change password - Page 455

CreateProcessWithLogonW : unable to start process

- by Vivek

Hi I am completely new to programming. And please someone help me. I am trying to start a pocess from a service. I need to start the new process by prompting user to enter admin credentials. I was trying to use CreateProcessWithLogonW(). Am I using the right function. I tried to give input username, password, domain as localhost. I gave full pathe to the .exe file that i need to start. Here is the piece of code. CreateProcessWithLogonW(L"Administrator", L"localhost", L"password", 0, NULL, L"c:\myupdates\myapp.exe", NORMAL_PRIORITY_CLASS | CREATE_CONSOLE, NULL, NULL, &si, &pi); Si.cb = sizeof(si); Si.lpDesktop = L"winsta0\\default"; But the process never started. Can you guys tell me what I am doing wrong. And what do I need to do to promt user to enter credentials of administrator instead of hardcoding it.

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JLabel transparency problem

- by Rendicahya

I have a dark-gray JPanel with a JLabel on it. I set new Color(0, 0, 0, .5f) (tranparent) as the background of the JLabel and I change the text several times using a button. The problem is, everytime the text is changed, the previous text still remains behind the new text. I change the text from "123456789" to "1234567", "12345" and "123". Here is the screenshot: How do I get rid of this "shadow"? Here's the code: public class TransparentJLabel extends JFrame { private int i = 0; private String[] value = {"123456789", "1234567", "12345", "123", "1"}; public TransparentJLabel() { setSize(300, 160); setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE); setLayout(null); JPanel panel = new JPanel(); panel.setBackground(new Color(102, 102, 102)); panel.setLayout(null); panel.setBounds(0, 0, 300, 160); final JLabel label = new JLabel(); label.setText(value[0]); label.setFont(new Font("Times New Roman", 1, 36)); label.setForeground(new Color(255, 255, 255)); label.setBackground(new Color(0, 0, 0, .5f)); label.setHorizontalAlignment(SwingConstants.CENTER); label.setOpaque(true); label.setBounds(10, 10, 270, 70); JButton button = new JButton(); button.setText("Change"); button.setBounds(100, 90, 90, 25); button.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent e) { label.setText(value[++i]); } }); panel.add(label); panel.add(button); add(panel); } public static void main(String[] args) { EventQueue.invokeLater(new Runnable() { public void run() { new TransparentJLabel().setVisible(true); } }); } }

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Retrieve nested list from XDocument with LINQ

- by twreid

Ok I want my link query to return a list of users. Below is the XML <section type="Users"> <User type="WorkerProcessUser"> <default property="UserName" value="Main"/> <default property="Password" value=""/> <default property="Description" value=""/> <default property="Group" value=""/> </User> <User type="AnonymousUser"> <default property="UserName" value="Second"/> <default property="Password" value=""/> <default property="Description" value=""/> <default property="Group" value=""/> </User> </section> And my current LINQ Query that doesn't work. doc is an XDocument var users = (from iis in doc.Descendants("section") where iis.Attribute("type").Value == "Users" from user in iis.Elements("User") from prop in user.Descendants("default") select new { Type = user.Attribute("type").Value, UserName = prop.Attribute("UserName").Value }); This does not work can anyone tell me what I need to fix? Here is my second attempt after fixing for the wrong property name. However this one does not seem to enumerate the UserName value for me when I try to use it or at least when I try to write it to the console. Also this returns 8 total results I should only have 2 results as I only have 2 users. (from iis in doc.Descendants("section") where iis.Attribute("type").Value == "Users" from user in iis.Elements("User") from prop in user.Descendants("default") select new { Type = user.Attribute("type").Value, UserName = (from name in prop.Attributes("property") where name.Value == "UserName" select name.NextAttribute.Value).ToString() });

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Skip subdirectory in python import

