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  • Java, LDAP: Make it not ignore blank passwords?

    - by Steve
    I'm maintaining some legacy Java LDAP code. I know next to nothing about LDAP. The program below basically just sends the userid and password to the LDAP server, receives notification back if the credentials are good. If so, it prints out the LDAP attributes received from the LDAP server, if not it prints out an exception. All works well if a bad password is given. An "invalid credentials" exception gets thrown. However, if a blank password is sent to the LDAP Server, authentication will still happen, LDAP attributes will still be returned. Is this unhappy situation due to the LDAP server allowing blank passwords, or does the code below need to be adjusted such a blank password will get fed to the LDAP server in such a way so it will get rejected? I do have data validation in place. I took it off in a testing environment to solve another issue and noticed this problem. I would prefer not to have this problem underneath the data validation. Thanks much in advance for any information import javax.naming.*; import javax.naming.directory.*; import java.util.*; import java.sql.*; public class LDAPTEST { public static void main(String args[]) { String lcf = "com.sun.jndi.ldap.LdapCtxFactory"; String ldapurl = "ldaps://ldap-cit.smew.acme.com:636/o=acme.com"; String loginid = "George.Jetson"; String password = ""; DirContext ctx = null; Hashtable env = new Hashtable(); Attributes attr = null; Attributes resultsAttrs = null; SearchResult result = null; NamingEnumeration results = null; int iResults = 0; int iAttributes = 0; env.put(Context.INITIAL_CONTEXT_FACTORY, lcf); env.put(Context.PROVIDER_URL, ldapurl); env.put(Context.SECURITY_PROTOCOL, "ssl"); env.put(Context.SECURITY_AUTHENTICATION, "simple"); env.put(Context.SECURITY_PRINCIPAL, "uid=" + loginid + ",ou=People,o=acme.com"); env.put(Context.SECURITY_CREDENTIALS, password); try { ctx = new InitialDirContext(env); attr = new BasicAttributes(true); attr.put(new BasicAttribute("uid",loginid)); results = ctx.search("ou=People",attr); while (results.hasMore()) { result = (SearchResult)results.next(); resultsAttrs = result.getAttributes(); for (NamingEnumeration enumAttributes = resultsAttrs.getAll(); enumAttributes.hasMore();) { Attribute a = (Attribute)enumAttributes.next(); System.out.println("attribute: " + a.getID() + " : " + a.get().toString()); iAttributes++; }// end for loop iResults++; }// end while loop System.out.println("Records == " + iResults + " Attributes: " + iAttributes); }// end try catch (Exception e) { e.printStackTrace(); } }// end function main() }// end class LDAPTEST

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  • Java -Android. Parser problem

