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  • MySQL/PHP: How to insert logged in user id into another table that is gathering data from a form tha

    - by Lisa
    For the first time I am needing to join information from two tables and am quite nervous about doing it without any advice first. Basically, I am building a secure site that is accessed by authorised users. I have my login table with user_id, username, password Once the user is on the site, they have the option of inputting data into another table called input. At the moment this table only captures the information that is entered, not the user_id or username of the inputter. I would like the form to be able to input the user_id and/or username from the login table into the input table. Please could somebody talk me through this process? I am sure that once this is amended, I will then be able to use the table to only allow the logged in user to access the information that he or she have inputted, is that correct? Many thanks

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  • How to check whether a mysql select statement result has a value or not in php?

    - by udaya
    I have a textbox UserName and a Check Availability button next to it..... I have checked the availability by passing UserName textbox value..... But it doesn't seem to work.... Here is what i am doing? echo $UserName = $_GET['CheckUsername']; $_SESSION['state'] = $State; $queryres = "SELECT dUser_name FROM tbl_login WHERE dUser_name='$UserName'"; $result = mysql_query($queryres,$cn) or die("Selection Query Failed !!!"); if($result==true) // this condition doesn't seem to work { echo "User Name Available"; } else { echo "Sorry user name taken"; }

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  • PHP : How to insert an array into other child array by same index?

    - by airi
    i am new to array. Hope you can help me. i have 2 array. Let say: array 1 = [[50,60],[70,80]] array 2 = ["Fire", "Marine"] array 1 index : Array([0]=Array ([0]=50 [1]=60) [1]=Array ([0]=70 [1]=80)) array 2 index : Array ([0]= Fire [1]=Marine) How i can insert array 2 into array 1 like output below : Output that i want like below: array 3 = [["Fire",50,60],["Marine",70,80]] array 3 index = (Array([0]=Array ([0]=Fire [1]=50 [2]=60) [1]=Array ([0]=Marine [1]=70 [2]=80)) Thanks

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  • Basic class returns object reference instead of Array

    - by php-b-grader
    I have very basic class: class Customer { protected $id; protected $customer; public function __construct($customer_id) { $this->id = $customer_id; return $this->set_customer(); } protected function set_customer() { $query = mysql_query("SELECT * FROM customer WHERE id = '$this->id'"); $this->customer = mysql_fetch_row($query); return $this->customer; } } $customer = new Customer($order->customer->id); print_r($customer); This is not doing what I want it to but I understand why... $customer returns a reference to the Customer Object... What I want is the MySQL row array from the mysql_fetch_row() - How do I return the array? What am I missing?

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  • [PHP] How to pass array as multiple parameters to function?

    - by vbklv
    I have a parameters array: $params[1] = 'param1'; $params[2] = 'param2'; $params[3] = 'param3'; ... $params[N] = 'paramN'; I have a caller to various functions: $method->$function( $params ); How can I parse the $params array, so multiple (and unlimited) parameters can be passed to any function: $method->$function( $param[1], $param[2], ..., $param[N] );

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  • Can a dropdown box using PHP / MySQL automatically select what was last saved in the database with it?

    - by wertz8090
    I am currently working on trying to get a dropdown box to display the most recently saved field each time I open a page for editing an item in an inventory. For example, let's say that my dropdown box selections are Iron, Copper, Gold, Silver, Titanium. The first time the dropdown box loads, I would like it to load in that order (the default order that I set it to). However, once a user submits a form that specifies a selection, I would like that selection to appear as the new default for the dropdown box (for example, if the user picks Gold, Gold will now display as the default). However - the new default that is selected and submitted can only appear for those fields which it is saved under (for example, since the user selected Gold, their preference is now saved as Gold and will appear as such under the field Necklace - however, Gold should not be the default for the fields Ring, Bracelet, and Earring when I open a page to view them). Basically, I need a dropdown box that can save the option of the latest selection on a page after the form is submitted, while at the same time making sure not to affect the default order of the dropdown box across other pages. Your help is much appreciated.