- by jstaab

Ok, so I'm trying to change this: app/ - lib.py - models.py - blah.py Into this: app/ - __init__.py - lib.py - models/ - __init__.py - user.py - account.py - banana.py - blah.py And still be able to import my models using from app.models import User rather than having to change it to from app.models.user import User all over the place. Basically, I want everything to treat the package as a single module, but be able to navigate the code in separate files for development ease. The reason I can't do something like add for file in __all__: from file import * into init.py is I have circular references between the model files. A fix I don't want is to import those models from within the functions that use them. But that's super ugly. Let me give you an example: user.py ... from app.models import Banana ... banana.py ... from app.models import User ... I wrote a quick pre-processing script that grabs all the files, re-writes them to put imports at the top, and puts it into models.py, but that's hardly an improvement, since now my stack traces don't show the line number I actually need to change. Any ideas? I always though init was probably magical but now that I dig into it, I can't find anything that lets me provide myself this really simple convenience.

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Error after redirection using CakePHP

- by Praveen kalal

I have created some code called LoginController. Whenever Admin gets successfully logged in I redirect the page to index. However, I got an error like "problem on loading page". This is my code: <?php class LoginController extends AdminAppController { var $name = 'Login'; var $uses = array('Admin.Login'); var $sessionkey= ''; /*function beforeFilter() { if($this->Session->read('user')=='Admin' || $this->params['action']=='login') { echo "in"; exit; } else { echo "else"; exit; $this->Session->setFlash('Login first','flash_failure'); $this->redirect(array('action'=>'login')); } }*/ function index() { } function login() { //pr($this->data); exit; if(!empty($this->data)) { $results = $this->Login->findByEmail($this->data['Login']['email']); if(!empty($results) && $results['Login']['password']== md5($this->data['Login']['password'])) { $this->Session->write('user', 'Admin'); $results['Login']['last_login']=date("Y-m-d H:i:s"); $this->Login->save($results); $this->Session->setFlash('Login successfully.', 'flash_success'); $this->redirect(array('controller'=>'login','action' => 'index')); } } } } ?> Can anyone help me? Thanks.

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zend_db and join

- by premtemp

Hello, I am trying to understand how to use Zend_DB in my program but I have some problem. The class below (DatabaseService) work when I pass it a simple query. However, if I pass it it query with a join clause my page just hangs and not error is return. I cut and paste the qry in a query browesr and it is valid Any help would be great $SQL = "select name from mytable" $db = new DatabaseService($dbinfo) $db ->fetchall($SQL ) // works ----------------------------------------------------------- $SQL = "select count(*) as cnt from EndPoints join CallID on EndPoints.`CallID` = CallID.CallID where EndPoints.LastRegister >= '2010-04-21 00:00:01' and EndPoints.LastRegister <= '2010-04-21 23:59:59' " $db = new DatabaseService($dbinfo) $db ->fetchall($SQL ) // DOES NO WORK class DatabaseService { function DatabaseService($dbinfo,$dbname="") { try { $dbConfig = array( 'host' => $this->host, 'username' => $this->username, 'password' => $password, 'dbname' => $this->dbname ); $this->db = Zend_Db::factory($this->adapter, $dbConfig); Zend_Db_Table::setDefaultAdapter($this->db); } catch(Zend_Exception $e) { $this->error = $e->getMessage(); Helper::log($this->error); return false; } } public function connnect() { if($this->db !=null) { try { $this->db->getConnection(); return true; } catch (Zend_Exception $e) { $err = "FAILED ::".$e->getMessage()." <br />"; } } return false; } public function fetchall($sql) { $res= $this->db->fetchAll($sql); return $res; } }

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java.lang.ClassNotFoundException: com.mysql.jdbc.Driver When run jar file

- by user1024858

Hi all, Connection conn = null; String url = "jdbc:mysql://localhost:3306/"; String dbName = "test"; String driver = "com.mysql.jdbc.Driver"; String userName = "root"; String password = "admin"; try { Class.forName(driver).newInstance(); conn = DriverManager.getConnection(url+dbName,userName,password); System.out.println("Connected to the database"); conn.close(); System.out.println("Disconnected from database"); } catch (Exception e) { e.printStackTrace();} I run in eclipse it's ok, but i built to jar file and run on command line java -jar Test.jar i get this error: java.lang.ClassNotFoundException: com.mysql.jdbc.Driver at java.net.URLClassLoader$1.run(Unknown Source) at java.net.URLClassLoader$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Unknown Source) Please help me how to fix it. Thanks!!!

