  - by Erik Vold

  How do I add/remove users to user groups on Mac OS X 10.5? Like 'bonic_master' for instance.. and out of curiosity how do I create a user group?

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• Which is the simplest way to exclude an user from a launchd agent?

  - by compriots

  I have some launchd plists that are now placed at the administrator per-user level, particularly inside: /Library/LaunchAgents /Library/LaunchDaemons I'd like to avoid that some of those services could start only for one user (possibly avoiding to move all the plists to each ~/Library/LaunchAgents), which is the simplest way? Thanks in advance.

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• How can I transfer a user state of a win7 machine that won't boot?

  - by askvictor

  I have a windows 7 machine that won't boot completely, even in safe mode. I want to re-image the machine using a generic software image, but would like to keep the user data (including settings etc) that are on there ala Windows Easy Transfer. I can mount the hard disk on another machine - can I use Easy Transfer to transfer the user state of an account on the non-booted OS? Or do I need explore USMT?

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• Sql Query - Selecting rows where user can be both friend and user

  - by Gublooo

  Hey Sorry the title is not very clear. This is a follow up to my earlier question where one of the members helped me with a query. I have a following friends Table Friend friend_id - primary key user_id user_id_friend status The way the table is populated is - when I send a friend request to John - my userID appears in user_id and Johns userID appears in user_id_friend. Now another scenario is say Mike sends me a friend request - in this case mike's userID will appear in user_id and my userID will appear in user_id_friend So to find all my friends - I need to run a query to find where my userID appears in both user_id column as well as user_id_friend column What I am trying to do now is - when I search for user say John - I want all users Johns listed on my site to show up along with the status of whether they are my friend or not and if they are not - then show a "Add Friend" button. Based on the previous post - I got this query which does part of the job - My example user_id is 1: SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id = u.user_id and f.user_id_friend = 1 where u.name like '%' So this only shows users with whom I am friends where they have sent me request ie my userID appears in user_id_friend. Although I am friends with others (where my userID appears in user_id column) - this query will return that as null To get those I need another query like this SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id_friend = u.user_id and f.user_id = 1 where u.name like '%' So how do I combine these queries to return 1 set of users and what my friendship status with them is. I hope my question is clear Thanks

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• Why do I get Detached Entity exception when upgrading Spring Boot 1.1.4 to 1.1.5

