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  • alternative to lag SQL command

    - by mahen
    I have a table which has a table like this. Month-----Book_Type-----sold_in_Dollars Jan----------A------------ 100 Jan----------B------------ 120 Feb----------A------------ 50 Mar----------A------------ 60 Mar----------B------------ 30 and so on I have to calculate the expected sales for each month and book type based on the last 2 months sales. So for March and type A it would be (100+50)/2 = 75 For March and type B it is 120/1 since no data for Feb is there. I was trying to use the lag function but it wouldn't work since there is data missing in a few rows. Any ideas on this?

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  • Greatest not null column

    - by Álvaro G. Vicario
    I need to update a row with a formula based on the largest value of two DATETIME columns. I would normally do this: GREATEST(date_one, date_two) However, both columns are allowed to be NULL. I need the greatest date even when the other is NULL (of course, I expect NULL when both are NULL) and GREATEST() returns NULL when one of the columns is NULL. This seems to work: GREATEST(COALESCE(date_one, date_two), COALESCE(date_two, date_one)) But I wonder... am I missing a more straightforward method?

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  • Multiple column Union Query without duplicates

    - by Adam Halegua
    I'm trying to write a Union Query with multiple columns from two different talbes (duh), but for some reason the second column of the second Select statement isn't showing up in the output. I don't know if that painted the picture properly but here is my code: Select empno, job From EMP Where job = 'MANAGER' Union Select empno, empstate From EMPADDRESS Where empstate = 'NY' Order By empno The output looks like: EMPNO JOB 4600 NY 5300 MANAGER 5300 NY 7566 MANAGER 7698 MANAGER 7782 MANAGER 7782 NY 7934 NY 9873 NY Instead of 5300 and 7782 appearing twice, I thought empstate would appear next to job in the output. For all other empno's I thought the values in the fields would be (null). Am I not understanding Unions correctly, or is this how they are supposed to work? Thanks for any help in advance.

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  • SQL Modify question

    - by Jeff
    I need to replace a lot of values for a Table in SQL if the inactivity is greater then 30 days. I have UPDATE VERSION SET isActive = 0 WHERE customerNo = ( SELECT c.VersionNo FROM Activity b INNER JOIN VERSION c ON b.VersionNo = c.VersionNo WHERE (Months_between(sysdate, b.Activitye) > 30) ); It only works for one value though, if there is more then one returned it fails. What am I missing here? If someone could educate me on what is going on, I'd also appreciate it.

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  • Performance: Subquery or Joining

    - by Auro
    Hello I got a little question about performance of a subquery / joining another table INSERT INTO Original.Person ( PID, Name, Surname, SID ) ( SELECT ma.PID_new , TBL.Name , ma.Surname, TBL.SID FROM Copy.Person TBL , original.MATabelle MA WHERE TBL.PID = p_PID_old AND TBL.PID = MA.PID_old ); This is my SQL, now this thing runs around 1 million times or more. Now my question is what would be faster? if I change TBL.SID to (Select new from helptable where old = tbl.sid) or if I add helptable to the from and do the joining in the where? greets Auro

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  • Long to timestamp for historic data (pre-1900s)

    - by Mike
    I have a database of start and stop times that have previously all had fairly recent data (1960s through present day) which i've been able to store as long integers. This is very simialr to unix timestamps, only with millisecond precision, so a function like java.util.Date.getTime() would be the value of the current time. This has worked well so far, but we recently got data from the 1860s, and the following code no longer works: to_timestamp('1-JAN-1970 00:00:00', 'dd-mon-yyyy hh24:mi:ss') + numtodsinterval(int_to_convert/(1000),'SECOND' ); This wraps the date and we get timestamps in the year 2038. Is there a way around this issue? All of the documentation i've looked at the documentation and timestamps should be able to handle years all the way back to the -4000 (BC), so i'm suspecting an issue with the numtodsinterval. Any ideas suggestions would be greatly appreciated.

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  • Does the order of the columns in a SELECT statement make a difference?