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Windows "forms" authentication - <deny users="?"> redirecting to foreign page!

- by Erik5388

Like the title states - I have a web.config file that looks like, <?xml version="1.0" encoding="UTF-8"?> <configuration> <system.web> <compilation debug="true" targetFramework="4.0" /> <authentication mode="Forms"> <forms name="login" protection="All" timeout="30" loginUrl="login" defaultUrl="~/"> <credentials passwordFormat="Clear"> <user name="admin" password="password" /> </credentials> </forms> </authentication> <authorization> <deny users="?" /> </authorization> </system.web> </configuration> I want to do exactly what it says it should do... I want to deny all users who try to enter the site. It works however, it redirects to a "Account/Login?ReturnUrl=%2flogin" url I have never heard of... Is there a place I can change this?

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Emacs: Often switching between Emacs and my IDE's editor, how can I 'synch' the file?

- by WizardOfOdds

I very often need to do some Emacs magic on some files and I need to go back and forth my IDE (IntelliJ IDEA) and Emacs. When a change is made under Emacs (and after I've saved the file) and I go back to IntelliJ the change appears immediately (if I recall correctly I configured IntelliJ to "always reload file when a modification is detected on disk" or something like that). I don't even need to reload: as soon as IntelliJ IDEA gains focus, it instantly reloads the file (and I hence have immediately access to the modifications I made from Emacs). So far, so very good. However "the other way round", it doesn't work yet. Can I configure Emacs so that everytime a file is changed on disk it reloads it? Or make Emacs, everytime it "gains focus", verify if any file currently opened has been modified on disk? I know I can start modifying the buffer under Emacs and it shall instantly warn that it has been modified, but I'd rather have it do it immediately (for example if I used my IDE to do some big change, when I come back to Emacs what I see may not be at all anymore what the file contains and it's a bit weird).

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JavaScript: Changing src-attribute of a embed-tag

- by Mike

I have the following scenario. I show the user some audio files from the server. The user clicks on one, then onFileSelected is eventually executed with both the selected folder and file. What the function does is change the source from the embedded object. So in a way, it is a preview of the selected file before accepting it and save the user's choice. A visual aid. HTML <embed src="/resources/audio/_webbook_0001/embed_test.mp3" type="audio/mpeg" id="audio_file"> JavaScript function onFileSelected(file, directory) { jQuery('embed#audio_file').attr('src', '/resources/audio/'+directory+'/'+file); }; Now, this works fine in Firefox, but Safari and Chrome simply refuse to change the source, regardless of Operating System. jQuery finds the object (jQuery.size() returns 1), it executes the code, but no change in the HTML Code. Why does Safari prevent me from changing the <embed> source and how can I circumvent this?

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Why changing the images name on server results in calling the old ones?

- by moderns

I am running a slideshow on Ubuntu 12.04.1 that loads the images (slide1.jpg, slide2.jpg, slide3.jpg.., slide5.jpg) using the Javascript and styles as below: document.getElementById('slide_area').className='slide'+step; .slide1{background-image: url(../upload/slide1.jpg)} .slide2{background-image: url(../upload/slide2.jpg)} .slide3{background-image: url(../upload/slide3.jpg)} .slide4{background-image: url(../upload/slide4.jpg)} .slide5{background-image: url(../upload/slide5.jpg)} When I change the images names (show1.jpg, show2.jpg, show3.jpg.., show5.jpg) and also change the style as below: .slide1{background-image: url(../upload/show1.jpg)} .slide2{background-image: url(../upload/show2.jpg)} .slide3{background-image: url(../upload/show3.jpg)} .slide4{background-image: url(../upload/show4.jpg)} .slide5{background-image: url(../upload/show5.jpg)} And open the network section on Chrome, I see the server is calling the new name and old name for images! I added the header in the index.php: header("Cache-Control: no-store, no-cache, must-revalidate, max-age=0"); header("Expires: Sat, 26 Jul 1997 05:00:00 GMT"); // Date in the past header("Cache-Control: post-check=0, pre-check=0", false); header("Pragma: no-cache"); Nothing worked out with me and the slideshow doesn't work properly when I change the name of images even when clearing the browser cache as I load images sequentially (one by one) depending on imageObject.complete property! But without changing the name everything is going perfect and the images are loaded smoothly! Thank you for your help!