    - by Kano
    I am making a very simple app with an RSS reader. The reader works great, but it's only giving me the title, and i want the description too. I'am very new to android, and I have tried a lot of things, but I can't get it to work. I've found a lot of parsers but they are to complicated for me to understand, so I was hoping to find a simple solution, since it's only title and description i want. Can anyone help me? import java.io.IOException; import java.net.MalformedURLException; import java.net.URL; import javax.xml.parsers.ParserConfigurationException; import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.Attributes; import org.xml.sax.InputSource; import org.xml.sax.SAXException; import org.xml.sax.XMLReader; import org.xml.sax.helpers.DefaultHandler; import android.app.Activity; import android.os.Bundle; import android.widget.TextView; public class NyhedActivity extends Activity { String streamTitle = ""; @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.nyheder); TextView result = (TextView)findViewById(R.id.result); try { URL rssUrl = new URL("http://tv2sport.dk/rss/*/*/*/248/*/*"); SAXParserFactory mySAXParserFactory = SAXParserFactory.newInstance(); SAXParser mySAXParser = mySAXParserFactory.newSAXParser(); XMLReader myXMLReader = mySAXParser.getXMLReader(); RSSHandler myRSSHandler = new RSSHandler(); myXMLReader.setContentHandler(myRSSHandler); InputSource myInputSource = new InputSource(rssUrl.openStream()); myXMLReader.parse(myInputSource); result.setText(streamTitle); } catch (MalformedURLException e) { // TODO Auto-generated catch block e.printStackTrace(); result.setText("Cannot connect RSS!"); } catch (ParserConfigurationException e) { // TODO Auto-generated catch block e.printStackTrace(); result.setText("Cannot connect RSS!"); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); result.setText("Cannot connect RSS!"); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); result.setText("Cannot connect RSS!"); } } private class RSSHandler extends DefaultHandler { final int stateUnknown = 0; final int stateTitle = 1; int state = stateUnknown; int numberOfTitle = 0; String strTitle = ""; String strElement = ""; @Override public void startDocument() throws SAXException { // TODO Auto-generated method stub strTitle = "Nyheder fra "; } @Override public void endDocument() throws SAXException { // TODO Auto-generated method stub strTitle += ""; streamTitle = "" + strTitle; } @Override public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException { // TODO Auto-generated method stub if (localName.equalsIgnoreCase("title")) { state = stateTitle; strElement = ""; numberOfTitle++; } else { state = stateUnknown; } } @Override public void endElement(String uri, String localName, String qName) throws SAXException { // TODO Auto-generated method stub if (localName.equalsIgnoreCase("title")) { strTitle += strElement + "\n"+"\n"; } state = stateUnknown; } @Override public void characters(char[] ch, int start, int length) throws SAXException { // TODO Auto-generated method stub String strCharacters = new String(ch, start, length); if (state == stateTitle) { strElement += strCharacters; } } } }

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  • how to determin what url has opened file now? (php)

    - by Ole Jak
    so I want to be able to get informed if my php script file is opened in localhost/myfile.php or in something like 222.22.22.22/myfile.php so I needa php function to determin if url starts with localhost or any other address (I want to get it as string like '22.33.22.33') How to do such thing?

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  • How to tell which php.ini files is loaded ?

    - by Vince Jacobs
    Looking at my php.info all it says is "Loaded Configuration file:" C:\xampp\php\php.ini Yet I have two ini files inside the php folder. One, "development", the other "production". I can not see within either ini file the value, "Loaded Configuration file" .. So How do I tell which one is being used and where is that managed ? My goal is to have only 1 ini file and disable the other. Many Thanks !

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  • Is It Possible to Make Close Sourced PHP Product?

    - by Morgan Cheng
    I'm curious that whether all PHP product must be open sourced if it is to be deployed to other's web site. Since PHP code is executed by interpretation, if I have PHP product to be deployed on other's host, it seems no reason to prevent others view the source code. So, PHP product is destined to be open source, right?

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  • Switching from PHP to Ruby - is it the answer to performance?

    - by Industrial
    Hi everyone, I get more often the answer, when asking performance related stuff regarding PHP applications, that PHP really isn't the language for high-performance applications, and that a compiled language really is the way to go. The only thing holding me back to PHP is that it's what I have learned to work with for some while now and the development is quite rapid. So, is PHP a thing of the past and should be put aside in web applications in favour of Ruby, for instance? Thanks

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  • pagination using php with mysql data

