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  • alternatyve in php (from java)

    - by Valdas
    I have some problem have class in java. But now need have in php. it's possible rewrite? Code: public class RealityStream { public RealityStream(byte abyte0[]) { m_dstream = null; m_dstream = new DataInputStream(new ByteArrayInputStream(abyte0)); } public int available() throws IOException { return m_dstream.available(); } public float readFloat() throws IOException { byte byte0 = m_dstream.readByte(); byte byte1 = m_dstream.readByte(); byte byte2 = m_dstream.readByte(); byte byte3 = m_dstream.readByte(); int i = (byte3 & 0xff) << 24 | (byte2 & 0xff) << 16 | (byte1 & 0xff) << 8 | byte0 & 0xff; return Float.intBitsToFloat(i); } public int readInt() throws IOException { byte byte0 = m_dstream.readByte(); byte byte1 = m_dstream.readByte(); byte byte2 = m_dstream.readByte(); byte byte3 = m_dstream.readByte(); return (byte3 & 0xff) << 24 | (byte2 & 0xff) << 16 | (byte1 & 0xff) << 8 | byte0 & 0xff; } public int readShort() throws IOException { byte byte0 = m_dstream.readByte(); byte byte1 = m_dstream.readByte(); return byte1 << 8 | byte0 & 0xff; } public int readUnsignedChar() throws IOException { return m_dstream.readUnsignedByte(); } private DataInputStream m_dstream; } very need. very thaks.

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  • Remove polyline

    - by Fran Rod
    I have the next code which show a path using a polyline. How can I remove it? downloadUrl("myfile.asp", function(data) { var xml = xmlParse(data); var markers = xml.documentElement.getElementsByTagName("marker"); var path = []; for (var i = 0; i < markers.length; i++) { var lat = parseFloat(markers[i].getAttribute("lat")); var lng = parseFloat(markers[i].getAttribute("lng")); var point = new google.maps.LatLng(lat,lng); path.push(point); }//finish loop var polyline = new google.maps.Polyline({ path: path, strokeColor: "#FF0000", strokeOpacity: 1.0, strokeWeight: 2 }); polyline.setMap(map); }); //end download url I have tried it using the next function but I m not able to make it work. function removePath() { polyline.setMap(null) }

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  • how to assign the html value to the php variable without post or get method

    - by Meena
    hi , in my program i had a php value $test = 2 using this value i done some operation for example: in my page i had a 2 block A and B and one select box. If the test value is A it enable the div A, if the value is B it hide div A and also i am able to show and hide the div using the select box onchange event. please check my sample code given below $test = $_GET["id"]; <select name="hideme" id="hideme" onchange="enableme();"> <option value="A">Show</option> <option value="B">Hide</option> </select> if($test == 'A') { <div id="div1" name="div1"> xxxxxxxxxxxxx </div> } Js Function : function enableme() { if(document.getElementByID('hideme').value == "A") { document.getElementById.style.display ="block"; } else { document.getElementById.style.display ="none"; } } my issue is at fist time using the $test($_get) value it show the correct div but the on change event is not working because of , if condition. If i remove the if condition then it show div A even if the value of the $test is B. how could i handle both. Please Help me

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  • Send SOAP XML via curl, PHP

