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  • custom cells uitableview - cannot display all the rows

    - by Matt Facer
    Hi guys, I'm creating a uitableview with custom cells which I created in Interface Builder. There are currently three cells (UITableViewCell). I have a UITableView which is on the view. The code I have is fairly standard, but I cannot work out how to actually SHOW the three custom cells. I am using the cellForRowAtIndexPath method. My aim is to get a grouped uitableview which shows like the following Item - Name Settings - alert - time So the above indented view should be my grouped uitableview. The problem is, I cannot get it to show using code. The uitableview will ALWAYS be this. I am trying to replicate the settings style screen... so I do not have any arrays to display the uitableview cells. How do I actually display my three cells? I have the following code - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { return 2; } - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { if (section == 0) return 1; else return 2; } - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section { if(section == 0) return @"Item"; else return @"Settings"; } So all I need to know is how to actually display my custom cells inside the tableview! Thanks for any information. I've searched for AGES in google .. all the tutorials use arrays to display data!

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  • NSFetchedResultsController is driving me crazy

    - by user267980
    Hi everyone. i've been building an app since 1 month using NSFetchedResultsController and i was testing the app on the 3.1.2 SDK. The poblem is that i've been using NSFetchedResultsController everywhere in my app and was working on the 3.1.2 version of the SDK, now my client say that i should make it compatible with the 3.0 version and the deadline is almost there. But is crashing everytime i change an object handled by the contoller, the application is crashing with very weird errors. The problem occure when removing the last object in a section and when a change make an object love to another section. I've been using a sample code from "More iPhone 3 Development Tackling iPhone SDK 3" by Dave Mark and Jeff LaMarche. I've also included some changes from link text Here is a sample output of the console when the application is crashing. * Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: 'Invalid update: invalid number of sections. The number of sections contained in the table view after the update (1) must be equal to the number of sections contained in the table view before the update (2), plus or minus the number of sections inserted or deleted (2 inserted, 0 deleted).' 2010-03-14 16:23:29.758 Instaproofs[5879:207] Stack: ( 807902715, 7364425, 807986683, 811271572, 815059090, 815007323, 211023, 4363331, 810589786, 807635429, 810579728, 3620573, 3620227, 3614682, 3609719, 27337, 810595174, 807686849, 807683624, 839142449, 839142646, 814752238 ) If i knew that NSFetchedResultsController is so buggy, i would never used it. So basicaly i need the my NSFetchedResultsControllerDelegate to work fine on the 3.0 and above SDKs. It would be life saver if someone help me figure out what i'm doing wrong.

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  • How do you replace an entire xaml element?

    - by luke
    <ListView> <ListView.Resources> <DataTempalte x:Key="label"> <TextBlock Text="{Binding Label}"/> </DataTEmplate> <DataTemplate x:Key="editor"> <UserControl Content="{Binding Control.content}"/> <!-- This is the line --> </DataTemplate> </ListView.Resources> <ListView.View> <GridView> <GridViewColumn Header="Name" CellTemplate="{StaticResource label}"/> <GridViewColumn Header="Value" CellTemplate="{StaticResource editor}"/> </GridView> </ListView.View> On the marketed line, I'm replacing the contents of a UserControl with the contents of another UserControl that is dynamically created in code. I'd like to replace the entire control, and not just the content. Is there a way to do this?