    - by pradeep
    i am trying to create a pagination in which there are 5 items at a time depending on the number of items in DB. i wrote this code . but i dono how to go further .its buggy..any better pagination or alteration for this <?php $myresult .= "<div class='pagination' >"; if ($pagenum == 1) { } else { $pagenum = 1; $myresult .= "<a href='javascript:newPage(\"".$pagenum."\")'>&nbsp;first&nbsp;</a>"; $myresult .= " "; $previous = $pagenum-1; $myresult .= "<a href='javascript:newPage(\"".$previous."\")'> &nbsp;Prev&nbsp;</a>"; if ($pagenum == $last) { $previous3 = $pagenum-4; $myresult .= "<a href='javascript:newPage(\"".$previous3."\")'> &nbsp; $previous3 &nbsp;</a>"; $previous2 = $pagenum-3; $myresult .= "<a href='javascript:newPage(\"".$previous2."\")'> &nbsp; $previous2 &nbsp;</a>"; } if ($pagenum > 2) { $previous1 = $pagenum-2; $myresult .= "<a href='javascript:newPage(\"".$previous1."\")'> &nbsp; $previous1 &nbsp;</a>"; } if ($pagenum > 1) { $previous2 = $pagenum-1; $myresult .= "<a href='javascript:newPage(\"".$previous2."\")'> &nbsp; $previous2 &nbsp;</a>"; $myresult .= " "; } } $myresult .= "<span class=\"disabled\"> $pagenum </span>"; if ($pagenum == $last) { } else { if($pagenum < $last - 1) { $next = $pagenum+1; $myresult .= "<a href='javascript:newPage(\"".$next."\")'>&nbsp; $next &nbsp;</a>"; } if($pagenum < $last - 2) { $next1 = $pagenum+2; $myresult .= "<a href='javascript:newPage(\"".$next1."\")'> &nbsp; $next1 &nbsp;</a>"; } if($pagenum == 1 ) { $next2 = $pagenum+3; $myresult .= "<a href='javascript:newPage(\"".$next2."\")'> &nbsp; $next2 &nbsp;</a>"; $next3 = $pagenum+4; $myresult .= "<a href='javascript:newPage(\"".$next3."\")'> &nbsp; $next3 &nbsp;</a>"; } if($pagenum == 2 ) { $next2 = $pagenum+3; $myresult .= "<a href='javascript:newPage(\"".$next2."\")'> &nbsp; $next2 &nbsp;</a>"; } $next = $pagenum+1; $myresult .= "<a href='javascript:newPage(\"".$next."\")'>&nbsp;Next&nbsp;</a>"; $myresult .= "<a href='javascript:newPage(\"".$last."\")'>&nbsp;Last</a>"; } $myresult .= "</div>"; $myresult .= "</br>"; ?>

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  • How do I make non-framework code to framework code? (PHP)

    - by ggfan
    I just started using CakePHP and it's very different from just normal procedural or basic OOP PHP. I am still learning PHP and still read "beginning PHP/mysql" books that teaches you basic PHP. Also lots of sites online provide code that isn't for a framework. Is the only way to make non-framework code to say a framework, say cakePHP, by learning cakePHP thoroughly than rewriting the code yourself to fit the MVC model?

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  • PHP Array issue - not looping through foreach...

    - by Homer_J
    Ok, Here is the code: function fetch_questions($page) { global $link; $proc = mysqli_prepare($link, "SELECT * FROM tquestions_cwh WHERE page = ?"); mysqli_stmt_bind_param($proc, "i", $page); mysqli_stmt_execute($proc); $rows = array(); stmt_bind_assoc($proc, $rowq); // loop through all result rows while ($proc->fetch()) { // print_r($rowq); $rows[]=$rowq; } mysqli_stmt_close($proc); mysqli_clean_connection($link); return($rows); } I then add this to a php variable, like so: $qs = fetch_questions($page); I then loop through is, like so: foreach($qs as $value){ echo "<tr>".$value['qnum']." is the questions number and the question text is ".$value['qtext'].". The page and q values are ".$value['page']." and ".$value['questions']." respectively.</tr>"; The output, however is this: 8 is the questions number and the question text is I know how what I do fits into my team's objectives. The page and q values are 1 and q8 respectively.8 is the questions number and the question text is I know how what I do fits into my team's objectives. The page and q values are 1 and q8 respectively.8 is the questions number and the question text is I know how what I do fits into my team's objectives. The page and q values are 1 and q8 respectively.8 is the questions number and the question text is I know how what I do fits into my team's objectives. The page and q values are 1 and q8 respectively.8 is the questions number and the question text is I know how what I do fits into my team's objectives. The page and q values are 1 and q8 respectively.8 is the questions number and the question text is I know how what I do fits into my team's objectives. The page and q values are 1 and q8 respectively.8 is the questions number and the question text is I know how what I do fits into my team's objectives. The page and q values are 1 and q8 respectively.8 is the questions number and the question text is I know how what I do fits into my team's objectives. The page and q values are 1 and q8 respectively. Which is not what I want, for information purposes, the array using the print function looks like this: Array ( [0] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [1] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [2] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [3] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [4] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [5] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [6] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [7] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) ) Clearly it's not looping through and displaying each row as it should...any advice? Homer.

