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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    I have a form with multiple fields in it along with a image input field, just below the form i have a list to be displayed on every submit of this form... this has to be done without the use of DB.. I think this can be achieved by using session but its not working with me, as evrytime page gets refreshed and session gets recreated/reset.. Please help me in resolving this issue

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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    How to make the use of hidden variables as array for consecutive submission of data so that they can be used to display the records list. I have a form with 4 text fields and a file upload field.. as i submit he form it should get appended to the list which needs to be displayed below the form, such that these values are NOT stored in the DB.. So in this case how can i use the post array to collect the data and display in the list below?

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  • Why is only 2 of my querys working? (PHP/Mysql)

    - by ggfan
    When I remove a posting, I want it to remove the posting itself, any comments related to it, and like/dislike of the comments, and favorites that people added. So there are 4 queries that do this, but somehow only 2 of the 4 are working. When I switch say query 2 for query 3, then query 2 works and query 3 doesn't... The table names are correct and it is getting the data via $_GET. // Grab the data from the GET $posting_id = $_GET['posting_id']; // Delete the posting from the database $query = "DELETE FROM posting WHERE posting_id=$posting_id LIMIT 1"; mysqli_query($dbc, $query) or die(mysql_error()); // Delete the comments $query2 = "DELETE FROM comments WHERE posting_id=$posting_id "; mysqli_query($dbc, $query2) or die(mysql_error()); // Delete the like/dislike $query3 = "DELETE FROM comment_likedislike WHERE posting_id=$posting_id "; mysqli_query($dbc, $query3) or die(mysql_error()); // Delete the favorites $query4 = "DELETE FROM favorite WHERE posting_id=$posting_id "; mysqli_query($dbc, $query4) or die(mysql_error());

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  • PHP mysql - ...AND column='anything'... ?

    - by Nike
    Is there any way to check if a column is "anything"? The reason is that i have a searchfunction that get's an ID from the URL, and then it passes it through the sql algorithm and shows the result. But if that URL "function" (?) isn't filled in, it just searches for: ...AND column=''... and that doesn't return any results at all. I've tried using a "%", but that doesn't do anything. Any ideas?

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  • How to generate all permutations of a string in PHP ?

    - by Johan
    I need an algorithm that return all possible combination of all characters in one string. I've tried: $langd = strlen($input); for($i = 0;$i < $langd; $i++){ $tempStrang = NULL; $tempStrang .= substr($input, $i, 1); for($j = $i+1, $k=0; $k < $langd; $k++, $j++){ if($j > $langd) $j = 0; $tempStrang .= substr($input, $j, 1); } $myarray[] = $tempStrang; } But that only returns the same amount combination as the length of the string. Say the $input is = "hey", the result would be: hey, hye, eyh, ehy, yhe, yeh.

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  • PHP export to text file - Only saving first line.

    - by wertz8090
    I'm trying to export some extracted $_POST information into a text file, however my code is only capturing the first variable and ignoring the rest. I'm saving the information to the text file in this manner: $values = "First Name: $fName\r\n"; $values .= "Last Name: $lName\r\n"; $values .= "Address: $address\r\n"; etc. This is the code I use to write to the text file: $fp = @fopen("person.data", "w") or die("Couldn't open person.data for writing!"); $numBytes = @fwrite($fp, $values) or die("Couldn't write values to file!"); @fclose($fp); Any ideas on why it would only save the first $values ($fName) variable but not the rest of them? It actually saves the first part of the $values string for all of them (so I see Last Name:, Address:, etc. on separate lines in the text file) but the called variables $lName and $address do not appear.

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  • transforming flat php array into multidimensional one based on key value?