    - by Frank Computer
    This question was inspired by a previous question posted on SO, "Does the order of the WHERE clause make a differnece?". Would it improve a SELECT statement's performance if the the columns used in the WHERE section are placed at the begining of the SELECT statement? example: SELECT customer.id, transaction.id, transaction.efective_date, transaction.a, [...] FROM customer, transaction WHERE customer.id = transaction.id; I do know that limiting the list of columns to only the needed ones in a SELECT statement improves performance as opposed to using SELECT * because the current list is smaller.

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  • trigger execution against condition satisfaction

    - by maheshasoni
    I have created this trigger which should give a error, whenever the value of new rctmemenrolno of table-receipts1 is matched with the memenrolno of table- memmast, but it is giving error in both condition(it is matched or not matched). kindly help me. CREATE OR REPLACE TRIGGER HDD_CABLE.trg_rctenrolno before insert ON HDD_CABLE.RECEIPTS1 for each row declare v_enrolno varchar2(9); cursor c1 is select memenrolno from memmast; begin open c1; fetch c1 into v_enrolno; LOOP If :new.rctmemenrolno<>v_enrolno then raise_application_error(-20186,'PLEASE ENTER CORRECT ENROLLMENT NO'); close c1; end if; END LOOP; end;

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  • Commit In loop gives wrong output?

    - by Vineet
    I am trying to insert 1 to 10 numbers except 6and 8 in table messages,but when i fetch it from table mesages1, output is coming in this order 4 5 7 9 10 1 2 3 It should be like this 1 2 3 4 5 7 9 10 According to the logic ,it works fine when i omit commit or put it some where else, Please explain why it is happening? this is my code. BEGIN FOR i IN 1..10 LOOP IF i<>6 AND i<>8 THEN INSERT INTO messages1 VALUES (i); END IF; commit; END LOOP; END; select * from messages1;

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  • replicating master tables mapping in transaction tables

    - by NoDisplay
    I have three master tables for location information Country {ID, Name} State {ID, Name, CountryID} City {ID, Name, StateID} Now I have one transcation table called Person which hold the person name and his location information. My Question is shall I have only CityID in the Person table like this: Person {ID, Name, CityID}' And have view of join query which give me detail like "Person{ID,Name,City,State,Country}" or Shall I replicate the mapping Person {ID, Name, CityID, StateID, CountryID} Please suggest which do you feel is to be selected and why? if there is any other option available, please suggest. Thanks in advance.

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  • sql exception handling

    - by christine33990
    CREATE OR REPLACE PROCEDURE p_createLocaltable IS table_already_exist EXCEPTION; PRAGMA EXCEPTION_INIT (table_already_exist, -00955); BEGIN create table local_table as select * from supplied_table where rownum < 1; EXCEPTION when table_already_exist then DBMS_OUTPUT.put_line('Table already exists , does not need to recreate it'); END; can anyone see any problem of the above code?

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  • Create trigger for auto incerment id and default unix datetime

    - by user1804985
    Any one help me to create a trigger for auto increment fld_id and Unix datetime. My table field is fld_id(int),fld_date(number),fld_value(varchar2). My insert query is insert into table (fld_value)values('xxx'); insert into table (fld_value)values('yyy'); I need the table record like this fld_id fld_date fld_value 1 1354357476 xxx 2 1354357478 yyy Please help me to create this.I can't able to do this..

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  • Delete from empty table taking forver

    - by Will
    Hello, I have an empty table that previously had a large amount of rows. The table has about 10 columns and indexes on many of them, as well as indexes on multiple columns. DELETE FROM item WHERE 1=1 This takes approximately 40 seconds to complete SELECT * FROM item this takes 4 seconds. The execution plan of SELECT * FROM ITEM shows the following; SQL> select * from midas_item; no rows selected Elapsed: 00:00:04.29 Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=CHOOSE (Cost=19 Card=123 Bytes=73 80) 1 0 TABLE ACCESS (FULL) OF 'MIDAS_ITEM' (Cost=19 Card=123 Byte s=7380) Statistics ---------------------------------------------------------- 0 recursive calls 0 db block gets 5263 consistent gets 5252 physical reads 0 redo size 1030 bytes sent via SQL*Net to client 372 bytes received via SQL*Net from client 1 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 0 rows processed any idea why these would be taking so long and how to fix it would be greatly appreciated!!

