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  • How can I run an android frame animation without it skewing?

    - by GameDev123
    I have a small state machine that runs a series of frame by frame animations in an ImageView, in a nested hierarchy of layouts. There is more than adequate space to display each frame of the animation. Each frame of the animation is cropped to fit the minimum amount of area, in order to save memory. If a frame only contains 50x50 worth of pixels then the png is 50x50. There is no transparent padding to keep them the same size. The ImageView is directly within a RelativeLayout, and is anchored to the bottom left with some padding. The general idea being that the character in the animation performs some action, which results in individual frames of the animation growing or shrinking. The issue is that individual frames of animation are skewed, and there does not appear to be any way of preventing this. If I set the source of the imageview directly to one of the frames of animation, it displays fine in the layout manager. I have tried this with Adjust View Bounds set to true, false, and undefined. I have tried using the background and the src attribute of imageview to set the animation drawable, I have tried every configuration of layout manager and setting minimum/maximum size that I can think of, and it still stretches the character on various frames depending on the size of the source png. In essence, all I want to do is say "I want this ImageView to anchor in the bottom left and then display any frame that happens to be in it without stretching or skewing it in any way aside from that which occurred when the frame png's were loaded." Seems simple, but I have yet to come across any way of doing it. Here is the layout of the imageview as of my last test, I had to remove bits of the XML to get it to display but nothing pertinent: RelativeLayout android:orientation="horizontal" android:layout_above="@+id/MenuOptions" android:layout_width="fill_parent" android:id="@+id/AnimationLayout" android:clipChildren="false" android:minHeight="180dp" android:layout_height="fill_parent" android:layout_below="@+id/GameBarLayout" ImageView android:id="@+id/animatedImg" android:layout_height="wrap_content" android:layout_width="wrap_content" android:visibility="visible" android:baselineAlignBottom="true" android:minHeight="180dp" android:minWidth="200dp" android:adjustViewBounds="true" android:layout_alignParentBottom="true" android:paddingLeft="30dp" android:paddingBottom="10dp" android:src="@drawable/idle01"/ImageView /RelativeLayout Here is how an animation is set up: animationDrawable = new AnimationDrawable(); animationDrawable.addFrame(res.getDrawable(R.drawable.idle01), 16); animationDrawable.addFrame(res.getDrawable(R.drawable.idle02), 16); animationDrawable.addFrame(res.getDrawable(R.drawable.idle03), 16);

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  • Defining a select list through controller and view model

    - by Ibrar Hussain
    I have a View Model that looks like this: public class SomeViewModel { public SomeViewModel(IEnumerable<SelectListItem> orderTemplatesListItems) { OrderTemplateListItems = orderTemplatesListItems; } public IEnumerable<SelectListItem> OrderTemplateListItems { get; set; } } I then have an Action in my Controller that does this: public ActionResult Index() { var items = _repository.GetTemplates(); var selectList = items.Select(i => new SelectListItem { Text = i.Name, Value = i.Id.ToString() }).ToList(); var viewModel = new SomeViewModel { OrderTemplateListItems = selectList }; return View(viewModel); } Lastly my view: @Html.DropDownListFor(n => n.OrderTemplateListItems, new SelectList(Model.OrderTemplateListItems, "value", "text"), "Please select an order template") The code works fine and my select list populates wonderfully. Next thing I need to do is set the selected value that will come from a Session["orderTemplateId"] which is set when the user selects a particular option from the list. Now after looking online the fourth parameter should allow me to set a selected value, so if I do this: @Html.DropDownListFor(n => n.OrderTemplateListItems, new SelectList(Model.OrderTemplateListItems, "value", "text", 56), "Please select an order template") 56 is the Id of the item that I want selected, but to no avail. I then thought why not do it in the Controller? As a final attempt I tried building up my select list items in my Controller and then passing the items into the View: public ActionResult Index() { var items = _repository.GetTemplates(); var orderTemplatesList = new List<SelectListItem>(); foreach (var item in items) { if (Session["orderTemplateId"] != null) { if (item.Id.ToString() == Session["orderTemplateId"].ToString()) { orderTemplatesList.Add(new SelectListItem { Text = item.Name, Value = item.Id.ToString(), Selected = true }); } else { orderTemplatesList.Add(new SelectListItem { Text = item.Name, Value = item.Id.ToString() }); } } else { orderTemplatesList.Add(new SelectListItem { Text = item.Name, Value = item.Id.ToString() }); } } var viewModel = new SomeViewModel { OrderTemplateListItems = orderTemplatesList }; return View(viewModel); } Leaving my View like so: @Html.DropDownListFor(n => n.OrderTemplateListItems, new SelectList(Model.OrderTemplateListItems, "value", "text"), "Please select an order template") Nothing! Why isn't this working for me?

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  • Changing the title of jQuery-UI dialog-box with in another dialog-box's function...

    - by Brian Ojeda
    Why doesn't doesn't the second jQuery-UI dialog box title change when popped. The first dialog box I change the title of the box with using the following .attr("title", "Confirm") -- it change the title of the first box to 'Confirm', like it should have. Now when the second box pops up it should change the title to 'Message' since did the same thing for the second box -- .attr("title", "Message"). Right? But it doesnt. It keep the title from before. However, the message change like it should have. I have tested in IE8, Chrome, and FF3.6. <div id="dialog-confirm" title=""></div> <-- This is the html before jQuery functions. Javascript / jQuery $('#userDelete').click(function() { $(function() { var dialogIcon = "<span class=\"ui-icon ui-icon-alert\"></span>"; var dialogMessage = dialogIcon + "Are you sure you want to delete?"; $("#dialog-confirm").attr("title", "Confirm").html(dialogMessage).dialog({ resizable: false, height: 125, width: 300, modal: true, buttons: { 'Delete': function() { $(this).dialog('close'); $.post('user_ajax.php', {action: 'delete', aId: $('[name=aId]').val() }, function(data) { if(data.success){ var dialogIcon = "<span class=\"ui-icon ui-icon-info\"></span>"; var dialogMessage = dialogIcon + data.message; $('#dialog-confirm').attr("title", "Message"); $('#dialog-confirm').html(dialogMessage); $('#dialog-confirm').dialog({ resizable: false, height: 125, width: 300, modal: true, buttons: { 'Okay': function() { $(this).dialog('close'); var url = $_httpaddress + "admin/index.php" $(location).attr('href',url); } // End of Okay Button Function } //--- End of Dialog Button Script });//--- End of Dialog Function } else { $_messageConsole.slideDown(); $_messageConsole.html(data.message); } }, 'json'); }, //--- End of Delete Button Function 'Cancel': function() { $(this).dialog('close'); } //--- End of Cancel Button Function } //--- End of Dialog Button Script }); //--- End of Dialog Script }); //--- End of Dialog Function return false; }); Thank you for you assistant, if you choose to help.