    - by PopRocks4344
    I have a flat array that I'm trying to make multidimensional. Basically, I want to find the items that have parents and create a subarray for that parent id. Right now (and this is simplified), it looks like this: Array ( [0] => stdClass Object ( [id] => 1 [parent] => 0 [name ] => Parent1 ) [1] => stdClass Object ( [id] => 7 [parent] => 1 [name] => Child1 ) [2] => stdClass Object ( [id] => 9 [parent] => 1 [name] => Child2 ) [3] => stdClass Object ( [id] => 2 [parent] => 0 [name ] => Parent2 ) [4] => stdClass Object ( [id] => 88 [parent] => 2 [name] => Childof2 ) ) I'm trying to make this: Array ( [0] => stdClass Object ( [id] => 1 [parent] => 0 [name ] => Parent1 [children] => stdClass Object ( [1] => stdClass Object ( [id] => 7 [parent] => 1 [name] => Child1 ) [2] => stdClass Object ( [id] => 9 [parent] => 1 [name] => Child2 ) ) ) [1] => stdClass Object ( [id] => 2 [parent] => 0 [name ] => Parent2 [children] => stdClass Object ( [0] => stdClass Object ( [id] => 88 [parent] => 2 [name] => Childof2 ) ) ) )

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  • How to get a list of unrepeatable date from my db in PHP?

    - by SzamDev
    Hi in my db there are 5 fields (id, list_date, amount, total, m_from) and contain data, for example : 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/4/2010 - 10 - 50 - 'example154 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/5/2010 - 10 - 50 - 'test' I need to know how I can get dates from list_date but without repeatable dates like '1/1/2010, 1/5/2010, 1/4/2010' Thanks in Advance.

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  • PHP - Why does my computation produce a different result when I assign it to a variable?

    - by David
    I want to round a number to a specific number of significant digits - basically I want the following function: round(12345.67, 2) -> 12000 round(8888, 3) -> 8890 I have the following, but there's a strange problem. function round_to_sf($number, $sf) { $mostsigplace = floor(log10(abs($number)))+1; $num = $number / pow(10, ($mostsigplace-$sf)); echo ($number / pow(10, ($mostsigplace-$sf))).' '.$num.'<BR>'; } round_to_sf(41918.522, 1); Produces the following output: 4.1918522 -0 How can the result of a computation be different when it's assigned to a variable?

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  • CodeIgniter -- unable to use an object

    - by Smandoli
    THE SUMMARY: When I call .../index.php/product, I receive: Fatal error: Call to a member function get_prod_single() on a non-object in /var/www/sparts/main/controllers/product.php on line 16 The offending Line 16 is: $data['pn_oem'] = $this->product_model->get_prod_single($product_id); Looks like I don't know how to make this a working object. Can you help me? THE CODE: In my /Models folder I have product_model.php: <?php class Product_model extends Model { function Product_model() { parent::Model(); } function get_prod_single($product_id) { //This will be a DB lookup ... return 'foo'; //stub to get going } } ?> In my /controllers folder I have product.php: <?php class Product extends Controller { function Product() { parent::Controller(); } function index() { $this->load->model('Product_model'); $product_id = 113; // will get this dynamically $data['product_id'] = $product_id; $data['pn_oem'] = $this->product_model->get_prod_single($product_id); $this->load->view('prod_single', $data); } } ?>

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  • codeigniter cron job with http access

    - by user1313850
    Sorry if this is a duplicate question...I've searched around and found similar advice but nothing that helps my exact problem. And please excuse the noob questions, CRON is a new thing for me. I have a codeigniter script that scrapes the html DOM of another site and stores some of that in a database. I'd like to run this script at a regular interval. This has lead me to looking into cron jobs. The page I have is at myserver.com/index.php/update I realize I can run a cron job with curl and run this page. If I want to be a bit more secure I can put a string at the end like: myserver.com/index.php/update/asdfh2784fufds And check for that in my CI controller. This seems like it would be mostly secure, but doesn't seem like the "right" way to do things. I've looked into running CI from the command line, and can execute basic pages like: php index.php mycontroller But when I try to do: php index.php update It doesn't work. I suspect this is because it needs to use HTTP to scrape the DOM of the outside page. So, my question: How do I securely run a codeigniter script with a cron job that needs HTTP access?

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  • Why did I get a 400 Bad Request when getting a page with PHP Curl?

    - by user307272
    Hi, I was trying to access a page using curl. I could access it perfectly using the browser and using "static" strings as the URL, like: $url = "http://www.example.com/?q=1234" But when I tried to access the page using a variable in the URL string like: $url = "http://www.example.com/?q=$param" I got a 400 error code. I checked out on the web and found some comments here in this stackoverflow thread: Then, just for curiosity I did the following: $url = "http://www.example.com/?q=" . trim($param); and it worked! And no, $param did NOT contain any spaces. To me, it seems that it can be some encoding error, but I really can't find an explanation for it. Does anyone here in stackoverflow know what it can possibly be? Thanks in advance :)

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  • PHP: How do I access child properties from a method in a base object?