    - by danrichardson
    Hi. This has been bugging me for days, i'm trying to send a SOAP post via curl but i just keep getting a 'couldn't connect to host' error but i really cant see how. I have an asp version which works fine with the same url and data, i think it's just a php/curl thing...? I currently have the following code (the CURLOPT_POSTFIELDS data is a valid soap envelope string) $soap_do = curl_init(); curl_setopt($soap_do, CURLOPT_URL, "https://xxx.yyy.com:517/zzz.asmx" ); curl_setopt($soap_do, CURLOPT_CONNECTTIMEOUT, 10); curl_setopt($soap_do, CURLOPT_TIMEOUT, 10); curl_setopt($soap_do, CURLOPT_RETURNTRANSFER, true ); curl_setopt($soap_do, CURLOPT_SSL_VERIFYPEER, false); curl_setopt($soap_do, CURLOPT_SSL_VERIFYHOST, false); curl_setopt($soap_do, CURLOPT_POST, true ); curl_setopt($soap_do, CURLOPT_POSTFIELDS, '<soap:Envelope>...</soap:Envelope>'); curl_setopt($soap_do, CURLOPT_HTTPHEADER, array('Content-Type: text/xml; charset=utf-8', 'Content-Length: '.strlen('<soap:Envelope>...</soap:Envelope>') )); if(curl_exec($soap_do) === false) { $err = 'Curl error: ' . curl_error($soap_do); curl_close($soap_do); return $err; } else { curl_close($soap_do); return 'Operation completed without any errors'; } So any ideas why it just errors all the time? The asp version works fine! The code is; Set xmlhttp = server.Createobject("MSXML2.ServerXMLHTTP") xmlhttp.Open "POST","https://xxx.yyy.com:517/zzz.asmx" xmlhttp.setRequestHeader "Content-Type", "text/xml; charset=utf-8" xmlhttp.Send('<soap:Envelope>...</soap:Envelope>')

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  • How to retrieve Google Blogger feed in ASP.NET medium trust?

    - by ChrisP
    I have an ASP.NET web site hosted at HostMySite.com and they recently changed the shared accounts to run in medium trust. In my web site I query my Blogger account and get blog posts to display on my web site. I am using Google.GData.Client v1.4.0.2 The retrieval works locally (and worked until medium trust was invoked at the ISP). Now I receive the following error: [SecurityException: Request for the permission of type 'System.Net.WebPermission, System, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089' failed.] System.Security.CodeAccessSecurityEngine.Check(Object demand, StackCrawlMark& stackMark, Boolean isPermSet) +0 System.Security.CodeAccessPermission.Demand() +58 System.Net.HttpWebRequest..ctor(Uri uri, ServicePoint servicePoint) +147 System.Net.HttpRequestCreator.Create(Uri Uri) +26 System.Net.WebRequest.Create(Uri requestUri, Boolean useUriBase) +216 System.Net.WebRequest.Create(Uri requestUri) +31 Google.GData.Client.GDataRequest.EnsureWebRequest() +77 Google.GData.Client.GDataRequest.Execute() +42 Google.GData.Client.Service.Query(Uri queryUri, DateTime ifModifiedSince, String etag, Int64& contentLength) +193 Google.GData.Client.Service.Query(FeedQuery feedQuery) +202 I've search the Google documentation and on-line but have not been able to find out what I need to change. Thanks

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  • Sending mail through PHP

    - by Angeline Aarthi
    I'm trying to sends mails in PHP. The code I used for sending a mail in CakePHP is given below. I get the message 'Simple Email Sent' in my web page but the mail is not delivered to my inbox. Am I missing something? The values in the to, subject and link fields are set with the values entered in the user interface. $this->set('to',$this->params['form']['to']); $this->set('subject',$this->params['form']['subject']); $this->set('link',$this->params['form']['link']); $this->Email->to = to; $this->Email->subject = subject; $this->Email->from = '[email protected]'; $this->Email->delivery= 'mail'; $this->Email->sendAs='text'; $this->Email->template = 'simple_message'; //$this->Email->send(link); if ( $this->Email->send(link) ) { $this->Session->setFlash('Simple email sent'); } else { $this->Session->setFlash('Simple email not sent'); }

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  • Weird problem with PHP mail() under Linux.

    - by Vilx-
    This is the case when it "works on my machine". Except that my machine is Windows, and the target is some sort of Linux. The idea is that the mail() function puts a newline between the MIME-Version and Content-Type headers, thus breaking the whole thing. Here's the code, simpliefied as much as possible: <?php $HTMLPart = chunk_split(base64_encode('<html><body style="color: red">Test.</body></html>')); $PlaintextPart = chunk_split(base64_encode('>>> TEST <<<')); $Headers =<<<AKAM From: "My Test" <[email protected]> Reply-To: [email protected] MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="9-1410065408-1410065408=:27514" AKAM; $Body =<<<AKAM This is a multi-part message in MIME format. --9-1410065408-1410065408=:27514 Content-Type: text/plain; charset="windows-1252" Content-Transfer-Encoding: base64 $PlaintextPart --9-1410065408-1410065408=:27514 Content-Type: text/html; charset="windows-1252" Content-Transfer-Encoding: base64 $HTMLPart --9-1410065408-1410065408=:27514-- AKAM; echo 'Try 3: '; echo mail('[email protected]', 'Testmail', $Body, $Headers) ? 'WIN' : 'FAIL'; ?>

