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  • Why is this simple file upload not working? JSF

    - by Nitesh Panchal
    Hello, Why is this code not working? I always get size() = 0, whenever i upload file. xhtml file :- <?xml version='1.0' encoding='UTF-8' ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html"> <h:head> <title>Abc</title> </h:head> <h:body> <center> <form method="post" enctype="multipart/form-data" id="form" action="/upload/uploadFile"> <input type="file"/> <br/> <input type="Submit" value="upload"/> </form> </center> </h:body> </html> This is my servlet :- package servlets; import java.io.IOException; import java.util.List; import java.util.logging.Level; import java.util.logging.Logger; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.apache.commons.fileupload.FileItem; import org.apache.commons.fileupload.FileUploadException; import org.apache.commons.fileupload.disk.DiskFileItemFactory; import org.apache.commons.fileupload.servlet.ServletFileUpload; @WebServlet(name="uploadFile", urlPatterns={"/uploadFile"}) public class uploadFile extends HttpServlet { protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException, FileUploadException { System.out.println("executed!"); List<FileItem> items = new ServletFileUpload(new DiskFileItemFactory()).parseRequest(request); System.out.println(items.size()); for (FileItem item : items) { if (!item.isFormField()) { System.out.println("Name: " + item.getName()); System.out.println("Size: " + item.getSize()); System.out.println("Type: " + item.getContentType()); } } } @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { processRequest(request, response); } catch (FileUploadException ex) { ex.printStackTrace(); } } @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { processRequest(request, response); } catch (FileUploadException ex) { ex.printStackTrace(); } } @Override public String getServletInfo() { return "Short description"; } }

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  • How do I make the directories in a zip file relative to the target directory instead of my working directory

    - by Nathan
    I'm calling the zip command from a script where I cannot change directory. I need to make a zip file of the stuff in data/kit123/ from the directory which data resides in, but I want the contents of the zip to only be the contents of kit123, with paths relative to kit123. This is the directory structure myworkingdir data kit123 kitpart1 file.xcf anotherfile.xcf kitpart2 ... kit124 ... My script runs in myworkingdir and cannot change directories. If I call zip -r kit123.zip data/kit123 then the structure in the zip file will be data kit123 kitpart1 file.xcf anotherfile.xcf kitpart2 but I want it to be kit123 kitpart1 file.xcf anotherfile.xcf kitpart2 Is there a zip option I can use to accomplish this? It seems odd that it should depend on my working directory I know it's not -j. that one destroys the structure within kit123

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  • Binary file reading problem

    - by ScReYm0
    Ok i have problem with my code for reading binary file... First i will show you my writing code: void book_saving(char *file_name, struct BOOK *current) { FILE *out; BOOK buf; out = fopen(file_name, "wb"); if(out != NULL) { printf_s("Writting to file..."); do { if(current != NULL) { strcpy(buf.catalog_number, current->catalog_number); strcpy(buf.author, current->author); buf.price = current->price; strcpy(buf.publisher, current->publisher); strcpy(buf.title, current->title); buf.price = current->year_published; fwrite(&buf, sizeof(BOOK), 1, out); } current = current->next; }while(current != NULL); printf_s("Done!\n"); fclose(out); } } and here is my "version" for reading it back: int book_open(struct BOOK *current, char *file_name) { FILE *in; BOOK buf; BOOK *vnext; int count; int i; in = fopen("west", "rb"); printf_s("Reading database from %s...", file_name); if(!in) { printf_s("\nERROR!"); return 1; } i = fread(&buf,sizeof(BOOK), 1, in); while(!feof(in)) { if(current != NULL) { current = malloc(sizeof(BOOK)); current->next = NULL; } strcpy(current->catalog_number, buf.catalog_number); strcpy(current->title, buf.title); strcpy(current->publisher, buf.publisher); current->price = buf.price; current->year_published = buf.year_published; fread(&buf, 1, sizeof(BOOK), in); while(current->next != NULL) current = current->next; fclose(in); } printf_s("Done!"); return 0; } I just need to save my linked list in binary file and to be able to read it back ... please help me. The program just don't read it or its crash every time different situation ...