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  • php code is not fetching data from mysql database using wamp server

    - by john
    I want to display a table from database in phpMyAdmin by putting the following conditions that in every different options in drop down menu it displays different table from database by pressing the button of search. But it is not doing so. <p class="h2">Quick Search</p> <div class="sb2_opts"> <p></p> <form method="post" action="" > <p>Enter your source and destination.</p> <p>From:</p> <select name="from"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <p>To:</p> <select name="To"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <input type="submit" value="search" /> </form> </form> </table> <?php $con=mysqli_connect("localhost","root","","test"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } if(isset($_POST['from']) and isset($_POST['To'])) { $from = $_POST['from'] ; $to = $_POST['To'] ; $table = array($from, $to); switch ($table) { case array ("Islamabad", "Lahore") : $result = mysqli_query($con,"SELECT * FROM flights"); echo "</flights>"; //table name is flights break; case array ("Islamabad", "Murree") : $result = mysqli_query($con,"SELECT * FROM isb to murree"); echo "</isb to murree>"; //table name isb to murree ; break; case array ("Islamabad", "Muzaffarabad") : $result = mysqli_query($con,"SELECT * FROM isb to muzz"); echo "</isb to muzz>"; break; //..... //...... default: echo "Your choice is nor valid !!"; } } mysqli_close($con); ?>

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  • Crystal Reports : How to add an external assembly class?

    - by Sunil
    I am using VS2010, CrystalReport13 & MVC3. My problem is unable to add an external assembly in Crystal Report using "Database Expert" Option. I have a class named WeeklyReportModel in an external assembly. In my web project, data retrieving from DB as IEnumerable collection of WeeklyReportModel. I tried ProjectData - .NetObjects in Crystal Report for adding the WeeklyReportModel. But this external assembly is not showing under ".NetObjects". Then I tried other option as Create New Connection - ADO.Net – Make New Connection and pointed this External Assembly. It has been added under Ado.Net node, but while expanding displays as "...no items found..." Totally frustrated. Please help. External Assembly Class: namespace SMS.Domain { public class WeeklyReportModel { public int StoreId { get; set; } public string StoreName{ get; set; } public decimal Saturday { get; set; } public decimal Sunday { get; set; } public decimal Monday { get; set; } public decimal Tuesday { get; set; } public decimal Wednesday { get; set; } public decimal Thurday { get; set; } public decimal Friday { get; set; } public decimal Average { get; set; } public string DateRange { get; set; } } } In Controller-action[Data retrieving as Collection Of WeeklyReportModel] namespace SMS.UI.Controllers { public class ReportController : Controller { public ActionResult StoreWeeklyReport(string id) { DateTime weekStart, weekClose; string[] dateArray = id.Split('_'); weekStart = Convert.ToDateTime(dateArray[0].ToString()); weekClose = Convert.ToDateTime(dateArray[1].ToString()); SMS.Infrastructure.Report.AuditReport weeklyReport = new SMS.Infrastructure.Report.AuditReport(); IEnumerable<SMS.Domain.WeeklyReportModel> weeklyRpt = weeklyReport.ReportByStore().WeeklyReport(weekStart, weekClose); Session["WeeklyData"] = weeklyRpt; Response.Redirect("~/Reports/Weekly/StoreWeekly.aspx"); return View(); } } } Thanks in advance.

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  • Defined variables and arrays vs functions in php

    - by Frank Presencia Fandos
    Introduction I have some sort of values that I might want to access several times each page is loaded. I can take two different approaches for accessing them but I'm not sure which one is 'better'. Three already implemented examples are several options for the Language, URI and displaying text that I describe here: Language Right now it is configured in this way: lang() is a function that returns different values depending on the argument. Example: lang("full") returns the current language, "English", while lang() returns the abbreviation of the current language, "en". There are many more options, like lang("select"), lang("selectact"), etc that return different things. The code is too long and irrelevant for the case so if anyone wants it just ask for it. Url The $Url array also returns different values depending on the request. The whole array is fully defined in the beginning of the page and used to get shorter but accurate links of the current page. Example: $Url['full'] would return "http://mypage.org/path/to/file.php?page=1" and $Url['file'] would return "file.php". It's useful for action="" within the forms and many other things. There are more values for $Url['folder'], $Url['file'], etc. Same thing about the code, if wanted, just request it. Text [You can skip this section] There's another array called $Text that is defined in the same way than $Url. The whole array is defined at the beginning, making a mysql call and defining all $Text[$i] for current page with a while loop. I'm not sure if this is more efficient than multiple calls for a single mysql cell. Example: $Text['54'] returns "This is just a test array!" which this could perfectly be implemented with a function like text(54). Question With the 3 examples you can see that I use different methods to do almost the same function (no pun intended), but I'm not sure which one should become the standard one for my code. I could create a function called url() and other called text() to output what I want. I think that working with functions in those cases is better, but I'm not sure why. So I'd really appreciate your opinions and advice. Should I mix arrays and functions in the way I described or should I just use funcions? Please, base your answer in this: The source needs to be readable and reusable by other developers Resource consumption (processing, time and memory). The shorter the code the better. The more you explain the reasons the better. Thank you PS, now I know the differences between $Url and $Uri.

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  • PHP & MySQL - saving and looping problems.