  - by mmeany

  On updating Spring Boot from 1.1.4 to 1.1.5 a simple web application started generating detached entity exceptions. Specifically, a post authentication inteceptor that bumped number of visits was causing the problem. A quick check of loaded dependencies showed that Spring Data has been updated from 1.6.1 to 1.6.2 and a further check of the change log shows a couple of issues relating to optimistic locking, version fields and JPA issues that have been fixed. Well I am using a version field and it starts out as Null following recommendation to not set in the specification. I have produced a very simple test scenario where I get detached entity exceptions if the version field starts as null or zero. If I create an entity with version 1 however then I do not get these exceptions. Is this expected behaviour or is there still something amiss? Below is the test scenario I have for this condition. In the scenario the service layer that has been annotated @Transactional. Each test case makes multiple calls to the service layer - the tests are working with detached entities as this is the scenario I am working with in the full blown application. The test case comprises four tests: Test 1 - versionNullCausesAnExceptionOnUpdate() In this test the version field in the detached object is Null. This is how I would usually create the object prior to passing to the service. This test fails with a Detached Entity exception. I would have expected this test to pass. If there is a flaw in the test then the rest of the scenario is probably moot. Test 2 - versionZeroCausesExceptionOnUpdate() In this test I have set the version to value Long(0L). This is an edge case test and included because I found reference to Zero values being used for version field in the Spring Data change log. This test fails with a Detached Entity exception. Of interest simply because the following two tests pass leaving this as an anomaly. Test 3 - versionOneDoesNotCausesExceptionOnUpdate() In this test the version field is set to value Long(1L). Not something I would usually do, but considering the notes in the Spring Data change log I decided to give it a go. This test passes. Would not usually set the version field, but this looks like a work-around until I figure out why the first test is failing. Test 4 - versionOneDoesNotCausesExceptionWithMultipleUpdates() Encouraged by the result of test 3 I pushed the scenario a step further and perform multiple updates on the entity that started life with a version of Long(1L). This test passes. Reinforcement that this may be a useable work-around. The entity: package com.mvmlabs.domain; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; import javax.persistence.Table; import javax.persistence.Version; @Entity @Table(name="user_details") public class User { @Id @GeneratedValue(strategy=GenerationType.AUTO) private Long id; @Version private Long version; @Column(nullable = false, unique = true) private String username; @Column(nullable = false) private Integer numberOfVisits; public Long getId() { return id; } public void setId(Long id) { this.id = id; } public Long getVersion() { return version; } public void setVersion(Long version) { this.version = version; } public Integer getNumberOfVisits() { return numberOfVisits == null ? 0 : numberOfVisits; } public void setNumberOfVisits(Integer numberOfVisits) { this.numberOfVisits = numberOfVisits; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } The repository: package com.mvmlabs.dao; import org.springframework.data.repository.CrudRepository; import com.mvmlabs.domain.User; public interface UserDao extends CrudRepository<User, Long>{ } The service interface: package com.mvmlabs.service; import com.mvmlabs.domain.User; public interface UserService { User save(User user); User loadUser(Long id); User registerVisit(User user); } The service implementation: package com.mvmlabs.service; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.stereotype.Service; import org.springframework.transaction.annotation.Propagation; import org.springframework.transaction.annotation.Transactional; import org.springframework.transaction.support.TransactionSynchronizationManager; import com.mvmlabs.dao.UserDao; import com.mvmlabs.domain.User; @Service @Transactional(propagation=Propagation.REQUIRED, readOnly=false) public class UserServiceJpaImpl implements UserService { @Autowired private UserDao userDao; @Transactional(readOnly=true) @Override public User loadUser(Long id) { return userDao.findOne(id); } @Override public User registerVisit(User user) { user.setNumberOfVisits(user.getNumberOfVisits() + 1); return userDao.save(user); } @Override public User save(User user) { return userDao.save(user); } } The application class: package com.mvmlabs; import org.springframework.boot.SpringApplication; import org.springframework.boot.autoconfigure.EnableAutoConfiguration; import org.springframework.context.annotation.ComponentScan; import org.springframework.context.annotation.Configuration; @Configuration @ComponentScan @EnableAutoConfiguration public class Application { public static void main(String[] args) { SpringApplication.run(Application.class, args); } } The POM: <?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.mvmlabs</groupId> <artifactId>jpa-issue</artifactId> <version>0.0.1-SNAPSHOT</version> <packaging>jar</packaging> <name>spring-boot-jpa-issue</name> <description>JPA Issue between spring boot 1.1.4 and 1.1.5</description> <parent> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-parent</artifactId> <version>1.1.5.RELEASE</version> <relativePath /> <!-- lookup parent from repository --> </parent> <dependencies> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-data-jpa</artifactId> </dependency> <dependency> <groupId>org.hsqldb</groupId> <artifactId>hsqldb</artifactId> <scope>runtime</scope> </dependency> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-test</artifactId> <scope>test</scope> </dependency> </dependencies> <properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> <start-class>com.mvmlabs.Application</start-class> <java.version>1.7</java.version> </properties> <build> <plugins> <plugin> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-maven-plugin</artifactId> </plugin> </plugins> </build> </project> The application properties: spring.jpa.hibernate.ddl-auto: create spring.jpa.hibernate.naming_strategy: org.hibernate.cfg.ImprovedNamingStrategy spring.jpa.database: HSQL spring.jpa.show-sql: true spring.datasource.url=jdbc:hsqldb:file:./target/testdb spring.datasource.username=sa spring.datasource.password= spring.datasource.driverClassName=org.hsqldb.jdbcDriver The test case: package com.mvmlabs; import org.junit.Assert; import org.junit.Test; import org.junit.runner.RunWith; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.boot.test.SpringApplicationConfiguration; import org.springframework.test.context.junit4.SpringJUnit4ClassRunner; import com.mvmlabs.domain.User; import com.mvmlabs.service.UserService; @RunWith(SpringJUnit4ClassRunner.class) @SpringApplicationConfiguration(classes = Application.class) public class ApplicationTests { @Autowired UserService userService; @Test public void versionNullCausesAnExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version Null"); user.setNumberOfVisits(0); user.setVersion(null); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(1L), user.getVersion()); } @Test public void versionZeroCausesExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version Zero"); user.setNumberOfVisits(0); user.setVersion(0L); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(1L), user.getVersion()); } @Test public void versionOneDoesNotCausesExceptionOnUpdate() throws Exception { User user = new User(); user.setUsername("Version One"); user.setNumberOfVisits(0); user.setVersion(1L); user = userService.save(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(1), user.getNumberOfVisits()); Assert.assertEquals(new Long(2L), user.getVersion()); } @Test public void versionOneDoesNotCausesExceptionWithMultipleUpdates() throws Exception { User user = new User(); user.setUsername("Version One Multiple"); user.setNumberOfVisits(0); user.setVersion(1L); user = userService.save(user); user = userService.registerVisit(user); user = userService.registerVisit(user); user = userService.registerVisit(user); Assert.assertEquals(new Integer(3), user.getNumberOfVisits()); Assert.assertEquals(new Long(4L), user.getVersion()); } } The first two tests fail with detached entity exception. The last two tests pass as expected. Now change Spring Boot version to 1.1.4 and rerun, all tests pass. Are my expectations wrong? Edit: This code saved to GitHub at https://github.com/mmeany/spring-boot-detached-entity-issue