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How does an ASP.NET programmer go from working on/developing existing sites, to creating one from sc

- by SLC

I've been an ASP.NET developer for some time, always working on existing ASP.NET pages, modifying functionality, adding features, tweaking things etc. but have never built a site up from scratch. I've read books on ASP.NET, and they generally talk you through the various features of ASP.NET with a mock up site, but it's always very basic and they jump straight in. The time has come however, to write a site from scratch for a client. I've never done this before. There are design considerations, but like a lot of ASP.NET sites, the basic idea is, you have a site, where users can log in, and save some information like their name and password and address. The site has some functionality, but that's the basic design of a majority of (business-related) asp.net websites I would wager. I know how to program in ASP.NET already on an existing site, but I don't know how to design my own properly that meets the criteria above. I guess the main worry is security. I don't know the best way to handle a simple log-in system that stores user information like their name and password. I understand there are a few approaches to this, but the catch with this project is that it has to be absolutely bulletproof. Maximum security. All those good practices for security, it needs to have them all. I'm not asking what they are, but I am asking where to begin. What should be the first steps after I do File New Project ? Where can I look for information about setting up a secure ASP.NET website? I'll figure out the content and page layout later, it's the framework that is the big thing. Any and all advice would be welcome. I really want to get my first from-scratch project right from the beginning. Just to confuse things, it's possible I will be using MVC, I am not sure if this has any impact.

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Create 2nd tables and add data

- by Tyler Matema

I have this task from school, and I am confuse and lost on how I got to do this. So basically I have to create 2 tables to the database but I have to created from php. I have created the first table, but not the second one for some reason. And then, I have to populate first and second tables with 10 and 20 sample records respectively, populate, does it mean like adding more fake users? if so is it like the code shown below? *I got error on the populating second part as well Thank you so much for the help. <?php $host = "host"; $user = "me"; $pswd = "password"; $dbnm = "db"; $conn = @mysqli_connect($host, $user, $pswd, $dbnm); if (!$conn) die ("<p>Couldn't connect to the server!<p>"); $selectData = @mysqli_select_db ($conn, $dbnm); if(!$selectData) { die ("<p>Database Not Selected</p>"); } //1st table $sql = "CREATE TABLE IF NOT EXISTS `friends` ( `friend_id` INT NOT NULL auto_increment, `friend_email` VARCHAR(20) NOT NULL, `password` VARCHAR(20) NOT NULL, `profile_name` VARCHAR(30) NOT NULL, `date_started` DATE NOT NULL, `num_of_friends` INT unsigned, PRIMARY KEY (`friend_id`) )"; //2nd table $sqlMyfriends = "CREATE TABLE `myfriends` ( `friend_id1` INT NOT NULL, `friend_id2` INT NOT NULL, )"; $query_result1 = @mysqli_query($conn, $sql); $query_result2 = @mysqli_query($conn, $sqlMyfriends); //populating 1st table $sqlSt3="INSERT INTO friends (friend_id, friend_email, password, profile_name, date_started, num_of_friends) VALUES('NULL','[email protected]','123','abc','2012-10-25', 5)"; $queryResult3 = @mysqli_query($dbConnect,$sqlSt3) //populating 2nd table $sqlSt13="INSERT INTO myfriends VALUES(1,2)"; $queryResult13=@mysqli_query($dbConnect,$sqlSt13); mysqli_close($conn); ?>

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Properly handling NSURLConnection errors