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  • form layout in drupal from a module

    - by EricP
    I created my own module called "cssswitch". I'm trying to create my own html layout to display the admin form portion of the module. I understand how to use the hook_form_alter() to modify form elements, but I need to create the entire form layout to make some fields appear next to each other. It seems I need something like the way I have the frontend view of the node displayed with theme_cssswitch_display(), but for the admin part of the node. function cssswitch_form_alter(&$form, $form_state, $form_id) { switch($form_id) { case 'cssswitch_node_form': $form['hour_start']['#prefix'] = '<div class="start-box">'; $form['ampm_start']['#suffix'] = '</div>'; $form['ampm_start']['#attributes'] = array("style" => "border-width:2px;"); break; } } function cssswitch_theme() { return array( 'cssswitch_display' => array( 'arguments' => array('node'), ), ); } // to display the view of the node function theme_cssswitch_display($node) { $output = '<div class="cssswitch-cssfilename">Filename: '. check_plain($node->cssfilename). '</div>'; $output .= '<div class="cssswitch-time_start">Start: '. check_plain($node->hour_start). ':'.check_plain($node->minute_start).' '.check_plain($node->ampm_start).'</div>'; $output .= '<div class="cssswitch-time_end">End: '. check_plain($node->hour_end). ':'.check_plain($node->minute_end).' '.check_plain($node->ampm_end).'</div>'; return $output; } thanks for any help

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  • Calling a method within Portlet when submitting form

    - by Roland
    I have a Portlet that contains a form. Now what I want to achieve is the following. 1) A Porlet containing a form is called within a page via <?php $this->widget('form'); ?> 2) The user fills in this form and clicks on submit "The submit button should be an ajax button" 3) When submit has been pressed the form should call a method within the form portlet class and the form should be replaced with a Thank you message. 4) I only want the current view in the portlet replaced with another view. My portlet class looks like this Yii::import('zii.widgets.CPortlet'); class Polls extends CPortlet{ public $usr_id=''; public function init(){ $cs = Yii::app()->clientScript; $cs->registerCoreScript('jquery'); parent::init(); } protected function renderContent(){ $this->render('form'); } public function update(){ $this->render('thankyou'); } } } Any advise, help would be highly appreciated.

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  • jQuery: How would I show/hide these elements?

    - by Shpigford
    Here's my HTML: <ul> <li> <p><label><input type="checkbox" name="permission" value="1" class="permission_check" checked> Joe Schmoe</label></p> <p class="radio_option"><label><input type="radio" name="viewpromote" value="1"> View and Promote</label></p> <p class="radio_option"><label><input type="radio" name="createedit" value="1" checked> ...plus Create and Edit</label></p> </li> <li> <p><label><input type="checkbox" name="permission" value="1" class="permission_check" checked> Bob Smith</label></p> <p class="radio_option"><label><input type="radio" name="viewpromote" value="1" checked> View and Promote</label></p> <p class="radio_option"><label><input type="radio" name="createedit" value="1"> ...plus Create and Edit</label></p> </li> </ul> What I need to do is when a user checks/unchecks the permission_check input, then it should show/hide the radio_option elements for that list item.

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  • How to develop modular web UIs with Django?

    - by nh2
    When doing larger sites in "big business", you most probalbly work in a team with several developers. Let's say dev A makes a form to insert new user data, B creates a user list, C makes some privilege administration and D does crazy statistic graphs work with image generation and so on. Each dev begins to develop his own component, creates a view and a template and tests that independently, until each component works. Now, the client wants to have all those components on one bit HTML page. How to achieve this? How to assemble different views/templates in a form of composition so that they remain modular and can be developed and tested independently? It seems inheritance is not the way to go because all of those UI components are equal and there is no hierarchy. The idea of the assembling template is something like <html> <head> // include the css for the components and their assembly </head> <body> // include user data form here <some containers, images, and so on> // show user list // show privilege administration in this part // and finally, the nice statistic graphs // perhaps, we want to display some other components here in future </body> </html> I have not found an answer on the net yet. Most people come up with one big template which just implements all of the UI functionality, removing all modularity. Each component shall have its own template and view dealing only with that component developed by one person each, and they then shall be sticked together just like bricks. I would highly appreciate any hints!

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  • Initial text and paperclipped-URL for action in UIActivityViewController & UIActivityItemSource?

