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• BufferedImage & ColorModel in Java

  - by spol

  I am using a image processing library in java to manipulate images.The first step I do is I read an image and create a java.awt.Image.BufferedImage object. I do it in this way, BufferedImage sourceImage = ImageIO.read( new File( filePath ) ); The above code creates a BufferedImage ojbect with a DirectColorModel: rmask=ff0000 gmask=ff00 bmask=ff amask=0. This is what happens when I run the above code on my macbook. But when I run this same code on a linux machine (hosted server), this creates a BufferedImage object with ColorModel: #pixelBits = 24 numComponents = 3 color space = java.awt.color.ICC_ColorSpace@c39a20 transparency = 1 has alpha = false isAlphaPre = false. And I use the same jpg image in both the cases. I don't know why the color model on the same image is different when run on mac and linux. The colormodel for mac has 4 components and the colormodel for linux has 3 components.There is a problem arising because of this, the image processing library that I use always assumes that there are always 4 components in the colormodel of the image passed, and it throws array out of bounds exception when run on linux box. But on macbook, it runs fine. I am not sure if I am doing something wrong or there is a problem with the library. Please let me know your thoughts. Also ask me any questions if I am not making sense!

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• How would I include open source library in my iPhone application?

  - by greypoint

  I have found an existing open source library that I would like to include in my iPhone project (the unrar source code found here: http://www.rarlab.com/rar_add.htm ). I have compiled this source as a linked library on my Mac with "make lib" which creates the libunrar.so file just fine. These are the makefile settings for that target: lib: WHAT=RARDLL lib: $(OBJECTS) $(LIB_OBJ) @rm -f libunrar.so $(LINK) -shared -o libunrar.so $(LDFLAGS) $(OBJECTS) $(LIB_OBJ) Obviously I can't use this on iPhone but I imagine I should be able to compile with different options to make a static library that I can use. Do I: Compile it on the Mac with different make options then drag the resulting library (some kind of .a ?) into my xcode project? or Drag all of the source code into my xcode project and create special targets of some kind to create it? or Something else entirely different? I've been working on solving my unrar problem for a couple of weeks now and I believe using this library will give me the best results but I just don't know the final steps to make use of it. Thanks for all advice.

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• Redirect in codeigniter after login

  - by edelweiss

  Trying to do a redirect after a successful login. The login info is sent using ajax to the controller. My controller code as below public function login_controller_function() { $this->load->model('login_model'); if ($this->input->is_ajax_request()) { $user_name=$this->input->post('username'); $user_password = $this->input->post('password'); $this->load->helper('url'); $result = $this->login_model->verify_user($user_name,$user_password); // echo 'user_logged_in'; if(strcmp($result,'user_logged_in')==0) { redirect('welcome'); } } } But it is not working at all. Anyone knows whats wrong? Hi my html as requested. i am using twitter bootstrap as well <li class="divider-vertical"></li> <li><a href="#" id="login_btn">Login</a></li> <li><a href="<?php echo base_url('register'); ?>">Register</a></li> for the buttons so when i click the login button, a modal window will appear and ask for login info. so when i click on the login button, my js code will send an ajax request my js code as below /*Attempt register user jquery ajax*/ $('#login').click(function(){ var user_name = $('#loginHere').find('#user_name').val(); var user_password = $('#loginHere').find('#login_pwd').val(); if(user_name==""||user_password=="") return; var login_data = { username:user_name, password:user_password}; $.ajax({ type: "POST", dataType: "json", async: false, url:"login_register/login_controller_function", data: login_data, success: function(data) { if(data.login) { alert(data.redirect); window.location.replace(data.redirect); } else if(!data.login) { alert('data login not true'); } }, error:function(data){ alert('ajax error'); } }); }); });

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• New user register, script auto create problems!

  - by SKY

  Hi, im currently trying to create a php script that when a new user register, a script (eg:wordpress,blog etc..) will install for them. I'm currently got the code below for just single setup, but how can i setup a form for multi user? which only allowing them to input the username (subdomain) and password. <?php class scriptname_Config { public static $title = 'new_script_title'; // Domain name and path where new script will installed in public static $domain = 'username.domain.com'; public static $absolutePath = '/new_register_username/'; // Settings for general mysql database public static $db = array( 'host' => 'localhost', 'database' => 'scriptname', 'user' => 'root', 'password' => '', 'prefix' => 'scriptname_' ); } define( 'scriptname_BASE_URL', 'http://'.scriptname_Config::$domain.scriptname_Config::$absolutePath ); ?> Or any tutorial that will help is appreciate! Thanks!