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  • Problem with Xpath PHP

    - by user294597
    Im tring to access some links through Google using xpath. The below does works fine and all the links are shown. $query = $xpath->evaluate("/html/body//a"); for ($x=0 ; $x < $query -> length; $x++) { $href=$query->item($x); $url=$href->getAttribute('href'); echo $url."<br>"; } But when i try the below xpath nothing is shown..Im sure that the xpath is correct coz its evaluated and the result is shown in xpather.. /html/body[@id='gsr']/div[@id='cnt']/div[@id='res']/div[1]/ol/li/div//cite for ($x=0 ; $x < $query -> length; $x++) { $href=$query->item($x); $url=$href->getAttribute('cite'); echo $url."<br>"; } can some one please tell me what i am doin wrong? any help will be much appreciated

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  • How to compare two file structures in PHP?

    - by OM The Eternity
    I have a function which gives me the complete file structure upto n-level, function getDirectory($path = '.', $ignore = '') { $dirTree = array (); $dirTreeTemp = array (); $ignore[] = '.'; $ignore[] = '..'; $dh = @opendir($path); while (false !== ($file = readdir($dh))) { if (!in_array($file, $ignore)) { if (!is_dir("$path/$file")) { //display of file and directory name with their modification time $stat = stat("$path/$file"); $statdir = stat("$path"); $dirTree["$path"][] = $file. " === ". date('Y-m-d H:i:s', $stat['mtime']) . " Directory == ".$path."===". date('Y-m-d H:i:s', $statdir['mtime']) ; } else { $dirTreeTemp = getDirectory("$path/$file", $ignore); if (is_array($dirTreeTemp))$dirTree = array_merge($dirTree, $dirTreeTemp); } } } closedir($dh); return $dirTree; } $ignore = array('.htaccess', 'error_log', 'cgi-bin', 'php.ini', '.ftpquota'); //function call $dirTree = getDirectory('.', $ignore); //file structure array print print_r($dirTree); Now here my requirement is , I have two sites The Development/Test Site- where i do testing of all the changes The Production Site- where I finally post all the changes as per test in development site Now, for example, I have tested an image upload in the Development/test site, and i found it appropriate to publish on Production site then i will completely transfer the Development/Test DB detail to Production DB, but now I want to compare the files structure as well to transfer the corresponding image file to Production folder. There could be the situation when I update the image by editing the image and upload it with same name, now in this case the image file would be already present there, which will restrict the use of "file_exist" logic, so for these type of situations....HOW CAN I COMPARE THE TWO FILE STRUCTURE TO GET THE SYNCHRONIZATION DONE AS PER REQUIREMENT??

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  • Trying to match variables in a PHP array

    - by Nick B
    I'm stuck with a php array problem. I've to a webpage that takes values from a URL, and I need to cross reference those values against some values on the page and if they match output a 'yes'. It's an expression engine bodge job. The URL is something like domain.com/page/C12&C14 The C12 and C14 represent different categories. I've taken the last bit of the url, removed the 'C' from the values and then exploded the 12&14 into an array. I print_r the array on the page and it shows: Array ( [0] = 12 [1] = 14 ) So, the values are in the array. Lovely. Now on the page I have an html list which looks like 10 12 14 15 I want to output a YES next to the variables that are current in the array so the ideal output would be: 10 12 - YES 14 - YES 15 I was trying this but it keeps just saying No next to all of them. $currentnumber = 12; foreach ($tharray as $element) { if ($element == $currentnumber) { echo "Yes"; } else { echo "No"; } } I thought that should work, but it's not. I checked and the array and the variable are both stings. I did a strlen() on both to see if they are the same, but $currentnumber outputs '13' and the array variable outputs '2'. Any ideas as to why it's saying 13? Is the variable the wrong type of string - and if so how would I convert it?

