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  • How to save/retrieve words to/from SQlite database?

    - by user998032
    Sorry if I repeat my question but I have still had no clues of what to do and how to deal with the question. My app is a dictionary. I assume that users will need to add words that they want to memorise to a Favourite list. Thus, I created a Favorite button that works on two phases: short-click to save the currently-view word into the Favourite list; and long-click to view the Favourite list so that users can click on any words to look them up again. I go for using a SQlite database to store the favourite words but I wonder how I can do this task. Specifically, my questions are: Should I use the current dictionary SQLite database or create a new SQLite database to favorite words? In each case, what codes do I have to write to cope with the mentioned task? Could anyone there kindly help? Here is the dictionary code: package mydict.app; import java.util.ArrayList; import android.database.Cursor; import android.database.sqlite.SQLiteDatabase; import android.database.sqlite.SQLiteException; import android.util.Log; public class DictionaryEngine { static final private String SQL_TAG = "[MyAppName - DictionaryEngine]"; private SQLiteDatabase mDB = null; private String mDBName; private String mDBPath; //private String mDBExtension; public ArrayList<String> lstCurrentWord = null; public ArrayList<String> lstCurrentContent = null; //public ArrayAdapter<String> adapter = null; public DictionaryEngine() { lstCurrentContent = new ArrayList<String>(); lstCurrentWord = new ArrayList<String>(); } public DictionaryEngine(String basePath, String dbName, String dbExtension) { //mDBExtension = getResources().getString(R.string.dbExtension); //mDBExtension = dbExtension; lstCurrentContent = new ArrayList<String>(); lstCurrentWord = new ArrayList<String>(); this.setDatabaseFile(basePath, dbName, dbExtension); } public boolean setDatabaseFile(String basePath, String dbName, String dbExtension) { if (mDB != null) { if (mDB.isOpen() == true) // Database is already opened { if (basePath.equals(mDBPath) && dbName.equals(mDBName)) // the opened database has the same name and path -> do nothing { Log.i(SQL_TAG, "Database is already opened!"); return true; } else { mDB.close(); } } } String fullDbPath=""; try { fullDbPath = basePath + dbName + "/" + dbName + dbExtension; mDB = SQLiteDatabase.openDatabase(fullDbPath, null, SQLiteDatabase.OPEN_READWRITE|SQLiteDatabase.NO_LOCALIZED_COLLATORS); } catch (SQLiteException ex) { ex.printStackTrace(); Log.i(SQL_TAG, "There is no valid dictionary database " + dbName +" at path " + basePath); return false; } if (mDB == null) { return false; } this.mDBName = dbName; this.mDBPath = basePath; Log.i(SQL_TAG,"Database " + dbName + " is opened!"); return true; } public void getWordList(String word) { String query; // encode input String wordEncode = Utility.encodeContent(word); if (word.equals("") || word == null) { query = "SELECT id,word FROM " + mDBName + " LIMIT 0,15" ; } else { query = "SELECT id,word FROM " + mDBName + " WHERE word >= '"+wordEncode+"' LIMIT 0,15"; } //Log.i(SQL_TAG, "query = " + query); Cursor result = mDB.rawQuery(query,null); int indexWordColumn = result.getColumnIndex("Word"); int indexContentColumn = result.getColumnIndex("Content"); if (result != null) { int countRow=result.getCount(); Log.i(SQL_TAG, "countRow = " + countRow); lstCurrentWord.clear(); lstCurrentContent.clear(); if (countRow >= 1) { result.moveToFirst(); String strWord = Utility.decodeContent(result.getString(indexWordColumn)); String strContent = Utility.decodeContent(result.getString(indexContentColumn)); lstCurrentWord.add(0,strWord); lstCurrentContent.add(0,strContent); int i = 0; while (result.moveToNext()) { strWord = Utility.decodeContent(result.getString(indexWordColumn)); strContent = Utility.decodeContent(result.getString(indexContentColumn)); lstCurrentWord.add(i,strWord); lstCurrentContent.add(i,strContent); i++; } } result.close(); } } public Cursor getCursorWordList(String word) { String query; // encode input String wordEncode = Utility.encodeContent(word); if (word.equals("") || word == null) { query = "SELECT id,word FROM " + mDBName + " LIMIT 0,15" ; } else { query = "SELECT id,content,word FROM " + mDBName + " WHERE word >= '"+wordEncode+"' LIMIT 0,15"; } //Log.i(SQL_TAG, "query = " + query); Cursor result = mDB.rawQuery(query,null); return result; } public Cursor getCursorContentFromId(int wordId) { String query; // encode input if (wordId <= 0) { return null; } else { query = "SELECT id,content,word FROM " + mDBName + " WHERE Id = " + wordId ; } //Log.i(SQL_TAG, "query = " + query); Cursor result = mDB.rawQuery(query,null); return result; } public Cursor getCursorContentFromWord(String word) { String query; // encode input if (word == null || word.equals("")) { return null; } else { query = "SELECT id,content,word FROM " + mDBName + " WHERE word = '" + word + "' LIMIT 0,1"; } //Log.i(SQL_TAG, "query = " + query); Cursor result = mDB.rawQuery(query,null); return result; } public void closeDatabase() { mDB.close(); } public boolean isOpen() { return mDB.isOpen(); } public boolean isReadOnly() { return mDB.isReadOnly(); } } And here is the code below the Favourite button to save to and load the Favourite list: btnAddFavourite = (ImageButton) findViewById(R.id.btnAddFavourite); btnAddFavourite.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { // Add code here to save the favourite, e.g. in the db. Toast toast = Toast.makeText(ContentView.this, R.string.messageWordAddedToFarvourite, Toast.LENGTH_SHORT); toast.show(); } }); btnAddFavourite.setOnLongClickListener(new View.OnLongClickListener() { @Override public boolean onLongClick(View v) { // Open the favourite Activity, which in turn will fetch the saved favourites, to show them. Intent intent = new Intent(getApplicationContext(), FavViewFavourite.class); intent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK); getApplicationContext().startActivity(intent); return false; } }); }