- by Cal S

Hi, I have a simple form interface set up that send username and password information to a server: (working) NSString *postData = [NSString stringWithFormat:@"user=%@&pass=%@",[self urlEncodeValue:sysUsername],[self urlEncodeValue:password]]; NSLog(@"Post data -> %@", postData); /// NSData* postVariables = [postData dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSMutableURLRequest* request = [[[NSMutableURLRequest alloc] init] autorelease]; NSString* postLength = [NSString stringWithFormat:@"%d", [postVariables length]]; NSURL* postUrl = [NSURL URLWithString:@"http://localhost/~csmith/cocoa/test.php"]; [request setURL:postUrl]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody: postVariables]; NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:NULL error:NULL]; NSLog(@"Post data SENT & returned -> %@", returnData); How do I handle connection errors such as no internet connection, firewall, etc. Also, does this method use the system-wide proxy settings? Many of my users are behind a proxy. Thanks a lot!

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find and replace values in csv using PHP

- by peirix

I'd think there was a question on this already, but I can't find one. Maybe the solution is too easy... Anyway, I have a csv and want to let the user change the values based on a name. I've already sorted out creating new name+value-pairs using the fopen('a') mode, using jQuery to send the AJAX call with newValue and newName. But say the content looks like this: host|http:www.stackoverflow.com folder|/questions/ folder2|/users/ And now I want to change the folder value. So I'll send in folder as oldName and /tags/ as newValue. What's the best way to overwrite the value? The order in the list doesn't matter, and the name will always be on the left, followed by a |(pipe), the value and then a new-line. My first thought was to read the list, store it in an array, search all the [0]'s for oldName, then change the [1] that belongs to it, and then write it back to a file. But I feel there is a better way around this? Any ideas? Maybe regex?

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Changing style sheets depending on useragent

- by John Vasiliou

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Replacing mysql user authentication with openid

- by David

So, I'm working with a really old system which uses a person's mysql database credentials to authenticate to a web site (the database was originally only accessed from the command line, but is now accessed from a php frontend). Because of some internal reasons (and to preserve the user's history), I have to leave the old authentication intact. I've been charged with adding openid authentication to this system. Somehow I need to be able to retrieve a users mysql username and password upon logging into the site through openid (using the Zend framework, by the way). I've thought of simply requiring registration at the first login, where the user must provide their mysql credentials, but I'd rather not store the password plain text. I've also considered blanking everyone's mysql passwords, and just setting the user's mysql username manually (rather than having the user provide this, since they could provide any username). This is turning into a security nightmare. Does anyone have any suggestions for alternatives? This is running on a Linux server, by the way. Also, I can't use mysql pluggable authentication because the mysql version is 5.0 (pluggable authentication requires mysql 5.5), and no, I can't update it.

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Shell script for generating HTML out put

- by user1638016

The following script is generating the desired out put but not redirecting the result to /home/myuser/slavedelay.html #!/bin/bash host=<ip> echo $host user=usr1 password=mypass threshold=300 statusok=OK statuscritical=CRITICAL for i in ert7 ert9 do echo "<html>" > /home/myuser/slavedelay.html if [ "$i" == "ert7" ]; then slvdelay=`mysql -u$user -p$password -h<ip> -S /backup/mysql/mysql.sock -e 'show slave status\G' | grep Seconds_Behind_Master | sed -e 's/ *Seconds_Behind_Master: //'` if [ $slvdelay -ge $threshold ]; then echo "<tr><td>$i</td><td>CRITICAL</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>CRITICAL</td>" else echo "<tr><td>$i</td><td>OK</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>OK</td>" fi fi done echo "</html>" >> /home/myuser/slavedelay.html If I cat the output file /home/myuser/slavedelay.html it gives. <html> </html> Execution result : sh slave_delay.sh <tr><td>sdb7</td><td>OK</td>

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if a JAR is placed on app servers's classpath how do we reference it from JSP

- by Omnipresent

On our application we are getting an error saying: PWC6117: File "/struts-tags" not found code in the file thats giving error is: <%@ taglib prefix="s" uri="/struts-tags" %> This file is in struts2-core.jar which is placed on the classpath of the app server (Sun 9.1). The code will work fine and not complain when the jar is actually in WEB-INF/lib of the application, compared to being on classpath of the appserver. But we can not change that. it has to be on appservers classpath. But how should we change our code so that this error goes away? I can create mapping in my web.xml so that tag uri's are change. but what should taglib-location be changed to? so that it references to app servers classpath? <taglib> <taglib-uri>/WEB-INF/struts-tags.tld</taglib-uri> <taglib-location>/WEB-INF/struts-tags.tld</taglib-location> </taglib>

