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  • MS Acess SQL - where clause to get year from date based on the year - data located in MS access form

    - by primus285
    OK, back again. I have a problem getting a drop down list to populate based on information in two fields. I have got the SQL correct as to Select just one year if I put DateValue('01/01/2001') in both places, but I am trying now to get it to grab the year data from the MS access form - another drop down named "cboYear". I'd hate to have to do something in VB, unless necessary. so far I have gotten this to pull up something (its always incorrect) SELECT DISTINCT Database_New.ASEC FROM Database_New WHERE Database_New.Date>=DateValue('01/01/' & [cboYear]) And Database_New.Date<=DateValue('12/31/' & [cboYear]); and SELECT DISTINCT Database_New.ASEC FROM Database_New WHERE Database_New.Date>=DateValue('01/01/' + [cboYear]) And Database_New.Date<=DateValue('12/31/' + [cboYear]); SELECT DISTINCT Database_New.ASEC FROM Database_New WHERE Database_New.Date>=DateValue('01/01/' AND [cboYear]) And Database_New.Date<=DateValue('12/31/' AND [cboYear]); both give errors saying that it is too complex to compute. Its probably something simple, but where do I go from here?

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  • How to install previously-archived apps from xcode organizer to my iphone

    - by Ben Clayton
    Hi all. Xcode keeps an archive of all the versions of my apps that I've submitted to the app store in the 'archived applications' section. I assumed using this I could install an old version of an app to my device, in order to reproduce any problems my client may have had with that particular version. However, when I try to do this I get an error: 'this executable was signed with invalid entitlements, the entitlements specified in your applications code signing entitlements do not match those specified in your provisioning profile' The original app was signed using our App Store distribution certificate, and I use the Organizer interface to re-sign it using our Developer profile. select the archived app select the version I want to test click 'share' select 'iphone developer' next to identity save to disk (saves the ipa file) then copy the ipa to the device using the little + button you see next to 'applications' on the screen you get when you select the connected device. Then I get the error, and the app isn't installed. Is there something obvious I'm doing wrong here? Or is there a different process to re-install an archived app to my device? Thanks,

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  • Django: DatabaseError column does not exist

    - by Rosarch
    I'm having a problem with Django 1.2.4. Here is a model: class Foo(models.Model): # ... ftw = models.CharField(blank=True) bar = models.ForeignKey(Bar) Right after flushing the database, I use the shell: Python 2.6.6 (r266:84292, Sep 15 2010, 15:52:39) [GCC 4.4.5] on linux2 Type "help", "copyright", "credits" or "license" for more information. (InteractiveConsole) >>> from apps.foo.models import Foo >>> Foo.objects.all() Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 67, in __repr__ data = list(self[:REPR_OUTPUT_SIZE + 1]) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 82, in __len__ self._result_cache.extend(list(self._iter)) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 271, in iterator for row in compiler.results_iter(): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/compiler.py", line 677, in results_iter for rows in self.execute_sql(MULTI): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/compiler.py", line 732, in execute_sql cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/util.py", line 15, in execute return self.cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute return self.cursor.execute(query, args) DatabaseError: column foo_foo.bar_id does not exist LINE 1: ...t_omg", "foo_foo"."ftw", "foo_foo... What am I doing wrong here?

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  • Avoid MySQL multi-results from SP with Execute

    - by hhyhbpen
    Hi, i have an SP like BEGIN DECLARE ... CREATE TEMPORARY TABLE tmptbl_found (...); PREPARE find FROM" INSERT INTO tmptbl_found (SELECT userid FROM ( SELECT userid FROM Soul WHERE .?.?. ORDER BY .?.?. ) AS left_tbl LEFT JOIN Contact ON userid = Contact.userid WHERE Contact.userid IS NULL LIMIT ?) "; DECLARE iter CURSOR FOR SELECT userid, ... FROM Soul ...; ... l:LOOP FETCH iter INTO u_id, ...; ... EXECUTE find USING ...,. . .,u_id,...; ... END LOOP; ... END// and it gives multi-results. Besides it's inconvenient, if i get all this multi-results (which i really don't need at all), about 5 (limit's param) for each of the hundreds of thousands of records in Soul, i'm afraid it will take all my memory (and all in vain). Also, i noticed, if i do prepare from an empty string, it still has multi-results... At least how to get rid of them in the execute statement? And i would like to have a recipe to avoid ANY output from SP, for any possible statement (i also have a lot of "update ..."s and "select ... into "s inside, if they can produce multi's). Tnx for any help...