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  • How to upload binary (audio) data from a Flash AS3 client to .NET server (WCF/REST/HTTP/?)?

    - by Bobby
    Simply stated: I'm trying to record audio in a browser, and get that data back up to the server. I originally tried to capture, encode and upload the audio using Silverlight, but because of the lack of suitable client-side encoding options, I'm now giving Flash a shot (Flash has baked-in support for encoding to Speex). I think I've figured out how to capture and encode the audio... But now what was easy in Silverlight, is the challenge in Flash. My server-side is .NET: MVC2- I'm open to receiving the audio in whatever manner is best- REST, WCF.. So that's my question: How could one upload binary data from Flash, to a .NET server-side endpoint. If the answer is WCF: then how would one setup the client-side proxies to communicate with the service? If the answer is REST or HTTP Post, then how would one construct this HTTP request and pass along the data? I've been reading up on AS3, but am new to Flash dev... Thanks for any help!

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  • How do I upload a file from a Java servlet to a location on a web server within Tomcat/webapps

    - by Ankur
    How do I upload a file from a Java servlet to a location on a web server within Tomcat/webapps. I am using Commons upload. I have a location such as myserver:8080/myapp/mylocation where I want to put the files that are uploaded. I tried using getServletContext().getRealPath("/"); to find where I am and then appended that with mylocation but I get a nullpointer exception. I know I sound vague, it's because I am confused about the big picture, what are the generals steps I need to perform to make this work. Any code or links to code would be much appreciated.

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  • Looking for a lean WYSIWYG inline editor for CMS projects that includes an image upload feature?

    - by Roeland
    Hey guys, I am looking to find a lean WYSIWYG inline editor. The main required feature is image uploading. A simple way to upload an image to the server and use it in the content being editted. I have come across a whole bunch of editors but nothing I liked so far. I am looking for something open source and free. So far I have checked out TinyMCE which is free.. untill you need image uploading capabilities. Ckeditor looks great.. uses jquery.. but requires you to have your own server side script to upload images. They barely give any documentation on how to do this. There were a few others, but the bottom line was that I cant find anything that is simple with out of the box image uploading capabilities. Thanks for any advice you may give!

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  • youtube - video upload failure - unable to convert file - encoding the video wrong?

    - by Anthony
    I am using .NET to create a video uploading application. Although it's communicating with YouTube and uploading the file, the processing of that file fails. YouTube gives me the error message, "Upload failed (unable to convert video file)." This supposedly means that "your video is in a format that our converters don't recognize..." I have made attempts with two different videos, both of which upload and process fine when I do it manually. So I suspect that my code is a.) not encoding the video properly and/or b.) not sending my API request properly. Below is how I am constructing my API PUT request and encoding the video: Any suggestions on what the error could be would be appreciated. Thanks P.S. I'm not using the client library because my application will use the resumable upload feature. Thus, I am manually constructing my API requests. Documentation: http://code.google.com/intl/ja/apis/youtube/2.0/developers_guide_protocol_resumable_uploads.html#Uploading_the_Video_File Code: // new PUT request for sending video WebRequest putRequest = WebRequest.Create(uploadURL); // set properties putRequest.Method = "PUT"; putRequest.ContentType = getMIME(file); //the MIME type of the uploaded video file //encode video byte[] videoInBytes = encodeVideo(file); public static byte[] encodeVideo(string video) { try { byte[] fileInBytes = File.ReadAllBytes(video); Console.WriteLine("\nSize of byte array containing " + video + ": " + fileInBytes.Length); return fileInBytes; } catch (Exception e) { Console.WriteLine("\nException: " + e.Message + "\nReturning an empty byte array"); byte [] empty = new byte[0]; return empty; } }//encodeVideo //encode custom headers in a byte array byte[] PUTbytes = encode(putRequest.Headers.ToString()); public static byte[] encode(string headers) { ASCIIEncoding encoding = new ASCIIEncoding(); byte[] bytes = encoding.GetBytes(headers); return bytes; }//encode //entire request contains headers + binary video data putRequest.ContentLength = PUTbytes.Length + videoInBytes.Length; //send request - correct? sendRequest(putRequest, PUTbytes); sendRequest(putRequest, videoInBytes); public static void sendRequest(WebRequest request, byte[] encoding) { Stream stream = request.GetRequestStream(); // The GetRequestStream method returns a stream to use to send data for the HttpWebRequest. try { stream.Write(encoding, 0, encoding.Length); } catch (Exception e) { Console.WriteLine("\nException writing stream: " + e.Message); } }//sendRequest

