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  • strange Django problem

    - by Pounds
    Sorrt to bother you everyone, but I really suffer a strange problem. I am working on a Django project for a company. This project worked very well before today. Today I found a page can not show images (and their corrsponding links). I checked source code of THAT PAGE, I found there are images and links, I just can not find them on the page. I checked the auth of the server and I am sure I can write things to the database. In fact, I think it is not database mistake because I can find what I want in the page source code, I just can not find them on the page. Oh my Gosh, I am going to be crazy... Has anyone suffered similar problem? What kind of problem could it be? Please help me! Thank you very much! PS: I can not provide any source code of the project because some business limit...I am really sorry...

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  • Filtering with joined tables

    - by viraptor
    I'm trying to get some query performance improved, but the generated query does not look the way I expect it to. The results are retrieved using: query = session.query(SomeModel). options(joinedload_all('foo.bar')). options(joinedload_all('foo.baz')). options(joinedload('quux.other')) What I want to do is filter on the table joined via 'first', but this way doesn't work: query = query.filter(FooModel.address == '1.2.3.4') It results in a clause like this attached to the query: WHERE foos.address = '1.2.3.4' Which doesn't do the filtering in a proper way, since the generated joins attach tables foos_1 and foos_2. If I try that query manually but change the filtering clause to: WHERE foos_1.address = '1.2.3.4' AND foos_2.address = '1.2.3.4' It works fine. The question is of course - how can I achieve this with sqlalchemy itself?

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  • How do you automatically remove the preview window after autocompletion in Vim?

    - by Ben Davini
    I'm using omnifunc=pythoncomplete. When autocompleting a word (e.g., os.), I get the list of eligible class members and functions, as expected, as well as a scratch buffer preview window with documentation about the selected member or function. This is great, but after selecting the function I want, the preview window remains. I can get rid of it with ":pc", but I'd like it just to automatically disappear after I've selected my function, a la Eclipse. I've played around with "completeopt" but to no avail.

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  • Should I use a metaclass, class decorator, or override the __new__ method?

    - by 007brendan
    Here is my problem. I want the following class to have a bunch of property attributes. I could either write them all out like foo and bar, or based on some other examples I've seen, it looks like I could use a class decorator, a metaclass, or override the __new__ method to set the properties automagically. I'm just not sure what the "right" way to do it would be. class Test(object): def calculate_attr(self, attr): # do calculaty stuff return attr @property def foo(self): return self.calculate_attr('foo') @property def bar(self): return self.calculate_attr('bar')

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  • How to make pdb recognize that the source has changed between runs?

    - by user88028
    From what I can tell, pdb does not recognize when the source code has changed between "runs". That is, if I'm debugging, notice a bug, fix that bug, and rerun the program in pdb (i.e. without exiting pdb), pdb will not recompile the code. I'll still be debugging the old version of the code, even if pdb lists the new source code. So, does pdb not update the compiled code as the source changes? If not, is there a way to make it do so? I'd like to be able to stay in a single pdb session in order to keep my breakpoints and such. FWIW, gdb will notice when the program it's debugging changes underneath it, though only on a restart of that program. This is the behavior I'm trying to replicate in pdb.

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  • Access to field in extended flatpage in django

    - by Stanislav Feldman
    How to access field in extended flatpage in django? I wrote this: class ExtendedFlatPage(FlatPage): teaser = CharField(max_length=150) class ExtendedFlatPageForm(FlatpageForm): teaser = CharField(max_length=150) class Meta: model = ExtendedFlatPage class ExtendedFlatPageAdmin(FlatPageAdmin): form = ExtendedFlatPageForm fieldsets = ( (None, {'fields': ('url', 'title', 'teaser', 'content', 'sites',)}), ) admin.site.unregister(FlatPage) admin.site.register(ExtendedFlatPage, ExtendedFlatPageAdmin) And creation in admin is ok. But then in flatpages/default.html I tried this: <html> <body> <h1>{{ flatpage.title }}</h1> <strong>{{ flatpage.teaser }}</strong> <p>{{ flatpage.content }}</p> </body> </html> And there was no flatpage.teaser! What is wrong?

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  • google contacts api service account oauth2.0 sub user

    - by user3709507
    I am trying to use the Google Contacts API to connect to a user's contact information, on my Google apps domain. Generating an access_token using the gdata api's ContactsService clientlogin function while using the API key for my project works fine, but I would prefer to not store the user's credentials, and from the information I have found that method uses OAuth1.0 So, to use OAuth2.0 I have: Generated a Service Account in the developer's console for my project Granted access to the service account for the scope of https://www.google.com/m8/feeds/ in the Google apps domain admin panel Attempted to generate credentials using SignedJwtAssertionCredentials: credentials = SignedJwtAssertionCredentials( service_account_name=service_account_email, private_key=key_from_p12_file, scope='https://www.google.com/m8/feeds/', sub=user_email') The problem I am running into is that attempting to generate an access token using this method fails. It succeeds in generating the token when I remove the sub parameter, but then that token fails when I try to fetch the user's contacts. Does anyone know why this might be happening?