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  • php and mysql site design question

    - by Jacksta
    I am trying to build a website with mysql and php. This is the first site I have attempted so I want to write a little plan and get some feedback. The site allows users to add some text in a text field as a “comment”. Once the comment has been entered into the site it is added to the database where it can be voted for by other users. When a new comment has been added to the database it needs to create a new page, e.g. www.xxxxx.com/commentname or www.xxxxxx.com/?id=99981. There will be a list of "Comments" in the database along with the number of votes for each comment. The home page will have two functions. 1) Allow users to add a "comment" 2) Display two tables, each with 20 rows containing most "popular comments" and "recent comments" Each comment will generate its one page where the comment will be displayed. Here users can read the comment and Vote for the comment if they wish. Please help me out by explaining how to do the following. -Generate a new page whenever a comment is added to the database -Add a vote to the vote count in the comment database. -Display the top 20 most popular comments as per number of votes.

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  • Filtering a PHP array containing dates into a yearly summary

    - by privateace
    I'm looking at a way to create a summary of transactions within a certain month based on the contents of a PHP array. Intended outcome (excusing layout): ------------------------------------------- | December 2009 | 12 | | January 2010 | 02 | | February 2010 | 47 | | March 2010 | 108 | | April 2010 | 499 | ------------------------------------------- Based on my array: Array ( [0] => Array ( [name] => 2009-10-23 [values] => Array ( [0] => INzY2MTI4ZWM4OGRm ) ) [1] => Array ( [name] => 2009-10-26 [values] => Array ( [0] => IYmIzOWNmMmU3OWQz ) ) [2] => Array ( [name] => 2009-11-23 [values] => Array ( [0] => INTg4YzgxYWU1ODkx [1] => IMjhkNDZkY2FjNDhl ) ) [3] => Array ( [name] => 2009-11-24 [values] => Array ( [0] => INTg4YzgxYWU1ODkx [1] => INTg4YzgxYWU1ODkx ) ) [4] => Array ( [name] => 2009-12-01 [values] => Array ( [0] => IMWFiODk5ZjU1OTFk ) ) I've had absolutely no luck no matter what I've tried. Especially with adding months that do not contain any variables.

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  • MySQL SELECT Statement not working when executed from PHP

    - by Andrew K
    Hello all, I have the following piece of code, executing a pretty simple MySQL query: $netnestquery = 'SELECT (`nested`+1) AS `nest` FROM `ipspace6` WHERE `id`<='.$adaddr.' AND `subnet`<='.$postmask.' AND `type`="net" AND `addr` NOT IN(SELECT `id` FROM `ipspace6` WHERE `addr`<'.$adaddr.' AND `type`="broadcast") ORDER BY `id`,`subnet` DESC LIMIT 1'; $netnestresults = mysql_query($netnestquery); $netnestrow = mysql_fetch_array($netnestresults); $nestlvl = $netnestrow['nest']; echo '<br> NESTQ: '.$netnestquery; Now, when I execute this in PHP, I get no results; an empty query. However, when I copy and paste the query echoed by my code (for debug purposes) into the mysql command line, I get a valid result: mysql> SELECT (`nested` + 1) AS `nest` FROM `ipspace6` WHERE `id`<=50552019054038629283648959286463168512 AND `subnet`<=36 AND `type`='net' AND `addr` NOT IN (SELECT `id` FROM `ipspace6` WHERE `addr`<50552019054038629283648959286463168512 AND `type`='broadcast') ORDER BY `id`,`subnet` DESC LIMIT 1; +------+ | nest | +------+ | 1 | +------+ 1 row in set (0.00 sec) Can anybody tell me what I'm doing wrong? I can't put quotes around my variables, as then MySQL will try to evaluate the variable as a string, when it is, in fact, a very large decimal. I think I might just be making a stupid mistake somewhere, but I can't tell where.