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  • Difference between INSERT INTO and INSERT ALL INTO

    - by emily soto
    While I was inserting some records in table i found that.. INSERT INTO T_CANDYBAR_DATA SELECT CONSUMER_ID,CANDYBAR_NAME,SURVEY_YEAR,GENDER,1 AS STAT_TYPE,OVERALL_RATING FROM CANDYBAR_CONSUMPTION_DATA UNION SELECT CONSUMER_ID,CANDYBAR_NAME,SURVEY_YEAR,GENDER,2 AS STAT_TYPE,NUMBER_BARS_CONSUMED FROM CANDYBAR_CONSUMPTION_DATA; 79 rows inserted. INSERT ALL INTO t_candybar_data VALUES (consumer_id,candybar_name,survey_year,gender,1,overall_rating) INTO t_candybar_data VALUES (consumer_id,candybar_name,survey_year,gender,2,number_bars_consumed) SELECT * FROM candybar_consumption_data 86 rows inserted. I have read somewhere that INSERT ALL INTO automatically unions then why those difference is showing.

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  • if not (i_ReLaunch = 1 and (dt_enddate is not null)) How this epression will be evaluated in Oracle

    - by Phani Kumar PV
    if not (i_ReLaunch = 1 and (dt_enddate is not null)) How this epression will be evaluated in Oracle 10g when the input value of the i_ReLaunch = null and the value of the dt_enddate is not null it is entering the loop. according to the rules in normal c# and all it should not enter the loop as it will be as follows with the values. If( not(false and (true)) = if not( false) =if( true) which implies it should enters the loop But it is not happening Can someone let me know if i am wrong at any place

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  • Select distinct ... inner join vs. select ... where id in (...)

    - by Tonio
    I'm trying to create a subset of a table (as a materialized view), defined as those records which have a matching record in another materialized view. For example, let's say I have a Users table with user_id and name columns, and a Log table, with entry_id, user_id, activity, and timestamp columns. First I create a materialized view of the Log table, selecting only those rows with timestamp some_date. Now I want a materliazed view of the Users referenced in my snapshot of the Log table. I can either create it as select * from Users where user_id in (select user_id from Log_mview), or I can do select distinct u.* from Users u inner join Log_mview l on u.user_id = l.user_id (need the distinct to avoid multiple hits from users with multiple log entries). The former seems cleaner and more elegant, but takes much longer. Am I missing something? Is there a better way to do this?

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  • Fill data gaps without UNION

    - by Dave Jarvis
    Problem There are data gaps that need to be filled, possibly using PARTITION BY. Query Statement The select statement reads as follows: SELECT count( r.incident_id ) AS incident_tally, r.severity_cd, r.incident_typ_cd FROM report_vw r GROUP BY r.severity_cd, r.incident_typ_cd ORDER BY r.severity_cd, r.incident_typ_cd Code Tables The severity codes and incident type codes are from: severity_vw incident_type_vw Actual Result Data 36 0 ENVIRONMENT 1 1 DISASTER 27 1 ENVIRONMENT 4 2 SAFETY 1 3 SAFETY Required Result Data 36 0 ENVIRONMENT 0 0 DISASTER 0 0 SAFETY 27 1 ENVIRONMENT 0 1 DISASTER 0 1 SAFETY 0 2 ENVIRONMENT 0 2 DISASTER 4 2 SAFETY 0 3 ENVIRONMENT 0 3 DISASTER 1 3 SAFETY Any ideas how to use PARTITION BY (or JOINs) to fill in the zero counts?