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Selenium problem locating by DOM

- by bartonlee

Hi, I'm trying to use the DOM to locate a form element in Selenium but I can't get it to work. Even if I use the example in the Selenium documentation it still fails, for example with this html... <html> <body> <form id="loginForm"> <input name="username" type="text" /> <input name="password" type="password" /> <input name="continue" type="submit" value="Login" /> <input name="continue" type="button" value="Clear" /> </form> </body> <html> and this command in the Selenium IDE... verifyElementPresent with target... dom=document.forms['loginForm'] I get [error] false in the log. The 'getElementById' example in the documentation does work, but none of the others. Can someone explain what I'm doing wrong here? Thanks.

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Discussion - Allowing / blocking user access to pages / Client Side Validation (Client Side Only!) -

- by Ozaki

TLDR Using plain HTML / Javascript (Client Side) I want to prevent viewing of certain pages. The user will have to type a username and password and depending on that they get access to different pages. Answers can NOT include server side whatsoever It does not matter if they can break it easily. There is no sensitive information etc. Also the target audience will not have access to internet OR probably know what a cookie is... At some point the user will have to type username / password.(I can define the cookie here) Currently I thought of using cookies to set a cookie for each page to say "true" / "false" but that would get messy with so many cookies. Or setting an array within a cookie for each page? I have div field "#Content" which as it looks encompasses all of my content on the page so blocking out content will be as simple as replacing it with ("sorry you don't have access") etc. For Example: $.cookie("Access","page1, page2, page3"{ expires: 1 }); I am looking for anyway to do this does not have to be with cookies. Would be nice to get a discussion of different ways this can be done. So the question is: What do YOU think would be a good way to go about doing this with client side validation? Also on another note discussion on how to make client side more secure or ways to do so are acceptable.

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make java plugin use the browser certificates

- by Shalom938

We have a java applet that communicates with a spring application running on tomcat and using spring's http invoker. We want to secure the applet using ssl with client authentication, we have a jsp page for login, after successful login the applet loads. The jsp page is secured with ssl, when the applet loads the http invoker inside the applet is doing a second handshake apparently not related to the browser handshake, OK, I don't mind that, but I want the java plugin to use browser certificates and client certificates but its not, I have to load the client certificate to the java plugin also using the java ControlPanel, and if my server's certificate is self signed then I have to load the server certificate also to the java ControlPanel and to the nrowser. Another thing is when the applet starts loading the java plugin pops a dialog asking for the client keystore password, I would like to avoid that. So to conclude: I would like the java plugin to use the browser's trusted certificates and client certificates, and to avoid the keystore password dialog that pops up. I have googled for it for two days and can't find any clue of how to accomplish that. I will appreciate any help. I'm using jdk 1.6.0 u23 and firefox 3.6.13.

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Paypal Sandbox 2014 Non US test account Sign Up proper link

- by Flood Gravemind

Ok I had a Paypal Sandbox account a year ago. I am developing a new site for a client and when I try to Login it won't recognize my email address. I tried forgot my password forgot password still nothing. So I guessed that maybe due to inactivity for such a long time they may have deleted my account. So then I try to Sign Up for a new one. I entered my details 3 times now and spent 6 hours trying to figure out what is the proper link to do this. Then I went to another Sandbox link which required me to entered a US Zip code and its a dead end. I am not even sure which Paypal account I signed up for those three times. No email nothing at all. I am a Non US developer and the FAQ link for Non US developers just points to their REST API. Can someone please guide me to the proper Paypal Sandbox Setup for Non US developers including the proper sign up links please. And I know Stackoverflow does not like rants but from my experience dealing with Paypal, GTA 6 should make a satirical Paypal company in their next Game with Paypal Developer Rampage mode for the main protagonist who also happens to be a Developer. EDIT: REST API does not include UK :(