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  • Flex : providing data with a PHP Class

    - by Tristan
    Hello, i'm a very new user to flex (never use flex, nor flashbuilder, nor action script before), but i want to learn this langage because of the beautiful RIA and chart it can do. I watched the video on adobe : 1 hour to build your first program but i'm stuck : On the video it says that we have to provide a PHP class for accessing data and i used the example that flash builder gave (with zend framework and mysqli). I never used those ones and it makes a lot to learn if i count zen + mysqli. My question is : can i use a PHP class like this one ? What does flash builder except in return ? i hear that was automatic. example it may be wrong, i'm not very familiar with classes when acessing to database : <?php class DBConnection { protected $server = "localhost"; protected $username = "root"; protected $password = "root"; protected $dbname = "something"; protected $connection; function __construct() { $this->connection = mysql_connect($this->server, $this->username, $this->password); mysql_select_db($this->dbname,$this->connection); mysql_query("SET NAMES 'utf8'", $this->connection); } function query($query) { $result = mysql_query($query, $this->connection); if (!$result) { echo 'request error ' . mysql_error($this->connection); exit; } return $result; } function getAll() { $req = "select * from servers"; $result = query($req) return $result } function num_rows() { return mysql_num_rows($result); } function end() { mysql_close($this->connection); } } ?> Thank you,

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  • PHP: saving multiple tuples to the same table

    - by Binaryrespawn
    Hi all, I am trying to save data into the same table several times from the same $_POST array. You see, on my registration form a family is allowed to specify the names, gender and age of all members they wish to bring along. This data is being stored in a database table called aditional_member. Based on family size, I am dynamically generating html table rows where each row has the number of input fields required. <tr id="additionalmember_3"> <td><input type="text" name="first_name1" maxlength="50" value="" /></td> <td><input type="text" name="last_name1" maxlength="50" value="" /></td> td><select name="gender1" value="" ><option value='Male'>Male</option><option value='Female'>Female</option></select></td> <td><select name="age_group"value="" ><option value='18 to 30'>18 to 30</option><option value='31 to 60'>31 to 60</option></select></td> </tr> When I POST, let us say I have three sets of input(3 table rows as above), Is there a simple way to insert into the addional_member table the data from row one, then row two, and so on. I tried looping the insert statement, which failed. I am basically open to suggestions, I do not need to use a table. Any ideas, Thank you.

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  • Lost Array After Validation Error

    - by Georges Kmeid
    I'm working on a CakePHP project and I have User, Post and Location models among others. User hasMany Location and Post belongsTo User so Location is not directly related to Post. This is my code in the Post controller: public function add() { if ($this->request->is('get')) { $this->loadModel('Location'); $this->set('locations', $this->Location->find('all', array('conditions' => array('user_id' => $this->Auth->user('id'))))); } ... } And this is my code in the posts/add view: <?php $i = 0; $j = 0; foreach ($locations as $location): $location_names[$i] = $location['Location']['name']; $i++; endforeach; echo "<select name=\"location\" onchange=\"select(this.value)\">"; echo "<option value=\"\">Select a saved location</option>"; foreach ($locations as $location): echo "<option value=\"" . $location['Location']['latitude'] . "," . $location['Location']['longitude'] . "\">" . $location_names[$j] . "</option>"; $j++; endforeach; ?> </select> If I enter a wrong value in one of the post inputs that has a validation rule in Post model, it redirects to the current add view, shows what is the validation error, but then the $locations array passed from controller to view disappears and can't use it in view and I get this error: Notice (8): Undefined variable: locations [APP\View\Posts\add.ctp, line 68]

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  • JDBC transaction dead-lock solution required?