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  • Can java do a timer on command line by overwriting the time on the same line?

    - by javaLearner.java
    HI I am a new java programmer (very new). What I want to do/test is (not sure if its recommendable or doable?), we know that System.out.println("Message"); will output the "Message" in command prompt. Is it possible to display the current time, without having to repeatly use the system.out.println()? Name, like instead of displaying: 10:00:01 10:00:02 10:00:03 I wand to have liek this: 10:00:0X where X will continue counting

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  • What is the best way to include a php file as a template?

    - by Jon
    I have simple template that's html mostly and then pulls some stuff out of SQL via PHP and I want to include this template in three different spots of another php file. What is the best way to do this? Can I include it and then print the contents? Example of template: Price: <?php echo $price ?> and, for example, I have another php file that will show the template file only if the date is more than two days after a date in SQL.

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  • Explanation of the definition of interface inheritance as described in GoF book

    - by Geek
    I am reading the first chapter of the Gof book. Section 1.6 discusses about class vs interface inheritance: Class versus Interface Inheritance It's important to understand the difference between an object's class and its type. An object's class defines how the object is implemented.The class defines the object's internal state and the implementation of its operations.In contrast,an object's type only refers to its interface--the set of requests on which it can respond. An object can have many types, and objects of different classes can have the same type. Of course, there's a close relationship between class and type. Because a class defines the operations an object can perform, it also defines the object's type . When we say that an object is an instance of a class, we imply that the object supports the interface defined by the class. Languages like c++ and Eiffel use classes to specify both an object's type and its implementation. Smalltalk programs do not declare the types of variables; consequently,the compiler does not check that the types of objects assigned to a variable are subtypes of the variable's type. Sending a message requires checking that the class of the receiver implements the message, but it doesn't require checking that the receiver is an instance of a particular class. It's also important to understand the difference between class inheritance and interface inheritance (or subtyping). Class inheritance defines an object's implementation in terms of another object's implementation. In short, it's a mechanism for code and representation sharing. In contrast,interface inheritance(or subtyping) describes when an object can be used in place of another. I am familiar with the Java and JavaScript programming language and not really familiar with either C++ or Smalltalk or Eiffel as mentioned here. So I am trying to map the concepts discussed here to Java's way of doing classes, inheritance and interfaces. This is how I think of of these concepts in Java: In Java a class is always a blueprint for the objects it produces and what interface(as in "set of all possible requests that the object can respond to") an object of that class possess is defined during compilation stage only because the class of the object would have implemented those interfaces. The requests that an object of that class can respond to is the set of all the methods that are in the class(including those implemented for the interfaces that this class implements). My specific questions are: Am I right in saying that Java's way is more similar to C++ as described in the third paragraph. I do not understand what is meant by interface inheritance in the last paragraph. In Java interface inheritance is one interface extending from another interface. But I think the word interface has some other overloaded meaning here. Can some one provide an example in Java of what is meant by interface inheritance here so that I understand it better?

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  • Which programming language to get into?