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  • How to change icons of specific file types on Ubuntu 11.10?

    - by Curious Apprentice
    I want to change file icons of some specific file types like- .html, .css etc. I have tried using "File Type Editor (assogiate)" which is not working. I have also tried using "Gnome Tweak Tool" using icon themes. But that also does not worked properly (Though I can change folder icons , dash menu icons but not file icons). Please suggest me a way so that I can change file icons properly. I have read some of the articles saying about some mime type changes. I could not get proper guide from any of those articles. If there is such a way then please write in detail. Many Many Thanks in Advance :)

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  • Server Error Message: No File Access

    - by iMayne
    Hello. Im having an issues but dont know where to solve it. My template works great in xampp but not on the host server. I get this message: Warning: file_get_contents() [function.file-get-contents]: URL file-access is disables in the server configuration in homepage/......./twitter.php. The error is on line 64. <?php /* For use in the "Parse Twitter Feeds" code below */ define("SECOND", 1); define("MINUTE", 60 * SECOND); define("HOUR", 60 * MINUTE); define("DAY", 24 * HOUR); define("MONTH", 30 * DAY); function relativeTime($time) { $delta = time() - $time; if ($delta < 2 * MINUTE) { return "1 min ago"; } if ($delta < 45 * MINUTE) { return floor($delta / MINUTE) . " min ago"; } if ($delta < 90 * MINUTE) { return "1 hour ago"; } if ($delta < 24 * HOUR) { return floor($delta / HOUR) . " hours ago"; } if ($delta < 48 * HOUR) { return "yesterday"; } if ($delta < 30 * DAY) { return floor($delta / DAY) . " days ago"; } if ($delta < 12 * MONTH) { $months = floor($delta / DAY / 30); return $months <= 1 ? "1 month ago" : $months . " months ago"; } else { $years = floor($delta / DAY / 365); return $years <= 1 ? "1 year ago" : $years . " years ago"; } } /* Parse Twitter Feeds */ function parse_cache_feed($usernames, $limit, $type) { $username_for_feed = str_replace(" ", "+OR+from%3A", $usernames); $feed = "http://twitter.com/statuses/user_timeline.atom?screen_name=" . $username_for_feed . "&count=" . $limit; $usernames_for_file = str_replace(" ", "-", $usernames); $cache_file = dirname(__FILE__).'/cache/' . $usernames_for_file . '-twitter-cache-' . $type; if (file_exists($cache_file)) { $last = filemtime($cache_file); } $now = time(); $interval = 600; // ten minutes // check the cache file if ( !$last || (( $now - $last ) > $interval) ) { // cache file doesn't exist, or is old, so refresh it $cache_rss = file_get_contents($feed); (this is line 64) Any help on how to give this access on my host server?

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  • Multithreaded FTP upload. Is it possible?

    - by Arty
    I need to upload multiple files from directory to the server via FTP and SFTP. I've solved this task for SFTP with python, paramiko and threading. But I have problem with doing it for FTP. I tried to use ftplib for python, but it seems that it doesn't support threading and I upload all files one by one, which is very slow. I'm wondering is it even possible to do multithreading uploads with FTP protocol without creating separate connections/authorizations (it takes too long)? Solution can be on Python or PHP. Maybe CURL? Would be grateful for any ideas.

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  • Is it possible to mod_rewrite BASED on the existence of a file/directory and uniqueID?