    - by user49767
    It's a scenario described my friend and challenged to find solution. He is using Oracle database and JDBC connection with read committed as transaction isolation level. In one of the transaction, he updates a record and executes selects statement and commits the transaction. when everything happening within single thread, things are fine. But when multiple requests are handled, dead-lock happens. Thread-A updates a record. Thread B updates another record. Thread-A issues select statement and waits for Thread-B's transaction to complete the commit operation. Thread-B issues select statement and waits for Thread-A's transaction to complete the commit operation. Now above causes dead-lock. Since they use command pattern, the base framework allows to issue commit only once (at the end of all the db operation), so they are unable to issue commit immediately after select statement. My argument was Thread-A supposed to select all the records which are committed and hence should not be issue. But he said that Thread-A will surely wait till Thread-B commits the record. is that true? What are all the ways, to avoid the above issue? is it possible to change isolation-level? (without changing underlying java framework) Little information about base framework, it is something similar to Struts action, their each and every request handled by one action, transaction begins before execution and commits after execution.

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  • BASH echo write mysql input

    - by jmituzas
    Have a bash menu where variables write to file for mysql input. heres what I have: echo "CREATE DATABASE '$mysqldbn'; #GRANT ALL PRIVILEGES ON *.* TO '$mysqlu'@'$myhost' IDENTIFIED BY '$mysqlup' WITH GRANT OPTION; GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES ON '$mysqldbn'.* TO '$mysqlu'@'$myhost' IDENTIFIED BY '$mysqlup'; GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES ON '$mysqldbn'.* TO '$mysqlu'@'$myip' IDENTIFIED BY '$mysqlup'; GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, INDEX, ALTER, CREATE TEMPORARY TABLES, LOCK TABLES ON '$mysqldbn'.* TO '$mysqlu'@'localhost' IDENTIFIED BY '$mysqlup'; GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, INDEX, ALTER, CREATE TEMPORARY TABLES< LOCK TABLES on '$mysqldbn'.* TO '$mysqlu'@'$rip' IDENTIFIED BY '$mysqlup';" > nmysql.db mysql -u root -p$mypass < nmysql.db problem is to get variables to show I had to put them in single quotes, the single quotes show up as I want for instances like '$mysqlu'@'localhost'. But how can I remove the quotes and still get to use the variable in the instance like, CREATE DATABASE '$mysqldbn' ? Double quotes wont work either, I am at a loss. Thanks in advance, Joe

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  • Algorithm for finding similar users through a join table

    - by Gdeglin
    I have an application where users can select a variety of interests from around 300 possible interests. Each selected interest is stored in a join table containing the columns user_id and interest_id. Typical users select around 50 interests out of the 300. I would like to build a system where users can find the top 20 users that have the most interests in common with them. Right now I am able to accomplish this using the following query: SELECT i2.user_id, count(i2.interest_id) AS count FROM interests_users as i1, interests_users as i2 WHERE i1.interest_id = i2.interest_id AND i1.user_id = 35 GROUP BY i2.user_id ORDER BY count DESC LIMIT 20; However, this query takes approximately 500 milliseconds to execute with 10,000 users and 500,000 rows in the join table. All indexes and database configuration settings have been tuned to the best of my ability. I have also tried avoiding the use of joins altogether using the following query: select user_id,count(interest_id) count from interests_users where interest_id in (13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,508) group by user_id order by count desc limit 20; But this one is even slower (~800 milliseconds). How could I best lower the time that I can gather this kind of data to below 100 milliseconds? I have considered putting this data into a graph database like Neo4j, but I am not sure if that is the easiest solution or if it would even be faster than what I am currently doing.