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• Problem with using PHPMailer for SMTP

  - by Frozenfire

  I have used PHPMailer for SMTP and there is problem in sending mail with error "Mailer Error: The following From address failed: [email protected]" My code is as follows: $mail = new PHPMailer(); $mail->IsSMTP(); // send via SMTP $mail->Host = "localhost;"; // SMTP servers $mail->SMTPAuth = true; // turn on SMTP authentication $mail->Username = ""; // SMTP username $mail->Password = ""; // SMTP password $mail->From = $email_address; $mail->FromName = $email_address; $mail->AddAddress($arrStudent[0]["email"]); $mail->WordWrap = 50; // set word wrap $mail->IsHTML(true); // send as HTML $mail->Subject = "Subject"; $theData = str_replace("\n", "<BR>", $stuff); $mail->Body = $theData; // "This is the <b>HTML body</b>"; $mail->AltBody = $stuff; if (!$mail->Send()) { $sent = 0; echo "Mailer Error: " . $mail->ErrorInfo; exit; } i researched everything and when i debug inside class.smtp.php i found error the function "get_lines()" is returning error value "550 Authentication failed" The code was working fine previously, i am wondering how this problem came suddenly. Desperate for some help. Thanks, Biplab

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• CreateProcessWithLogonW : unable to start process

  - by Vivek

  Hi I am completely new to programming. And please someone help me. I am trying to start a pocess from a service. I need to start the new process by prompting user to enter admin credentials. I was trying to use CreateProcessWithLogonW(). Am I using the right function. I tried to give input username, password, domain as localhost. I gave full pathe to the .exe file that i need to start. Here is the piece of code. CreateProcessWithLogonW(L"Administrator", L"localhost", L"password", 0, NULL, L"c:\myupdates\myapp.exe", NORMAL_PRIORITY_CLASS | CREATE_CONSOLE, NULL, NULL, &si, &pi); Si.cb = sizeof(si); Si.lpDesktop = L"winsta0\\default"; But the process never started. Can you guys tell me what I am doing wrong. And what do I need to do to promt user to enter credentials of administrator instead of hardcoding it.

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• Windows Service Start-Up Error 1069

  - by Gavin

  Hello, I am installing a new windows service coded in C# on a server. I installed the service fine on the server, but once i manually start up the service on a server, with the same login credentials that our other services use, i get the fatal error message notification: "Could not start the %service name% on Local Computer. Error 1069: The Service did not start due to a logon failure." I looked in the event log and i got a 7038 and 7000 event id error in that order. 7038 event id message: "The %service name% service was unable to log on as %login% with the currently configured password due to the following error: Logon failure: unknown user name or bad password. To ensure that the service is configured properly, use the Services snap-in in Microsoft Management Console (MMC)." 7000 event id message: "The %service name% service failed to start due to the following error: The service did not start due to a logon failure. " I have other services that are using the same exact login account and they work fine. Is there something simple I could be missing? Thanks

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• Error after redirection using CakePHP

  - by Praveen kalal

  I have created some code called LoginController. Whenever Admin gets successfully logged in I redirect the page to index. However, I got an error like "problem on loading page". This is my code: <?php class LoginController extends AdminAppController { var $name = 'Login'; var $uses = array('Admin.Login'); var $sessionkey= ''; /*function beforeFilter() { if($this->Session->read('user')=='Admin' || $this->params['action']=='login') { echo "in"; exit; } else { echo "else"; exit; $this->Session->setFlash('Login first','flash_failure'); $this->redirect(array('action'=>'login')); } }*/ function index() { } function login() { //pr($this->data); exit; if(!empty($this->data)) { $results = $this->Login->findByEmail($this->data['Login']['email']); if(!empty($results) && $results['Login']['password']== md5($this->data['Login']['password'])) { $this->Session->write('user', 'Admin'); $results['Login']['last_login']=date("Y-m-d H:i:s"); $this->Login->save($results); $this->Session->setFlash('Login successfully.', 'flash_success'); $this->redirect(array('controller'=>'login','action' => 'index')); } } } } ?> Can anyone help me? Thanks.