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  • How to create multiple inputs in yii + Q&A admin page

    - by user1764357
    In yii, i am developing page for Creating Question with multiple options using forms. So i have two tables Question QuestionId Question optionId Option OptionId Option To create multiple options, option field should be provided with add button so that after clicking add button, it should display new textbox control to get the new option. All these options displayed in a gridview. So can you please help me. I am very new to yii.

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  • Drupal menu permissions question

    - by Luke
    I'm creating an admin module for my client that gives then access to some administration functionality concerning their content. I'm starting off my adding some permissions in my module by implementing hook_perm: function mymodule_perm() { return array( 'manage projects', ); } I can then create my menu by adding to the admin section that already exists: function mymodule_menu() { $items['admin/projects'] = array( 'title' => 'Projects', 'description' => 'Manage your projects.', 'page callback' => 'manage_projects_overview', 'access callback' => 'user_access', 'access arguments' => array('manage projects'), 'type' => MENU_NORMAL_ITEM, 'weight' => -100, ); $items['admin/projects/add'] = array( 'title' => 'Add project', 'access arguments' => array('manage projects'), 'page callback' => 'mymodule_projects_add', 'type' => MENU_NORMAL_ITEM, 'weight' => 1, ); return $items; } This will add a Projects section to the Administration area with an Add project sub section. All good. The behavior I want is that my client can only see the Projects section when they log in. I've accomplished this by ticking the "manage projects" permission for authenticated users. Now to give my client actual access to the Administration area I also need to tick "access administration pages" under the "system module" in the users permissions section. This works great, when I log in as my client I can only see the Projects section in the Administration area. There is one thing though, I my Navigation menu shown in the left column I can see the following items: - Administer - Projects - Content management - Site building - Site configuration - User management I was expecting only the see Administer and Projects, not the other ones. When I click e.g. Content Management I get a Content Management titled page with no options. Same for Site Building, Site Configuration and User Management. What's really odd is that Reports is not being shown which is also a top level Administration section. Why are these other items, besides my Projects section, being shown and how can I make them stop from appearing if I'm not logged in as administrator?