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  • Php JSON Response Array

    - by Nick Kl
    I have this php code. As you can see i query a mysql database through a function showallevents. I return a the $result to the $event variable. I try to return all rows of the data that i take with the msql_fetch_assoc. I don't get response even when i encode the $response variable. It returns null to all fields. Can anyone help me on what i am doing wrong. I had a valid code but it was returning only 1 row of data so i tried to make an associative array but seems i am failing. if ($tag == 'showallevents') { // Request type is show all events // show all events $event = $db->showallevents(); if ($event != false) { $data = array(); while($row = mysql_fetch_assoc($event)) { $data[] = array( $response["success"] = 1, $response["uid"] = $event["uid"], $response["event"]["date"] = $event["date"], $response["event"]["hours"] = $event["hours"], $response["event"]["store_name"] = $event["store_name"], $response["event"]["event_information"] = $event["event_information"], $response["event"]["event_type"] = $event["event_type"], $response["event"]["Phone"] = $event["Phone"], $response["event"]["address"] = $event["address"], $response["event"]["created_at"] = $event["created_at"], $response["event"]["updated_at"] = $event["updated_at"]); } echo json_encode($data); } else { // event not found // echo json with error = 1 $response["error"] = 1; $response["error_msg"] = "Events not found"; echo json_encode($response); } } else { echo "Access Denied"; } } ?>

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  • DOM manipulation in PHP

    - by bluedaniel
    Hello everyone, Im trying to use the DOM in PHP to do a pretty specific job and Ive got no luck so far, the objective is to take a string of HTML from a Wordpress blog post (from the DB, this is a wordpress plugin). And then out of that HTML replace <div id="do_not_edit">old content</div>" with <div id="do_not_edit">new content</div>" in its place. Saving anything above and below that div in its structure. Then save the HTML back into the DB, should be simple really, I have read that a regex wouldnt be the right way to go here so Ive turned to the DOM instead. The problem is I just cant get it to work, cant extract the div or anything. Help me!! UPDATE The HTML coming out of the wordpress table looks like: Congratulations on finding us here on the world wide web, we are on a mission to create a website that will show off your culinary skills better than any other website does. <div id="do_not_edit">blah blah</div> We want this website to be fun and easy to use, we strive for simple elegance and incredible functionality.We aim to provide a 'complete package'. By this we want to create a website where people can meet, share ideas and help each other out. After several different (incorrect) workings all Ive got below is: $content = ($wpdb->get_var( "SELECT `post_content` FROM $wpdb->posts WHERE ID = {$article[post_id]}" )); $doc = new DOMDocument(); $doc->validateOnParse = true; $doc->loadHTMLFile($content); $element = $doc->getElementById('do_not_edit'); echo $element;

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  • Google AppEngine + Local JUnit Tests + Jersey framework + Embedded Jetty

    - by xamde
    I use Google Appengine for Java (GAE/J). On top, I use the Jersey REST-framework. Now i want to run local JUnit tests. The test sets up the local GAE development environment ( http://code.google.com/appengine/docs/java/tools/localunittesting.html ), launches an embedded Jetty server, and then fires requests to the server via HTTP and checks responses. Unfortunately, the Jersey/Jetty combo spawns new threads. GAE expects only one thread to run. In the end, I end up having either no datstore inside the Jersey-resources or multiple, having different datastore. As a workaround I initialise the GAE local env only once, put it in a static variable and inside the GAE resource I add many checks (This threads has no dev env? Re-use the static one). And these checks should of course only run inside JUnit tests.. (which I asked before: "How can I find out if code is running inside a JUnit test or not?" - I'm not allowed to post the link directly here :-|)

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  • Restrict allowed file upload types PHP

    - by clang1234
    Right now I have a function which takes my uploaded file, checks the extension, and if it matches an array of valid extensions it's processed. It's a contact list importer. What I need to figure out is how to be sure that file (in this case a .csv) is actually what it says it is (ex. not an excel file that just got renamed as a .csv). Our servers run PHP 5.2.13 Here's the current validation function I have public static function validateExtension($file_name,$ext_array) { $extension = strtolower(strrchr($file_name,".")); $valid_extension="FALSE"; if (!$file_name) { return false; } else { if (!$ext_array) { return true; } else { foreach ($ext_array as $value) { $first_char = substr($value,0,1); if ($first_char <> ".") { $extensions[] = ".".strtolower($value); } else { $extensions[] = strtolower($value); } } foreach ($extensions as $value) { if ($value == $extension) { $valid_extension = "TRUE"; } } if ($valid_extension==="TRUE") { return true; } else { return false; } } } }