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  • mysql row locking via php

    - by deezee
    I am helping a friend with a web based form that is for their business. I am trying to get it ready to handle multiple users. I have set it up so that just before the record is displayed for editing I am locking the record with the following code. $query = "START TRANSACTION;"; mysql_query($query); $query = "SELECT field FROM table WHERE ID = \"$value\" FOR UPDATE;"; mysql_query($query); (okay that is greatly simplified but that is the essence of the mysql) It does not appear to be working. However, when I go directly to mysql from the command line, logging in with the same user and execute START TRANSACTION; SELECT field FROM table WHERE ID = "40" FOR UPDATE; I can effectively block the web form from accessing record "40" and get the timeout warning. I have tried using BEGIN instead of START TRANSACTION. I have tried doing SET AUTOCOMMIT=0 first and starting the transaction after locking but I cannot seem to lock the row from the PHP code. Since I can lock the row from the command line I do not think there is a problem with how the database is set up. I am really hoping that there is some simple something that I have missed in my reading. FYI, I am developing on XAMPP version 1.7.3 which has Apache 2.2.14, MySQL 5.1.41 and PHP 5.3.1. Thanks in advance. This is my first time posting but I have gleaned alot of knowledge from this site in the past.

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  • Relational MySQL - fetched properties?

    - by Kelso.b
    I'm currently using the following PHP code: // Get all subordinates $subords = array(); $supervisorID = $this->session->userdata('supervisor_id'); $result = $this->db->query(sprintf("SELECT * FROM users WHERE supervisor_id=%d AND id!=%d",$supervisorID, $supervisorID)); $user_list_query = 'user_id='.$supervisorID; foreach($result->result() as $user){ $user_list_query .= ' OR user_id='.$user->id; $subords[$user->id] = $user; } // Get Submissions $submissionsResult = $this->db->query(sprintf("SELECT * FROM submissions WHERE %s", $user_list_query)); $submissions = array(); foreach($submissionsResult->result() as $submission){ $entriesResult = $this->db->query(sprintf("SELECT * FROM submittedentries WHERE timestamp=%d", $submission->timestamp)); $entries = array(); foreach($entriesResult->result() as $entries) $entries[] = $entry; $submissions[] = array( 'user' => $subords[$submission->user_id], 'entries' => $entries ); $entriesResult->free_result(); } Basically I'm getting a list of users that are subordinates of a given supervisor_id (every user entry has a supervisor_id field), then grabbing entries belonging to any of those users. I can't help but think there is a more elegant way of doing this, like SELECT FROM tablename where user->supervisor_id=2222 Is there something like this with PHP/MySQL? Should probably learn relational databases properly sometime. :(

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  • XSL Reuse? YES! But: Element must not contain an xsl:import element! :-(

    - by Fedor Steeman
    I am using a heavy stylesheet with a lot of recurring transformations, so I thought it would be smart to reuse the same chunks of code, so I would not need to make the same changes at a bunch of different places. So I discovered , but -alas- it won't allow me to do it. When trying to run it in Sonic Workbench I get the following error: An xsl:for-each element must not contain an xsl:import element This is my stylesheet code: <xsl:template match="/"> <InboundFargoMessage> <EdiSender> <xsl:value-of select="TransportInformationMessage/SenderId"/> </EdiSender> <EdiReceiver> <xsl:value-of select="TransportInformationMessage/RecipientId"/> </EdiReceiver> <EdiSource>PORLOGIS</EdiSource> <EdiDestination>FARGO</EdiDestination> <Transportations> <xsl:for-each select="TransportInformationMessage/TransportUnits/TransportUnit"> <xsl:import href="TransportCDMtoFDM_V0.6.xsl"/> </xsl:for-each> <xsl:for-each select="TransportInformationMessage/Waybill/TransportUnits/TransportUnit"> <xsl:import href="TransportCDMtoFDM_V0.6.xsl"/> </xsl:for-each> </Transportations> </InboundFargoMessage> </xsl:template> </xsl:stylesheet> I will leave out the child xsl-sheets for now, as the problem appears to be happening at the base. If I cannot use xsl:import, is there any option of reuse?