    - by Benjamin Kreeger
    Finally been making it through Apple's (rather dismal) documentation on the new UIActivityViewController class and the UIActivityItemSource protocol, and I'm trying to send different data sets to different actions called from the activity view. To simplify things, I'm looking at two things. A Facebook posting action, which should say "Check this out!" and also attach a URL to the post (with that cute little paperclip). A Twitter posting action, which should say "Check this out, with #hashtag!" and also attach that same URL (with the same paperclip). Here's the code I've got implemented right now. - (id)activityViewController:(UIActivityViewController *)activityViewController itemForActivityType:(NSString *)activityType { if ([activityType isEqualToString:UIActivityTypePostToFacebook]) { return @"Check this out!"; } else if ([activityType isEqualToString:UIActivityTypePostToTwitter]) { return @"Check this out, with #hashtag!"; } return @""; } - (id)activityViewControllerPlaceholderItem:(UIActivityViewController *)activityViewController { return @""; } And then when I set up this activity view controller (it's in the same class), this is what I do. UIActivityViewController *activityView = [[UIActivityViewController alloc] initWithActivityItems:@[self] applicationActivities:nil]; [self presentViewController:activityView animated:YES completion:nil]; My dilemma is how to attach that NSURL object. It's relatively easy when calling the iOS 6 SL-class posting modals; you just call the individual methods to attach a URL or an image. How would I go about doing this here? I'll note that instead of returning NSString objects from -activityViewController:itemForActivityType, if I return just NSURL objects, they show up with that paperclip, with no body text in the post. If I return an array of those two items, nothing shows up at all.

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  • Wpf binding with nested properties

    - by byte
    ViewModel I have a property of type Member called KeyMember. The 'Member' type has an ObservableCollection called Addresses. The Address is composed of two strings - street and postcode . View I have a ListBox whose item source need to be set to ViewModels's KeyMember property and it should display the Street of all the Past Addresses in the collection. Question My ViewModel and View relationship is established properly. I am able to write a data template for the above simple case as below <ListBox ItemsSource="{Binding KeyMember.Addresses}"> <ListBox.ItemTemplate> <DataTemplate DataType="Address"> <TextBlock Text="{Binding Street}"/> </DataTemplate> </ListBox.ItemTemplate> </ListBox> How would I write the DataTemplate if I change KeyMember from type Member to ObservableCollection< Member assuming that the collection has only one element. PS: I know that for multiple elements in collection, I will have to implement the Master-Detail pattern/scenario.

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  • ASP.net MVC 2 EditorFor Dictionary Bind

    - by user307540
    Hi! I try this, but don't work. bemutatkozas@Modify = null all the time. public class Iroda { public Dictionary<int,string> bemutatkozas { get; set; } } public ActionResult Index() { var dct = new Dictionary<int, string>(); dct.Add(1, "magyar"); dct.Add(2, "angol"); dct.Add(3, "olasz"); return View(new Iroda { bemutatkozas = dct }); } [HttpPost] public ActionResult Modify(Dictionary<int,string> bemutatkozas) { return View(); } <% using (Html.BeginForm("Modify","Iroda")) {%> <%= Html.ValidationSummary(true) %> <fieldset> <legend>Fields</legend> <%= Html.EditorFor(o=>o.bemutatkozas,"MultiLanguageEditor") %> <p> <input type="submit" value="Save" /> </p> </fieldset> <% } %> <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<Dictionary<int, string>>" %> <% int i = 0; %> <% foreach (var s in Model) { %> <%= Html.Hidden(Html.ViewContext.ViewData.TemplateInfo.HtmlFieldPrefix+"["+i+"].key", s.Key) %> <%= Html.TextBox(Html.ViewContext.ViewData.TemplateInfo.HtmlFieldPrefix+"["+i+"].value",s.Value) %> <% i++; %> <% }%> Whats the solution? Thx!