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  • wordpress php > div issue

    - by Philip Bateman
    Thanks in advance for you help Ive been doing this as a lovejob for friends and now im getting quotes of several hundred dollars for minor homepage variation and I'm not sure if its valid. I'm not a programmer myself, just trying hard :) Via the CafePress press75 theme, I'm trying to go from 1 / 2 / 3 column home layout, to 1-2 merged and 3, push the 2nd column data to the right and have the 1st column span as a 16:9 gallery (nextgengallery plugin installed). Is this really a complex thing from a coding perspective? The current guy talking to me is saying its going to cost $700 or 800 AUD to alter, which is rough when the template cost $85.. From this http://shocolate.com.au.previewdns.com/wp-content/uploads/2010/05/shocolatecurrent.jpg to this 'url+Shocolatelooklikethis.jpg' I was able to get the sidebar removed by taking out ‘‘ near the bottom of home.css.. Just can’t get the middle data to flow over it? This would be ideal as a result, as the system puts the latest selected blog post on the homepage, so if we can get rid of the sidebar div and have the text appear where it was, that would be ideal. Removing the sidebar from the bottom of home.php and setting the thumbnail width to say 450 gives me the result im after EXCEPT the text doesn’t fill where the sidebar is, it wraps underneath. Reference 'shocolate.com.au.previewdns.com' for current site Thank you!!! Phil (Melbourne)

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  • I need to sort php jquery gallery script alphabetically

    - by David Cahill
    know nothing about php, but I have this script that reads a folder and displays a thumbnail gallery, problem is it dosent display alphabetically. Have searched the net and seen that sort does this but have no idea where to start any help would be much appreciated. heres the script $sitename = $row_wigsites['id']; $directory = 'sites/'.$sitename.'/pans'; $allowed_types=array('jpg','jpeg','gif','png'); $file_parts=array(); $ext=''; $title=''; $i=0; $dir_handle = @opendir($directory) or die("There is an error with your image directory!"); while ($file = readdir($dir_handle)) { if($file=='.' || $file == '..') continue; $file_parts = explode('.',$file); $ext = strtolower(array_pop($file_parts)); $title = implode('.',$file_parts); $title = htmlspecialchars($title); $nomargin=''; if(in_array($ext,$allowed_types)) { if(($i+1)%4==0) $nomargin='nomargin'; echo ' <div class="pic '.$nomargin.'" style="background:url('.$directory.'/'.$file.') no-repeat 50% 50%;"> <a href="'.$directory.'/'.$file.'" title="Panoramic Stills taken at '.$title.'°" rel="pan1" target="_blank">'.$title.'</a> </div>'; $i++; } } closedir($dir_handle);

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  • using 'or' operator not working for menu

    - by John Wilkes
    In my code here, I have a CSS class called "active" which I use if the $_GET['page'] == tutorials, php, mysql, etc... The problem is, even if the 'page' variable is not equal to any of these values, the Tutorials button in this case is still active for some reason. Any ideas why this would be happening? Am I using the 'or' (||) operand incorrectly? <?php if($_GET['page'] == 'tutorials' || 'php' || 'mysql' || 'html' || 'css' || 'js') { ?> <li class="active"> <?php } else { ?> <li> <?php } ?> <a href="index.php?page=tutorials">Tutorials</a> <ul> <li><a href="index.php?page=php">PHP</a></li> <li><a href="index.php?page=mysql">MySQL</a></li> <li><a href="index.php?page=html">HTML</a></li> <li><a href="index.php?page=css">CSS</a></li> <li><a href="index.php?page=js">JS</a></li> </ul> </li>

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  • PHP driven site needs password change.