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  • Assign Multiple Custom User Roles to a Custom Post Type

    - by OUHSD Webmaster
    Okay here's the situation.... I'm working on a my business website. There will be a work/portfolio area. "Work" is a custom post type. "Designer" is a custom user role. "Client" is a custom user role. In creating a new "Work" post I would like to be able to select both a "designer" and "Client" to assign to the piece of work, as I would assign an author to a regular ol' post. I tried the method from this answer but it did not work for me. ) I placed it in my functions.php file. ` add_filter('wp_dropdown_users', 'test'); function test($output) { global $post; //Doing it only for the custom post type if($post->post_type == 'work') { $users = get_users(array('role'=>'designer')); //We're forming a new select with our values, you can add an option //with value 1, and text as 'admin' if you want the admin to be listed as well, //optionally you can use a simple string replace trick to insert your options, //if you don't want to override the defaults $output .= "<select id='post_author_override' name='post_author_override' class=''>"; foreach($users as $user) { $output .= "<option value='".$user->id."'>".$user->user_login."</option>"; } $output .= "</select>"; } return $output; } ` Any help would be extremely appreciated!

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  • JoinColumn name not used in sql

    - by Vladimir
    Hi! I have a problem with mapping many-to-one relationship without exact foreign key constraint set in database. I use OpenJPA implementation with MySql database, but the problem is with generated sql scripts for insert and select statements. I have LegalEntity table which contains RootId column (among others). I also have Address table which has LegalEntityId column which is not nullable, and which should contain values referencing LegalEntity's "RootId" column, but without any database constraint (foreign key) set. Address entity is mapped: @Entity @Table(name="address") public class Address implements Serializable { ... @ManyToOne(fetch=FetchType.LAZY, optional=false) @JoinColumn(referencedColumnName="RootId", name="LegalEntityId", nullable=false, insertable=true, updatable=true, table="LegalEntity") public LegalEntity getLegalEntity() { return this.legalEntity; } } SELECT statement (when fetching LegalEntity's addresses) and INSERT statment are generated: SELECT t0.Id, .., t0.LEGALENTITY_ID FROM address t0 WHERE t0.LEGALENTITY_ID = ? ORDER BY t0.Id DESC [params=(int) 2] INSERT INTO address (..., LEGALENTITY_ID) VALUES (..., ?) [params=..., (int) 2] If I omit table attribute from mentioned statements are generated: SELECT t0.Id, ... FROM address t0 INNER JOIN legalentity t1 ON t0.LegalEntityId = t1.RootId WHERE t1.Id = ? ORDER BY t0.Id DESC [params=(int) 2] INSERT INTO address (...) VALUES (...) [params=...] So, LegalEntityId is not included in any of the statements. Is it possible to have relationship based on such referencing (to column other than primary key, without foreign key in database)? Is there something else missing? Thanks in advance.

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  • Asp.Net Basic Program

    - by Abid Ali
    I want to Visible the combo Box named Cities when i click the Country Pakistan.. but the combo box visibility remains Hidden.. how do i do so ? I think my Code is correct but it is not working :s .. Help Required.. <select id="Items" name = "Countries"> <option id="Pakistan" onclick="VisibileTrue()">Pakistan</option> <option id = "Taiwan">Taiwan</option> </select> <select id="Items2" name="Cities" style="display:none" > <option>Karachi</option> <option>Sindh</option> </select> </div> </form> function VisibileTrue() { var element = document.getElementById(Pakistan); if(element == Pakistan) { var element2 = document.getElementsByTagName("Items2"); element2.style.display = "inline"; } }

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  • WF -- how do I use a custom activity without creating it in a separate Workflow Activity Library?

