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  • unable to access Bluetooth in emulator

    - by Abhijeet
    I want to run Bluetooth chat apps, but my emulator is unable to switch Bluetooth on . I am using Android 2.2 . The Bluetooth option is not being highlighted in the emulator . Please anyone tell me , how to activate Bluetooth on the emulator . Thanks in advance Abhijeet

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  • What's wrong with this jQuery fading gallery code?

    - by Meep3D
    So I am creating a fading gallery and am a bit of a noob to javascript (but not to programming). I have no idea what is wrong though. Here's the function in question: /* */ function show_next () { // Hide current $('.s_gallery_images li.s_current').fadeTo(200, .2); $('.s_gallery_images li.s_current').css("border","1px green solid"); // if ($('.s_gallery_images li').hasClass ('.s_current')) { console.log ('Incrementing existing'); // Class already exists $('.s_current:first').removeClass('s_current').next().addClass('s_current'); // Was that the last one? if ($('.s_gallery_images li').hasClass ('.s_current')) { console.log ('Current found'); } else { // Class doesn't exist - add to first $('.s_gallery_images li:first').addClass ('.s_current'); console.log ('Wrapping'); } } else { console.log ('Adding new class'); // Class doesn't exist - add to first $('.s_gallery_images li:first').addClass ('.s_current'); } // Show new marked item $('.s_gallery_images li.s_current').fadeTo(200, .8); } The HTML is a very simple: <ul class="s_gallery_images"> <li><img src="imagename" alt="alt" /></li> <li><img src="imagename" alt="alt" /></li> <li><img src="imagename" alt="alt" /></li> </ul> And it displays the list and the images fine. I am using firebugs console.log for debugging, plus have a class set for s_current (bright border) but nothing happens at all. The firebug console log says: Adding New Class Incrementing Existing Current Found Incrementing Existing Current Found Incrementing Existing Current Found Incrementing Existing Current Found ... to infinity The function is called on a setInterval timer, and as far as I can tell it should be working (and I have done something similar before), but it just isn't happening :(

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  • Python and Unicode: How everything should be Unicode

    - by A A
    Forgive if this a long a question: I have been programming in Python for around six months. Self taught, starting with the Python tutorial and then SO and then just using Google for stuff. Here is the sad part: No one told me all strings should be Unicode. No, I am not lying or making this up, but where does the tutorial mention it? And most examples also I see just make use of byte strings, instead of Unicode strings. I was just browsing and came across this question on SO, which says how every string in Python should be a Unicode string. This pretty much made me cry! I read that every string in Python 3.0 is Unicode by default, so my questions are for 2.x: Should I do a: print u'Some text' or just print 'Text' ? Everything should be Unicode, does this mean, like say I have a tuple: t = ('First', 'Second'), it should be t = (u'First', u'Second')? I read that I can do a from __future__ import unicode_literals and then every string will be a Unicode string, but should I do this inside a container also? When reading/ writing to a file, I should use the codecs module. Right? Or should I just use the standard way or reading/ writing and encode or decode where required? If I get the string from say raw_input(), should I convert that to Unicode also? What is the common approach to handling all of the above issues in 2.x? The from __future__ import unicode_literals statement? Sorry for being a such a noob, but this changes what I have been doing for a long time and so clearly I am confused.

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  • how to programatically determine Bluetooth master/slave roles?

    - by Rich
    So in a bluetooth piconet, there is one master with upto seven slaves. The master sets the clock and frequency hop that the slaves sync with. But is there a way to determine which device is the master and which is the slave? I'm mainly interested in portable devices (Android,iPhone) but beggars can't be choosers, if anybody has info in this field I would be interested. Thanks

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  • Easiest RPC client method in PHP

    - by T.K.
    I've been asked to help a friend's company to bring up a web application. I have very limited time and I reluctantly accepted the request, at one condition. As most of the logic goes on in the back-end, I suggested that I would finish the complete back-end only, allowing a front-end developer to simply interface with my backend. I plan to do the back-end in Java EE or Python (with Pylons). It does not really matter at this point. I plan to have my back-end completely ready and unit-tested, so that my input will hardly be needed after my work is done. I know they have a PHP programmer, but as far as I could tell he is a real rookie. I want him to basically interface with my backend's services in the easiest possible way, with no way of him "stuffing" it up. It's basically a CRUD-only application. I could implement the backend as accessible through a webservice such as XML-RPC or SOAP. Even a RESTful API could be possible. However, my main objective is to make something that complete "noob" PHP programmer can easily interface with without getting confused. Preferably I do not even want to talk to him because I generally have an extremely busy schedule, and doing "support calls" is not something I am willing to do. Which approach should I choose? I would welcome any suggestions and inputs!