    - by JM4
    My site currently forces all non www. pages to use www. Ultimately, I am able to handle all unique subdomains and parse correctly but I am trying to achieve the following: (ideally with mod_rewrite): when a consumer visits www.site.com/john4, the server processes that request as: www.site.com?Agent=john4 Our requirements are: The URL should continue to show www.site.com/john4 even though it was redirected to www.site.com?index.php?Agent=john4 If a file (of any extension OR a directory) exists with the name, the entire process stops an it tries to pull that file instead: for example: www.site.com/file would pull up (www.site.com/file.php if file.php existed on the server. www.site.com/pages would go to www.site.com/pages/index.php if the pages directory exists). Thank you ahead of time. I am completely at a crapshot right now.

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  • Is there a way to recover a file that I have deleted but is still open somewhere?

    - by George Edison
    This question is related to How to recover deleted files? but it is slightly different in nature. Suppose I have a file named ~/something open in a text editor. Further suppose that I open a terminal and run the following command while the file is still open in the text editor: rm ~/something This will delete the file. Now suppose that I changed my mind and wanted to get the file back. The file is still open in the text editor, so it hasn't been removed from the disk or filesystem yet. Is there any way to recover it?

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  • Rails 3: How do I call a javascript function from a js.erb file

    - by user321775
    Now that I've upgraded to Rails 3, I'm trying to figure out the proper way to separate and reuse pieces of javascript. Here's the scenario I'm dealing with: I have a page with two areas: one with elements that should be draggable, the other with droppables. When the page loads I use jQuery to setup the draggables and droppables. Currently I have the script in the head portion of application.html.erb, which I'm sure is not the right solution but at least works. When I press a button on the page, an ajax call is made to my controller that replaces the draggables with a new set of elements that should also be draggable. I have a js.erb file that renders a partial in the correct location. After rendering I need to make the new elements draggable, so I'd like to reuse the code that currently lives in application.html.erb, but I haven't found the right way to do it. I can only make the new elements draggable by pasting the code directly into my js.erb file (yuck). What I'd like to have: - a javascript file that contains the functions prepdraggables() and prepdroppables() - a way to call either function from application.html.erb or from a js.erb file I've tried using :content_for to store and reuse the code, but can't seem to get it working correctly. What I currently have in the head section of application.html.erb <% content_for :drag_drop_prep do %> <script type="text/javascript" charset="utf-8"> $(document).ready(function () { // declare all DOM elements with class draggable to be draggable $( ".draggable" ).draggable( { revert : 'invalid' }); // declare all DOM elements with class legal to be droppable $(".legal").droppable({ hoverClass : 'legal_hover', drop : function(event, ui) { var c = new Object(); c['die'] = ui.draggable.attr("id"); c['cell'] = $(this).attr("id"); c['authenticity_token'] = encodeURIComponent(window._token); $.ajax({ type: "POST", url: "/placeDie", data: c, timeout: 5000 }); }}); }); </script> <% end %> undo.js.erb $("#board").html("<%= escape_javascript(render :partial => 'shared/board', :locals => { :playable => true, :restartable => !session[:challenge]}) %>") // This is where I want to prepare draggables. <%= javascript_include_tag "customdragdrop.js" %> // assuming this file had the draggables code from above in a prepdraggables() function prepdraggables();

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  • Efficient file buffering & scanning methods for large files in python