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• Struts2 Hibernate Login with User table and group table

  - by J2ME NewBiew

  My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

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• Couldn't drop privileges: User is missing UID (see mail_uid setting)

  - by drecute

  I'm hoping I can use some help. I'm configuring dovecot_ldap, but I can't seem to be able to get dovecot to authenticate the ldap user. Below is my config and log info: hosts = 192.168.128.45:3268 dn = cn=Administrator,cn=Users,dc=company,dc=example,dc=com dnpass = "passwd" auth_bind = yes ldap_version = 3 base = dc=company, dc=example, dc=com user_attrs = sAMAccountName=home=/var/vmail/example.com/%$,uid=1001,gid=1001 user_filter = (&(sAMAccountName=%Ln)) pass_filter = (&(ObjectClass=person)(sAMAccountName=%u)) dovecot.conf # 2.0.19: /etc/dovecot/dovecot.conf # OS: Linux 3.2.0-33-generic x86_64 Ubuntu 12.04 LTS auth_mechanisms = plain login auth_realms = example.com auth_verbose = yes disable_plaintext_auth = no mail_access_groups = mail mail_location = mbox:~/mail:INBOX=/var/mail/%u mail_privileged_group = mail passdb { driver = pam } passdb { driver = passwd } passdb { args = /etc/dovecot/dovecot-ldap.conf.ext driver = ldap } passdb { args = scheme=CRYPT username_format=%u /etc/dovecot/users driver = passwd-file } protocols = " imap pop3" service auth { unix_listener /var/spool/postfix/private/auth { group = postfix mode = 0660 user = postfix } } service imap-login { inet_listener imap { port = 143 } inet_listener imaps { port = 993 ssl = yes } } ssl_cert = </etc/ssl/certs/dovecot.pem ssl_key = </etc/ssl/private/dovecot.pem userdb { driver = passwd } userdb { args = /etc/dovecot/dovecot-ldap.conf.ext driver = ldap } userdb { args = username_format=%u /etc/dovecot/users driver = passwd-file } protocol imap { imap_client_workarounds = tb-extra-mailbox-sep imap_logout_format = bytes=%i/%o mail_plugins = } mail.log Nov 29 10:51:44 mail dovecot: auth-worker: pam(charyorde,10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:44 mail dovecot: auth-worker: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:44 mail dovecot: auth: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:44 mail dovecot: imap-login: Login: user=<charyorde>, method=PLAIN, rip=10.10.1.28, lip=10.10.1.30, mpid=1892, TLS Nov 29 10:51:44 mail dovecot: imap(charyorde): Error: user charyorde: Couldn't drop privileges: User is missing UID (see mail_uid setting) Nov 29 10:51:44 mail dovecot: imap(charyorde): Error: Internal error occurred. Refer to server log for more information. Nov 29 10:51:46 mail dovecot: auth-worker: pam(charyorde,10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:46 mail dovecot: auth-worker: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:46 mail dovecot: auth: passwd(charyorde,10.10.1.28): unknown user Nov 29 10:51:46 mail dovecot: imap-login: Login: user=<charyorde>, method=PLAIN, rip=10.10.1.28, lip=10.10.1.30, mpid=1894, TLS Nov 29 10:51:46 mail dovecot: imap(charyorde): Error: user charyorde: Couldn't drop privileges: User is missing UID (see mail_uid setting) Nov 29 10:51:46 mail dovecot: imap(charyorde): Error: Internal error occurred. Refer to server log for more information. Nov 29 10:51:48 mail dovecot: auth-worker: pam([email protected],10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:48 mail dovecot: auth-worker: passwd([email protected],10.10.1.28): unknown user Nov 29 10:51:48 mail dovecot: auth: ldap([email protected],10.10.1.28): unknown user Nov 29 10:51:48 mail dovecot: auth: passwd-file([email protected],10.10.1.28): unknown user Nov 29 10:51:54 mail postfix/smtpd[1880]: idle timeout -- exiting Nov 29 10:51:54 mail postfix/smtpd[1879]: idle timeout -- exiting Nov 29 10:51:54 mail postfix/smtpd[1886]: proxymap stream disconnect Nov 29 10:51:54 mail postfix/smtpd[1887]: proxymap stream disconnect Nov 29 10:51:54 mail postfix/smtpd[1886]: auto_clnt_close: disconnect private/tlsmgr stream Nov 29 10:51:54 mail postfix/smtpd[1887]: auto_clnt_close: disconnect private/tlsmgr stream Nov 29 10:51:54 mail postfix/smtpd[1887]: idle timeout -- exiting Nov 29 10:51:54 mail postfix/smtpd[1886]: idle timeout -- exiting Nov 29 10:51:56 mail dovecot: auth-worker: pam([email protected],10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:51:56 mail dovecot: auth-worker: passwd([email protected],10.10.1.28): unknown user Nov 29 10:51:56 mail dovecot: auth: ldap([email protected],10.10.1.28): unknown user Nov 29 10:51:56 mail dovecot: auth: passwd-file([email protected],10.10.1.28): unknown user Nov 29 10:52:04 mail dovecot: auth-worker: pam([email protected],10.10.1.28): pam_authenticate() failed: Authentication failure (password mismatch?) Nov 29 10:52:04 mail dovecot: auth-worker: passwd([email protected],10.10.1.28): unknown user Nov 29 10:52:04 mail dovecot: auth: ldap([email protected],10.10.1.28): unknown user Nov 29 10:52:04 mail dovecot: auth: passwd-file([email protected],10.10.1.28): unknown user Nov 29 10:52:06 mail dovecot: imap-login: Disconnected (auth failed, 3 attempts): user=<[email protected]>, method=PLAIN, rip=10.10.1.28, lip=10.10.1.30, TLS Thank you for looking into this.

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• Are email addresses mandatory for Windows 8 login names?

  - by Cedric Martin

  I've got a computer running Windows 8 and in the user accounts I can see four accounts (they're in french, here's a rough translation): [email protected] / administrator Veronique YYY / [email protected] ASP.NET Machine Account / local account guest account / the guest account is desactivated I've got several questions but they're all related to email addresses and login names / accounts. Are email addresses mandatory for Windows 8 login names? Can you mix live and non-live user accounts on a Windows 8 system? Is it possible to have a live Windows 8 user account which is not using a @live.xx email address? Is it possible to have a non-live Windows 8 user account which is using a @live.xx email address? If the gmail.com email address of the admin is not a live Windows 8 account, does this mean I can create a "fake" email and use that as the email of a new Windows 8 account? Basically I don't understand very well why there are email addresses displayed on the login screen and why there are both @live.xx and @gmail.com email addresses on the same system and answer to the questions I asked above may help me understand a bit better what is going on (I'm coming from a Linux / OS X background. I literally haven't used Windows in more than a decade).

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• "log on as a batch job" user rights removed by what GPO?