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  • Problem facing to run ruport from other machine

    - by shabi
    I am using SQL Server 2008 Reporting Services and set mode remotely. All is going fine and reports running on my machine. I am not using report viewer control, but switch to browser. Problem is that when I access the report from any other system in browser by providing required url. I m getting the following premission error: Server Error in /ReportServer Application. Access is denied: Description: An error is occured while accessing the resources required to serve for this request. You might have not premission to view the requested resources. Error message: 401.3 : You dont have the premission to view this directory or page using the creditinals you supplied. I have go through all step of this article "http://msdn.microsoft.com/en-us/library/ms365170.aspx" and set remotly premession but after all changes no success and getting same error. Please some one can tell me or provide step list, that how can I set the premession? that the report can run from other machine. Quick and detail response will

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  • Datatemplate binding

    - by Lasse O
    How can i achieve something like this: <ListView Name="OverviewTitlesListView" ItemsSource="{Binding OverviewTitlesCollection}"> <ListView.View> <GridView> <GridViewColumn Header="Index" Width="60" DisplayMemberBinding="{Binding TitleIndex}"/> <GridViewColumn Header="Start Time" Width="100" DisplayMemberBinding="{Binding StartTime}"/> <GridViewColumn Header="End Time" Width="100" DisplayMemberBinding="{Binding EndTime}"/> <GridViewColumn Header="Title Text" Width="550" DisplayMemberBinding="{Binding Text}"/> <GridViewColumn Header="Approved" Width="80"> <GridViewColumn.CellTemplate> <DataTemplate> <TextBlock Name="Test"/> <DataTemplate.Triggers> <Trigger Property="{Binding IsApproved}" Value="true"> <Setter TargetName="Test" Property="Text" Value="Approved"/> </Trigger> <Trigger Property="{Binding IsApproved}" Value="false"> <Setter TargetName="Test" Property="Text" Value="Not Approved"/> </Trigger> </DataTemplate.Triggers> </DataTemplate> </GridViewColumn.CellTemplate> </GridViewColumn> </GridView> </ListView.View> </ListView> When IsApproved property changes on my object in OverviewTitlesCollection i want to control the text of the TextBlock. How can i control this by triggers in my datatemplate?

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  • Windows Mobile : How to bind dropdown's selectedvalue to a column in table A and the list data to a

    - by Rob
    Hi, I am trying to learn the basics of Windows Mobile development against SQL CE and have come across a basic problem. I have two tables. One called Customers that stores customer info and has an identity column called ID as the primary key. The other table is called Orders which has a column called CustomerID (the FK constraint is present). I have added a DataSet to the project that contains both tables and have autogenerated the edit/view forms. This has produced a text control for the CustomerID column in the Order table for the new/edit form and I deleted it and replaced it with a dropdown list. Then, using the 'Advanced' databinding options (in Properties) I set the datasource of the list to the Customers table setting the value to the ID field and the text to the CustomerName field. I then set the SelectedValue of the list box to the CustomerID field of the Orders dataset. So far so good. When I run the app in the emulator and view the 'New' form for Orders the Customer dropdown is indeed populated with a list of customer names and I can select one and happily create a new order successfully. This is confirmed when I see the order appear in the Orders Grid form. However, when I then click on the order in the grid and then select 'Edit' the order loads but the dropdown always shows the first customer in the list and doesn't seem to bind the SelectedValue to the Orders dataset CustomerID field. Now I am an ASP.NET guy and normally hand craft the DAL and it's binding to the UI so I'm not entirely sure where to look to investigate what is going wrong here as this is all generated code. I am sure it is something very trivial but any pointers would be appreciated. My gut feeling is that the SelectedValue and the Customers.CustomerID values do not match for some reason? Many thanks, Rob.