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  • Where is the help.py for Android's monkeyrunner

    - by Keyboardsurfer
    Hi, I just can't find the help.py file in order to create the API reference for the monkeyrunner. The command described at the Android references monkeyrunner <format> help.py <outfile> does not work when i call monkeyrunner html help.py /path/to/place/the/doc.html. It's quite obvious that the help.py file is not found and the monkeyrunner also tells me "Can't open specified script file". But a locate on my system doesn't bring me a help.py file that has anything to do with monkeyrunner or Android. So my question is: Where did they hide the help.py file for creating the API reference?

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  • Google App Engine getting verbose_name of a property from an instance

    - by Brian M. Hunt
    Given a model likeso: from google.appengine.ext import db class X(db.Model): p = db.StringProperty(verbose_name="Like p, but more modern.") How does one access verbose_name from x=X() (an instance of X)? One might expect that x.p.verbose_name would work, or alternatively x.properties()['p'].verbose_name, but neither seems to work. Thanks! EDIT: x.name.verbose_name = x.p.verbose_name

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  • What did I do wrong with this function?

    - by Felipe Galdino Campos
    I don't know what I did - it's wrong . Can someone help me? def insert_sequence(dna1, dna2, number): '''(str, str, int) -> str Return the DNA sequence obtained by inserting the second DNA sequence at the given index. (You can assume that the index is valid.) >>> insert_sequence('CCGG', 'AT', 2) 'CCATGG' >>> insert_sequence('TTGC', 'GG', 2) 'TTGGGC' ''' index = 0 result = ''; for string in dna1: if index == number: result = result + dna2 result = result + string index += 1 print(result)

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  • Detect if 2 HTML fragments have identical hierarchical structure

    - by sergzach
    An example of fragments that have identical hierarchical structure: (1) <div> <span>It's a message</span> </div> (2) <div> <span class='bold'>This is a new text</span> </div> An example of fragments that have different structure: (1) <div> <span><b>It's a message</b></span> </div> (2) <div> <span>This is a new text</span> </div> So, fragments with a similar structure correspond to one hierarchical tree (the same tag names, the same hierarchical structure). How can I detect if 2 elements (html fragments) have the same structure simply with lxml? I have a function that does not work properly for some more difficult case (than the example): def _is_equal( el1, el2 ): # input: 2 elements with possible equal structure and tag names # e.g. root = lxml.html.fromstring( buf ) # el1 = root[ 0 ] # el2 = root[ 1 ] # move from top to bottom, compare elements result = False if el1.tag == el2.tag: # has no children if len( el1 ) == len( el2 ): if len( el1 ) == 0: return True else: # iterate one of them, for example el1 i = 0 for child1 in el1: child2 = el2[ i ] is_equal2 = _is_equal( child1, child2 ) if not is_equal2: return False return True else: return False else: return False The code fails to detect that 2 divs with class='tovar2' have an identical structure: <body> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333193003"> ?????? ?/? </a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333193003,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b> 3 150 </b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"><input value="" type="submit"> </li> </ul> </form> </div> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333124803">?????? ?/?</a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333124803,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b>3 150</b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"> <input value="" type="submit"> </li> </ul> </form> </div> </body>

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  • scraping blog contents

    - by goh
    Hi lads, After obtaining the urls for various blogspots, tumblr and wordpress pages, I faced some problems processing the html pages. The thing is, i wish to distinguish between the content,title and date for each blog post. I might be able to get the date through regex, but there are so many custom scripts people are using now that the html classes and structure is so different. Does anyone has a solution that may help?

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  • How to check wether a path represented by a QString with german umlauts exists?

    - by MB
    Hey, i get a QString which represents a directory from a QLineEdit. Now i want to check wether a certain file exists in this directory. But if i try this with os.path.exists and os.path.join and get in trouble when german umlauts occur in the directory path: #the direcory coming from the user input in the QLineEdit #i take this QString to the local 8-Bit encoding and then make #a string from it target_dir = str(lineEdit.text().toLocal8Bit()) #the file name that should be checked for file_name = 'some-name.txt' #this fails with a UnicodeDecodeError when a umlaut occurs in target_dir os.path.exists(os.path.join(target_dir, file_name)) How would you check if the file exists, when you might encounter german umlauts?