  - by LarsH

  I am not much of a server administrator, but get my feet wet when I have to. Right now I'm running some COTS software on a Windows 2008 Server machine. The software installer creates a few user accounts for running its processes, and then gives those users the right to "log on as a batch job". Every so often (e.g. yesterday at 2:52pm and this morning at 7:50am), those rights disappear. The software then stops working. I can verify that the user rights are gone by using secedit /export /cfg e:\temp\uraExp.inf /areas USER_RIGHTS and I have a script that does this every 30 seconds and logs the results with a timestamp, so I know when the rights disappear. What I see from the export is that in the "good" state, i.e. after I install the software and it's working correctly, the line for SeBatchLogonRight from the secedit export includes the user accounts created by the software. But every few hours (sometimes more), those user accounts are removed from that line. The same thing can be seen by using the GUI tool Local Security Policy > Security Settings > Local Policies > User Rights Assignment > Log on as a batch job: in the "good" state, that policy includes the needed user accounts, and in the bad state, the policy does not. Based on the above-mentioned logging script and the timestamps at which the user rights are being removed, I can see clearly that some GPOs are causing the change. The GPO Operational log shows GPOs being processed at exactly the right times. E.g.: Starting Registry Extension Processing. List of applicable GPOs: (Changes were detected.) Local Group Policy I have run GPOs on demand using gpupdate /force, and was able to verify that this caused the User Rights to be removed. We have looked over local group policies till our eyes are crossed, trying to figure out which one might be stripping these User Rights to "log on as a batch job." We have not configured any local group policies on this machine, that we know of; so is there a default local group policy that might typically do such a thing? Are there typical domain policies that would do this? I have been working with our IT staff colleagues to troubleshoot the problem, but none of them are really GPO experts... They wear many hats, and they do what they need to do in order to keep most things running. Any suggestions would be greatly appreciated!

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• How to eliminate the domain suffix off my user profile folder when migrating to a new domain?

  - by Jerry Dodge

  We have just upgraded a decade old SBS 2003 server to a brand new SBS 2011 machine. During the process, over 30 other client/server machines on that domain also needed to be dis-joined and re-joined from the old domain to the new one. These domains have different names and is not migrated in any way. It's built from scratch. Since each client machine had very unique user profiles under this domain, we needed to make sure these were all backed up and migrated over to the new domain. For the most part, profiles were migrated with no hassle, just by renaming the user profile folder names. However, in one case, when I log in to my domain account, it creates a profile folder with a suffix of the new domain name. I have replaced all the files in the profile's root which begin with "ntuser" with the files of the new profile. The only problem is half the applications can't find their data, because the folder name is different. How can I change this folder name and maintain this profile on the new domain? I have deleted every user account (except admin), deleted their profiles/folders, removed them from the registry, and made sure every trace of this account was gone. The computer was basically a dummy with only an admin account. Then, I log into the machine under my new domain user account (same username as the old domain). It creates a profile folder with my username plus a suffix extension of the new domain name. The client machine is Windows 7 Ultimate, the old server was SBS 2003, and the new server is SBS 2011.

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• [GEEK SCHOOL] Network Security 1: Securing User Accounts and Passwords in Windows