    - by user602479
    I'm ending my third term in a few weeks so I have some spare time coming up. I'd like to spend it seriously digging into programming. My problem: I'm not sure which language to begin with. Just to be clear, I don't want to start a language-y-compared-to-language-z discussion. There are a some other issues that play a major role. In my 5th term I'm going to be participating in a major practical course which will include either Java or C programming. It will take a lot of time and energy, as I found out while talking to a few students who passed the final exams (only 15% pass on their first try). Which practical course I will take is randomly decided. My skills so far are the absolute basics of Java and C programming. I know the different data types and how to handle them, objects, pointers, thread programming, etc. All of that is on a very low level, though. My question now is, what language should I start seriously practicing? Java: I did my first GUIs with this language. I'm familiar with Eclipse but I need a project to work on (which I don't have) to really keep me pushing. Besides that, I don't think it would help me if I have to do C in a year. C: As with Java, I can't think of a personal project to keep me working and keep me interested in programming. If I get assigned to Java in a year, this wouldn't give me any advantages either, would it? (No objects, etc.) Objective-C: I recently came up with this idea. I have a Mac; I'm not really familiar with Xcode but I have one or two personal projects I'd like to work on. Further, I would be working with objects (as in Java) and C language constructs which would both be great for this practical course in a year. What do you think I should begin with? Should I just stick to Java and hope for the best, force myself through C or start (nearly) completely from the beginning with Objective C? Maybe you folks could give me some good advice that would stop me from switching from one language to the next?

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  • JCP.next.3: time to get to work

    - by Patrick Curran
    As I've previously reported in this blog, we planned three JSRs to improve the JCP’s processes and to meet our members’ expectations for change. The first - JCP.next.1, or more formally JSR 348: Towards a new version of the Java Community Process - was completed in October 2011. This focused on a small number of simple but important changes to make our process more transparent and to enable broader participation. We're already seeing the benefits of these changes as new and existing JSRs adopt the new requirements. However, because we wanted to complete this JSR quickly we deliberately postponed a number of more complex items, including everything that would require modifying the JSPA (the legal agreement that members sign when they join the organization) to a follow-on JSR. The second JSR (JSR 355: JCP Executive Committee Merge) is in progress now and will complete later this year. This JSR is even simpler than the first, and is focused solely on merging the two Executive Committees into one for greater efficiency and to encourage synergies between the Java ME and Java SE platforms. Continuing the momentum to move Java and the JCP forward we have just filed the third JSR (JCP.next.3) as JSR 358: A major revision of the Java Community Process. This JSR will modify the JSPA as well as the Process Document, and will tackle a large number of complex issues, many of them postponed from JSR 348. For these reasons we expect to spend a considerable amount of time working on it - at least a year, and probably more. The current version of the JSPA was created back in 2002, although some minor changes were introduced in 2005. Since then the organization and the environment in which we operate have changed significantly, and it is now time to revise our processes to ensure that they meet our current needs. We have a long list of topics to be considered, including the role of independent implementations (those not derived from the Reference Implementation), licensing and open source, ensuring that our new transparency requirements are implemented correctly, compatibility policy and TCKs, the role of individual members, patent policy, and IP flow. The Expert Group for JSR 358, as with all process-change JSRs, consists of all members of the Executive Committees. Even though the JSR has just been filed we started discussions on the various topics several months ago (see the EC's meeting minutes for details) and our EC members - including the new members who joined within the last year or two - are actively engaged. Now it's your opportunity to get involved. As required by version 2.8 of our Process (introduced with JSR 348) we will conduct all our business in the open. We have a public java.net project where you can follow and participate in our work. All of our deliberations will be copied to a public Observer mailing list, we'll track our issues on a public Issue Tracker, and all our documents (meeting agendas and minutes, task lists, working drafts) will be published in our Document Archive. We're just getting started, but we do want your input. Please visit us on java.net where you can learn how to participate. Let's get to work...