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  • iPhone Core Data does not refresh table

    - by Brian515
    Hi all, I'm trying to write an application with Core Data, and I have been able to successfully read and write to the core data database. However, if I write to the database in one view controller, my other view controllers will not see the change until the app is closed then reopened again. This is really frustrating. I'm not entirely sure how to get the refresh - (void)refreshObject:(NSManagedObject *)object mergeChanges:(BOOL)flag method to work. How do I get a reference to my managed object? Anyways, here's the code I'm using to read the data back. This is in the viewDidLoad method. NSFetchRequest *request = [[NSFetchRequest alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"Website" inManagedObjectContext:managedObjectContext]; [request setEntity:entity]; NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"siteName" ascending:NO]; NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:sortDescriptor, nil]; [request setSortDescriptors:sortDescriptors]; [sortDescriptor release]; [sortDescriptors release]; NSError *error = nil; NSMutableArray *mutableFetchResults = [[managedObjectContext executeFetchRequest:request error:&error] mutableCopy]; if(mutableFetchResults == nil) { //Handle the error } [self setNewsTitlesArray:mutableFetchResults]; [mutableFetchResults release]; [request release]; [newsSourcesTableView reloadData]; Thanks for help in advance!

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  • [iOS] becomeFirstResponder: automatically scroll to the UIControl that becomes first responder

    - by Manni
    I have a grouped UITableViewController with one section and many rows. Each cell consists of two elements: a UILabel with a description and a UITextField for an input. A form, I would say. On the bottom is a button "Next" the go to the next view. But before that, I validate the UITextField's: if the user hasn't filled a field, this field should get the focus, so that the user sees that he needs to enter something. I tried with this: [inputField becomeFirstResponder]; Remember, the button I pressed is on the bottom of my view and imagine that the UITextField is on the top. In this situation, the field doesn't get the focus because it is too far away. Now when I scroll up slowly and the field gets visible, the field becomes first responder and gets the cursor :-) Conclusion: The becomeFirstResponder worked, but does not exactly do what I wanted to. I don't want to scroll up with my finger, the field should get the focus and visible automatically. Is there any way to "jump" directly to my field? Use an alternative to becomeFirstResponder? Scroll to my field automatically? Thanks for your help!

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  • Rails - Debugging Nested Routes

    - by stringo0
    Hi, I have 2 models, Assessments and Questions. Assessments have many questions. In routes, I have: map.resources :assessments, :has_many => :questions map.root :assessments I checked rake routes, it's as expected On the form to create a new question, I get the following error: undefined method `questions_path' for #<ActionView::Base:0x6d3cdb8> If I take out the form, the view loads fine, so I think it's something with the code in this view - I'm getting the error on the form_for line: <h1>New question</h1> <% form_for [@assessment, @question] do |f| %> <%= f.error_messages %> <p> <%= f.label :content %><br /> <%= f.text_field :content %> </p> <p> <%= f.submit 'Create' %> </p> <% end %> <%= link_to 'Cancel', assessment_path(@assessment) %> Link to rake routes, if needed - http://pastebin.com/LxjfmXQw Can anyone help me debug it? Thanks!

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  • How to make images hosted on Amazon S3 less public but not completely private?

    - by Jay Godse
    I fired up a sample application that uses Amazon S3 for image hosting. I managed to coax it into working. The application is hosted at github.com. The application lets you create users with a profile photo. When you upload the photo, the web application stores it on Amazon S3 instead of your local file system. (Very important if you host at heroku.com) However, when I did a "view source" in the browser of the page I noticed that the URL of the picture was an Amazon S3 URL in the S3 bucket that I assigned to the app. I cut & pasted the URL and was able to view the picture in the same browser, and in in another browser in which I had no open sessions to my web app or to Amazon S3. Is there any way that I could restrict access to that URL (and image) so that it is accessible only to browsers that are logged into my applications? Most of the information I found about Amazon ACLs only talk about access for only the owner or to groups of users authenticated with Amazon or AmazonS3, or to everybody anonymously.