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  • User Management: Managing users in user-defined "groups", database schema and logistics

    - by Kevin Brown
    I'm a noob, development wise and logistically-wise. I'm developing a site that lets people take a test... My client wants the ability for a user with the roll/privledge "admin" (a step below a super-admin) to be allowed to create users and only see/edit the users that they create... The users created in that "category" or group need some information that their superior provides. For example, I log in as a "manager", I have the ability to invite people to take the test, and manage those people. Before adding those people, I will have filled out a short survey about myself... Right now, the users that are invited will be asked some of the same questions as the manager. I'd like to cut down the redundancy by using the information put into the database by the manager and apply it to the invited users. How do I set up my database to work with this criterion? I'm a little confused about how to do this! Let me know if I can add more details... (This is a mysql and php app)

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  • Concatenate CLOB-rows with PL/SQL

    - by david K
    Hi, I've got a table which has an id and a clob content like: Create Table v_example_l ( nip number, xmlcontent clob ); We insert our data: Insert into V_EXAMPLE_L (NIP,XMLCONTENT) Values (17852,'<section><block><name>delta</name><content>548484646846484</content></block></section>'); Insert into V_EXAMPLE_L (NIP,XMLCONTENT) Values (17852,'<section><block><name>omega</name><content>545648468484</content></block></section>'); Insert into V_EXAMPLE_L (NIP,XMLCONTENT) Values (17852,'<section><block><name>gamma</name><content>54564846qsdqsdqsdqsd8484</content></block></section>'); I'm trying to do a function that concatenates the rows of the clob that gone be the result of a select, i mean without having to give multiple parameter about the name of table or such, i should only give here the column that contain the clobs, and it should handle the rest. CREATE OR REPLACE function assemble_clob(q varchar2) return clob is v_clob clob; tmp_lob clob; hold VARCHAR2(4000); --cursor c2 is select xmlcontent from V_EXAMPLE_L where id=17852 cur sys_refcursor; begin OPEN cur FOR q; LOOP FETCH cur INTO tmp_lob; EXIT WHEN cur%NOTFOUND; --v_clob := v_clob || XMLTYPE.getClobVal(tmp_lob.xmlcontent); v_clob := v_clob || tmp_lob; END LOOP; return (v_clob); --return (dbms_xmlquery.getXml( dbms_xmlquery.set_context("Select 1 from dual")) ) end assemble_clob; The function is broken... (if anybody could give me a help, thanks a lot, and i'm noob in sql so ....). Thanks!

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  • UITableViewCell imageView images loading small even when they are the correct size!

    - by Alex Barlow
    Im having an issue whilst loading images into a UITableViewCell after an asynchronous download and placement into an UIImage variable.. The images appear smaller than they actually are! But when scrolled down and scrolled back up to the image, or the whole table is reloaded, they appear at the correct size... Here is a code excerpt... - (void)reviewImageDidLoad:(NSIndexPath *)indexPath { ThumbDownloader *thumbDownloader = [imageDownloadsInProgress objectForKey:indexPath]; if (thumbDownloader != nil) { UITableViewCell *cell = [self.tableView cellForRowAtIndexPath:thumbDownloader.indexPathInTableView]; [UIView beginAnimations:nil context:nil]; [UIView setAnimationDuration:0.4]; [self.tableView cellForRowAtIndexPath:indexPath].imageView.alpha = 0.0; [UIView commitAnimations]; cell.imageView.image = thumbDownloader.review.thumb; [UIView beginAnimations:nil context:nil]; [UIView setAnimationDuration:0.4]; [self.tableView cellForRowAtIndexPath:indexPath].imageView.alpha = 1.0; [UIView commitAnimations]; } } Here is an image of the app just after calling this method.. http://www.flickr.com/photos/arbarlow/5288563627/ After calling tableView reloadData or scrolling around the appear correctly, go the the next flickr image, to see the normal result, but im sure you can guess that.. Does anyone have an ideas as to make the images appear correctly? im absolutely stumped?! Regards, Alex iPhone noob

