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  • How can I merge two lists and sort them working in 'linear' time?

    - by Sergio Tapia
    I have this, and it works: # E. Given two lists sorted in increasing order, create and return a merged # list of all the elements in sorted order. You may modify the passed in lists. # Ideally, the solution should work in "linear" time, making a single # pass of both lists. def linear_merge(list1, list2): finalList = [] for item in list1: finalList.append(item) for item in list2: finalList.append(item) finalList.sort() return finalList # +++your code here+++ return But, I'd really like to learn this stuff well. :) What does 'linear' time mean?

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  • Import Error: No module named testrunner

    - by JiL
    I followed this to add zc.recipe.testrunner to my buildout. I can run buildout successfully but when I run bin/test, I get: ImportError: No module named testrunner I have zope.testrunner-4.0.4-py2.4.egg in /usr/local/lib/python2.4/site-packages I also pinned zope.testrunner = 4.0.4 zc.recipe.testruner = 1.4.0 zc.recipe.egg = 1.3.2 When I ran buildout, I used -vvv and I got: ... Installing 'zc.recipe.testrunner'. We have the distribution that satisfies 'zc.recipe.testrunner==1.4.0'. Egg from site-packages: z3c.recipe.scripts 1.0.1 Egg from site-packages: zope.testrunner 4.0.4 Egg from site-packages: zope.interface 3.8.0 Egg from site-packages: zope.exceptions 3.7.1 ... We have the distribution that satisfies 'zope.testrunner==4.0.4'. Egg from site-packages: zope.testrunner 4.0.4 Adding required 'zope.interface' required by zope.testrunner 4.0.4. We have a develop egg: zope.interface 0.0 Adding required 'zope.exceptions' required by zope.testrunner 4.0.4. We have a develop egg: zope.exceptions 0.0 ... Why is it I get an ImportError? Is zope.testrunner not installed correctly?

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  • Why do all module run together?

    - by gunbuster363
    I just made a fresh copy of eclipse and installed pydev. In my first trial to use pydev with eclipse, I created 2 module under the src package(the default one) FirstModule.py: ''' Created on 18.06.2009 @author: Lars Vogel ''' def add(a,b): return a+b def addFixedValue(a): y = 5 return y +a print "123" run.py: ''' Created on Jun 20, 2011 @author: Raymond.Yeung ''' from FirstModule import add print add(1,2) print "Helloword" When I pull out the pull down menu of the run button, and click "ProjectName run.py", here is the result: 123 3 Helloword Apparantly both module ran, why? Is this the default setting?

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  • Can pydoc/help hide the documentation for inherited class methods and attributes?

    - by EOL
    When declaring a class that inherits from a specific class: class C(dict): added_attribute = 0 the documentation for C lists all the methods of dict (either through help(C) or pydoc). Is there a way to hide the inherited methods from the automatically generated documentation (the documentation string can refer to the base class, for non-overwritten methods)? This would be useful: pydoc lists the functions defined in a module after its classes. Thus, when the classes have a very long documentation, a lot of less than useful information is printed before the new functions provided by the module are presented, which makes the documentation harder to exploit (you have to skip all the documentation for the inherited methods until you reach something specific to the module being documented).

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  • MUD (game) design concept question about timed events.

    - by mudder
    I'm trying my hand at building a MUD (multiplayer interactive-fiction game) I'm in the design/conceptualizing phase and I've run into a problem that I can't come up with a solution for. I'm hoping some more experienced programmers will have some advice. Here's the problem as best I can explain it. When the player decides to perform an action he sends a command to the server. the server then processes the command, determines whether or not the action can be performed, and either does it or responds with a reason as to why it could not be done. One reason that an action might fail is that the player is busy doing something else. For instance, if a player is mid-fight and has just swung a massive broadsword, it might take 3 seconds before he can repeat this action. If the player attempts to swing again to soon, the game will respond indicating that he must wait x seconds before doing that. Now, this I can probably design without much trouble. The problem I'm having is how I can replicate this behavior from AI creatures. All of the events that are being performed by the server ON ITS OWN, aka not as an immediate reaction to something a player has done, will have to be time sensitive. Some evil monster has cast a spell on you but must wait 30 seconds before doing it again... I think I'll probably be adding all these events to some kind of event queue, but how can I make that event queue time sensitive?

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  • Problem with Django styling

    - by Brob
    Hi new to django but I'm having issues with the styling of pages. my settings.py contains MEDIA_ROOT = '' MEDIA_URL = '' TEMPLATE_DIRS = ( os.path.join(os.path.dirname(__file__), 'templates'), ) please can someone help me shed some light on what I need to do to get the styles working in my templates Thanks

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  • what would be a frozen dict ?