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  • How to structure applications as multiple projects an name the packages in Java

    - by lostiniceland
    Hello Everyone I would like to know how you set up your projects in Java For example, in my current work-project, a six year old J2EE app with approximately 2 million LoC, we only have one project in Eclipse. The package structure is split into tiers and then domains, so it follows guidelines from Sun/Oracle. A huge ant-script is building different jars out of this one source-folder Personally I think it would be better to have multiple projects, at least for each tier. Recently I was playing around with a projects-structure like this: Domainproject (contains only annotated pojos, needed by all other projects) Datalayer (only persistence) Businesslogic (services) Presenter View This way, it should be easier to exchange components and when using a build tool like Maven I can have everything in a repository so when only working on the frontend I can get the rest as a dependecy in my classpath. Does this makes sense to you? Do you use different approaches and how do they look like? Furthermore I am struggeling how to name my packages/projects correctly. Right now, the above project-structure reflects in the names of the packages, eg. de.myapp.view and it continues with some technical subfolders like internal or interfaces. What I am missing here, and I dont know how to do this properly, is the distinction to a certain domain. When the project gets bigger it would be nice to recognise a particular domain but also the technical details to navigate more easily within the project. This leads to my second question: how do you name your projects and packages?

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  • Class 'org.springframework.http.converter.ResourceHttpMessageConverter' not found - how to correct?

    - by Ash Kim
    Eclipse STS is reporting I have problem with my spring project. It's a fresh project generated from the Spring Web MVC Project Template (File-New-Spring Template Project-Spring Web MVC ). When I create the project it has no problems - it's only once I modify the pom (by adding the hibernate dependencies) that STS then picks up the spring problem. Strangely if I revert the pom the problem remains. Also I can run the project on a spring tc server and all works correctly. Any ideas how I can satisfy this problem report? "Class 'org.springframework.http.converter.ResourceHttpMessageConverter' not found" mvc-config.xml /src/main/webapp/WEB-INF/spring line 9 Spring Beans Problem mvc-config.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd"> <mvc:annotation-driven /> <!-- <= PROBLEMATIC LINE REPORTED BY STS --> <!-- Resolves view names to protected .jsp resources within the /WEB-INF/views directory --> <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="prefix" value="/WEB-INF/views/"/> <property name="suffix" value=".jsp"/> </bean> </beans>

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  • NSArrayController not working with NSMutableDictionary for NSTableView

    - by Miraaj
    Hi all, I am trying to display content in NSTableView using NSMutableArrayController of NSMutableDictionary records. I followed steps written below: In application delegate class, I created an NSMutableArray object with name 'geniuses' and stored some NSMutableDictionary objects with keys: 'geniusName' and 'domain'. I took an NSArrayController object in IB, binded its controller content property to application delegate class, and set its model key path to 'geniuses'. In attribute inspector pane set mode as class and class name as NSMutableDictionary. Added keys: 'geniusName' and 'domain' to it. In IB I took a table view object. Binded its content property to array controller, controller key path set as arranged objects. Binded value property of its first column to array controller, controller key path set as arranged objects, model key path set as 'geniusName'. Binded value property of its second column to array controller, controller key path set as arranged objects, model key path set as 'geniusName'. After following these steps when I tried to build and run the project I found un-populated table view. You can find my code here. Can anyone suggest me where I may be wrong? Thanks, Miraaj

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  • Passing data between ViewControllers versus doing local Fetch in each VC