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• zend_db and join

  - by premtemp

  Hello, I am trying to understand how to use Zend_DB in my program but I have some problem. The class below (DatabaseService) work when I pass it a simple query. However, if I pass it it query with a join clause my page just hangs and not error is return. I cut and paste the qry in a query browesr and it is valid Any help would be great $SQL = "select name from mytable" $db = new DatabaseService($dbinfo) $db ->fetchall($SQL ) // works ----------------------------------------------------------- $SQL = "select count(*) as cnt from EndPoints join CallID on EndPoints.`CallID` = CallID.CallID where EndPoints.LastRegister >= '2010-04-21 00:00:01' and EndPoints.LastRegister <= '2010-04-21 23:59:59' " $db = new DatabaseService($dbinfo) $db ->fetchall($SQL ) // DOES NO WORK class DatabaseService { function DatabaseService($dbinfo,$dbname="") { try { $dbConfig = array( 'host' => $this->host, 'username' => $this->username, 'password' => $password, 'dbname' => $this->dbname ); $this->db = Zend_Db::factory($this->adapter, $dbConfig); Zend_Db_Table::setDefaultAdapter($this->db); } catch(Zend_Exception $e) { $this->error = $e->getMessage(); Helper::log($this->error); return false; } } public function connnect() { if($this->db !=null) { try { $this->db->getConnection(); return true; } catch (Zend_Exception $e) { $err = "FAILED ::".$e->getMessage()." <br />"; } } return false; } public function fetchall($sql) { $res= $this->db->fetchAll($sql); return $res; } }

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• Creating a OS X Cocoa App Web View in Xcode 5.0.1

  - by user1822824

  I created a HTML5 web app that I’m trying to wrap in a web view and submit to the Mac App Store. I’ve done the following: 1) Opened Xcode 5.0.1 and selected “Create a new Xcode project” 2) Under “OS X” I selected “Application” then I selected “Cocoa Application” then “Next” 3) I entered a “Product Name” and a “Company Identifier” then selected “Next” (I left all the other settings untouched) then “Create” 4) Under “General” “Deployment Info” “Deployment Target” I selected 10.6 — because I want the app to be compatible with all versions of OS X that support the Mac App Store 5) I clicked “MainMenu.xib” and selected “Window - My App” 6) From the “Object library” I drug the “Web View” object into my window and made it fill the window size 7) I saved my project and click the Play button in the upper left corner of Xcode The app tries to open but freezes. I don’t get an error in Xcode but it does open “main.m” and highlight “return NSApplicationMain(argc, argv);” in green and says “Thread 1: signal SIGABRT” I was hoping that someone could clarify why this isn’t working? And provide me with the last step to link the web view object? I searched Google and found tutorials for iOS and a few for OS X but for different versions of Xcode.

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• Windows "forms" authentication - <deny users="?"> redirecting to foreign page!

  - by Erik5388

  Like the title states - I have a web.config file that looks like, <?xml version="1.0" encoding="UTF-8"?> <configuration> <system.web> <compilation debug="true" targetFramework="4.0" /> <authentication mode="Forms"> <forms name="login" protection="All" timeout="30" loginUrl="login" defaultUrl="~/"> <credentials passwordFormat="Clear"> <user name="admin" password="password" /> </credentials> </forms> </authentication> <authorization> <deny users="?" /> </authorization> </system.web> </configuration> I want to do exactly what it says it should do... I want to deny all users who try to enter the site. It works however, it redirects to a "Account/Login?ReturnUrl=%2flogin" url I have never heard of... Is there a place I can change this?

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• java.lang.ClassNotFoundException: com.mysql.jdbc.Driver When run jar file

  - by user1024858

  Hi all, Connection conn = null; String url = "jdbc:mysql://localhost:3306/"; String dbName = "test"; String driver = "com.mysql.jdbc.Driver"; String userName = "root"; String password = "admin"; try { Class.forName(driver).newInstance(); conn = DriverManager.getConnection(url+dbName,userName,password); System.out.println("Connected to the database"); conn.close(); System.out.println("Disconnected from database"); } catch (Exception e) { e.printStackTrace();} I run in eclipse it's ok, but i built to jar file and run on command line java -jar Test.jar i get this error: java.lang.ClassNotFoundException: com.mysql.jdbc.Driver at java.net.URLClassLoader$1.run(Unknown Source) at java.net.URLClassLoader$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Unknown Source) Please help me how to fix it. Thanks!!!