    - by dugres
    A frozen set is a frozenset. A frozen list could be a tuple. What would be a frozen dict ? An immutable, hashable dict. I guess it could be something like collections.namedtuple, but namedtuple is more like a frozenkeys dict (an half-frozen dict). No ?

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  • Is there a functional way to do this?

    - by Ishpeck
    def flattenList(toFlatten): final=[] for el in toFlatten: if isinstance(el, list): final.extend(flattenList(el)) else: final.append(el) return final When I don't know how deeply the lists will nest, this is the only way I can think to do this. 2

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  • How to test custom handler500?

    - by Gr1N
    I write my handler for server errors and define it at root urls.py: handler500 = 'myhandler' And I want to write unittest for testing how it works. For testing I write view with error and define it in test URLs configuration, when I make request to this view in browser I see my handler and receive status code 500, but when I launch test that make request to this view I see stack trace and my test failed. Have you some ideas for testing handler500 by unittests?

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  • Creating a Group of Groups in Django

    - by Greg
    I'm creating my own Group model; I'm not referring to the builtin Group model. I want each hroup to be a member of another group (it's parent), but there is the one "top" group that doesn't have a parent group. The admin interface won't let me create a group without entering a parent. I get the error personnel_group.parent_id may not be NULL. My Group model looks like this: class Group(models.Model): name = models.CharField(max_length=50) parent = models.ForeignKey('self', blank=True, null=True) order = models.IntegerField() icon = models.ImageField(upload_to='groups', blank=True, null=True) description = models.TextField(blank=True, null=True) How can I accomplish this? Thanks.

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  • Trying and expand the contrib.auth.user model and add a "relatipnships" manage

    - by dotty
    I have the following model setup. from django.db import models from django.contrib.auth.models import User class SomeManager(models.Manager): def friends(self): # return friends bla bla bla class Relationship(models.Model): """(Relationship description)""" from_user = models.ForeignKey(User, related_name='from_user') to_user = models.ForeignKey(User, related_name='to_user') has_requested_friendship = models.BooleanField(default=True) is_friend = models.BooleanField(default=False) objects = SomeManager() relationships = models.ManyToManyField(User, through=Relationship, symmetrical=False) relationships.contribute_to_class(User, 'relationships') Here i take the User object and use contribute_to_class to add 'relationships' to the User object. The relationship show up, but if call User.relationships.friends it should run the friends() method, but its failing. Any ideas how i would do this? Thanks

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  • Optimization of Function with Dictionary and Zip()

    - by eWizardII
    Hello, I have the following function: def filetxt(): word_freq = {} lvl1 = [] lvl2 = [] total_t = 0 users = 0 text = [] for l in range(0,500): # Open File if os.path.exists("C:/Twitter/json/user_" + str(l) + ".json") == True: with open("C:/Twitter/json/user_" + str(l) + ".json", "r") as f: text_f = json.load(f) users = users + 1 for i in range(len(text_f)): text.append(text_f[str(i)]['text']) total_t = total_t + 1 else: pass # Filter occ = 0 import string for i in range(len(text)): s = text[i] # Sample string a = re.findall(r'(RT)',s) b = re.findall(r'(@)',s) occ = len(a) + len(b) + occ s = s.encode('utf-8') out = s.translate(string.maketrans("",""), string.punctuation) # Create Wordlist/Dictionary word_list = text[i].lower().split(None) for word in word_list: word_freq[word] = word_freq.get(word, 0) + 1 keys = word_freq.keys() numbo = range(1,len(keys)+1) WList = ', '.join(keys) NList = str(numbo).strip('[]') WList = WList.split(", ") NList = NList.split(", ") W2N = dict(zip(WList, NList)) for k in range (0,len(word_list)): word_list[k] = W2N[word_list[k]] for i in range (0,len(word_list)-1): lvl1.append(word_list[i]) lvl2.append(word_list[i+1]) I have used the profiler to find that it seems the greatest CPU time is spent on the zip() function and the join and split parts of the code, I'm looking to see if there is any way I have overlooked that I could potentially clean up the code to make it more optimized, since the greatest lag seems to be in how I am working with the dictionaries and the zip() function. Any help would be appreciated thanks!