  - by Matt Klein

  This How-To Geek School class is intended for people who want to learn more about security when using Windows operating systems. You will learn many principles that will help you have a more secure computing experience and will get the chance to use all the important security tools and features that are bundled with Windows. Obviously, we will share everything you need to know about using them effectively. In this first lesson, we will talk about password security; the different ways of logging into Windows and how secure they are. In the proceeding lesson, we will explain where Windows stores all the user names and passwords you enter while working in this operating systems, how safe they are, and how to manage this data. Moving on in the series, we will talk about User Account Control, its role in improving the security of your system, and how to use Windows Defender in order to protect your system from malware. Then, we will talk about the Windows Firewall, how to use it in order to manage the apps that get access to the network and the Internet, and how to create your own filtering rules. After that, we will discuss the SmartScreen Filter – a security feature that gets more and more attention from Microsoft and is now widely used in its Windows 8.x operating systems. Moving on, we will discuss ways to keep your software and apps up-to-date, why this is important and which tools you can use to automate this process as much as possible. Last but not least, we will discuss the Action Center and its role in keeping you informed about what’s going on with your system and share several tips and tricks about how to stay safe when using your computer and the Internet. Let’s get started by discussing everyone’s favorite subject: passwords. The Types of Passwords Found in Windows In Windows 7, you have only local user accounts, which may or may not have a password. For example, you can easily set a blank password for any user account, even if that one is an administrator. The only exception to this rule are business networks where domain policies force all user accounts to use a non-blank password. In Windows 8.x, you have both local accounts and Microsoft accounts. If you would like to learn more about them, don’t hesitate to read the lesson on User Accounts, Groups, Permissions & Their Role in Sharing, in our Windows Networking series. Microsoft accounts are obliged to use a non-blank password due to the fact that a Microsoft account gives you access to Microsoft services. Using a blank password would mean exposing yourself to lots of problems. Local accounts in Windows 8.1 however, can use a blank password. On top of traditional passwords, any user account can create and use a 4-digit PIN or a picture password. These concepts were introduced by Microsoft to speed up the sign in process for the Windows 8.x operating system. However, they do not replace the use of a traditional password and can be used only in conjunction with a traditional user account password. Another type of password that you encounter in Windows operating systems is the Homegroup password. In a typical home network, users can use the Homegroup to easily share resources. A Homegroup can be joined by a Windows device only by using the Homegroup password. If you would like to learn more about the Homegroup and how to use it for network sharing, don’t hesitate to read our Windows Networking series. What to Keep in Mind When Creating Passwords, PINs and Picture Passwords When creating passwords, a PIN, or a picture password for your user account, we would like you keep in mind the following recommendations: Do not use blank passwords, even on the desktop computers in your home. You never know who may gain unwanted access to them. Also, malware can run more easily as administrator because you do not have a password. Trading your security for convenience when logging in is never a good idea. When creating a password, make it at least eight characters long. Make sure that it includes a random mix of upper and lowercase letters, numbers, and symbols. Ideally, it should not be related in any way to your name, username, or company name. Make sure that your passwords do not include complete words from any dictionary. Dictionaries are the first thing crackers use to hack passwords. Do not use the same password for more than one account. All of your passwords should be unique and you should use a system like LastPass, KeePass, Roboform or something similar to keep track of them. When creating a PIN use four different digits to make things slightly harder to crack. When creating a picture password, pick a photo that has at least 10 “points of interests”. Points of interests are areas that serve as a landmark for your gestures. Use a random mixture of gesture types and sequence and make sure that you do not repeat the same gesture twice. Be aware that smudges on the screen could potentially reveal your gestures to others. The Security of Your Password vs. the PIN and the Picture Password Any kind of password can be cracked with enough effort and the appropriate tools. There is no such thing as a completely secure password. However, passwords created using only a few security principles are much harder to crack than others. If you respect the recommendations shared in the previous section of this lesson, you will end up having reasonably secure passwords. Out of all the log in methods in Windows 8.x, the PIN is the easiest to brute force because PINs are restricted to four digits and there are only 10,000 possible unique combinations available. The picture password is more secure than the PIN because it provides many more opportunities for creating unique combinations of gestures. Microsoft have compared the two login options from a security perspective in this post: Signing in with a picture password. In order to discourage brute force attacks against picture passwords and PINs, Windows defaults to your traditional text password after five failed attempts. The PIN and the picture password function only as alternative login methods to Windows 8.x. Therefore, if someone cracks them, he or she doesn’t have access to your user account password. However, that person can use all the apps installed on your Windows 8.x device, access your files, data, and so on. How to Create a PIN in Windows 8.x If you log in to a Windows 8.x device with a user account that has a non-blank password, then you can create a 4-digit PIN for it, to use it as a complementary login method. In order to create one, you need to go to “PC Settings”. If you don’t know how, then press Windows + C on your keyboard or flick from the right edge of the screen, on a touch-enabled device, then press “Settings”. The Settings charm is now open. Click or tap the link that says “Change PC settings”, on the bottom of the charm. In PC settings, go to Accounts and then to “Sign-in options”. Here you will find all the necessary options for changing your existing password, creating a PIN, or a picture password. To create a PIN, press the “Add” button in the PIN section. The “Create a PIN” wizard is started and you are asked to enter the password of your user account. Type it and press “OK”. Now you are asked to enter a 4-digit pin in the “Enter PIN” and “Confirm PIN” fields. The PIN has been created and you can now use it to log in to Windows. How to Create a Picture Password in Windows 8.x If you log in to a Windows 8.x device with a user account that has a non-blank password, then you can also create a picture password and use it as a complementary login method. In order to create one, you need to go to “PC settings”. In PC Settings, go to Accounts and then to “Sign-in options”. Here you will find all the necessary options for changing your existing password, creating a PIN, or a picture password. To create a picture password, press the “Add” button in the “Picture password” section. The “Create a picture password” wizard is started and you are asked to enter the password of your user account. You are shown a guide on how the picture password works. Take a few seconds to watch it and learn the gestures that can be used for your picture password. You will learn that you can create a combination of circles, straight lines, and taps. When ready, press “Choose picture”. Browse your Windows 8.x device and select the picture you want to use for your password and press “Open”. Now you can drag the picture to position it the way you want. When you like how the picture is positioned, press “Use this picture” on the left. If you are not happy with the picture, press “Choose new picture” and select a new one, as shown during the previous step. After you have confirmed that you want to use this picture, you are asked to set up your gestures for the picture password. Draw three gestures on the picture, any combination you wish. Please remember that you can use only three gestures: circles, straight lines, and taps. Once you have drawn those three gestures, you are asked to confirm. Draw the same gestures one more time. If everything goes well, you are informed that you have created your picture password and that you can use it the next time you sign in to Windows. If you don’t confirm the gestures correctly, you will be asked to try again, until you draw the same gestures twice. To close the picture password wizard, press “Finish”. Where Does Windows Store Your Passwords? Are They Safe? All the passwords that you enter in Windows and save for future use are stored in the Credential Manager. This tool is a vault with the usernames and passwords that you use to log on to your computer, to other computers on the network, to apps from the Windows Store, or to websites using Internet Explorer. By storing these credentials, Windows can automatically log you the next time you access the same app, network share, or website. Everything that is stored in the Credential Manager is encrypted for your protection.