    - by R.I.P.coalMINERS
    I'm new to PHP and MySQL I want a user to be able to store multiple names and there meanings in a MySQL database tables named names using PHP I will dynamically create form fields with JQuery every time a user clicks on a link so a user can enter 1 to 1,000,000 different names and there meanings which will be stored in a table called names. Since I asked my last question I figured out how to store my values from my form using the for loop but every time I loop my values when I add one or more dynamic fields the second form field named meaning will not save the value entered also my dynamic form fields keep looping doubling, tripling and so on the entered values into the database it all depends on how many form fields are added dynamically. I was wondering how can I fix these problems? On a side note I replaced the query with echo's to see the values that are being entered. Here is the PHP code. <?php if(isset($_POST['submit'])) { $mysqli = mysqli_connect("localhost", "root", "", "site"); $dbc = mysqli_query($mysqli,"SELECT * FROM names WHERE userID='$userID'"); $name = $_POST['name']; $meaning = $_POST['meaning']; if(isset($name['0']) && mysqli_num_rows($dbc) == 0 && trim($name['0'])!=='' && trim($meaning['0'])!=='') { for($n = 0; $n < count($name); $n++) { for($m = 0; $m < count($meaning); $m++) { echo $name[$n] . '<br />'; echo $meaning[$m] . '<br /><br />'; break; } } } } ?> And here is the HTML code. <form method="post" action="index.php"> <ul> <li><label for="name">Name: </label><input type="text" name="name[]" id="name" /></li> <li><label for="meaning">Meaning: </label><input type="text" name="meaning[]" id="meaning" /></li> <li><input type="submit" name="submit" value="Save" /></li> </ul> </form> If needed I will place the JQuery code.

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  • Not sure what happens to my apps objects when using NSURLSession in background - what state is my app in?

    - by Avner Barr
    More of a general question - I don't understand the workings of NSURLSession when using it in "background session mode". I will supply some simple contrived example code. I have a database which holds objects - such that portions of this data can be uploaded to a remote server. It is important to know which data/objects were uploaded in order to accurately display information to the user. It is also important to be able to upload to the server in a background task because the app can be killed at any point. for instance a simple profile picture object: @interface ProfilePicture : NSObject @property int userId; @property UIImage *profilePicture; @property BOOL successfullyUploaded; // we want to know if the image was uploaded to out server - this could also be a property that is queryable but lets assume this is attached to this object @end Now Lets say I want to upload the profile picture to a remote server - I could do something like: @implementation ProfilePictureUploader -(void)uploadProfilePicture:(ProfilePicture *)profilePicture completion:(void(^)(BOOL successInUploading))completion { NSUrlSession *uploadImageSession = ..... // code to setup uploading the image - and calling the completion handler; [uploadImageSession resume]; } @end Now somewhere else in my code I want to upload the profile picture - and if it was successful update the UI and the database that this action happened: ProfilePicture *aNewProfilePicture = ...; aNewProfilePicture.profilePicture = aImage; aNewProfilePicture.userId = 123; aNewProfilePicture.successfullyUploaded = NO; // write the change to disk [MyDatabase write:aNewProfilePicture]; // upload the image to the server ProfilePictureUploader *uploader = [ProfilePictureUploader ....]; [uploader uploadProfilePicture:aNewProfilePicture completion:^(BOOL successInUploading) { if (successInUploading) { // persist the change to my db. aNewProfilePicture.successfullyUploaded = YES; [Mydase update:aNewProfilePicture]; // persist the change } }]; Now obviously if my app is running then this "ProfilePicture" object is successfully uploaded and all is well - the database object has its own internal workings with data structures/caches and what not. All callbacks that may exist are maintained and the app state is straightforward. But I'm not clear what happens if the app "dies" at some point during the upload. It seems that any callbacks/notifications are dead. According to the API documentation- the uploading is handled by a separate process. Therefor the upload will continue and my app will be awakened at some point in the future to handle completion. But the object "aNewProfilePicture" is non existant at that point and all callbacks/objects are gone. I don't understand what context exists at this point. How am I supposed to ensure consistency in my DB and UI (For instance update the "successfullyUploaded" property for that user)? Do I need to re-work everything touching the DB or UI to correspond with the new API and work in a context free environment?

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  • Undefined index: email in C:\wamp\www\emailvalidate.php on line 4

    - by klari
    I am new to Ajax. In my Ajax I get the following error message : Notice: Undefined index: address in C:\wamp\www\test\sample.php on line 11 I googled but I didn't get a solution for my specified issue. Here is what I did. HTML Form with Ajax (test1.php) <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <script> function loadXMLDoc() { var xmlhttp; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("mydiv").innerHTML=xmlhttp.responseText; } } xmlhttp.open("POST","test2.php",true); xmlhttp.send(); } </script> </head> <body> <form id="form1" name="form1" method="post" action="sample.php"> <p> <label for="mail"></label> <input type="text" name="mail" id="mail" onblur="loadXMLDoc()" /> <input type="submit" name="submit" id="submit" value="Submit" /> </p> <p><div id = 'mydiv'></div></p> </form> </body> </html> test2.php <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <?php echo "Your Address is ".$_POST['address']; ?> </body> </html> I am sure it is very simple issue but I don't know how to solve it. Any help ?

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  • how to invoke an activity of a library project from an android apps

    - by Austin
    I have an open source android code that I need to use in my android apps. It has all the source code as well as resource files, manifest files and class path. It can be compiled as a separate android apps. I have constraints for using the open source. 1. I can't change a single line of code. 2. I can't use it as a separate apps. These constraints are non negotiable. What I have done is I have compiled the open source as class library(in Eclipse: Project Properties-Android- Tick check box Is Library). This has resulted in generation of .class files(in bin) for the java files and resource files. This open source has an android activity that i want to open from my application. So I have linked the directory of these sets of class files in the source section of my java build path( in .classpath). I have declared the activity in my manifest file with proper action intent filters. Now when I am trying to call activity from my code, its not working. Cleaning and rebuilding doesn't help. However, if I build the open source project and my apps in the same workspace of eclipse and link the open source in my apps in exact same manner it works fine. I am not able to identify the difference. All settings seems to be same(all files are identical in both the cases). But only in the second case it works. I have tried it as jar file also. I have build the open source as project library and exported it into a jar file(excluding manifest file). But in that case I am getting the following error UNEXPECTED TOP-LEVEL EXCEPTION: java.lang.IllegalArgumentException: already added: .... Conversion to Dalvik format failed with error 1 This I guess is coming because the android library(2.2) has been included twice in my apps( one for building my apps & another for building the open source). I dont know how to avoid this. Cleaning the project doesn't help. What i require is to use the open source and invoking it's activities in my apps without violating the constraints. If i can use the open source as bunch of .class files then great, or else any other way will do fine. Please look into it and let me know. Thanks