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  • Chrome not displaying a div

    - by Kyle Sevenoaks
    Click here to see a simple example of what I want. It's really easy, but for some reason Google won't display the "subTotalCaption2" div. It's part of a foreach loop, if needed I can add other codes. There is nothing else in the rest of the css to mess with this, I have checked about 10 times. See it live at euroworker.no/order (add items to basket) In FF and Chrome. Thanks.

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  • script attributes

    - by Alex Ivasyuv
    Hi, I need to control some script elements, that's why I want to add class attribute to do it. But, w3c says that it's invalid. Some effect, if I add rel or id attribute. Any other ideas how I can access appropriate script tag? Doctype: XHTML 1.0 Strict Thanks,

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  • Problem with displaying usernames in my flash[:notice] - Agile Web Development With Rails - Chapter

    - by Lee
    I can't figure out what I'm doing wrong here. I can’t seem to get the #{@user.name} to work in my flash[:notice] Everything else works just fine I can add new users, but when I add a new user instead of saying “User John Doe was successfully created”, it says “User #{@user.name} was successfully created.” I'm at this point in the depot app: depot_p/app/controllers/users_controller.rb to work.

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  • JQuery addclass to another div (but not parent) if no data is found

    - by Danny
    I have this to add a class to the main table that the report is in if there is no data returned. $('#report-area table td:contains("Sorry, your search did not return any data")').parents('#reportArea').addClass('no-report-data') However, I have another div area "#report-footer" but it's not inside #report-area. I'd like to also add the .no-report-data class to "#report-footer" as well but in this case I don't think the .parents selector will work. Is there another selector I can use to do this?

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  • Annotate anonymous inner class

    - by Scobal
    Is there a way to annotate an anonymous inner class in Java? In this example could you add a class level annotation to Class2? public void method1() { add(new Class2() { public void method3() {} }); }

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  • Windows Azure and dynamic elasticity

    - by Ryan Elkins
    Is there a way do do dynamic elasticity in Windows Azure? If my workers begin to get overloaded, or queues start to get too full, or too many workers have no work to do, is there a way to dynamically add or remove workers through code or is that just done manually (requires human intervention) right now? Does anyone know of any plans to add that if its not currently available?

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  • What can be inside a class that derive from OmniAuth?

    - by Richard77
    I have the following class class Identity < OmniAuth:: Identity:: Models:: ActiveRecord attr_accessible :email, :name, :password_digest, :password, :password_confirmation end I wonder if the above properties are the only ones allowed for a class that derive from a OmniAuth. I wish I could add some more like FirstName, LastName, age, gender, and so on. Do I need to create an other model for those properties or can I just add them to the Identity model? Thanks for helping.

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  • adding a UITableView programmatically to a UIViewController

    - by Adam
    I'm loading a UIViewController into one of my Nav controller's hierarchies, which will contain some text and some images. At the bottom, I will want to create a expandable and collapsable tableview. First off, is this idea possible? If it is, how do I add it and where do I place the data source and delegate methods? Can I just make a separate subclass of the TableViewController and then add it to my ViewController as a subview?