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  • ipad tabbar rotation

    - by MaKo
    hi, please help with this noob questions but really making me go crazy if I create a project from scratch (using windows based app) for the ipad, and add a tabbar , with firstviewController, and secondviewController, it works fine, starts in landscape mode, but in info.plist I set it to Landscape(left home button), but really in simulator starts with the button on the right side! in the FirstViewController.m (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { if (interfaceOrientation == UIInterfaceOrientationLandscapeLeft || interfaceOrientation == UIInterfaceOrientationLandscapeRight) return YES; else { return NO; }} so it starts in landscape, and rotates as the simulator rotates, but if I create a template app for iphone tabbar, set the info.plist Initial interface orientation Landscape (left home button) and add the code above, IT DOESNT WORK!!! simulator starts with button at left but tab bar on the side, same problem that I had with an app that Im porting from iphone to ipad, (landscape intended) I get to the landscape start mode, but the tab bar remains on the side! also the only way to make the old ported app to show the simulator on the side was with UIInterfaceOrientation UIIntefaceOrientationLandscapeLeft (didnt work with Initial interface orientation), does not let me choose the value for the key, but it shows the simulator on landscape,, so,, what can I do please to show the tab bar on landscape mode??? the tabbar from scratch was made to see if the code will work , but it didnt?? why does it work in the tab bar made from windows app and not tab bar app? I just want the tab bar to show in landscape ahhh, thanks

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  • Public code repository

    - by Andy White
    Can anyone recommend a public code repository? A few friends and I are thinking of starting a few projects for iPhone, web, Android, etc., and it would be nice to have a public (internet) code repository to use that would work well on any platform (Mac, PC, Linux). Any type of repository is fine (SVN, CVS, Git, etc.). A few ideas are Sourceforge or Google Code. Any recommendations? Thanks

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  • ObjectiveFlickr - how to call getSizes on a photo ID not known until the response?

    - by Jonathan Cohen
    Hi guys, I'm building a free music instrument iPhone app with the Flickr API and ObjectiveFlickr.A random photo from the interestingness list is displayed in the background, but I can't center it without knowing its size. (so I can reset the UIWebView frame) I've been researching this for awhile, and if the answer is super easy, please have some mercy on a noob - it's my first time playing with a web service API. =) Since I don't know the photo ID until after I receive the response from the interestingness feed, how would I call flickr.photo.getSizes on the response? This is what I have so far: - (void)flickrAPIRequest:(OFFlickrAPIRequest *)inRequest didCompleteWithResponse:(NSDictionary *)inResponseDictionary{ int randomResponse = arc4random() % 49; photoDict = [[inResponseDictionary valueForKeyPath:@"photos.photo"] objectAtIndex:randomResponse]; NSString *photoID = [photoDict valueForKeyPath:@"id"]; NSLog(@"%@",photoID); NSURL *photoURL = [flickrContext photoSourceURLFromDictionary:photoDict size:OFFlickrMediumSize]; NSString *htmlSource = [NSString stringWithFormat: @"<html>" @"<head>" @" <style>body { margin: 0; padding: 0; } </style>" @"</head>" @"<body>" @"<img src=\"%@\" />" @"</body>" @"</html>" , photoURL]; [webView loadHTMLString:htmlSource baseURL:nil]; }

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  • What makes this "declarator invalid"? C++