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  • cakephp & nginx config/rewrite rules

    - by seanl
    Hi somebody please help me out, I've asked this at stackoverflow as well but not got much of a response and was debating whether it was programming or server related. I’m trying to setup a cakephp environment on a Centos server running Nginx with Fact CGI. I already have a wordpress site running on the server and a phpmyadmin site so I have PHP configured correctly. My problem is that I cannot get the rewrite rules setup correct in my vhost so that cake renders pages correctly i.e. with styling and so on. I’ve googled as much as possible and the main consensus from the sites like the one listed below is that I need to have the following rewrite rule in place location / { root /var/www/sites/somedomain.com/current; index index.php index.html; # If the file exists as a static file serve it # directly without running all # the other rewrite tests on it if (-f $request_filename) { break; } if (!-f $request_filename) { rewrite ^/(.+)$ /index.php?url=$1 last; break; } } http://blog.getintheloop.eu/2008/4/17/nginx-engine-x-rewrite-rules-for-cakephp problem is these rewrite assume you run cake directly out of the webroot which is not what I want to do. I have a standard setup for each site i.e. one folder per site containing the following folders log, backup, private and public. Public being where nginx is looking for its files to serve but I have cake installed in private with a symlink in public linking back to /private/cake/ this is my vhost server { listen 80; server_name app.domain.com; access_log /home/public_html/app.domain.com/log/access.log; error_log /home/public_html/app.domain.com/log/error.log; #configure Cake app to run in a sub-directory #Cake install is not in root, but elsewhere and configured #in APP/webroot/index.php** location /home/public_html/app.domain.com/private/cake { index index.php; if (!-e $request_filename) { rewrite ^/(.+)$ /home/public_html/app.domain.com/private/cake/$1 last; break; } } location /home/public_html/app.domain.com/private/cake/ { index index.php; if (!-e $request_filename) { rewrite ^/(.+)$ /home/public_html/app.domain.com/public/index.php?url=$1 last; break; } } # pass the PHP scripts to FastCGI server listening on 127.0.0.1:9000 location ~ \.php$ { fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME /home/public_html/app.domain.com/private/cake$fastcgi_script_name; include /etc/nginx/fastcgi_params; } } Now like I said I can see the main index.php of cake and have connected it to my DB but this page is without styling so before I proceed any further I would like to configure it correctly. What am I doing wrong………. Thanks seanl

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  • Use MTOM/streaming from C# calling a webservice in java exposed via jaxws

    - by raticulin
    We have this webservice created with jax-ws @WebService(name = "Mywebser", targetNamespace = "http://namespace") @MTOM(threshold = 2048) @SOAPBinding(style = SOAPBinding.Style.DOCUMENT, use = SOAPBinding.Use.LITERAL, parameterStyle = SOAPBinding.ParameterStyle.WRAPPED) public class Mywebser { @WebMethod(operationName = "doStreaming", action = "urn:doStreaming") @WebResult(name = "return") public ResultInfo doStreaming(String username, String pwd, @XmlMimeType("application/octet-stream") DataHandler data, boolean overw){ ... } } The generated client side looks like this: @WebMethod(action = "urn:doStreaming") @WebResult(targetNamespace = "") @RequestWrapper(localName = "doStreaming", targetNamespace = "http://namespace", className = "com.mypack.client.doStreaming") @ResponseWrapper(localName = "doStreamingResponse", targetNamespace = "http://namespace", className = "com.mypack.client.doStreamingResponse") public ResultInfo doStreaming( @WebParam(name = "arg0", targetNamespace = "") String arg0, @WebParam(name = "arg1", targetNamespace = "") String arg1, @WebParam(name = "arg2", targetNamespace = "") DataHandler arg2, @WebParam(name = "arg3", targetNamespace = "") boolean arg3); By using it this way it uses streaming properly (verified we can pass an argument of 80mb when the jvm had less allowed. MywebserService serv = ...; Mywebser wso = serv.getMywebserPort(new MTOMFeature()); Map<String, Object> ctxt = ((BindingProvider) wso).getRequestContext(); ctxt.put(JAXWSProperties.HTTP_CLIENT_STREAMING_CHUNK_SIZE, 8192); DataHandler dataHandler = new DataHandler(new FileDataSource("c:\\temp\\A.dat")); arcres = wso.doStreaming("a", "b", dataHandler, true); We generate a clienet for .net, with VS2008, using "Add Web Reference", we get this C# code: [System.Web.Services.Protocols.SoapDocumentMethodAttribute("urn:doStreaming",RequestNamespace="http://namespace",ResponseNamespace="http://namespace",Use=System.Web.Services.Description.SoapBindingUse.Literal,ParameterStyle=System.Web.Services.Protocols.SoapParameterStyle.Wrapped)] [return: System.Xml.Serialization.XmlElementAttribute("return",Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] public ResultInfo doStreaming( [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] string arg0, [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] string arg1, [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified,DataType="base64Binary")] byte[] arg2, [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] bool arg3) Apparently this is not using streaming? The type base64Binary of arg2 seems not the right one? In java it's a DataHandler. By testing it with low memory on the java side we can see it is not using streaming as it fails with OOM. Does someone knows if this is possible, and if so how? Our environment: server: jdk1.6, jaxws 2.1.7 client: C# 2.0, visual studio 2008