    - by Drea
    I have inherited a website that needs the password changed that accesses the database. I can see that there are two tables within the database but neither of them have username or password info. The previous web guy moved out of the country and can't be reached. I am not up-to-speed enough to figure this out. I have gone through all the files to try and find the answer but can't get it. It's hosted by goDaddy.com and I have changed the passwords there but it didn't change this login info. www.executivehomerents.com/cpanel <-this brings up the prompt for the username & password which I won't give out but the page only gives you 5 choices and none of them deal with changing the password. They are simply to change the data in the tables. If you go to: http://www.websitedatabases.com/ <=this is the company that the PHPMagic program was purchased from-- They have no contact number. Here is another page that might help: http://www.executivehomerents.com/cpanel/dbinput/setup.php I don't think I'll get an answer to this but it's worth a try... thanks.

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  • Dynamically including multiple files within php for image descriptions

    - by Steve Jones
    Working on implementing image descriptions to a php run gallery and can't seem to figure out how to call each text file for each individual image. //total number of images $total = 77; //max number of thumbnails per page $max = 9; //what image do we want to start from? $startcount = $_GET["start"]; //if there is not a defined starting image, we start with the first if(empty($startcount)) { $startcount = 0; } //start off the loop at 1 $loop = 1; //start the loop while($loop <= $max) { //for the picture labels $num = $startcount + $loop; if($num > $total) { $num = $num - 1; break; } // Add class="last" to every third list item if(is_int($num / 3)) { $last = ' class="last"'; } else { $last = ""; } //the code for the image echo ' <li'.$last.'><a href="images/portfolio/pic-'.$num.'.jpg" rel="milkbox[gall1]"><img src="images/portfolio/thumbs/pic-'.$num.'-thumb.jpg" width="256" height="138" alt="Thumbnail of image '.$num.'" /></a><div>'.$num.'</div></li>'; I see that I can call the text files by number using '.$num.' (I have 77 individual text files with a phrase in each) but how do I tell it to call the files?

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  • PHP & MYSQL: How can i neglect empty variables from select

    - by cash-cash
    hello all; if i have 4 variables and i want to select DISTINCT values form data base <?php $var1 = ""; //this variable can be blank $var2 = ""; //this variable can be blank $var3 = ""; //this variable can be blank $var4 = ""; //this variable can be blank $result = mysql_query("SELECT DISTINCT title,description FROM table WHERE **keywords ='$var1' OR author='$var2' OR date='$var3' OR forums='$var4'** "); ?> note: some or all variables ($var1,$var2,$var3,$var4) can be empty what i want: i want to neglect empty fields lets say that $var1 (keywords) is empty it will select all empty fileds, but i want if $var1 is empty the result will be like $result = mysql_query("SELECT DISTINCT title,description FROM table WHERE author='$var2' OR date='$var3' OR forums='$var4' "); if $var2 is empty the result will be like $result = mysql_query("SELECT DISTINCT title,description FROM table WHERE keywords ='$var1' OR date='$var3' OR forums='$var4' "); if $var1 and $var2 are empty the result will be like $result = mysql_query("SELECT DISTINCT title,description FROM table WHERE date='$var3' OR forums='$var4' "); and so on

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  • Lambda Functions in PHP aren't Logical

    - by Chacha102
    Note: I have condensed this article into my person wiki: http://wiki.chacha102.com/Lambda - Enjoy I am having some troubles with Lambda style functions in PHP. First, This Works: $foo = function(){ echo "bar"; }; $foo(); Second, This Works: class Bar{ public function foo(){ echo "Bar"; } Third, This works: $foo = new stdClass; $foo->bar = function(){ echo "bar"; }; $test = $foo->bar; $test(); But, this does not work: $foo = new stdClass; $foo->bar = function(){ echo "bar"; }; $foo->bar(); And, this does not work class Bar{ public function foo(){ echo "Bar"; } $foo = new Bar; $foo->foo = function(){ echo "foo"; }; $foo->foo(); // echo's bar instead of Foo. My Question is Why?, and how can I assure that both this: $foo->bar = function(){ echo "test"; }; $foo->bar(); and this $foo = new Bar; $foo->bar(); are called properly? Extra Points if you can point to documentation stating why this problem occurs.

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