    - by nieldw
    I have Vertex template in vertex.h. From my graph.h: 20 template<class edgeDecor, class vertexDecor, bool dir> 21 class Vertex; which I use in my Graph template. I've used the Vertex template successfully throughout my Graph, return pointers to Vertices, etc. Now for the first time I am trying to declare and instantiate a Vertex object, and gcc is telling me that my 'declarator' is 'invalid'. How can this be? 81 template<class edgeDecor, class vertexDecor, bool dir> 82 Graph<edgeDecor,int,dir> Graph<edgeDecor,vertexDecor,dir>::Dijkstra(vertex s, bool print = false) const 83 { 84 /* Construct new Graph with apropriate decorators */ 85 Graph<edgeDecor,int,dir> span = new Graph<edgeDecor,int,dir>(); 86 span.E.reserve(this->E.size()); 87 88 typename Vertex<edgeDecor,int,dir> v = new Vertex(INT_MAX); 89 span.V = new vector<Vertex<edgeDecor,int,dir> >(this->V.size,v); 90 }; And gcc is saying: graph.h: In member function ‘Graph<edgeDecor, int, dir> Graph<edgeDecor, vertexDecor, dir>::Dijkstra(Vertex<edgeDecor, vertexDecor, dir>, bool) const’: graph.h:88: error: invalid declarator before ‘v’ graph.h:89: error: ‘v’ was not declared in this scope I know this is probably another noob question, but I'll appreciate any help.

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  • Java Speech recognition api

    - by jaymin
    HI, i am currently developing an android application where i am required to implement speech recognition...could u suggest a link where i could find a java speech recognition API...? Thanks

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  • Clearly defined Rails routing problem - undefined method for Nil:NilClass

    - by sscirrus
    Guys and girls, I have been working on this problem for a while but still no joy. This is my second question within this general area, because the last question was getting too long and this is now more well-defined. Summary of the Problem: I am loading a page for my customers and I get error: undefined method 'name' for Nil:NilClass My Code #Link on views/users/show.html.erb: <%= link_to "Customer Account", :action => "home", :controller => "customers", :id => @user.user_type_id %> #Regular Route: map.connect 'customers/home/:id', :controller => 'customers', :action => 'home' #Rake Routes, first entry: /customers/home/:id :controller=>:"customers", :action=>"home" #Customers Controller: def home render :layout => 'home' @customer = Customer.find(params[:id]) @user = @current_user_session.user flash[:error] = "Customer not found" and return unless @customer @jobs = @customer.jobs end #views/customers/home.html.erb: <%= @customer.name %> I have absolutely no idea why this seemingly clear sequence of events is resulting in a NilClass. Search the console for Customer.find(2) returns the correct customer. What is this noob missing? Thank you very much.

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  • Rewrite a URL that's already been redirected?

    - by Jack
    Hi guys, I'm running an Apache2 web server with a dynamic IP address. I bought exampledomain.net, and I use no-ip.com's domain-update service to redirect any visitors to my current ip address (endnote #1). For example, someone visits exampledomain.net and they get redirected to 73.181.57.34. It works like a charm. However, it isn't all that user-friendly. Can I rewrite the redirected, ip-address URL? I tried these rewrite rules in the root folder's .htaccess... RewriteEngine On RewriteCond %{HTTP_HOST} ^73\.181\.57\.34:88 RewriteRule ^(.*)$ http://www.exampledomain.net/$1 [L,NC] # I simplified the RewriteCond. I would use regex in a real situation. Of course, this creates an infinite loop. The user visits www.exampledomain.net. They're redirected to 73.181.57.34:88 by no-ip. Apache redirects them to www.exampledomain.net which redirects them back to 73.181.57.34:88... so on and so forth. I'm a noob when it comes to rewriting, but is there a way to rewrite a URL without redirecting? I tried these rewrite rules too (a shot in the dark)... RewriteEngine On RewriteCond %{HTTP_HOST} ^73\.181\.57\.34:88 RewriteRule ^(.*)$ my.exampledomain.net/$1 [L,NC] # I'd read that Apache replied with a redirect header when you include http Thanks! (1) No-IP works like this: You download and install their dynamic update client on your server. Every couple of minutes it polls your server for its current external ip address. If it's changed, it updates your server's ip address in no-ip's records.