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  • log file is not getting created using JDK logging with Commons-logging

    - by Saida Dhanavath
    When I run the TestJcLLoggingService class log messages are coming to Console but no log file is created, please help me if you know the answer. two source files are pasted below. TestJcLLoggingService.java package com.amadeus.psp.pasd.logging; import org.apache.commons.logging.Log; import org.apache.commons.logging.LogFactory; import org.springframework.stereotype.Service; @Service public class TestJCLLoggingService { private static Log psp_log = LogFactory.getLog(TestJCLLoggingService.class); public static String testJCLLoggingServiceMethod(){ psp_log.info("start of method testJCLLoggingServiceMethod class TestJCLLoggingService"); psp_log.info("start of method testJCLLoggingServiceMethod class TestJCLLoggingService"); return "This is a test string for JCLLogging"; } public static void main(String[] args){ testJCLLoggingServiceMethod(); } } logging.properties handlers = java.util.logging.ConsoleHandler, java.util.logging.FileHandler .level = ALL com.amadeus.psp.pasd.level=ALL java.util.logging.ConsoleHandler.level = ALL java.util.logging.ConsoleHandler.formatter = java.util.logging.SimpleFormatter java.util.logging.FileHandler.pattern = %h/java%u.log java.util.logging.FileHandler.level=ALL java.util.logging.FileHandler.limit=50000 java.util.logging.FileHandler.count=1 java.util.logging.FileHandler.formatter=java.util.logging.SimpleFormatter java.util.logging.FileHandler.append=true Thanks in advance.

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  • Play Framework: Error getting sequence nextval using H2 in-memory database