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  • jQuery slider to load content one at a time

    - by Barrett
    I have a slider that load all of my content at once. Into a div. Like so: external page.php $get_users = mysql_query("SELECT * FROM user WHERE id!='$user_id'"); while ($rows = mysql_fetch_assoc($get_users)) { $id = $rows['id']; $firstname = $rows['firstname']; $display_info .= ' <div class="f_outer" id="' . $id . '"> <div class="f_name likeu">' . $firstname . '</div> </div>'; } echo $display_info; I call this page from my find.php page using bxslider Here is my find.php page below. <script type="text/javascript"> $(function() { var slider = $("#slider1").bxSlider(); $("#slider-like").live('click', function() { slider.goToNextSlide(); return false; }); }); </script> <div id="slider-like>Yes</div> <div id="slider1"> <?PHP include ("external.php"); ?> </div> So what I get is all of my .f_outer div on the find.php page. I have hundreds of user and they will all be loaded at once. I would like to only load one slide at a time. So when I click #slider-like it load one of my dive from my external page.

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  • Creating a PHP web page that enables you to reboot the server in Linux?

    - by Stuart
    I want to create a web page that allows the user to initiate a reboot on the linux server. Obviously this would only be avaliable for system admins and would also be controlled by using iptables. Below is a sample of code that I was thinking of using but I wanted to know if there is another way to do this and how also to use this in a web page? Also is there any thing else that I should consider? $command = "cat $pass | su -c 'shutdown -r now'"; $output = array(); try{ echo shell_exec($command); exec($command, $output); system($command, $output); } catch(Exception $e) { print "Unable to shutdown system...\n"; } foreach ($output as $line) { print "$line<br>"; } Thanks in advance.

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  • PHP mysql - ...AND column='anything'... ?

    - by Nike
    Is there any way to check if a column is "anything"? The reason is that i have a searchfunction that get's an ID from the URL, and then it passes it through the sql algorithm and shows the result. But if that URL "function" (?) isn't filled in, it just searches for: ...AND column=''... and that doesn't return any results at all. I've tried using a "%", but that doesn't do anything. Any ideas?

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  • How to get a list of unrepeatable date from my db in PHP?

    - by SzamDev
    Hi in my db there are 5 fields (id, list_date, amount, total, m_from) and contain data, for example : 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/4/2010 - 10 - 50 - 'example154 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/5/2010 - 10 - 50 - 'test' I need to know how I can get dates from list_date but without repeatable dates like '1/1/2010, 1/5/2010, 1/4/2010' Thanks in Advance.

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  • How to seperate database entries and display them as individual records using PHP?

    - by Clark
    I used to have database entries separated by ampersands (&), but this was causing certain search issues so I decided to encapsulate my entries on both sides by $ and & symbols like: $this& But I am having trouble displaying all the entries of a cell as indiivdual records. Before I used: $unsplitItems = $row['files']; $files = explode("@", $unsplitItems); foreach ($files as $file) { if(strlen($file)) { echo "<li>$file</li>"; } } Any idea how I can split my records and display all the items in the array as individual entries?

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  • PHP - Why does my computation produce a different result when I assign it to a variable?

    - by David
    I want to round a number to a specific number of significant digits - basically I want the following function: round(12345.67, 2) -> 12000 round(8888, 3) -> 8890 I have the following, but there's a strange problem. function round_to_sf($number, $sf) { $mostsigplace = floor(log10(abs($number)))+1; $num = $number / pow(10, ($mostsigplace-$sf)); echo ($number / pow(10, ($mostsigplace-$sf))).' '.$num.'<BR>'; } round_to_sf(41918.522, 1); Produces the following output: 4.1918522 -0 How can the result of a computation be different when it's assigned to a variable?

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  • how to show jquery notify bar on submit using php or zend?

    - by user1400
    hi guys in my application on zend framework i use of 'jQuery Notify Bar' plugin for display messages, i'd like to show message when my form submit ,the other page is opened and notify bar be open until the other page is completely load and even some second more but the problem is that notify bar show for short Moment and when the other page begin to load , notify bar is closed, and the delay property is not effect to that $('#myForm').submit(function(){ $.notifyBar({ html: "Thank you, your settings were updated!", **delay: 20000,** animationSpeed: "normal" }); how to show notify bar in the other page too? thanks

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