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  • unique items from an observableArray of object properties

    - by Joe
    I'm trying to extract unique properties from a knockout.js observableArray of objects, to populate a drop menu. Being new to knockout, I'm really struggling with this! I want to iterate over a contacts list, and populate a drop menu with a unique value from each person object within the observableArray. So in my code example below, I wish to populate my drop menu with a list of people 'type' - family, friend etc. Looking on Google, I found a similar function, but it does not return any values, even if I console.log the results? //dummy data more rows in actual code... var people = [ { name: "Contact 1", address: "1, a street, a town, a city, AB12 3CD", tel: "0123456789", email: "[email protected]", type: "family" }, { name: "Contact 2", address: "1, a street, a town, a city, AB12 3CD", tel: "0123456789", email: "[email protected]", type: "friend" } ]; function ContactsViewModel(people) { var self = this; self.contacts = ko.observableArray(people); self.uniqueSelect = ko.dependentObservable(function() { return( ko.utils.arrayGetDistinctValues(self.contacts().type).sort()); }, self); }; ko.applyBindings(new ContactsViewModel()); And HTML template <p>Show me: <select data-bind="options: ContactsViewModel.uniqueSelect"></select></p> Any help appreciated, as a noob I'm lost! Thanks

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  • How to Send Headers Through PHP Proxy?

    - by blabus
    Okay, so I have an issue with an AJAX request. I currently have this URL: http://www.google.com/images?hl=en&safe=off&gbv=2&tbs=isch%3A1&sa=1&q=cars+imagesize%3A500x500&aq=f&aqi=&aql=&oq=&gs_rfai=&start=0 I then pass it to my proxy script by modifying the string to this: proxy.php?url=http://www.google.com/images?hl=en&safe=off&gbv=2&tbs=isch%3A1&sa=1&q=cars+imagesize%3A500x500&aq=f&aqi=&aql=&oq=&gs_rfai=&start=0 I need to use the PHP proxy script to grab that page's HTML so that I can then parse through it with javascript. However, the problem is that the headers in that URL are also being sent to the proxy script, and as a result, I get a 'malformed or illegal request' error. I'm pretty sure the two different sets of headers are the problem, because if I just replace the original URL string with 'http://wwww.google.com', the proxy returns the HTML of the page correctly. So basically, I don't know how to fix this. I'm a complete PHP noob, and I tried escaping the original URL before I appended it to the 'proxy.php?url=', but that doesn't fix anything. Any ideas? Thanks!

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  • How to learn how to program?

    - by twinbornJoint
    I would like to know the best methods for learning to program. I've been directed towards the Python language because I was told it is good for beginners. I ultimately want to make games for OS X/iPhone. My problem is that I understand what I read but I can't apply my knowledge to anything. I am a programming noob. Should I stick with Python? (is there a better language I should be learning?) Where can I learn programming theory? I get very hyper when reading my book sometimes, any tips on staying calm and focusing? What are effective ways to learn how to program? Are there standard exercises for programming? (I feel solving problems helps my understanding immensely) Ultimately I feel like I am in a never ending tunnel that leads me no where. It feels like I am just completely unable to pursue anything in the world of programming, yet it is something I want to do very much. Thanks.

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  • Controlling usb devices from a droid?

    - by user324721
    Anyone know where I can find information on how I can control the USB port on a Droid running Android 2.0? I want to know how to either initialize the USB port or send data across it vi a program. I want to be able to atatch a device to the USB port to act as a switch to control a microservo. So when I said "send data" across the port, I just need to be able to energize the transmit pin on the USB to turn the servo on. Thanks ahead, Tom

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  • open iphone google maps with back button

    - by christian
    Hi, i have a webview in my iphone app where a google map location is opened like; Directions now the google map native app opens fine, but how could i add a RETURN button so it would jump back to my html page. Now i have to click my home button and the app close back to the desktop, so i have to start my webview again. in android its more easy, because there is always a back button and after viewing my gmap i simply back in my webview. thx chris

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  • URL conventions for Maps on Windows Phone 7

    - by Stan Wiechers
    What is the best practice for opening a map from the mobile internet explorer on windows phone 7? On BlackBerry you use a JavaScript method and on Android/iOS you simply link to a google maps URL. I am planning to integrate the different ways of opening maps into my mobile geo javascript library and don't have a windows phone device. http://code.google.com/p/geo-location-javascript/ Thanks, Stan Wiechers

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