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• Retrieve nested list from XDocument with LINQ

  - by twreid

  Ok I want my link query to return a list of users. Below is the XML <section type="Users"> <User type="WorkerProcessUser"> <default property="UserName" value="Main"/> <default property="Password" value=""/> <default property="Description" value=""/> <default property="Group" value=""/> </User> <User type="AnonymousUser"> <default property="UserName" value="Second"/> <default property="Password" value=""/> <default property="Description" value=""/> <default property="Group" value=""/> </User> </section> And my current LINQ Query that doesn't work. doc is an XDocument var users = (from iis in doc.Descendants("section") where iis.Attribute("type").Value == "Users" from user in iis.Elements("User") from prop in user.Descendants("default") select new { Type = user.Attribute("type").Value, UserName = prop.Attribute("UserName").Value }); This does not work can anyone tell me what I need to fix? Here is my second attempt after fixing for the wrong property name. However this one does not seem to enumerate the UserName value for me when I try to use it or at least when I try to write it to the console. Also this returns 8 total results I should only have 2 results as I only have 2 users. (from iis in doc.Descendants("section") where iis.Attribute("type").Value == "Users" from user in iis.Elements("User") from prop in user.Descendants("default") select new { Type = user.Attribute("type").Value, UserName = (from name in prop.Attributes("property") where name.Value == "UserName" select name.NextAttribute.Value).ToString() });

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• How does an ASP.NET programmer go from working on/developing existing sites, to creating one from sc

  - by SLC

  I've been an ASP.NET developer for some time, always working on existing ASP.NET pages, modifying functionality, adding features, tweaking things etc. but have never built a site up from scratch. I've read books on ASP.NET, and they generally talk you through the various features of ASP.NET with a mock up site, but it's always very basic and they jump straight in. The time has come however, to write a site from scratch for a client. I've never done this before. There are design considerations, but like a lot of ASP.NET sites, the basic idea is, you have a site, where users can log in, and save some information like their name and password and address. The site has some functionality, but that's the basic design of a majority of (business-related) asp.net websites I would wager. I know how to program in ASP.NET already on an existing site, but I don't know how to design my own properly that meets the criteria above. I guess the main worry is security. I don't know the best way to handle a simple log-in system that stores user information like their name and password. I understand there are a few approaches to this, but the catch with this project is that it has to be absolutely bulletproof. Maximum security. All those good practices for security, it needs to have them all. I'm not asking what they are, but I am asking where to begin. What should be the first steps after I do File New Project ? Where can I look for information about setting up a secure ASP.NET website? I'll figure out the content and page layout later, it's the framework that is the big thing. Any and all advice would be welcome. I really want to get my first from-scratch project right from the beginning. Just to confuse things, it's possible I will be using MVC, I am not sure if this has any impact.

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• Create 2nd tables and add data

  - by Tyler Matema

  I have this task from school, and I am confuse and lost on how I got to do this. So basically I have to create 2 tables to the database but I have to created from php. I have created the first table, but not the second one for some reason. And then, I have to populate first and second tables with 10 and 20 sample records respectively, populate, does it mean like adding more fake users? if so is it like the code shown below? *I got error on the populating second part as well Thank you so much for the help. <?php $host = "host"; $user = "me"; $pswd = "password"; $dbnm = "db"; $conn = @mysqli_connect($host, $user, $pswd, $dbnm); if (!$conn) die ("<p>Couldn't connect to the server!<p>"); $selectData = @mysqli_select_db ($conn, $dbnm); if(!$selectData) { die ("<p>Database Not Selected</p>"); } //1st table $sql = "CREATE TABLE IF NOT EXISTS `friends` ( `friend_id` INT NOT NULL auto_increment, `friend_email` VARCHAR(20) NOT NULL, `password` VARCHAR(20) NOT NULL, `profile_name` VARCHAR(30) NOT NULL, `date_started` DATE NOT NULL, `num_of_friends` INT unsigned, PRIMARY KEY (`friend_id`) )"; //2nd table $sqlMyfriends = "CREATE TABLE `myfriends` ( `friend_id1` INT NOT NULL, `friend_id2` INT NOT NULL, )"; $query_result1 = @mysqli_query($conn, $sql); $query_result2 = @mysqli_query($conn, $sqlMyfriends); //populating 1st table $sqlSt3="INSERT INTO friends (friend_id, friend_email, password, profile_name, date_started, num_of_friends) VALUES('NULL','[email protected]','123','abc','2012-10-25', 5)"; $queryResult3 = @mysqli_query($dbConnect,$sqlSt3) //populating 2nd table $sqlSt13="INSERT INTO myfriends VALUES(1,2)"; $queryResult13=@mysqli_query($dbConnect,$sqlSt13); mysqli_close($conn); ?>