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  • why resubmit after refresh php page

    - by user2719452
    why resubmit after refresh php page? try it, go to: http://qass.im/message-envelope/ and upload any image now try click F5, after refresh page "resubmit" Why? I don't want resubmit after refresh page What is the solution? See this is my form code: <form id="uploadedfile" name="uploadedfile" enctype="multipart/form-data" action="upload.php" method="POST"> <input name="uploadedfile" type="file" /> <input type="submit" value="upload" /> </form> See this is php code upload.php file: <?php $allowedExts = array("gif", "jpeg", "jpg", "png", "zip", "pdf", "docx", "rar", "txt", "doc"); $temp = explode(".", $_FILES["uploadedfile"]["name"]); $extension = end($temp); $newname = $extension.'_'.substr(str_shuffle(str_repeat("0123456789abcdefghijklmnopqrstuvwxyz", 7)), 4, 7); $imglink = 'attachment/attachment_file_'; $uploaded = $imglink .$newname.'.'.$extension; if ((($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpg") || ($_FILES["uploadedfile"]["type"] == "image/pjpeg") || ($_FILES["uploadedfile"]["type"] == "image/x-png") || ($_FILES["uploadedfile"]["type"] == "image/gif") || ($_FILES["uploadedfile"]["type"] == "image/png") || ($_FILES["uploadedfile"]["type"] == "application/msword") || ($_FILES["uploadedfile"]["type"] == "text/plain") || ($_FILES["uploadedfile"]["type"] == "application/vnd.openxmlformats-officedocument.wordprocessingml.document") || ($_FILES["uploadedfile"]["type"] == "application/pdf") || ($_FILES["uploadedfile"]["type"] == "application/x-rar-compressed") || ($_FILES["uploadedfile"]["type"] == "application/x-zip-compressed") || ($_FILES["uploadedfile"]["type"] == "application/zip") || ($_FILES["uploadedfile"]["type"] == "multipart/x-zip") || ($_FILES["uploadedfile"]["type"] == "application/x-compressed") || ($_FILES["uploadedfile"]["type"] == "application/octet-stream")) && ($_FILES["uploadedfile"]["size"] < 5242880) // Max size is 5MB && in_array($extension, $allowedExts)) { move_uploaded_file($_FILES["uploadedfile"]["tmp_name"], $uploaded ); echo '<a target="_blank" href="'.$uploaded.'">click</a>'; // If has been uploaded file echo '<h3>'.$uploaded.'</h3>'; } if($_FILES["uploadedfile"]["error"] > 0){ echo '<h3>Please choose file to upload it!</h3>'; // If you don't choose file } elseif(!in_array($extension, $allowedExts)){ echo '<h3>This extension is not allowed!</h3>'; // If you choose file not allowed } elseif($_FILES["uploadedfile"]["size"] > 5242880){ echo "Big size!"; // If you choose big file } ?> if you have solution, please edit my php code and paste your solution code! Thanks.

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  • Creating a mySQL query using PHP form dropdowns - If user ignores dropdown, do not filter by that pa

    - by user303043
    Hello, I am creating a simple MySQL query that will be built from the user selecting options from 2 dropdowns. The issue I am having is that I would like each drop down to default that if they do not actually choose an option, do not filter by that dropdown parameter. So, if they come in, and simply hit submit without choosing from a dropdown they should see everything. If they come in and pick from only one of the dropdowns, the query will basically ignore filtering by the other dropdown. I tried making <OPTION VALUE='any'>Choose but my query didn't know what to do with the 'any' and just shows no results. Here is my code. Thank you very much for whatever help you can provide. FORM <form method="POST" action="<?php echo $_SERVER['REQUEST_URI']; ?>"> <select name="GameType"> <OPTION VALUE='any'>Choose Game Type <option value="Game1">Option 1</option> <option value="Game2">Option 2</option> <option value="Game3">Option 3</option> </select> <select name="Instructor"> <OPTION VALUE='any'>Choose Instructor <option VALUE="InstructorA">Instructor A</option> <option value="InstructorB">Instructor B</option> <option value="InstructorC">Instructor C</option> </select> <input type='submit' value='Search Videos'> </form> MYSQL <?PHP connection stuff $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "SELECT * FROM Videos WHERE GameType=\"{$_POST['GameType']}\" AND Instructor=\"{$_POST['Instructor']}\""; $result = mysql_query($SQL); while ($db_field = mysql_fetch_assoc($result)) { echo $db_field['ShortDescription'] . ", "; echo $db_field['LongDescription'] . ", "; echo $db_field['GameType'] . ", "; echo $db_field['NumberOfPlayers'] . ", "; echo $db_field['Instructor'] . ", "; echo $db_field['Stakes'] . ", "; echo $db_field['UserPermissionLevel'] . ", "; echo $db_field['DateCreated'] . "<BR>"; } mysql_close($db_handle); } else { print "Database NOT Found "; mysql_close($db_handle); } ?>

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  • Routing error when trying to use same view for update and create flows (Rails 3)