    - by eblume
    The description of the problem I am having is a bit complicated, and I will err on the side of providing more complete information. For the impatient, here is the briefest way I can summarize it: What is the fastest (least execution time) way to split a text file in to ALL (overlapping) substrings of size N (bound N, eg 36) while throwing out newline characters. I am writing a module which parses files in the FASTA ascii-based genome format. These files comprise what is known as the 'hg18' human reference genome, which you can download from the UCSC genome browser (go slugs!) if you like. As you will notice, the genome files are composed of chr[1..22].fa and chr[XY].fa, as well as a set of other small files which are not used in this module. Several modules already exist for parsing FASTA files, such as BioPython's SeqIO. (Sorry, I'd post a link, but I don't have the points to do so yet.) Unfortunately, every module I've been able to find doesn't do the specific operation I am trying to do. My module needs to split the genome data ('CAGTACGTCAGACTATACGGAGCTA' could be a line, for instance) in to every single overlapping N-length substring. Let me give an example using a very small file (the actual chromosome files are between 355 and 20 million characters long) and N=8 import cStringIO example_file = cStringIO.StringIO("""\ header CAGTcag TFgcACF """) for read in parse(example_file): ... print read ... CAGTCAGTF AGTCAGTFG GTCAGTFGC TCAGTFGCA CAGTFGCAC AGTFGCACF The function that I found had the absolute best performance from the methods I could think of is this: def parse(file): size = 8 # of course in my code this is a function argument file.readline() # skip past the header buffer = '' for line in file: buffer += line.rstrip().upper() while len(buffer) = size: yield buffer[:size] buffer = buffer[1:] This works, but unfortunately it still takes about 1.5 hours (see note below) to parse the human genome this way. Perhaps this is the very best I am going to see with this method (a complete code refactor might be in order, but I'd like to avoid it as this approach has some very specific advantages in other areas of the code), but I thought I would turn this over to the community. Thanks! Note, this time includes a lot of extra calculation, such as computing the opposing strand read and doing hashtable lookups on a hash of approximately 5G in size. Post-answer conclusion: It turns out that using fileobj.read() and then manipulating the resulting string (string.replace(), etc.) took relatively little time and memory compared to the remainder of the program, and so I used that approach. Thanks everyone!

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  • Will the app file be sync from dmgr side after we remove it from installedApps path in Websphere?

    - by wing2ofsky
    do you know whether the app file will be sync from dmgr side and regenerated after we remove it from installedApps path? i've got one issue recently from customer. That is, they uploaded one image file into WASNode installedApps app path manually. Afterwards, they removed that file manually again from installedApps app path. But after restarting the Application server process, that file has been regenerated under same installedApps path. So i suspect that file maybe has been resync from dmgr node, like app file under applications folder. However, first of all, i don't see that image file within application ear file from DMGR applications folder. Moreover, i made a test myself, if i deleted file from installedApps app path, that file never be regenerated any more even though the node sync completed. So does anybody know why? Thanks in advance

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  • Use matching value of a RegExp to name the output file.

    - by fx42
    I have this file "file.txt" which I want to split into many smaller ones. Each line of the file has an id field which looks like "id:1" for a line belonging to id 1. For each id in the file, I like to create a file named idid.txt and put all lines that belong to this id in that file. My brute force bash script solution reads as follows. count=1 while [ $count -lt 19945 ] do cat file.txt | grep "id:$count " >> ./sets/id$count.txt count='expr $count + 1' done Now this is very inefficient as I have do read through the file about 20.000 times. Is there a way to do the same operation with only one pass through the file? - What I'm probably asking for is a way to use the value that matches for a regular expression to name the associated output file.

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  • A question about making a C# class persistent during a file load

    - by Adam
    Apologies for the indescriptive title, however it's the best I could think of for the moment. Basically, I've written a singleton class that loads files into a database. These files are typically large, and take hours to process. What I am looking for is to make a method where I can have this class running, and be able to call methods from within it, even if it's calling class is shut down. The singleton class is simple. It starts a thread that loads the file into the database, while having methods to report on the current status. In a nutshell it's al little like this: public sealed class BulkFileLoader { static BulkFileLoader instance = null; int currentCount = 0; BulkFileLoader() public static BulkFileLoader Instance { // Instanciate the instance class if necessary, and return it } public void Go() { // kick of 'ProcessFile' thread } public void GetCurrentCount() { return currentCount; } private void ProcessFile() { while (more rows in the import file) { // insert the row into the database currentCount++; } } } The idea is that you can get an instance of BulkFileLoader to execute, which will process a file to load, while at any time you can get realtime updates on the number of rows its done so far using the GetCurrentCount() method. This works fine, except the calling class needs to stay open the whole time for the processing to continue. As soon as I stop the calling class, the BulkFileLoader instance is removed, and it stops processing the file. What I am after is a solution where it will continue to run independently, regardless of what happens to the calling class. I then tried another approach. I created a simple console application that kicks off the BulkFileLoader, and then wrapped it around as a process. This fixes one problem, since now when I kick off the process, the file will continue to load even if I close the class that called the process. However, now the problem I have is that cannot get updates on the current count, since if I try and get the instance of BulkFileLoader (which, as mentioned before is a singleton), it creates a new instance, rather than returning the instance that is currently in the executing process. It would appear that singletons don't extend into the scope of other processes running on the machine. In the end, I want to be able to kick off the BulkFileLoader, and at any time be able to find out how many rows it's processed. However, that is even if I close the application I used to start it. Can anyone see a solution to my problem?