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  • Django extending user model and displaying form

    - by MichalKlich
    Hello, I am writing website and i`d like to implement profile managment. Basic thing would be to edit some of user details by themself, like first and last name etc. Now, i had to extend User model to add my own stuff, and email address. I am having troubles with displaying form. Example will describe better what i would like achieve. This is mine extended user model. class UserExtended(models.Model): user = models.ForeignKey(User, unique=True) kod_pocztowy = models.CharField(max_length=6,blank=True) email = models.EmailField() This is how my form looks like. class UserCreationFormExtended(UserCreationForm): def __init__(self, *args, **kwargs): super(UserCreationFormExtended, self).__init__(*args, **kwargs) self.fields['email'].required = True self.fields['first_name'].required = False self.fields['last_name'].required = False class Meta: model = User fields = ('username', 'first_name', 'last_name', 'email') It works fine when registering, as i need allow users to put username and email but when it goes to editing profile it displays too many fields. I would not like them to be able to edit username and email. How could i disable fields in form? Thanks for help.

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  • Can this django query be improved?

    - by Hobhouse
    Given a model structure like this: class Book(models.Model): user = models.ForeignKey(User) class Readingdate(models.Model): book = models.ForeignKey(Book) date = models.DateField() One book may have several readingdates. How do I list books having at least one readingdate within a specific year? I can do this: from_date = datetime.date(2010,1,1) to_date = datetime.date(2010,12,31) book_ids = Readingdate.objects\ .filter(date__range=(from_date,to_date))\ .values_list('book_id', flat=True) books_read_2010 = Book.objects.filter(id__in=book_ids) Is it possible to do this with one queryset, or is this the best way?

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  • App Engine Django Form Uniqueness Validation?

    - by GeekTantra
    Is there a simpler way to use uniqueness validation with Django Forms in AppEngine? I understand that performance would be problem if we keep an uniqueness constraint but since the amount of data being added is very small performance is not a big concern, rather development time is a concern here. Any help is appreciated.

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  • How would make this run with an if statement and one for loop?

    - by Nick Jacobs
    I'm trying to get this to run by using an if statment, a for loop, and a list. The list is part of the parameters. I am not sure how to write the if statement and have the program loop through all of the different words and set everything how it is supposed to be. newSndIdx=0; for i in range (8700, 12600+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (15700, 17600+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (18750, 22350+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (23700, 27250+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx +=1 newSndIdx=newSndIdx+500 for i in range (106950, 115300+1): sampleValue=getSampleValueAt(sound, i) setSampleValueAt(newSnd, newSndIdx, sampleValue) newSndIdx+=1

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  • A RAM error of big array

    - by flint
    I have a big file, more than 400M. In that file, there are 13496*13496 number, means 13496 rows and 13496 cols. I want to read them to a array. This is my code: _L1 = [[0 for col in range(13496)] for row in range(13496)] _L1file = open('distanceCMD.function.txt') while (i<13496): print "i="+str(i) _strlf = _L1file.readline() _strlf = _strlf.split('\t') _strlf = _strlf[:-1] _L1[i] = _strlf i += 1 _L1file.close() And this is my error massage: MemoryError: File "D:\research\space-function\ART3.py", line 30, in <module> _strlf = _strlf.split('\t')

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  • django url matching

    - by ben
    can anyone see why this wouldn't be working. Fairly new to django so any help would be much appreciated actual url: http://127.0.0.1:8000/2010/may/12/my-second-blog-post/ urls.py: (r'(?P<year>d{4})/(?P<month>[a-z]{3})/(?P<day>w{1,2})/(?P<slug>[-w]+)/$', 'object_detail', dict(info_dict, slug_field='slug',template_name='blog/detail.html')),

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  • Problem opening Solr *.jsp pages with urllib2.urlopen.

    - by nestling
    I'm trying to open a page at http://localhost:8983/solr/admin/stats.jsp but urllib2.urlopen returns a blank string. It works fine for solr/ and solr/admin, but for all the pages above /solr/admin/ I get nothing but a blank string. 76]: t = urllib2.urlopen('http://localhost:8983/solr/admin/stats.jsp') 77]: s = t.read() 78]: s 78]: 79]: type(s) 79]: <type 'str'> 80]: urllib2.urlopen('http://localhost:8983/solr/admin/registry.jsp').read() 80]: In [84]: urllib2.urlopen('http://localhost:8983/solr/admin/schema.jsp').read() Out[84]: I know this isn't a problem with urllib2, but beyond that I am at a loss. I wish solr (or jetty) had an easy to get to log file, so that perhaps it could tell me its side of the story.

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  • Add string to another string

    - by daemonfire300
    Hi there, I currently encountered a problem: I want to handle adding strings to other strings very efficiently, so I looked up many methods and techniques, and I figured the "fastest" method. But I quite can not understand how it actually works: def method6(): return ''.join([`num` for num in xrange(loop_count)]) From source (Method 6) Especially the ([numfor num in xrange(loop_count)]) confused me totally.

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  • django admin site - filtering available objects for user

    - by JPG
    I have models that belong to some 'group' (Company class). I want to add users, who will also belong to a one group and should be able to edit/manage/add objects with membership in associated group. something like: class Company() class Something() company = ForeignKey(Company) user Microsoft_admin company = ForeignKey(Company) and this user should only see and edit objects belonging to associated Company in the Admin Interface. How to acomplish that?

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