    - by alexhanschke
    As the title suggests, I get an error running Play 2.0.1 Tests using a FakeApplication w/ H2 in memory. I set up a basic unit test: public class ModelTest { @Test public void checkThatIndustriesExist() { running(fakeApplication(inMemoryDatabase()), new Runnable() { public void run() { Industry industry = new Industry(); industry.name = "Some name"; industry.shortname = "some-name"; industry.save(); assertThat(Industry.find.all()).hasSize(1); } }); } Which yields the following exception: [info] test.ModelTest [error] Test test.ModelTest.checkThatIndustriesExist failed: Error getting sequence nextval [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.getMoreIds(SequenceIdGenerator.java:213) [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.loadMoreIds(SequenceIdGenerator.java:163) [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.nextId(SequenceIdGenerator.java:118) [error] at com.avaje.ebeaninternal.server.deploy.BeanDescriptor.nextId(BeanDescriptor.java:1218) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.setIdGenValue(DefaultPersister.java:1304) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.insert(DefaultPersister.java:403) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.saveEnhanced(DefaultPersister.java:345) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.saveRecurse(DefaultPersister.java:315) [error] at com.avaje.ebeaninternal.server.persist.DefaultPersister.save(DefaultPersister.java:282) [error] at com.avaje.ebeaninternal.server.core.DefaultServer.save(DefaultServer.java:1577) [error] at com.avaje.ebeaninternal.server.core.DefaultServer.save(DefaultServer.java:1567) [error] at com.avaje.ebean.Ebean.save(Ebean.java:538) [error] at play.db.ebean.Model.save(Model.java:76) [error] at test.ModelTest$1.run(ModelTest.java:24) [error] at play.test.Helpers.running(Helpers.java:277) [error] at test.ModelTest.checkThatIndustriesExist(ModelTest.java:21) [error] ... [error] Caused by: org.h2.jdbc.JdbcSQLException: Syntax Fehler in SQL Befehl "SELECT INDUSTRY_SEQ.NEXTVAL UNION[*] SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL "; erwartet "identifier" [error] Syntax error in SQL statement "SELECT INDUSTRY_SEQ.NEXTVAL UNION[*] SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL UNION SELECT INDUSTRY_SEQ.NEXTVAL "; expected "identifier"; SQL statement: [error] select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval union select industry_seq.nextval [42001-158] [error] at org.h2.message.DbException.getJdbcSQLException(DbException.java:329) [error] at org.h2.message.DbException.get(DbException.java:169) [error] at org.h2.message.DbException.getSyntaxError(DbException.java:194) [error] at org.h2.command.Parser.readColumnIdentifier(Parser.java:2777) [error] at org.h2.command.Parser.readTermObjectDot(Parser.java:2336) [error] at org.h2.command.Parser.readTerm(Parser.java:2453) [error] at org.h2.command.Parser.readFactor(Parser.java:2035) [error] at org.h2.command.Parser.readSum(Parser.java:2022) [error] at org.h2.command.Parser.readConcat(Parser.java:1995) [error] at org.h2.command.Parser.readCondition(Parser.java:1860) [error] at org.h2.command.Parser.readAnd(Parser.java:1841) [error] at org.h2.command.Parser.readExpression(Parser.java:1833) [error] at org.h2.command.Parser.parseSelectSimpleSelectPart(Parser.java:1746) [error] at org.h2.command.Parser.parseSelectSimple(Parser.java:1778) [error] at org.h2.command.Parser.parseSelectSub(Parser.java:1673) [error] at org.h2.command.Parser.parseSelectUnion(Parser.java:1518) [error] at org.h2.command.Parser.parseSelect(Parser.java:1506) [error] at org.h2.command.Parser.parsePrepared(Parser.java:405) [error] at org.h2.command.Parser.parse(Parser.java:279) [error] at org.h2.command.Parser.parse(Parser.java:251) [error] at org.h2.command.Parser.prepareCommand(Parser.java:217) [error] at org.h2.engine.Session.prepareLocal(Session.java:415) [error] at org.h2.engine.Session.prepareCommand(Session.java:364) [error] at org.h2.jdbc.JdbcConnection.prepareCommand(JdbcConnection.java:1119) [error] at org.h2.jdbc.JdbcPreparedStatement.<init>(JdbcPreparedStatement.java:71) [error] at org.h2.jdbc.JdbcConnection.prepareStatement(JdbcConnection.java:267) [error] at com.jolbox.bonecp.ConnectionHandle.prepareStatement(ConnectionHandle.java:820) [error] at com.avaje.ebean.config.dbplatform.SequenceIdGenerator.getMoreIds(SequenceIdGenerator.java:193) [error] ... 80 more My model looks like this: @Entity @Table(name = "industry") public class Industry extends Model { @Id public Long id; public String name; public String shortname; // called in the view to trigger lazy-loading public String getName() { return name; } public static Finder<Long, Industry> find = new Finder<Long, Industry>(Long.class, Industry.class); } ... and finally the relevant part from my initial evolution: create table industry ( id bigint not null, name varchar(255), shortname varchar(255), constraint pk_industry primary key (id) } create sequence industry_seq start with 1000; Everything works fine running on my PostgreSQL DB, and from my point of view the code is not any different from the Play2.0 Computer Database Sample. I am happy for any help - thanks! Regards, Alex

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