    - by Nick
    I'd like for all of my objects to be able to return a JSON string of themselves. So I created a base class for all of my objects to extend, with an AsJSON() method: class BaseObject { public function AsJSON() { $JSON=array(); foreach ($this as $key = $value) { if(is_null($value)) continue; $JSON[$key] = $value; } return json_encode($JSON); } } And then extend my child classes from that: class Package extends BaseObject { ... } So in my code, I expect to do this: $Box = new Package; $Box-SetID('123'); $Box-SetName('12x8x6'); $Box-SetBoxX('12'); $Box-SetBoxY('8'); $Box-SetBoxZ('6'); echo $Box-AsJSON(); But the JSON string it returns only contains the BaseClass's properties, not the child properties. How do I modify my AsJSON() function so that $this refers to the child's properties, not the parent's?

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  • checking is username exists on two tables PHP PDO?

    - by PHPLOVER
    Me again. I have a users table and a users_banlist table. On my registration form i want to check all in one query whether the username someone entered on form exists in the users table and see if it also exists on the users_banlist table. I can do them on there own in individual queries but would rather do it all in one. Here is what i got, but even thou i enter a username that is taken it does not tell me its already taken. $stmt = $dbh->prepare(" SELECT users.user_login, users_banlist.user_banlist FROM users , users_banlist WHERE users.user_login = ? OR users_banlist.user_banlist = ?"); // checker if username exists in users table or users_banlist table $stmt->execute(array($username, $username)); if ( $stmt->rowCount() > 0 ) { $error[] = 'Username already taken'; } Basically i think it is something to do with the execute or rowCount(), could anyone tell me where i am going wrong ? being new to pdo im finding it a little confusing at the moment until i get my pdo book delivered to learn pdo. Thank you as always, phplover

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  • Can a dropdown box using PHP / MySQL automatically select what was last saved in the database with it?

    - by wertz8090
    I am currently working on trying to get a dropdown box to display the most recently saved field each time I open a page for editing an item in an inventory. For example, let's say that my dropdown box selections are Iron, Copper, Gold, Silver, Titanium. The first time the dropdown box loads, I would like it to load in that order (the default order that I set it to). However, once a user submits a form that specifies a selection, I would like that selection to appear as the new default for the dropdown box (for example, if the user picks Gold, Gold will now display as the default). However - the new default that is selected and submitted can only appear for those fields which it is saved under (for example, since the user selected Gold, their preference is now saved as Gold and will appear as such under the field Necklace - however, Gold should not be the default for the fields Ring, Bracelet, and Earring when I open a page to view them). Basically, I need a dropdown box that can save the option of the latest selection on a page after the form is submitted, while at the same time making sure not to affect the default order of the dropdown box across other pages. Your help is much appreciated.

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  • How to get a nicely formatted PHP Web Service response?

    - by Bruno
    I called an API like this: $service = new Class_Service(); $parameters = new GetClasses(); $parameters->Request = new GetClassesRequest(); $parameters->Request->SourceCredentials = new SourceCredentials(); $parameters->Request->SourceCredentials->SourceName = "Name"; $parameters->Request->SourceCredentials->Password = "Pass"; $parameters->Request->SourceCredentials->SiteIDs = array( 12 ); $classes = $service->GetClasses($parameters); var_dump($classes); And received a response like this: object(GetClassesResponse)#7 (1) { ["GetClassesResult"]=> object(GetClassesResult)#8 (6 { ["Classes"]=> object(stdClass)#9 (1) { ["Class"]=> array(25) { [0]=> object(Mi_Class)#10 (21) { ["ClassScheduleID"]=> int(15) ["Visits"]=> NULL ["Clients"]=> NULL ["Location"]=> object(Location)#11 (30) { ["BusinessID"]=> NULL ["SiteID"]=> int(12) ["BusinessDescription"]=> NULL ["AdditionalImageURLs"]=> object(stdClass)#12 (0) { } ["FacilitySquareFeet"]=> NULL Does a response normally look like this? How do I go about getting the data in a formatted manner?

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