    - by Jamis Charles
    My overall use case: I have a Listing model that has many images. The Listing detail page lists all the fields that can be updated inline (through ajax). I want to be able to use the same view for both update listing and create new listing. My listing controller looks as follows: def detail @listing = Listing.find(params[:id]) @image = Image.new #should this link somewhere else? respond_to do |format| format.html # show.html.erb format.xml { render :xml => @listing } end end def create # create a new listing and save it immediately. Assign it to guest, with a status of "draft" @listing = Listing.new(:price_id => 1) # Default price id # save it to db # TODO add validation that it has to have a price ID, on record creation. So the view doesn't break. @listing.save @image = Image.new # redirect_to "/listings/detail/@listing.id" #this didn't work respond_to do |format| format.html # show.html.erb format.xml { render :xml => @listing } end end The PROBLEM I'm using a partial that shows the same form for the create view and the detail view. This works perfectly except for one thing: When I pull up http://0.0.0.0:3000/listings/detail/7, it works perfectly. When I pull up http://0.0.0.0:3000/listings/new, I get the following error: Showing /Applications/MAMP/htdocs/rails_testing/feedbackd/app/views/listings/_edit_form.html.erb where line #100 raised: No route matches {:action="show", :controller="images"} Extracted source (around line #100): 97: <!-- Form for new images --> 98: <div class="span-20 append-bottom"> 99: <!-- <%# form_for :image, @image, :url => image_path, :html => { :multipart => true } do |f| %> --> 100: <%= form_for @image, :url => image_path, :html => { :multipart => true } do |f| %> 101: <%= f.text_field :description %><br /> 102: <%= f.file_field :photo %> 103: <%= submit_tag "Upload" %> What I think the issue is: When I upload a new image (I'm using Paperclip), it requires the listing_id to create the image record. Since the listing_id isn't passed in with listings/new it can't find the listing_id. How can I pass in the id? Via a redirect? What's the best way to solve this? Thank you.

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  • I am having trouble using jquery to submit a form. It was working before

    - by noah
    When a user clicks a link it uses jquery ajax to submit a form to go to paypal. Not working for some reason. Really appreciate any help... LINK TO CLICK I put this in an href for onClick: javascript:go_paypal(); CODE TO EXECUTE ON CLICK function go_paypal() { data = 'req_paypal=1'; $.blockUI({ message: '<h1> Going to Paypal...</h1>',css:{background:'#000'} }); $.ajax({ type: "POST", url: "index.php", data: data, success: function(data) { $("#paypal_form").html(data); $("#payPalForm").submit(); } , error: function() {$.unblockUI(); alert('Unable to communicate to server.'); } }); return false; } CODE TO GO ON SUBMIT if(isset($_POST['req_paypal']) && $_POST['req_paypal'] == 1 ) { $sql = 'INSERT INTO `transactions` (id,type,ip,time,ammount,status) VALUES (NULL,1,\''.$_SERVER['REMOTE_ADDR'].'\',\''.time().'\',\''.$global['paypal_prod_amount'].'\',0) '; echo $sql; mysql_query($sql); $id = mysql_insert_id(); $html = ' <form action="https://www.sandbox.paypal.com/cgi-bin/webscr" method="post" id="payPalForm"> <input type="hidden" name="item_number" value="One Year of Imgur Pro"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="no_note" value="1"> <input type="hidden" name="business" value="'.$global['paypal_email'].'"> <input type="hidden" name="custom" value="'.base64_encode($id).'"> <input type="hidden" name="currency_code" value="USD"> <input type="hidden" name="return" value="'.$global['paypal_return'].'"> <input name="item_name" type="hidden" id="item_name" value="One Year of Imgur Pro" > <input name="amount" type="hidden" id="amount" value="'.$global['paypal_prod_amount'].'" > </form> '; echo $html;exit; }

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  • Message passing chrome extension

    - by Mayur Kataria
    I wants to create an extension where content script will send message to background page and then on browser action means clicking on extension icon will access that background page and get some data.I am using chrome Version 23.0.1271.64 m on windows8. I am getting following error. Port error: Could not establish connection. Receiving end does not exist. I tried to solve the same. but people are using sendRequest which is not supported by chrome20+. i also found solution mentioned for chrome 20+. But not working. Please help. Below is the file contents. manifest.json { "name": "Test Extension", "version": "1.0", "manifest_version": 2, "description": "A test extension.", "background": "background.html", "content_scripts": [ { "matches": ["<all_urls>"], "js": ["jquery.js","content.js"] } ], "permissions": ["tabs", "http://*/", "https://*/"], "browser_action": { "default_icon": "icon.png", "default_popup": "popup.html" } } background.html <html> <head> <script src="background.js"></script> </head> <body> <h1>Wy</h1> </body> </html> background.js chrome.extension.onMessage.addListener(function(request, sender, sendResponse) { // Chrome 20+ alert(request); console.log('received in listener'); sendResponse({farewell: "goodbye"}); }); content.js $(function(){ console.log('start-sending message'); chrome.extension.sendMessage({greeting: "hello"},function(response){alert(response);}); console.log('end-sending message'); }); popup.html <!doctype html> <html> <head> <title>Getting Started Extension's Popup</title> </style> <!-- JavaScript and HTML must be in separate files for security. --> <script src="jquery.js"></script> <script src="popup.js"></script> </head> <body> </body> </html> popup.js $(function(){ var str_html = "<tr><td width='60%'>S</td><td width='40%'>15</td></tr><tr><td width='60%'>M</td><td width='40%'>25</td></tr>"; $('#sizes_container').html(str_html); var bkg = chrome.extension.getBackgroundPage(); console.log(bkg); });

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  • Is there a way for a user to disable an AlertDialog completely?

    - by NewGuyChris
    In the app I'm making, I have an "if" statement where if two strings are saved to a certain string, an AlertDialog pops up. These strings will stay the same for some users, thus having this AlertDialog constantly pop up whenever they launch the activity where the ALertDialog is set to appear. Code (I have no setNegativeButton as of yet): private void SetWarning() { AlertDialog.Builder alert = new AlertDialog.Builder(this); alert.setTitle("Warning!"); alert.setMessage(R.string.Warning); alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int whichButton) { //No action needed; just close the AlertDialog. } }); alert.show(); } Here is a segment of my code that makes this AlertDialog appear: SharedPreferences sharedPreferences = getSharedPreferences("MY_PREF", MODE_PRIVATE); String s = sharedPreferences2.getString("MEM1", ""); String s2 = sharedPreferences2.getString("MEM2", ""); if(s.equals("String1") && s2.equals("String2")) SetWarning(); Is there a way to make an "alert.setNegativeButton" method where if the user clicks it, the AlertDialog will NEVER appear again? I'm thinking of maybe somehow implementing another SavedPreferences somehow so it saves the users selection and will then prevent the AlertDialog from ever appearing again. So far, to no luck. I've searched to find nothing, other than people asking how to disable buttons in an AlertDialog. Thank you! New updated code: alert.setNegativeButton("Cancel", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int whichButton) { //set sharedpreferences boolean called DONTSHOWAGAIN to true; SharedPreferences sharedPreferences2 = getSharedPreferences("MY_PREF", MODE_PRIVATE); Boolean dontShowAgain = sharedPreferences2.getBoolean("dontShowAgain ", false); SharedPreferences.Editor ed = sharedPreferences2.edit(); ed.putBoolean("dontShowAgain", true); ed.commit(); } }); alert.show(); } private void StringWarning() { SharedPreferences sharedPreferences2 = getSharedPreferences("MY_PREF", MODE_PRIVATE); String s = sharedPreferences2.getString("MEM1", ""); String s2 = sharedPreferences2.getString("MEM2", ""); if(s.equals("String1") && s2.equals("String2")){ if(!dontShowAgain){ SetWarningExamConflict(); } }