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  • Caluculating sum of activity

    - by Maddy
    I have a table which is with following kind of information activity cost order date other information 10 1 100 -- 20 2 100 10 1 100 30 4 100 40 4 100 20 2 100 40 4 100 20 2 100 10 1 101 10 1 101 20 1 101 My requirement is to get sum of all activities over a work order ex: for order 100 1+2+4+4=11 1(for activity 10) 2(for activity 20) 4 (for activity 30) etc. i tried with group by, its taking lot time for calculation. There are 1lakh plus records in warehouse. is there any possibility in efficient way. SELECT SUM(MIN(cost)) FROM COST_WAREHOUSE a WHERE order = 100 GROUP BY (order, ACTIVITY)

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  • Understanding the value of Customer Experience & Loyalty for the Telecommunications Industry

    - by raul.goycoolea
    Worried by economic woes and market forces, especially in mature markets, communications service providers (CSPs) increasingly focus on improving customer experience. In fact, it seems difficult to find a major message by a C-level executive in the developed world that does not include something on "meeting and exceeding customers' needs". Frequently in customer satisfaction studies by prominent firms, CSPs fall short of the leadership demonstrated by other industries that take customer-centric approaches to their bottom-line strategies. Consider the following:Despite the continued impact of global economic crisis, in July 2010, Apple Computer posted record revenue and net quarterly profit. Those who attribute the results primarily to the iPhone 4 launch should note that Apple also shipped around 30% more Macintosh computers than the same period the previous year. Even sales of the iPod line increased by 8% in a highly commoditized, shrinking media player market. Finally, Apple began selling iPads during the quarter, with total sales of more than 3 million units. What does Apple have that the others lack? Well, some great products (and services) to be sure, but it also excels at customer service and support, marketing, and distribution, and has one of the strongest brands globally. Its products are useful, simple to use, easy to acquire and augment, high quality, and considered very cool. They also evoke such an emotional response from many of Apple's customers, which they turn up their noses at competitive products.In other words, Apple appears to have mastered virtually every aspect of customer experience and the resultant loyalty of its customer base - even in difficult financial times. Through that unwavering customer focus, Apple continues to drive its revenues and profits to new heights. Other customer loyalty leaders like Wal-Mart, Google, Toyota and Honda are also doing well by focusing on customer experience as an essential driver of profitability. Service providers should note this performance and ask themselves how they might leverage the same principles to increase their own profitability. After all, that is what customer experience and loyalty are all about: profitability.To successfully manage all the critical touch points of customer experience, CSPs must shun the one-size-fits-all approach. They can no longer afford to view customer service fundamentally as an act of altruism - which mentality dates back to the industry's civil service days, when CSPs were typically government organizations that were critical to economic development and public safety.As regulators and public officials have pushed, and continue to push, service providers to new heights of reliability - using incentives and punishments - most CSPs already have some of the fundamental building blocks of customer service in place. Yet despite that history and experience, service providers still lag other industries in providing what is seen as good customer service.As we observed in the TMF's 2009 Insights Research report, Customer Experience Management: Driving Loyalty & Profitability there has been resurgence in interest by CSPs. More and more of them have stated ambitions to catch up other industries, and they are realizing that good customer service is a powerful strategy for increasing business performance and profitability, not an act of good will.CSPs are recognizing the connection between customer experience and profitability, as demonstrated in many studies. For example, according to research by Bain & Company, a 5 percent improvement in customer retention rates can yield as much as a 75 percent increase in profits for companies across a range of industries.After decades of customer experience strategy formulation, Bain partner and business author, Frederick Reichheld, considers "would you recommend us to a friend?" as the ultimate question for a customer. How many times have you or your friends recommended an iPod, iPhone or a Mac? What do your children recommend to their peers? Their peers to them?There are certain steps service providers have to take to create more personalized relationships with their customers, as well as reduce churn and increase profitability, all while becoming leaner and more agile. First, they have to define customer experience, we define it as the result of the sum of observations, perceptions, thoughts and feelings arising from interactions and relationships between customers and their service provider(s). Virtually every customer touch point - whether directly or indirectly linked to service providers and their