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• Replacing mysql user authentication with openid

  - by David

  So, I'm working with a really old system which uses a person's mysql database credentials to authenticate to a web site (the database was originally only accessed from the command line, but is now accessed from a php frontend). Because of some internal reasons (and to preserve the user's history), I have to leave the old authentication intact. I've been charged with adding openid authentication to this system. Somehow I need to be able to retrieve a users mysql username and password upon logging into the site through openid (using the Zend framework, by the way). I've thought of simply requiring registration at the first login, where the user must provide their mysql credentials, but I'd rather not store the password plain text. I've also considered blanking everyone's mysql passwords, and just setting the user's mysql username manually (rather than having the user provide this, since they could provide any username). This is turning into a security nightmare. Does anyone have any suggestions for alternatives? This is running on a Linux server, by the way. Also, I can't use mysql pluggable authentication because the mysql version is 5.0 (pluggable authentication requires mysql 5.5), and no, I can't update it.

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• Selenium problem locating by DOM

  - by bartonlee

  Hi, I'm trying to use the DOM to locate a form element in Selenium but I can't get it to work. Even if I use the example in the Selenium documentation it still fails, for example with this html... <html> <body> <form id="loginForm"> <input name="username" type="text" /> <input name="password" type="password" /> <input name="continue" type="submit" value="Login" /> <input name="continue" type="button" value="Clear" /> </form> </body> <html> and this command in the Selenium IDE... verifyElementPresent with target... dom=document.forms['loginForm'] I get [error] false in the log. The 'getElementById' example in the documentation does work, but none of the others. Can someone explain what I'm doing wrong here? Thanks.

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• Shell script for generating HTML out put

  - by user1638016

  The following script is generating the desired out put but not redirecting the result to /home/myuser/slavedelay.html #!/bin/bash host=<ip> echo $host user=usr1 password=mypass threshold=300 statusok=OK statuscritical=CRITICAL for i in ert7 ert9 do echo "<html>" > /home/myuser/slavedelay.html if [ "$i" == "ert7" ]; then slvdelay=`mysql -u$user -p$password -h<ip> -S /backup/mysql/mysql.sock -e 'show slave status\G' | grep Seconds_Behind_Master | sed -e 's/ *Seconds_Behind_Master: //'` if [ $slvdelay -ge $threshold ]; then echo "<tr><td>$i</td><td>CRITICAL</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>CRITICAL</td>" else echo "<tr><td>$i</td><td>OK</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>OK</td>" fi fi done echo "</html>" >> /home/myuser/slavedelay.html If I cat the output file /home/myuser/slavedelay.html it gives. <html> </html> Execution result : sh slave_delay.sh <tr><td>sdb7</td><td>OK</td>

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• Discussion - Allowing / blocking user access to pages / Client Side Validation (Client Side Only!) -

  - by Ozaki

  TLDR Using plain HTML / Javascript (Client Side) I want to prevent viewing of certain pages. The user will have to type a username and password and depending on that they get access to different pages. Answers can NOT include server side whatsoever It does not matter if they can break it easily. There is no sensitive information etc. Also the target audience will not have access to internet OR probably know what a cookie is... At some point the user will have to type username / password.(I can define the cookie here) Currently I thought of using cookies to set a cookie for each page to say "true" / "false" but that would get messy with so many cookies. Or setting an array within a cookie for each page? I have div field "#Content" which as it looks encompasses all of my content on the page so blocking out content will be as simple as replacing it with ("sorry you don't have access") etc. For Example: $.cookie("Access","page1, page2, page3"{ expires: 1 }); I am looking for anyway to do this does not have to be with cookies. Would be nice to get a discussion of different ways this can be done. So the question is: What do YOU think would be a good way to go about doing this with client side validation? Also on another note discussion on how to make client side more secure or ways to do so are acceptable.