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  • EJB / JSF java.lang.ClassNotFoundException: com.ericsantanna.jobFC.dao.DAOFactoryRemote from [Module "com.sun.jsf-impl:main" from local module loader

    - by Eric Sant'Anna
    I'm in my first time using EJB and JSF, and I can't resolve this: 20:23:12,457 Grave [javax.enterprise.resource.webcontainer.jsf.application] (http-localhost-127.0.0.1-8081-2) com.ericsantanna.jobFC.dao.DAOFactoryRemote from [Module "com.sun.jsf-impl:main" from local module loader @439db2b2 (roots: C:\jboss-as-7.1.1.Final\modules)]: java.lang.ClassNotFoundException: com.ericsantanna.jobFC.dao.DAOFactoryRemote from [Module "com.sun.jsf-impl:main" from local module loader @439db2b2 (roots: C:\jboss-as-7.1.1.Final\modules)] I'm getting this when I do an action like a selectOneMenu or a commandButton click. DAOFactory.class @Singleton @Remote(DAOFactoryRemote.class) public class DAOFactory implements DAOFactoryRemote { private static final long serialVersionUID = 6030538139815885895L; @PersistenceContext private EntityManager entityManager; @EJB private JobDAORemote jobDAORemote; /** * Default constructor. */ public DAOFactory() { // TODO Auto-generated constructor stub } @Override public JobDAORemote getJobDAO() { JobDAO jobDAO = (JobDAO) jobDAORemote; jobDAO.setEntityManager(entityManager); return jobDAO; } JobDAO.class @Stateless @Remote(JobDAORemote.class) public class JobDAO implements JobDAORemote { private static final long serialVersionUID = -5483992924812255349L; private EntityManager entityManager; /** * Default constructor. */ public JobDAO() { // TODO Auto-generated constructor stub } @Override public void insert(Job t) { entityManager.persist(t); } @Override public Job findById(Class<Job> classe, Long id) { return entityManager.getReference(classe, id); } @Override public Job findByName(Class<Job> clazz, String name) { return entityManager .createQuery("SELECT job FROM " + clazz.getName() + " job WHERE job.nome = :nome" , Job.class) .setParameter("name", name) .getSingleResult(); } ... TriggerFormBean.class @ManagedBean @ViewScoped @Stateless public class TriggerFormBean implements Serializable { private static final long serialVersionUID = -3293560384606586480L; @EJB private DAOFactoryRemote daoFactory; @EJB private TriggerManagerRemote triggerManagerRemote; ... triggerForm.xhtml (a portion with problem) </p:layoutUnit> <p:layoutUnit id="eastConditionPanel" position="center" size="50%"> <p:panel header="Conditions to Release" style="width:97%;height:97%;"> <h:panelGrid columns="2" cellpadding="3"> <h:outputLabel value="Condition Name:" for="conditionName" /> <p:inputText id="conditionName" value="#{triggerFormBean.newCondition.name}" /> </h:panelGrid> <p:commandButton value="Add Condition" update="conditionsToReleaseList" id="addConditionToRelease" actionListener="#{triggerFormBean.addNewCondition}" /> <p:orderList id="conditionsToReleaseList" value="#{triggerFormBean.trigger.conditionsToRelease}" var="condition" controlsLocation="none" itemLabel="#{condition.name}" itemValue="#{condition}" iconOnly="true" style="width:97%;heigth:97%;"/> </p:panel> </p:layoutUnit> In TriggerFormBean.class if comments daoFactory we get the same exception with triggerManagerRemote, both annotated with @EJB. I'm don't understand the relationship between my DAOFactory and the "Module com.sun.jsf-impl:main"... Thanks.

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  • Linking Post Title to Specific Page ID

    - by ThatMacLad
    I've created a form to update my websites homepage with content but I wanted to know how I could set it up so that a posts title links to a specific post ID. I'd also like to add a Read More link that directs anybody reading the blog to the correct post. Here is my PHP code: <html> <head> <title>Blog Name</title> </head> <body> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $password = $row['password']; $id = $row['id']; if ($password == 1) { echo "<p><strong>" . $title . "</strong></p>"; printf("<p>This is a password protected entry. If you have a password, log in below.</p>"); printf("<form method=\"post\" action=\"post.php?id=%s\"><p><strong><label for=\"username\">Username:</label></strong><br /><input type=\"text\" name=\"username\" id=\"username\" /></p><p><strong><label for=\"pass\">Password:</label></strong><br /><input type=\"password\" name=\"pass\" id=\"pass\" /></p><p><input type=\"submit\" name=\"submit\" id=\"submit\" value=\"submit\" /></p></form>",$id); print "<hr />"; } else { ?> <p><strong><?php echo $title; ?></strong><br /><br /> <?php echo $entry; ?><br /><br /> Posted on <?php echo $date; ?> <hr /></p> <?php } } ?> </body> </html> Thanks for any help. I really appreciate any input!