    - by Tofrizer
    Hi All, I'm developing an iPhone app using Core Data and I'm looking for some general advice and recommendations on whether its acceptable to pass data between ViewControllers versus doing a local fetch in each ViewController as you navigate to it. Ordinarily I would say it all depends on various factors (e.g. performance etc) but the passing data approach is so prevalent in my app and I'm spooked by all the stories about Apple rejecting apps because of not conforming to their standard guidelines. So let me put another way -- is it non-standard to pass data between VC's? The reason I pass data so much is because each ViewController is just another view on to data present in my object model / graph. Once I have a handle on my first object in the first view controller (which I of course do have to fetch), I can use the existing object composition / relationships to drill down into the next level of detail into data and so I just pass these objects to the next VC. Separately, one possible downside with this passing-data-to-each-VC approach is I don't benefit from (what I perceive to be) the optimisation/benefits that NSFetchedResultsController provides in terms of efficient memory usage and section handling. My app is read-only but I do have one table with 5000 rows and I'm curious if I am missing out on NSFetchedResultsController benefits. Any thoughts on this as well? Can I somehow still benefit from NSFetchedResultsController goodness without having to do a full fetch (as I would have already passed in the data from my previous VC)? Thanks a lot.

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  • Warning: Cannot modify header information - headers already sent