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• make java plugin use the browser certificates

  - by Shalom938

  We have a java applet that communicates with a spring application running on tomcat and using spring's http invoker. We want to secure the applet using ssl with client authentication, we have a jsp page for login, after successful login the applet loads. The jsp page is secured with ssl, when the applet loads the http invoker inside the applet is doing a second handshake apparently not related to the browser handshake, OK, I don't mind that, but I want the java plugin to use browser certificates and client certificates but its not, I have to load the client certificate to the java plugin also using the java ControlPanel, and if my server's certificate is self signed then I have to load the server certificate also to the java ControlPanel and to the nrowser. Another thing is when the applet starts loading the java plugin pops a dialog asking for the client keystore password, I would like to avoid that. So to conclude: I would like the java plugin to use the browser's trusted certificates and client certificates, and to avoid the keystore password dialog that pops up. I have googled for it for two days and can't find any clue of how to accomplish that. I will appreciate any help. I'm using jdk 1.6.0 u23 and firefox 3.6.13.

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• Paypal Sandbox 2014 Non US test account Sign Up proper link

  - by Flood Gravemind

  Ok I had a Paypal Sandbox account a year ago. I am developing a new site for a client and when I try to Login it won't recognize my email address. I tried forgot my password forgot password still nothing. So I guessed that maybe due to inactivity for such a long time they may have deleted my account. So then I try to Sign Up for a new one. I entered my details 3 times now and spent 6 hours trying to figure out what is the proper link to do this. Then I went to another Sandbox link which required me to entered a US Zip code and its a dead end. I am not even sure which Paypal account I signed up for those three times. No email nothing at all. I am a Non US developer and the FAQ link for Non US developers just points to their REST API. Can someone please guide me to the proper Paypal Sandbox Setup for Non US developers including the proper sign up links please. And I know Stackoverflow does not like rants but from my experience dealing with Paypal, GTA 6 should make a satirical Paypal company in their next Game with Paypal Developer Rampage mode for the main protagonist who also happens to be a Developer. EDIT: REST API does not include UK :(

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• Commons VFS and IBM MVS System

  - by Liming

  Hello All, I'm using Apache Commons VFS / SFTP, we are trying to download files from the IBM MVS system. The download part is all good, however, we can not open up the zipped files after downloading. Seems like the zip file was compressed using a different algorithm or something Anyone has any pointers? *Note, the same function works fine if we connect to a regular unix/linux SFTP server. Below is an example of what we did String defaultHost = "[my sftp ip address]"; String host = defaultHost; String defaultRemotePath = "//__root.dir1.dir2."; String remotePath = defaultRemotePath; String user = "test"; String password = "test"; String remoteFileName = "Blah.ZIP.BLAH"; log.info("FtpPojo() begin instantiation"); FileObject localFileObject = fsManager.resolveFile("C:/Work/Blah.ZIP.BLAH"); log.debug("local file name is :"+localFileObject.getName().getBaseName()); log.debug("FtpPojo() instantiated and fsManager created"); String uri = createSftpUri(host, user, password) + ":322"+remotePath+remoteFileName; remoteRepo = fsManager.resolveFile(uri, fsOptions); remoteRepo.copyFrom(localFileObject, Selectors.SELECT_ALL);

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• JDBC with JSP fails to insert

  - by StrykeR

  I am having some issues right now with JDBC in JSP. I am trying to insert username/pass ext into my MySQL DB. I am not getting any error or exception, however nothing is being inserted into my DB either. Below is my code, any help would be greatly appreciated. <% String uname=request.getParameter("userName"); String pword=request.getParameter("passWord"); String fname=request.getParameter("firstName"); String lname=request.getParameter("lastName"); String email=request.getParameter("emailAddress"); %> <% try{ String dbURL = "jdbc:mysql:localhost:3306/assi1"; String user = "root"; String pwd = "password"; String driver = "com.mysql.jdbc.Driver"; String query = "USE Users"+"INSERT INTO User (UserName, UserPass, FirstName, LastName, EmailAddress) " + "VALUES ('"+uname+"','"+pword+"','"+fname+"','"+lname+"','"+email+"')"; Class.forName(driver); Connection conn = DriverManager.getConnection(dbURL, user, pwd); Statement statement = conn.createStatement(); statement.executeUpdate(query); out.println("Data is successfully inserted!"); } catch(SQLException e){ for (Throwable t : e) t.printStackTrace(); } %> DB script here: CREATE DATABASE Users; use Users; CREATE TABLE User ( UserID INT NOT NULL AUTO_INCREMENT, UserName VARCHAR(20), UserPass VARCHAR(20), FirstName VARCHAR(30), LastName VARCHAR(35), EmailAddress VARCHAR(50), PRIMARY KEY (UserID) );