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  • Get values from HTML in a multidimensional array and calculate values using PHP

    - by Frank Nwoko
    I have searched but could not get solution on this issue. I am working on an application which will generate unknown number of items and have users select the quantity from a drop down against each item. Eg. Item(s) | price | Select qty Rice 23 3 Beans 22 4 Eggs 52 5 ... ... ... unknown Please, how can I capture the above in an array and also calculate the total value for all selected items and corresponding fees? I have the following HTML code: <form id='form1' name='form1' method='post' action='item_calc.php'> <?php ..... while($t_row = mysql_fetch_assoc($get_items)) { echo "<p><label>$t_row['$item_name'] <input type='text' READONLY name='item_price[]' value='$t_row['$item_price']' /></label> <input type='text' READONLY name='item_fees[]' value='$t_row['$item_fee']' /> <select name="item_qty"> <option value="1"> <option value="2"> <option value="3"> <option value="4"> <option value="5"> </select> </p><p>"; } echo "<label><input type='submit' name='submit' value='Submit' /></label></p> </form>"; Please, how can I get item_price[] + item_fees[] * item_qty for all selected items? This is what I have tried: for ($i = 0; $i < count($_POST['item_price']); $i++) { // Do something here with $_POST['checkbx'][$i] foreach ($_POST['item_fees'] as $tkey => $tvalue) { //echo "Key: $tkey; Value: $tvalue<br>"; } foreach ($_POST['item_price'] as $pkey => $pvalue) { //echo "Key: $pkey; Value: $pvalue<br>"; } $total = $tvalue + $pvalue; } echo $total;

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  • Parse error in PHP login form

    - by user225269
    I'm trying to have a login form in php. But my current code doesnt work. Here is the form: <form name="form1" method="post" action="loginverify.php"> <td><font size="3">Username:</td> <td></td> <td><input type="text" name="uname" value="" maxlength="15"/><br/></td> <td><font size="3">Password:</td> <td></td> <td><input type="text" name="pword" value="" maxlength="15"/><br/></td> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </form> And the verify.php <?php session_start(); ?> <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="login"; $tbl="users"; $connection=mysql_connect($host, $username, $password) or die("cannot connect"); mysql_select_db($db_name, $connection) or die("cannot select db"); $user=$_POST['uname'] $pass=$_POST['pword'] $sql="SELECT Username, Password from users where Username='$user' and Password='$pass'"; $result=mysql_query[$sql]; $count=mysql_num_rows($result); if($count==1){ $SESSION['Username']=$user; echo"<a href='searchmain.php'> CONTINUE</a>"; } else{ echo"wrong username or password"; echo"<a href='loginform.php'>Back</a>"; } ?> Is there something wrong with my code. I get this parse error at line 15, which is this: $pass=$_POST['pword'] But when I try to remove it.It goes to line 16 or line 17 again. What do I do

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  • jquery ajax form success callback not being called

    - by Michael Merchant
    I'm trying to upload a file using "AJAX", process data in the file and then return some of that data to the UI so I can dynamically update the screen. I'm using the JQuery Ajax Form Plugin, jquery.form.js found at http://jquery.malsup.com/form/ for the javascript and using Django on the back end. The form is being submitted and the processing on the back end is going through without a problem, but when a response is received from the server, my Firefox browser prompts me to download/open a file of type "application/json". The file has the json content that I've been trying to send to the browser. I don't believe this is an issue with how I'm sending the json as I have a modularized json_wrapper() function that I'm using in multiple places in this same application. Here is what my form looks after Django templates are applied: <form method="POST" enctype="multipart/form-data" action="/test_suites/active/upload_results/805/"> <p> <label for="id_resultfile">Upload File:</label> <input type="file" id="id_resultfile" name="resultfile"> </p> </form> You won't see any submit buttons because I'm calling submit with a button else where and am using ajaxSubmit() from the jquery.form.js plugin. Here is the controlling javascript code: function upload_results($dialog_box){ $form = $dialog_box.find("form"); var options = { type: "POST", success: function(data){ alert("Hello!!"); }, dataType: "json", error: function(){ console.log("errors"); }, beforeSubmit: function(formData, jqForm, options){ console.log(formData, jqForm, options); }, } $form.submit(function(){ $(this).ajaxSubmit(options); return false; }); $form.ajaxSubmit(options); } As you can see, I've gotten desperate to see the success callback function work and simply have an alert message created on success. However, we never reach that call. Also, the error function is not called and the beforeSubmit function is executed. The file that I get back has the following contents: {"count": 18, "failed": 0, "completed": 18, "success": true, "trasaction_id": "SQEID0.231"} I use 'success' here to denote whether or not the server was able to run the post command adequately. If it failed the result would look something like: {"success": false, "message":"<error_message>"} Your time and help is greatly appreciated. I've spent a few days on this now and would love to move on.

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  • When does logic belong in the Business Object/Entity, and when does it belong in a Service?

    - by Casey
    In trying to understand Domain Driven Design I keep returning to a question that I can't seem to definitively answer. How do you determine what logic belongs to a Domain entity, and what logic belongs to a Domain Service? Example: We have an Order class for an online store. This class is an entity and an aggregate root (it contains OrderItems). Public Class Order:IOrder { Private List<IOrderItem> OrderItems Public Order(List<IOrderItem>) { OrderItems = List<IOrderItem> } Public Decimal CalculateTotalItemWeight() //This logic seems to belong in the entity. { Decimal TotalWeight = 0 foreach(IOrderItem OrderItem in OrderItems) { TotalWeight += OrderItem.Weight } return TotalWeight } } I think most people would agree that CalculateTotalItemWeight belongs on the entity. However, at some point we have to ship this order to the customer. To accomplish this we need to do two things: 1) Determine the postage rate necessary to ship this order. 2) Print a shipping label after determining the postage rate. Both of these actions will require dependencies that are outside the Order entity, such as an external webservice to retrieve postage rates. How should we accomplish these two things? I see a few options: 1) Code the logic directly in the domain entity, like CalculateTotalItemWeight. We then call: Order.GetPostageRate Order.PrintLabel 2) Put the logic in a service that accepts IOrder. We then call: PostageService.GetPostageRate(Order) PrintService.PrintLabel(Order) 3) Create a class for each action that operates on an Order, and pass an instance of that class to the Order through Constructor Injection (this is a variation of option 1 but allows reuse of the RateRetriever and LabelPrinter classes): Public Class Order:IOrder { Private List<IOrderItem> OrderItems Private RateRetriever _Retriever Private LabelPrinter _Printer Public Order(List<IOrderItem>, RateRetriever Retriever, LabelPrinter Printer) { OrderItems = List<IOrderItem> _Retriever = Retriever _Printer = Printer } Public Decimal GetPostageRate { _Retriever.GetPostageRate(this) } Public void PrintLabel { _Printer.PrintLabel(this) } } Which one of these methods do you choose for this logic, if any? What is the reasoning behind your choice? Most importantly, is there a set of guidelines that led you to your choice?