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JDBC with JSP fails to insert

- by StrykeR

I am having some issues right now with JDBC in JSP. I am trying to insert username/pass ext into my MySQL DB. I am not getting any error or exception, however nothing is being inserted into my DB either. Below is my code, any help would be greatly appreciated. <% String uname=request.getParameter("userName"); String pword=request.getParameter("passWord"); String fname=request.getParameter("firstName"); String lname=request.getParameter("lastName"); String email=request.getParameter("emailAddress"); %> <% try{ String dbURL = "jdbc:mysql:localhost:3306/assi1"; String user = "root"; String pwd = "password"; String driver = "com.mysql.jdbc.Driver"; String query = "USE Users"+"INSERT INTO User (UserName, UserPass, FirstName, LastName, EmailAddress) " + "VALUES ('"+uname+"','"+pword+"','"+fname+"','"+lname+"','"+email+"')"; Class.forName(driver); Connection conn = DriverManager.getConnection(dbURL, user, pwd); Statement statement = conn.createStatement(); statement.executeUpdate(query); out.println("Data is successfully inserted!"); } catch(SQLException e){ for (Throwable t : e) t.printStackTrace(); } %> DB script here: CREATE DATABASE Users; use Users; CREATE TABLE User ( UserID INT NOT NULL AUTO_INCREMENT, UserName VARCHAR(20), UserPass VARCHAR(20), FirstName VARCHAR(30), LastName VARCHAR(35), EmailAddress VARCHAR(50), PRIMARY KEY (UserID) );

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Resource allocation and automatic deallocation

- by nabulke

In my application I got many instances of class CDbaOciNotifier. They all share a pointer to only one instance of class OCIEnv. What I like to achieve is that allocation and deallocation of the resource class OCIEnv will be handled automatically inside class CDbaOciNotifier. The desired behaviour is, with the first instance of class CDbaOciNotifier the environment will be created, after that all following notifiers use that same environment. With the destruction of the last notifier, the environment will be destroyed too (call to custom deleter). What I've got so far (using a static factory method to create notifiers): #pragma once #include <string> #include <memory> #include "boost\noncopyable.hpp" class CDbaOciNotifier : private boost::noncopyable { public: virtual ~CDbaOciNotifier(void); static std::auto_ptr<CDbaOciNotifier> createNotifier(const std::string &tnsName, const std::string &user, const std::string &password); private: CDbaOciNotifier(OCIEnv* envhp); // All notifiers share one environment static OCIEnv* m_ENVHP; // Custom deleter static void freeEnvironment(OCIEnv *env); OCIEnv* m_envhp; }; CPP: #include "DbaOciNotifier.h" using namespace std; OCIEnv* CDbaOciNotifier::m_ENVHP = 0; CDbaOciNotifier::~CDbaOciNotifier(void) { } CDbaOciNotifier::CDbaOciNotifier(OCIEnv* envhp) :m_envhp(envhp) { } void CDbaOciNotifier::freeEnvironment(OCIEnv *env) { OCIHandleFree((dvoid *) env, (ub4) OCI_HTYPE_ENV); *env = null; } auto_ptr<CDbaOciNotifier> CDbaOciNotifier::createNotifier(const string &tnsName, const string &user, const string &password) { if(!m_ENVHP) { OCIEnvCreate( (OCIEnv **) &m_ENVHP, OCI_EVENTS|OCI_OBJECT, (dvoid *)0, (dvoid * (*)(dvoid *, size_t)) 0, (dvoid * (*)(dvoid *, dvoid *, size_t))0, (void (*)(dvoid *, dvoid *)) 0, (size_t) 0, (dvoid **) 0 ); } //shared_ptr<OCIEnv> spEnvhp(m_ENVHP, freeEnvironment); ...got so far... return auto_ptr<CDbaOciNotifier>(new CDbaOciNotifier(m_ENVHP)); } I'd like to avoid counting references (notifiers) myself, and use something like shared_ptr. Do you see an easy solution to my problem?

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