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• Resource allocation and automatic deallocation

  - by nabulke

  In my application I got many instances of class CDbaOciNotifier. They all share a pointer to only one instance of class OCIEnv. What I like to achieve is that allocation and deallocation of the resource class OCIEnv will be handled automatically inside class CDbaOciNotifier. The desired behaviour is, with the first instance of class CDbaOciNotifier the environment will be created, after that all following notifiers use that same environment. With the destruction of the last notifier, the environment will be destroyed too (call to custom deleter). What I've got so far (using a static factory method to create notifiers): #pragma once #include <string> #include <memory> #include "boost\noncopyable.hpp" class CDbaOciNotifier : private boost::noncopyable { public: virtual ~CDbaOciNotifier(void); static std::auto_ptr<CDbaOciNotifier> createNotifier(const std::string &tnsName, const std::string &user, const std::string &password); private: CDbaOciNotifier(OCIEnv* envhp); // All notifiers share one environment static OCIEnv* m_ENVHP; // Custom deleter static void freeEnvironment(OCIEnv *env); OCIEnv* m_envhp; }; CPP: #include "DbaOciNotifier.h" using namespace std; OCIEnv* CDbaOciNotifier::m_ENVHP = 0; CDbaOciNotifier::~CDbaOciNotifier(void) { } CDbaOciNotifier::CDbaOciNotifier(OCIEnv* envhp) :m_envhp(envhp) { } void CDbaOciNotifier::freeEnvironment(OCIEnv *env) { OCIHandleFree((dvoid *) env, (ub4) OCI_HTYPE_ENV); *env = null; } auto_ptr<CDbaOciNotifier> CDbaOciNotifier::createNotifier(const string &tnsName, const string &user, const string &password) { if(!m_ENVHP) { OCIEnvCreate( (OCIEnv **) &m_ENVHP, OCI_EVENTS|OCI_OBJECT, (dvoid *)0, (dvoid * (*)(dvoid *, size_t)) 0, (dvoid * (*)(dvoid *, dvoid *, size_t))0, (void (*)(dvoid *, dvoid *)) 0, (size_t) 0, (dvoid **) 0 ); } //shared_ptr<OCIEnv> spEnvhp(m_ENVHP, freeEnvironment); ...got so far... return auto_ptr<CDbaOciNotifier>(new CDbaOciNotifier(m_ENVHP)); } I'd like to avoid counting references (notifiers) myself, and use something like shared_ptr. Do you see an easy solution to my problem?

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• Rails: Duplicate functionality across controllers? A humble plea.

  - by Alex

  So I'm working with authlogic, and I'm trying to duplicate the login functionality to the welcome page, so that you can log in by restful url or by just going to the main page. No, I don't know if we'll keep that feature, but I want to test it out anyway. Here's the error message: RuntimeError in Welcome#index Called id for nil, which would mistakenly be 4 -- if you really wanted the id of nil, use object_id The code is below. Basically, what's happening is the index view (the first code snippet) is sending the information from the form to the create method of user_sessions controller. At this point, in theory, it create should just pick up, but it doesn't. PLEASE help. Please. I've been doing this for about 8 hours. I checked Google. I checked IRC. I checked every book I could find. You don't even have to answer, I can to the grunt work if you just point me in the right direction. <% form_for @user_session, :url => user_sessions_path do |f| %> <%= f.text_field :email %><br /> <%= f.password_field :password %> <%= submit_tag 'Login' %> <% end %> class ApplicationController < ActionController::Base helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # Scrub sensitive parameters from your log # filter_parameter_logging :password helper_method :current_user_session, :current_user before_filter :new_session_object protected def new_session_object unless current_user @user_session = UserSession.new(params[:user_session]) end end private def current_user_session return @current_user_session if defined?(@current_user_session) @current_user_session = UserSession.find end def current_user return @current_user if defined?(@current_user) @current_user = current_user_session && current_user_session.record end end

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