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  • Can I copy large files faster without using the file cache?

    - by Veazer
    After adding the preload package, my applications seem to speed up but if I copy a large file, the file cache grows by more than double the size of the file. By transferring a single 3-4 GB virtualbox image or video file to an external drive, this huge cache seems to remove all the preloaded applications from memory, leading to increased load times and general performance drops. Is there a way to copy large, multi-gigabyte files without caching them (i.e. bypassing the file cache)? Or a way to whitelist or blacklist specific folders from being cached?

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  • could not save the file /usr/... permission denied (13.04)

    - by plaguedoctor
    I am running Ubuntu 13.04 and am trying to create an .sh file for conky in /usr/bin using gedit. When trying to save I get the error dialogue: Could not save the file /usr/bin/conky-start.sh You do not have the permissions necessary to save the file. Please check that you typed the location correctly and try again." From searching, I think I have to run a command in terminal to allow permission, but I couldn't find out what that is. Edit: I'm trying to create the file conky-start.sh, not change or run it. Thus far, I've opened gedit, copied and pasted some required info from the net, and I'm trying to save-as /usr/bin/conky-start.sh Perhaps I need to create the file first in terminal, then edit it? How would I do that?

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  • php download file slows

    - by hobbywebsite
    OK first off thanks for your time I wish I could give more than one point for this question. Problem: I have some music files on my site (.mp3) and I am using a php file to increment a database to count the number of downloads and to point to the file to download. For some reason this method starts at 350kb/s then slowly drops to 5kb/s which then the file says it will take 11hrs to complete. BUT if I go directly to the .mp3 file my browser brings up a player and then I can right click and "save as" which works fine complete download in 3mins. (Yes both during the same time for those that are thinking it's my connection or ISP and its not my server either.) So the only thing that I've been playing around with recently is the php.ini and the .htcaccess files. So without further ado, the php file, php.ini, and the .htcaccess: download.php <?php include("config.php"); include("opendb.php"); $filename = 'song_name'; $filedl = $filename . '.mp3'; $query = "UPDATE songs SET song_download=song_download+1 WHER song_linkname='$filename'"; mysql_query($query); header('Content-Disposition: attachment; filename='.basename($filedl)); header('Content-type: audio/mp3'); header('Content-Length: ' . filesize($filedl)); readfile('/music/' . $filename . '/' . $filedl); include("closedb.php"); ?> php.ini register_globals = off allow_url_fopen = off expose_php = Off max_input_time = 60 variables_order = "EGPCS" extension_dir = ./ upload_tmp_dir = /tmp precision = 12 SMTP = relay-hosting.secureserver.net url_rewriter.tags = "a=href,area=href,frame=src,input=src,form=,fieldset=" ; Defines the default timezone used by the date functions date.timezone = "America/Los_Angeles" .htaccess Options +FollowSymLinks RewriteEngine on RewriteCond %{HTTP_HOST} !^(www.MindCollar.com)?$ [NC] RewriteRule (.*) http://www.MindCollar.com/$1 [R=301,L] <IfModule mod_rewrite.c> RewriteEngine On ErrorDocument 404 /errors/404.php ErrorDocument 403 /errors/403.php ErrorDocument 500 /errors/500.php </IfModule> Options -Indexes Options +FollowSymlinks <Files .htaccess> deny from all </Files> thanks for you time