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  • remote_form_for in index.html.erb file not working w/ AJAX...Ruby on Rails...

    - by bgadoci
    Just curious if I am overlooking something simple here. I have deployed the remote_form_for in the show.html.erb code before to render comments on a post (project in this case) without a problem. I have moved this code to the index view and seems to degrade to the normal form_for action (page refresh). I am not getting any javascript errors so not sure what is wrong here. Here is my code: index.html.erb <% remote_form_for [project, Comment.new] do |f| %> <p> <%= f.label :body, "New Comment" %><br/> <%= f.text_area (:body, :class => "textarea") %> </p> <p> <%= f.label :name, "Name" %> (Required)<br/> <%= f.text_field (:name, :class => "textfield") %> </p> <p> <%= f.label :email, "Email" %> (Required but will not be displayed)<br/> <%= f.text_field (:email, :class => "textfield") %> </p> <p><%= f.submit "Add Comment" %></p> <% end %> CommentsController#create def create @project = Project.find(params[:project_id]) @comment = @project.comments.create!(params[:comment]) respond_to do |format| format.html { redirect_to projects_path } format.js end end /views/comments/create.js.rjs page.insert_html :bottom, :commentwrapper, :partial => @comment page[@comment].visual_effect :highlight page[:new_comment].reset page.replace_html :notice, flash[:notice] flash.discard /views/comments/_comment.html.erb <% div_for comment do %> <div id="commentwrapper"> <% if admin? %> <%=link_to_remote "X", :url => [@project, comment], :method => :delete %> <% end %> <%= h(comment.body) %><br/><br/> Posted <%= time_ago_in_words(comment.created_at) %> ago by <%= h(comment.name) %> <% if admin? %> | <%= h(comment.email) %> <% end %></div> <% end %>

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  • form inside tabview doesn't work

    - by user3536737
    i am working with jsf and primefaces , and here is what 've tried well i want to creat a tabview that get data from an arraylist in my bean i get for exemple 4 tabs , and inside each one i've created a hidden panel where i have a form with 2 input text to update informations , do i display the panel when i click on the second button Update , after that my panel is not hidden anymore , and i set the new values and click on the second button to update the informations , the problem is that the updating and the execution is working only for the first tab , it means when i try to update the new informations it works for the first one and for the other tabs it doesn't here is the code <p:tab title="#{rr.nom_ressource}"> <h:panelGrid> <h:graphicImage value="Ressources/images/emp.jpg" style="vertical-align:middle" /> <span style="font-size:15px; width:170px; display:inline-block;"> Nom : #{rr.nom_ressource} Type: #{rr.type_ressource} Specification: #{rr.experience} </span> <h:commandButton image="Ressources/images/delete.jpg" actionListener="#{SelectBean.act}" update=":form" style="vertical-align:middle" > Update </h:commandButton> <h:commandButton update=":outPanel" actionListener="#{SelectBean.mod1()}" image="Ressources/images/update.png" style="vertical-align:middle" > Modifier </h:commandButton> <h:form id="form111"> <p:growl id="growl" showDetail="true" sticky="true" /> <p:panel rendered ="#{SelectBean.bol}" closable="true" toggleable="true" id="outPanel" styleClass="outPanel" widgetVar="outpanel"> <h:outputLabel value="Nom " /> <h:inputText value="#{SelectBean.nom}" /> <br/> <h:outputLabel value="Experience " /> <h:inputText value="#{SelectBean.exp}" /> <br/> <h:commandButton value="Update" action="#{SelectBean.done}"/> </p:panel> </h:form> </h:panelGrid> </p:tab> for my managedbean the code is correct i think the problem is here

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  • How do i know in the detail view what cell in tableview was selected?

    - by Daniel Rotaru
    how can i know what tableview cell was selected?(being in the detail view) The problem is that. I have an table view controller. Here are parsed from the internet entries to the table. So it's a dynamic tabe view that loads from internet. I will not know how many entries will be in the table so i will not know what details view to call when i click a row. So i have maked one view. This view contains an calendar. On this calendar(wich is the detail iew) i will parse data from internet depending on the selected row. For exemple: i have table: entry 1, entry 2,entry 3,entry 4 When i click entry 2 i need to call a php with the argument entry 2. The php will know what entry on the table i have selected and will generate me the correct xml that i will parse. Here is my tableview didSelectRow function: - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { // Navigation logic -- create and push a new view controller if(bdvController == nil) bdvController = [[BookDetailViewController alloc] initWithNibName:@"BookDetailView" bundle:[NSBundle mainBundle]]; Villa *aVilla = [appDelegate.villas objectAtIndex:indexPath.row]; [self.navigationController pushViewController:bdvController animated:YES] And here is my self view function on detailviewcontroller: -(void)loadView { [super loadView]; self.title=@"Month" UIBarButtonItem *addButtonItem = [[UIBarButtonItem alloc] initWithTitle:@"ListView" style:UIBarButtonItemStyleDone target:self action:@selector(add:)]; self.navigationItem.rightBarButtonItem = addButtonItem; calendarView = [[[KLCalendarView alloc] initWithFrame:CGRectMake(0.0f, 0.0f, 320.0f, 373.0f) delegate:self] autorelease]; appDelegate1 = (XMLAppDelegate *)[[UIApplication sharedApplication] delegate]; myTableView=[[UITableView alloc]initWithFrame:CGRectMake(0, 260, 320, 160)style:UITableViewStylePlain]; myTableView.dataSource=self; myTableView.delegate=self; UIView *myHeaderView=[[UIView alloc]initWithFrame:CGRectMake(0, 0, myTableView.frame.size.width,2)]; myHeaderView.backgroundColor=[UIColor grayColor]; [myTableView setTableHeaderView:myHeaderView]; [self.view addSubview:myTableView]; [self.view addSubview:calendarView]; [self.view bringSubviewToFront:myTableView]; } I think that here in self load i need to make the if procedure.. If indexPath.row=x parse fisier.php?variabila=title_of_rowx but the question is how i know the indexPath variable?

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