    - by Pankaj Khurana
    Hi, I am using code available on http://www.forosdelweb.com/f18/zip-lib-php-archivo-zip-vacio-431133/ for creating zip file. First file-zip.lib.php <?php /* $Id: zip.lib.php,v 1.1 2004/02/14 15:21:18 anoncvs_tusedb Exp $ */ // vim: expandtab sw=4 ts=4 sts=4: /** * Zip file creation class. * Makes zip files. * * Last Modification and Extension By : * * Hasin Hayder * HomePage : www.hasinme.info * Email : [email protected] * IDE : PHP Designer 2005 * * * Originally Based on : * * http://www.zend.com/codex.php?id=535&single=1 * By Eric Mueller <[email protected]> * * http://www.zend.com/codex.php?id=470&single=1 * by Denis125 <[email protected]> * * a patch from Peter Listiak <[email protected]> for last modified * date and time of the compressed file * * Official ZIP file format: http://www.pkware.com/appnote.txt * * @access public */ class zipfile { /** * Array to store compressed data * * @var array $datasec */ var $datasec = array(); /** * Central directory * * @var array $ctrl_dir */ var $ctrl_dir = array(); /** * End of central directory record * * @var string $eof_ctrl_dir */ var $eof_ctrl_dir = "\x50\x4b\x05\x06\x00\x00\x00\x00"; /** * Last offset position * * @var integer $old_offset */ var $old_offset = 0; /** * Converts an Unix timestamp to a four byte DOS date and time format (date * in high two bytes, time in low two bytes allowing magnitude comparison). * * @param integer the current Unix timestamp * * @return integer the current date in a four byte DOS format * * @access private */ function unix2DosTime($unixtime = 0) { $timearray = ($unixtime == 0) ? getdate() : getdate($unixtime); if ($timearray['year'] < 1980) { $timearray['year'] = 1980; $timearray['mon'] = 1; $timearray['mday'] = 1; $timearray['hours'] = 0; $timearray['minutes'] = 0; $timearray['seconds'] = 0; } // end if return (($timearray['year'] - 1980) << 25) | ($timearray['mon'] << 21) | ($timearray['mday'] << 16) | ($timearray['hours'] << 11) | ($timearray['minutes'] << 5) | ($timearray['seconds'] >> 1); } // end of the 'unix2DosTime()' method /** * Adds "file" to archive * * @param string file contents * @param string name of the file in the archive (may contains the path) * @param integer the current timestamp * * @access public */ function addFile($data, $name, $time = 0) { $name = str_replace('', '/', $name); $dtime = dechex($this->unix2DosTime($time)); $hexdtime = 'x' . $dtime[6] . $dtime[7] . 'x' . $dtime[4] . $dtime[5] . 'x' . $dtime[2] . $dtime[3] . 'x' . $dtime[0] . $dtime[1]; eval('$hexdtime = "' . $hexdtime . '";'); $fr = "\x50\x4b\x03\x04"; $fr .= "\x14\x00"; // ver needed to extract $fr .= "\x00\x00"; // gen purpose bit flag $fr .= "\x08\x00"; // compression method $fr .= $hexdtime; // last mod time and date // "local file header" segment $unc_len = strlen($data); $crc = crc32($data); $zdata = gzcompress($data); $zdata = substr(substr($zdata, 0, strlen($zdata) - 4), 2); // fix crc bug $c_len = strlen($zdata); $fr .= pack('V', $crc); // crc32 $fr .= pack('V', $c_len); // compressed filesize $fr .= pack('V', $unc_len); // uncompressed filesize $fr .= pack('v', strlen($name)); // length of filename $fr .= pack('v', 0); // extra field length $fr .= $name; // "file data" segment $fr .= $zdata; // "data descriptor" segment (optional but necessary if archive is not // served as file) $fr .= pack('V', $crc); // crc32 $fr .= pack('V', $c_len); // compressed filesize $fr .= pack('V', $unc_len); // uncompressed filesize // add this entry to array $this -> datasec[] = $fr; // now add to central directory record $cdrec = "\x50\x4b\x01\x02"; $cdrec .= "\x00\x00"; // version made by $cdrec .= "\x14\x00"; // version needed to extract $cdrec .= "\x00\x00"; // gen purpose bit flag $cdrec .= "\x08\x00"; // compression method $cdrec .= $hexdtime; // last mod time & date $cdrec .= pack('V', $crc); // crc32 $cdrec .= pack('V', $c_len); // compressed filesize $cdrec .= pack('V', $unc_len); // uncompressed filesize $cdrec .= pack('v', strlen($name) ); // length of filename $cdrec .= pack('v', 0 ); // extra field length $cdrec .= pack('v', 0 ); // file comment length $cdrec .= pack('v', 0 ); // disk number start $cdrec .= pack('v', 0 ); // internal file attributes $cdrec .= pack('V', 32 ); // external file attributes - 'archive' bit set $cdrec .= pack('V', $this -> old_offset ); // relative offset of local header $this -> old_offset += strlen($fr); $cdrec .= $name; // optional extra field, file comment goes here // save to central directory $this -> ctrl_dir[] = $cdrec; } // end of the 'addFile()' method /** * Dumps out file * * @return string the zipped file * * @access public */ function file() { $data = implode('', $this -> datasec); $ctrldir = implode('', $this -> ctrl_dir); return $data . $ctrldir . $this -> eof_ctrl_dir . pack('v', sizeof($this -> ctrl_dir)) . // total # of entries "on this disk" pack('v', sizeof($this -> ctrl_dir)) . // total # of entries overall pack('V', strlen($ctrldir)) . // size of central dir pack('V', strlen($data)) . // offset to start of central dir "\x00\x00"; // .zip file comment length } // end of the 'file()' method /** * A Wrapper of original addFile Function * * Created By Hasin Hayder at 29th Jan, 1:29 AM * * @param array An Array of files with relative/absolute path to be added in Zip File * * @access public */ function addFiles($files /*Only Pass Array*/) { foreach($files as $file) { if (is_file($file)) //directory check { $data = implode("",file($file)); $this->addFile($data,$file); } } } /** * A Wrapper of original file Function * * Created By Hasin Hayder at 29th Jan, 1:29 AM * * @param string Output file name * * @access public */ function output($file) { $fp=fopen($file,"w"); fwrite($fp,$this->file()); fclose($fp); } } // end of the 'zipfile' class ?> My second file newzip.php <? include("zip.lib.php"); $ziper = new zipfile(); $ziper->addFiles(array("index.htm")); //array of files // the next three lines force an immediate download of the zip file: header("Content-type: application/octet-stream"); header("Content-disposition: attachment; filename=test.zip"); echo $ziper -> file(); ?> I am getting this warning while executing newzip.php Warning: Cannot modify header information - headers already sent by (output started at E:\xampp\htdocs\demo\zip.lib.php:233) in E:\xampp\htdocs\demo\newzip.php on line 6 I am unable to figure out the reason for the same. Please help me on this. Thanks

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