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  • Save file in a different location in iPhone App

    - by zp26
    Hi, I have a problem. My proget create a xml file. In the iPhone this file was store in the NSDocumentDirectory. I wanna save this file in another directory like Desktop(where there are the apps) or another visible folder. Thanks. This is my code: -(void)saveInXML:(NSString*)name:(float)x:(float)y:(float)z{ //NSDocumentDirectory put the file in the app directory NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES); NSString *documentsDirectoryPath = [paths objectAtIndex:0]; NSString *filePath = [documentsDirectoryPath stringByAppendingPathComponent:@"filePosizioni.xml"]; NSFileHandle *myHandle; NSFileManager *fileManager = [NSFileManager defaultManager]; NSString *titoloXML = [NSString stringWithFormat:@"File Xml delle posizioni del iPhone"]; NSString *inizioTag = [NSString stringWithFormat:@"\n\n\n<posizione>"]; NSString *tagName = [NSString stringWithFormat:@"\n <name>%@</name>", name]; NSString *tagX = [NSString stringWithFormat:@"\n <x>%f</x>", x]; NSString *tagY = [NSString stringWithFormat:@"\n <y>%f</y>", y]; NSString *tagZ = [NSString stringWithFormat:@"\n <z>%f</z>", z]; NSString *fineTag= [NSString stringWithFormat:@"\n</posizione>"]; NSData* dataTitoloXML = [titoloXML dataUsingEncoding: NSASCIIStringEncoding]; NSData* dataInizioTag = [inizioTag dataUsingEncoding: NSASCIIStringEncoding]; NSData* dataName = [tagName dataUsingEncoding: NSASCIIStringEncoding]; NSData* dataX = [tagX dataUsingEncoding: NSASCIIStringEncoding]; NSData* dataY = [tagY dataUsingEncoding: NSASCIIStringEncoding]; NSData* dataZ = [tagZ dataUsingEncoding: NSASCIIStringEncoding]; NSData* dataFineTag = [fineTag dataUsingEncoding: NSASCIIStringEncoding]; if(![fileManager fileExistsAtPath:filePath]) [fileManager createFileAtPath:filePath contents:dataTitoloXML attributes:nil]; myHandle = [NSFileHandle fileHandleForUpdatingAtPath:filePath]; [myHandle seekToEndOfFile]; [myHandle writeData:dataInizioTag]; NSLog(@"writeok"); [myHandle seekToEndOfFile]; [myHandle writeData:dataName]; NSLog(@"writeok"); [myHandle seekToEndOfFile]; [myHandle writeData:dataX]; NSLog(@"writeok"); [myHandle seekToEndOfFile]; [myHandle writeData:dataY]; NSLog(@"writeok"); [myHandle seekToEndOfFile]; [myHandle writeData:dataZ]; NSLog(@"writeok"); [myHandle seekToEndOfFile]; [myHandle writeData:dataFineTag]; NSLog(@"writeok"); [myHandle seekToEndOfFile]; NSLog(@"zp26 %@",filePath); }

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  • In BASH how can i find my system on active internet interface, what is the upload speed?

    - by YumYumYum
    I am trying to write an TUI bandwidth trace application which on query can instantly tell me, that my download and upload speed is XXXX. I have figured out that download i can use with wget and parse it using BASH, but how do i get the upload speed? Example of download parse method: 1) Remote download : wget http://x.x.com:7007/files/software/vnc.zip Length: 1594344 (1.5M) [application/zip] Saving to: `vnc.zip' 100%[==================================================================>] 1,594,344 573K/s in 2.7s 2012-03-24 11:35:22 (573 KB/s) - `vnc.zip' saved [1594344/1594344] 2) Local download tells Length: 1594344 (1.5M) [application/zip] Saving to: `vnc.zip' 100%[==================================================================>] 1,594,344 --.-K/s in 0.1s 2012-03-24 06:43:04 (11.4 MB/s) - `vnc.zip' saved [1594344/1594344]

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