partners - contributes to customer perception, satisfaction, loyalty, and ultimately profitability. Gaining leadership in customer experience and satisfaction will not be a simple task, as it is affected by virtually every customer-facing aspect of the service provider, and in turn impacts the service provider deeply - especially on the all-important bottom line. The scope of issues affecting customer experience is complex and dynamic.With new services, devices and applications extending the basis of customer experience to domains beyond the direct control of the service provider, it is likely to increase in complexity and dynamism.Customer loyalty = increased profitsAs stated earlier, customer experience programs are not fundamentally altruistic exercises, but a strategic means of improving competitiveness and profitability in the short and long term. Loyalty is essential to deriving long term profits from customers.Some of the earliest loyalty programs date back to the 1930s, when packaged goods companies offered embedded coupons for rewards to buyers, and eventually retail chains began offering reward programs to frequent shoppers. These programs continued for decades but were leapfrogged in the 1980s by more aggressive programs from the airlines.This movement was led by American Airlines, which launched the first full-scale loyalty marketing program of the modern era with the AAdvantage frequent flyer scheme. It was the first to reward frequent fliers with notional air miles that could be accumulated and later redeemed for free travel. Figure 1: Opportunities example of Customer loyalty driven profitOther airlines and travel providers were quick to grasp the incredible value of providing customers with an incentive to use their company exclusively. Within a few years, dozens of travel industry companies launched similar initiatives and now loyalty programs are achieving near-ubiquity in many service industries, especially those in which it is difficult to differentiate offerings by product attributes.The belief is that increased profitability will result from customer retention efforts because:•    The cost of acquisition occurs only at the beginning of a relationship: the longer the relationship, the lower the amortized cost;•    Account maintenance costs decline as a percentage of total costs, or as a percentage of revenue, over the lifetime of the relationship;•    Long term customers tend to be less inclined to switch and less price sensitive which can result in stable unit sales volume and increases in dollar-sales volume;•    Long term customers may initiate word-of-mouth promotions and referrals, which cost the company nothing and arguably are the most effective form of advertising;•    Long-term customers are more likely to buy ancillary products and higher margin supplemental products;•    Long term customers tend to be satisfied with their relationship with the company and are less likely to switch to competitors, making market entry or competitors gaining market share difficult;•    Regular customers tend to be less expensive to service, as they are familiar with the processes involved, require less 'education', and are consistent in their order placement;•    Increased customer retention and loyalty makes the employees' jobs easier and more satisfying. In turn, happy employees feed back into higher customer satisfaction in a virtuous circle. Figure 2: The virtuous circle of customer loyaltyFigure 2 represents a high-level example of a virtuous cycle driven by customer satisfaction and loyalty, depicting how superiority in product and service offerings, as well as strong customer support by competent employees, lead to higher sales and ultimately profitability. As stated above, this is not a new concept, but succeeding with it is difficult. It has eluded many a company driven to achieve profitability goals. Of course, for this circle to be virtuous, the customer relationship(s) must be profitable.Trying to maintain the loyalty of unprofitable customers is not a viable business strategy. It is, therefore, important that marketers can assess the profitability of each customer (or customer segment), and either improve or terminate relationships that are not profitable. This means each customer's 'relationship costs' must be understood and compared to their 'relationship revenue'. Customer lifetime value (CLV) is the most commonly used metric here, as it is generally accepted as a representation of exactly how much each customer is worth in monetary terms, and therefore a determinant of exactly how much a service provider should be willing to spend to acquire or retain that customer.CLV models make several simplifying assumptions and often involve the following inputs:•    Churn rate represents the percentage of customers who end their relationship with a company in a given period;•    Retention rate is calculated by subtracting the churn rate percentage from 100;•    Period/horizon equates to the units of time into which a customer relationship can be divided for analysis. A year is the most commonly used period for this purpose. Customer lifetime value is a multi-period calculation, often projecting three to seven years into the future. In practice, analysis beyond this point is viewed as too speculative to be reliable. The model horizon is the number of periods used in the calculation;•    Periodic revenue is the amount of revenue collected from a customer in a given period (though this is often extended across multiple periods into the future to understand lifetime value), such as usage revenue, revenues anticipated from cross and upselling, and often some weighting for referrals by a loyal customer to others; •    Retention cost describes the amount of money the service provider must spend, in a given period, to retain an existing customer. Again, this is often forecast across multiple periods. Retention costs include customer support, billing, promotional incentives and so on;•    Discount rate means the cost of capital used to discount future revenue from a customer. Discounting is an advanced method used in more sophisticated CLV calculations;•    Profit margin is the projected profit as a percentage of revenue for the period. This may be reflected as a percentage of gross or net profit. Again, this is generally projected across the model horizon to understand lifetime value.A strong focus on managing these inputs can help service providers realize stronger customer relationships and profits, but there are some obstacles to overcome in achieving accurate calculations of CLV, such as the complexity of allocating costs across the customer base. There are many costs that serve all customers which must be properly allocated across the base, and often a simple proportional allocation across the whole base or a segment may not accurately reflect the true cost of serving that customer;  This is made worse by the fragmentation of customer information, which is likely to be across a variety of product or operations groups, and may be difficult to aggregate due to different representations.In addition, there is the complexity of account relationships and structures to take into consideration. Complex account structures may not be understood or properly represented. For example, a profitable customer may have a separate account for a second home or another family member, which may appear to be unprofitable. If the service provider cannot relate the two accounts, CLV is not properly represented and any resultant cancellation of the apparently unprofitable account may result in the customer churning from the profitable one.In summary, if service providers are to realize strong customer relationships and their attendant profits, there must be a very strong focus on data management. This needs to be coupled with analytics that help business managers and those who work in customer-facing functions offer highly personalized solutions to customers, while maintaining profitability for the service provider. It's clear that acquiring new customers is expensive. Advertising costs, campaign management expenses, promotional service pricing and discounting, and equipment subsidies make a serious dent in a new customer's profitability. That is especially true given the rising subsidies for Smartphone users, which service providers hope will result in greater profits from profits from data services profitability in future.  The situation is made worse by falling prices and greater competition in mature markets.Customer acquisition through industry consolidation isn't cheap either. A North American service provider spent about $2,000 per subscriber in its acquisition of a smaller company earlier this year. While this has allowed it to leapfrog to become the largest mobile service provider in the country, it required a total investment of more than $28 billion (including assumption of the acquiree's debt).While many operating cost synergies clearly made this deal more attractive to the acquiring company, this is certainly an expensive way to acquire customers: the cost per subscriber in this case is not out of line with the prices others have paid for acquisitions.While growth by acquisition certainly increases overall revenues, it often creates tremendous challenges for profitability. Organic growth through increased customer loyalty and retention is a more effective driver of profit, as well as a stronger predictor of future profitability. Service providers, especially those in mature markets, are increasingly recognizing this and taking steps toward a creating a more personalized, flexible and satisfying experience for their customers.In summary, the clearest path to profitability for companies in virtually all industries is through customer retention and maximization of lifetime value. Service providers would do well to recognize this and focus attention on profitable customer relationships.

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  • Is there a standard site structure format?

    - by artlung
    Is there a standard site structure format? The use of this would be for export and import into a CMS or framework to define the urls, content, metadata for a website. Something tool agnostic would be the goal. JSON, YAML, XML, whatever. Maybe something like: { 'baseurl': 'http://example.com', 'site': [ {'slug': '/', 'title': 'ExampleCo. Inc.'}, {'slug': '/about', 'title': 'About Our Company'}, {'slug': '/services', 'title': 'Our Services'}, {'slug': '/products', 'title': 'Products'}, {'slug': '/products/purchase', 'title': 'Purchase Products Now'}, {'slug': '/products/downloads', 'title': 'Downloads'}, {'slug': '/contact', 'title': 'Contact Us'} ] } My thinking is that it would allow you to quickly populate a content management system or framework with a generic site navigational structure. Does something like this exist?

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