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  • Get return values from a stored procedure in c# (login process)

    - by Jin
    Hi all, I am trying to use a Stored Procedure which takes two parameters (login, pw) and returns the user info. If I execute the SP manually, I get Session_UID User_Group_Name Sys_User_Name ------------------------------------ -------------------------------------------------- - NULL Administrators NTMSAdmin No rows affected. (1 row(s) returned) @RETURN_VALUE = 0 Finished running [dbo].[p_SYS_Login]. But with the code below, I only get the return value. do you know how to get the other values shown above like Session_UID, User_Group_Name, and Sys_User_Name ? if you see the commented part below code. I tried to add some output parameters but it doesn't work with incorrect number of parameters error. string strConnection = Settings.Default.ConnectionString; using (SqlConnection conn = new SqlConnection(strConnection)) { using (SqlCommand cmd = new SqlCommand()) { SqlDataReader rdr = null; cmd.Connection = conn; cmd.CommandText = "p_SYS_Login"; //cmd.CommandText = "p_sys_Select_User_Group"; cmd.CommandType = CommandType.StoredProcedure; SqlParameter paramReturnValue = new SqlParameter(); paramReturnValue.ParameterName = "@RETURN_VALUE"; paramReturnValue.SqlDbType = SqlDbType.Int; paramReturnValue.SourceColumn = null; paramReturnValue.Direction = ParameterDirection.ReturnValue; //SqlParameter paramGroupName = new SqlParameter("@User_Group_Name", SqlDbType.VarChar, 50); //paramGroupName.Direction = ParameterDirection.Output; //SqlParameter paramUserName = new SqlParameter("@Sys_User_Name", SqlDbType.VarChar, 50); //paramUserName.Direction = ParameterDirection.Output; cmd.Parameters.Add(paramReturnValue); //cmd.Parameters.Add(paramGroupName); //cmd.Parameters.Add(paramUserName); cmd.Parameters.AddWithValue("@Sys_Login", textUserID.Text); cmd.Parameters.AddWithValue("@Sys_Password", textPassword.Text); try { conn.Open(); object result = cmd.ExecuteNonQuery(); int returnValue = (int)cmd.Parameters["@RETURN_VALUE"].Value; if (returnValue == 0) { Hide(); Program.MapForm.Show(); } else if (returnValue == 1) { MessageBox.Show("The username or password you entered is incorrect", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } else if (returnValue == 2) { MessageBox.Show("This account is disabled", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } else { MessageBox.Show("Database error. Please contact administrator", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } } catch (Exception ex) { string message = ex.Message; string caption = "MAVIS Exception"; MessageBoxButtons buttons = MessageBoxButtons.OK; MessageBox.Show( message, caption, buttons, MessageBoxIcon.Warning, MessageBoxDefaultButton.Button1); } } } Thanks for your help.

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  • outllook addin threading issues

    - by Sanju
    hi i am having threading issues in my vsto project // code for function var threadUpdate = new Thread(_fun){IsBackgroud = true}; threadUpdate.Start(); threadList.add(threadUpdate); // code for progressbar Progressbar pb = new Prgressbar(){Title =@"abc"} pb.Show() it was working in perfect condition before i add wpf progress bar. as the plugin has been running as single thread can i ask how can running multi threading in outlook thanks

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  • Can I have a set containing identical elements?

    - by Roman
    It is convenient for me to use a set. I like how I can "add" ("remove") an element to (from) the set. It is also convenient to check if a given element is in the set. The only problem, I found out that I cannot add a new element to a set if the set has already such an element. Is it possible to have "sets" which can contain several identical elements.

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  • How to make the firewall popup a warning to my http server?

    - by user497032
    I integrated a small http server in my software distribution, so when my customer installs my software, a http server is also installed on his computer, he can visit the http server from his LAN (local network). The problem is that my customer has to manually add my software into the firewall's trusted applications list, I want the firewall to AUTOMATICALLY popup warning to let my customer choose yes/no to add my software into trusted applications list when my customer visit the small http server from LAN at first time. Any suggestions?