    - by Kevin Craft
    I am trying to accomplish something that seems like it should be very simple. I have a State Machine Workflow Console Application with a workflow in it. I have created a custom activity for it. This activity will NEVER be used ANYWHERE ELSE. I just want to use this activity on my workflow, but: It does not appear in the toolbox. I cannot drag it from the Solution Explorer onto the workflow designer. I absolutely do not want to create a separate State Machine Workflow Activity Library, since that will just clutter my solution. Like I said, I will never use this activity in any other project, so I would like to keep it confined to this one...but I just can't figure out how to get it onto the designer! Am I going crazy!? Here is the code for the activity: public partial class GameSearchActivity: Activity { public GameSearchActivity() { InitializeComponent(); } public static DependencyProperty QueryProperty = System.Workflow.ComponentModel.DependencyProperty.Register("Query", typeof(string), typeof(GameSearchActivity)); [Description("Query")] [Category("Dependency Properties")] [Browsable(true)] [DesignerSerializationVisibility(DesignerSerializationVisibility.Visible)] public string Query { get { return ((string)(base.GetValue(GameSearchActivity.QueryProperty))); } set { base.SetValue(GameSearchActivity.QueryProperty, value); } } public static DependencyProperty ResultsProperty = System.Workflow.ComponentModel.DependencyProperty.Register("Results", typeof(string), typeof(GameSearchActivity)); [Description("Results")] [Category("Dependency Properties")] [Browsable(true)] [DesignerSerializationVisibility(DesignerSerializationVisibility.Visible)] public IEnumerable<Game_GamePlatform> Results { get { return ((IEnumerable<Game_GamePlatform>)(base.GetValue(GameSearchActivity.ResultsProperty))); } set { base.SetValue(GameSearchActivity.ResultsProperty, value); } } protected override ActivityExecutionStatus Execute(ActivityExecutionContext executionContext) { IDataService ds = executionContext.GetService<IDataService>(); Results = ds.SearchGames(Query); return ActivityExecutionStatus.Closed; } } Thanks. EDIT: OK, so I've discovered that if I change the project type from Console Application to Class Library, the custom activity appears in the toolbox. However, this is not acceptable. It needs to be a Console/Windows Application. Anyone know a way around this?

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  • comma separated values in oracle function body

    - by dmitry
    I've got following oracle function but it does not work and errors out. I used Ask Tom's way to convert comma separated values to be used in select * from table1 where col1 in <> declared in package header: TYPE myTableType IS table of varchar2 (255); Part of package body: l_string long default iv_value_with_comma_separated|| ','; l_data myTableType := myTableType(); n NUMBER; begin begin LOOP EXIT when l_string is null; n := instr( l_string, ',' ); l_data.extend; l_data(l_data.count) := ltrim( rtrim( substr( l_string, 1, n-1 ) ) ); l_string := substr( l_string, n+1 ); END LOOP; end; OPEN my_cursor FOR select * from table_a where column_a in (select * from table (l_data)); CLOSE my_cursor END; above fails but it works fine when I remove select * from table (l_data) Can someone please tell me what I might be doing wrong here??

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  • I have a problem with mysql and php

    - by neo skosana
    Hi I have a problem, this is my code: $db = new mysqli("localhost", "root", "", "blah"); $result1 = $db-query("select * from c_register where email = '$eml' and password = '$pass'"); if($result1-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'client'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result2 = $db-query("select * from b_register where email = '$eml' and password = '$pass'"); if($result2-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'business'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result3 = $db-query("select * from g_register where email = '$eml' and password = '$pass'"); if($result3-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'employee'; promptUser("You have successfully logged in!!!","index.php"); } $db = new mysqli("localhost", "root", "", "blah"); $result4 = $db-query("select * from k_register where email = '$eml' and password = '$pass'"); if($result4-fetch_array()) { $auth->createSession(); $_SESSION['user'] = 'super'; promptUser("You have successfully logged in!!!","index.php"); } else { promptUser("Username/Password do not match. Please try again!!!",""); } Funny enough this code works, but I no that I went about it the wrong way. I am new with php and mysql, so please help. I also tried e.gresult4->free(); for all the variable that save the data, and I got this error: Fatal error: Call to a member function free() on a non-object in...

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  • TextBox value not updated