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  • Tkinter mouse event initially triggered

    - by user3714884
    I'm currently learning Tkinter and I cannot find a solution for my problem here nor outside Stackoverflow. In a nutshell, all events that I bind to my widgets are triggered initialy and don't respond to my actions. In this example, the red rectangle appears on the canvas when I run the code, and color=random.choice(['red', 'blue']) revealed that the event binding doesn't work after that: import Tkinter as tk class application(tk.Frame): def __init__(self, master=None): tk.Frame.__init__(self, master) self.can = tk.Canvas(master, width=200, height=200) self.can.bind('<Button-2>', self.draw()) self.can.grid() def draw(self): self.can.create_rectangle(50, 50, 100, 100, fill='red') app = application() app.mainloop() I use a Mac platform, but I haven't got a clue about its role in the problem. Could anyone please point me at the mistake i did here?

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  • Paramiko ssh output stops at --more--

    - by Anesh
    The output stops printing at --more-- any idea how to get the end of the output >>> import paramiko >>> ssh = paramiko.SSHClient() >>> ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy()) >>> conn=ssh.connect("ipaddress",username="user", password="pass") >>> channel = ssh.invoke_shell() >>> channel.send("en\n") 3 >>> channel.send("password\n") 9 >>> channel.send("show security local-user-list\n") 30 >>> results = '' >>> channel.send("\n") 1 >>> results += channel.recv(5000) >>> print results bluecoat>en Password: bluecoat#show security local-user-list Default List: local_user_database Append users loaded from file to default list: false local_user_database Lockout parameters: Max failed attempts: 60 Lockout duration: 3600 Reset interval: 7200 Users: Groups: admin_local Lockout parameters: Max failed attempts: 60 Lockout duration: 3600 Reset interval: 7200 Users: <username> Hashed Password: Enabled: true Groups: <username> Hashed Password: Enabled: true **--More--** As you can see above the output stops printing at --more-- any idea how to get the output to print till the end.

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  • Django complex queries

    - by Josh K
    I need to craft a filter for an object that checks date ranges. Right now I'm performing a very inefficient loop which checks all the objects. I would like to simplify this to a database call. The logic is you have a start and an end date objects. I need to check if the start OR the end is within the range of an appointment. if (start >= appointment.start && start < appointment.end) || (end > appointment.start && end <= appointment.end) I could do this in SQL, but I'm not as familiar with the Django model structure for more complex queries.

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  • how to detect escape characters in a string

    - by mix
    Given a string named line whose raw version has this value: \rRAWSTRING how can I detect if it has the escape character \r? What I've tried is: if repr(line).startswith('\r'): blah... but it doesn't catch it. I also tried find, such as: if repr(line).find('\r') != -1: blah doesn't work either. What am I missing? thx!

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  • beautifulsoup can't find exist href in file

    - by young001
    I have a html file like following: <form action="/2811457/follow?gsid=3_5bce9b871484d3af90c89f37" method="post"> <div> <a href="/2811457/follow?page=2&amp;gsid=3_5bce9b871484d3af90c89f37">next_page</a> &nbsp;<input name="mp" type="hidden" value="3" /> <input type="text" name="page" size="2" style='-wap-input-format: "*N"' /> <input type="submit" value="jump" />&nbsp;1/3 </div> </form> how to extract the "1/3" from the file? It is a part of html,I intend to make it clear. When I use beautifulsoup, I'm new to beautifulsoup,and I have look the document,but still confused. how to extract"1/3" from the html file? total_urls_num = soup.find(re.compile('.*/d\//d.*')) doesn't work As JBernardo said,\d should be a number,When I change to .*\d/\d.*,it doesn't work too. my code: from BeautifulSoup import BeautifulSoup import re with open("html.txt","r") as f: response = f.read() print response soup = BeautifulSoup(response) delete_urls = soup.findAll('a', href=re.compile('follow\?page')) #works print delete_urls #total_urls_num = soup.find(re.compile('.*\d/\d.*')) total_urls_num = soup.find('input',style='submit') #can't work print total_urls_num

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  • Why doesn't this list comprehension do what I expect it to do?

    - by Az
    The original list project_keys = sorted(projects.keys()) is [101, 102, 103, 104, 105, 106, 107, 108, 109, 110] where the following projects were deemed invalid this year: 108, 109, 110. Thus: for project in projects.itervalues(): # The projects dictionary is mapped to the Project class if project.invalid: # Where invalid is a Bool parameter in the Project class project_keys.remove(project.proj_id) print project_keys This will return a list of integers (which are project id's) as such: [101, 102, 103, 104, 105, 106, 107] Sweet. Now, I wanted it try the same thing using a list comprehension. project_keys = [project_keys.remove(project.proj_id) for project in projects.itervalues() if project.invalid print project_keys This returns: [None, None, None] So I'm populating a list with the same number as the removed elements but they're Nones? Can someone point out what I'm doing wrong? Additionally, why would I use a list comprehension over the for-if block at the top? Conciseness? Looks nicer?

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