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  • hibernate search and projection - different fields on different objects

    - by Odelya
    Hi! I have the following code: Criteria crit = sess.createCriteria(Product.class); ProjectionList proList = Projections.projectionList(); proList.add(Projections.property("name")); proList.add(Projections.property("price")); crit.setProjection(proList); But I also have User.class and I would like the name to be restricted on User.class and price from Product class. How can I restrict different columns on different objects in Hibernate Search?

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  • FBML limit on Fan pages...

    - by Monosofr
    I tried to add 15 tabs to a page of mine, with just images and information, but i could only add 10 FMBL apps and make them on tabs...Any idea whether the FMBL limit is 10 ? Is there any way i can increase that limit ?

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  • how to build a simple gridview only for insertion (no bind)?

    - by user359706
    Hello, how do I implement a rapid gridview with two columns, with ability to add rows by clicking the add button, and remove in the same way. I look for plugins, but often contain many unnecessary option in my case, I'm looking for something fairly simple. solution jquery, ajax.. I'm using ASP.net (C #) someone has an idea ? thank you

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  • SE friendly URLs appache code snippets

    - by Dan
    I want example.com/23-45 be transformed to example.com?id=23-45 Could you please post the code I should add to .htaccess file to make this work (Is this everything I should do to make this work - add a piece of code to .htaccess file ???) Thanks a lot!

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  • Dojo treemodel- adding large number of items

    - by Ashley
    I am trying to add a large number of items (100+) to my tree via ForestStoreModel by calling newItem in a loop. This seems to be quite slow and locks up the browser. Is there any way I can do something similar to grid's beginUpdate & endUpdate? I want to basically 'turn off' my tree, add 100 items in a batch, then 'turn on' my tree. Any ideas? Thanks!

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  • jquery - clone nth row of a table?

    - by John
    I'm trying to use jquery to clone a table row everytime someone presses the add-row button. Can anyone tell me what's wrong with my code? I'm using HTML + smarty templating language in my view. Here's what my template file looks like: <table> <tr> <td>Description</td> <td>Unit</td> <td>Qty</td> <td>Total</td> <td></td> </tr> <tbody id="entries"> {foreach from=$arrItem item=i name=inv} <tr> <td> <input type="hidden" name="invoice_item_id[]" value="{$i.invoice_item_id}"/> <input type="hidden" name="assignment_id[]" value="{$i.assignment_id}" /> <input type="text" name="description[]" value="{$i.description}"/> </td> <td><input type="text" class="unit_cost" name="unit_cost[]" value="{$i.unit_cost}"/></td> <td><input type="text" class="qty" name="qty[]" value="{$i.qty}"/></td> <td><input type="text" class="cost" name="cost[]" value="{$i.cost}"/></td> <td><a href="javascript:void(0);" class="delete-invoice-item">delete</a></td> </tr> {/foreach} </tbody> <tfoot> <tr><td colspan="5"><input type="button" id="add-row" value="add row" /></td></tr> </tfoot> </table> Here's my Jquery Javascript call, which I know gets fired when I put in an alert() statement. So the problem is with me not knowing how jquery works. $('#add-row').live('click', function() {$('#entries tr:nth-child(0)').clone().appendTo('#entries');}); So what am I doing wrong?

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  • Decorator Design Pattern Use With Service Objects (wSingleton)

    - by Dustin
    I'm working on a project where I need to add some functionality to a service object and using a decorator to add it in seems like a good fit. However, I've only ever used decorators with simple beans, never on a singleton like a service object. Has anyone ever done this before and what are the pros and cons? In this case I don't think creating a subclass will work so a decorator seems to be a good fit. What are your thoughts on doing this?

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  • C# Property Delegate?

    - by Mark
    In my other methods I could do something like this, public void Add(T item) { if (dispatcher.CheckAccess()) { ... } else { dispatcher.Invoke(new Action<T>(Add), item); } } But how do I invoke a property for a situation like this? public T this[int index] { get { ... } set { if (dispatcher.CheckAccess()) { ... } else { dispatcher.Invoke(???, index); // <-- problem is here } } }

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