    - by Jignesh
    I am fetching data from database to textbox using Linq.When i try update the same textbox value,it does not work. DAL.TournamentsDataContext tdc = new SchoolSports.DAL.TournamentsDataContext(); var tournamentTable = tdc.GetTable<DAL.Tournament>(); var tournamentRecord = (from rec in tournamentTable where rec.TournamentId == TournamentId select rec).Single(); tournamentRecord.Tournament_type = Tournament_type; tournamentRecord.Tournament_Name = Tournament_Name; ; tournamentRecord.Tournament_Level = Tournament_Level; tournamentRecord.Tournament_For = Tournament_For; tournamentRecord.Country_Code = Country_Code; tournamentRecord.Tournament_Status = Tournament_Status; tournamentRecord.Tournament_begin_date = Tournament_begin_date; tournamentRecord.Tournament_end_date = Tournament_end_date; tournamentRecord.Sponsored_By = Sponsored_By; tournamentRecord.Tournament_Details = Tournament_Details; var organiserTable = tdc.GetTable<DAL.Organiser>(); var organiserRecord = (from rec in organiserTable where rec.Tournament_Id == TournamentId select rec).Single(); organiserRecord.Name_Of_Organiser = OrName; organiserRecord.Telephone = OrTeleNo; organiserRecord.Email = OrEmail; organiserRecord.Mobile = OrMobile; organiserRecord.Fax = OrFax; if (Tournament_For == "School") { var invitedSchoolIdTable = tdc.GetTable<DAL.Invited_School>(); var invitedSchoolIdRecord = (from rec in invitedSchoolIdTable where rec.Tournament_Id == TournamentId select rec).Single(); invitedSchoolIdRecord.School_Ids = SchoolUniIds; } if (Tournament_For == "University") { var invitedUniversityTable = tdc.GetTable<DAL.Invited_University>(); var invitedUniversityIdRecord = (from rec in invitedUniversityTable where rec.Tournament_Id == TournamentId select rec).Single(); invitedUniversityIdRecord.University_Ids = SchoolUniIds; } tdc.SubmitChanges();

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  • How to write this function as a pL/pgSQl function ?

    - by morpheous
    I am trying to implement some business logic in a PL/pgSQL function. I have hacked together some pseudo code that explains the type of business logic I want to include in the function. Note: This function returns a table, so I can use it in a query like: SELECT A.col1, B.col1 FROM (SELECT * from some_table_returning_func(1, 1, 2, 3)) as A, tbl2 as B; The pseudocode of the pl/PgSQL function is below: CREATE FUNCTION some_table_returning_func(uid int, type_id int, filter_type_id int, filter_id int) RETURNS TABLE AS $$ DECLARE where_clause text := 'tbl1.id = ' + uid; ret TABLE; BEGIN switch (filter_type_id) { case 1: switch (filter_id) { case 1: where_clause += ' AND tbl1.item_id = tbl2.id AND tbl2.type_id = filter_id'; break; //other cases follow ... } break; //other cases follow ... } // where clause has been built, now run query based on the type ret = SELECT [COL1, ... COLN] WHERE where_clause; IF (type_id <> 1) THEN return ret; ELSE return select * from another_table_returning_func(ret,123); ENDIF; END; $$ LANGUAGE plpgsql; I have the following questions: How can I write the function correctly to (i.e. EXECUTE the query with the generated WHERE clause, and to return a table How can I write a PL/pgSQL function that accepts a table and an integer and returns a table (another_table_returning_func) ?

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  • Javascript timezone solution needed(taking into account the actual difference in UTC timestamps)

    - by user198729
    I have unix timestamps from time zone X which is not known, the current timestamp(now()) in TZ X is known 1275143019, how to approach a javascript function so that it can generate the datetime in the users current TZ in the format 2010-05-29 15:32:35 ? UPDATE I'm not a unix timestamp expert,if unix timestamp is always the same in different TZ, then I have to change the question a little,so that the current datetime in TZ X is known(like 2010-05-29 22:32:28),and the other datetime is also in this format,how to convert them to the user's TZ based on the difference between now() ? UPDATE Something strange from MySQL: On server: mysql> select now(); +---------------------+ | now() | +---------------------+ | 2010-05-29 18:34:30 | +---------------------+ 1 row in set (0.00 sec) mysql> select UNIX_TIMESTAMP(); +------------------+ | UNIX_TIMESTAMP() | +------------------+ | 1275143674 | +------------------+ 1 row in set (0.00 sec) On local: mysql> select now(); +---------------------+ | now() | +---------------------+ | 2010-05-29 22:41:30 | +---------------------+ 1 row in set (0.00 sec) mysql> select UNIX_TIMESTAMP(); +------------------+ | UNIX_TIMESTAMP() | +------------------+ | 1275144091 | +------------------+ 1 row in set (0.00 sec) Why the difference between now() (2010-05-29 22:41:30-2010-05-29 18:34:30=6hours) and UNIX_TIMESTAMP() (1275144091 - 1275143674 = 417seconds) is not the same ?