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• Structuring Access Control In Hierarchical Object Graph

  - by SB2055

  I have a Folder entity that can be Moderated by users. Folders can contain other folders. So I may have a structure like this: Folder 1 Folder 2 Folder 3 Folder 4 I have to decide how to implement Moderation for this entity. I've come up with two options: Option 1 When the user is given moderation privileges to Folder 1, define a moderator relationship between Folder 1 and User 1. No other relationships are added to the db. To determine if the user can moderate Folder 3, I check and see if User 1 is the moderator of any parent folders. This seems to alleviate some of the complexity of handling updates / moved entities / additions under Folder 1 after the relationship has been defined, and reverting the relationship means I only have to deal with one entity. Option 2 When the user is given moderation privileges to Folder 1, define a new relationship between User 1 and Folder 1, and all child entities down to the grandest of grandchildren when the relationship is created, and if it's ever removed, iterate back down the graph to remove the relationship. If I add something under Folder 2 after this relationship has been made, I just copy all Moderators into the new Entity. But when I need to show only the top-level Folders that a user is Moderating, I need to query all folders that have a parent folder that the user does not moderate, as opposed to option 1, where I just query any items that the user is moderating. Thoughts I think it comes down to determining if users will be querying for all parent items more than they'll be querying child items... if so, then option 1 seems better. But I'm not sure. Is either approach better than the other? Why? Or is there another approach that's better than both? I'm using Entity Framework in case it matters.

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• Can I restore one of my user's profiles in Vista?

  - by Rod

  My youngest daughter uses my 4 year old laptop, which has Windows Vista installed. Somehow she got some Trojan (Vista Internet Security). (I'd love to know how that happened, seeing as how she is a standard user, and I have VIPRE as my AV.) Anyway, I ran a deep anti-virus scan using VIPRE, which identified it. I decided to delete everything that it identified. Now she cannot use anything in her profile. If she tries to bring up the browser, it recycles over and over again a dialog box asking which program to use. If I try to run any program at all, it doesn't know what to do. For example, it is totally lost trying to run the command line. If I bring up Windows Explorer and navigate to Windows\System32 and try to run the command line, or anything at all from there, it goes "Huh?" What in heck has happened?? Is it possible to fix this, and if so, how? As an aside, I can log into my account (my account on that machine is an administrator) and it works fine.

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