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  • Loading default value in a dropdown and calling onchange event

    - by J. Davidson
    Hi i have following dropdown <div class="fcolumn"> <label class="text" for="o_Id">Months:</label> <select class="textMonths" id="o_Id" name="periodName" > <option value="000">Select Period--</option> </select> </div> In the following jquery, first it loads fnLoadP() in a drop down list. Than as a default I am loading one of the values in drop down which is '10'. It loads too as default value. But it should be executing $("#o_Id").change.. which it doesn't. $(document).ready(function () { var sProfileUserId = null; $("#o_Id").change(function () { //---- }); fnLoadP(); $("select[name='pName']").val('10'); }); }); Basically my goal is. After dropdown values are loaded, to load '10' as default value and call onchange event in the dom. Please let me know how to fix it.

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  • NHibernate unintential lazy property loading

    - by chiccodoro
    I introduced a mapping for a business object which has (among others) a property called "Name": public class Foo : BusinessObjectBase { ... public virtual string Name { get; set; } } For some reason, when I fetch "Foo" objects, NHibernate seems to apply lazy property loading (for simple properties, not associations): The following code piece generates n+1 SQL statements, whereof the first only fetches the ids, and the remaining n fetch the Name for each record: ISession session = ...IQuery query = session.CreateQuery(queryString); ITransaction tx = session.BeginTransaction(); List<Foo> result = new List<Foo>(); foreach (Foo foo in query.Enumerable()) { result.Add(foo); } tx.Commit(); session.Close(); produces: NHibernate: select foo0_.FOO_ID as col_0_0_ from V1_FOO foo0_ NHibernate: SELECT foo0_.FOO_ID as FOO1_2_0_, foo0_.NAME as NAME2_0_ FROM V1_FOO foo0_ WHERE foo0_.FOO_ID=:p0;:p0 = 81 NHibernate: SELECT foo0_.FOO_ID as FOO1_2_0_, foo0_.NAME as NAME2_0_ FROM V1_FOO foo0_ WHERE foo0_.FOO_ID=:p0;:p0 = 36470 NHibernate: SELECT foo0_.FOO_ID as FOO1_2_0_, foo0_.NAME as NAME2_0_ FROM V1_FOO foo0_ WHERE foo0_.FOO_ID=:p0;:p0 = 36473 Similarly, the following code leads to a LazyLoadingException after session is closed: ISession session = ... ITransaction tx = session.BeginTransaction(); Foo result = session.Load<Foo>(id); tx.Commit(); session.Close(); Console.WriteLine(result.Name); Following this post, "lazy properties ... is rarely an important feature to enable ... (and) in Hibernate 3, is disabled by default." So what am I doing wrong? I managed to work around the LazyLoadingException by doing a NHibernateUtil.Initialize(foo) but the even worse part are the n+1 sql statements which bring my application to its knees. This is how the mapping looks like: <class name="Foo" table="V1_FOO"> ... <property name="Name" column="NAME"/> </class> BTW: The abstract "BusinessObjectBase" base class encapsulates the ID property which serves as the internal identifier.

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  • Creating reusable chunks of Linq to SQL

    - by tia
    Hi, I am trying to break up horrible linq to sql queries to make them a bit more readable. Say I want to return all orders for product which in the previous year had more than 100 orders. So, original query is: from o in _context.Orders where (from o1 in _context.Orders where o1.Year == o.Year - 1 && o1.Product == o.Product select o1).Count() > 100 select o; Messy. What I'd like to be able to do is to be able to break it down, eg: private IEnumerable<Order> LastSeasonOrders(Order order) { return (from o in _context.Orders where o.Year == order.Year - 1 && o.Product == order.Product select o); } which then lets me change the original query to: from o in _context.Orders where LastSeasonOrders(o).Count() > 100 select o; This doesn't seem to work, as I get method Blah has no supported translation to SQL when the query is run. Any quick tips on the correct way to achieve this?

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